Answer:
[tex]3 -\sqrt[2]3[/tex]
Step-by-step explanation:
Given
[tex]\frac{2\sqrt[3]{9}}{1 + \sqrt[3]{3} + \sqrt[3]{9}}[/tex]
Required
Simplify
Rewrite the given expression in index form
[tex]\frac{2 * 9 ^\frac{1}{3}}{1 + 3^{\frac{1}{3}} + 9^{\frac{1}{3}}}[/tex]
Express 9 as 3²
[tex]\frac{2 * 3^2^*^\frac{1}{3}}{1 + 3^{\frac{1}{3}} + 3^2^*^{\frac{1}{3}}}[/tex]
[tex]\frac{2 * 3^\frac{2}{3}}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}}}[/tex]
Multiply the numerator and denominator by [tex]1 - 3^{\frac{1}{3}}[/tex]
[tex]\frac{2 * 3^\frac{2}{3}}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}}} * \frac{1 - 3^{\frac{1}{3}}}{1 - 3^{\frac{1}{3}}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) (1 - 3^{\frac{1}{3}})}{(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})(1 - 3^{\frac{1}{3}})}[/tex]
Open the bracket
[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{2}{3})(3^{\frac{1}{3}})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
Simplify the Numerator using Laws of Indices
[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{2+1}{3})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
Further Simplify
[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{3}{3})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3^1)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
Simplify the denominator
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - (3^{\frac{1}{3}})(3^{\frac{1}{3}}) - (3^{\frac{1}{3}})(3^{\frac{2}{3}})}[/tex]
Further Simplify Using Laws of Indices
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - (3^{\frac{1+1}{3}}) - (3^{\frac{1+2}{3}})}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3^{\frac{3}{3}}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3^1}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3}}[/tex]
Collect Like Terms
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 - 3+ 3^{\frac{1}{3}} - 3^{\frac{1}{3}}+ 3^{\frac{2}{3}} - 3^{\frac{2}{3}} }}[/tex]
Group Like Terms for Clarity
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{(1 - 3) + (3^{\frac{1}{3}} - 3^{\frac{1}{3}}) + (3^{\frac{2}{3}} - 3^{\frac{2}{3}} )}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{(- 2)+ (0) + (0)}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{-2}}[/tex]
Divide the fraction
[tex]-(3^\frac{2}{3}) + (3)[/tex]
Reorder the above expression
[tex]3 -3^\frac{2}{3}[/tex]
The expression can be represented as
[tex]3 -\sqrt[2]3[/tex]
Hence;
[tex]\frac{2\sqrt[3]{9}}{1 + \sqrt[3]{3} + \sqrt[3]{9}}[/tex] when simplified is equivalent to [tex]3 -\sqrt[2]3[/tex]
first correct answer gets best marks
Answer:
the answer would be x is less than 6.
Step-by-step explanation:
the reason why it would not be x is less than or equal to 6 is that the circle is not filled in.
Answer:
B
Step-by-step explanation:
x≤6
We can see from the graph that it starts from 6 and goes to 5, 4, 3, 2.
Hope this helps ;) ❤❤❤
48 - 8x equivalent expression
Answer:
8(6-x)
Step-by-step explanation:
Both 48 and 8 can be divisible by 8.
48 ÷ 8 = 6
8 ÷ 8 = 1
Therefore you get the answer 8(6-x)
as the simplest form.
Hope this helps.
Points A(-l, y) and B(5,7) lie on a circle with centre 0(2, -3y). Find the values of y. Hence, find the radius of the circle
Answer:
The answer is below
Step-by-step explanation:
Points A(-l, y) and B(5,7) lie on a circle with centre O(2, -3y). This means that AB is the diameter of the circle and OA = OB = radius.
For two points X([tex]x_1,y_1[/tex]) and Y([tex]x_2, y_2[/tex]), the coordinates of the midpoint (x, y) between the two points is given as:
[tex]x=\frac{x_1+x_2}{2},y=\frac{y_1+y_2}{2}[/tex].
For A(-l, y) and B(5,7) with center O(2, -3y), the value of y can be gotten by:
[tex]For\ x\ coordinate:\\2=\frac{-1+5}{2}\\ 2=2.\\For\ y\ coordinate:\\-3y=\frac{y+7}{2}\\ -6y=y+7.\\-6y-y=7\\-7y=y\\y=-1[/tex]
The value of y is -1. Therefore A is at (-1, -1) and O is at (2, -3(-1))= (2, 3)
The radius of the circle = OA. The distance between two points X([tex]x_1,y_1[/tex]) and Y([tex]x_2, y_2[/tex]) is given as:
[tex]|OX|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\Therefore\ the\ radius \ |OA|\ is :\\|OA|=\sqrt{(2-(-1))^2+(3-(-1))^2}=\sqrt{25}=5[/tex]
The radius of the circle is 5 units
Find the area ratio of a regular octahedron and a tetrahedron regular, knowing that the diagonal of the octahedron is equal to height of the tetrahedron.
Answer:
[tex]\frac{4}{3}[/tex]
Step-by-step explanation:
The area of a regular octahedron is given by:
area = [tex]2\sqrt{3}\ *edge^2[/tex]. Let a is the length of the edge (diagonal).
area = [tex]2\sqrt{3}\ *a^2[/tex]
Given that the diagonal of the octahedron is equal to height (h) of the tetrahedron i.e.
a = h, where h is the height of the tetrahedron and a is the diagonal of the octahedron. Let the edge of the tetrrahedron be e. To find the edge of the tetrahedron, we use:
[tex]h=\sqrt{\frac{2}{3} } e\\but\ h=a\\a=\sqrt{\frac{2}{3} } e\\e=\sqrt{\frac{3}{2} }a[/tex]
The area of a tetrahedron is given by:
area = [tex]\sqrt{3}\ *edge^2[/tex] = [tex]\sqrt{3} *(\sqrt{\frac{3}{2} }a)^2=\frac{3}{2}\sqrt{3} *a^2[/tex]
The ratio of area of regular octahedron to area tetrahedron regular is given as:
Ratio = [tex]\frac{2\sqrt{3}\ *a^2}{\frac{3}{2} \sqrt{3}*a^2} =\frac{4}{3}[/tex]
Hope is the coach of the Wilson High School girls' soccer team. There are 3 minutes left in the game they are currently playing, and they are losing by 1 goal. In the past, when losing by 1 goal, Hope has pulled a defender out of the game and replaced her with a forward a total of 9 times. When in the same position, she has left the defender in the game 10 times. In the situations when Hope has pulled her defender, the team has lost 4 times, tied 2 times, and won 3 times. In situations when she has left her defender in the game, the team has lost 1 time, tied 3 times, and won 6 times. Based on the information above, if the goal is to either tie or win the game, should Hope pull the defender or leave her in the game?
Answer:
Hope should not pull her defender.
Step-by-step explanation:
When Hope has pulled her defender:
The team had lost 4 times, tied 2 times, and won 3 times.
Hence, the total number of times she meets her goal is:
6 times (Since the goal is to either tie or win the game )
Hence, the probability that she meets her goal is = 6/9=2/3=0.66
When she left her defender in the game:
The team has lost 1 time, tied 3 times, and won 6 times.
Hence, the total number of times she meets her goal is: 9
Hence, the probability that she meets her goal is: 9/10=0.9
As the probability of meeting her goal is more when she left her defender in the game is more.
Hence, Hope should not pull her defender.
What fraction is equal to six-sevenths times eight-fifths?
Answer:
1 13/35 (mixed number) or 48/35 (simplified)
Step-by-step explanation:
6/7 times 8/5
= (6 times 8) / (7 times 5)
= 48/35 or 1 13/35
hope this helped :)
Answer:
48/35
Step-by-step explanation:
6/7*8/5=48/35
Miriam is setting up a fishing game in a kiddie pool for her niece's birthday party. The pool has a circular base with a diameter of 4 feet and a height of 0.75 feet. She wants to fill the pool halfway so there is plenty of space left for the plastic fish. Approximately how many cubic feet of water does she need? 9.4 1.5 2.4 4.7
Answer:
4.7 feet³ of water
Step-by-step explanation:
Diameter of 4 feet
Radius = 2 feet
Height = 0.75 feet
Formula for Volume = 2·[tex]\pi[/tex]·radius·height
But she only wants to fill half, so divide by 2, cancels the 2 in the formula for volume, giving us: [tex]\pi[/tex]·radius·height
[tex]\pi[/tex]·2·0.75 = 4.71 feet³
Help please!!!!!thxxxx
Answer:
144
Step-by-step explanation:
An angle of a regular pentagon is of 180(5-2)/5=108°
and that all the sides are equal so angle MNL=108/3=36
then MNK=180-MNL=180-36=144
I don't know if you understand this but it's hard to work without more points :)
Can somebody plz help me 15-[7+(-6)+1]^3
Answer:
7.
Step-by-step explanation:
15 - [7 + (-6)+ 1]^3
Using PEMDAS:
= 15 - [ 7-6+1]^3
Next work out what is in the parentheses:
= 15 - 2*3
Now the exponential:
= 15 - 8
= 7.
Step-by-step explanation:
Hi,
I hope you are searching this, right.
=15[7+(-6)+1]^3
=15[7-6+1]^3
=15[2]^3
=15-8
=7...is answer.
Hope it helps..
An umbrella has 8 ribs which are equally spaced (see fig.). Assuming umbrellato
be a flat circle of radius 45 cm, find the area between the two consecutive ribs of
the umbrella.
Answer:
Yes.
Step-by-step explanation:
You are correct except to the nearest hundredth it is 795.54 cm^2.
Help please thanks don’t know how to do this
Answer:
a = 11.71 ; b = 15.56
Step-by-step explanation:
For this problem, we need two things. The law of sines, and the sum of the interior angles of a triangle.
The law of sines is simply:
sin(A)/a = sin(B)/b = sin(C)/c
And the sum of interior angles of a triangle is 180.
45 + 110 + <C = 180
<C = 25
We can find the sides by simply applying the law of sines.
length b
7/sin(25) = b/sin(110)
b = 7sin(110)/sin(25)
b = 15.56
length a
7/sin(25) = a/sin(45)
a = 7sin(45)/sin(25)
a = 11.71
abby owns a square plot of land. she knows that the area of the plot is between 2200 and 2400 square meters. which of the following answers is a possible value for the side length of the plot of land?
Answer:
48
Step-by-step explanation:
The formula for the area of a square is A = s². Plug in each value and see if is in between 2200 and 2400.
A = s²
A = (46)²
A = 2116
A = s²
A = (48)²
A = 2304
A = s²
A = (50)²
A = 2500
A = s²
A = (44)²
A = 1936
The only value that fits in between 220 and 2400 is 48.
Simplify (2^3)^–2. PLEASE I NEED HELP U WILL GET 10 POINTS
Answer:
I won't give you the answer straight away so you take the time to read my answer and understand
Step-by-step explanation:
We knoe that 2 to the third is 8. when you square to a negative power, you do squaring normally, and then take the reciprocal of that number. so 8 to the second power is 64, and we flip it over, sp the answer is 1/64
At the shop near the beach, ice cream is offered in a cone or in a cylindrical cup as shown
below. The ice cream fills the entire cone and has a hemisphere on top. The ice cream
levelly fills the cylindrical cup.
radius of cone= 3 cm
radius of cylinder= 4.5 cm
height of cone = 10 cm
height of cylinder = 5 cm
Determine how much more ice cream the larger option has. Show your work. ( 19)
Answer:
B
Step-by-step explanation:
plzzz helpp ASAP 1. Why is it important to know what the limitations of a particular model are? A. so you can create a prototype based on your model B. so you don't make the mistake of confusing an object and a system C. so you can revise your model to represent every property of the real thing D. so you don't confuse properties of the model with properties of the real thing
2. Mathematical and computer models are similar because both involve _____. A. using calculations to represent an object or system B. comparisons between an object or system and something familiar C. building a complex object or system isolated from the natural world D. creating real-life objects that show features of the modeled object or system
3. Some models can illustrate a system. What does the term system refer to? A. a collection of interacting things B. a set of rules or laws about things C. something with advantages and limitations D. something illustrating parts of a real-life thing
4. J.J. Thomson's Plum Pudding Model is an example of _____. A. a picture B. an analogy C. a prototype D. a mathematical model
5. An advantage of describing a cell as being like a factory is that it _____. A. makes cells easier to understand B. shows the limitations of cells clearly C. prevents having to study the complexities of cells D. is cheaper to do experiments in a factory than on a cell
6. Scientists like using models because they are often _____ than the real thing. A. more accurate B. more enjoyable to study C. cheaper and more complex D. cheaper and easier to work with
7. An advantage of J.J. Thomson's Plum Pudding Model was that it _____. A. was a much less expensive way to study atoms B. simplified the calculations necessary to describe an atom C. clearly explained where electrons were located in an atom D. is much less expensive to bake a plum pudding than to look at an atom
8. A small clay model of a volcano is an example of _____. A. an analogy B. a prototype C. a physical model D. a computer model
9. An advantage of using a model instead of the real thing is that models _____. A. include better detail B. can be easier to change C. are much more interesting to study D. don't include any features of the real thing
Answer:
D. so you don't confuse properties of the model with properties of the real thing.
2-Mathematical and computer models are similar because both involve using calculation to represent an object or system
3- Some models can illustrate a system. What does the term system refer to
A. a collection of interacting things
4-J.J. Thomson's Plum Pudding Model is an example of _____B. an analogy
5. An advantage of describing a cell as being like a factory is that it _____
A. makes cells easier to understand
6- C. cheaper and more complex
7-C. clearly explained where electrons were located in an atom
8-C. a physical model
9-B. can be easier to change
GOOD LUCK
Please help i will mark brainliest
Answer:
See below.
Step-by-step explanation:
To find the equation, we need to find the slope and the y-intercept. Afterwards, we can put the numbers into the slope-intercept form:
[tex]y=mx+b[/tex]
From the graph, we can see that the line crosses the y-intercept at y=-6. Thus, the y-intercept (b) is -6.
Now we need to find the slope. Pick any two points where the line crosses. I'm going to pick (0,-6) and (4,-7).
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{-7-(-6)}{4-0}= -1/4[/tex]
Therefore, the equation of the line would be:
[tex]y=mx+b\\y=-1/4x-6[/tex]
If the m1 = 40, what is the m 3
Answer:
Your Answer is 120Step-by-step explanation:
m1=40
Taking m3
m3=40 ×3
m3= 120
Hope It helps UHere are two sets of cards.
X has the same value on both cards.
Each set of cards has a range of 4.
Work out the value of X
Answer:
3
Step-by-step explanation:
In Set A, the minimum is 4 and the maximum is 7 without X which would make the range 7 - 4 = 3 but we want the range to be 4, therefore X has to be 4 + 4 = 8. Unfortunately, this would then make the range of Set B 8 - 1 = 7 so X has to be the smallest number in Set A which would be 7 - 4 = 3.
Find the area of the shape shown below
Answer: 28
Step-by-step explanation:
I can't really think of a way to explain this well without visuals and idk how to add images on my answer. But, what I normally do is draw out the shape on paper divide the shape into different sections. Solve the area of the separate sections. It simplifies the more complex figure and turns them into basic shapes. After solving each shape, add all of them together and that leaves you with the area. Hopefully you understand what I mean. I hope this sort of helped:)
Solve by the quadratic formula: x^2= 6x-4
Answer:
3 [tex]\pm[/tex] [tex]\sqrt{5}[/tex].
Step-by-step explanation:
x^2 = 6x - 4
x^2 - 6x + 4 = 0
Now, we can use the quadratic formula to solve.
[tex]\frac{-b\pm\sqrt{b^2 - 4ac} }{2a}[/tex], where a = 1, b = -6, and c = 4.
[tex]\frac{-(-6)\pm\sqrt{(-6)^2 - 4 * 1 * 4} }{2 * 1}[/tex]
= [tex]\frac{6\pm\sqrt{36 - 4 * 4} }{2}[/tex]
= [tex]\frac{6\pm\sqrt{36 - 16} }{2}[/tex]
= [tex]\frac{6\pm\sqrt{20} }{2}[/tex]
= [tex]\frac{6\pm2\sqrt{5} }{2}[/tex]
= 3 [tex]\pm[/tex] [tex]\sqrt{5}[/tex]
x = 3 [tex]\pm[/tex] [tex]\sqrt{5}[/tex].
Hope this helps!
the diagrams shows a right-angled triangle. find the size of angle x. give your answer correct to 1 decimal place.
Answer:
1. 40.8 degrees
2. 65.6 degrees
Step-by-step explanation:
1.
sin(x) = opposite / hypotenuse = 17/26
x = arcsin(17/26) = 40.83 degrees
2. tan(x) = opposite / adjacent = 11/5 = 2.2
x = arctan(11/5) = 65.56 degrees
Please answer this in two minutes
Answer:
20/29
Step-by-step explanation:
SOH CAH TOA
so its opposite/hyp...
20/29
is the answer
Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2ab-6a+5b+___ Please include an explanation too!
Answer:
[tex]2ab - 6a + 5b - 15[/tex]
Step-by-step explanation:
Given
[tex]2ab - 6a + 5b + \_[/tex]
Required
Fill in the gap to produce the product of linear expressions
[tex]2ab - 6a + 5b + \_[/tex]
Split to 2
[tex](2ab - 6a) + (5b + \_)[/tex]
Factorize the first bracket
[tex]2a(b - 3) + (5b + \_)[/tex]
Represent the _ with X
[tex]2a(b - 3) + (5b + X)[/tex]
Factorize the second bracket
[tex]2a(b - 3) + 5(b + \frac{X}{5})[/tex]
To result in a linear expression, then the following condition must be satisfied;
[tex]b - 3 = b + \frac{X}{5}[/tex]
Subtract b from both sides
[tex]b - b- 3 = b - b+ \frac{X}{5}[/tex]
[tex]- 3 = \frac{X}{5}[/tex]
Multiply both sides by 5
[tex]- 3 * 5 = \frac{X}{5} * 5[/tex]
[tex]X = -15[/tex]
Substitute -15 for X in [tex]2a(b - 3) + 5(b + \frac{X}{5})[/tex]
[tex]2a(b - 3) + 5(b + \frac{-15}{5})[/tex]
[tex]2a(b - 3) + 5(b - \frac{15}{5})[/tex]
[tex]2a(b - 3) + 5(b - 3)[/tex]
[tex](2a + 5)(b - 3)[/tex]
The two linear expressions are [tex](2a+ 5)[/tex] and [tex](b - 3)[/tex]
Their product will result in [tex]2ab - 6a + 5b - 15[/tex]
Hence, the constant is -15
Jane exchanged £100 for 216 Swiss francs. After buying a meal and a present to take home,she had 70 francs left.How much is this in £?
Answer:
£32.4
Step-by-step explanation:
£100 = 216 Swiss francs
x = 70 francs
70 x 100=7000/216=32.4
HELP MEEEEEEE please
Answer:
scale factor = [tex]\frac{1}{3}[/tex]
Step-by-step explanation:
Consider the ratio of corresponding sides, image to original, that is
scale factor = [tex]\frac{T'V'}{TV}[/tex] = [tex]\frac{2}{6}[/tex] = [tex]\frac{1}{3}[/tex]
Please help fast! 25 points and brainliest!!
Let f(x) = 36x5 − 44x4 − 28x3 and g(x) = 4x2. Find f of x over g of x
Answer:
The answer is
9x³ - 11x² - 7xStep-by-step explanation:
f(x) = 36x^5 − 44x⁴ − 28x³
g(x) = 4x²
To find f(x) / g(x) Divide each term of f(x) by g(x)
That's
[tex] \frac{f(x)}{g(x)} = \frac{ {36x}^{5} - {44x}^{4} - {28x}^{3} }{ {4x}^{2} } \\ \\ = \frac{ {36x}^{5} }{ {4x}^{2} } - \frac{ {44x}^{4} }{ {4x}^{2} } - \frac{ {28x}^{3} }{ {4x}^{2} } \\ \\ = {9x}^{3} - {11x}^{2} - 7x[/tex]
Hope this helps you
Answer:
9x³ - 11x² - 7x
Step-by-step explanation:
guy abpove is right or bwlowe
6. Find d.
Please help
Answer:
Step-by-step explanation:
The first thing we are going to do is to fill in the other angles that we need to solve this problem. You could find ALL of them but all of them isn't necessary. So looking at the obtuse angle next to the 35 degree angle...we know that those are supplementary so 180 - 35 = the obtuse angle in the small triangle. 180 - 35 = 145. Within the smaller triangle we have now the 145 and the 10, and since, by the Triangle Angle-Sum Theorem all the angles have to add up to equal 180, then 180 - (10 + 145) = the 3rd angle, so the third angle is 180 - 155 = 25. Now let's get to the problem. If I were you, I'd draw that out like I did to keep track of these angles cuz I'm going to name them by their degree. In order to find d, we need to first find the distance between d and the right angle. We'll call that x. The reference angle is 35, the side opposite that angle is 12 and the side we are looking for, x, is adjacent to that angle. So we will use the tan ratio to find x:
[tex]tan(35)=\frac{12}{x}[/tex] Isolating x:
[tex]x=\frac{12}{tan(35)}[/tex] so
x = 17.1377 m
Now we have everything we need to find d. We will use 25 degrees as our reference angle, and the side opposite it is 12 and the side adjacent to it is
d + 17.1377, so that is the tan ratio as well:
[tex]tan(25)=\frac{12}{d+17.1377}[/tex] and simplifying a bit:
[tex]d+17.1377=\frac{12}{tan(25)}[/tex] and a bit more:
d + 17.1377 = 25.73408 so
d = 8.59, rounded
Calcule o valor dos produtos a) (-4). (-7/8) b) (-4). (-7/8) n sei pq tá repetido tá aqui na folha ;-; c) (-4).(+ 3,5) d) (-2).(-3/4). (-1/7) PRA HOJEE
Answer:
a) (-4). (-7/8) = 28/8
b) (-4). (-7/8)= 28/8
c) (-4).(+ 3/5) = -12/5
d) (-2).(-3/4). (-1/7) = (6/4)(-1/7)= -6/28
Step-by-step explanation:
a) (-4). (-7/8) = 28/8
b) (-4). (-7/8)= 28/8
c) (-4).(+ 3/5) = -12/5
d) (-2).(-3/4). (-1/7) = (6/4)(-1/7)= -6/28
É repetido talvez com sinal alterado para mostrar a diferença na resposta. Se o sinal for alterado, a resposta também se tornará negativa. Seria - 28/8.
Quando um número negativo é multiplicado por um número negativo, obtém um número positivo. Mas quando um número positivo é multiplicado por um número negativo, dá uma resposta negativa.
Sempre se lembre
negativo * negativo = positivo
positivo * negativo = negativo
negativo * positivo = negativo
positivo * positivo = positivo
Em palavras simples, dois sinais diferentes dão um sinal negativo e dois sinais semelhantes dão um sinal positivo na multiplicação.
English
a) (-4). (-7/8) = 28/8
b) (-4). (-7/8)= 28/8
c) (-4).(+ 3/5) = -12/5
d) (-2).(-3/4). (-1/7) = (6/4)(-1/7)= -6/28
Its repeated maybe with a changed sign to show the difference in the answer. If the sign is changed the answer would also become negative . It would become - 28/8.
When a negative number is multiplied with a negative number it gives a positive number. But when a positive number is multiplied with a negative number it gives a negative answer.
Always remember
negative * negative= positive
positive *negative=negative
negative *positive =negative
positive * positive = positive
In simple words two unlike signs give a negative sign and two similar signs give a positive sign in multiplication.
Pls help I need help with 12
Answer:
B. 14
Step-by-step explanation:
22/x = 11/(21-x)
462 - 22x = 11x
462 = 33x
x = 14
Answer: The value of x is 14, answer choice B
Let y be the other line segment connected to x
Using proportions:
[tex]\dfrac{11}{22}=\dfrac{y}{x}[/tex]
Cross multiply and simplify
[tex]22y=11x[/tex]
[tex]y=\dfrac{1}{2}x[/tex]
We know that x and y add to 21, so we can create the following equation:
[tex]x+y=21[/tex]
Substitute y=(1/2)x
[tex]x+\dfrac{1}{2}x=21[/tex]
Simplify by adding like terms
[tex]\dfrac{3}{2}x=21[/tex]
Divide both sides by 3/2
[tex]x=14[/tex]
Let me know if you need any clarifications, thanks!
I NEED HELP WITH THIS! I need to pass...
Answer: A) The log parent function has negative values in the range.
Step-by-step explanation:
The domain of y = ln (x) is D: x > 0
The domain of y = [tex]\sqrtx[/tex][tex]\sqrt x[/tex] is D: x ≥ 0
The range of y = ln (x) is: R: -∞ < y < ∞
So the only valid option is A because the range of a log function contains negative y-values when 0 < x < 1.