Select the correct answer.
Solve – 93-(-103)
OA.
-13
11
OB.
Oc. 1917
D. 19 /

Answer:

1522km^2

Step-by-step explanation:

To solve this, first convert the percentage to a decimal. That would be .0475.

Now subtract that from 1.0 to get the factor it decreases by. This would be 1-.0475 = .9525

Multiply 2600 x (.9525)^11 = 1522.258 which rounds to 1522 km^2

Answer:

The area will be 1292.98 km² after 11 years.

Step-by-step explanation:

To find what decreases by 4.57% each year in kilometers:

2600 × 4.57/100 = 26 × 4.57

= 118.82 km²

To find the area after 11 years:

118.82 × 11 = 1307.02

2600 - 1307.02 = 1292.98 km²

1292.98 km² is the answer.

Answer:

rational numbers are perfect squares irrational numbers are non terminating/go on forever

Step-by-step explanation:

Answer:

I think the answer is 2

Step-by-step explanation:

Between 30 and 60 is double b so just divide 4 by 2.

Answer: Try 2. This is my best guess

Answer:

Toni's Tiles and Bob's Bathrooms are in a proportional relationship as they have the same unit rate

Step-by-step explanation:

The given parameters are;

,                                           Area Tiled (ft²)                                    Time (Hr:min)

,                                            

Toni's Tiles,                                   803                               2:12

Bob's Bathrooms,                         1,460                             4:00

Rhonda's Restroom Redos          753                                1:30

The unit rate for each tiler

Toni's Tiles = 803/2:12 = 803/(2×60 + 12) =  6.083 ft²/min

Bob's Bathrooms = 1460/(4×60) =  6.083 ft²/min

Rhonda's Restroom Redos  = 753/(60 + 30) = 8.37 ft²/min

Therefore we have;

The rates at which Toni's Tiles and Bob's Bathrooms tile are to one another = 6.083 to 6.083  = 1:1

The rates at which Toni's Tiles and Rhonda's Restroom Redos tile are to one another = 73/12×30/251 = 365:502

The rate at which Bob's Bathrooms  and Rhonda's Restroom Redos tile are to one another = 73/12×30/251 = 365:502

Therefore, Toni's Tiles and Bob's Bathrooms are in a proportional relationship as they have the same unit rate.

Answer:

Step-by-step explanation:

The diagonal ^2= 13^2+7^2

=169+49=218

diagonal = V218

the lengh of the square=l

l^2+l^2= 218

2l^2=218

l^2= 218/2= 109

l= ✓109

Answer:

  2 × (14 – 9) – (17 – 14) = 7

Step-by-step explanation:

Evaluate the choices to see which is true.

(2 x 14) – 9 – (17 – 14) = 7   ⇒  28 -9 -3 ≠ 7

2 x (14 – 9) + (– 17 – 14) = 7   ⇒  2(5) +(-31) ≠ 7

(2 x 14) – (9 – 17) – 14 = 7   ⇒   28 -(-8) -14 ≠ 7

2 x (14 – 9) – (17 – 14) = 7   ⇒   2(5)- 3 = 7 . . . . true

It will be 50° as it's adjacent to each other

Answer:

For "Negative 23 greater-than x" , highlight the left half of the number line starting at -23 and use a parenthesis ) on -23.

For "x greater-than-or-equal-to negative 23", highlight the right half of the number line starting at -23, and use a square bracket [ on -23.

Step-by-step explanation:

Start by locating the number -23 on the number line. Please see attached image to accompany the explanation.

In the first case:  "Negative 23 greater-than x" , which is expressed mathematically as:

[tex]-23 >x[/tex]

notice that "x" has to be strictly smaller than the number -23, therefore those sought x values must reside to the left of the number -23, so we have to highlight that half of the number line. Apart from that, we need to include a symbol on top of the number -23, that indicates that -23 itself shouldn't be considered as part of the set, that symbol is by convention a parenthesis ).

In the second case: "x greater-than-or-equal-to negative 23", which is expressed mathematically as:

[tex]x\geq -23[/tex]

notice that "x" has to be greater than or equal to the number -23, therefore those sought x values must reside to the right of the number -23, so we have to highlight that half of the number line. Apart from that, we need to include a symbol on top of the number -23, that indicates that -23 itself should be considered as part of the set, that symbol is by convention a square bracket [.

Answer:

the answer is A

Step-by-step explanation:

Answer:

x≥5

Step-by-step explanation:

3(x+15)≤5(x+2)+15

3x+45≤5x+10+15

3x+35≤5x+25

3x-5x≤25-35

-2x≤-10

x≥5

{x:xEx:6,7,8,9,10....}

Hope this helps ;) ❤❤❤

Greetings from Brasil...

a)

Let's just use Pythagoras

L² = X² + (X - 7)²

b)

If L = 13, then what is the value of X ???

L² = 2X² - 14X + 49

2X² - 14X - 120 = 0

X = 12  or  X = - 5

(The distance cannot be negative, so X = 12)

By way of example, suppose A = {1, 2, 3} and B = {a, b, c}. Then the Cartesian product of A and B is

A × B = {{1, a}, {1, b}, {1, c}, {2, a}, {2, b}, {2, c}, {3, a}, {3, b}, {3, c}}

That is, each element in A gets a pairing with each element in B, and for each pairing you have n(A) choices for the first element and n(B) choices for the second element.

So if n(A) = p and n(B) = q, then n(A × B) = pq.

Answer:

slope - (2x)

y-intercept - (-1)

Step-by-step explanation:

-8x + 4y = - 4

4y = 8x - 4

y = 2x - 1

Answer:

9x + 4y +(-5)

Step-by-step explanation:

Given

9x + 4y - 5

Required

Interpret

Write as a sum

The parts of an expression can be interpreted in the following ways; Terms, Variables, Constant, Coefficient, etc.

The terms are the expression being added together and they are 9x, 4y and -5

The variables are the represented with alphabets they change in values; the two variables in the given question are x and y

Constant are numbers standing alone; This is 5

Coefficient are numbers in front of variables; In this case, the coefficient are 9 and 4

Writing 9x + 4y - 5 as a sum

The -5 can be written as +(-5); So, we have

9x + 4y +(-5)

Answer:

19 throws.

Step-by-step explanation:

For her success rate to be 80% in 37 throws she must make  0.8 * 37

= 29.6 throw - that is 30 to nearest throw.

So for the next 20 throws she must make  30 - 11 = 19 throws.

Hey there! I'm happy to help!

First, let's find the volume of the cylindrical tank.

To find the volume of a cylinder, take the area of the circle base and multiply it by the height of the cylinder.

To find the area of a circle, you square the radius and multiply it by pi (we will use 3.14).

The diameter is always twice the radius, so we divide by two to find the radius.

1.4/2=0.7

We square this.

0.7²=0.49

And we multiply by 3.14.

0.49×3.14=1.5386

Now that we have the area of the circle, we multiply by the height (length in our case since the cylinder is sideways).

1.5386×4.5=6.9237

Now, we see that we will be losing 1.7 feet every minute. To see how many times 1.7 feet goes into our cylinder, we just divide!

6.9237÷1.7= 4.07276470588

So we see that it will take just over 4 minutes for the tank to empty.

Have a wonderful day and keep on learning! :D

Answer:

D

Step-by-step explanation:

Answer:

( 4,7)    ( -1,2)

Step-by-step explanation:

y = x + 3

y = x^2 - 2x - 1

Set the equations equal to each other

x + 3  = x^2 - 2x - 1

Subtract x from each side

3 = x^2 -3x -1

Subtract 3 from each side

0 = x^2 -3x -4

Factor

0 = ( x-4) ( x+1)

Using the zero product property

x-4 =0   x+1 =0

x = 4     x=-1

Find y for each x

x=4    y =x+3  y = 4+2  y=7

x = -1  y = x+3   y = -1+3 y = 2

( 4,7)    ( -1,2)

Answer:

D.  (-1, 2) and (4, 7).

Step-by-step explanation:

Eliminating y:

x^2 - 2x - 1 = x + 3

x^2 - 3x - 4 = 0

(x - 4)(x + 1) = 0

x = -1, 4.

When x = -1, y = -1 + 3 = 2.

When x = 4, y =  4 + 3 = 7.

So the answer is (-1, 2) and (4, 7).

Answer:

A

Step-by-step explanation:

since there are 3 corresponding sides shown, the SSS similarity theorem can be utilized.

Answer:

Answer is A

Step-by-step explanation:

Hope it helps

Answer: rectangle.

Step-by-step explanation:

Given points: K(0,0) I(2,2) T(5,-5) E(7,-3)

Distance formula to find distance between [tex]A(a,b)[/tex] and [tex]B(c,d)[/tex]: [tex]AB=\sqrt{(d-b)^2+((c-a)^2}[/tex]

[tex]KI=\sqrt{(2-0)^2+(2-0)^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\ units[/tex]

[tex]KT=\sqrt{(5-0)^2+(-5-0)^2}=\sqrt{25+25}=\sqrt{50}=5\sqrt{2}\ units[/tex]

[tex]TE=\sqrt{(7-5)^2+(-3+5)^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\ units[/tex]

[tex]IE=\sqrt{(7-2)^2+(-3-2)^2}=\sqrt{25+25}=\sqrt{50}=5\sqrt{2}\ units[/tex]

i.e. KI = TE and KT= IE, so opposite sides equal.

It can be a parallelogram or rectangle. [if all sides are equal it would be square or rhombus]

[tex]IT=\sqrt{(5-2)^2+(-5-2)^2}=\sqrt{3^2+7^2}=\sqrt{9+49}=\sqrt{58}\ units[/tex]

[tex]KE=\sqrt{(7-0)^2+(-3-0)^2}=\sqrt{7^2+3^2}=\sqrt{9+49}=\sqrt{58}\ units[/tex]

IT= KE, i.e. diagonals are equal.

It means KIET is  a rectangle.

Answer:

C. Yes; the graph passes the vertical line test.

Step-by-step explanation:

Reasons the others are wrong:

A. It does pass the vertical line test.

B. Y-values can have any x values. It is x-values that can't have multiple y-values.

D. There are y-values with more than one x-value on this graph so that's just false. Even if it were true, that still doesn't invalidate it due to the reasons given in Answer B.

Answer a:

Figure 4 = 5 blocks up, 5 blocks right

Figure 5 = 6 blocks up, 5 blocks right

Answer b: Grows 2 blocks each time, 1 blocks at the top and 1 blocks on the right.

Answer c: Since you add 2 blocks each time, you do the opposite so you subtract 2 blocks. The answer will be 1 block.

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

All the denominators are factors of 12.

Answer:

90π sq cm

Step-by-step explanation:

2πrh = 2π(5)(9) = 90π sq cm

Answer:

Combine numerators over the common denominator to make one term

Step-by-step explanation:

Answer:

D: Add the fractions together on the right side of the equation

Step-by-step explanation:

Let's finish this proof:

Add the fractions together on the right side of the equation

[tex]$x^2+\frac{b}{a} x+\left(\frac{b}{2a} \right)^2=\frac{b^2-4ac}{4a^2} $[/tex]

[tex]\text{Consider the discriminant as }\Delta[/tex]

[tex]\Delta=b^2-4ac[/tex]

Once we got a trinomial here, just put in factored form:

[tex]$\left(x+\frac{b}{2a}\right)^2=\frac{\Delta}{4a^2} $[/tex]

[tex]$x+\frac{b}{2a}=\pm\frac{\Delta}{4a^2} $[/tex]

[tex]$x+\frac{b}{2a}=\pm \sqrt{\frac{\Delta}{4a^2} } $[/tex]

[tex]$x=-\frac{b}{2a}\pm \sqrt{\frac{\Delta}{4a^2} } $[/tex]

[tex]$x=-\frac{b}{2a}\pm \frac{ \sqrt{\Delta} }{2a} $[/tex]

[tex]$x= \frac {-b\pm \sqrt{\Delta}}{2a} $[/tex]

[tex]$x= \frac {-b\pm \sqrt{b^2-4ac}}{2a} $[/tex]