Samples of airline departure times are obtained and compared to the scheduled departure times. Major airlines are compared and their mean delay times are recorded. Identify the null and alternative hypotheses for applying an analysis of variance.

When QP bisects DQL, then the angles DQP and angle PQL is 23°.

Given that,

In the picture we can see the diagram,

The QL  line is there and the QD line.

QP line bisect the angles DQL

The angle DQP is 5x-7

The angle PQL is 11+2x

We have to find the x value and the angles DQP and PQL.

We know,

From the bisection we can say the angle are equal to each other

The angle DQP=The angle PQL

5x-7=11+2x

5x-2x=11+7

3x=18

x=18/3

x=6

Substitute x value in angles DQP and angle PQL.

The angle DQP=5x-7=5(6)-7=30-7=23°

The angle PQL=11+2x=11+2(6)=11+12=23°.

Therefore, the angles DQP and angle PQL is 23°.

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Graph is attached below.

Given,

y = 2x - 4

We have to draw a graph according to this

Here,

x E {-2; "-1;" 0; 1; 2}:

Image is attached.

How to draw a graph?

First, label and draw your X and Y axes at a straight angle. Axis Y is vertical, whereas axis X is horizontal. Write the scale for each axis down the line and mark the junction as 0, then draw a line. Calculate the values of Y for various values of X after drawing the axes.

So, the graph is given below.

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Answer:

c

Step-by-step explanation:
A two-step equation is one that you need to use two properties of equality to solve.

A circle has a radius of 5 units, 3 students tried to calculate the circumference of the circle, put their answers in order from most accurate to least accurate

31.4π units

10π units

31.4 units ​

we know that

the circumference of a circle is equal to

we have

pi=3.14

r=5 units

substitute

the exact value is 10pi units

the approximate value (assume pi=3.14)

C=31.4 units

so

order from most accurate to least accurate is

10π units

31.4 units

31.4π units

Answer:

Step-by-step explanation:

35-27=8

Answer:22.85%

Step-by-step explanation:

27 - 35

|35|

× 100% =

-8

35

× 100 = -22.8571428571% (decrease)

The parallel between 2 highlights is called eduidistand

The function f(x) = 600(0.75)^x. is a decay function by 25%

The equation of the function is given as

f(x) = 600(0.75)^x.

The above function is an exponential function

An exponential function is represented as

y = ab^x

When f(x) = 600(0.75)^x. and y = ab^x are compared, we have

b = 0.75

The value of b in this case is the factor

Also if b is less than 1, then the function is a decay function

0.75 is less than 1

So, the function represents a decay function

The decal percentage is then calculated as

Decay = 1 - b

So, we have

Decay = 1 - 0.75

Evaluate

Decay = 25%

Hence, the function is a decay function

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We are given the following absolute value equation

Let us solve the problem then we will compare it with the given solution.

Now we will solve for the positive and negative sign separately

Comparing it with the given solution, there is an error on the left-hand side step 2. (the sign of 38 should be positive but in the figure, it is shown negative)

Now let us substitute the obtained x values into the original absolute value equation and check if they satisfy the equation.

For x = -4:

Hence, x = -4 is a valid solution.

For x = -38:

Hence, x = -38 is not a valid solution.

The above is an example of an extraneous solution.

An extraneous solution is a solution that we get during the process of solving an equation but it is not really the solution meaning that it does not satisfy the equation!

Therefore, x = -4 is the only solution to the given equation.

The movies for the movie marathon can be chosen in 120  different ways .

In the question ,

it is given that

total number of movies = 10 movies

number of movies that need to be played in specific order = 7 movies .

we have to find how many different ways can the movies be selected for the movie marathon .

we can solve this with Combination ,

where n = 10  and r = 7

So C(n,r) =  C (10,7)

= 10! / (3! * 7! )

= (10*9*8*7!)/(3! * 7! )

= ( 10*9*8) / (3*2 )

= 10 * 3 * 4

= 120 ways .

Therefore , The movies for the movie marathon can be chosen in 120  different ways .

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The 'x' and 'y' variables are highlighted in the box

Answer:

x = 7

y = 15

Step-by-step explanation:

Disclosure:  After I had completed my answer, I found that Answerwell had already posted a solution.  It is more straightforward than my approach.  While the answers are the same, I'm still adding mine because 1) I worked hard on it, and 2) it illustrates there can be different ways of reaching a solution.

See attached worksheet.

Answer:15 twice

Step-by-step explanation:

Given

To fill the blanks.

Now,

The grpah of f(x)=tanx is given as,

Therefore, from the graph,

Then,

Also,

For x=0, tan(0)=0.

Therefore, the y-intercept is (0,0).

The points for the function f(x)=tanx is,

Since

Then, the points of the graph y=tanx is,

Hence, the answer should be in the order,

i)

ii)

iii)

Given the following Quadratic equation:

You can use the Quadratic formula to solve it:

In this case, you need to add "3x" to both sides of the equation:

You can identify that:

Substituting values into the formula and evaluating, you get:

Answer

Complex roots:

Answer:

[tex]y=\frac{3}{2}x+5[/tex]

Step-by-step explanation:

[tex]-6x+4y=20 \\ \\ 4y=6x+20 \\ \\ y=\frac{3}{2}x+5[/tex]

=========================================================

Explanation:

A hand of two pairs is when we have 2 cards of the same value, and another 2 of the same value, then the fifth card is something else entirely.

An example hand is:

-------------

We use the nCr formula since order doesn't matter.

C(n,r) = (n!)/(r!*(n-r)!)

For any suit, there are n = 13 cards. We make r = 2 selections for each of the two pair.

C(n,r) = (n!)/(r!(n-r)!)

C(13,2) = (13!)/(2!*(13-2)!)

C(13,2) = (13!)/(2!*11!)

C(13,2) = (13*12*11!)/(2!*11!)

C(13,2) = (13*12)/(2!)

C(13,2) = (13*12)/(2*1)

C(13,2) = (156)/(2)

C(13,2) = 78

There are 78 ways to select which two ranks will be chosen to represent each of the two pair.

Let's say one of the ranks of the two pair is a king. There are n = 4 kings and we select r = 2 of them. That gives C(4,2) = 6 ways to select those two kings. We'll also have 6 ways to select the other two cards in the other pair.

Therefore, we have 78*6*6 = 2808 ways to pick the first four cards that consist of the two pair (eg: 2 kings and 2 queens).

-----------------

So far we've considered just the two pairs. We have one card left to select. There are 13-2 = 11 cards of any particular suit that weren't part of the two pair. There are 4 suits to pick from, which means we have 11*4 = 44 cards to pick from for that fifth and final slot.

-----------------

Summary so far:

That gives 2808*44 = 123,552 different two pair hands possible.

This is out of C(52,5) = 2,598,960 hands

Divide those two values to get the final answer

(123,552)/(2,598,960) = 0.04753901560624

This then rounds to 0.04754 as the final answer.

The equation relating T to H is H = 45 - 7T.

Temperature simply means the degree of hotness and coldness in a body.

In this case, they find that the surface temperature at one location is 45 ° Celsius. They also find that the temperature decreases by 7 ° Celsius for each kilometer you go up from the surface.

Let T = the temperature (in Celsius).

Let H = the height above the surface (in kilometers).

The equation will be:

H = 45 - (7 × T)

H = 45 - 7T

The axes aren't given and can't be graphed.

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Using concept of Quadratic Equation we got that best ticket price is $16, maximum income is $19,200 and the corresponding number of tickets are 1200.

A Quadratic Equation is one of the following: f(x) = ax2 + bx + c, where a, b, and c are positive integers and an is not equal to zero. A parabola is basically a curve that represents the graph of a quadratic equation. Parabolas can open up or down, and their "width" or "steepness" can vary, but they all have the same basic "U" shape.

We know that,

No. of people who will buy tickets at $4 = 600

For each 20¢ decrease, additional no. of people buying tickets = 50

Revenue = (No. of tickets sold)(Pricing)

Revenue = (600+50x)(4+x)

= 50[tex]x^{2}[/tex] + 800x + 2400

Solving the quadratic equation we got,

x = -4 or -12

Since we're dealing with real-life entities such as money, we'll take the value of x as positive.

Taking x as 12 (higher value),

No. of tickets sold = 600 + 50x = 1200

Pricing = 4 + x = 16

Revenue = 1200×16 = $19,200

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The simplified form of polynomials are:

1.  (a² - 3a)² = 3a²

2. (1/2x³ + 6x)² = -12x²

Given,

We have to expand the given polynomials and simplify them.

1. The polynomial: (a² - 3a)²

Here,

The polynomial is in the form of (a - b)²

So,

(a - b)² = a² - 2ab + b²

Then,

(a² - 3a)² = (a²)² - (2 × a² × 3a) + (3a)²

(a² - 3a)² = a⁴ - 6a³ + 9a²

(a² - 3a)² = a²(a² - 6a + 9)

Here,

(a² - 6a + 9) is in quadratic form. Solve using quadratic formula.

a = 1, b = -6 and c = 9

[tex]\frac{-b(+-)\sqrt{b^{2} -4ac} }{2a}[/tex] = [tex]\frac{6(+-)\sqrt{(-6)^{2}-4(1)(9) } }{2(1)}[/tex] = [tex]\frac{6(+-)\sqrt{36 - 36} }{2}[/tex] = [tex]\frac{6(+-)\sqrt{0} }{2}[/tex] = (6±0) / 2

= 6/2 = 3

Then,

(a² - 3a)² = a²(a² - 6a + 9)

Here,

(a² - 6a + 9) = 3

So,

(a² - 3a)² = 3a²

2. The polynomial: (1/2x³ + 6x)²

Here, the polynomial is in the form (a + b)²

(a + b)² = a² + 2ab + b²

Here,

(1/2x³ + 6x)² = (1/2x³)² + (2 × 1/2x³ × 6x) + (6x)²

(1/2x³ + 6x)² = 1/4x⁶ + 6x⁴ + 36x²

(1/2x³ + 6x)² = x²(1/4x⁴ + 6x² + 36)

a = 1/4, b = 6 and c = 36

Quadratic formula: [tex]\frac{-b(+-)\sqrt{b^{2} -4ac} }{2a}[/tex]

= [tex]\frac{-6(+-)\sqrt{(-6)^{2} -4(1/4)(36)} }{2(1/4)}[/tex] = [tex]\frac{-6(+-)\sqrt{36-36} }{1/2}[/tex] = (-6±0) / (1/2) = -6 × 2 = -12

Therefore,

(1/2x³ + 6x)² = x²(1/4x⁴ + 6x² + 36)

Here,

(1/4x⁴ + 6x² + 36) = -12

Then,

(1/2x³ + 6x)² = -12x²

That is,

The simplified form of polynomials are:

1.  (a² - 3a)² = 3a²

2. (1/2x³ + 6x)² = -12x²

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Answer:

each cube is 5 feet long because 5*5*5 = 125

Step-by-step explanation:

Part A

Explanation: Count the number of leaves.

======================================================

Part B

Reason:

Look at the largest stem (9) and the largest leaf of this largest stem (5).

This forms the largest value of 95.

The smallest value is 41 since it corresponds to the smallest stem and smallest leaf.

The term "min" and "max" are often used here.

======================================================

Part C

Explanation:

The data set is

41, 52, 57, 58, 65, 66, 70, 75, 78, 80, 81, 95

There are n = 12 items in this set.

Splitting in half gets us n/2 = 12/2 = 6.

The item in slot 6 is 66, and the next item over is 70.

The midpoint of these values is the median. (66+70)/2 = 68.

This midpoint rule only applies if n is even.

To find the range, we subtract the largest and smallest items.

range = max - min = 95 - 41 = 54

======================================================

Part D

Reason:

The stem 8 doesn't have a leaf of 5 attached to it.

It only has the leaves 0 and 1 to form the numbers 80 and 81.

Answer:  [tex](h\circ m)(2) = 6[/tex]

=======================================================

Explanation:

The notation [tex](h \circ m)(2)[/tex] refers to function composition

It's the same as writing [tex]h(m(2))[/tex]

According to

m = {(3,4), (2,-2), (-2,6), (5,8)}

We have m(2) = -2 since x = 2 leads to m(x) = -2

Then the output -2 is treated as the input of the outer function h(x)

Looking through

h = {(1,5), (-2,6), (4, -3), (6,9)}

shows that h(-2) = 6

Therefore, [tex]h(m(2)) = h(-2) = 6, \ \text{ and } \ (h\circ m)(2) = 6[/tex]

Optionally we can write out a table like shown below.

The row highlighted shows the input x = 2 leading to m(x) = -2, which is then plugged into h(x) to get 6 as the final output. Think of it like a chain of dominoes.

Answer:

x ≈ 3.33

Step-by-step explanation:

given y varies inversely as x then the equation relating them is

y = [tex]\frac{k}{x}[/tex] ← k is the constant of variation

to find k use the condition y = 6 , x = 10

6 = [tex]\frac{k}{10}[/tex] ( multiply both sides by 10 )

60 = k

y = [tex]\frac{60}{x}[/tex] ← equation of variation

when y = 18 , then

18 = [tex]\frac{60}{k}[/tex] ( multiply both sides by k to clear the fraction )

18k = 60 ( divide both sides by 18 )

k = [tex]\frac{60}{18}[/tex] ≈ 3.33 ( to 3 significant figures )

If segment BD is congruent to segment BC, and BD = 4x - 18, BC = x + 3, and AC = 34, then AB = 31/x.

Let the equation be AB + BC = AC

substitute the values in the above equation, we get

AB + x + 3 = 34

simplifying the value of x,

Subtract A B from both sides AB + x + 3 - AB = 34 - A B

x + 3 = 34 - AB

Subtract 3 from both sides,

x + 3 - 3 = 34 - AB - 3

x = -AB + 31

Plug in this value of x into the line segments to find BC and AC.

Where, BC = x + 3

substitute the value of x in the above equation, we get

BC = [-AB + 31 ] + 3

BC = -AB + 34

Then, AB + BC = AC

x = -AB + 31

AB = 31/x

Hence, If segment BD is congruent to segment BC, and BD = 4x - 18,

BC = x + 3, and AC = 34, then AB = 31/x.

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Answer:

1. 5ft

2. 2ft

3. 2ft

4. 1ft

Step-by-step explanation:

In linear equation,  that price of shorts before discount was $25

What in mathematics is a linear equation?

Assume that the price of shorts after the discount is x

Total payment = price of shorts + taxes

We know that:

total payment = $21

taxes = 5% = 0.05 of the price

This means that:

21 = x + 0.05x

21 = 1.05x

x = $20

Therefore, the price of the shorts is $20 after the discount

Now, we will get the price of the shorts before the discount:

Assume that the price of shorts before discount is y

We know that:

The discount was 20%

This means that Jennifer paid:

100% - 20% = 80% of the price of the shorts

Therefore:

80% of the price = $20

0.8y = 20

y = $25

This means that price of shorts before discount was $25.

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Answer:

5 inches of wire.

Step-by-step explanation:

60/12 = 5

So at .05 an inch,  you can afford 5 inches at 25 cents

Please mark brainliest!

Answer:

It would be MOP is adjacent

Step-by-step explanation:

Answer:

A = {KL}

Step-by-step explanation:

The subset of the sample space that represents the complement of the event in which Joe plays in the first match is A = {JL, KL}

It is a branch of mathematics that deals with the occurrence of a random event.

The sample space of this experiment consists of all possible ways of choosing two names from a group of three.

Since the order in which the names are chosen does not matter, the size of the sample space is given by the number of combinations of 3 things taken 2 at a time, which is 3.

The three possible outcomes are: {JK, JL, KL}.

If we want to find the complement of the event in which Joe plays in the first match, we need to find the outcomes in which Joe does not play in the first match.

There are two such outcomes: JL and KL.

Therefore, the subset of the sample space that represents the complement of the event in which Joe plays in the first match is A = {JL, KL}

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The function that could represent g(x) is (c) g(x) = f(x) - 5

The figure of the graph that completes the question is added as an attachment

From the attached graph,  we have the equation of the function to be

y = f(x)

Also, the graph of the function f(x) has its intercept to be

y-intercept of f(x) = 3

From the question, we have

y-intercept of g(x) = -2

Subtract the intercepts

Difference = y-intercept of g(x) - y-intercept of f(x)

So, we have

Difference = -2 - 3

Evaluate

Difference = -5

The function g(x) is then represented as

g(x) = f(x) + Difference

So, we have

g(x) = f(x) - 5

Hence, the function g(x) is g(x) = f(x) - 5

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