Simplify -8n - 7(6n - 6)

Answers

Answer 1

Answer:

-50n + 42

General Formulas and Concepts:

Pre-Algebra

Distributive Property

Algebra I

Combining Like Terms

Step-by-step explanation:

Step 1: Define

-8n - 7(6n - 6)

Step 2: Simplify

Distribute -7:                   -8n - 42n + 42Combine like terms:       -50n + 42

Related Questions

Help... it’s multiple choice math

Answers

Answer:

D

Step-by-step explanation:

This is equivalent to t < 4.

clearly this is not part of the set.

pls help work is due tonight i will give brainliest

Answers

Answer

the first one is the answer and none of the above

Step-by-step explanation:

i have a c please help it will mean alot

Answers

[tex]\Large\boxed{\tt Answer: 5\frac{2}{3} }[/tex]

[tex]\tt Step-by-step~explanation:[/tex]

We can solve this by dividing both numbers by four.

[tex]\tt 8\div4=2\\12\div4=3\\\frac{2}{3}[/tex]

We then add that to 5 to get our answer.

Part A The domain of a function is the set of all possible values and range of a function is a set of all possible values?​

Answers

Answer:

value is 35 and the range is2

Step-by-step explanation:

Identify the like terms:
4x - 7+ 6y + 2x + x + 16 - 3x

Answers

The answer is 4x+9+6y

Answer:

4x−7+6y+2x+x+16−3x

=4x+−7+6y+2x+x+16+−3x

Combine Like Terms:

=4x+−7+6y+2x+x+16+−3x

=(4x+2x+x+−3x)+(6y)+(−7+16)

=4x+6y+9

Answer:

=4x+6y+9

For 4 weeks in June, Cameron biked 3 1/4 miles each week and swam 2 1/2 miles each week. For 3 weeks in July, he biked 4 3/4 miles each week and swam 3 1/2 miles each week

Answers

Step-by-step explanation:

Given that,

For 4 weeks in June, Cameron biked 3 1/4 miles each week and swam 2 1/2 miles each week.

For 3 weeks in July, he biked 4 3/4 miles each week and swam 3 1/2 miles each week.

We need to find how much greater was the total distance Cameron bike and swim in July compared to the total distance he bike in swim in June.

In July, total distance is ,

[tex]4\dfrac{3}{4}\times 3+3\dfrac{1}{2}\times 3\\\\= \dfrac{19}{4}\times 3+\dfrac{7}{2}\times 3\\\\=24.75\ \text{miles}[/tex]

In June, total distance is :

[tex]=4\times 3\dfrac{1}{4}+4\times 2\dfrac{1}{2}\\\\=\dfrac{13}{4}\times 4+\dfrac{5}{2}\times 4\\\\=23\ \text{miles}[/tex]

Hence, in June total distance is 23 miles and in July total distance is 24.75 miles.

Please help me wiyh this
In triangle △WXY, XY ≅ WX and m∠X=38 Find m∠W

Answers

A because fhmwtjstney egg scbwfjrw eyed tenet her

The table represents a Linear function, what is the slope of the function?

Answers

Answer:

m = 3

Step-by-step explanation:

Pick two points from the table.

(-1, 1) and (1, 7)

Apply the slope formula.

[tex]m=\frac{7-1}{1+1}=\frac{6}{2}=\boxed{3}[/tex]

Hope this helps.

Plz and quick!
I rly rly need this

Answers

Step-by-step explanation:

20x² = y - 24

y = 20x² + 24

For y to have the least possible value, x² have to be the least possible, which is 0.

Since -3 <= x <= 2 includes x = 0, this is allowed.

Hence least possible value of y

= 20(0)² + 24 = 24.

Answer:

24

Step-by-step explanation:

-3---> 20(-3)^2=y-24 ----> y=204

-2---> 20(-2)^2=y-24 ----> y=104

-1---> 20(-1)^2=y-24 ----> y=44

0---> 20(0)=y-24 ----> y=24

1---> 20(1)^2=y-24 ----> y=44

2---> 20(2)^2=y-24 ----> y=104

Twice the sum of x and 3 is decreased by 13

Answers

Given:

Twice the sum of x and 3 is decreased by 13.

To find:

The expression for the given statement.

Solution:

The sum of x and 3 is (x+3).

Twice the sum of x and 3 is two times of (x+3), i.e., 2(x+3)

Negative sign is used of decrease.

Decreased by 13 is represented by -13.

Using these representation, we get

Twice the sum of x and 3 is decreased by 13: [tex]2(x+3)-13[/tex]

Therefore, the required expression is [tex]2(x+3)-13[/tex].

The perimeter of a rectangle is 64 feet. The length is two more than double the width. Find the dimensions of the rectangle.

Answers

Answer:

Length = 22 ; width = 10

Step-by-step explanation:

Perimeter of a rectangle = 2(length + width)

Perimeter = 64 feets

Length = 2 + (2*width)

Let :

Length = l ; width = w

Perimeter = 2((2 + (2w)) + w)

64 = 2(2 + 3w)

64 = 4 + 6w

64 - 4 = 6w

60 = 6w

w = 60/6

w = 10

Width = 10

Length = 2 + (2*width) = 2 + (2*10) = 2 + 20 = 22

Eric rented a truck for one day the base fee was 16.95 for additional charge of .76 cents for each mile driven eric had to pay 152.23 when he returned the truck how many miles did he drive

Answers

Answer:

178 miles

Step-by-step explanation:

Let Eric has driven d miles.

As the rate of charge of driving the truck = 76 cents /mile

So, the charge of driving the truck for d miles = 76d cents= $0.76d

The base fee of the truck was $16.95.

Total money paid at the time of returning the truck = $152.23

So, 16.95+0.76d=152.23

0.76d= 152.23-16.95=135.28

d=135.28/0.76

d=178

Hence, he drives 178 miles.

Help me please. I need helpppppoooooopppppopopppp

Answers

Answer:

0

Step-by-step explanation:

The minimum number of cavities a patient had was 0 cavities.

Answer:

0

Step-by-step explanation:

The smallest number that indicates cavity is '0' therefore it is the minimum number of cavities

Please help!

Sin A =

Sin C =

Cos A =

Cos C =

I’ll give brainliest!!

Answers

Answer:

sin A= 3/5

sin C= 4/5

cos A= 4/5

cos C= 3/5

Step-by-step explanation:

Please see the attached picture for the full solution.

Please help due in 10 minutes

Answers

Answer:

The 2nd one should be the correct answer

answer: the 2nd option. (aka: 2(3x+5)

if : 3x+3x+5+5= 6x+10

THEN: 2(3x+5)

HOW: 2 times 3x.

           2 times 5

           6x+10.

hope i helped! we just passed this subject in my class. Good luck!!

Work out an approximate solution to x^3+2x-1=0 use the iteration...... Help please!!!!?????

Answers

Approximate solutions are the estimate values of an equation

The approximate solution of the equation is x = 0.45

How to determine the approximate solution

The equation is given as:

[tex]x^3 + 2x- 1= 0[/tex]

The iteration is given as:

[tex]x_{n+1} = \frac{1}{x_n^2 + 2}[/tex]

To start with, we have:

[tex]x_1 = 1[/tex]

So, we have:

[tex]x_2 = \frac{1}{1^2 + 2} = \frac 13 =0.33333333[/tex]

The next iteration is:

[tex]x_3 = \frac{1}{0.33333333^2 + 2} = 0.47368421102[/tex]

The next iteration is:

[tex]x_4 = \frac{1}{0.47368421102^2 + 2} = 0.4495641344[/tex]

The next iteration is:

[tex]x_5 = \frac{1}{0.4495641344^2 + 2} = 0.45411035264[/tex]

The next iteration is:

[tex]x_6 = \frac{1}{0.45411035264^2 + 2} = 0.45326473189[/tex]

Notice that:

x5 and x6 have the same value to 2 decimal places.

i.e. [tex]x_5 \approx x_6 = 0.45[/tex]

Hence, the approximate solution of the equation is x = 0.45

Read more about approximate solutions at:

https://brainly.com/question/10171109

Is it true that Terms with no variables are like terms?

Answers

Answer:

yes

Step-by-step explanation:

Jordan is buying plastic plates for a party.The plates usually cost $2.40 per 10 plates,but they are on sale for 30% off usual price.If jordan buys 50 plates,how much will they cost

Answers

30% off means they are paying 70% of the original price.

Sale price = 2.40 x 0.70 = $1.68 for 10 plates

50 plates /  10  = 5

They buy 5 packages of plates.

1.68 x 5 = $8.40

Total price = $8.40

Answer:

Step-by-step explanation:

2.40 X 5 =$12

12 X 0.3=$3.6 off

12-3.6=$8.40

Therefore it'll cost $8.40

The regular price of a jacket is $62.00. If the discount rate is 15%, how much was the discount?

Answers

Discount amount = price x discount percentage as a decimal:

Discount amount = 62.00 x 0.15 = 9.30

Discount = $9.30

Answer:

$52.70

Step-by-step explanation:

Is it a, b, c, d, plz answer this

Answers

Answer:

d 4x^2 + 24x - 8

Step-by-step explanation:

Perimeter of the rectangle = 2x² - 5 + 12x + 1 + 2x² - 5 + 12x + 1

                                            = (2x²+ 2x²) + (12x+ 12x) + (- 5 + 1 - 5 + 1)

                                            = 4x² + 24x - 8

11r - 14r - 3 + 16 what is the answer

Answers

Answer:

-3r + 13

Step-by-step explanation:

11r - 14r - 3 + 16

add like terms

-3r + 13

Combine like-terms of 6x-2x-2=-3x+4(x+7)

Answers

3x-2 = 3x+4x+28x

3x-2 = 7x + 28

Please explain how to solve it​

Answers

You just distribute the power of 3 so it should end up as
(8x^3)/(27y^6)

(the 3 and the 2 multiply to equal 6)

Hope it helps!

Answer:  [tex]\frac{8x^3}{27y^6}[/tex]

This is the fraction 8x^3 all over 27y^6

On a keyboard, we can write it as (8x^3)/(27y^6)

===========================================================

Explanation:

The exponent tells you how many copies of the base to multiply with itself.

We'll have three copies of [tex]\left(\frac{2x}{3y^2}\right)[/tex] multiplied with itself due to the cube exponent on the outside.

So,

[tex]\left(\frac{2x}{3y^2}\right)^3 = \left(\frac{2x}{3y^2}\right)*\left(\frac{2x}{3y^2}\right)*\left(\frac{2x}{3y^2}\right)\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{2x*2x*2x}{(3y^2)*(3y^2)*(3y^2)}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{(2*2*2)*(x*x*x)}{(3*3*3)*(y^2*y^2*y^2)}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{8x^3}{9y^6}\\\\[/tex]

-------------------

Or another approach you could take is to cube each component of the fraction. The rule I'm referring to is [tex]\left(\frac{a}{b}\right)^c = \frac{a^c}{b^c}[/tex]

Applying that rule will lead to:

[tex]\left(\frac{2x}{3y^2}\right)^3 = \frac{(2x)^3}{(3y^2)^3}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{2^3*x^3}{3^3*(y^2)^3}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{8x^3}{27y^{2*3}}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{8x^3}{27y^6}\\\\[/tex]

Either way you should get 8x^3 all over 27y^6 as one fraction.

Which is the equation of a hyperbola with directrices at y = ±2 and foci at (0, 6) and (0, −6)?

Answers

Given:

Hyperbola with directrices at y = ±2 and foci at (0, 6) and (0, −6).

To find:

The equation of hyperbola.

Solution:

We have, directrices at y = ±2 so this hyparabola is along the y-axis.

The standard form of hyperbola is

[tex]\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2}=1[/tex]      ...(i)

where, (h,k) is center, foci are [tex](h,k\pm c)[/tex] and directrix are [tex]y=k\pm \dfrac{a^2}{c}[/tex].

On comparing foci, we get

[tex](h,k\pm c)=(0,\pm 6)[/tex]

[tex]h=0,k=0,c=6[/tex]

On comparing directrix we get

[tex]k\pm \dfrac{a^2}{c}=\pm 2[/tex]

[tex]\dfrac{a^2}{c}=2[/tex]

[tex]\dfrac{a^2}{6}=2[/tex]

[tex]a^2=12[/tex]

Now,

[tex]a^2+b^2=c^2[/tex]

[tex]12+b^2=(6)^2[/tex]

[tex]b^2=36-12[/tex]

[tex]b^2=24[/tex]

Putting [tex]h=0,k=0,a^2=12,b^2=24[/tex], we get

[tex]\dfrac{(y-0)^2}{12}-\dfrac{(x-0)^2}{24}=1[/tex]

[tex]\dfrac{y^2}{12}-\dfrac{x^2}{24}=1[/tex]

Therefore, the equation of hyperbola is [tex]\dfrac{y^2}{12}-\dfrac{x^2}{24}=1[/tex].

Answer:

the person above has the right answer. I took the test.

Step-by-step explanation:

The person above is correct.

I will mark brainliest for the best and first answer .......:​

Answers

Answer:

its the first one

Step-by-step explanation:


What is the slope?

Simplify your answer and write it as a proper fraction, improper fraction, or integer.

Answers

Answer:

[tex]\displaystyle m=\frac{1}{2}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Slope Formula: [tex]\displaystyle m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point (0, 40)

Point (20, 50)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Substitute [SF]:                    [tex]\displaystyle m=\frac{50-40}{20-0}[/tex]Subtract:                              [tex]\displaystyle m=\frac{10}{20}[/tex]Simplify:                               [tex]\displaystyle m=\frac{1}{2}[/tex]

What is the range of this (may be more than one answer)

Answers

the area of variation between upper and lower limits on a particular scale.The range is the difference between the largest and smallest numbers. The midrange is the average of the largest and smallest number.

2. You are rolling a number cube. What is the probability that you will roll a
3? Answer in fraction form only.

Answers

Answer:

Step-by-step explanation:

1/2

Triangle GHI with vertices G(4, 1), H(5, -4), and I(2, -8) REFLECTED over the line y = x.

Answers

Answer:

[tex]G' = (1,4)[/tex]

[tex]H' = (-4,5)[/tex]

[tex]I = (-8,2)[/tex]

Step-by-step explanation:

Given

[tex]G = (4,1)[/tex]

[tex]H = (5,-4)[/tex]

[tex]I = (2,-8)[/tex]

Reflection: [tex]y = x[/tex]

Required

Determine the coordinates of G'H'I'

The following applies when a line A is reflected over [tex]y = x[/tex]

[tex]A = (x,y)[/tex]

[tex]A' = (y,x)[/tex]

i.e, we simply swap the positions of x and y

So, for:

[tex]G = (4,1)[/tex]

[tex]H = (5,-4)[/tex]

[tex]I = (2,-8)[/tex]

The reflections are:

[tex]G' = (1,4)[/tex]

[tex]H' = (-4,5)[/tex]

[tex]I = (-8,2)[/tex]

See attachment

If f(x) = x2 – 2x and g(x) = 6x + 4, for which value of x does (f + g)(x) = 0?
-4
-2
2
4

Answers

Answer:

x = - 2

Step-by-step explanation:

(f + g)(x) = f(x) + g(x)

f(x) + g(x)

= x² - 2x + 6x + 4

= x² + 4x + 4

Equating to zero

x² + 4x + 4 = 0 ← left side is a perfect square

(x + 2)² = 0, thus

x + 2 = 0 ( subtract 2 from both sides )

x = - 2

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