Can anyone help me out
Answer:
14.49 people per square mile
Step-by-step explanation:
Divide to find the answer:
836,109/57,714 = 14.49
From the equation below, where is the center of the circle located and what is the radius?
(x – 4)2 + (y + 8)2 = 16
A) Center: (4, -8) Radius = 4
B) Center: (-4, 8) Radius = 4
C) Center: (4, -8) Radius = 16
D) Center: (-4, 8) Radius = 16
Answer:
B Center: (-4, 8) Radius = 4
Step-by-step explanation:
5% equals what fraction, in lowest terms?
Answer:
1/20
Step-by-step explanation:
According to G0ogle 5 percent equals 1/20 in lowest terms.
Answer:
5% equals 5/100 which is 1/20 in lowest terms.
Step-by-step explanation:
5% is basically equivalent to 5/100. 5/100 in lowest terms is 1/20 since you divide the numerator and denominator by 5.
I hope this helps, have a nice day.
Is the line a good fit for the data points plotted in the scatter plot below?
There are 50 pennies in a roll. If you have 150 rolls of pennies, how many pennies do you have?
Answer: 7500
Step-by-step explanation:
multiply 150 by 50
The scale on a map is 55 cm : 88 km.
If the distance between two cities is 5656 km, how far apart in cm are the two cities on the map?
Answer:
look at the picture i have sent
Answer:
The cities are 35 cm apart in map.
The scale on a map is 5 cm : 8 km.
Step-by-step explanation:
mrk me brainliest please
PLEASE HELP FAST WILL MARK BRAINLIEST PLEASEEE
Answer:
[tex]\frac{8x^{18} }{y^{2} }[/tex]
Step-by-step explanation:
Can someone help me please?
Slope : -2
y - intercept : 3
Equation : y = -2x+3
Answer:
Step-by-step explanation:
Slope: -0.5
Y-Intercept: 3
y = -0.5x+3
Which statement describes whether the function is continuous at x = 2?
O The function is continuous at x = 2 because f(2) exists.
O The function is continuous at x = 2 because lim f(x) exists.
X-2
The function is not continuous at x = 2 because f(2) does not exist.
The function is not continuous at x = 2 because lim f(x) does not equal f(2).
X-2
Answer: (b)
Step-by-step explanation:
Given
The function is given as
[tex]f(x)=\dfrac{x^2-12x+20}{x-2}[/tex]
Solving the function
[tex]f(x)=\dfrac{x^2-2x-10x+20}{x-2}\\\\f(x)=\dfrac{(x-2)(x-10)}{(x-2)}\\\\f(x)=x-10[/tex]
for [tex]x=2[/tex]
[tex]f(2)=2-10\\f(2)=-8[/tex]
The function is continuous at [tex]x=2[/tex] because [tex]\lim_{x \to 2} f(x)[/tex] exists.
If the limit exists at a point, then the function is continuous.
Answer:
on edge its fs not b or c
Step-by-step explanation:
PLEASE HELPP!!
An initial amount of money is placed in an account at an interest rate of 5% per year, compounded continuously. After five years, there is $3287.11 in the
account. Find the initial amount placed in the account. Round your answer to the nearest cent.
9514 1404 393
Answer:
$2560.00
Step-by-step explanation:
The account balance is given by the formula ...
A = Pe^(rt) . . . . principal P invested at rate r for t years
Filling in your numbers, we have ...
$3287.11 = Pe^(0.05·5)
P = $3287.11e^(-0.25) = $2560.00
The initial amount was $2560.00.
The price of a cell phone is usually $240 Ella mom buys one of these cell phones when the discount is 25 how much did Ella mom save?
Answer:
$60
Step-by-step explanation:
$240 = 100%
Discount = 25%
100% - 25% = 75%
75% as a decimal is 0.75
Multiply:
240(0.75) = 180
You could also do 3/4 of 240 because 0.75 is 3/4
To find out how much she saved, let's subtract the sale price from the original price:
240 - 180 = 60
Ella's mom saved $60 from the discount
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
How much is three times two
Answer:
the answer is 6.
Step-by-step explanation:
Answer:
6.
Step-by-step explanation:
3+3=6 = 2×3=6
you can do draw 3 circles 2 times and add it all together.
A store wants to have an end of year sale so they discount all prices by 35%. If you buy an item that originally sells for $80.00, how much are you paying for it after the discount?
Answer:
$52.00
Step-by-step explanation:
35% of $80
(35÷100) ×80
0.35× 80
$28.00
$80 -$28
$52.00
Consider the initial value problem my''+cy'+ky=F(t), y(0)=0, y'(0)=0, modeling the motion of a spring mass dashpot system initially at rest and subjected to an applied force F(t), where the unit of force is the Newton (N). Assume that m=2 kilograms, c=8 kilograms per second, k=80 Newtons per meter, and F(t)=20 sin(6t) Newtons.
1. Solve the initial value problem. y(t)=?
2. Determine the long term behavior of the system. Is lim as t goes to infinity of y(t)=0? If it is, enter zero. If not, enter a function that approximates y(t) for very large positive values of t. For very large positive values of t, y(t) is approximately.. ?
Answer:
Hence, the [tex]y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t))\end{array}[/tex] and approximately value of [tex]y(t)[/tex] is [tex]-0.844[/tex].
Given :
[tex]my''+cy'+ky=F(t), y(0)=0, y'(0)=0,[/tex]
Where [tex]m=2[/tex] kilograms
[tex]c=8[/tex] kilograms per second
[tex]k=80[/tex] Newtons per meter
[tex]F(t)=20\sin (6t)[/tex] Newtons
Explanation :
(1)
Solve the initial value problem. [tex]y(t)[/tex]
[tex]my''+cy'+ky=F(t), y(0)=0, y'(0)=0,[/tex]
[tex]\Rightarrow 2y''+8y'+80y=20\sin (6t)[/tex]
[tex]\Rightarrow y''+4y'+40y=10\sin (6t)[/tex]
Auxilary equations :[tex]F(t)=0[/tex]
[tex]\Rightarrow r^2+4r+40=0[/tex]
[tex]\Rightarrow r=\frac{-4\pm\sqrt{4^2-4\times 1\times 40}}{2\times 1}[/tex]
[tex]\Rightarrow r=\frac{-4\pm\sqrt{16-160}}{2}[/tex]
[tex]\Rightarrow r=\frac{-4\pm\sqrt{-144}}{2}[/tex]
[tex]\Rightarrow r=\frac{-4\pm12i}{2}[/tex]
[tex]\Rightarrow r=-2\pm6i[/tex]
The complementary solution is [tex]y_c=e^{-2t}\left(c_1\cos 6t+c_2\sin 6t\right)[/tex]
The particular Integral, [tex]y_p=\frac{1}{f(D)}F(t)[/tex]
[tex]y_{y} &=\frac{1}{D^{2}+4 D+40} 25 \sin (6 t) \\\\ y_{y} &=\frac{25}{-6^{2}+4 D+40} \sin (6 t) \quad\left(D^{2} \text { is replaced with }-6^{2}=-36\right) \\\\y_{y} &=\frac{25}{4 D+4} \sin (6 t) \\\\y_{y} &=\frac{25}{4(D+1)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4(D+1)(D-1)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4\left(D^{2}-1\right)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4(-36-1)} \sin (6 t) \\\\y_{y} &=-\frac{25}{148}(D-1) \sin (6 t) \\y_{y} &=-\frac{25}{148}\left(\frac{d}{d t} \sin (6 t)-\sin (6[/tex]
Hence the general solution is :[tex]y=y_c+y_p=e^{-2t}(c_1\cos 6t+c_2\sin 6t)-\frac{25}{148}(6\cos 6t-\sin 6t)[/tex]
Now we use given initial condition.
[tex]y(t) &=e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\\y(0) &=e^{-\alpha 0)}\left(c_{1} \cos (0)+c_{2} \sin (0)\right)-\frac{25}{148}(6 \cos (0)-\sin (0)) \\\\0 &=\left(c_{1}\right)-\frac{25}{148}(6) \\\\c_{1} &=\frac{75}{74} \\\\y(t) &=e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\[/tex]
[tex]y^{\prime}(t)=-2 e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)+e^{-2 t}\left(-6 c_{1} \sin 6 t+6 c_{2} \cos 6 t\right)-\frac{25}{148}(-36 \sin (6 t)-6 \cos (6 t)) \\\\y^{\prime}(0)=-2 e^{0}\left(c_{1} \cos 0+c_{2} \sin 0\right)+e^{0}\left(-6 c_{1} \sin 0+6 c_{2} \cos 0\right)-\frac{25}{148}(-36 \sin 0-6 \cos 0) \\\\0=-2\left(c_{1}\right)+\left(6 c_{2}\right)-\frac{25}{148}(-6) \\\\0=-2 c_{1}+6 c_{2}+\frac{75}{74} \\\\0=-2\left(\frac{75}{74}\right)+6 c_{2}+\frac{75}{74} \\\\[/tex][tex]\begin{array}{l}0=-\frac{150}{74}+6 c_{2}+\frac{75}{74} \\\\\frac{150}{74}-\frac{75}{74}=6 c_{2}\end{array}[/tex]
[tex]\begin{array}{l}c_{2}=\frac{25}{148}\\\\\text { Substitute } c_{1} \text { and } c_{2} \text { in } y(t) \text { . Then }\\\\y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t))\end{array}[/tex]
(2)
[tex]y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\y(t)=\left(\frac{75}{74} e^{-2 t} \cos 6 t+\frac{75}{148} e^{-2 t} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\y(t)=\frac{75}{74}\left(e^{-2 t}-1\right) \cos 6 t+\frac{25}{148}\left(3 e^{-2 t}+1\right) \sin 6 t \\\\|y(t)| \leq \frac{75}{74} e^{-2 t}-1|\cos 6 t|+\frac{25}{148}\left|3 e^{-2 t}+1\right||\sin 6 t| \\\\[/tex]
[tex]|y(t)| \leq \frac{75}{74}\left|e^{-2 t}-1\right|+\frac{25}{148}\left|3 e^{-2 t}+1\right| \\\\\lim _{t \rightarrow \infty} y(t) \leq \lim _{t \rightarrow \infty}\left\{\frac{75}{74}\left|e^{-2 t}-1\right|+\frac{25}{148}\left|3 e^{-2 t}+1\right|\right\} \\\\\lim _{t \rightarrow \infty} y(t)=\left\{\frac{75}{74}\left|\lim _{t \rightarrow \infty}\left(e^{-2 t}-1\right)\right|+\frac{25}{148}\left|\lim _{t \rightarrow \infty}\left(3 e^{-2 t}+1\right)\right|\right\} \\[/tex]
[tex]\lim _{t \rightarrow \infty} y(t)=\left\{\frac{75}{74}(-1)+\frac{25}{148}(1)\right\}=-\frac{75}{74}+\frac{25}{148}=-\frac{-150+25}{148}=-\frac{125}{148} \approx-0.844[/tex]
My faces are not all
congruent.
I contain 12 edges.
I contain 6 faces.
Answer:
its a rectangle
Step-by-step explanation:
which expression defines function h?
Answer:
[tex]h(x) = (\frac{f}{g})(x)[/tex]
Step-by-step explanation:
Given
[tex]f(x) = 3x^3 + 9x^2 -12x[/tex]
[tex]g(x) = x - 1[/tex]
[tex]h(x) = 3x^2 + 12x[/tex]
Required
What defines h(x)
Looking at the degree of f(x), g(x) and h(x), we have:
[tex]h(x) = (\frac{f}{g})(x)[/tex]
See proof
[tex]h(x) = (\frac{f}{g})(x)[/tex]
This gives:
[tex]h(x) = \frac{f(x)}{g(x)}[/tex]
[tex]h(x) = \frac{3x^3 + 9x^2 -12x}{x - 1}[/tex]
Factorize
[tex]h(x) = \frac{(3x^2 + 12x)(x - 1)}{x - 1}\\[/tex]
[tex]h(x) = 3x^2 + 12x[/tex]
Two friends are to meet at the library. Each independently and randomly selects an arrival time within the same one-hour period. Each agrees to wait a maximum of fifteen minutes for the other to arrive. What is the probability that they will meet
Answer:
The probability that they will meet is 0.4375
Step-by-step explanation:
Let A and B be two friends who choose to meet the same one-hour period.Since there are 60 minutes in an hour therefore n= 60
A can wait for 15 minutes
So the probability of A to meet is given by P(A)= (15/60)= 1/4
Similarly
B can wait for 15 minutes
So the probability of B to meet is given by P(B)= (15/60)= 1/4
The probability that A cannot meet is given by 1- P(A)= 1-1/4= 3/4
Similarly
The probability that B cannot meet is given by 1- P(B)= 1-1/4= 3/4
And
The probability that both A and B cannot meet is given by = 3/4*3/4= 9/16
So the probability that both will meet = 1- 9/16= 7/16= 0.4375
When you plug in 8 for m, what problem will you have to solve?
3+m
3+m=8
3+8
Please help! im extremely confused
the results of rolling a single die are shown in a table below. find the experimental probability of rolling a 5
number total
1 12
2 16
3 21
4 23
5 18
6 10
Answer:
1/12
Step-by-step explanation:
To find experimental probability you have to solve the Number of times an event occurs / Total number of trials. So since the 5 only appears once and there are 12 numbers, it would be 1/12. Did this help?
The experimental probability of rolling 5 will be 0.18.
What is probability?Its fundamental concept is that someone will nearly surely occur. The proportion of positive events in comparison to the total of occurrences. Then the probability is given as,
P = (Favorable event) / (Total event)
The table is given below:
Number Total
1 12
2 16
3 21
4 23
5 18
6 10
The experimental probability of rolling a 5 is calculated as,
P = 18 / (12 + 16 + 21 + 23 + 18 + 10)
P = 18 / 100
P = 0.18
Thus, the probability is 0.18.
More about the probability link is given below.
https://brainly.com/question/795909
#SPJ2
15) Find the product. Show all your work.
Reduce all your answers into simplest
form
3 - x
5
л |N
Answer:
[tex]\frac{3}{2}[/tex]
Step-by-step explanation:
3 [tex]\frac{3}{4}[/tex] x [tex]\frac{2}{5}[/tex]
[tex]\frac{15}{4}[/tex] x [tex]\frac{2}{5}[/tex]
[tex]\frac{30}{20}[/tex] = [tex]\frac{3}{2}[/tex]
or another way
[tex]\frac{15}{4}[/tex] x [tex]\frac{2}{5}[/tex]
[tex]\frac{3}{2}[/tex] x [tex]\frac{1}{1}[/tex] = [tex]\frac{3}{2}[/tex]
NEED HELP ASAP WILL GIVE BRAINLIEST REAL ANSWERS ONLY PLZ WILL REPORT FAKE ANSWERS
Answer:
The graph has a domain of {x|0 < x < infinite} and approaches 0 as x decreases
The graph has a domain of {y| -infinite < y < infinite} and decreases as x approaches 0.
Step-by-step explanation:
I was confused at first because I was like "There is 2 answers" and I reread the question again and found my mistake.
And sorry for the wait because "I am in class"
Simran has a bag containing white and yellow marbles. Simran randomly selects one marble from the bag,
records the result, and returns the marble to the bag. The results of the first 65 selections are shown below.
A white marble was selected 41 times.
A yellow marble was selected 24 times.
Based on these results, what is the probability that the next marble Simran selects, rounded to the nearest
Answer:
d. 63%
Step-by-step explanation:
percent, will be white?
A41% b50% c59% d63%
The probability of white = P (w) = 41/65= 0.63
The probability of yellow = P (y)= 24/65= 0.369=0.37
The probability of choosing white is 0.63 . When rounded to nearest percent gives
0.63*100/100
=0.63*100 percent
= 63 percent
= 63%
the probability of getting the next marble white is the same as the probability of getting a white.
This graph shows the altitude of an airplane over time. Which story matches the graph?
A.)The aircraft rose quickly into the air at takeoff, and then it continued at a constant altitude.
B.)The aircraft rose steadily over the entire flight.
C.)The aircraft rose quickly to its maximum height, and then it immediately began going back down toward the grou
D.)The aircraft rose quickly into the air at takeoff, and then it rose slowly for the rest of the flight.
SHOW HINT
Answer:
A.) The aircraft rose quickly into the air at takeoff, and then continued at a constant altitude.:)
Answer:
Omg, thank u so much I am on this question rn on Edulatic and I have 100 Q's and I'm only on Q 45, This Question rly helped me a lot bc it came with the answer. God Bless you!!
The first question
(Worth 10 points) please help
9514 1404 393
Answer:
C. 7
Step-by-step explanation:
To find the value of 2Ω3 using the definition of AΩB, we are replacing A with 2, and B with 3. This seems to give us ...
2Ω3 = 2² +3² -2·3 = 4 + 9 - 6 = 7
The value of 2Ω3 is 7.
The scatter chart below displays the residuals verses the dependent variable, x. Which of the following conclusions can be drawn based upon this scatter chart? a. The residuals are normally distributed. b. The model over predicts the value of the dependent variable for small values and large values of the independent variable. c. The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship. d. The residuals have a constant variance.
Answer: Hello the scatter plot related to your question is missing attached below is the scatter plot
answer : The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship ( C )
Step-by-step explanation:
The conclusion that can be drawn based upon the scatter chart is that The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship
A scatter plot helps in observing the relationship within different numeric variables but the scatter plot attached fails in the showing the actual relationship
The bottom of a ladder is placed 4 feet from the side of a building. The top of the ladder must be 13 feet off the ground.
What is the shortest ladder that will do the job? SHOW your work.
10 foot ladder
12 foot ladder
14 foot ladder
Answer:14
Step-by-step explanation:
1) A farmer has sheep and cattle in the ratio 8:3.
a) How many sheep has the farmer if he has 180 cattle?
b) Find the ratio of the number of sheep to the total number of animals.
c) Find the ratio of the total number of animals to the number of cattle.
2)My fortune of $ 810 000 is to be divided in the ratio 4:3:2. How much does each person receive?
Good
Answer:
Q 1)
a) No of sheep = 480
b) 8 : 11
c) 11 : 3
Q 2)
Each person will receive: $360,000, $270,000 and $180,000
Step-by-step explanation:
Ratio of sheep to cattle = 8 : 3
Let the number of sheep be 8x
And number of cattle be 3x
a)
No of cattle = 180 (Given)
Therefore,
3x = 180
x = 180/3
x = 60
Therefore, 8x = 8*60 = 480
No of sheep = 480
b)
Total animals = 180 + 480 = 660
Ratio of sheep to the total number of animals
= 480 : 660
= 8 : 11
c)
Ratio of total animals to the number of cattle
= 660 : 180
= 11 : 3
Q 2) Let each person will receive 4x, 3x and 2x dollars.
Therefore,
4x + 3x + 2x = 810,000
9x = 810000
x = 810000/9
x = 90,000
Therefore,
4x = 4*90,000 = $360,000
3x = 3*90,000 = $270,000
2x = 2*90,000 = $180,000
So, each person will receive $360,000, $270,000 and $180,000.
What is the degree measure of FEG?
A 20°
B 31°
C 56°
D
124°
Answer:
C) 56
Step-by-step explanation:
DEG and FEG are on a straight line forming 180 degree.
Set your formula up as
180 = (3x+31)+(2x-6)
180 = 3x +2x +31 - 6
180 - 31 + 6 = 5x
155 = 5x
155/5 = x
31 = x
Now substitute 31 in place of x
FEG = (2*31-6)
FEG = 56
Find the exact value of sin A in simplest radical form.
Using the sine rule,
[tex] \frac{a}{sin(a)} = \frac{b}{sin(b)} = \frac{c}{sin(c)} [/tex]
Here we are going to use the values of A and C,
[tex] \frac{12}{sin(a)} = \frac{14}{sin(90)} \\ \frac{12}{sin(a)} = \frac{14}{1} \\ sin(a) = 12 \div 14 \\ sin(a) = 0.8571[/tex]
So sin(A) = 12/14 = 6/7 = 0.8571, but since the question says in its simplest radical form, I think the closest answer to it should be
[tex] \frac{ \sqrt{3} }{2} [/tex]
The X and Y coordinates (in feet) for station Shore are 2058.97 and 6980.06, respectively, and those for station Rock are 1408.03 and 6980.06, respectively. What are the azimuth, bearing, and length of the line connecting station Shore to station Rock
Answer:
Hence, the azimuth, bearing, and length of the line connecting station Shore to station Rock are [tex]270^{\circ},90^{\circ}[/tex] and [tex]650.94[/tex] feet.
Given :
The shore station point [tex](X_1,Y_1)[/tex] in feet,
[tex](X_1,Y_1)=(2058.97, 6980.06)[/tex]
The Rock station point [tex](X_2,Y_2)[/tex] in feet
[tex](X_2,Y_2)=(1408.03,6980.06)[/tex]
From the figure
[tex]x=2058.97-1408.03=650.94[/tex] feet
[tex]y=6980.06-6980.06=0\\[/tex] feet
Length of the line [tex]L=\sqrt{x^2+y^2}[/tex]
[tex]\Rightarrow L=\sqrt{(650.94)^2+0}=650.94[/tex]
[tex]\Rightarrow L=650.94[/tex] feet
[tex]\because[/tex] [tex]\tan \theta=\frac{y}{x}=\frac{0}{x}=0[/tex]
[tex]\Rightarrow \theta=\tan^{-1}(0)=0[/tex]
Azimuth of line[tex]=270^{\circ}+\theta[/tex]
[tex]=270^{\circ}+0[/tex]
[tex]=270^{\circ}[/tex]
[tex]\therefore[/tex] Bearing [tex]=360^{\circ}-\text{Azimuth}[/tex]
[tex]=360^{\circ}-270^{\circ}[/tex]
[tex]=90^{\circ}[/tex]