.- Sí 159.6 gramos de Fe2O3 liberan 67.2 litros de CO2 ¿cuántos litros de CO2 se liberan si reaccionan 45 gramos de Fe2O3? de acuerdo a la siguiente reacción: Fe2O3 (s) + 3 CO (g) 2 Fe (s) + 3 CO2 (g)

Answer:

45 g de oxido de hierro (III) liberarán 18.9 L de CO₂

Step-by-step explanation:

La reaccion quimica es la siguiente:

Fe₂O₃ (s) + 3CO (g)  →  2Fe (s) + 3CO₂ (g)

1 mol de oxido de hierro (III), reacciona con 3 moles de monoxido de carbono para liberar 3 moles de CO₂ y 2 moles de Fe sólido.

Pasamos la masa de F₂O₃ a moles:

159.6 g . 1 mol /159.7g = 1 mol de oxido

Entonces, aplicamos la regla de tres:

1 mol de oxido produce 3 moles de dioxido de carbono, indudablemente eso será lo que formemos de producto, por lo tanto 3 moles de CO₂ estan ocupando 67.2 litros.

Ahora calculamos los nuevos moles:

45g . 1 mol /159.7 g = 0.282 moles

Aplicamos la regla de tres:

Si un mol de oxido produce 3 moles de CO₂

0.282 moles producen (0.82 . 3 ) = 0.845 moles de CO₂

Como tenemos menos moles de gas, el volumen ocupado sera mayor, hacemos la regla de tres:

Si 3 moles de CO₂ ocupan 67.2 litros

0.845 moles ocuparan (0.845  . 67.2/  3 ) =  18.9 litros

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