Answer:
mass flow rate = 0.0534 kg/sec
velocity at exit = 29.34 m/sec
Explanation:
From the information given:
Inlet:
Temperature [tex]T_1 = -16^0\ C[/tex]
Quality [tex]x_1 = 0.2[/tex]
Outlet:
Temperature [tex]T_2 = -16^0 C[/tex]
Quality [tex]x_2 = 1[/tex]
The following data were obtained at saturation properties of R134a at the temperature of -16° C
[tex]v_f= 0.7428 \times 10^{-3} \ m^3/kg \\ \\ v_g = 0.1247 \ m^3 /kg[/tex]
[tex]v_1 = v_f + x_1 ( vg - ( v_f)) \\ \\ v_1 = 0.7428 \times 10^{-3} + 0.2 (0.1247 -(0.7428 \times 10^{-3})) \\ \\ v_1 = 0.0255 \ m^3/kg \\ \\ \\ v_2 = v_g = 0.1247 \ m^3/kg[/tex]
[tex]m = \rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ m = \dfrac{1}{0.0255} \times \dfrac{\pi}{4}\times (1.7 \times 10^{-2})^2\times 6 \\ \\ \mathbf{m = 0.0534 \ kg/sec}[/tex]
[tex]\rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ A_1 =A_2 \\ \\ \rho_1v_1 = \rho_2v_2 \\ \\ \implies \dfrac{1}{0.0255} \times6 = \dfrac{1}{0.1247}\times (v_2)\\ \\ \\\mathbf{\\ v_2 = 29.34 \ m/sec}[/tex]
In 1951, a small approach embankment was constructed for a highway bridge over a river south of Los Angeles. The embankment was underlain by 5 ft of organic clay. Records of the settlement rate indicate that 90% of the consolidation settlements occurred in the first 4.5 years after construction. A new bridge over the river is now planned for a site a few hundred yards from the old bridge. The approach embankment to the new bridge will be underlain by 20 ft of the same organic clay found at the old bridge site. Estimate the time required to achieve an average degree of consolidation of 90% under the new embankment. Assume single drainage from the organic clay at both sites..
Answer:
72 years
Explanation:
The degree of consideration is the same for both bridges = 90%
Height of first highway bridge( d1 ) = 5 ft
Time to consolidation ( t1 )= 4.5 years
Height of second bridge ( d2 ) = 20 ft
Time to consolidation ( t2 ) = ?
we will apply this relation below
Tv = Cv * t / d^v
Tv = constant
for a single drainage condition : t ∝ d^v hence; d = H
∴ [tex]\frac{t_{2} }{t_{1} } = (\frac{d_{2} }{d_{1} })[/tex]^2
t2 = t1 ( d2/d1 )^2
= 4.5 ( 20 / 5 )^2
= 72 years
Fig_Q5
6. A steel rod is stressed by a tension force of 250 N. It is found that the rod has length of 45
m and diameter of 1.5 mm. If the modulus of elasticity of the steel rod is assumed as 2 x 105
MPa, determine the strain of the steel rod due to the applied force.
Answer:
The strain of the steel rod due to the applied force is 41.93
Explanation:
Modulus of elasticity is equal to stress divided by strain.
And stress is equal to force divided by area
Surface area of cylindrical rod
[tex]2\pi r (r+h)[/tex]
Substituting the given values we get -
[tex]2 *3.14 * \frac{1.5}{1000} * 45 (45 + \frac{1.5}{1000}) = 19.07[/tex]
[tex]2 * 10 ^5 = \frac{250}{19.07 * S=(\frac{\Delta L}{L} )}[/tex]
Hence, strain is equal to
Strain = 41.93
In the production of soybean oil, dried and flaked soybeans are brought in contact with a solvent (often hexane) that extracts the oil and leaves behind the residual solids and a small amount of oil.
a. Draw flow diagram of the process, labeling the two feed streams (beans and solvent) and the leaving streams (solids and extract).
b. The soybeans contain 18.5 wt% oil and the remainder insoluble solids, and the hexane is fed at a rate corresponding to 2.0 kg hexane per kg beans. The residual solids leaving the extraction unit contain 35.0 wt% hexane, all of the non-oil solids that entered with beans, and 1.0% of the oil that entered the beans. For a feed rate of 1000 kg/h of dried flaked soybeans, calculate mass flow rates of extract and residual solids and the composition of extract.
Answer: its c
Explanation:
A 10 cm thick slab (density 8530 kg/m3 , specific heat 380J/kg K, conductivity 110 W/m K) initially at 650C is being cooled by air at 15C (convection coefficient 220 W/m2 K) at left surface. The right surface is insulated. We want to estimate temperature in the slab. a. What will be the temperature of the slab after a very long time
Answer:
The temperature after a long time will return to 15°C
Explanation:
Determine the temperature of the slab after a very long time
First we calculate the heat flow for m^2 area normal to the surface
= q / A = 650°c - 15°C / ( 1 / h + L / K )
= 635°c / ( 1 / 220 + 0.1 / 110 ) = 116.416 kw/m^2
Total heat content in the slab is calculated as
= m* c * ΔT
= 8530 * A * 0.1 * 380 * ( 650 - 15 )
= 205828.9 kJ/m^2
The temperature will return to 15°C after a long time
g Design of a spindle present in an existing design needs to be reviewed for use under new loading needs. It is currently designed to withstand combined torsional and compressive loading. The design team needs to determine what the maximum torque it can withstand before failing if a compressive, axial load of 15 kips is present. The ultimate compressive and tensile strengths of the material are 135 ksi and 40 ksi, respectively. Determine the torsional shear stress that will just cause failure using a non-conservative failure theory.
Answer: its c
Explanation:
Fill in the blank to output the quotient of dividing 100 by 42. print (100______42)
Answer:
print(100/42)
Explanation:
This is the operand for division in python and some other languages.
can someone please help me with this
I've an exams tomorrow
Answer:
I am in Eight Grade
Explanation:
Knowing that the central portion of the link BD has a uniform cross-sectional area of 800 2, determine the magnitude of the load P for which the normal stress in that portion of BD is 50 .
Answer: 50
Explanation:
Water from an upper tank is drained into a lower tank through a 5 cm diameter iron pipe with roughness 2 mm. The entrance to the pipe has minor loss coefficient 0.4 and the exit has minor loss coefficient of 1, both referenced to the velocity in the pipe. The water level of the upper tank is 4 m above the level of the lower tank, and the pipe is 5 m long. You will find the drainage volumetric flow rate. a) What is the relative roughness
Answer:
Relative roughness = 0.04
Explanation:
Given that:
Diameter = 5 cm
roughness = 2 mm
At inlet:
Minor coefficient loss [tex]k_{L1} = 0.4[/tex]
At exit:
Minor coefficient loss [tex]k_{L2} = 1[/tex]
Height h = 4m
Length = 5 m
To find the relative roughness:
Relative roughness is a term that is used to describe the set of irregularities that exist inside commercial pipes that transport fluids. The relative roughness can be evaluated by knowing the diameter of the pipe made with the absolute roughness in question. If we denote the absolute roughness as e and the diameter as D, the relative roughness is expressed as:
[tex]e_r = \dfrac{e}{D}[/tex]
[tex]e_r = \dfrac{0.2 }{5}[/tex]
[tex]\mathbf{e_r = 0.04}[/tex]
The ____ neurons allow the body to move and are greatly influenced by electri
A. compression
B. motor
C. positive
D. mobile
Answer:
the answer would be B motor
Explain what the engineering team should advise in the following scenario.
Situation: An engineering team is analyzing a problem with a dam near a large metropolitan area. The dam reservoir has a capacity of 300 billion cubic feet, and it produces hydroelectric power for local municipalities. The dam has developed a severe crack.
Answer: its c
Explanation:
2. (Problem 4.60 on main book, diameters different) Water flows steadily through a fire hose and nozzle. The hose is 35 mm diameter and the nozzle tip is 25 mm diameter; water gage pressure in the hose is 510 kPa, and the stream leaving the nozzle is uniform. The exit speed and pressure are 32 m/s and atmospheric, respectively. Find the force transmitted by the coupling between the nozzle and hose. Indicate whether the coupling is in tension or compression.
Answer:
coupling is in tension
Force = -244.81 N
Explanation:
Diameter of Hose ( D1 ) = 35 mm
Diameter of nozzle ( D2 ) = 25 mm
water gage pressure in hose = 510 kPa
stream leaving the nozzle is uniform
exit speed and pressure = 32 m/s and atmospheric
Determine the force transmitted by the coupling between the nozzle and hose
attached below is the remaining part of the detailed solution
Inlet velocity ( V1 ) = V2 ( D2/D1 )^2
= 32 ( 25 / 35 )^2
= 16.33 m/s
Define;
i) Voltage
ii) Current
iii) Electrical Power
iv) Electrical Energy
Answer:
I) Voltage - is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light. In brief, voltage = pressure, and it is measured in volts (V).
II) Current - is the movement of electrons through a wire. Electric current is measured in amperes (amps) and refers to the number of charges that move through the wire per second. If we want current to flow directly from one point to another, we should use a wire that has as little resistance as possible.
III) Electrical Power - is the rate, per unit time, at which electrical energy is transferred by an electric circuit. The SI unit of power is the watt, one joule per second. Electric power is usually produced by electric generators, but can also be supplied by sources such as electric batteries.
IV) Electrical Energy - is a form of energy resulting from the flow of electric charge. Energy is the ability to do work or apply force to move an object. In the case of electrical energy, the force is electrical attraction or repulsion between charged particles.
Explanation:
I hope ot helps to you a lot! Correct me if I'm wrong.
Which statements describe the motion of car A and car B? Check all that apply. Car A and car B are both moving toward the origin. Car A and car B are moving in opposite directions. Car A is moving faster than car B. Car A and car B started at the same location. Car A and car B are moving toward each other until they cross over.
Answer:
car a is moving faster than the car b
Answer:
B: Car A and car B are moving in opposite directions.
C: Car A is moving faster than car B.
E: Car A and car B are moving toward each other until they cross over.
Explanation:
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Combinations of velocity and acceleration
Answer:
acceleration=change in velocity/ time
Explanation:
The velocity of an object is its speed in a particular direction. Velocity is a vector quantity because it has both a magnitude and an associated direction. To calculate velocity, displacement is used in calculations, rather than distance.
Consider a convergent-
In warm climates, a vapor barrier is placed on the exterior side of the insulation, and in cold climates it is installed on the interior side of the
insulation. Which of the following explains this placement of the barrier?
The barrier should always be placed on the side opposite from where the water condenses.
The barrier should always be placed on the side opposite where rain or snow hit.
The barrier should always be placed on the side where rain or snow hit.
The barrier should always be placed on the side where the water condenses
Answer: its c
Explanation: