Question 4 of 10
Multiple Choice: Please select the best answer and click "submit."
What is the length of the altitude of the equilateral triangle below?
30°
6
09
a
60° 90°
3
60°
3
O A. 1
OB. 6
O C. 313
OD. 3
O E. 6.13
O F. 27

Question 4 Of 10Multiple Choice: Please Select The Best Answer And Click "submit."What Is The Length

Answers

Answer 1

Answer:

Option C. 3√3

Step-by-step explanation:

Please see attached photo for brief explanation.

In the attached photo, we obtained the following:

Opposite = a

Adjacent = 3

Hypothenus = 6

Angle θ = 60°

We can obtain the value of 'a' as follow:

Tan θ = Opposite /Adjacent

Tan 60° = a/3

Cross multiply

a = 3 x Tan 60°

But: Tan 60° = √3

a = 3 x Tan 60°

a = 3 x √3

a = 3√3

Therefore, the length of the altitude of the equilateral triangle is 3√3.

Question 4 Of 10Multiple Choice: Please Select The Best Answer And Click "submit."What Is The Length

Related Questions

Solve using the quadratic formula.

2x2=8x-7

Answers

Answer:

[tex]\boxed{x=\frac{4\pm\sqrt{2}}{2}}[/tex]

Step-by-step explanation:

Part 1: Rewriting equation to match ax² + bx + c = 0 (quadratic function)

The given equation is not written in quadratic form. To rewrite the equation:

All values need to be on the left side of the equation and set equal to zero.

To overcome this difficulty, follow these mathematical steps:

[tex]2x^2=8x-7\\2x^2-8x=-7\\2x^2-8x+7=0[/tex]

Subtract 8x from both sides of the equation to rearrange it to the left side. Then, add 7 to rearrange it as well. Finally, set the three values on the left of the equation equal to zero.

Part 2: Using the quadratic formula

The quadratic formula is defined as [tex]\boxed{x=\frac{-b\pm\sqrt{b^2-4ac} }{2a} }[/tex].

Using the parent quadratic function, the values are easy to find in the given equation. [tex]\boxed{a=2, b=-8, c=7}[/tex]

Substitute these values into the quadratic formula and solve for x.

[tex]x=\frac{8\pm\sqrt{(-8)^2-4(2)(7)}}{2(2)} \\\\x=\frac{8\pm\sqrt{64-4(14)}}{4}\\\\x=\frac{8\pm\sqrt{64-56}}{4} \\\\x=\frac{8\pm\sqrt{8}}{4}\\\\x= 2\pm\frac{\sqrt{8}}{4}\\ \\x=2\pm\frac{\sqrt{2}}{2}[/tex]

Part 3: Solving for x with the values from the quadratic formula

Now that x is set equal to the simplified version of the equation, the operations have to be followed through with.

This equation will have two zeros/roots to solve for by setting x equal to zero.

Operation 1: Addition

[tex]x=2+\frac{\sqrt{2} }{2}\\\\x=\frac{4+\sqrt{2}}{2}[/tex]

Operation 2: Subtraction

[tex]x=2-\frac{\sqrt{2}}{2}\\ \\x=\frac{4-\sqrt{2}}{2}[/tex]

Because both values are the exact same (minus the operations), the roots can be simplified even further to one value:

[tex]\boxed{x=\frac{4\pm\sqrt{2}}{2}}[/tex]

What is the equation of the line that passes through (1, 3) and (-2, -3)? y = -2x + 1 y = 2x + 1 y = x - 1 y = -x + 1

Answers

Answer: y = 2x+1

Step-by-step explanation:

It is the only line with (1,3) as a solution.  A slower algebraic way to solve this would be to plug in 1 for x and 3 for y, then, out of the equations in which it works, plug in -2 for x and -3 for y.  The equation that remains true for both points is the answer.

Hope it helps <3

Answer:

[tex]\boxed{y = 2x + 1}[/tex]

Step-by-step explanation:

The line passes through (1, 3).

The solution of the line is the points it crosses.

x = 1

y = 3

Plug x as 1 and y as 3 in the equation.

y = -2x + 1

3 = -2(1) + 1

3 = -2 + 1

3 = -1 False

Plug x as 1 and y as 3 in the equation.

y = 2x + 1

3 = 2(1) + 1

3 = 2 + 1

3 = 3 True

Plug x as 1 and y as 3 in the equation.

y = x - 1

3 = 1 - 1

3 = 0 False

Plug x as 1 and y as 3 in the equation.

y = -x + 1

3 = -(1) + 1

3 = -1 + 1

3 = 0 False

Select the correct answer.
Which relation is a function?

A. {(2,3), (1,5), (2,7)}

B. {(-1,5), (-2,6), (-3,7)}

C. {(11,9), (11,5), (9,3)}

D. {(3,8), (0,8), (3,-2)}

Answers

Answer:

The answer is option B.

Explanation:

A rule that uniquely associates elements of one set A with the elements of another set B and each element in set A maps to only one element in set B.

Each element from X is related to only one element in Y. But it is okay for two different elements in X to be related to the same element in Y. So its  still a function. Let suppose

{ (1,a) , (2, b) , (2, c) , (3, d) }

This relation is not a function from X to Y because the element 2 in X is related to two different elements, b and c.

If you vertically stretch the exponential function, f(x) = 2^x, by a factor of 4, what is the equation of the new function?

Answers

Answer:

f( x ) = 4( [tex]2^x[/tex] )

Step-by-step explanation:

If we vertically stretch a graph by a factor of 4, the " exponential slope " extending from the x - axis, should increase by a factor of 4 as well.

Therefore, the previous function is expressed by the following ...

f( x ) = [tex]2^x[/tex] ... then this new function should be -

f( x ) = 4( [tex]2^x[/tex] )

The equation of this new function is f( x ) = 4( [tex]2^x[/tex] )

Lily is using dark power crystals to raise an army of zombies. Each crystal can raise 999 zombies. How many crystals does Lily need to raise 6{,}1746,1746, comma, 174 zombies?

Answers

Answer:

X= 618079825.9

Y= 6.18 crystals

Step-by-step explanation:

It takes Lily a crystal to raise 999 zombies.

It will take her x crystals to Raise 617461746174 zombies

Mathematically

One crystal= 999 zombies

X = 617461746174

X=( 617461746174*1)/999

X= 617461746174/999

X= 618079825.9

Again

It took one crystal to raise 999 zombies

It will take y crystal to raise 6174 zombies

Mathematically

One = 999

Y =( 6174*1)/999

Y= 6.18 crystals

PLEASE ANSWER ASAP WITH AN EXPLANATION
The eighth grade class at Seven Bridges Middle School has 93 students. Each student takes a current events class, a foreign language class, or both a current events class and a foreign language class. There are 70 eighth graders taking a current events class, and there are 54 eighth graders taking a foreign language class. How many eighth graders take only a current events class and not a foreign language class?

Answers

Answer:

39 students

Step-by-step explanation:

let x represent the number of students taking both current event and foreign language

there are : 70 eight grader taking current event and 54 taking foreign

70+54-x=93

-x=93-124

x= 31 students taking both

number of eighth graders take only a current events class and not a foreign language class: 70-31=39 students

determine (a) the area and (b) the circumference of the circle.

a. the area of the circle is ___

b. the circumference of the circle is ____

Answers

Step-by-step explanation:

a).

To find the area of the circle we must first find the radius using the formula

radius = diameter / 2

From the question

diameter = 21 ft

The radius is

21/2 = 10.5 ft

Area of a circle = πr²

where r is the radius

Area = π(10.5)²

= 110.25π

= 346.36 cm²

b).

Circumference of a circle = πd

where d is the diameter

Circumference = π(21)

= 65.97cm

Hope this helps you

Answer:

[tex]\huge\boxed{Answer\hookleftarrow}[/tex]

Given,

Diameter of the ⭕ (d) = 21 ft

So, radius of the ⭕ (r) = ?

[tex]r = \frac{d}{2} \\ r = \frac{21}{2} \\ r = 10.5 \: \: ft[/tex]

[tex]\boxed{Radius \ = \ 10.5 \ ft}[/tex]

____________________

a) Find the area of the ⭕.

[tex]\boxed{Area \ (a) \ = \ πr^{2}}[/tex]

[tex]a = \pi \: r ^{2} \\ a = \pi(10.5) {}^{2} \\ a = 110.25 \: \pi \\ a = 110.25 × 3.14 \\ a = 346.18 \ ft^{2}[/tex]

[tex]\boxed{Area \ = \ 346.18 \ ft^{2}}[/tex]

____________________

b) Find the circumference of the ⭕.

[tex]\boxed{Circumference \ (c) \ = \ \pi \:d}[/tex]

[tex]c = \pi \: d \\ c = \pi(21) \\ c = 21\pi \\ c = 21 × 3.14 \\ c = 65.94 \ ft[/tex]

[tex]\boxed{Circumference \ = \ 65.94 \ ft}[/tex]

____________________

Value of [tex]\pi [/tex]is taken as 3.14

____________________

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

╭═══════ღ❦ღ══╮

[tex] ღRainbowSalt2^{2}2^{2} [/tex]

╰══ღ❦ღ═══════╯

224,112,56,28 what are the two next answers?

Answers

Answer:

14,7

Step-by-step explanation: if it is being divided by 2 it is 14 and 7

Find the value of each trigonometric ratio.

Answers

Answer: 40/41

Step-by-step explanation:

The cosine can be represented as adjacent/hypotenuse.  Thus, the cosine of C is 40/41

Answer:

[tex] \frac{40}{41} [/tex]

Solution,

BC = 40

AC = 41

Now,

[tex]cos \: theta \: = \frac{adjacent}{hypotenuse} [/tex]

[tex]cos \: c \: = \frac{bc}{ac} [/tex]

Plugging the values

[tex]cos \: c \: = \frac{40}{41} [/tex]

Hope this helps..

Good luck on your assignment..

To find the number of units that gives break-even for the product, solve the equation R C. Round your answer to the nearest whole unit A manufacturer has total revenue given by the function R = 90x and has total cost given by C 35x + 17,000, where x is the number of units produced and sold. A, 55 units
B. 125 units
C. 136 units
D. 309 units

Answers

Answer:

The correct answer is D.

Step-by-step explanation:

Giving the following information:

R = 90x

Total cost= 35x + 17,000

x= is the number of units produced and sold

Now, we know that:

Unitary variable cost= 35

Fixed costs= 17,000

Selling price per unit= 90

To calculate the break-even point in units, we need to use the following formula:

Break-even point in units= fixed costs/ contribution margin per unit

Break-even point in units= 17,000 / (90 - 35)

Break-even point in units= 309 units

f(x) = 4x^4 – 2x^3 – 3x^2 + 6x - 9 Find the Zeros Using Descartes' Rule of Signs

Answers

Answer:

So possibilities of zeroes are:

Positive       Negative       Imaginary

   1                    1                   2

   3                   1                   0

Zeroes = -1.4549, 1.2658, 0.34457-1.0503i, 0.34457+1.0503i.  

Step-by-step explanation:

Note: Descartes' Rule of Signs is used to find the signs of zeroes not the exact value.

The given function is

[tex]f(x)=4x^4-2x^3-3x^2+6x-9[/tex]

Degree of polynomial is 4 so number of zeroes is 4.

There are three sign changes, so there are either 3 positive zeros or 1 positive zero.

Now, put x=-x in f(x).

[tex]f(-x)=4(-x)^4-2(-x)^3-3(-x)^2+6(-x)-9[/tex]

[tex]f(-x)=4x^4+2x^3-3x^2-6x-9[/tex]

There is one variation in sign change, so there is 1 negative zero.

So possibilities of zeroes are:

Positive       Negative       Imaginary

   1                    1                   2

   3                   1                   0

Using graphing calculator the zeroes of given function are -1.4549, 1.2658, 0.34457-1.0503i and 0.34457+1.0503i.  

people tend to be more Satisfied with election results if their top choices win.for how many,and what percentage,of people was the winning
A. their first choice (12 people)
B their second choice (7 people)
C their third choice (3 people)
D their last choice (3 people)
im so dum and suck at math ​

Answers

Answer:

Our set of data is:

A. their first choice (12 people)

B their second choice (7 people)

C their third choice (3 people)

D their last choice (3 people)

The total number of people is:

12 + 7 + 3 + 3 = 25.

You already know the number of people for each situation, but let's calculate the percentage:

1st choice: The first choice of 12 people winned, and the total number of people is 25.

Now, 25 is our 100%, then 12 is equivalent to x;

Then we have

12*100% = 25*x

x = (12/25)*100% = 48%

This is:

The quotient between

Second choice:

Same reasoning as above, here the percentage is:

(7/25)*100% = 28%

Third choice:

Same reasoning as above, here the percentage is:

(3/25)*100% = 12%

Fourth/Last choice:

Same reasoning as above, here the percentage is:

(3/25)*100% = 12%

In the Olympic tennis event ( in which each tennis player gets eliminated from the tournament after the first defeat) there are 37 players participating. Can you count how many matches there need to be until there is one winner.?

Answers

Answer: 26 games in total.

Step-by-step explanation:

If in each game we have one winner and one loser, then after each game we have one less player.

first, out of 37 players, we can write it as 36 players  + 1 player that does not play in the first round

the 36 players play games. Because in each game we need 2 players, we have a total of 36/2 = 18 games

in those 18 games, we eliminate 18 players, so now we have 37 - 18 = 19 players.

Now, we can write 19 = 18 players + 1 player that does not play this round.

From the 18 players, we have 18/2 = 9 games.

And from those 9 games, we lose 9 players, so now we have:

19 - 9 = 10 players.

Now from those 10 players, we have 10/2 = 5 games, so after those 5 games we have 10 - 5 = 5 players.

Now we can write 5 = 4 players + 1 player that does not play this round.

from the 4 players we have 4/2 = 2 games, after those 2 games we end with 5 - 2 = 3 players.

And from those last 3 players, we have two games, where in each game one player is eliminated until we have only one winner.

Then the total number of games is:

18 + 9 + 5 + 2 + 2 = 26 games

given the equation below which of the following shows the quadratic formula correctly applied? 3x^2-4x-12=0

Answers

[tex] {3x}^{2} - 4x - 12 = 0[/tex]

[tex]a = 3[/tex]

[tex]b = - 4[/tex]

[tex]c = - 12[/tex]

Formula:

[tex] \boxed{x = \dfrac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }[/tex]

Replacing:

[tex]x = \dfrac{ -( - 4) \pm \sqrt{ { (- 4)}^{2} - 4(3)( - 12)} }{2(3)} [/tex]

Option: C).

4= t/2.5,what is t?

Answers

Answer:

T=10

Step-by-step explanation:

Answer:

t=10

Step-by-step explanation:

you multiply each side by 2.5 so 4*2.5= 10

Pls help ASAP will make brailist

Answers

Answer:

B. 1296 in.^2

Step-by-step explanation:

The rectangles are similar, and sides ST and YZ are corresponding sides.

The linear scale factor is k = YZ/ST = 24/8 = 3

The area scale factor is k^2 = 3^2 = 9

A = 144 sq in. * k^2 = 144 sq in. * 9 = 1296 sq in.

Answer: B. 1296 in.^2

Answer:

4)1,296in^2

5)510.4ft

Step-by-step explanation:

4)

24/8=3 This is the dilation

144/8=18 This is the side length for QRST

18*3=54 The side length for WXYZ

24*54=1296 The area of WXYZ

5)

319*8/5 Your fence with a scale factor of 8/5

319*1.6 Changing 8/5 into fraction form

319*1.6=510.4 The length of the friend's fence.

Hope this helps. I could not see the end of the last question so I am sorry if it is not written properly.

Have a good day!

with a y-intercept 10, x-intercept 2, and equation of axis of symmetry x-3=0

Answers

Answer: f(x) = -3x^2 + 3x - 2

Explain: x of vertex: [tex]x[/tex] = [tex](-\frac b{2}{a} )[/tex]  = [tex]-\frac{3}{-6} = \frac{1}{2}[/tex]

y of vertex: y = [tex]f (\frac{1}{2} ) = - \frac{3}{4} + \frac{3}{2} -2=-\frac{5}{4}[/tex]

y-intercept: y = -2

x-intercept: y = 0

D = b[tex]^[/tex]^2 - 4ac = 9 - 24 = - 15 <0. There are no real roots (no x-intercepts) because D<0.

Since a <0, parabola opens downward. The parabola is below the x-axis

2. Find the distance between the two points. Round to the nearest tenth if necessary.
(0,9), (-8, -4)
21
15.3
9.4
233​

Answers

Answer:

[tex]\boxed{D = 15.8\ units}[/tex]

Step-by-step explanation:

The coordinates are (0,9) and (-8,-4)

Distance Formula = [tex]\sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]

D = [tex]\sqrt{(-8-0)^2+(-4-9)^2}[/tex]

D = [tex]\sqrt{(-8)^2+(-13)^2}[/tex]

D = [tex]\sqrt{81+169}[/tex]

D = [tex]\sqrt{250}[/tex]

D = 15.8 units

Answer:

15.3

Step-by-step explanation:

The coordinates are (0,9) and (-8,-4)

Distance of two points formula:

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Plug in the values.

[tex]D=\sqrt{(-8-0)^2+(-4-9)^2}[/tex]

[tex]D=\sqrt{(-8)^2+(-13)^2}[/tex]

[tex]D=\sqrt{64+169}[/tex]

[tex]D=\sqrt{250}[/tex]

[tex]D= 15.264338...[/tex]

[tex]D \approx 15.3[/tex]

Jonathan was laying on the ground and enjoying the shade but now the sun is shining
on him. He knows he is 10 yards away from the building that was shading the sun and
that the building is 8 yards high. At what angle does the sunlight hit the ground? Write
only the number rounded to the nearest degree.

Answers

Answer:

38.5°

Step-by-step explanation:

Given that the height of the building is 8 yard and the distance between Jonathan and the building is 10 yards.

The sun is at the top of the building, let the distance between Jonathan laying on the ground and the top of the building be x. Using Pythagoras:

x² = 10² + 8²

x² = 100 + 64

x² = 164

x = √164 = 12.86 yards

For a triangle with sides a, b, c and their respective opposite angles A, B, and C. The sine rule is given as:

[tex]\frac{a}{sin(A)} =\frac{b}{sin(B)}=\frac{c}{sin(C)}[/tex]

Let the angle that the sunlight hit the ground be y°. The andle between the building and the ground is 90°. Therefore using sine rule:

[tex]\frac{8}{sin(y)}=\frac{12.86}{sin(90)}\\\\sin(y)=\frac{8*sin(90)}{12.86}\\\\sin(y)=0.622\\\\y=sin^{-1}0.622\\\\y = 38.5^0[/tex]

pls answer asap i need this answer quick plus the full explanation #4

Answers

Answer:

Her Verticle ramp support was 5.5 ft tall.

Step-by-step explanation:

In this type of question, you would need to use the saying "soh cah toa".

Soh Cah Toa is a saying that people use for Sin, Cosine, and tagent. Each of those mean

Sine: opposite/hypotenuse Cosine: Adjacent/hypotenuse and Tagent: Opposite/Adjacent

In this specific question to figure out how tall or high her support is or needs to be have to 20 degree  angle off the ground, you will need to use Sin which is opposite over Hypotenuse or x/16

To find the answer in your calculator you would do:

Sin(20)=x/16

First thing you do is the get the x on one side by itself so you would multiply 16 on both sides giving you:

16 × Sin(20)= x

You would then follow to put Sin(20) in your calculator giving you 0.34202014332

After that you multiply that number by 16

5.47232229321

Rounding to the nearest tenth you get answer:

5.5

The art club is planning a meeting. They are planning to serve cookies and brownie bites and want to have one dessert per person. They expect an attendance of a total of 75 people. Cupcakes (c), come in packs of 6 each, and the brownie bites (b) come in packages of 15. (here is the equation > 6c+15b=75).
Question #1) If the treasurer buys 1 package of brownie bites, how many packages of cupcakes are needed according to this equation? Question #2) If the treasurer buys 7 packages of brownie bites, how many packages of cupcakes are needed according to this equation?

Answers

Answer:

see explanation

Step-by-step explanation:

1) 6c + 15(1) = 75

6c = 60

c = 10 packs of cupcakes

2) 6c + 15(7) = 75

6c + 105 = 75

6c = -30

c = -5, since he bought more brownies than needed, he does not need to buy any cupcakes.

Answer:

6c+15b=75

1)If the treasurer buys 1 package of brownie bites

6(1)+15b=75

15b=75-6

b=69/15=4.6 ( means the treasure needs to buy 5 packages).

2): If the treasurer buys 7 packages of brownie bites,

6c+15(7)=75

6c+105=75

c=-30/6=-5( you can not buy negative amount)

the treasure does not need to buy, because brownies are enough and more.

Use the formula for the area of a circle to find the area of the bull’s eye and the next ring together A. 22,686.5 mm2
O B. 31,400 mm2
O C. 452.39 mm
O D. 314 mm2

Answers

Answer:

B. 31,400 mm2

Step-by-step explanation:

We know that the bull's eye target has a diameter of 20 centimeters, which equals 200 milimeters.

So, we find the area

[tex]A_{target}= \pi (100mm) ^{2} =(3.14)(10000) mm^{2} =31,400 mm^{2}[/tex]

Therefore, the right answer is B.

Answer:

D. 31,400mm^2

Step-by-step explanation:

Please answer this now in two minutes

Answers

Answer:

[tex] s = 14.1 [/tex]

Step-by-step explanation:

Find s using the Law of Cosines:

m < S = 31°

SR = q = 21

SQ = r = 9

QR = s = ?

Thus,

[tex] s^2 = r^2 + q^2 - 2(r)(q)*cos(S) [/tex]

[tex] s^2 = 9^2 + 21^2 - 2(9)(21)cos(31) [/tex]

[tex] s^2 = 81 + 441 - 378*0.8572 [/tex]

[tex] s^2 = 522 - 324.0216 [/tex]

[tex] s^2 = 197.9784 [/tex]

[tex] s = \sqrt{197.9784} [/tex]

[tex] s = 14.07 [/tex]

[tex] s = 14.1 [/tex] (to the nearest tenth)

evaluate arctan(tan(2pi/3))

Answers

Answer:

For this case we know that [tex]\frac{2\pi}{3}= 120 degrees[/tex]. For this case we want to find:

[tex] arctan(tan(\frac{2\pi}{3}))[/tex]

Since the tan and arctan functions are inverse when we apply bth at the same time we got the identity function so then we got for this case:

[tex]  arctan(tan(\frac{2\pi}{3})) = I(\frac{2\pi}{3}) = \frac{2\pi}{3}[/tex]

Step-by-step explanation:

For this case we know that [tex]\frac{2\pi}{3}= 120 degrees[/tex]. For this case we want to find:

[tex] arctan(tan(\frac{2\pi}{3}))[/tex]

Since the tan and arctan functions are inverse when we apply bth at the same time we got the identity function so then we got for this case:

[tex]  arctan(tan(\frac{2\pi}{3})) = I(\frac{2\pi}{3}) = \frac{2\pi}{3}[/tex]

On the day after my birthday this year, I can truthfully say: "The day after tomorrow is a Monday". On which day is my birthday?

Answers

Answer: Friday

Step-by-step explanation:

Answer:you got this

Step-by-step explanation:

Please help me with this question regarding TRIGONOMETRY!

Answers

Answer:

The answer is option 2.

Step-by-step explanation:

First, you have to find the length of CD using Tangent Rule, tanθ = opposite/adjacent:

[tex] \tan(θ) = \frac{oppo.}{adj.} [/tex]

[tex]let \: θ = 48[/tex]

[tex]let \: oppo. = cd[/tex]

[tex]let \: adj. = ad = 110[/tex]

[tex] \tan(48) = \frac{cd}{110} [/tex]

[tex]cd = 110 \tan(48)[/tex]

[tex]cd = 122.17 \: feet[/tex]

Next, you have to find the length of BC using Sine Rule:

[tex] \sin(θ) = \frac{oppo.}{hypo.} [/tex]

[tex]let \: θ = 65[/tex]

[tex]let \: oppo. = cd = 122.17[/tex]

[tex]let \: hypo. = bc[/tex]

[tex] \sin(65) = \frac{122.17}{bc} [/tex]

[tex]bc = \frac{122.17}{ \sin(65) } [/tex]

[tex]bc = 134.8 \: feet \: (near.tenth)[/tex]

Answer:

[tex]\boxed{134.8 \: \mathrm{ft}}[/tex]

Step-by-step explanation:

Let’s take triangle ACD.

Find length CD.

tan θ = [tex]\frac{opposite}{adjacent}[/tex]

tan (48) = [tex]\frac{CD}{110}[/tex]

110 tan (48) = CD

CD ≈ 122.167

Let’s take triangle BCD.

Find length BC.

sin θ = [tex]\frac{opposite}{hypotenuse}[/tex]

sin (65) = [tex]\frac{122.167}{BC}[/tex]

BC = [tex]\frac{122.167}{sin(65)}[/tex]

BC ≈ 134.796

Instructions: Find the missing length indicated.
225
144
X=

Answers

Answer:

108

Step-by-step explanation:

To find x, you need the geometric mean. First, find the second part of 225 by doing 225 - 144 = 81. Now, to find geometric mean, do 81 x 144 = 11,664; [tex]\sqrt{11,664} = 108[/tex].

The missing length in the right triangle as given in the task content is; 108.

What is the missing length indicated?

It follows from the complete question that the triangle given is a right triangle and the missing length can be calculated as;

First, find the second part of 225 by

225 - 144 = 81.

Now, to find geometric mean,

81 × 144 = x²

11,664 = x²

x = 108

Thus, The missing length in the right triangle as given in the task content is; 108.

Read more on missing length;

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A pennant is shaped like a right triangle with a hypotenuse of 10feet. The length of one side of the pennant is two feet longer than the length of the other side. Find the length of the two sides of the pennant.

Answers

Answer:

6 ft and 8 ft

Step-by-step explanation:

let x be the length of one leg then (x + 2) is the other leg.

Using Pythagoras' identity in the right triangle, that is

x² + (x + 2)² = 10² ← expand left side and simplify

x² + x² + 4x + 4 = 100 ( subtract 100 from both sides )

2x² + 4x - 96 = 0 ( divide all terms by 2 )

x² + 2x - 48 = 0 ← in standard form

(x + 8)(x - 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 8 = 0 ⇒ x = - 8

x - 6 = 0 ⇒ x = 6

But x > 0 ⇒ x = 6

Thus the 2 sides are 6 ft and x + 2 = 6 + 2 = 8 ft

What is the answer now in two minutes

Answers

Answer:

m<R=48.2 to the nearest tenth

Step-by-step explanation:

1. sin(m<T)=2/3

m<T=arcsin(2/3)=41.81 degrees

m<R=180-90-m<T=180-90-41.81=48.19 degrees

AYOOO PLZ HELP ASAP!!!

Answers

Answer:

B.

Step-by-step explanation:

Well we know that

[tex]224=2^{5} *7[/tex]

so we can get the 2 outside of the radical

[tex]x^{11} =(x^{5} )^{2} *x[/tex]

and we can get the x^2 outside too.

[tex]y^8=y^5*y^3[/tex]

and we also can get y outside.

so we have:

[tex]2x^{2}y\sqrt[5]{7xy^3}[/tex]

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