Answer:
The correct option is D) Fission
Explanation:
There are several methods through which Radioactive isotopes are created.
Using a nuclear reactor that has a field of neutrons, insert a stable sample such as Lutetium-176. When it gets bombarded with neutrons, it acquires some, and fission is said to have occurred. Note that when Lutetium-176 acquires a neutron, it becomes radioactive Lu-177. Fission is also used to create Fluorine-18. To obtain the same, you need to bombard pure or enriched [[tex]^{18} O[/tex]] water with ~18 MeV protons which are high energy in nature. The bombarding is achieved using a cyclotron or an accelerator.Cheers
One way to probe the nucleus is to bombard a sample with high-energy electrons. To learn about the nuclear structures in a sample, the de Broglie wavelengths of these electrons would need to be a little smaller than a nuclear radius. Estimate the energy of such electrons. Give your answer in electron-volts. (Assume that the wavelength used is about 9.0 fm.) eV
Answer:
E = 1.38 x 10⁸ eV = 138 MeV
Explanation:
The energy associated with the given wavelength can be found from the following formula:
[tex]E = \frac{hc}{\lambda}[/tex]
where,
E = Energy of electron = ?
h = Plank's Constant = 6.625 x 10⁻³⁴ J.s
c = Speed of Light = 3 x 10⁸ m/s
λ = wavelength = 9 fm = 9 x 10⁻¹⁵ m
Therefore,
[tex]E = \frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{9\ x\ 10^{-15}\ m}\\\\E = (2.21\ x\ 10^{-11}\ J)(\frac{1\ eV}{1.6\ x\ 10^{-19}\ J})[/tex]
E = 1.38 x 10⁸ eV = 138 MeV
X-rays have wavelengths between 0.1 to 10 nanometers (x10-9). What is the range of its frequency?
3x1017-3x1015 Hz
3x10, 18, -3x10, 16, Hz
3x1018-3x1017 Hz
3x1017-3x1016 Hz
10. Refraction occurs...
A. only with light waves
B. at any, unpredictable time
C. when a wave changes speed
D. only at a wave front
E. All of the above
A uniform ladder of length 10.8 m is leaning against a vertical frictionless wall. The weight of the ladder is 323 N, and it makes an angle of 1.16 radians with the floor. A man weighing 734 N climbs slowly up the ladder. When he has climbed to a point that is 7.46 m from the base of the ladder (measured along the ladder), the ladder starts to slip. Find the coefficient of static friction between the floor and the ladder.
Answer:
0.3625
Explanation:
From the given information:
Consider the equilibrium conditions;
On the ladder, net torque= 0
Thus,
[tex]\tau_{net} = 0[/tex]; and
[tex]-fL \s in \theta +m_L g \dfrac{L}{2} cos \theta + mg (7.46\ m) cos \theta = 0[/tex]
However, by rearrangement;
[tex]fL \s in \theta =m_L g \dfrac{L}{2} cos \theta + mg (7.46\ m) cos \theta \\ \\ \mu(m_L + m) gL \ sin \theta = (323 \ N) ( 10.8 \ meters) \ cos 56^0 + (734 \ N) (7.46 \ m) \ cos \ 66.46^0[/tex]
[tex]\mu= \dfrac{ (323 \ N) ( 10.8 \ m) \ cos 56^0 + (734 \ N) (7.46 \ m) \ cos \ 66.46^0}{\Big [(323 \ N)+(734 \ N) \Big] (10.8 \ m)}[/tex]
[tex]\mathbf{\mu= 0.3625 }[/tex]
please help with both questions I’m giving all my points :) it’s 23 and 24
A 10 kg migratory swan cruises at 20m/s. A calculation that takes into ac-count the necessary forces shows that this motion requires 200W of mechanical power. If we assume an efficiency similar to humans (say, 25%), a reasonableassumption, then the metabolic power of the swan is significantly higher thanthis. The swan does not stop to eat during a long day of flying; it get theenergy it needs from fat stores. Assuming an efficiency similar to humans, after12 hours of flight.
Required:
a. How far has the swan traveled?
b. How much metabolic energy has it used?
c. What fraction of its body mass does it lose?
Answer:
Part A:
Distance=864000 m=864 km
Part B:
Energy Used=ΔE=8638000 Joules
Part C:
[tex]\frac{\triangle m}{m}=0.004998=0.49985\%[/tex]
Explanation:
Given Data:
v=20m/s
Time =t=12 hours
In Secs:
Time=12*60*60=43200 secs
Solution:
Part A:
Distance = Speed**Time
Distance=v*t
Distance= 20*43200
Distance=864000 m=864 km
Part B:
Energy Used=ΔE= Energy Required-Kinetic Energy of swans
Energy Required to move= Power Required*time
Energy Required to move=200*43200=8640000 Joules
Kinetic Energy=[tex]\frac{1}{2}mv^2[/tex]
[tex]K.E\ of\ Swans=\frac{1}{2} *10*(20)^2=2000\ Joules[/tex]
Energy Used=ΔE=8640000 -2000
Energy Used=ΔE=8638000 Joules
Part C:
Fraction of Mass used=Δm/m
For This first calculate fraction of energy used:
Fraction of energy=ΔE/Energy required to move
ΔE is calculated in part B
Fraction of energy=8638000/8640000
Fraction of energy=0.99977
Kinetic Energy=[tex]\frac{1}{2}mv^2[/tex]
Now, the relation between energies ratio and masses is:
[tex]\frac{\triangle E}{E}=\frac{\triangle m}{2m}v^2[/tex]
[tex]\frac{\triangle m}{m}=\frac{2}{v^2} *\frac{\triangle E}{E}\\\frac{\triangle m}{m}=\frac{2}{20^2} *0.99977[/tex]
[tex]\frac{\triangle m}{m}=0.004998=0.49985\%[/tex]
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an object is moving with initial velocity of 5 m/s. After 10 seconds final velocity is 10 m/s. Calculate its acceleration.
Answer:
0.5 m/s 2 is the acceleration
Explanation:
hope it helped!!!
Jack has a weight of 300 N and sits 2.0 m from the pivot of see - saw. Jill has a weight of 450 N and sits 1.5 m from pivot. Who will move down?
Answer:
Jill will move down first
Explanation:
please help me with this! i will give brainliest if you get it right! NO LINKS OR IM REPORTING
Another word for kinetic energy
could be
energy.
A. Safe
B. Moving
C. Stored
D. Potential
Answer:
moving
Explanation:
hope it helped!!!
Answer:
B
Explanation:
The activity of a radioisotope is found to decrease 40% of its original value in 2.59 x 10 s.
Calculate the decay constant of the radioisotope.
Answer: [tex]0.0353\ s^{-1}[/tex]
Explanation:
Given
Radioactive material is found to decrease 40% of its original value in [tex]2.59\times 10\ s[/tex]
Sample at any time is given by
[tex]N=N_oe^{-\lambda t}[/tex]
where, [tex]\lambda=\text{decay constant}[/tex]
Put values
[tex]\Rightarrow 0.4N_o=N_oe^{-\lambda\cdot 2.59\times 10}\\\Rightarrow 0.4=e^{-\lambda\cdot 2.59\times 10[/tex]
Taking natural logarithm both side
[tex]\Rightarrow \lambda=\dfrac{\ln 2.5}{25.9}\\\\\Rightarrow \lambda =0.0353\ s^{-1}[/tex]
In an NMR experiment, the RF source oscillates at 34 MHz and magnetic resonance of the hydrogen atoms in the sample being in- vestigated occurs when the external field Bext has magnitude 0.78 T. Assume that Bint and Bext are in the same direction and take the pro- ton magnetic moment component u, to be 1.41 X 10-26 J/T. What is the magnitude of Bint?
Answer:
[tex]B_{int}=-0.015T[/tex]
Explanation:
From the question we are told that:
RF source oscillation speed [tex]\sigma= 34 MHz[/tex]
The external field [tex]Bext =0.78 T[/tex].
Pro- ton magnetic moment component [tex]\mu=1.41 X 10-26 J/T[/tex]
Generally the equation for magnitude of [tex]B_{int}[/tex] is mathematically given by
[tex]B_{int}=B_{ext}-\frac{h\triangle \sigma}{2 \mu}[/tex]
[tex]B_{int}=0.78-\frac{6.6*10^{-34}*34*10^6}{2*1.41*10^{26}}[/tex]
[tex]B_{int}=0.78-0.7957[/tex]
[tex]B_{int}=-0.015T[/tex]
What is the answer to this?
Answer:
B
Explanation:
Answer:
B
Explanation:
Anatomy and Phys PLEASE HELP
Identify at least two STDs that are caused by different microorganisms (such as bacteria, viruses, and so on). Propose at least two ethical strategies for helping to prevent these STDs OTHER THAN abstinence and male and female condoms.
least two STDs that are caused by different microorganisms (such as bacteria, viruses, and so on). Propose at least two ethical strategies for helping to prevent these STDs OTHER THAN abstinence and male and female condoms.
Answer:
Explanation:
Chlamydia is a bacterial infection that affects the reproductive system in a myriad of nasty and invasive ways, including pain during micturition, genital discharge, and spreading to the rectum and eyes. Other than safe sex practices and abstinence, ways to prevent and treat Chlamydia are antibiotics for both partners (if they're both infected) and surgical intervention in severe cases.
Trichomoniasis is a parasitic sexually transmitted disease that infects women but can affect men during intercourse, women who are infected are more likely to suffer from pain in the vaginal area during moments including micturition and intercourse as foul-smelling discharge. The more concerning aspect of this disease is how women afflicted are more likely to give premature birth and spread the infection to the baby upon birth. Much like Chlamydia, Trichomoniasis can be prevented via safe-sex practices and abstinence, but it can also be treated by antibiotics for both sexual partners to prevent spreading it between them.
PLS HELP.
A rope breaks when the speed of a 0.309 kg mass moving in a circle of radius of 0.429 m reaches 12.9 m/s
how much tension is in the strings when it breaks?
unti=n
120 works for acellus
Answer: 119.9
Explanation:
F = (mv^2)/r
Here we know m (0.309kg), v (12.9m/s) and r (0.429m)
So F = (0.309*12.9^2)/0.429 = 119.861748
Which of the following is true of a boat moving on water with
no net force acting on it?*
A. It is rising with increasing speed.
B. It is sinking with increasing speed.
C. It is traveling at a constant velocity.
D. It is accelerating forward.
A compact fluorescent bulb is 17.0% efficient. How much energy input would be required for the bulb to produce 252 J of light energy?
What time of energy is the waste output and how much would be created?
Help
Answer:
1482.35J
Explanation:
Efficency=(output energy/input energy) x100
17.0 =(252/input energy) x100
input energy =100x252/17=1482.35J
wasted energy=1482.35-252=1230.35J
Which of the following best describes Earth's crust, according to the theory of plate tectonics?
Answer:
the Earth's crust is broken into about 12 plates that float on hotter, softer rocks in the underlying mantle
Explanation:
Determine the angle between the directions of vector A with rightwards arrow on top = 3.00i + 1.00j and vector B with rightwards arrow on top = -3.00i + 3.00j.
A) 117°
B) 88.1°
C) 26.6°
D) 30.0°
E) 45.2°
Answer:
C) 26.6
Explanation:
I don't know how to calculate vector
The angle between the two vectors is 117⁰
The given parameters;
vector A = 3.00i + 1.00j
vector B = -3.00i + 3.00j
The angle between the two vectors is calculated as follows;
[tex]cos \ \theta = \frac{A\ . \ B}{|A| \ . \ |B|}[/tex]
The dot product of vector A and B is calculated as;
[tex]A \ . \ B = (3i \ + j) \ . \ (-3i \ + 3j) = (3\times -3) + (1 \times 3) = -9 + 3 =- 6[/tex]
The magnitude of vector A and B is calculated as;
[tex]|A| = \sqrt{3^2 + 1^2} = \sqrt{10} \\\\|B| = \sqrt{(-3)^2 + (3)^2} = \sqrt{18}[/tex]
The angle between the two vectors is calculated as;
[tex]cos \ \theta = \frac{-6}{\sqrt{10} \ . \sqrt{18} } \\\\cos \ \theta = \frac{-6}{\sqrt{180} } \\\\cos \ \theta = -0.4472\\\\\theta = cos \ ^{-1} (-0.4472) \\\\\theta = 116.6^0 \approx 117^0[/tex]
Thus, the angle between the two vectors is 117⁰
Learn more here: https://brainly.com/question/15006306
An experiment is performed on an unknown material and produces the given heat curve. The temperature of the material is shown as a function of heat added. Other experiments determine that the material has a temperature of fusion of fusion=235 °C and a temperature of vaporization of vapor=471 °C.
If the sample of material has a mass of =9.80 g, calculate the specific heat when this material is a solid, s, and when it is liquid, l.
The specific heat of the solid phase is 0.333 joules per gram-degree Celsius.
The specific heat of the liquid phase is 0.593 joules per gram-degree Celsius.
In this case, we need to determine that specific heat for solid and liquid states of matter. By Heat Physics, we understand that specific heat is contained in the slopes of the two sensible phases in the following form:
[tex]\frac{\Delta T}{\Delta Q} = \frac{1}{m\cdot c}[/tex] (1)
Where:
[tex]\Delta T[/tex] - Temperature change, in degrees Celsius.[tex]\Delta Q[/tex] - Heat received, in joules.[tex]m[/tex] - Mass of the sample, in grams.[tex]c[/tex] - Specific heat of the sample, in joules per kilogram-degrees Celsius.Solid phase
If we know that [tex]m = 9.80\,g[/tex], [tex]T_{1} = 40\,^{\circ}C[/tex], [tex]T_{2} = 235\,^{\circ}C[/tex], [tex]Q_{1} = 183\,J[/tex] and [tex]Q_{2} = 819\,J[/tex], then the specific heat of the solid phase is:
[tex]c = \frac{\Delta Q}{m\cdot \Delta T}[/tex]
[tex]c = \frac{819\,J-183\,J}{(9.80\,g)\cdot (235\,^{\circ}C - 40\,^{\circ}C)}[/tex]
[tex]c = 0.333\,\frac{J}{g\cdot ^{\circ}C}[/tex]
The specific heat of the solid phase is 0.333 joules per gram-degree Celsius.
Liquid phase
If we know that [tex]m = 9.80\,g[/tex], [tex]T_{3} = 230\,^{\circ}C[/tex], [tex]T_{4} = 471\,^{\circ}C[/tex], [tex]Q_{3} = 1470\,J[/tex] and [tex]Q_{4} = 2870\,J[/tex], then the specific heat of the liquid phase is:
[tex]c = \frac{\Delta Q}{m\cdot \Delta T}[/tex]
[tex]c = \frac{2870\,J - 1470\,J}{(9.80\,g)\cdot (471\,^{\circ}C - 230\,^{\circ}C)}[/tex]
[tex]c = 0.593\,\frac{J}{g\cdot ^{\circ}C}[/tex]
The specific heat of the liquid phase is 0.593 joules per gram-degree Celsius.
We kindly invite you to see this question related to specific heat: https://brainly.com/question/11194034
Choose the correct statement regarding the sign conventions for lenses.
a. The focal length f is positive for diverging lenses.
b. Virtual images appear on same side of the lens as the object and have a negative value for the image distance.
c. Real images appear on the opposite side of the lens from the object and have a negative value for the image distance.
d. The focal length f is negative for converging lenses.
e. Virtual images appear on same side of the lens as the object and have a positive value for the image distance.
Answer:
a) false
b) True
c) True
d) False
e) False
Explanation:
a) False
For a diverging lens, the focal length is negative while it is positive for a converging lens
b) True
Image distances for virtual images are always negative and it also forms on the the same side of the lens as the object and is enlarged
c) True
d) False
For a diverging lens, the focal length is negative while it is positive for a converging lens
e) False
Image distances for virtual images are always negative and it also forms on the the same side of the lens as the object and is enlarged
In this equation, what shows that transmutation has taken place?
242 Cm – 328 Pu + He
A. There is conservation of both nucleons and atoms.
B. The nucleus of an atom changes
C. It involves more than one element
D. The number of atoms is conserved,but the number of nucleons is not
how does gravity affect objects of different mass close to earth, and how does that effect change as an object moves farther from earth?
Answer:
It makes it lighter when its closer and heavier when its farther way.
Explanation:
Types of telescope
for Space
observation
Answer:The three main types are reflecting telescopes, refracting telescopes, and catadioptric telescopes. Radio telescopes collect and focus radio waves from distant objects. Space telescopes orbit Earth, collecting wavelengths of light that are normally blocked by the atmosphere.
Answer:
oii me manda mensagem fofo vc tem namorada fofo
A student is giving a presentation to a class describing magnetic and electric fields in a region of space. First, the student describes what happens when there is a constant magnetic field in the region of space. Then, the student describes what happens when there is a time-dependent magnetic field in the region of space. Which of the following a correct description by the student abo what occurs when the magnetic field changes from being constant to being time dependent?
a. When the magnetic field is constant, there is only a magnetic field in the region of space. When the magnetic field is time dependent, there will be both a magnetic field and an electric field in the region of space.
b. When the magnetic field is constant, there will be both a magnetic field and an electric field in the region of space. When the magnetic field is time dependent, there is only a magnetic field in the region of space.
с. In both situations, there will be both a magnetic field and an electric field in the region of space. In both situations, there will only be a magnetic field in the region of space. If the magnetic field is not constant over the region, then there will be both a magnetic field and an electric field in the region of space
d. In both situations there will only be a magnetic field in the region of space. If the magnetic field is not constant over the region, there will still be only a magnetic field in the region of space.
Answer:
a. When the magnetic field is constant, there is only a magnetic field in the region of space. When the magnetic field is time dependent, there will be both a magnetic field and an electric field in the region of space.
Explanation:
This is true because according to Maxwell's equation, a time dependent magnetic field produces an electric field.
When the magnetic field is constant, there is no electric field in that region of space. But, when it begins to vary, an electric field is then generated by Maxwell's equation which is given by
CurlE = -dB/dt
So, there is initially no electric field when the magnetic field is constant, but it exists when the magnetic field becomes time dependent.
So when dB/dt = 0
CurlE = 0 ⇒ E = 0
So when dB/dt ≠ 0
CurlE ≠ 0 ⇒ E ≠ 0
A football is thrown down off of a building with a force of 70
Newtons. Gravity is pulling down the football with a force of
19 Newtons. What is the net force on the football?
Answer:
89 N downward.
Explanation:
Both forces are working in the same direction -- down.
Therefore you can add them together.
F = F1 + F2
F is the total force
F1 is the gravitational force
F2 is the force the person provides
F1 = 19
F2 = 70
F = ?
F = 19 + 70
F = 89 Newtons downward.
Answer:
wE dONt taLk aBt brunooooOoooOoOo ;')
Explanation:
Which of the following should a warm up NOT include?
Select one:
A. A few minutes of cardiovascular exercise
B. A light version of the exercise you will be performing
C. Intense stretching
D. All of the above should be included in a warm up
Which point has more gravitational potential energy?
How is the energy changing in the picture
What makes astronomers think that impact rates for the Moon must have been higher earlier than 3.8 billion years ago?
Answer: See explanation
Explanation:
The reason why astronomers think that the rates of impact for the Moon must have been higher earlier than 3.8 billion years ago is because on the older highlands, there are ten times more craters than on the younger maria.
It is believed that the impact rate was higher earlier and thus can be seen when the numbers of the craters that can be seen on the lunar highlands is being compared to that on the maria. It should be noted that there are about 10 times more craters that can be found on the highlands than those on the maria.
If there was a constant rate of impact throughout the history of the Moon, then the highlands be about 10 times older and therefore will have been formed about 38 billion years ago.