RS is a chord of circle P, and TU is a chord of circle Q. Circle P is congruent to circle Q.Which statement cannot be verified from the information that is given?If RS TU, then RS = TU.RIf RS TU, then RS - TQ.If RS = TU, then RS = TU.If RS TU, then RS = TU.
Answers
The proposition that can not be verified using the given information is
[tex]If\text{ }\hat{\text{RS}}\cong\hat{TV,}\text{ then }\bar{\text{RS}}\cong\bar{TQ}[/tex]Because there is no result (regarding chords) relating a chord that doesn't go through the center Q with a chord going through it. Look at the conclusion of the proposition
[tex]\bar{RS}\cong\bar{TQ}[/tex]RS doesn't go through Q, and TQ does it.
Related Questions
A system of equations is created by using the line represented by 2x+4y= 0 and the line represented by the data in the table below. x -1 3 5 6 у 8 -1 3 5 -10 6 -13 What is the x-value of the solution to the system?
Answers
To find what we are looking for we first need to find the second equation.
To do this we need to use the equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]where (x1,y1) is a point on the line and m is the slope. The slope of a line is given by:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Using the first two points on the table we get:
[tex]\begin{gathered} m=\frac{-4-8}{3-(-1)} \\ =\frac{-12}{4} \\ =-3 \end{gathered}[/tex]Now that we have the slope we plug it in the equation of a line with the values of any of the points in the table (we are going to use the first one). Then:
[tex]\begin{gathered} y-8=-3(x-(-1)) \\ y-8=-3(x+1) \\ y-8=-3x-3 \\ 3x+y=5 \end{gathered}[/tex]Now that we have the equation of the second line we conclude that we have the system of equations:
[tex]\begin{gathered} 2x+4y=0 \\ 3x+y=5 \end{gathered}[/tex]To find the x value of the solution we solve the second equation for y, then:
[tex]y=5-3x[/tex]now we plug this value into the first equation and solve for x:
[tex]\begin{gathered} 2x+4(5-3x)=0 \\ 2x+20-12x=0 \\ -10x=-20 \\ x=\frac{-20}{-10} \\ x=2 \end{gathered}[/tex]Therefore, the x value of the solution of the system is 2.
Jose bought a 20-pound bag of food for his dog. He fed his dog one-half of a pound of dog food each day. Which equation is used to determine, y, the amount of dog food that remains at the end of each day, x? Ay= 20 – 0.52 B.y= 20 + 0.51 cy= 200 – 0.5 Dy=202 + 0.5 Copyrig y
Answers
ok
y = amount of food dog that remains
x days
y = 20 - 0.5x This is the answer, It is letter
2.- slope = ((-100 - 160) / (4 - 8)
= -260 / -4
= 65 the answer is the third option
In January, Joanna deposited $250into her savings account. InFebruary, she deposited anadditional $100. If her account hasan APR of 6% compounded monthly,how much interest did Joanna earnin the first two months?
Answers
Given:
In January Joanna deposited $250 into her savings account.
In February, she deposited an additional $100.
Her account has an APR of 6% compounded monthly.
Required:
We have to find how much interest did Joanna earn in the first two months.
Explanation:
For the month of January:
[tex]A=P(1+\frac{r}{100})^n[/tex]Here, P=$250, r=6%, amd n= 1 month=1/12 year.
Then,
[tex]\begin{gathered} A=250(1+\frac{6}{100})^{\frac{1}{12}} \\ \\ A=250(\frac{106}{100})^{\frac{1}{12}} \end{gathered}[/tex][tex]\begin{gathered} A=250\times1.005 \\ A=\text{ \$}251.25 \end{gathered}[/tex]Then the interest is
[tex]I=A-P=251.25-250=\text{ \$}1.25[/tex]For the month of February:
P=251.24+100=351.25
Then we have
[tex]\begin{gathered} A=351.25(1+\frac{6}{100})^{\frac{1}{12}} \\ \\ A=351.25(\frac{106}{100})^{\frac{1}{12}} \end{gathered}[/tex][tex]\begin{gathered} A=351.5\times1.005 \\ A=\text{ \$}353.01 \end{gathered}[/tex]Then the interest is
[tex]A=P-I=353.01-351.25=\text{ \$}1.76[/tex]Therefore, the total interest is
[tex]1.25+1.76=\text{ \$}3.01[/tex]Final answer:
Hence the final answer is
[tex]\text{ \$}3.01[/tex]
Solve the compound inequality X-3 <5
Answers
x < 8
Explanations:The inequality is:
x - 3 < 5
Add 3 to both sides of the inequality
x - 3 + 3 < 5 + 3
Note: -3 + 3 = 0
x + 0 < 8
x < 8
1.Liz buys three apples, a dozen bananas, and one cantaloupe for $2.36. Bob buys a dozen apples and two cantaloupe for $5.26. Carol buys two bananas and three cantaloupe for $2.77. How much do single pieces of each fruit cost?
Answers
ANSWER
• Apple = $0.29
,• Banana = $0.05
,• Cantaloupe = $0.89
EXPLANATION
First, we have to name the variables:
• x = cost of one apple
,• y = cost of one banana
,• z = cost of one cantaloupe
Next, we have to write equations for the purchases each person did:
• Liz,: 3 apples (3x), 12 bananas (12y), and 1 cantaloupe (z) for $2.36
,• Bob,: 12 apples (12x), no bananas (0y), and 2 cantaloupe (2z) for $5.26
,• Carol,: no apples (0x), 2 bananas (2y), and 3 cantaloupe (3z) for $2.77
We have the following system of equations,
[tex]\begin{cases}3x+12y+z=2.36 \\ 12x+2z=5.26 \\ 2y+3z=2.77\end{cases}[/tex]We can solve this system using the method of substitution.
Solve the second equation for x,
[tex]\begin{gathered} 12x+2z=5.26 \\ \\ 12x=5.26-2z \\ \\ x=\frac{5.26}{12}-\frac{2z}{12} \end{gathered}[/tex]Solve the third equation for y,
[tex]\begin{gathered} 2y+3z=2.77 \\ \\ 2y=2.77-3z \\ \\ y=\frac{2.77}{2}-\frac{3z}{2} \end{gathered}[/tex]Next, replace x and y with these two expressions as functions of z in the first equation,
[tex]3\mleft(\frac{5.26}{12}-\frac{2z}{12}\mright)+12\mleft(\frac{2.77}{2}-\frac{3z}{2}\mright)+z=2.36[/tex]We have an equation for z. Apply the distributive property to eliminate the parenthesis,
[tex]3\cdot\frac{5.26}{12}-3\cdot\frac{2z}{12}+12\cdot\frac{2.77}{2}-12\cdot\frac{3z}{2}+z=2.36[/tex]Solve the products and quotients - with the help of a calculator,
[tex]1.315-0.5z+16.62-18z+z=2.36[/tex]Add like terms,
[tex]\begin{gathered} (1.315+16.62)+(-0.5z-18z+z)=2.36 \\ \\ 17.935-17.5z=2.36 \end{gathered}[/tex]Subtract 17.935 from both sides,
[tex]\begin{gathered} 17.935-17.935-17.5z=2.36-17.935 \\ \\ -17.5z=-15.575 \end{gathered}[/tex]And divide both sides by -17.5,
[tex]\begin{gathered} \frac{-17.5z}{-17.5}=\frac{-15.575}{-17.5} \\ \\ z=0.89 \end{gathered}[/tex]Now, knowing that z = 0.89, we can replace this value into the second and third equations that we solved for x and y before,
[tex]x=\frac{5.26}{12}-\frac{2z}{12}=\frac{5.26}{12}-\frac{2\cdot0.89}{12}[/tex]Solving this with the help of a calculator, we get x = 0.29.
For y,
[tex]y=\frac{2.77}{2}-\frac{3z}{2}=y=\frac{2.77}{2}-\frac{3\cdot0.89}{2}[/tex]Again, using a calculator, we have that y = 0.05.
Hence, the cost of each fruit is:
• Apple = $0.29
,• Banana = $0.05
,• Cantaloupe = $0.89
The salaries of several employees at Company X are listed below:$52000 $62500 $56000$49000$67500 $60000What is the median salary of the employees at Company X?
Answers
The median salary of the employees at company X is $58000
Explanation:Given:
The median salaries: $52000, $62500, $56000, $49000, $67500, $60000
To find:
the median salary of the employees
To determine the median, we need to rearrange the salaries. Then, we will pick the median salary
$49000, $52000, $56000, $60000, $62500, $67500
There are 6 salaries. The median salary will be the sum of the two middle salaries divided by 2
[tex]\begin{gathered} median\text{ = }\frac{56000\text{ + 60000}}{2} \\ \\ median\text{ = }\frac{116000}{2} \\ \\ median\text{ = 58000} \end{gathered}[/tex]The median salary of the employees at company X is $58000
Solve for s.-2s = 6 - sS =
Answers
-2s = 6 - s
To solve for s, combine like terms
So,
-2s + s = 6
-s = 6
s = -6
So, the value of S = - 6
A cooling tower, such as the one shown in the figure
Answers
Step 1
State the standard form of a hyperbola with the horizontal transverse axis with center at (0,0)
[tex]\frac{x^2}{a^2}-\frac{y^2}{b^2}=1[/tex]Step 2
For a hyperbola with the horizontal transverse axis with center at (0,0)
[tex]\begin{gathered} Length\text{ of horizontal transverse axis }=48=2a \\ \text{Therefore} \\ a=\frac{48}{2}=24 \end{gathered}[/tex]Points to work with include;
[tex]\begin{gathered} one\text{ corner of the base -(50,-84)} \\ one\text{ corner of the top- (}x,36) \\ At\text{ the center- (}24,0) \end{gathered}[/tex]Step 3
Using points (50,-84) to find b²
We have;
[tex]\begin{gathered} \frac{50^2}{24^2}-\frac{(-84)^2}{b^2}=1 \\ \frac{50^2}{24^2}-\frac{7056}{b^2}=1 \\ \frac{50^2}{24^2}-1=\frac{7056}{b^2} \end{gathered}[/tex][tex]\begin{gathered} 3.340277778=\frac{7056}{b^2} \\ 3.340277778b^2=7056 \\ b^2=\frac{7056}{3.340277778} \\ b^2=\frac{7056}{3.340277778} \\ b^2=2112.399168 \end{gathered}[/tex]Step 4
Solve for the x-coordinate of the right corner of the top
[tex]\begin{gathered} The\text{ equation now becomes} \\ \frac{x^2}{24^2}-\frac{36^2}{2112.399168}=1 \\ \frac{x^2}{24^2}=1+\frac{36^2}{2112.399168} \\ \frac{x^2}{24^2}=\frac{1265}{784} \\ 784x^2=728640 \\ x^2=\frac{728640}{784} \\ x^2=\frac{45540}{49} \\ x=\sqrt[]{\frac{45540}{49}} \\ x=30.48586156 \end{gathered}[/tex]But the diameter at the top = 2x
Therefore,
[tex]\begin{gathered} 2(30.48586156)=60.97172312 \\ \approx60.97\text{meters} \end{gathered}[/tex]Hence approximately to 2, decimal places the diameter at the top = 60.97 meters
Trigonometry in baseball Identify a major league ballpark in which the distance from home plate to the center field fence and the height of the center field fence require that a ball hit 2ft above the ground will necessitate an angle of elevation less than to just clear the center field fence.
Answers
Given:
A height of 2ft above the ground
Required:
The distance from the home plate to the centerfield
Explanation:
A height of 2ft above the ground and angle of elevation of 86 degree.
Assuming that the form of our problem is a right angle triangle, we can solve for the remaining angle:
180-(90+86)=4 degrees
The distance from the home plate to the centerfield is
[tex]\frac{2}{sin4}=\frac{x}{sin86}[/tex]Final answer:
x=26.6ft
Review the proof of the identity cos(-A) = -COSA. at which step was an error made
Answers
The given identity is
[tex]\cos (\pi-A)=-\cos A[/tex]Step 1 is about the trigonometric identify of angle difference which states
[tex]\cos (\pi-A)=\cos \pi\cdot\cos A+\sin \pi\cdot\sin A[/tex]So, the first step is wrong since they used subtraction instead of addition.
Step 2 is about solving each trigonometric function of pi. We know that the cosine of pi is -1, and the sine of pi is 0. So, we have
[tex](-1)\cdot\cos A+0\cdot\sin A[/tex]The second step is correct.
Steps 3 and 4 are about solving the products.
[tex](-1)\cdot\cos A+0\cdot\sin A=-\cos A+0[/tex]Steps 3 and 4 are correct.
Step 5 is also correct since the zero doesn't change the cosine function.
Therefore, step 1 is the mistake in the given demonstration.Answer: A. Step 1
Step-by-step explanation: on edge
Which set of ordered pairs represents y as a function of x?O {(3, 3), (3,4), (4,3), (4,4)}O {(2, -1), (4, -2), (6,-3), (8, -4)}|O {(0,0), (1, 1), (1, 0), (2, 1)}o {(1, -5), (1,5), (2, -10), (2, -15)
Answers
Answer:
Second choice from the top.
Explanation.
An ordered pair will be considered a function if no two different values of y are given by the same value of x.
For example, a set of ordered pairs constaining (4, 3) and (4, 8) would not be considered a function.
Looking at the choices given we see that only the second choice in the couln gives
Find the side labeled x. (Round your answer to one decimal place.) 23 17 1080
Answers
x = 15.1 (1 decimal place)
Explanation:we apply the cosine rule:
a² = b² + c² -2bc CosA
let a = 23, b = 17, c = x
a is the side facing the given angle
CosA = 108°
23² = 17² + x² -2(17)(x)Cos 108
529 = 289 + x²- 34(Cos108)
subtract 289 from both sides:
529 - 289 = x²- 34(Cos108)
240 = x²- 34(Cos108)
240 + 34(Cos108) = x²
240 + 34(-0.3090) = x²
240 - 10.506 = x²
229.494 = x²
Square root both sides:
√229.494 = √x²
x = 15.149
x = 15.1 (1 decimal place)
Question 17 of 18How many degrees has 4ABC been rotated counterclockwise about theorigin?
Answers
Solution
- The triangle ABC and its image A'B'C' are just one quadrant from each other.
- This means that ABC was either rotated to the left in the shorter path 90 degrees or to the right at an angle of 270 degrees.
- However, a left rotation is in a counterclockwise direction while a right rotation is in a clockwise direction.
- Thus, we can conclude that this must be a 90-degree counterclockwise rotation.
- This is depicted below:
In the accompanying diagram, ARST is a right triangle, SU is the altitude to hypotenuse RT, RU = 4, and UT = 12. What is the length of RS? A 8 S B 48 R T C 160 4 U 12 D 24
Answers
RU / leg = leg /RT
4/RS = RS/16
RS^2 = 16 x 4
RS = √64 = 8
RS = 8
Solve each equation for the variable. 1/3 d + 6 = 10
Answers
Simplify the equation.
[tex]\begin{gathered} \frac{1}{3}d+6=10 \\ \frac{1}{3}d=10-6 \\ d=4\cdot3 \\ d=12 \end{gathered}[/tex]So answer is 12.
Find the value of X in the image below. Enter your answer without any labels. fc B 399 (3x)º A Z D
Answers
We are asked to find the value of x in the following image:
Where we see that the addition of the angle that measures 39 degrees plus the angle indicated as 3x degrees, must give us a right angle (that is 90 degrees) in order to be the suplementary angle to a right angle formed at the intersection Z
So we can write the following equation:
39 + 3 x = 90
and solve for x by subtracting 39 from both sides
3 x = 90 - 39
3 x = 51
divide both sides by 3 in order to isolate x completely
x = 51 / 3
x = 17
A physical education teacher plans to divide the seventh graders at Wilson middle school into teams of equal size for a year-ending mock Olympic event. He wants each team to have between 4 and 8 students, and all teams need to have the same number of students. The seventh grade of Wilson consists of three classes; one with 28 student, one with 29, and one with 34. How many students should be be on each team?
Answers
Answer:
• It is possible to divide the seventh graders into teams of equal sizes.
,• 13 students should be on each team.
Explanation:
The seventh grade of Wilson consists of three classes; one with 28 students, one with 29, and one with 34. Therefore, the total number of students in seventh grade is:
[tex]\text{Total}=28+29+34=91[/tex]He wants each team to have between 4 and 8 students.
[tex]\begin{gathered} \frac{91}{4}\approx22.75 \\ \frac{91}{5}\approx18.2 \\ \frac{91}{6}\approx15.2 \\ \frac{91}{7}\approx13 \\ \frac{91}{8}\approx11.4 \end{gathered}[/tex]Therefore:
• It is possible to divide the seventh graders into teams of equal sizes.
,• 13 students should be on each team.
We are standing on the top of a 384 feet tall building and launch a small object upward. The object's vertical position, measured in feet, after t seconds is h(t) = -16t^2 + 160t + 384. What is the highest point that the object reaches?
Answers
In linear equation, the highest point that the object reaches is x + y ≤ 20.
What in mathematics is a linear equation?
A linear equation is a first-order (linear) term plus a constant in the algebraic form y=mx+b, where m is the slope and b is the y-intercept.Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables.The three main types of linear equations are the slope-intercept form, standard form, and point-slope form. In this post, we examine all three.h(t)=−16t2+64t+80
highest point
x co - ordinate = -96/2(-10) = 3 seconds
h ( 3) = 16(3)² + 76(3) + 112
= 256 ft
Learn more about linear equation
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B is a midpoint of ACAC = 38AB = 3x+4BC = 5x-6a) Find x.b) Find AB.c) Find BC
Answers
we have the following:
[tex]\begin{gathered} AC=AB+BC \\ \end{gathered}[/tex]replacing:
[tex]\begin{gathered} 38=3x+4+5x-6 \\ 3x+5x=38+6-4 \\ 8x=40 \\ x=\frac{40}{8} \\ x=5 \end{gathered}[/tex]AB:
[tex]3\cdot5+4=15+4=19[/tex]BC:
[tex]\begin{gathered} 5\cdot5-6=25-6=19 \\ \end{gathered}[/tex]therefore,
x = 5
AB = 19
BC = 19
Which quadratic expression matches the standard form expression? (2.2 – 1) (3x - 1) 6x2.5x-1 6x2 + 5x + 1 6x2 - 5x + 1 5x2.5x + 1
Answers
The given expression is
[tex](2x-1)(3x-1)[/tex]Let's use the distributive property
[tex]\begin{gathered} 2x\cdot3x-1\cdot2x-1\cdot3x+1=6x^2-2x-3x+1 \\ 6x^2-5x+1 \end{gathered}[/tex]Hence, the right answer is C.Write e^(½) = 1.6487 . . . in logarithm form.
Answers
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the given exponential form
[tex]e^{\frac{1}{2}}=1.6487[/tex]STEP 2: Convert to logarithmic form
[tex]\begin{gathered} \operatorname{Re}call\text{ that, }e^x=y\Rightarrow\ln y=x \\ \text{Therefore, }e^{\frac{1}{2}}=1.6487\Rightarrow\ln 1.6487=\frac{1}{2} \end{gathered}[/tex]Hence, the logarithm form of the given exponential is written as:
[tex]\frac{1}{2}=\ln 1.6487[/tex]OPTION B
Part #1: Find the solution of the inequality.11 < n + 6Part #2: Describe the solution.
Answers
We have the next inequality
[tex]11we need to isolate the n[tex]\begin{gathered} 11-6We need to change the n to the left side if we do that the sign of inequality will change to greater than[tex]n>5[/tex]Describe the solution
n > 5 means that the value of n needs to be greater than 5 to be a solution to the inequality.
#6 Solve each with quadratic formula simplify in radical form if needed
Answers
Given:
[tex]11v^2+8v=4[/tex]Sol:.
[tex]\begin{gathered} 11v^2+8v=4 \\ 11v^2+8v-4=0 \end{gathered}[/tex][tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-8\pm\sqrt[]{64-4(11)(-4)}}{2\times11} \\ x=\frac{-8\pm\sqrt[]{64+176}}{2\times11} \\ x=\frac{-8\pm15.49}{22} \\ x=\frac{-8-15.49}{22};x=\frac{-8+15.49}{22} \\ x=-1.0678;x=0.340 \end{gathered}[/tex]Answer this question and show me how to check it
Answers
Given:
[tex]\text{length =}8\times10^4\text{ m}[/tex][tex]t\text{hickness}=5\times10^{-6}m[/tex]To find the standard form of length, multiply and divide the length by 10, we get
[tex]\text{length =}8\times10^4\text{ }\times\frac{10}{10}[/tex][tex]\text{length =}\frac{8}{10}\times10^4\text{ }\times10[/tex][tex]\text{Use }\frac{8}{10}=0.8\text{ and }10^4\times10=10^{4+1}=10^5.[/tex][tex]\text{length =}0.8\times10^5m[/tex]To find the standard form of thickness, multiply and divide the thickness by 10, we get
[tex]t\text{hickness}=5\times10^{-6}\times\frac{10}{10}[/tex][tex]t\text{hickness}=\frac{5}{10}\times10^{-6}\times10[/tex][tex]\text{Use }\frac{5}{10}=0.5\text{ and }10^{-6}\times10=10^{-6+1}=10^{-5}.[/tex][tex]t\text{hickness}=0.5\times10^{-5}m[/tex]Hence the standard form of length and thickness is
[tex]\text{length =}0.8\times10^5m[/tex][tex]t\text{hickness}=0.5\times10^{-5}m[/tex]3. The table below shows the distance of the cat and the mouse from the cat's starting point at given times. Which of the following statements must be true?
Answers
By the values of the table, we see that both mouse and cat are moving at the same speed (0.5 units of distance per 0.1 units of time).
The difference between their positions is constant (equal to 5 units). This can be expla
They start at different positions.
So the statement that is true is: A. The cat and the mouse ran at the same speed.
4x-6= 10x-3. solve for x
Answers
Select the correct answer. Which is the inverse of this matrix? 1 2 5 35 9 11 -2. A. -19 9 - 71 15 -7 6 -2 1 -199 -2 1 15 -7 -7 6 B. Oc. [152 7 0 ] OD. - 19 15 - 7 -2 1 O E. The matrix is noninvertible.
Answers
We will have that the inverse of the matrix will be the following:
[tex]A=\mleft[\begin{array}{ccc}1 & 2 & 5 \\ 3 & 5 & 9 \\ 1 & 1 & -2 \\ \end{array}\mright][/tex][tex]A^{-1}=\mleft[\begin{array}{ccc}-19 & 9 & -7 \\ 15 & -7 & 6 \\ -2 & 1 & -1 \\ \end{array}\mright][/tex]A rectangular room that is 20ft by 35ft is being constructed. The scale from theblueprint to the actual size of the room is 1in to 5 ft. What is the area of the actualroom?
Answers
Given:
The length of the room l = 20ft.
The breadth of the room b = 35ft.
To find: The actual area
Explanation:
Using the formula of area of the rectangle,
[tex]\begin{gathered} A=l\times b \\ =20\times35 \\ =700\text{ square fe}et. \end{gathered}[/tex]Thus, the area of the actual room is 700 square feet.
Final answer: Area = 700 square feet.
a spinner has three unequal sections: red, yellow, and blue. the table shows the results of nolan’s spins (red:10, yellow:14, blue:6). find the experimental probability of landing on yellowanswer choices are 1/4 7/15 7/30 1/2
Answers
A spinner has three unequal sections.
Red = 10
Yellow = 14
Blue = 6
[tex]Total\: sections=Red+Yellow+Blue=10+14+6=30[/tex]We are asked to find the experimental probability of landing on yellow.
Recall that the experimental probability is given by
[tex]P=\frac{\text{number of desired outcomes}}{\text{total number of possible outcomes}}[/tex]In this case, the number of desired outcomes are
Yellow = 14
The total number of possible outcomes is
Total sections = 30
[tex]P=\frac{14}{30}=\frac{7}{15}[/tex]Therefore, the experimental probability of landing on yellow is 7/15
I’m not sure which is translation reflection or rotation some assistance on this question would be greatly appreciated
Answers
Solution
From the diagram
C is rotation
B is Translation
A is reflection