slope line in simplest form​

Answer:

Point D

because you go 5 to the right and 3 down.

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Answer: -6 You answered your own question-

Answer:

2/7, 3/7

Step-by-step explanation:

Total outcomes=7

No. 6 outcomes=2

P(E)= Favourable outcomes/total outcomes

    =2/7

Total even no.= 3

∴ P(E)= 3/7

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Answer:

16√3 cm²

Step-by-step explanation:

The perimeter of a triangle is the sum of its all three sides. Since this is an equilateral triangle, all sides are equal.

Let's consider one side of the triangle to be 'x'

Givent that, the perimeter is 24cm,

The equation should be x + x + x = 24

⇒3x = 24

∴ x = 8 cm

To find the area of the triangle, we need to find the height, and for that, we can use trigonometry.

Since it is an equilateral triangle, all angles are exact 60°.

let's draw a line and mark it as 'h'.

we can use sine formula to find out the opposite i.e. h

sin∅ = opposite ÷ hypotaneous

sin 60° = h ÷ 8

h = 8 sin 60°

h= 4√3

Now, let's find the area

Area = 1/2 × base × height

Area = 1/2 × 8 × 4√3

area= 16√3 cm²

Answer:

Step-by-step explanation:

P = pizza slices

S= soda drinks

98 = 23*P + 31*S

Answer:

-17

Step-by-step explanation:

The angles are corresponding angles so when the lines are parallel, the lines are equal

3x-12 = 4x+5

Subtract 3x from each side

3x-12 -3x = 4x+5-3x

-12 = x+5

Subtract 5 from each side

-12 -5 = x+5-5

-17 = x

Answer:

-17

Step-by-step explanation:

The two angles that are shown are *corresponding angles* which means they lie in the same spot, just on two different parallel lines. They are congruent angles. Therefore, you should set up an equation to solve for x. Since the two angles are congruent, you should set the expressions equal to each other. 3x-12=4x+5.

Answer:

C.

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

the line is perpendicular to y=1/2x-3

so its gradient, m, would be -2 (m¹m²= -1)

sub the coordinates and the gradient into this equation to find the equation of line in slope intercept form

y-y¹ = m(x-x¹)

The equation of the line  in slope-intercept form that passes through (-2,2) and is perpendicular to the graph of y= 1/2x-3 is; y = -2x - 2

The equation of the straight line has its slope and given point.

If we have a non-vertical line that passes through any point(x1, y1) and has a gradient m. then general point (x, y) must satisfy the equation

y-y₁ = m(x-x₁)

Where x₁ - x coordinate, y₁ - y coordinate, m - slope

Point (-2,2)

Then the equation of a line perpendicular to the graph of y= 1/2x-3.

its gradient, m, would be; -2 (m¹m²= -1)

Now Write the equation as;

y-y₁ = m(x-x₁)

y - 2= -2(x + 2)

y = -2x - 2

Hence, the equation of the line  in slope-intercept form that passes through (-2,2) and is perpendicular to the graph of y= 1/2x-3 is; y = -2x - 2

Learn more about equations here;

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Answer:

x = 35

Step-by-step explanation:

x - 13 = 22

Add 13 to each side

x - 13+13 = 22+13

x = 35

See attachment for math work and answer.

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Answer:

your answer should be, D.135

i hope this helps!

Answer:

D) 135

Step-by-step explanation:

--------------- = 180 degrees

It's split and the other half is 45 degrees.

All you have to do is subtract.

180-45=135

<8 = D) 135

Answer:

Y=4/3x - 4

Step-by-step explanation:

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of the given line is y=(4/3)x-4.

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is the y-intercept.

The slope of the line can be calculated with the two points that are present on the line, in this case, these points are (3,0) and (0, -4). Therefore, the slope is,

Slope, m = (-4 - 0)/(0 - 3) = -4/-3 = 4/3

The y-intercept of the line is -4, therefore, the equation of the line can be written as,

y = mx + c

y = (4/3)x - 4

Hence, the equation of the given line is y=(4/3)x-4.

Learn more about Equation of Line here:

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Answer:

V=72x³y³

Step-by-step explanation:

The formula to apply is;

V= l * w * h where

V= volume in units cubed.

l= length = 3xy

w=width = 4xy

h= height = 6xy

Substitute values in the formula as;

V= l*w*h

V=3xy * 4xy * 6xy ----find product for the numbers {3*4*6=72} then multiply by the product for x's {x*x*x =x³} that of y's {y*y*y=y³}

V= 72*x³*y³

V= 72x³y³  --------where xy are the units used.

Answer:

the answer is C. lake Texoma

hope this helps

Answer:

a

Step-by-step explanation:

:)

Answer:

The volume of the swimming pool is approximately 2475 yd³ to the nearest whole number

Step-by-step explanation:

The given information are;

The width of the swimming pool = 75 ft. 1 in.

The length of swimming pool = 60 ft.

The depth of the swimming pool = 14 ft. 10 in.

Therefore;

The volume of the swimming pool = Width × Length × Depth

The volume of the swimming pool = 75 ft. 1 in. × 60 ft. × 14 ft. 10 in.

The volume of the swimming pool = 901 in. × 720 in. × 178 in. = 115472160 in.³

1 in.³ = 2.14335 × 10⁻⁵ yd³

∴ 115472160 in.³ = 115472160 in.³  × 2.14335 × 10⁻⁵ yd³/in³ ≈ 2474.969 yd³

Which gives;

The volume of the swimming pool ≈ 2475 yd³ to the nearest whole number.

Given :

Carson was shopping online for bow ties to wear with his school uniform he bought a certain number of ties that each cost $12.50 and paid a flat rate of 19 for shipping and handling.

He has $220 in his bank account before buying the tie.

To Find :

Maximum number of ties he can buy.

Solution :

Let, price of buying x ties is y.

y = 19 + (12.50)x

It is given that he has $200 in his bank account.

So, price of buying tie ≤ $200

y ≤ 200

19 + (12.50)x ≤ 200

(12.50)x ≤ 200 - 19

x ≤ 14.48

Since, number of tie cannot be in decimal.

x ≤ 14

Therefore, maximum tie he can buy is 14.

Hence, this is the required solution.

Answer: Choice B

h(c) = 1 for at least one c between -3 and 4

====================================================

Explanation:

Draw an xy axis system. Plot the points (-3,-1) and (4,2) on this grid. These points come from the fact that h(-3) = -1 and h(4) = 2. These are the endpoints of the h(x) function.

Next, draw horizontal lines through both points. Also, draw vertical lines through the two points as well. A rectangle will form.

The region inside this rectangle is all we care about.

We're told that h(x) has endpoints mentioned earlier, and h(x) is continuous, so that means we have some curve or line through the two points. One such example is shown below. There are infinitely many possible curves to draw out as long as they stay in the rectangle.

----------------------

After you have your h(x) function curve drawn, draw a horizontal line through y = 1 on the y axis. This is the dashed line in the diagram below.

This horizontal line crosses the green h(x) curve at one point or more. In my example, it does so at one point only. However, you could easily draw h(x) so that it crosses y = 1 as many times as you want (just have it squiggle up and down multiple times).

This shows that h(c) = 1 is possible when [tex]-3 \le c \le 4[/tex]. Here c is playing the role of x since it is the input of a function. The h(c) is the output, so that's the y value.

This says that for some input between -3 and 4, it's possible to get an output of 1.

-------------------------

Here's a real world example of the intermediate value theorem.

Let's say the endpoints are A and B, and they are two towns.

The h(x) curve is a road connecting the towns.

To go from A to B, or vice versa, we need to cross over some border that is between the towns. The border in this case is the dashed horizontal line in the diagram.

side note: A special use of the intermediate value theorem is to show that a root exists on some interval (if you know the function changes between positive to negative, or vice versa).

Answer

There are two common ways of describing or specifying the members of a set: roster notation and set builder notation. These are examples of extensional and intensional definitions of sets, respectively