Round to 2 decimal places 0.966

Answer: 63 votes

Step-by-step explanation:

Simply multiply 81 by 7/9 to get the answer, 63 votes.

Hope it helps :) and let me know if you want me to elaborate.

63

Step-by-step explanation:

(7/9) x 81 = 63

I'm not good in math ok bye

A) Atra = 0.5 ( 7 + 3 ) x 3 = 15 cm^2

B) Atri1 = 1/2 x 3 x 2 = 3 cm^2

Atri2 = 1/2 x 3 x 2 = 3 cm^2

Arec = 3 x 3 = 9 cm^2

Atra = Atri1 + Atri2 +  Arec = 3 + 3 + 9 = 15 cm^2

ok done. Thank to me :>

Answer:

Square because the area of a square is length times width.

The formula matches with square.

A branch of mathematics that deals with the measurement, properties, and relationships of points, lines, angles, surfaces, and solids

As,

First, Area of circle  = πr²

Hence, it is not possible.

Second, square

Area of square = l * b = LW

Similarly for trapezium

Area= 1/2( a+ b)* h

Hence, the formula matches with square figure.

Learn more about geometry here:

https://brainly.com/question/12168921

#SPJ2

Answer:

Step-by-step explanation:

Answer: (3,9)

Step-by-step explanation:

They're asking which ordered pair [tex](x,y)[/tex] satisfies both equations when you plug in [tex]x[/tex] and [tex]y[/tex]. Well since you're plugging in the same [tex]y[/tex] to both equations, [tex]3x[/tex] should equal [tex]2x + 3[/tex] (think about it). And solving [tex]3x = 2x + 3[/tex] gives [tex]x = 3[/tex], so the answer is

[tex](x,y) = \boxed{(3, 9)}[/tex]

Answer:

I don't know..,.............,,.,.......,

Answer: 78 paperback books.

Step-by-step explanation:

1. Since 2/3 of the books are hardcover books, then 1/3 of the books are paperback books.

2. 234/3 = 78 books.

Answer:

78 paperback books

Step-by-step explanation:

234 x (2/3) = 156

234 - 156 = 78

Answer:

5

Step-by-step explanation:

yeah idek what you said I just need the points please write in English next time but I see something a about marginal

Answer:

We want the ith row of the new matrix SijA to be the old jth row of A, so we need the ith row of Sij to extract the jth entry of column of A.

This mean the ith row of Sij must have a 1 in the jth entry and 0's everywhere else.

Similarly, the jth row of Sij must have a 1 in the ith entry and 0's everywhere else.

in the piecewise notation this is

(Sij)kl ={1 if k=i and l=j, 1 if k=k and l=i; 1 if k=l but k#i,j, 0 otherwise

Step-by-step explanation:

Answer:

1162.0356

Step-by-step explanation:

Answer:

with what?

Step-by-step explanation:

I think you forgot to attach something.

Answer:

11

Step-by-step explanation:

2x + x + x + 13 = 57

4x + 13 = 57

4x = 57-13

4x = 44

44/4 = 11

x = 11

Answer:

10% 0f 70 is 7

Step-by-step explanation:

70÷10=7

10%=7

Answer:

(6,0) (-6,0)

Step-by-step explanation:

sorry kung mali pero sana makahelp

Answer:

l = P -2w

________ D is the correct choice

2

If you subtract 3x from both sides of that equation, you'll go from

3x+4 = 3x+3

to

4 = 3

which is a false statement. No matter what you plug in for x, the original equation is always false as well. This is why it has no solutions.

Answer:

195, 295, 395, 495?

Step-by-step explanation:

Answer:

Step-by-step explanation:

Average = (Ymax + Ymin)/2 = (4 + (- 2))/ 2  = 1

Amplitude =  (Ymax - Ymin)/2 = (4 - (- 2))/ 2  = 3

y is at a maximum when x = 0, so cosine function is easy.

one cycle (2π radians) is completed in 2π/3

therefore

y = 1 + 3cos(2π(x /(2π/3))

y = 1 + 3cos(3x)

Answer(s):

[tex]\displaystyle y = 3sin\:(3x + \frac{\pi}{2}) + 1 \\ y = 3cos\:3x + 1[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{6}} \hookrightarrow \frac{-\frac{\pi}{2}}{3} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 3[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 3[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 3sin\:3x + 1,[/tex]in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{6}\:unit[/tex]to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{6}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{6}} = \frac{-\frac{\pi}{2}}{3}.[/tex]So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 3sin\:(3x + \frac{\pi}{2}) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-\frac{2}{9}\pi, -\frac{1}{2}],[/tex]from there to [tex]\displaystyle [\frac{4}{9}\pi, -\frac{1}{2}],[/tex]they are obviously [tex]\displaystyle \frac{2}{3}\pi\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \frac{2}{3}\pi.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Two systems of equations are equivalent if they have they have the same solution/solutions.

I hope that the attachment helps you..

Answer:

x=68 and y = 112

Step-by-step explanation:

angles of a triangle must equal 180, so

52°+60°+x°=180

112+x=180 <-- subtract 112 to get x on one side.

x=68

To solve for y, a straight line = 180 so

68+y=180 --> just subtract 180-68

y=112

Step-by-step explanation:

jam : sugar : cheese = 4 : 1 : 16

that means she uses 4 times more jam than sugar, and 16 times more cheese than sugar (and therefore 4 times more cheese than jam).

so, now we know, she uses 32 oz of cheese.

that is (as we just determined) 4 times more than jam.

therefore, she uses

32/4 = 8 oz of jam.

1 oz = 28.3 grams

so, 8 oz are

8 × 28.3 = 226.4 grams

Answer:

14,17, 20

Step-by-step explanation:

Kindly see the picture I have solved it as required

9514 1404 393

Answer:

  C.  $166.50

Step-by-step explanation:

The rate Sara pays for parking is ...

  $10.50/(3 hours) = $3.50 /hour

So, Sara's net pay, after paying for parking, is ...

  $12.75/hour - 3.50/hour = $9.25 /hour

If she works 18 hours per week, her net earnings are ...

  (18 h)($9.25/h) = $166.50 . . . . weekly earnings

Answer:

Commutative Property of Addition

Step-by-step explanation:

This is because the commutative property of addition and multiplication is

[tex]a+b=b+a\\a*b=b*a[/tex]

and as an example

[tex]5+9=14 \\9+5=14\\10*6=60\\6*10=60[/tex]