Sam needs a web designer. Designer A is offering her services for an initial $500 in addition to $100 per hour. Designer B is offering her service for an initial $600 in addition to $50 per hour. Till how many hours company B will be cheaper option for him?

Answer:

y = 2x+4

Step-by-step explanation:

The y intercept ( where it crosses the y axis ) is 4

The slope is positive because the line goes up from the bottom left to top right

We pick two point ( -2,0) and ( 0,4)

The slope is found by

m= (y2-y1)/(x2-x1)

 = ( 4-0)/(0- -2)

  = 4/ (0+2)

  = 4/2

   = 2

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = 2x+4

Answer:

The equation to this line is y=-4x+4

Step-by-step explanation:

If you look at the graph you can see that the y intercept is 4.

To find the slope take two points on the graph and plug it into be y2-y1/x2-x1

I chose (0,-2) and (-1,2) So  2+2=4  and -1-0= -1 so  4/-1= -4

Answer:

[tex]\boxed{x=1}[/tex]

Step-by-step explanation:

[tex]mean=\frac{sum \: of \: terms}{number \: of \: terms}[/tex]

[tex]2=\frac{2+4+1+1+x+3+2}{7}[/tex]

[tex]2=\frac{13+x}{7}[/tex]

[tex]14=13+x[/tex]

[tex]x=1[/tex]

Answer:

  80°

Step-by-step explanation:

The sum of the measures of the acute angles in a right triangle is 90°. The sum of ratio measures in the ratio 8 : 1 is (8+1) = 9. Thus, each of those measures stands for 90°/9 = 10°. Then the angle ratio is ...

  80° : 10° = 8 : 1

The measure of the largest acute angle in the triangle is ...

  10° × 8 = 80°

Answer:

12

Step-by-step explanation:

If you add the ratio you will get 8 and 1 in the ratio number represents

6 people so 5-3=2

Therefore, the no. of girls minus boys= 6×2=12

so you need 12 more boys to make it to be a ratio of 1:1

Answer:

A. Volume = 462 cm³; Surface Area = 458 cm²

B. Volume

C. Surface area

Step-by-step explanation:

A. Given a rectangular box:

[tex] Width (w) = 3 cm [/tex]

[tex] Height (h) = 14 cm [/tex]

[tex] length (l) = 11 cm [/tex]

=>Volume of the juice box

[tex] Volume (V) = whl [/tex]

[tex] Volume (V) = 3*14*11 [/tex]

[tex] = 3*14*11 = 462 [/tex]

Volume of juice box = 462 cm³

=>Surface area (S.A) of juice box:

[tex] S.A = 2(wl + hl + hw) [/tex]

[tex] S.A = 2(3*11 + 14*11 + 14*3) [/tex]

[tex] S.A = 2(33 + 154 + 42) [/tex]

[tex] S.A = 2(229) [/tex]

[tex] S.A = 458 cm^2 [/tex]

Surface area of juice box = 458 cm²

B. Volume would be used to find the amount of juice the box can hold

C. Surface area would be used to know how much wax to buy to use in coating the box.

Answer:

-4.81647993062

Step-by-step explanation:

Look at the image below ↓

Based on the mathematical analysis, the value of log 0.5^16 is -4.816.

A logarithm is a mathematical term that is used to describe the exponent or power to which a base must be raised to yield a given number.

In this case, to calculate the value of log0.5^16 use logarithm properties.

rewrite the expression as log(0.5)^(16).

=> log(a^b) = b * log(a)

=> 16 * log(0.5).

Given that the Logarithm is the inverse of exponentiation => log(0.5) is equal to -0.301.

Substitute this value back into the expression:

16 * (-0.301) = -4.816.

Hence, in this case, it is concluded that the correct answer to the value of log 0.5^16 is -4.816.

Learn more about Logarithms here: https://brainly.com/question/30226560

#SPJ6

Answer:

1

Step-by-step explanation:

1 to the tenth power is also 1 multiplied by 1 10 times.

1 · 1 · 1 · 1 · 1 · 1 · 1 · 1 · 1 · 1 = 1

1 to any power will always have the answer of 1.

Answer:

$4

Step-by-step explanation:

2 Bracelets + 3 rings = $26

2 rings = $12

3 rings = x

To get the cost of 1 ring you divide 12 by 2 and the answer you get is 6.

The total cost of the 3 rings is $18( $6*3)

Then you subtract the cost of both 2 bracelets and 3 rings($26) from the cost of 3 rings($18). The answer is $8. ( THIS IS THE COST OF 2 BRACELETS)

1 BRACELET= $4( $8/2)

Answer:

Step-by-step explanation:

It depends on how it is written. By definition

[tex]\csc(x) = (\sin(x))^{-1} = \frac{1}{\sin(x)}[/tex]

[tex]\sec(x) = (\cos(x))^{-1} = \frac{1}{\cos(x)}[/tex]

[tex]\cot(x) = (\tan(x))^{-1} = \frac{1}{\tan(x)}[/tex]

however the functions

[tex]\sin^{-1}(x), \cos^{-1}(x), \tan^{-1}(x)[/tex] are the inverse functions of sine, cosine and tangent respectively. So, they are not equivalent functions

Answer:

i need help this too

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given,

x = 5

Now, let's find the value of C

[tex]c = 3x - 2[/tex]

plug the value of x

[tex] = 3 \times 5 - 2[/tex]

Multiply the numbers

[tex] = 15 - 2[/tex]

Calculate the difference

[tex] = 13[/tex]

Hope this helps..

Best regards!!

Answer:

             [tex]\bold{A_{_{\Delta XYZ}}=927.5\ cm^2}[/tex]

Step-by-step explanation:

m∠Z = 180° - 118° - 28° = 34°

[tex]\sin(28^o)\approx0.4695\\\\\sin(118^o)=\sin(180^o-62^o)=\sin62^o\approx0.8829 \\\\\sin(34^o)\approx0.5592\\\\[/tex]

[tex]\dfrac{\overline{XY}}{\sin Z}=\dfrac{\overline{YZ}}{\sin X}\\\\\\\overline{XY}=\dfrac{\overline{YZ}}{\sin X}\cdot\sin Z\\\\\\\overline{XY}=\dfrac{42}{0.4695}\cdot0.5592\\\\\overline{XZ}=50.024281...\\\\\\A_{_{\Delta XYZ}}=\frac12\cdot\overline{XY}\cdot\overline{YZ}\cdot\sin(\angle Z)\\\\\\A_{_{\Delta XYZ}}\approx\frac12\cdot50.0243\cdot42\cdot0.8829=927.4955...\approx927.5[/tex]

Answer:

Hey there!

The solution is where the lines intersect, and here we see that would be (-4,3)

Hope this helps :)

Answer:

a) 20 students

b) 20 students

Step-by-step explanation:

a) From the given frequency table, we have to check the number of students that scored above 73.5 and add them up.

Therefore, the number of students that have grades above 73.5 are:

14 + 4 + 2 = 20 students

b) 75 falls in between 74 - 76 and we do not have the individual frequencies of the grades (74, 75, 76).

However, we can use the data we have from the table to make an assumption.

The number of students that have grades below 75 will be:

13 + 5 + 2 = 20 students

Answer:

45.

Step-by-step explanation:

100% of a number is the number itself. So, 100% of 45 is 45.

Hope this helps!

Answer:it’s 45

Step-by-step explanation:It’s just the whole number nothing less:)

Answer:

Given,

Volume of a cone = 1540 cm[tex] {}^{3} [/tex]

Radius ( r ) = 7 cm

π ( pi ) = [tex] \frac{22}{7} [/tex]

Height of cone ( h ) = ?

Now, let's find the height of cone:

Volume of cone = [tex]\pi \: {r}^{2} \frac{h}{3} [/tex]

plug the values

[tex]1540 = \frac{22}{7} \times {(7)}^{2} \times \frac{h}{3} [/tex]

Evaluate

[tex]1540 = \frac{22}{7} \times 49 \times \frac{h}{3} [/tex]

Calculate

[tex]1540 = \frac{154 \: h}{3} [/tex]

Apply cross product property

[tex]154 \: h = 1540 \times 3[/tex]

Calculate the product

[tex]154 \: h = 4620[/tex]

Divide both sides of the equation by 154

[tex] \frac{154 \: h}{154} = \frac{4620}{154} [/tex]

Calculate

[tex]h \: = 30 \: cm[/tex]

Hope this helps...

Best regards!!

Answer:

Part 1: 359,007 ft³

Part 2: 216 times smaller

Part 3: 21600%

Step-by-step explanation:

Part 1:

The parameters for the tank are;

The radius of the tank = 70 feet

The volume of a sphere = 4/3·π·r³

Therefore, the volume of a quarter sphere = 1/4×The volume of a sphere

The volume of a quarter sphere = 1/4×4/3·π·r³ = π·r³/3

Plugging in the value for the radius gives

Volume = π×70³/3 = 114,333.33×3.14 = 359,006.7≈ 359,007 ft³.

Part 2:

The dimension of the scale model  = 1/6 × Actual dimension

Therefore, we have the radius of the sphere of the scale model = 1/6 × 70

Which gives;

The radius of the sphere of the scale model = 35/3 = 11.67 feet

The volume of the scale model = π·r³/3 = (3.14×11.67³)/3 = 1662.07 ≈ 1662 ft³

The number of times smaller the scale model is than the actual volume = (Actual volume)/(Scale model) = (359,007 ft³)/(1662 ft³) = 216 times

The number of times smaller the scale model is than the actual volume =  216 times = (1/Scale of model)³ = (1/(1/6))³ = 6³.

Part 3:

The percentage of the mock-up, x, to the volume of the actual tank is given as follows

x/100 ×  1662  = 359,007

∴ x = 216 × 100 = 21600%

The percentage of the mock-up, to the volume of the actual tank is 21600%.

Answer:

Part 1: 359,007 ft³

Part 2: 216 times smaller

Part 3: 21600%

Step-by-step explanation:

Part 1:

The parameters for the tank are;

The radius of the tank = 70 feet

The volume of a sphere = 4/3·π·r³

Therefore, the volume of a quarter sphere = 1/4×The volume of a sphere

The volume of a quarter sphere = 1/4×4/3·π·r³ = π·r³/3

Plugging in the value for the radius gives

Volume = π×70³/3 = 114,333.33×3.14 = 359,006.7≈ 359,007 ft³.

Part 2:

The dimension of the scale model  = 1/6 × Actual dimension

Therefore, we have the radius of the sphere of the scale model = 1/6 × 70

Which gives;

The radius of the sphere of the scale model = 35/3 = 11.67 feet

The volume of the scale model = π·r³/3 = (3.14×11.67³)/3 = 1662.07 ≈ 1662 ft³

The number of times smaller the scale model is than the actual volume = (Actual volume)/(Scale model) = (359,007 ft³)/(1662 ft³) = 216 times

The number of times smaller the scale model is than the actual volume =  216 times = (1/Scale of model)³ = (1/(1/6))³ = 6³.

Part 3:

The percentage of the mock-up, x, to the volume of the actual tank is given as follows

x/100 ×  1662  = 359,007

∴ x = 216 × 100 = 21600%

The percentage of the mock-up, to the volume of the actual tank is 21600%.

Answer:

2,666.67 L of water

Step-by-step explanation:

Solve for W:

1) 3200 = 2400 + 0.3w

2) 800 = 0.3w

Divide both sides by 0.3 to get the variable alone

3) (800)/0.3 = (0.3w)/0.3

4) w = 2,666.67 L

Answer:

[tex]\dfrac{10}{4} \ hour[/tex]

Step-by-step explanation:

Given that :

Jack had 4 hours of school.

He spent 45 minutes in the library

1/2 hour on a science lecture  and;

had a lunch break of 25 minutes

The objective is to determine how much time is left for the school to get over and we are to write the answer as a fraction.

In order to do that, we will have to convert the minutes into hours,

we all know that; 60 minutes = 1 hour.

Then,

45 minutes = (45/60)hour = 3/4 hour

25/60 minutes = 1/4 hour

Therefore, the amount of time left  for the school to get over is:

= [tex]4 - (\dfrac{3}{4}+\dfrac{1}{2}+ \dfrac{1}{4})[/tex]

=  [tex]\dfrac{16-(3+2+1)}{4}[/tex]

= [tex]\dfrac{16-6}{4}[/tex]

= [tex]\dfrac{10}{4} \ hour[/tex]

Answer:

Yes, because each x-value corresponds to one y value.

Step-by-step explanation:

If you look at the table, you notice that there is one output (y) for every input (x). This means that it is a function. It would NOT be a function if you had two outputs for an input. For example, there are two x values that are 6. For one coordinate pair, the table says (6,9) and (6,8). Since there are two values for the same input- it wouldn't be a function. In this case, there is an input of 4 and 5 with the same output. That is okay! Even though they have the same y value, those inputs still only have ONE output.

Answer:

m ∠DBC=80−10=70

m ∠ABC=80+30=110

Step-by-step explanation:

m ∠DBC+m ∠ABC=180

( x−10)+(x+30.)=180

2x+20=180

2x=180-20

2x=160

x=80

>>m ∠DBC=80−10=70

>>m ∠ABC=80+30=110

Answer:

[tex]\boxed{<DBC = 70 degrees}\\\boxed{<ABC = 110 degrees}[/tex]

Step-by-step explanation:

∠ABC and ∠DBC are supplementary which means that the sum of these two angles is equal to 180.

∠ABC + ∠DBC = 180

Given that: ∠ABC = x+30 and ∠DBC = x - 10

So,

=> x+30+x-10 = 180

=> 2x+20 = 180

=> 2x = 180-20

=> 2x = 160

Dividing both sides by 2

=> x = 80

Now, Finding measures of the angles.

=> ∠DBC = x-10 = 80-10 = 70 degrees

=> ∠ABC = x+30 =80+30 = 110 degrees

Answer:

3

Step-by-step explanation:

We are adding 2 each time

-3 +2 = -1

-1 +2 = 1

To get the next term add 2

1 +2 = 3

Answer: 3

Step-by-step explanation:

Answer:

3/2

Step-by-step explanation:

Perpendicular lines have slopes that multiply to -1

m * -2/3  =-1

Multiply by -3/2 to isolate m

m * -2/3 * -3/2 = -1 * -3/2

m = 3/2

The perpendicular line has a slope of 3/2

Answer

2

Step-by-step explanation

The radius of the large sphere is double the radius of the small sphere

In the language of modular arithmetic, we're given

[tex]x-3\equiv0\pmod7\implies x\equiv3\pmod7[/tex]

[tex]y+3\equiv0\pmod7\implies y\equiv-3\equiv4\pmod7[/tex]

Then x = 7a + 3 and y = 7b + 4 for integers a and b.

Substitute these into the quadratic expression and simplify:

[tex]x^2+xy+y^2+n\equiv0\pmod7[/tex]

[tex](7a+3)^2+(7a+3)(7b+4)+(7b+4)^2+n\equiv0\pmod7[/tex]

[tex]49a^2+42a+9+49ab+28a+21b+12+49b^2+56b+16+n \equiv 0\pmod7[/tex]

[tex]37+n\equiv 0\pmod7[/tex]

[tex]n\equiv-2\equiv5\pmod7[/tex]

which means the smallest positive integer n we are looking for is 5.

Answer:

it is c because i took test review

Step-by-step explanation:

Answer:

C The solution should be 6, and the cyclists will need to ride 6 laps before the sprint to the finish.

Answer:

Check the answer below.

Step-by-step explanation:

This is a very trivial but professional question. Note that all of millimetre, centimetre and metres are acceptable metric units but the millimetre is more preferable by builders and architects because:

1. It is easier to work with integer values on building and architectural plans, an advantage given by measuring and recording in millimetre.

2. working in millimetre allows for precision. The builder will record values that are very close to the true value

3. The measurement will be easily readable by anybody that sees it.

Answer:

Option B is the correct option.

Step-by-step explanation:

[tex] {(4 - 2)}^{3} - 3 \times 4[/tex]

Subtract the numbers

[tex] = {(2)}^{3 } - 3 \times 4[/tex]

Multiply the numbers

[tex] = {(2)}^{3} - 12[/tex]

Evaluate the power

[tex] = 8 - 12[/tex]

Calculate the difference

[tex] = - 4[/tex]

Hope this helps..

Best regards!!

Answer:

[tex]\boxed{-4}[/tex]

Step-by-step explanation:

[tex](4-2)^3-3 \times 4[/tex]

Brackets or parenthesis are to be evaluated first. Subtract the numbers in the brackets.

[tex](2)^3-3 \times 4[/tex]

Evaluate the power or exponent.

[tex]8-3 \times 4[/tex]

Multiply the numbers.

[tex]8-12[/tex]

Finally, subtract the numbers.

[tex]=-4[/tex]