select the equations of the lines that are parallel to the line whose equation is y = 3x + 5
​

Multiply price per pound by total pounds:

2.50 x 3.5 = 8.75

Total cost = $8.75

Answer:

The cost is $8.75  for 3.5 lbs

Step-by-step explanation:

The rate is 2.50 per pound

Multiply the number of pounds by the rate

3.5 * 2.50 =8.75

The cost is $8.75  for 3.5 lbs

Answer:

x⁴ = -0.955939

x³ = 0.206897

x² = -2.07471

x = 2.65517

Step-by-step explanation:

Step 1: Rewrite equations in standard form

30x⁴ - 5x³ - 10x² + 3x = -1

-3x⁴ + 5x³ + 7x² + 4x = 0

-3x⁴ + x³ + x² = 1

6x⁴ - 10x³ - 2x² + x = -1

Step 2: Write in matrix form

Top Row: [30 -5 -10 3 | -1]

2nd Row: [-3 5 7 4 | 0]

3rd Row: [-3 1 1 0 0 | 1]

Bottom Row: [6 -10 -2 1 | -1]

Step 3: Plug in calc with RREF function

Top Row: [1 0 0 0 | -499/522]

2nd Row: [0 1 0 0 | 6/29]

3rd Row: [0 0 1 0 | -361/174]

4th Row: [0 0 0 1 | 77/29]

Answer:

5/16

Step-by-step explanation:

Use the formula to find slope when 2 points are given.

m = rise/run

m = y2 - y1 / x2 - x1

m = 3 - 8 / -10 - 6

m = -5 / -16

m = 5/16

The slope of the line is 5/16.

Answer: m=5/16

Step-by-step explanation:

The area bounded by region between the curve [tex]y = x^2- 24[/tex]  and [tex]y = 1[/tex] is

[tex]0[/tex] square units.

To find the Area,

Integrate the difference between the two curves over the interval of intersection.

Find the points of intersection between the curves [tex]y = x^2- 24[/tex] and [tex]y = 1[/tex] .

The point of Intersection is the common point between the two curve.

Value of [tex]x[/tex] and [tex]y[/tex] coordinate  will be equal for both curve at point of intersection

In the equation [tex]y = x^2- 24[/tex], Put the value of [tex]y = 1[/tex].

[tex]1 = x^2-24[/tex]

Rearrange, like and unlike terms:

[tex]25 = x^2[/tex]

[tex]x =[/tex]  ±5

The point of intersection for two curves are:

[tex]x = +5[/tex]  and  [tex]x = -5[/tex]

Integrate the difference between the two curve over the interval [-5,5] to calculate the area.

Area =   [tex]\int\limits^5_{-5} {x^2-24-1} \, dx[/tex]

Simplify,

[tex]= \int\limits^5_{-5} {x^2-25} \, dx[/tex]

Integrate,

[tex]= [\dfrac{1}{3}x^3 - 25x]^{5} _{-5}[/tex]

Put value of limits in [tex]x[/tex] and subtract upper limit from lower limit.

[tex]= [\dfrac{1}{3}(5)^3 - 25(5)] - [\dfrac{1}{3}(-5)^3 - 25(-5)][/tex]

= [tex]= [\dfrac{125}{3} - 125] - [\dfrac{-125}{3} + 125][/tex]

[tex]= [\dfrac{-250}{3}] - [\dfrac{-250}{3}]\\\\\\= \dfrac{-250}{3} + \dfrac{250}{3}\\\\\\[/tex]

[tex]= 0[/tex]

The Area between the two curves is [tex]0[/tex] square  units.

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Answer:

[tex]\boxed{Option A ,D}[/tex]

Step-by-step explanation:

The remote (non-adjacent) interior angles of the exterior angle 1 are <4 and <6

Answer:

x= -3, y= -5

or x= 5, y=3

Step-by-step explanation:

① Label the 2 equations

x² +y²= 34 -----(1)

3x -3y= 6 -----(2)

From (2):

x -y= 2 -----(3)

Notice that (x-y)²= x² -2xy +y²

Thus, (equation 3)²= (equation 1) -2xy

Squaring (3):

(x -y)²= 2²

(x -y)²= 4

Expand terms in bracket:

x² -2xy +y²= 4

x² +y² -2xy= 4 -----(4)

subst. (1) into (4):

34 -2xy= 4

2xy= 34 -4 (bring constant to 1 side)

2xy= 30 (simplify)

xy= 30 ÷2 (÷2 throughout)

xy= 15 -----(5)

From (3):

x= y +2 -----(6)

I'll rewrite 2 of the equations.

x= y +2 -----(6)

xy= 15 -----(5)

Subst. (6) into (5):

y(y+2)= 15

y² +2y= 15

y² +2y -15= 0

(y +5)(y -3)=0

y+5= 0 or y-3=0

y= -5 or y= 3

Subst. into (6):

x= -5 +2 or x= 3 +2

x= -3 or x= 5

Answer:

y=-5,                 y=3

x=-3.,                x=5

Step-by-step explanation:

x^2+y^2=34

3x-3y=6

isolate x in te equation

3x-3y=6

x=3/3 y+6/3

x=y+2

plug the y+2 in the equation:

x^2+y^2=34

(y+2)^2+y^2=34

y^2+4y+4+y^2=34

2y^2+4y=34-4

2y^2+4y=30 divide by 2

y^2+2x-15=0 factorize

(y+5)(y-3)=0 eiter y+5=0 ten y=-5 or y-3=0 then y=3

now plug the solution in the equation

3x-3y=6

3x-3(-5)=6

3x=6-15

x=-9/3=-3

for y=3

3x-3y=6

3x-9=6

3x=15

x=5

Answer:

  6 inches square by 3 inches high

Step-by-step explanation:

For a given surface area, the volume of an open-top box is maximized when it has the shape of half a cube. If the area were than of the whole cube, it would be 216 in² = 6×36 in².

That is, the bottom is 6 inches square, and the sides are 3 inches high.

_____

Let x and h represent the base edge length and box height, respectively. Then we have ...

  x² +4xh = 108 . . . . box surface area

Solving for height, we get ...

  h = (108 -x²)/(4x) = 27/x -x/4

The volume is the product of base area and height, so is ...

  V = x²h = x²(27/x -x/4) = 27x -x³/4

We want to maximize the volume, so we want to set its derivative to zero.

  dV/dx = 0 = 27 -(3/4)x²

  x² = (4/3)(27) = 36

  x = 6

  h = 108/x² = 3

The box is 6 inches square and 3 inches high.

_____

Comment on maximum volume, minimum area

In the general case of an open-top box, the volume is maximized when the cost of the bottom and the cost of each pair of opposite sides is the same. Here, the "cost" is simply the area, so the area of the bottom is 1/3 the total area, 36 in².

If the box has a closed top, then each pair of opposite sides will have the same cost for a maximum-volume box. If costs are uniform, the box is a cube.

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Professor Sanchez has been teaching Principles of Economics for over 25 years. He uses the following scale for grading. Grade Numerical Score Probability A 4 0.090 B 3 0.240 C 2 0.360 D 1 0.165 F 0 0.145

a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)

b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)

c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)

Answer:

a. Cumulative Probability Distribution

Grade             P(X ≤ x)

F                      0.145

D                     0.310

C                     0.670

B                     0.910

A                         1

b. P(at least B) = 0.330

c. P(pass) = 0.855

Step-by-step explanation:

Professor Sanchez has been teaching Principles of Economics for over 25 years.

He uses the following scale for grading.

Grade     Numerical Score      Probability

A                       4                            0.090

B                       3                            0.240

C                       2                            0.360

D                       1                            0.165

F                       0                            0.145

a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)

The cumulative probability distribution is given by

Grade = F

P(X ≤ x) = 0.145

Grade = D

P(X ≤ x) = 0.145 + 0.165 = 0.310

Grade = C

P(X ≤ x) = 0.145 + 0.165 + 0.360 = 0.670

Grade = B

P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 = 0.910

Grade = A

P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 + 0.090 = 1

Cumulative Probability Distribution

Grade             P(X ≤ x)

F                      0.145

D                     0.310

C                     0.670

B                     0.910

A                         1

b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)

At least B means equal to B or greater than B grade.

P(at least B) = P(B) + P(A)

P(at least B) = 0.240 + 0.090

P(at least B) = 0.330

c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)

Passing the course means getting a grade of A, B, C or D

P(pass) = P(A) + P(B) + P(C) + P(D)

P(pass) = 0.090 + 0.240 + 0.360 + 0.165

P(pass) = 0.855

Alternatively,

P(pass) = 1 - P(F)

P(pass) = 1 - 0.145

P(pass) = 0.855

Answer:

6.5 ft

Step-by-step explanation:

When we draw out our picture of our triangle and label our givens, we should see that we need to use cos∅:

cos57° = x/12

12cos57° = x

x = 6.53567 ft

Answer:

5n

Step-by-step explanation:

Think about it:

If Tommy has 4 friends (n = 4), then he will have to give 5 pencils to each person. The total number of pencils is 5 * n or 5 * 4 = 20.

Similarly, if Tommy has 0 friends (I can relate), then he will have to give 5 pencils to each of his imaginary friends. The total number of pencils he has to give out to his real friends is 5 * n or 5 * 0 = 0.

Answer:

(a) Probability that a random sample of n = 45 oil changes results in a sample mean time < 10 ​minutes i=0.0001.

(b) The mean oil-change time is 15.55 minutes.

Step-by-step explanation:

Let us denote the sample mean time as x

From the Then x = mean time = 16.2 minutes

  The given standard deviation = 3.4 minutes

The value of  n sample size = 45

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

Answer:

y = x/6 − 11/6

Step-by-step explanation:

y = 6x + 11

To find the inverse, switch x and y, then solve for y.

x = 6y + 11

x − 11 = 6y

y = x/6 − 11/6

Answer:

Dy/Dx=1/√ (2x+3)

Yeah it's correct

Step-by-step explanation:

Applying differential by chain differentiation method.

The differential of y = √(2x+3) with respect to x

y = √(2x+3)

Let y = √u

Y = u^½

U = 2x +3

The formula for chain differentiation is

Dy/Dx = Dy/Du *Du/Dx

So

Dy/Dx = Dy/Du *Du/Dx

Dy/Du= 1/2u^-½

Du/Dx = 2

Dy/Dx =( 1/2u^-½)2

Dy/Dx= u^-½

Dy/Dx=1/√ u

But u = 2x+3

Dy/Dx=1/√ (2x+3)

Answer: 0.0023

Step-by-step explanation:

Let X be the binomial variable that represents the number of receipts will show that the above three food items were ordered.

probability of success p = 32% = 0.32

Sample size : n= 10

Binomial probability function :

[tex]P(X=x)= \ ^nC_xp^x(1-p)^{n-x}[/tex]

Now, the probability that eight receipts will show that the above three food items were ordered :

[tex]P(X=8)=\ ^{10}C_8(0.32)^8(1-0.32)^2\\\\=\dfrac{10!}{8!2!}(0.32)^8(0.68)^2\\\\=5\times9(0.0000508414176684)\\\\=0.00228786379508\approx0.0023[/tex]

hence, the required probability = 0.0023

Answer:

1. continuous random variable

2. not a random variable

3. a continuous random variable

Step-by-step explanation:

The classifications are as follow

a)  The height of the player reported in the game day program is treated as a continuous random variable as these values could be determined through measuring them

b)  The color of student car is not a random variable as it does not contain any quantitative data or we can say numerical data

c)  The exact weight of the bag is a continuous variable as it is lie between the range

Answer:

[tex] 7.72 -2.539 \frac{2.5}{\sqrt{20}} =6.30[/tex]

[tex] 7.72 +2.539 \frac{2.5}{\sqrt{20}} =9.14[/tex]

Step-by-step explanation:

For this case we have the following info given:

[tex]\bar X= 7.72[/tex] represent the sample mean

[tex]s= 2.5[/tex] represent the sample deviation

[tex] n=20[/tex] represent the sample size

The confidence interval is given by:

[tex] \bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}}[/tex]

The confidence interval is 98% and the significance level is [tex]\alpha=0.02[/tex] the degrees of freedom are given by:

[tex] df= n-1 = 20-1=19[/tex]

And the critical value would be:

[tex] t_{\alpha/2}= 2.539[/tex]

And replacing we got:

[tex] 7.72 -2.539 \frac{2.5}{\sqrt{20}} =6.30[/tex]

[tex] 7.72 +2.539 \frac{2.5}{\sqrt{20}} =9.14[/tex]

The 98% confidence interval is between 6.42 hamsters per liter to  9.02 hamsters per liter

Mean (μ) = 7.72, standard deviation (σ) = 2.5, sample size (n) = 20, Confidence (C) = 98% = 0.98

α = 1 - C = 0.02

α/2 = 0.01

The z score of α/2 is the same as the z score of 0.49 (0.5 - 0.01) which is equal to 2.326.

The margin of error E is:

[tex]E = Z_\frac{\alpha }{2} *\frac{\sigma}{\sqrt{n} } \\\\E=2.326*\frac{2.5}{\sqrt{20} } =1.3[/tex]

The confidence interval = (μ ± E) = (7.72 ± 1.3) = (6.42, 9.02)

Hence the 98% confidence interval is between 6.42 hamsters per liter to  9.02 hamsters per liter

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Answer:

The 90% onfidence interval for the mean number of cans that all of the families in the city recycle per month is between 129.34 and 150.66 cans per month

Step-by-step explanation:

We have the standard deviation of the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 18 - 1 = 17

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 17 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 1.74

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 1.74\frac{26}{\sqrt{18}} = 10.66[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 140 - 10.66 = 129.34 cans per month

The upper end of the interval is the sample mean added to M. So it is 140 + 10.66 = 150.66 cans per month.

The 90% onfidence interval for the mean number of cans that all of the families in the city recycle per month is between 129.34 and 150.66 cans per month

Answer:

1/7 = 0.142857... repeating

Step-by-step explanation:

7^(-1) = 1/(7^1) =1/7 = 0.142857... repeating

Answer:

Solution,

[tex] {7}^{ - 1} \\ = \frac{1}{ {7}^{1} } \\ = \frac{1}{7} [/tex]

[tex] {x}^{0} = 1[/tex]

[tex] {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]

( powers are added in multiplication of same base)

[tex] {( {x}^{m} )}^{n} = {x}^{m \times n} [/tex]

[tex] {x}^{ - m} = \frac{1}{ {x}^{m} } [/tex]

[tex] {x}^{ \frac{p}{q} } = \sqrt[q]{ {x}^{p} } [/tex]

Hope this helps ....

Good luck on your assignment...

Answer: CITY B: Dew Point Temperature = 45°F, expected low Temperature = 50°F

Step-by-step explanation:

CITY C: Dew Point Temperature = 25°F, expected low Temperature = 20°F

CITY A: Dew Point Temperature = 65°F, expected low Temperature = 60°F

CITY B: Dew Point Temperature = 45°F, expected low Temperature = 50°F

city B is going to have dew on their lawn in the morning as the dew point temperature is less than the lowest temperature.

When surface temperature drops, eventually reaching the dew point, atmospheric water vapor condenses to form small droplets on the surface. Thus dew will be formed as the conditions are suitable only for city B.

Answer:

45

Step-by-step explanation:

I really don't but it seems right

Answer:

b

Step-by-step explanation:

just did it on edge

Answer:

85.932 cm³

Step-by-step explanation:

The volume of rectangular prism is obtained as the product of its length (l) by its width (w) and by its height (h):

[tex]V=l*w*h[/tex]

The volume of a prism with a length of 4.4 cm, a width of 3.1 cm, and a height of 6.3 cm is:

[tex]V=4.4*3.1*6.3\\V=85.932\ cm^3[/tex]

The volume of this prism is 85.932 cm³.

Answer:

3, 12

Step-by-step explanation:

Et x and y be the required integers.

Case 1: x = 5y - 3...(1)

Case 2: xy = 36

Hence, (5y - 3)*y = 36

[tex]5 {y}^{2} - 3y = 36 \\ 5 {y}^{2} - 3y - 36 = 0 \\ 5 {y}^{2} - 15y + 12y - 36 = 0 \\ 5y(y - 3) + 12(y - 3) = 0 \\ (y - 3)(5y + 12) = 0 \\ y - 3 = 0 \: or \: 5y + 12 = 0 \\ y = 3 \: \: or \: \: y = - \frac{12}{5} \\ \because \: y \in \: I \implies \: y \neq - \frac{12}{5} \\ \huge \purple{ \boxed{ \therefore \: y = 3}} \\ \because \: x = 5y - 3..(equation \: 1) \\ \therefore \: x = 5 \times 3 - 3 = 15 - 3 = 12 \\ \huge \red{ \boxed{ x = 12}}[/tex]

Hence, the required integers are 3 and 12.

let

x  = one integer

y = another integer

x = 5y - 3

If the product of the two integers is 36, then find the integers.

x * y = 36

(5y - 3) * y = 36

5y² - 3y = 36

5y² - 3y - 36 = 0

Solve the quadratic equation using factorization method

That is, find two numbers whose product will give -180 and sum will give -3

Note: coefficient of y² multiplied by -36 = -180

5y² - 3y - 36 = 0

The numbers are -15 and +12

5y² - 15y + 12y - 36 = 0

5y(y - 3) + 12 (y - 3) = 0

(5y + 12) (y - 3) = 0

5y + 12 = 0      y - 3 = 0

5y = - 12           y = 3

y = -12/5

The value of y can not be negative

Therefore,

y = 3

Substitute y = 3 into x = 5y - 3

x = 5y - 3

x = 5(3) - 3

= 15 - 3

= 12

x = 12

Therefore,

(x, y) = (12, 3)

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Answer:

X = 50

Step-by-step explanation:

(5x - 100) + (x - 20) = 180 (sum of angle on a straight line is = 180)

5x + x -100 -120 = 180

6x - 120 = 180

6x = 180 + 120

6x = 300

x = 300/6

x = 50

For y

3y + y + 140 = 180

4y = 180 -140

4y = 40

y = 40/4

y = 10

Answer:

C. -4/3

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes.

We know that line m is perpendicular to line l.

Line l has a slope of 3/4. To find the slope of line m, find the negative reciprocal of 3/4.  Negate the fraction and find the reciprocal.

Negative: switch the sign

3/4 --> -3/4

Reciprocal: switch the numerator (top number) and denominator (bottom number)

-3/4 --> -4/3

Line m has a slope of -4/3 and C is correct.

Answer:

  68

Step-by-step explanation:

The number of chips tested is the integral of the rate over the specified time interval: t = 2 to 6.

  [tex]\displaysyle n=\int_2^6{-3t^2+16t+5}\,dt=\left.-3\dfrac{t^3}{3}+16\dfrac{t^2}{2}+5t\right|_2^6\\\\=-(6^3-2^3) +8(6^2-2^2)+5(6-2)=-(216-8)+8(32) +5(4)\\\\=-208+256+20=\boxed{68}[/tex]

The technician can test 68 chips in that time period.

Answer:

  11/10

Step-by-step explanation:

The area ratio is the square of the radius ratio (k):

  (121/100) = k²

  k = √(121/100) = 11/10

The ratio of radii is 11/10.

Answer:

(38.8%...7/10), than (47%...8/17) I didnt know if u needrd it in fraction or percent.

Step-by-step explanation:

You want to first add up everyone. So in total there are 18 people.

There is than a 38.8% chance that a independent will be picked first. 7/18.

But since one person was picked already you have to subtract 1 person from the total, so now its out of 17.

There is now a 47% chance that a democrat will be picked next. 8/17.

The profit made in week 1 is 0.69 and week 2 is 0.71.

In general, the term "proportion" refers to a part, share, or amount that is compared to a total.

According to the concept of proportion, two ratios are in proportion when they are equal.

A mathematical comparison of two numbers is called a proportion. According to proportion, two sets of provided numbers are said to be directly proportional to one another if they increase or decrease in the same ratio. "::" or "=" are symbols used to indicate proportions.

Given:

A takeaway sells 10-inch pizzas and 12-inch pizzas.

From the table

For week 1:

Proportion= 509/ 736 = 0.69

and, week 2:

Proportion= 765/ 1076 = 0.71

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Answer:

24

Step-by-step explanation:

Answer:

Option C

Step-by-step explanation:

The chi square test of independence is used to determine if there is a significant association between two categorical variables from a population.

It tests the claim that the row and column variables are independent of each other.

The degrees of freedom for the chi-square are calculated using the following formula: df = (r-1) (c-1) where r is the number of rows and c is the number of columns.