Social media is popular around the world. Statista provides estimate of the number of social media users in various countries in 2017 as well as the projections for 2022. Assume that the results for surveys in the United Kingdom, China, Russia, and the United States are as follows. Excel File: data 12-23.xlsx Country Use Social United United Media Kingdom China Russia States Yes 480 215 343 640 No 320 285 357 360 a. Conduct a hypothesis test to determine whether the proportion of adults using social media is equal for all four countries. Using a 0.05 level of significance. 1. H. : P1 + P2 = P3 = P4 2. H. : P1 = P2 = P3 = P4 3. H. : P1 + P2 = P3 + P4 Choos correct answer from above choice 2 + Ha: Not all population proportions are equal What is the p-value?

Answer:

x=2 or x=-4. You can also write it as x=2,-4

Step-by-step explanation:

Write your equation and start by subtracting 9 from both sides

10x^2+20x-71-9=9-9

You should end up with

10x^2+20x-80=0

For this equation: a=10, b=20, c=-80

Now we use the quadratic formula and substitute the information. I have attached a picture for you.

When the width is 4 inches, the area of the photograph is 20 square inches.

To write a polynomial that represents the area of the photograph, we need to use the formula for the area of a rectangle, which is A = l x w (where A is the area, l is the length, and w is the width).

From the given information, we know that the length (l) is 3 inches less than twice the width (w). So, we can write:

l = 2w - 3

Substituting this expression for l into the formula for the area, we get:

A = (2w - 3) x w

Simplifying this expression, we get:

A = 2w^2 - 3w

This is the polynomial that represents the area of the photograph.

To find the area of the photograph when the width is 4 inches, we simply need to substitute w = 4 into the polynomial we just found:

A = 2(4)^2 - 3(4)
A = 32 - 12
A = 20

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The only options that are quadratic functions are:

Option A:  5x² + 15 x = 0

Option C: x² - 4x = 4 x + 7

Option E: 3x² + 5 x - 7 = 0

The general form of expression of quadratic functions is:

y = ax² + bx + c

where:

a, b, and c are numbers with a not equal to zero.

The graph of a quadratic function is a curve called a parabola.

Looking at the given options, it is clear that:

6 x - 1 = 4x + 7 is not a quadratic equation because it has only one degree.

2 x - 1 = 0 is a linear equation and not a quadratic equation

x³ - 2 x² + 1 = 0 is a cubic polynomial as it has three degrees.

Thus, only options A, C and E are quadratic equations with two degrees.

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1. The width is  7 1/9 feet

2. The number of containers is  10 9/16 containers

3. The length is 15/8 miles

4. 15/184 servings

The formula for determining the area of a rectangle is expressed as;

A = lw

Given that the parameters are;

We have that;

1. Substitute the values

32 = 9/2w

Make the width subject of formula

32× 2/9 = w

Multiply the values

w = 64/9 = 7 1/9 feet

2. To determine the value, we have;

Area = 13/2 × 13/8

Multiply the values

Area = 169/16

Divide the values

Area = 10 9/16 containers

3. The area is 15/56

Width = 1/7

Then

Length = area/width

Length = 15/56 × 7/1

Multiply the values

Length = 15/8 miles

4. We have that;

1 serving = 5/4

then x = 46/3

cross multiply the values

x = 5/4 × 3/46

Multiply the values

x = 15/184 servings

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The volume of the smaller triangular prism is calculated as:

= 9.6 cubic cm.

To find the volume of similar triangular prisms, recall that:

the cube of the ratio of their linear measures = the ratio of their volumes.

Given the following:

ratio of the linear measures of the two similar triangular prisms = 2/5

Volume of the larger prism = 150 cubic cm

Volume of the smaller prism = x

Set up the equation as shown below:

2³ / 5³ = x / 150

8/125 = x/150

Cross multiply:

125x = 8 * 150

125x = 1,200

x = 1,200/125

x = 9.6 cubic cm.

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[tex]\angle AQO + \angle OQB = 120^\circ$, so $\boxed{\theta = 60^\circ}$[/tex] is the solution.

Let's first draw a diagram to visualize the problem:

Since [tex]$\triangle ABC$[/tex] is isosceles, we have [tex]$\angle BAC = \angle BCA = \theta$[/tex] and [tex]$\angle ABC = 180^\circ - 2\theta$[/tex]. Let O be the center of the circle, and let D and E be the points of tangency of the tangents through A and C, respectively.

Since [tex]$AD$[/tex] and [tex]$CE$[/tex] are tangents to the circle, we have [tex]$OD \perp AD$[/tex] and [tex]$OE \perp CE$[/tex]. Since [tex]$AO$[/tex] and [tex]$CO$[/tex] are radii of the circle, we have [tex]$AO \perp BC$[/tex] and [tex]$CO \perp AB$[/tex].

Therefore, [tex]$OD \parallel CO$[/tex] and [tex]$OE \parallel AO$[/tex]. It follows that [tex]$\angle DOB = \angle COB = \theta$[/tex], and [tex]$\angle EOA = \angle AOB = \theta$[/tex].

Thus, [tex]$\angle DOA = \angle EOC = \theta$[/tex], and [tex]$\angle AOE = \angle DOC = \theta$[/tex].

Now, consider the quadrilateral [tex]$AODE$[/tex]. Since [tex]$\angle AOE = \angle DOA = \theta$[/tex], we have [tex]$\angle OAE = \angle ODE = 90^\circ - \theta$[/tex]. Similarly, [tex]$\angle OCE = \angle OED = 90^\circ - \theta$[/tex]. Since [tex]$\triangle ABC$[/tex] is isosceles, we have [tex]$AB = BC$[/tex], so [tex]$AD = EC$[/tex].

It follows that [tex]$\triangle AOD \cong \triangle CEO$[/tex] by SAS congruence.

Therefore, [tex]$AO = CO$[/tex], so [tex]$\triangle AOB$[/tex] and [tex]$\triangle COB$[/tex] are congruent by SAS congruence.

Thus, [tex]$AB = BC$[/tex], so [tex]$\triangle ABC$[/tex] is equilateral.

Therefore, [tex]$\theta = 60^\circ$[/tex].

Finally, since [tex]$\angle AOB = \theta = 60^\circ$[/tex], we have [tex]$\frac{1}{2}\angle APB = \theta = 60^\circ$[/tex], so [tex]$\angle APB = 120^\circ$[/tex].

Therefore, [tex]$\angle APQ = \angle BPQ = \frac{1}{2}(180^\circ - \angle APB) = 30^\circ$[/tex]. Since [tex]$\triangle APQ$[/tex] is isosceles, we have [tex]$\angle QAP = \angle QPA = \frac{1}{2}(180^\circ - \angle APQ) = 75^\circ$[/tex].

Therefore, [tex]$\angle AQP = \angle BQP = 105^\circ$[/tex], so [tex]$\angle AQB = 2\angle BQP = 210^\circ$[/tex].

Thus, [tex]$\angle AQO = \frac{1}{2}(360^\circ - \angle AQB) = 75^\circ$[/tex], and [tex]$\angle OQB = \frac{1}{2}(180^\circ - \angle AQB) = 45^\circ$[/tex].

Therefore, [tex]\angle AQO + \angle OQB = 120^\circ$, so $\boxed{\theta = 60^\circ}$[/tex] is the solution.

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The balance of the account after 20 years with continuous compounding interest is $733.86.

The formula accrued amount compounded continuously is expressed as;

A = P × e^(rt)

Where A is accrued amount, P is principal, r is interest rate and t is time.

Given that:

First, convert R as a percent to r as a decimal

r = R/100

r = 6.5/100

r = 0.065

Plugging in the given values, we get:

A = P × e^(rt)
A = $200 × e^( 0.065 × 20)

A = $733.86

Therefore, the accrued amount after 20 years is $733.86.

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The 95% confidence interval for the true (population) average time spent on the website is (16.08, 23.92) minutes. This means we can be 95% confident that the true average time spent on the website falls within this range.

To estimate the true (population) average time spent on the Relentless.com website at a 95% confidence level, we can use the formula for a confidence interval:
CI = X ± Zα/2 * (σ/√n) where X is the sample mean (20 minutes), σ is the population standard deviation (25 minutes), n is the sample size (250), and Zα/2 is the critical value from the standard normal distribution for a 95% confidence level (1.96).
Plugging in the values, we get:
CI = 20 ± 1.96 * (25/√250)
Simplifying, we get:
CI = 20 ± 3.92

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True. If v is an eigenvector of A with eigenvalue λ, then for any scalar c ≠ 0, we have Av = λv, and multiplying both sides by c gives Acv = cAv = cλv. Therefore, cv is also an eigenvector of A with eigenvalue cλ.

Let A be an n x n matrix and let v be a non-zero n-dimensional column vector. We say that v is an eigenvector of A if there exists a scalar λ such that Av = λv. The scalar λ is called the eigenvalue corresponding to the eigenvector v.

Now, suppose that v is an eigenvector of A with eigenvalue λ. If we multiply both sides of the equation Av = λv by a non-zero scalar c, we get:

Acv = cAv = cλv

Therefore, if we let w = cv, we have:

Aw = A(cv) = (Ac)v = (cλ)v = λ(cv) = λw

This shows that w = cv is also an eigenvector of A, with eigenvalue λ, as required. So, if v is an eigenvector of A, then any non-zero scalar multiple of v is also an eigenvector of A with the same eigenvalue.

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The situation where we can approximate the sampling distribution with a normal distribution is Op = .90 and n = 32.

In order to approximate the sampling distribution with a normal distribution, both of the following conditions must be satisfied:

The sample size n must be large enough (typically, n >= 30).

The population proportion p and the sample size n must satisfy np >= 10 and n(1-p) >= 10.

Let's check these conditions for each of the given situations:

Op = 24 and n = 30: Since np = 24*30/100 = 7.2 < 10 and n(1-p) = 22.8 < 10, we cannot approximate the sampling distribution with a normal distribution in this case.

Op = .90 and n = 32: Since np = 28.8 >= 10 and n(1-p) = 3.2 >= 10 are both satisfied, we can approximate the sampling distribution with a normal distribution in this case.

Op = .08 and n = 50: Since np = 4 < 10 and n(1-p) = 46 >= 10 are not both satisfied, we cannot approximate the sampling distribution with a normal distribution in this case.

Op = .70 and n=9: Since np = 6.3 >= 10 and n(1-p) = 2.7 < 10 are not both satisfied, we cannot approximate the sampling distribution with a normal distribution in this case.

Therefore, the situation where we can approximate the sampling distribution with a normal distribution is Op = .90 and n = 32.

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The balance after 12 years with an interest rate of 8.4% compounded monthly on $6500 is $7,046

The Amount after compound interest is calculated by

[tex]A=P(1+\frac{r}{n})^t[/tex]

where A is the Amount

P is the Principal

r is the Interest rate (in decimals)

n is the frequency at which the interest is compounded per year

t is the Time duration

According to the question,

Principal = $6500

interest rate = 8.4% compound monthly

Since interest is compounded monthly, n = 12

Time duration = 12 years

Therefore, A = [tex]6500(1+\frac{0.084}{12})^{12}[/tex]

= 6500 (1.007[tex])^{12[/tex]

= 6500 * 1.084

= $7,046

Hence, the balance is $7,046.

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The value of the given input function for F(x) = 12/x + 1/2 is found to be 4.5, -0.5, 36.5 and 16 is respectively.

To find the values of the function F(x) for the given inputs, we simply substitute the inputs into the formula,

F(x) = 12/x + 1/2

a) F(3)

Substituting x = 3, we get,

F(3)

= 12/3+1/2

= 4+0.5

= 4.5

b) F(-12)

Substituting x = -12, we get,

F(-12) = 12/(-12)+1/2

=-1+0.5

= -0.5

c) F(1/3)

Substituting x = 1/3, we get,

F(1/3)

= 12/(1/3)+1/2

= 36+0.5

= 36.5

d) F(3/4)

Substituting x = 3/4, we get:

F(3/4)

= 12/(3/4)+1/2

= 16+0.5

= 16.5

The above are the value of all the given input functions.

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Complete question - The function F is defined by F(x)= 12/x + 1/2 . Use this formula to find the following values of the function.

F(3)

F(−12)

F( 1/3 )

F( 3/4 )

Sampling in statistics provides us with data to make inferences about a larger population. It helps to reduce uncertainty and allows for more efficient data analysis. As the sample size increases, the variability decreases, making it easier to estimate population parameters. Remember, though, that not every sample is normally distributed, and sample parameters can still vary.

Sampling in statistics refers to the process of selecting a subset of individuals or objects from a larger population in order to make inferences or draw conclusions about the population. One true statement about sampling in statistics is that sample values are estimated from known population parameters. This means that statistical analysis is based on the assumption that the sample is representative of the population and that the values obtained from the sample can be used to estimate the values in the population. Another true statement is that as the sample size increases, the variability decreases. This is because larger samples are more likely to include a diverse range of individuals or objects, which can help to reduce the impact of outliers or unusual values. However, it is important to note that variability can still exist in larger samples, and statistical techniques such as standard deviation and confidence intervals can be used to assess the level of uncertainty. It is also important to note that not every sample is normally distributed, and techniques such as bootstrapping or non-parametric tests may be necessary in such cases. Overall, sampling is a crucial aspect of statistical analysis, and careful consideration of sample size and representativeness is essential for obtaining accurate and meaningful results.
In statistics, sampling is a method used to gather data from a subset of a larger population, allowing us to make inferences about the whole population. Sampling is important because it enables us to collect and analyze data in a more efficient and cost-effective manner, rather than attempting to study the entire population.
As the sample size increases, the variability of the sample typically decreases. This means that larger samples provide more accurate estimates of population parameters, reducing the uncertainty associated with making inferences. However, it is important to note that sample parameters can still vary and are not always known, which is why we use statistical techniques to estimate them.
Sample values are indeed estimated from known population parameters, and these estimates help us to understand the underlying population characteristics. However, it is not accurate to say that every sample is normally distributed. The distribution of a sample depends on the characteristics of the population and the sampling method employed.
In conclusion, sampling in statistics provides us with data to make inferences about a larger population. It helps to reduce uncertainty and allows for more efficient data analysis. As the sample size increases, the variability decreases, making it easier to estimate population parameters. Remember, though, that not every sample is normally distributed, and sample parameters can still vary.

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The amount of fabric that is needed for the tent is 18350 in² (optionC)

A prism is a solid shape that is bound on all its sides by plane faces. The surface area of a prism is expressed as ;

SA = 2B +pH

where B is the base area , p is the perimeter of the base and H is the height of the prism.

Base area =1/2bh

= 1/2 × 50× 70

= 25 × 70

= 1750in²

Perimeter of the base = 74+74+50

= 198 in

height = 75in

Therefore SA = 2×1750 +198 × 75

= 3500 + 14850

= 18350 in²

therefore the amount of fabric that will be needed nis 18350 in²

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The perimeter of the bottom of the storage container is,

⇒ 24 feet

We have to given that;

The storage container has a length of 7 feet and a width of 5 feet.

Hence, we get;

The perimeter of the bottom of the storage container is,

⇒ 2 (7 + 5)

⇒ 2 × 12

⇒ 24 feet

Thus, The perimeter of the bottom of the storage container is,

⇒ 24 feet

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The equation of the axis of symmetry for the parabola is x = 4.

In this problem we find the representation of a parabola whose axis of symmetry is parallel with the y-axis, the formula of the parabola is:

y = a · x² + b · x + c

Where:

And the axis of symmetry of the parabola is shown below:

x = h

Where h is the x-coordinate of the vertex.

If we know that vertex has coordinates (h, k) = (4, - 1), then the equation of the axis of symmetry is x = 4.

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The probability that one marble is red and the other is white when two marbles are selected from the bag is 3/7

To find the probability that one marble is red and the other is white when two marbles are selected from a bag containing 6 red and 2 white marbles, you can use the following formula:

P(Red and White) = P(Red first) * P(White second) + P(White first) * P(Red second)

In this case:

P(Red first) = 6/8 (since there are 6 red marbles and a total of 8 marbles)
P(White second) = 2/7 (after removing one red marble, there are 2 white marbles and a total of 7 marbles left)

P(White first) = 2/8 (since there are 2 white marbles and a total of 8 marbles)
P(Red second) = 6/7 (after removing one white marble, there are 6 red marbles and a total of 7 marbles left)

Now, substitute these values into the formula:

P(Red and White) = (6/8) * (2/7) + (2/8) * (6/7) = (12/56) + (12/56) = 24/56

Simplify the fraction:

P(Red and White) = 3/7

So, the probability that one marble is red and the other is white when two marbles are selected from the bag is 3/7.

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The value of each variable in the given circle are:

a = 65.5°    b = 90°    c = 49°

In order to find the value of each variable in the given circle, recall the following:

Find a:

a = 1/2(131)

a = 65.5°

Find b:

b is an inscribed angel of half of the circle, therefore:

b = 90°

Find c:

c = 180 - 131

c = 49°

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Answer:

To find the solutions to this system of equations, we need to set f(x) equal to each other and solve for x.

x² - 2x - 15 = -x - 9

Simplifying and solving for x, we get:

x² - x - 6 = 0

Factoring the left side, we get:

(x - 3)(x + 2) = 0

So, the solutions are x = 3 and x = -2.

To find the corresponding y values, we can plug these x values back into either of the original equations. Using f(x) = x² - 2x - 15, we get:

f(3) = 3² - 2(3) - 15 = -3

f(-2) = (-2)² - 2(-2) - 15 = -9

Therefore, the ordered pair solutions for the system of equations are (3, -3) and (-2, -9).

To test the hospital recruiting company's claim, we can use a one-sample t-test with a null hypothesis that the population mean salary is equal to $86,000 and an alternative hypothesis that the population mean salary is greater than $86,000.

Using the given sample of 26 doctors' salaries, we can calculate the sample mean and standard deviation. The sample mean is $91,000 and the sample standard deviation is $12,000.

Next, we need to calculate the t-statistic using the formula:

t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))

Plugging in the values, we get:

t = ($91,000 - $86,000) / ($12,000 / sqrt(26))
t = 2.34

Using a t-table with 25 degrees of freedom (26-1), we can find the critical value for a one-tailed test at a 5% level of significance. The critical value is 1.711.

Since our calculated t-value of 2.34 is greater than the critical value of 1.711, we reject the null hypothesis and conclude that there is evidence to support the claim that the average doctor's salary is significantly more than $86,000 at a 5% level of significance.

Therefore, the hospital recruiting company's claim is supported by the given sample data.

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we know that

P (A or B) = P(A) + P(B) -P (A and B)

putting values we get

P (A or B) = 0.2 + 0.3 - 0.1

P (A or B)= 0.4

hence the ans. = 0.4

The surface area of the pylon, obtained by considering the pylon as a composite figure consisting of a prism and a pyramid is 1824 square inches

A composite figure is a figure that consists of two or more regular or simpler figures.

The surface area of the pylon can be considered as a composite figure consisting of a square prism and a pyramid

The surface area of the accessible part of the square pyramid is; A = 2 × (30 × 12 + 30 × 12 + 12 × 12) - 12 × 12 = 1584

The surface area of the square pyramid part is 1584 in²

The surface area of the prism, A = 4 × (1/2) × 12 × 10 = 240

The surface area of the prism is 240 in²

The surface area of the pylon is therefore;

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If {v1, v2, v3} is an orthonormal basis for a subspace W of a vector space V, then multiplying v3 by a non-zero scalar c does not necessarily give a new orthonormal basis for W.

To see why, consider the dot product of cv3 with itself. If v3 is an orthonormal vector, then its norm is 1, so the dot product of cv3 with itself is (cv3) • (cv3) = c^2(v3 • v3) = c^2(1) = c^2. Thus, cv3 has a norm of |c|, rather than 1, and so it cannot be an element of an orthonormal basis for W.

However, multiplying v3 by a scalar does give a new basis for W. Specifically, {v1, v2, cv3} is a basis for W if c is non-zero, since v1 and v2 are orthogonal to cv3, and any vector in W can be written as a linear combination of these three vectors. But this new basis is not orthonormal, since cv3 has a norm of |c|. To obtain an orthonormal basis from this new basis, we can normalize each vector in the basis by dividing it by its norm.

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One possible null hypothesis for this paired sample study could be: "There is no significant difference in the amount of caffeine (in milligrams) ingested before and after lunch among the 45 volunteer citizens from the small community."

Based on your question, we can construct a null hypothesis for this paired sample study involving 45 volunteer citizens from a small community. The terms "studies," "samples," and "small" are included in the context of the question. Here's a possible null hypothesis:
Null Hypothesis (H0): There is no significant difference in the mean amount of caffeine ingested by the 45 volunteer citizens before and after lunch each day.

The null hypothesis is a statistical assumption that says there is no statistical significance in a group of observations. Hypothesis testing is used to test the reliability of a hypothesis using sample data. It is sometimes called "blank" and stands for H0. The null hypothesis, also known as the Conjecture, is used in quantitative analysis to test a theory about business, investment, or the economy to determine whether the idea is true or false.

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13 is the value of z from the given figure.

The properties of the triangle are:

From the given figure,

∠ABE + ∠EBC =. 180

∠EBC = 180- ∠ABE

∠EBC = 180 - 9z -----(1)

∠ECB + 115 = 180

∠ECB = 65-----(2)

IN ∆EBC

∠BEC + ∠ECB + ∠EBC = 180

4Z + 180- 9Z + 65 = 180 ---------(from eq i & ii)

-5Z = -65

Z = -65/-5y

Z = 13

The value of z from the given figure is 13.

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Complete question:

Yes, it is possible for a process to pass through the 2nd or 4th quadrant. The 2nd quadrant is characterized by negative values of work done and positive values of heat added.

This could happen in a scenario where a gas is compressed at a constant temperature, which results in negative work done, but heat is added to the gas to maintain its temperature. The 4th quadrant is characterized by negative values of both work done and heat added. This could happen in a scenario where a gas is expanded at a constant temperature, which results in negative work done and no heat is added or removed from the gas.

As for the effect of a negative value of the polytropic index 'n', it indicates that the process is non-adiabatic and not reversible. A negative value of 'n' means that the process is not able to maintain constant heat transfer or constant entropy. This could result in energy losses and a decrease in the efficiency of the process. It could also indicate that the process is not in equilibrium and is being driven by external forces. Overall, a negative value of 'n' can have negative effects on the performance and stability of a process.

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The solution of the logarithmic equation log16 - log8(x -5) is 55.

We can use the following logarithmic property to simplify the left side of the equation:

log a - log b = log (a/b)

Using this property, we can rewrite the left side of the equation as:

log (16/8(x-5)) = log (2(x-5))

So the equation becomes:

log (2(x-5)) = 2

To solve for x, we need to use another logarithmic property:

log a = b if and only if a = 10ᵇ

Using this property, we can rewrite the equation as:

2(x-5) = 10²

Simplifying:

2x - 10 = 100

2x = 110

x = 55

Therefore, the solution to the equation is x = 55.

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