QUESTION TWO a A Mercedes Benz mechanic, in determining whether to purchase a device of design A or design B, checks the times for completing a certain task on each device. Eight operators were used in the testing, with each operator using both device A and B in a randomized order. The times in seconds) required to complete the task are given in the following tables. B Operator A 1 32 2. 40 3 42 4 26 5 35 6 29 7 45 8 22 aaNION 30 39 42 23 36 27 41 21 a) At alpha level equal to 0.05; test to see if there is a significant difference between mean completion times. (5 Marks) b) Determine the 95% level of confidence interval for the difference between A and B. (5 Marks) .​

Answers

Answer 1

At alpha level equal to 0.05, there is no significant difference between mean completion times.

How to illustrate the significance level?

From the complete information, the test statistic will be:

t = [(33.875 - 32.375) - 0]/8.1472 × ✓0.25

t = 0.3682

The tabulated value is 1.76. Therefore, we will accept the null hypothesis. Therefore, there is no significant difference between mean completion times.

Learn more about significance level on:

https://brainly.com/question/14279939


Related Questions


Find the distance between the two points in simplest radical form (5,2)and (-3,-5)

Answers

Answer:

[tex]\sqrt{113}\\[/tex]

Step-by-step explanation:

[tex]distance= \sqrt{(5-[-3])^2+(2-[-5])^2}\\\\distance= \sqrt{(8)^2+(7)^2}\\\\distance= \sqrt{64+49}\\\\distance= \sqrt{113}\\[/tex]

Use the following statement to answer parts ​a) and​ b). One hundred raffle tickets are sold for​ $3 each. One prize of ​$500 is to be awarded. Winners do not have their ticket costs of​ $3 refunded to them. Raul purchases one ticket.
​a) Determine his expected value.
​b) Determine the fair price of a ticket.

Answers

Using the expected value of a discrete distribution, it is found that:

a) His expected value is of -$2.5.

b) The fair price of a ticket is of $0.5.

What is the mean of a discrete distribution?

The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.

In this problem, the distribution for the net value of the ticket is:

P(X = 497) = 1/1000.P(X = -3) = 999/1000.

Item a:

The expected value is given by:

[tex]E(X) = 497\frac{1}{1000} - 3\frac{999}{1000} = -2.5[/tex]

His expected value is of -$2.5.

Item b:

With an unknown ticket price, the distribution is:

P(X = 500 - x) = 1/1000.P(X = -x) = 999/1000.

The game is fair if E(X) = 0, hence:

[tex]\frac{500 - x}{1000} - \frac{999x}{1000} = 0[/tex]

0.5 - x = 0

x = 0.

The fair price of a ticket is of $0.5.

More can be learned about the expected value of a discrete distribution at https://brainly.com/question/24855677

Helpp. Mee\\\..........

Answers

Answer:

may not be exact

1- surveying every fifth student who walks in

2-randomly selected people of both genders

3-asking 8 random students from each second period

4-asking 4 girls and 4 boys from each~~

5-randomly choosing a page and counting the words

Step-by-step explanation:

1-explanation; the first one is skewed two 7th graders, the third one is skewed to volleyball players, the fourth one is skewed to eight graders

Find the value of y.

Answers

Answer:

this is your answer hope u like it

If you owned 2,000 shares of Exxon Mobile stock, how much dividend did you receive? Use the stock table below to find
your answer.
Name
Exxon Mobil
Symbol
XOM
Close
$82.80
Day Range
$82.47-$83.23
52-Week Range $80.30-$95.55
Volume
7,513,630
P/E
34.50
Dividend
$3.08
Dividend Yield
3.7%
EPS
$2.40

Answers

Answer:

  $6,160

Step-by-step explanation:

The total amount of dividend received is the product of the number of shares and the dividend per share:

  (2000 shares) × ($3.08/share) = $6,160.00 . . . dividend received

calculus, question 5 to 5a​

Answers

5. Let [tex]x = \sin(\theta)[/tex]. Note that we want this variable change to be reversible, so we tacitly assume 0 ≤ θ ≤ π/2. Then

[tex]\cos(\theta) = \sqrt{1 - \sin^2(\theta)} = \sqrt{1 - x^2}[/tex]

and [tex]dx = \cos(\theta) \, d\theta[/tex]. So the integral transforms to

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = \int \frac{\sin^3(\theta)}{\cos(\theta)} \cos(\theta) \, d\theta = \int \sin^3(\theta) \, d\theta[/tex]

Reduce the power by writing

[tex]\sin^3(\theta) = \sin(\theta) \sin^2(\theta) = \sin(\theta) (1 - \cos^2(\theta))[/tex]

Now let [tex]y = \cos(\theta)[/tex], so that [tex]dy = -\sin(\theta) \, d\theta[/tex]. Then

[tex]\displaystyle \int \sin(\theta) (1-\cos^2(\theta)) \, d\theta = - \int (1-y^2) \, dy = -y + \frac13 y^3 + C[/tex]

Replace the variable to get the antiderivative back in terms of x and we have

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = -\cos(\theta) + \frac13 \cos^3(\theta) + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = -\sqrt{1-x^2} + \frac13 \left(\sqrt{1-x^2}\right)^3 + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = -\frac13 \sqrt{1-x^2} \left(3 - \left(\sqrt{1-x^2}\right)^2\right) + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = \boxed{-\frac13 \sqrt{1-x^2} (2+x^2) + C}[/tex]

6. Let [tex]x = 3\tan(\theta)[/tex] and [tex]dx=3\sec^2(\theta)\,d\theta[/tex]. It follows that

[tex]\cos(\theta) = \dfrac1{\sec(\theta)} = \dfrac1{\sqrt{1+\tan^2(\theta)}} = \dfrac3{\sqrt{9+x^2}}[/tex]

since, like in the previous integral, under this reversible variable change we assume -π/2 < θ < π/2. Over this interval, sec(θ) is positive.

Now,

[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = \int \frac{27\tan^3(\theta)}{\sqrt{9+9\tan^2(\theta)}} 3\sec^2(\theta) \, d\theta = 27 \int \frac{\tan^3(\theta) \sec^2(\theta)}{\sqrt{1+\tan^2(\theta)}} \, d\theta[/tex]

The denominator reduces to

[tex]\sqrt{1+\tan^2(\theta)} = \sqrt{\sec^2(\theta)} = |\sec(\theta)| = \sec(\theta)[/tex]

and so

[tex]\displaystyle 27 \int \tan^3(\theta) \sec(\theta) \, d\theta = 27 \int \frac{\sin^3(\theta)}{\cos^4(\theta)} \, d\theta[/tex]

Rewrite sin³(θ) just like before,

[tex]\displaystyle 27 \int \frac{\sin(\theta) (1-\cos^2(\theta))}{\cos^4(\theta)} \, d\theta[/tex]

and substitute [tex]y=\cos(\theta)[/tex] again to get

[tex]\displaystyle -27 \int \frac{1-y^2}{y^4} \, dy = 27 \int \left(\frac1{y^2} - \frac1{y^4}\right) \, dy = 27 \left(\frac1{3y^3} - \frac1y\right) + C[/tex]

Put everything back in terms of x :

[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = 9 \left(\frac1{\cos^3(\theta)} - \frac3{\cos(\theta)}\right) + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = 9 \left(\frac{\left(\sqrt{9+x^2}\right)^3}{27} - \sqrt{9+x^2}\right) + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = \boxed{\frac13 \sqrt{9+x^2} (x^2 - 18) + C}[/tex]

2(b). For some constants a, b, c, and d, we have

[tex]\dfrac1{x^2+x^4} = \dfrac1{x^2(1+x^2)} = \boxed{\dfrac ax + \dfrac b{x^2} + \dfrac{cx+d}{x^2+1}}[/tex]

3(a). For some constants a, b, and c,

[tex]\dfrac{x^2+4}{x^3-3x^2+2x} = \dfrac{x^2+4}{x(x-1)(x-2)} = \boxed{\dfrac ax + \dfrac b{x-1} + \dfrac c{x-2}}[/tex]

5(a). For some constants a-f,

[tex]\dfrac{x^5+1}{(x^2-x)(x^4+2x^2+1)} = \dfrac{x^5+1}{x(x-1)(x+1)(x^2+1)^2} \\\\ = \dfrac{x^4 - x^3 + x^2 - x + 1}{x(x-1)(x^2+1)^2} = \boxed{\dfrac ax + \dfrac b{x-1} + \dfrac{cx+d}{x^2+1} + \dfrac{ex+f}{(x^2+1)^2}}[/tex]

where we use the sum-of-5th-powers identity,

[tex]a^5 + b^5 = (a+b) (a^4-a^3b+a^2b^2-ab^3+b^4)[/tex]

PLEASE HELPPPPPPPPPPPPPPPPPPPPPPPPPPP
Consider this dilation.



(a) Is the image of the dilation a reduction or an enlargement of the original figure? Explain.
(b) What is the scale factor? Explain and show your work.

ANSWER BOTH PARTS YOU MAY GET EXTRA POINTS!

Answers

Step-by-step explanation:

1) if the initial figure ABCD, then the figure A'B'C'D' is reduction of the initial one.

2) the scale factor is 0.5: the ratio of all the corresponded coordinates is 2:1 [D(8;4) - D'(4;2); C(4;0)-C'(2;0); B(0;-2)-B'(0;-1) and A(-4;4)-A'(-2;2)].

Mark the quadrilaterals ABcD and A'B'C'D'

The image is reduced in size hence it's reduction

Take 2 sides two calculate scale factor

AD=12unitsA'D'=6units

Scale factor:-

6/121/2

16. An online magazine charges $45,000 for a 3-month contract for a banner ad
displayed above its weekly feature article. The magazine has 120,000
subscribers and gets 195,000 hits per day. What is the banner's cost per
subscriber if a banner ad was taken for a year?

Answers

Answer:

$1.50

Step-by-step explanation:

There are 4 3-month periods in a year.

$45,000 per 3 months period × 4 = $180,000 cost

$180,000 ÷ 120,000 subscribers = $1.50

The banner ad costs about $1.50 per subscriber

Which decimal is greater: 0.347 or 0.437?

Answers

Answer:

0.437

Step-by-step explanation:

Decimals are read the same as whole numbers, starting with the first digit, which is the largest, to the right. So, to find the larger decimal you need to look at the first digit. If this digit is the same then continue to the right until there is a difference in the number. In this case, the first digit is different. Therefore, whichever has the larger first digit must be the greater one. Since 4 > 3, 0.437 must be greater than 0.347.

eter and Area
5
Annita is sewing a lace edge around a rectangular quilt. She will need 160 inches of lace to do the entire quilt. If the quilt is 46
inches wide, how long is the quilt?
A. 32 inches
B. 34 inches
C. 80 inches
D.
68 inches
Reset
Submit

Answers

Answer:

b 34

Step-by-step explanation:

its 34 because if you do 46×2 because of the both sides you will get 92 then subtract 92 from 160 and you will get 68 then do 68÷2 to find out the second side and you will get 34

1.Measurement of segment QR is 2Measurement of segment TS is 3.Measurement if segment QT is
4 The vallue of x is 5 the value of y is​​​

Answers

In a parallelogram, opposite sides are of equal measure.

QR = TS

find x

5(x) - 1 = 2(x) + 55(x) - 2(x) = 5 + 13(x) = 6x = 2

1)

QR:5(x) - 15(2) - 110 - 19

2)

QR = TS = 9

Find value of y:

QT = RSy + 8 = 3(y) - 2y - 3(y) = -2 - 8-2(y) = -10y = 5

3)

QT:

y + 85 + 813

4)

if x = 5

means the diagram is enlarged.

scale factor = 5/2 = 2.5

then y will be:

2.5 * 5 = 12.5

We need x and y

Opposite sides of a parallelogram are equal

QR=TS5x-1=2x+53x=6x=2

And

RS=QT3y-2=y+82y=10y=5

Hence

QR=TS=5x-1=5(2)-1=9RS=QT=y+8=5+8=13

#3

Segment QT is 4

so

y+8=4y=4+8y=12

Another way

x is 5

old x is 2

So

scale factor:-

k=5/2=2.5

Find y

y=5ky=5(2.5)y=12.5

Seven more than a number is less than 18

Answers

Answer:

The first thing to do is translate the sentence into mathematical notation.

"no more than" means "less than or equal to" which is written as ≤

"seven less than a number" means we are subtracting 7 from a number. We don't know what the number is, so we can use a variable (like n) for the number. So "seven less than a number" becomes n - 7.

The whole thing becomes 12 ≤ n - 7.

To solve for n, we can add 7 to both sides.

19 ≤ n.

19 is less than or equal to n, which means the smallest (minimum) value of the number is 19.

We could also do it without an inequality:

If 12 is 7 less than a number, then the number is 19, because 19-7=12. If we chose a smaller number, like 18, then 7 less than 18 is smaller than 12, which is not allowed (12 is no more than 7 less than the number). So the smallest possible value of the number is 19.

hello!

Let the number be p.

Next, "seven times p" can be written like so:-

[tex]\pmb{7p}[/tex]

This expression is less than 18:-

[tex]\bigstar{\boxed{\pmb{7p < 18}}}[/tex]

note:-

Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)

Write the standard equation of the circle with the center ​(-14​,-5​) that passes through the point ​(​-7,​5).

Answers

equation: (x + 14)² + (y + 5)² = 149

Given:

centre :  ​(-14​,-5​)point ​(​-7,​5)

=============

Formula's:

(x-h)² + (y-k)² = r²centre : (h, k)radius : rdistance between points : [tex]\sf \sqrt{(x2-x1)^2 + (y2-y1)^2}[/tex]

Find the radius:

[tex]\rightarrow \sf \sqrt{(-7-(-14))^2 + (5-(-5))^2}[/tex]

[tex]\sf \rightarrow \sqrt{\left(-7+14\right)^2+\left(5+5\right)^2}[/tex]

[tex]\sf \rightarrow \sqrt{149}[/tex]

Equation of circle:

(x-h)² + (y-k)² = r²(x-(-14))² + (y-(-5))² = (√149)²(x + 14)² + (y + 5)² = 149

Graph for clarification:

Answer:

[tex]\sf (x+14)^2+(y+5)^2=149[/tex]

Step-by-step explanation:

Standard equation of a circle:  [tex]\sf (x-a)^2+(y-b)^2=r^2[/tex]

(where (a, b) is the center and r is the radius of the circle)

Substitute the given center (-14, -5) into the equation:

[tex]\sf \implies (x-(-14))^2+(y-(-5))^2=r^2[/tex]

[tex]\sf \implies (x+14)^2+(y+5)^2=r^2[/tex]

Now substitute the point (-7, 5) into the equation to find r²:

[tex]\sf \implies ((-7)+14)^2+(5+5)^2=r^2[/tex]

[tex]\sf \implies (7)^2+(10)^2=r^2[/tex]

[tex]\sf \implies 149=r^2[/tex]

Final equation:

[tex]\sf (x+14)^2+(y+5)^2=149[/tex]

Help I don't understand this math. Whoever gets the right answer gets Brainlist! :)

Do part B please! :)​

Answers

Answer:

1=32

2=44

3=56

4=70

Step-by-step explanation:

if need working please ask

Write 8.6 × 10–3 as a basic numeral.

Answers

Answer:

[tex]8.6\times 10^{-3}=0.0086[/tex]

Step-by-step explanation:

Please help me with Part C of this question

Answers

Answer:

14-18 minutes

Step-by-step explanation:

Part a is 32 inches per minute

part b is 252 inches per minute

The question asks the change in elevation fastest, in part b 252 is greater than 32 so 14-18 minutes is the answer.

Answer:

14-18 minutes

Step-by-step explanation:

Part a is 32 inches per minute and part b is 252 inches per minute

this question asks the change in elevation fastest, in part b 252 is greater than 32 so 14-18 minutes is the answer.

Tim has a checking account with $1,200 remaining after paying bills after several months. He wants to earn interest on
this money rather than keep extra money he does not need for monthly bills in his checking account. Over the next
year, he thinks he might need to withdraw $100 one or two times. His bank requires $250 to open a regular savings
account, $500 for a one-year CD, $750 for a two-year CD, and $1,000 to open a money market account. Decide which
choice would be the best for his situation

Answers

Assuming  He wants to earn interest on this money rather than keep extra money he does not need. The choice that would be the best for his situation is  $250 to open a regular savings.

What is regular savings account?

A regular savings account is a saving acount that enables you to save and earn interest based on the amount saved because it is an interest bearing account.

Although this account gives you interest but the interest rate is low. Since Tim has $1200 in his checking account  assuming he withdraw $100 twices, Tim will have $1,000 ($1,200-$200).

Now if he open a regular saving with $250 he will have $750 left ($1,000-$250) with which he can earn interest with.

Inconclusion the choice that would be the best for his situation is  $250 to open a regular savings.

Learn more about regular account here:https://brainly.com/question/25787382

What is the value of h?

21 + h = 345

Answers

Answer:

324

Step-by-step explanation:

21 + h = 345

group like terms

h = 345 - 21

h = 324

Answer:

h=324

Step-by-step explanation:

21+h = 345

(Substituting the equation)

h=345 - 21

h= 324

!!PLEASE PLEASE PLEASE MARK ME THE BRAINLIEST!

Select ALL of the expressions that are equivalent to 4√5.

A. 2√20
B. 6^1/2-5^1/2
c. 3*5^1/2+5^1/2
D.4*5^1/2
E.2√10
F.3*5^1/2

Answers

Answer:

A, C, D


All 3 of those simplfiy to 4√5

a rope is tied to the top of a 4-meter building its other end is tied to the ground 1 meter away form the building. what is an equation for the ropes height y at distance x from the building in standard from a x-4y=4 b 4x-y =4 c 4x+y=4d x-4y=-4

Answers

Given ↷Top of the buliding = 4mThe distance between the rope knot from the buliding = 1mTo find↷equation for the ropes height (y) at distance (x) from the building in standard fromAnswer ↷4x+y=4

Solution↷

Let the equation be

[tex] \rightarrow y = mx + c[/tex]

y = height of the bulidingx = distance from buildingm = slope of equation

[tex] \huge\rightarrow \: m = \frac{y' - y}{x' - x} \\ [/tex]

(x,y) =(1,0)(x'y') =(0,4)

[tex] \huge\rightarrow \: m = \frac{4 - 0 }{0 \: - 1} = - 4 \\ [/tex]

m = -4y = mx+cy = -4x+cx= 0,y = 4 4= -4 x 0 + cc= 4

hence ,our equation would be,

[tex]\huge \rightarrow 4x + y = 4[/tex]

Given the complex number z_1=3\big(\cos \frac{14\pi}{15} +i\sin \frac{14\pi}{15}\big)z 1 ​ =3(cos 15 14π ​ +isin 15 14π ​ ) and z_2=3\sqrt{3}\big(\cos \frac{11\pi}{15} +i\sin \frac{11\pi}{15}\big)z 2 ​ =3 3 ​ (cos 15 11π ​ +isin 15 11π ​ ), express the result of z_1z_2z 1 ​ z 2 ​ in rectangular form with fully simplified fractions and radicals.

Answers

The product of z₁ = 3 · (cos 14π/15 + i · sin 14π/15) and z₂ = 3 √3 · (cos 11π/15 + i · sin 11π/15) in rectangular form with fully simplified expressions is z₁ · z₂ = 7.794 - i · 13.5.

How to determine the product of two complex numbers

Let be two numbers of the form z = a + i · b, where i = √-1, the product of two of these numbers in rectangular form is described by the following formula:

z₁ · z₂ = (a + i · b) · (c + i · d) = (a · c - b · d) + i · (a · d + b · c)   (1)

If we know that a = 3 · cos 14π/15, b = 3 · sin 14π/15, c = 3√3 · cos 11π/15, d = 3√3 · sin 11π/15, then the result in rectangular form is:

z₁ · z₂ = 7.794 - i · 13.5

The product of z₁ = 3 · (cos 14π/15 + i · sin 14π/15) and z₂ = 3 √3 · (cos 11π/15 + i · sin 11π/15) in rectangular form with fully simplified expressions is z₁ · z₂ = 7.794 - i · 13.5. [tex]\blacksquare[/tex]

Remark

The statement presents typing mistakes and is poorly formatted, the correct form is introduced below:

Given the complex number z₁ = 3 · (cos 14π/15 + i · sin 14π/15) and z₂ = 3 √3 · (cos 11π/15 + i · sin 11π/15), express the result of z₁ · z₂ in rectangular form with fully simplified fractions and radicals.

To learn more on complex numbers, we kindly invite to check this verified question: https://brainly.com/question/10251853

30
According to a survey at a local mall, 32% of the shoppers jog at least 3 days per week. Sam
asked 15 people at the mall whether they jog at least 3 days per week, and 8 people said yes.
Based on the survey, how many people should Sam have expected to say yes?
A
3
B 5
С
7
D 10
to know the most imnortant reason that neonle choose their brand of

Answers

Using the binomial distribution, it is found that Sam should have expected 5 people to say yes.

What is the binomial distribution formula?

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.

The expected value is given by:

E(X) = np.

In this problem:

15 people were sampled, hence n = 15.32% of the shoppers jog at least 3 days per week, hence p = 0.32.

Hence, the expected value for the number of people that say yes is given by:

E(X) = np = 15 x 0.32 = 5.

More can be learned about the binomial distribution at https://brainly.com/question/24863377

Determine the correct answer to the following
system of equations:
=
3x – y = 2
-2x + 4y = -8

Answers

Answer:

(0,-2)

Step-by-step explanation:

one way to solve...

3x - y = 2 --> *4

-2x + 4y = -8

multiply the first equation by 4

12x - 4y = 8

-2x + 4y = -8

-----------------

10x = 0

x = 0

y = -2

this method is called elimination

another way to solve...

3x - y = 2 simplify for y to get y = 3x - 2

-2x + 4y = -8 substitute y into this equation to solve for x

-2x + 4(3x - 2) = -8

-2x + 12x - 8 = -8

10x = 0

x = 0

y = -2

substitution

alsoo if there are options, just plug in the numbers to the correct variables

Answer:

3xy=2 2x4y=8

3x2=6x8=48x8

2. When plotting a point on a coordinate grid using an ordered pair, the
first number tells you to go up.
O True
False

Answers

Answer:  False

Explanation:

Any point is of the form (x,y)

The first coordinate is x which tells us to go either left or right depending on whether x is negative or positive.

Example: (-2,3) means we go left 2 units

Another example: (5,7) means we go to the right 5 units.

The starting point is the origin where the x and y axis meet up.

Answer:

False

Step-by-step explanation:

I NEED HELP ON THIS QUESTION (I will give a Brainlist to the best one no links please.)

Answers

The answer is 69.6 degrees because all of the angles of a triangle always add up to 180 degrees so adding 42 and 68.4 gets 110.4, and then subtracting that from 180 gets 69.9.

please help! (math)

Which expression is equivalent to the one below?
-1/2(10+1/4)

Answers

Answer:

B

Step-by-step explanation:

-½(10+¼)

-½*10 + -½*¼

-5 + -⅛

-5-⅛

Don't forget a positive and negative makes a negative

A flower garden is shaped like a circle. Its diameter is 40yd. A ring-shaped path goes around the garden. Its outer edge is a circle with diameter 48yd.
The gardener is going to cover the path with sand. If one bag of sand can cover 6yd^2, how many bags of sand does the gardener need? Note that sand comes only by the bag, so the number of bags must be a whole number. (Use the value 3.14 for pi number .)

Answers

Answer:

About 5 bags of sand

Step-by-step explanation:

1. Create Equation

[(48x3.14)-(40x3.14)]/6

2. Solve

[(48x3.14)-(40x3.14)]/6

[150.72-125.6]/6

25.12/6

Now if you use a calculater you will get

4.1866666667

So lets just round the number to 5 instead of

4 beacuse if we round it to 4 it won't be enough

to cover the whole path.

so your answer is 5

3^x= 3*2^x


solve this equation✂️​

Answers

Step-by-step explanation:

this is what i get , i hope this will help you

HELPPPPPP PLEASEEE PLEASEEEEEEEEEEEEEEEEEE

Answers

Answer:

31.63495408

Step-by-step explanation:

Find area of trinagles and semicurucles and then add up

Answer:

31.625 ft²

Step-by-step explanation:

It is assumed we need to find the area of shaded figure.

The figure comprises of two semicircles and a triangle.

The two semicircles add to one full circle with the diameter of 5 ft.

Area of circle

A = πr² = 3.14*(5/2)² = 19.625 ft²

Area of triangle

A = 1/2bh = 1/2(6)(4) = 12 ft²

Total area

19.625 + 12 = 31.625 ft²

Which of the following q values satisfies: 6-3q≤1

Q=0
Q=1
=
Q=2

Answers

Answer:

Q = 2

Step-by-step explanation:

6-3(2) = 0

0 ≤ 1

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