Select the correct answer.
The force exerted by a moving 100 kg object is 1,000 newtons. What is the acceleration of the object?
ОА.
100 m/s2
OB. 10 m/s
Ос.
1,000 m/s2
OD
10,000 m/s2
Reset
Nex

Answers

Answer 1

Answer:

the correct answer is not in the options

the answer is supposed to be 10m/s² from the formula F=ma


Related Questions

What is manufacturing machining ?

Answers

Machining is a process in which a metal is cut into a desired final shape and size by a controlled material-removal process. Machining is a part of the manufacture of many metal products, but it can also be used on materials such as wood, plastic, ceramic, and composites.

Answer:

Machining is a process in which a metal is cut into a desired final shape and size by a controlled material-removal

The in-situ dry density of a sand is 1.72Mg/m3. The maximum and minimum drydensities, determined by standard laboratory tests, are 1.81 and 1.54 Mg/m3,respectively. Determine the relative density of the sand and soil description based on its density.

Answers

Answer:

Relative density = 0.7 or 70%

Explanation:

The following information was provided by this question

Pd = 1.72mg/mg³

Pd max = 1.81 mg/mg³

Pd min = 1.54 mg/mg³

We substitute into the formula. This formula is contained in the attachment.

[(1/1.54)-(1/1.72)]/[1/1.54 - 1/1.81]

= 0.649350 - 0.581395 / 0.649350 - 0.552486

= 0.067955/0.096864

= 0.7015

= 0.7

The relative density is Therefore 0.7 or 70% when converted to percentage

Which statement about the seal between the respirator and the wearer's face is true?
POSSIBLE ANSWERS:
Negative pressure respirators prevent ambient air from entering the mask.
Cosmetic surgery can be completed without a re-evaluation of respirator fit.
Positive pressure respirators tighten the face mask when the wearer inhales.
Facial hair can prevent a respirator from properly sealing to the wearer’s face.

Answers

A true statement about the seal between the respirator and the wearer's face is: D. facial hair can prevent a respirator from properly sealing to the wearer’s face.

What is a respirator?

A respirator can be defined as a personal protective equipment that is typically worn over the face to protect the mouth and nose, while protecting the wearer from inhaling smoke, dust, or other toxic chemical substances.

In this context, a true statement about the seal between the respirator and the wearer's face is that facial hair has the ability to prevent a respirator from properly sealing to the wearer’s face.

Read more on protective equipment here: https://brainly.com/question/19131588

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Do not hoist employees if weather conditions are bad

Answers

Yeah I think but I hope this helps
Shutup give me points

design process 8 steps with definition​

Answers

Answer:

Step 1: Define the Problem.  

Step 2: Do Background Research. .

Step 3: Specify Requirements. .

Step 4: Brainstorm, Evaluate and Choose Solution.  

Step 5: Develop and Prototype Solution.  

Step 6: Test Solution.

Step 7: Does Your Solution Meet the Requirements?  

Step 8: Communicate Results.

can u tell me the definition tho?

palled correctly as “though” which is an alternate form of “although”) at the end is informal usage. It's better placed before “she seems better today

In manufacturing a particular set of motor shafts, only shaft diameters of between 38.20 and 37.50 mm are usable. If the process mean is found to be 37.80 mm with a standard deviation of 0.20 mm, what percentage of the population of manufactured shafts are usable?

Answers

Answer:

we can conclude that  91.04% population of shafts are usable

Explanation:

Given that;

X[tex]_{min}[/tex] = 37.50 mm

X[tex]_{max}[/tex] = 38.20 mm

mean μ = 37.80

standard deviation σ = 0.20 mm

This problem is based on normal probability distribution so, to get the probability, we must calculate; z = x-μ / σ

so;

Z[tex]_{min}[/tex] = (X[tex]_{min}[/tex] - μ) / μ = (37.50 - 37.80) / 0.20 =  -1.5

Z[tex]_{max}[/tex] = (X[tex]_{max}[/tex] - μ) / μ = (38.20 - 37.80) / 0.20 =  2

Hence;

P( 37.50 < X < 38.20 ) = P( -1.5 < Z < 2 )

P( 37.50 < X < 38.20 ) = P( 0 < Z < 1.5 ) + P( 0 < Z < 2 )

from the standard normal table table;

P( 37.50 < X < 38.20 ) = 0.4332 + 0.4772

P( 37.50 < X < 38.20 ) = 0.9104 = 91.40%

Hence, we can conclude that  91.04% population of shafts are usable

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