Ralph has a cylindrical container of parmesan cheese. The diameter of the base of the container is 2.75 inches, and the height is 6 inches. What is the area of a horizontal cross section of the cylinder to the nearest tenth of a square inch?

Answers

Answer 1

Answer:

The solution is given below:

Step-by-step explanation:

The computation of the area of the horizontal cross section of the cyclinder is given below:

In the case when it is a circle

The area of the circle is

= πr^2

= 3.14 × (2.75 ÷ 2)^2

= 11.873 inches^2

In the case when it is a rectangle

The area of the rectangle is

= 6 × 2.75

= 16.5 inches^2

Hence, the above show the calculations

Answer 2

The area of the horizontal cross section.

When circular is [tex]11.873 inches^2[/tex]

When it is rectangular [tex]16.5inches^2[/tex]

The computation of the area of the horizontal cross section of the cylinder

What is the formula of the area of the circle?

The area of the circle is[tex]=\pi r^{2}[/tex]

use the given value in above formula we get,

[tex]= 3.14 \times (\frac{2.75}{2} )^2[/tex]

[tex]= 11.873 inches^2[/tex]

when it is a rectangle then the area of the rectangle is

[tex]= 6 \times 2.75[/tex]

[tex]= 16.5 inches^2[/tex]

Therefore,the area of the horizontal cross section.

when circular is [tex]11.873 inches^2[/tex]

When it is rectangular [tex]16.5inches^2[/tex]

To learn more about the area of the cross section visit:

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Answer:

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Step-by-step explanation:

Answer:

[tex]\boxed {\boxed {\sf 2 \ hours}}[/tex]

Step-by-step explanation:

Let's set up a proportion to solve. Use the following setup:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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