Answer:
9[tex]a^{4}[/tex]b³
Step-by-step explanation:
The 2 terms are like terms and can be combined, that is
[tex]a^{4}[/tex]b³ ( 1 + 8)
= 9[tex]a^{4}[/tex]b³
Answer:
9a^4b^3
Step-by-step explanation:
a^4b^3 + 8a^4b^3
These are like terms so we can add them together
Factor out a^4b^3
a^4b^3( 1+8)
a^4b^3 (9)
9a^4b^3
The vertices of triangle ABC are A(5,2), B(-1,-6), and C(1,5). If triangle DEF is similar to triangle ABC and AB/DE = 5, which could be the coordinates of D and E
Answer:
im pretty sure its the third one
Step-by-step explanation:
i guessed but it might be right
Please help
Factorise completely 36ab - 18b+6a-3
Answer:
[tex]3(6b-1)(2a-1)[/tex]
Step-by-step explanation:
[tex]36ab-18b+6a-3\\18b(2a-1)+3(2a-1)[/tex]
Taking (2a-1) as common
[tex](18b+3)(2a-1)[/tex]
=> [tex]3(6b-1)(2a-1)[/tex]
Answer:
[tex]3(6b+1)(2a-1)[/tex]
Step-by-step explanation:
[tex]36ab - 18b+6a-3[/tex]
Factor the two groups.
[tex]18b(2a-1)+3(2a-1)[/tex]
Take 2a - 1 common.
[tex](18b+3)(2a-1)[/tex]
Factor 18b + 3.
[tex]3(6b+1)(2a-1)[/tex]
Heyy umm I need help
Answers
B, D and E are proportional
A, C, and F are not proportional
y = 3+x .... not proportional
y = 1.6x .... proportional
y = 3/(4x) .... not proportional
y = x .... proportional
y = 12x .... proportional
y = 2x+1 ... not proportional
=================================================
Explanations:
Anything in the form y = k*x is a direct proportional equation. As x goes up, so does y. The same happens if x decreases, and we'll have y also decrease. They go up together or down together. This is where the "direct" comes from. Specifically they change the same amount each time (hence the term "proportional").
For something like y = 1.6x, we have k = 1.6
In the equation y = x, we have y = 1x in reality so k = 1 here.
Lastly, y = 12x has k = 12.
----------------------
The other equations are not in the form y = kx. Whenever we have y = mx+b, with b nonzero, then y = mx+b is not proportional. The value of b must be 0 for it to fit y = kx form. This rules out y = 2x+1 and y = 3+x or y = x+3.
The equation y = 3/(4x) is an inversely proportional equation in the form y = k/x. It cannot be written as y = kx. Note how x is in the denominator for y = 3/(4x) while the same can't be said for y = kx. Inversely proportional equations have x increase and y decrease, or vice versa. They go in opposite directions.
∫1/(1+sinx^2 +2cos^2x)
Answer:
Im not sure, is this correct?
F(x) = 3x+2 what is f(5)
Answer:
f(5) = 17Step-by-step explanation:
f(x) = 3x + 2
To find f(5) substitute 5 into f(x)
That's
f(5) = 3(5) + 2
= 15 + 2
= 17
Hope this helps you
Answer:
17
Step-by-step explanation:
You just plug 5 into the equation
f(5)= 3(5)+2
=15+2
=17
Hope this helped! :)
Find the indicated functional value for the ceiling function: f(1.5)?
Answer:
The correct answer is 2Step-by-step explanation:
The ceiling function is a python programming function that rounds a decimal point number to the nearest whole number.
Given the function expression f(1.5), the ceiling function will round 1.5 to the nearest whole number which is 2
Please help me.. I'm very confused about this
Answer:
C
Step-by-step explanation:
1:draw a very simple Cartesian plane for the graph
2:label the quadrants 1-4 from top right round to bottom right as 4
3:then apply x>0 (1,2) is top right and y<0 is bottom right (-1,-2)
which geometric solid is formed by rotating the rectangle about line m?
Answer:
rectangular prism
Step-by-step explanation:
check by rotating the shape in images
pls answer asap i need this answer quick plus the full explanation #7
Explain please --
Find the measure of angle A to the nearest degree.
a. 26
b. 27
c. 63
Explanation:
We'll use the tangent ratio to connect the opposite and adjacent sides with the reference angle
tan(angle) = opposite/adjacent
tan(A) = 14/7
Then use the arctangent function (aka inverse tangent) to fully isolate A
A = arctan(14/7)
A = 63.4349 degrees approximately; make sure your calculator is in degree mode
Round this to the nearest whole number to get 63.
find three examples of corporate logos. do they incorporate symmetry? if so, and what kind? your response should be 3-5 sentences long
Answer:
Symmetry is the property of an object to retain its shape even if it is turned or turned.
The three corporate logos are McDonald, Shell, Snapcaht
McDonald company logo is symmetrical and it is a reflective symmetry.
Shell logo is symmetrical and it is also reflective symmetry.
Snaphcat logo is symmetrical and it is also reflective symmetry.
The cosine function reaches a value of 0 when x is equal to
Answer:
Step-by-step explanation:
The values of the cosine function are represented by the axis OX of the goniometric circumference (circumference centered at the origin and of radius 1). Therefore the cosine is zero for the 90º and 270º angles.
Which is a qualitative graph? On a coordinate plane, a line with positive slope goes through points (negative 1, 0) and (0, 3). On a coordinate plane, points are at (0, 2), (1, 3), (2, 2.5), (3, 3), (4, 4), and (4.5, 5). A graph has time on the x-axis and height on the y-axis. The graph increases to point A, increases to point B, and then decreases to point C. A graph has time on the x-axis and height on the y-axis. Segment A increases, segment B is increases, and segment C decreases.
Answer:
(-1,0), (0,3) and (2,2.25)
Step-by-step explanation:
The qualitative graph is as follows:
A(-1,0) ------> B(0,3) ------> C(2,2.25)
Hence, slope = (2.25 - 0)/(2 - (-1)) = 2.25/3
∴ slope = 0.75
Except for the option graph on a coordinate plane, a line with a positive slope goes through points (negative 1, 0) and (0, 3), all the graph is qualitative. Options B, C, and D are correct.
What is a qualitative graph?The kind of graph that shows the quality curve such as decreasing and increasing events, is called a qualitative graph or curve.
Here,
1. On a coordinate plane, a line with a positive slope goes through points (negative 1, 0) and (0, 3), since this graph does not represent any data as well as also constantly increasing between two points so it is not a qualitative graph.
Similarly,
Graphs B, C, and D have an increasing and decreasing order, so all are qualitative graphs.
Thus, except for graph A all the graphs are qualitative graphs.
Learn more about qualitative graphs here:
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anyone plss heeelp me...i only need answer 6c..
Answer:
6c1; [tex]Area = 81.12m^2[/tex]
6cii: See Explanation
Step-by-step explanation:
Given
[tex]A = 3p^2[/tex]
[tex]0 \leq p \leq 6[/tex]
Where A represents Area and P represents Width
Required
Solve 6c
Please note that because you only need 6c, I'll solve using calculations;
Solving 6ci:
Area of the cage, when width is 5.2m
Substitute 5.2m for p in[tex]A = 3p^2[/tex]
[tex]A = 3 * 5.2m^2[/tex]
[tex]A = 3 * 27.04m^2[/tex]
[tex]A = 81.12m^2[/tex]
Hence, the area of the cage is 81.12m²
Solving 6cii:
Area of the cage, when width is 40m
From the range of value of p: [tex]0 \leq p \leq 6[/tex], 40m is out of range of the values of p
However, if the range is extended; the value of Area is as follows;
Substitute 40m for p
[tex]A = 3 * 40m^2[/tex]
[tex]A = 3 * 1600m^2[/tex]
[tex]A = 4,800m^2[/tex]
What is the result of adding these two equations?
62 + 2y = -2
3x - 2y = -5
Answer:
x = -7/9; y = 4/3.
Step-by-step explanation:
I will assume that the top equation is 6x + 2y = -2, and the bottom one is 3x - 2y = -5.
If you add the two...
(6x + 3x) + (2y + (-2y)) = (-2 + (-5))
9x + 0 = -7
9x = -7
x = -7/9
6(-7/9) + 2y = -2
-42/9 + 2y = -18/9
2y = 24/9
y = 24/18
y = 12/9
y = 4/3
Hope this helps!
At a central train station, there are 4 different train routes with trains that leave every 6 minutes, 10 minutes, 12 minutes, and 15 minutes. If each train can hold up to 200 passengers, what is the maximum number of passengers who can leave the station on a train in one hour?
Answer:
5,000 passengers
Step-by-step explanation:
1. Find out how many trains leave each hour.
6 min – 60/6 = 10 x 200 passengers = 2000
10 min – 60/10 = 6 x 200 passengers = 1200
12 min – 60/12 = 5 x 200 passengers = 1000
15 min – 60/15 = 4 x 200 passengers = 800
2. Add it all up.
2000 + 1200 + 1000 + 800 = 5000 passengers
Answer:
5000
Step-by-step explanation:
6 minute train leaves 10 times
10 x 200 = 2000 passengers
10 minute train leaves 6 times
6x200 = 1200
12 minute train leaves 5 times
5x200 =1000
15 minute train leaves 4 times
4x200 =800
2000+1200+1000+800=5000
assuming more than 1 train can be at the station at once
Simplify each expression.
1) 3(8Z² - 52 - 7)
2) 8d(2d-4)
6) 6(5x - 4)
7) 6q- 4
Answer:
1) 24Z^2 - 177.
2) 16d^2 - 32d.
6) 30x - 24.
7) 6q - 4.
Step-by-step explanation:
1) 3(8Z^2 - 52 - 7)
= 3(8Z^2 - 59)
= 24Z^2 - 177
2) 8d(2d - 4)
= (8d * 2d) - (8d * 4)
= 16d^2 - 32d
6) 6(5x - 4)
= (6 * 5x) - (6 * 4)
= 30x - 24
7) Already simplified. 6q - 4.
Hope this helps!
In a different plan for area codes the first digit could be any number from 3 through 6 the second digit was either 5,6,7 or 8 and the third digit could be any number except 5. With this plan how many different area codes are possible?
Answer:
144 codes are possible
Step-by-step explanation:
Okay for the first digit, we shall be selecting one out of 3,4,5,6.
Meaning we are selecting one out of four choices
The number of ways this can be done is 4C1 ways = 4 ways
For the second digit, we have 5,6,7 or 8, we are still selecting 1 out of 4 selections and the number of ways we can do this is also 4 ways
And lastly , we can choose any digit for the last number expect 5 , so from 0 to 9, we are removing 1 which means we are left with 9 choices
So the number of different area codes possible are ; 9 * 4 * 4 = 144 codes
130 students choose to attend one of three after school activities: football, tennis or running. There are 58 boys. 49 students choose football, of which 27 are girls. 27 students choose tennis. 24 girls choose running. A student is selected at random. What is the probability this student chose running? Give your answer in its simplest form.
Answer: [tex]\dfrac{27}{65}[/tex]
Step-by-step explanation:
There are 130 students.
There are 58 boys --> 72 girls
A) 49 chose football: 27 are girls --> 22 are boys
B) 72 girls: 24 chose running, 27 chose football --> 21 girls chose tennis
C) 27 students chose tennis: 21 are girls --> 6 are boys.
D) 58 boys: 22 chose football, 6 chose tennis --> 30 boys chose running.
[tex]\large\boxed{\begin{array}{l|cc||c}&\underline{Boys}&\underline{Girls}&\underline{Total}\\Football&22&27&49\\Tennis&6&21&27\\\underline{Running}&\underline{\quad 30\quad}&\underline{\quad 24\quad}&\underline{\quad 54\quad}\\Total&58&72&130\end{array}}[/tex]
Total running = 30 boys + 24 girls = 54
Total students = 130
[tex]\dfrac{\text{Total running}}{\text{Total students}}=\dfrac{54}{130}\quad \rightarrow \large\boxed{\dfrac{27}{65}}[/tex]
Solve sin 20 = COS CE-30)
Answer:
CE = 100°
Step-by-step explanation:
Using the cofunction identity
sin x = cos(90 - x)
Given x = 20°, then 90° - 20° = 70° thus
CE - 30 = 70° ( add 30 to both sides )
CE = 100°
Thus
sin20° = cos(100 - 30)° = cos70°
Answer:
CE = 100
have a nice day!
Step-by-step explanation:
Dan believes he can use the information given in the diagram and the SAS rule to prove the two triangles are congruent. Is he correct? Explain.
Answer:
Yes. There are two pairs of congruent sides and a pair of congruent angles. This follows the SAS rule.
griffin ordered a pair of sneakers online. he had 16 credit that he applied toward the purchase, and then he used a credit card to pay for the rest of the cost. if the the shoes cost 80, then how much did griffin charge to his credit card when he bought the sneakers? PLEASE ANSWER I BEG Y'ALL
Answer: Griffin charge $79.854 to his credit card when he bought the sneakers.
Step-by-step explanation:
Griffin ordered a pair of sneakers online.
Value of each credit point = 1 cent
Then , value of 16 credit points = 16 cents = $0.16 [1$ = 100 cents]
Cost of shoes = Rs $80
Charge to credit card = (Cost of shoes) - (Value of 16 credit points)
= $(80-0.16)
= $79.84
Hence, Griffin charge $79.854 to his credit card when he bought the sneakers.
Consider the functions. F(x)=(x+1)2-4 and g(x)=-4|x+1| which statement compares the range of the functions?
Answer:
The fourthStep-by-step explanation:
Vertex of f is (-1, -4) so its range is limited to y≥-4
|x+1| is always ≥0 therefore -|x+1| is always ≤0 {4 is insignificant to this - slope doesn't mean in range} so its range is limited to y≤0
Answer:
D
Step-by-step explanation:
i just took the test
Which best describes the relationship between the lines with equations 5x +y = 4 and 20.0 + 4y = 16?
Answer:
There is no relationship, except they do intersect at the point (1, -1). Hope this helps :)
Brainliest?
Both given lines are going to intersect at ( 1,-1 ) that's it.
What is a line segment?A line section that can connect two places is referred to as a segment.
The line is here! It extends endlessly in both directions and has no beginning or conclusion.
In other words, a line segment is just part of a big line that is straight and going unlimited in both directions.
Given that
Line 1 ; 5x +y = 4
Line 2 ; 20 + 4y = 16 ⇒ y = -1
At y = -1 the first line is
5x - 1 = 4 ⇒ x = 1
So,
It is clear that line 1 has a point ( 1 .-1 ) and line 2 also passes
through it hence there will an intersection.
For more about line segment
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List some typical benefits an employee might receive on top of their wage?
Answer:
paid vacation
paid medical
401k
PLS HELP !! I’ll appreciate it
In a two-column proof, what would you write in the reason column for any statement that is given to
you?
Answer:
explanation
Step-by-step explanation:
the reason for your statement is just your explanation of why you think that.
What the answer question
its b the answer is b
Answer:
the answer on the B
Step-by-step explanation:
what is the value of "c" by completing the square. x^2 - 14x +
Answer:
[tex]\large\boxed{\sf \ \ 49 \ \ }[/tex]
Step-by-step explanation:
Hello,
we need to get the discriminant = 0 meaning
[tex]\Delta = b^2-4ac = 0\\\\<=>14^2-4c=0\\\\<=>c=\dfrac{196}{4}=49[/tex]
And then the square is
[tex]x^2-2\cdot 7\cdot x+7^2=(x-7)^2[/tex]
Hope this helps
My age if I am half as old as two more than twice Mack's age if Mack is m years old.
Answer:
You are m + 1 years old.
Step-by-step explanation:
Let's say that you are x years old, and Mack is m years old.
x = 1/2( two plus twice m)
x = 1/2(2 + 2m)
x = 1 + m
x = m + 1
Hope this helps!
find the value of x and y if the distance of the point (x,y) from (-2,0) and (2,0) are both 14 units.
Answer:
[tex] (0, 8\sqrt{3}) [/tex] and [tex] (0, -8\sqrt{3}) [/tex] are both 14 units from points (-2, 0) and (2, 0).
Step-by-step explanation:
distance formula
[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
We want the distance, d, from points (-2, 0) and (2, 0) to be 14.
Point (-2, 0):
[tex] 14 = \sqrt{(x - (-2))^2 + (y - 0)^2} [/tex]
[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]
Point (2, 0):
[tex] 14 = \sqrt{(x - 2)^2 + (y - 0)^2} [/tex]
[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]
We have a system of equations:
[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]
[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]
Since the right sides of both equations are equal, we set the left sides equal.
[tex] \sqrt{(x + 2)^2 + y^2} = \sqrt{(x - 2)^2 + y^2} [/tex]
Square both sides:
[tex] (x + 2)^2 + y^2 = (x - 2)^2 + y^2 [/tex]
Square the binomials and combine like terms.
[tex] x^2 + 4x + 4 + y^2 = x^2 - 4x + 4 + y^2 [/tex]
[tex] 4x = -4x [/tex]
[tex] 8x = 0 [/tex]
[tex] x = 0 [/tex]
Now we substitute x = 0 in the first equation of the system of equations:
[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]
[tex] \sqrt{(0 + 2)^2 + y^2} = 14 [/tex]
[tex] \sqrt{4 + y^2} = 14 [/tex]
Square both sides.
[tex] y^2 + 4 = 196 [/tex]
[tex] y^2 = 192 [/tex]
[tex] y = \pm \sqrt{192} [/tex]
[tex] y = \pm \sqrt{64 \times 3} [/tex]
[tex] y = \pm 8\sqrt{3} [/tex]
The points are:
[tex] (0, 8\sqrt{3}) [/tex] and [tex] (0, -8\sqrt{3}) [/tex]