Solution :
When non volatile solute is added to solvent, vapor pressure gets lowered.
Relative lowering in vapor pressure is given :
[tex]$\frac{P^0-P}{P^0}$[/tex] = [tex]$\text{mole fraction}$[/tex] of solute
[tex]$\frac{P^0-P}{P^0}=x_B$[/tex]
[tex]$P^0$[/tex] = vapor pressure of pure solvent
P = vapor pressure of solution
[tex]$x_B$[/tex] = mole fraction of solute
[tex]$x_B=\frac{n_B}{n_A+n_B}$[/tex]
[tex]$n_B $[/tex] = [tex]$\text{number of moles of solute}$[/tex]
[tex]$n_A$[/tex] = [tex]$\text{number of moles of solvent}$[/tex]
Number of moles [tex]$=\frac{\text{weight}}{\text{molecular weight}}$[/tex]
[tex]$\frac{P^0-P}{P^0}=\frac{w_B/M_B}{w_A/M_A+w_B/M_B}$[/tex]
[tex]$\approx \frac{w_B/M_B}{w_A/M_A}$[/tex]
1. For 10 g of [tex]$CH_3COOK$[/tex]
[tex]$CH_3COOK \rightarrow CH_3COO^- + K^+$[/tex]
Ions = 2
It will affect colligative property.
[tex]$\frac{P^0-P}{P^0} = \frac{i \times 10/98}{w_A/M_A}$[/tex]
Relative lowering in vapor pressure will be :
[tex]$=\frac{2 \times 10/98}{w_A/M_A}$[/tex]
[tex]$=\frac{0.20}{w_A/M_A}$[/tex]
2. For 20 g sucrose
Sucrose is non electrolyte, i = 1
[tex]$\frac{P^0-P}{P^0} = \frac{ 20/342}{w_A/M_A}$[/tex]
[tex]$=\frac{0.050}{w_A/M_A}$[/tex]
3. For 20 g of glucose.
Glucose is a non electrolyte, i = 1
[tex]$\frac{P^0-P}{P^0} = \frac{20/180}{w_A/M_A}$[/tex]
[tex]$=\frac{0.11}{w_A/M_A}$[/tex]
[tex]$w_A/M_A$[/tex] is same in all three solutions.
Hence, lowering in vapor pressure is maximum in [tex]$CH_3COOK$[/tex] and minimum is Sucrose.
Vapor pressure from lowest to highest.
10 g of [tex]$CH_3COOK$[/tex] < 20 g of glucose < 20 g of sucrose
The pressure exerted by vapor to the other gas is called vapor pressure.
The formula used to solve the question is as follows:-
[tex]\frac{P^o -P}{P^o}[/tex]
The water vapor depends on the following:-
Water pressureTemperature.After solving the equation, the correct sequence is as follows:-
[tex]CH_3COOK > GLUCOSE > SUCROSE[/tex]
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A chemistry student heated 2.255 g of oxygen gas in the presence of 5.145
Answer:
a
Explanation:
How do I turn on a Girl???
Answer:
7 Ways to turn a woman on. ...
Ask her what she likes, and do your homework. ...
Know the three parts of foreplay. ...
Be creative: Not all women are the same. ...
Know her body. ...
Help her feel comfortable receiving oral sex. ...
Play with lube or toys. ...
Remember that great sex won't happen overnight.
Explanation:
Answer: Ask her what she likes, and do your homework. ...
Know the three parts of foreplay. ...
Be creative: Not all women are the same.
Hope this helps
How many stoms of oxygen in 4 molecules of HNO,?
Answer: the answer is a
To achieve the highest return during recrystallization of a given solid, one must: Group of answer choices Add the minimum amount of boiling solvent necessary to dissolve the solid to be crystallized. Add an excess amount of cold solvent necessary to dissolve the solid to be crystallized. Add the minimum amount of cold solvent necessary to dissolve the solid to be crystallized. Add an excess amount of boiling solvent necessary to dissolve the solid to be crystallized.
Answer:
Option A
Explanation:
Addition of too much of solvent will make the solution dilute due to which the crystals will not form. Hence option D is incorrect
On the other hand adding a minimum amount of boiling solvent will give a saturated solution for recrystallization. Hence, option A is incorrect
Addition of cold solvent will lower the rate of formation of crystals. Hence, both option B and C are incorrect
how real gases differ from ideal gases?
An ideal gas is one that follows the gas laws at all conditions of temperature and pressure. To do so, the gas would need to completely abide by the kinetic-molecular theory. On the other hand, a real gas is a gas that does not behave according to the assumptions of the kinetic-molecular theory.
Furthermore, the particles of an ideal gas are extremely small and have a mass equivalent to practically zero. Ideal gas particles also have no volume.
An example of a real gas is helium, oxygen, and nitrogen.
What happens to the entropy when a solution is made?
A. The entropy increases.
B. The entropy decreases.
C. The entropy goes to zero.
D. The entropy is unaffected.
Answer:
The entropy increases
Explanation:
Just took the quiz
What is the mass in grams of 7.5 mol of C8H18?
Answer:
[tex]\boxed {\boxed {\sf 856.74 \ g \ C_8H _{18}}}[/tex]
Explanation:
To convert from grams to moles, the molar mass is used. These values tells us the grams in 1 mole of a substance. They can be found on the Periodic Table (they are equivalent to the atomic masses, but the units are grams per mole).
We are given the compound C₈H₁₈. Look up the molar masses of the individual elements.
Carbon (C): 12.011 g/mol Hydrogen (H): 1.008 g/molNotice there are subscripts that tell us the number of atoms of each element. We must multiply the molar masses by the subscripts.
C₈: 8(12.011 g/mol)=96.088 g/mol H₁₈: 18(1.008 g/mol)=18.144 g/molAdd these 2 values together to find the molar mass of the whole compound.
C₈H₁₈: 96.088 g/mol +18.144 g/mol=114.232 g/molUse this number as a ratio.
[tex]\frac{ 114.232 \ g \ C_8H_{18}}{1 \ mol \ C_8H_{18}}[/tex]
Multiply by the given number of moles: 7.5
[tex]7.5 \ mol \ C_8H_{18}*\frac{ 114.232 \ g \ C_8H_{18}}{1 \ mol \ C_8H_{18}}[/tex]
The moles of C₈H₁₈ will cancel each other out.
[tex]7.5 *\frac{ 114.232 \ g \ C_8H_{18}}{1}[/tex]
[tex]7.5 *{ 114.232 \ g \ C_8H_{18}}[/tex]
[tex]856.74 \ g \ C_8H _{18}[/tex]
7.5 moles of C₈H₁₈ is equal to 856.74 grams of C₈H₁₈
How many liters of 3.6 M solution can be made using 110 grams of
lithium bromide (LiBr)?
Answer:
0.2878 liters
Explanation:
It is possible to make 0.2878 liters of 4 M solution of lithium bromide using 100 grams of the compound.
Is water an acid, base, or neutral?
How many liters of solvent are are required to make a 5.34 M solution using 12.52
mol of solute?
How do children use food molecules to grow taller?
Options
A - Children grow taller when they use food molecules they eat to build large molecules that make up new cells.
B - Children grow taller when they use the food molecules they eat to make up new cells without changing the food molecules.
C - Children grow taller when they use the energy from the food molecules, but all of the molecules leave the body as waste.
D- Children grow taller when they store food molecules as fat.
A or B or C Or D ?
Answer:
C) Children grow taller when they use the energy from the food molecule, but all of the molecules leave the body as waste.
hope it helps.
Answer:
C - Children grow taller when they use the energy from the food molecules, but all of the molecules leave the body as waste.
hope it is helpful to you ☺️☺️☺️☺️
1 point
Marlene sits in a roller coaster that is at the top of a 72 m hill. Marlene and
the rollercoaster have a combined mass of 120 kg. Calculate the energy.
829,785 J
311,080J
84,672 J
O 42,336 J
Answer:
84672 J
Explanation:
From the question given above, the following data were obtained:
Height (h) = 72 m
Combined mass (m) = 120 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Energy (E) =?
We can obtain the energy by using the following formula:
E = mgh
Where
E => is the energy.
g => is the acceleration due to gravity
m => is the mass.
h => is the height.
E = 120 × 9.8 × 72
E = 84672 J
Thus, the energy is 84672 J
how many moles of lithium are in 18.2 grams of lithium
Answer:
I think 2.6 sorry if its wrong
The number of moles of 18.3 grams of lithium is equal to 2.62 mol.
What is a mole?A mole can be defined as a metric unit that is used to evaluate a count of particles in the sample of a given substance. The particles counted are generally identical chemical entities, but they are individually distinct.
A mole is used for a large number of quantities of molecules, atoms, ions, or other specific particles. The number of chemical compounds or elements can be measured in the terms of moles.
The number of units of the chemical which are present in 1 mole is equal to 6.023 × 10 ²³ refers to Avogadro’s constant.
Given, the mass of lithium in the sample = 18.2 g
The mass of one mole of lithium = 6.94 g
6.94 grams of lithium has moles = 1 mol
18.2 g of lithium has moles of Li = 18.2/6.94 = 2.62 mol
Therefore, the moles in 18.2 g of Lithium is 2.62 mol.
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Laughing gas can decompose into nitrogen and oxygen
Nitrous oxide decomposes into nitrogen and oxygen, according to 2 N2O (g) -> 2 N2 (g) + O2 (g). ... In an experiment, a stream of N2O is passed through a tube 25 mm in diameter and 20 cm long. The flow rate of the gas is 0.75 L/min.
HOW MANY MOLES OF CS2 FORMS WHEN 2.7 MOLE C REACTS
Which is a LIMIT that authors telling stories using aural media, such as radio plays, must deal with?
A. listeners can hear how each actor says lines of dialogue
B. sound effects can enhance the story's action
C. music can reinforce the story's emotional moments
D. characters thoughts and feelings must be spoken aloud
A sample of polonium-210 has an initial mass of 390 milligrams (mg). If the half-life of polonium-210 is 36 days, how many mg of the sample remains after 72 days?
A.
392 mg
B.
195 mg
C.
97.5 mg
D.
48.75 mg
Answer: D. 48.75
Explanation: just took the test
Answer:
D
Explanation:
I got this question right on my test.
22. Radon has a half-life of 3.83 days. How long will it take a 225 g sample to decay to 14.06 g? (3pts.)
What’s the answer
Answer:
15.32 days
Explanation:
From the question given above, the following data were obtained:
Half-life (t½) = 3.83 days
Original amount (N₀) = 225 g
Amount remaining (N) = 14.06 g
Time (t) =.?
Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:
Original amount (N₀) = 225 g
Amount remaining (N) = 14.06 g
Number of half-lives (n) =?
N = N₀ / 2ⁿ
14.06 = 225 / 2ⁿ
Cross multiply
14.06 × 2ⁿ = 225
Divide both side by 14.06
2ⁿ = 225 / 14.06
2ⁿ = 16
Express 16 in index form with 2 as the base
2ⁿ = 2⁴
n = 4
Thus, 4 half-lives has elapsed.
Finally, we shall determine the time. This can be obtained as follow:
Half-life (t½) = 3.83 days
Number of half-lives (n) = 4
Time (t) =.?
n = t / t½
4 = t / 3.83
Cross multiply
t = 4 × 3.83
t = 15.32 days
Therefore the time for 225 g sample of Radon to decay to 14.06 g is 15.32 days
At a pressure of 1.76 atm and 305 K, a certain gas has a volume of 350.0 mL. What will be the new volume of this gas under STP.
Answer:
hi
Explanation:
I'm just figuring this out
करताह!
गर्मियों में घड़े का जल ठंडा क्यों होता है?
Answer:
I don't understand the question
Explanation:
what is your name
What is the mass of 7.004 x 1023 molecules of calcium chloride?
Answer:
Bubv amp hindi marunong amp
Using the balanced reaction below, answer the following question:
2 Al + 3 ZnCl2 → 3 Zn + 2 AlCl3
How many moles of ZnCl2 are needed to react when 1.75 moles of AlCl3 form?
Answer:
Calculate the number of grams of AlCl3 produced from 2.5 moles of Cl2. The reaction between H2 and O2 produced 31.0 g of water. How many grams of O2 reacted?
Explanation:
Which statement describes the best way to determine how different levels of light affect the growth of seedling plants?
Choose three different light levels, and place four identical plants under each light level to observe the light’s effect on multiple plants.
Choose five different light levels, and place one identical plant under each of the light levels for exactly one week.
Choose four different light levels, and place eight different plant types under the light levels, two under each one, and observe them every day.
Choose one type of light and one type of plant, and then observe the plant for at least four weeks, measuring it each day.
Answer:
Choose three different light levels, and place four identical plants under each light level to observe the light’s effect on multiple plants.
Explanation:
A mixture of He, Ar, and Xe has a total pressure of 2.40 atm. The partial pressure of He is 0.300 atm, and the partial pressure of Ar is 0.250 atm. What is the partial pressure of Xe?
Express your answer to three significant figures and include the appropriate units.
The partial pressure of Xe in the mixture is 1.850 atm. (partial pressure of Xe = Total pressure - Partial pressure of He - Partial pressure of Ar = 1.850 atm).
To find the partial pressure of Xe, we need to subtract the partial pressures of He and Ar from the total pressure.
Total pressure = partial pressure of He + partial pressure of Ar + partial pressure of Xe
Given:
Total pressure = 2.40 atm
Partial pressure of He = 0.300 atm
Partial pressure of Ar = 0.250 atm
Let's solve for the partial pressure of Xe:
Partial pressure of Xe = Total pressure - Partial pressure of He - Partial pressure of Ar
Partial pressure of Xe = 2.40 atm - 0.300 atm - 0.250 atm
Partial pressure of Xe = 1.850 atm
Therefore, the partial pressure of Xe in the mixture is 1.850 atm.
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FeCI2 + Na2CO3 = FeCO3 + NaCI Balance this equation please
No links
FeCl2 + Na2CO3 = FeCO3 + 2NaCl
Becky wants to model an ecosystem. Which of the following modeling tools would best help her illustrate an ecosystem?
A.
a rubber ball
B.
a terrarium
C.
a map
D.
a set of building blocks
Answer:
c
Explanation:
When elemental sodium reacts with water, sodium hydroxide and hydrogen will form. What mass of sodium (in grams) must be reacted with excess water to produce 325 mL of hydrogen gas at 25.0oC and 1.15 atm?
Answer:
0.703g Na must reacted
Explanation:
The reaction of Sodium, Na, With water, H₂O is:
2Na(s) + 2H₂O(l) → 2NaOH(aq) + H₂(g)
Where 2 moles of sodium reacts with an excess of water to produce 1 mole of hydrogen
To solve this question we have to use PV = nTR to solve the moles of the gas. With the moles of hydrogen we can find the moles of sodium that reacted and its mass:
Moles H₂:
PV = nRT
PV /RT = n
Where P is pressure = 1.15atm
V is volume in liters = 0.325L
R is gas constant = 0.082atmL/molK
T is absolute temperature = 25°C + 273 = 298.0K
1.15atm*0.325L / 0.082atmL/molK*298.0K = n
0.0153 moles of hydrogen are produced
Moles Na:
0.0153 moles H₂ * (2moles Na / 1mol H₂) = 0.0306 moles Na
Mass Na -Molar mass: 22.99g/mol-:
0.0306 moles Na * (22.99g / mol) =
0.703g Na must reactedIf 36.0 g of NaOH (MM = 40.00 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the concentration of NaOH in the resulting solution
Answer:
Molarity of NaOH = 1.8 M.
Explanation:
From the question given above, the following data were obtained:
Mass of NaOH = 36 g
Molar mass of NaOH = 40 g/mol
Volume = 500 mL
Molarity of NaOH =?
Next, we shall determine the number of mole in 36 g of NaOH. This can be obtained as follow:
Mass of NaOH = 36 g
Molar mass of NaOH = 40 g/mol
Mole of NaOH =?
Mole = mass / molar mass
Mole of NaOH = 36 / 40
Mole of NaOH = 0.9 mole
Next, we shall convert 500 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
500 mL = 500 mL × 1 L / 1000 mL
500 mL = 0.5 L
Finally, we shall determine the molarity of NaOH. This can be obtained as follow:
Mole of NaOH = 0.9 mole
Volume = 0.5 L
Molarity of NaOH =?
Molarity = mole / Volume
Molarity of NaOH = 0.9 / 0.5
Molarity of NaOH = 1.8 M
Consider pure water separated from an aqueous sugar solution by a semipermeable membrane, which allows water to pass freely but not sugar. After some time has passed, the concentration of sugar solution: a. will have decreased b. will be the same on both sides of the membrane c. might have increased or decreased depending on other factors d. will not have changed e. will have increased
Answer:
it will be the same on both sides of the membrane
When the pure water is separated from the aqueous sugar solution when the sugar cannot pass through the semipermeable membrane. So the water moves through the membrane to the sugar solution. Therefore, the concentration of sugar solution will be decreased.
What is osmosis?Osmosis can be described as the spontaneous net movement or diffusion of solvent molecules through a permeable membrane from a region of lower solute concentration to a higher solute concentration in a direction that tends to balance the solute concentrations on both sides.
A physical process in which any solvent moves across a selectively permeable membrane separating two solutions of different concentrations.
Osmotic pressure can be described as the external pressure needed to be applied so that there is no net movement of a solvent across the membrane. Osmotic pressure can be defined as a colligative property because it depends on the molar concentration of the solute but not on its identity.
Therefore, option (A) is correct.
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4. Calculate the final temperature of 75.4 g water originally at 12.6 °C after it absorbs 3.85 kcal
of heat.
Answer:
63.7 °C
Explanation:
Step 1: Given and required data
Mass of water (m): 75.4 gInitial temperature (T₁): 12.6 °CAbsorbed heat (Q): 3.85 kcalSpecific heat capacity of water (c): 1 cal/g.°CStep 2: Calculate the final temperature of the water (T₂)
We will use the following expression.
Q = c × m × (T₂ - T₁)
T₂ = Q/c × m + T₁
T₂ = 3.85 × 10³ cal/(1 cal/g.°C) × 75.4 g + 12.6 °C = 63.7 °C