Assuming the question is:
[tex]a=d+\frac{c}{b}[/tex]we need to solve for d.
We keep "d" to one side and simplify the other side for a formula for d. Shown below:
[tex]\begin{gathered} a=d+\frac{c}{b} \\ d=a-\frac{c}{b} \\ d=\frac{ab-c}{b} \end{gathered}[/tex]The lifespan of pet goldfish is a normally distributed random variable. The mean lifespan is 210 days with a standard deviation of 22 days.In a random sample of 50 pet goldfish, how many would you expect to live between 166 and 254 days?Your answer should include both a numerical component and a justification component.
Z-score is computed as follows:
[tex]z=\frac{x-\mu}{\sigma}_{}[/tex]where,
x: observed value
μ: mean
σ: standard deviation
Substituting with x = 166, μ = 210, and σ = 22, we get:
[tex]\begin{gathered} z_1=\frac{166-210}{22}_{} \\ z_1=-2 \end{gathered}[/tex]Substituting with x = 254, μ = 210, and σ = 22, we get:
[tex]\begin{gathered} z_2=\frac{254-210}{22}_{} \\ z_2=2 \end{gathered}[/tex]Now, we need to find P(-2From the above graph, P(-2This means that 95.44% of the sample is between the z-scores -2 and 2.
In the context of this problem, 50x95.44% = 47.72 ≈ 47 goldfish are expected to live between 166 and 254 days.
a. Assuming a linear relationship between year and salaries by gender, determine when the median annual salary for women will exceed men. Justify your answer. Include in the discussion the regression analysis you performed. b. Based on the answer you found in the above step, provide an argument pro or con to the statement “As the number of women exceed men in the number of bachelor degrees received, expect there to be a corresponding change in the median annual salaries for each gender
First We have to find the tendency for both cases individually. Let's calculate the equation of the line for each one.
For Men we take two points (year, salary) ( 2 , 35,308) ( 4 , 37076) With these points we are going to calculate the slope of the line.
[tex]m=\frac{y2-y1}{x2-x1}=\frac{37076-35308}{4-2}=884[/tex]Then, we have to calculate the intercept of the line with the slope and point (2, 35,308)
y= mx+ b
35,308 = 884*(2)+b
Isolating b,
35,308 - 1768 = b
33540=b
The first equation must be y = 884x +33540
For Women we take two points (year, salary) ( 2 , 27,508) ( 4 , 29,796 ) With these points we are going to calculate the slope of the line
[tex]m=\frac{y2-y1}{x2-x1}=\frac{29,796-27,508}{4-2}=1144[/tex]Then, we have to calculate the intercept of the line with the slope and point (2, 27,508)
y= mx+ b
27,508 = 1144*(2)+b
Isolating b,
27,508 - 2288 = b
25220=b
The second equation must be y = 1144x +25220
Now We are going to find the incercept of these equations, we are going to formulate the following equation
884x+33540 = 1144x+25220
33540-25220=1144x-884x ( Isolating terms with x)
8320=260x (Solving on each side)
8320/260 = x =32 ( Isolating x)
It implies that after 32 years Women would exceed men.
B. It seems that as the number of bachelor degrees of women exceeds men's number, the salary increases at a higher rate. So , the change would be greater for women than men every year.
A lime has a pH of 2.2. What is the hydrogen ion concentration? Round answers to four decimal places. Group of answer choices
The relationship between the PH of a solution and the hydrogen ion concentration is given by the formula:
[tex]PH=-\text{log\lbrack{}H}^+\rbrack[/tex]Given that the PH is 2.2, therefore,
[tex]undefined[/tex]Answer:
its 2.2
Step-by-step explanation:
Solving for x gives us x = ?The value for x cannot equal ?
Solving the rational equation, we have:
[tex]\begin{gathered} \frac{5}{x+1}+\frac{1}{x-3}=\frac{-6}{x^2-2x-3} \\ \frac{5(x-3)+1(x+1)}{(x+1)(x-3)}=\frac{-6}{(x+1)(x-3)} \\ 5x-15+x+1=-6 \\ 6x-14=-6 \\ 6x=-6+14 \\ 6x=8 \\ x=\frac{8}{6}=\frac{4}{3} \end{gathered}[/tex]So the solution is x = 4/3 = 1.33
Now let's calculate the values that x cannot be equal, calculating where the denominators of the fractions are equal to zero:
[tex]\begin{gathered} x+1\ne0\to x\ne-1 \\ x-3\ne0\to x\ne3 \end{gathered}[/tex]So x cannot be equal to -1 or 3.
A circle has diameter of 8 centimeters.What is the area, in square centimeters, of the circleA. 4πB. 8πC. 16π
The diameter of circle is d = 8 cm.
The formula for the area of circle is,
[tex]A=\frac{\pi\cdot(d)^2}{4}[/tex]Determine the area of circle.
[tex]\begin{gathered} A=\frac{\pi\cdot(8)^2}{4} \\ =16\pi \end{gathered}[/tex]Option C is correct.
The image below shows a parking lot support pole. The pole is cylinder-shaped with a spherical top. All sides, except for the bottom, will be painted. How much surface area is going to be painted?
Solution:
Given:
Since the bottom of the cylinder will not be painted and the top is spherical.
The top is a hemisphere. Hence, the surface area to be painted will be;
[tex]\begin{gathered} A=2\pi rh+2\pi r^2 \\ \\ where; \\ r=10in \\ h=26in \end{gathered}[/tex]Hence,
[tex]\begin{gathered} A=(2\times\pi\times10\times26)+(2\times\pi\times10^2) \\ A=520\pi+200\pi \\ A=720\pi\text{ sq in} \end{gathered}[/tex]Therfore, the surface area to be painted is ;
[tex]undefined[/tex]Decreasing the sample size while the confidence level remains the same, will do what to the length of your confidence interval?1. Make it smaller 2. Make it bigger 3. It will stay the same 4.cannot be determined from the given information
Explanation
Increasing the sample size decreases the width of confidence intervals because it decreases the standard error.
Explanation: Sample Size: Smaller sample sizes generate wider intervals. There is an inverse square root relationship between confidence intervals and sample sizes.
Larger samples give narrower intervals. We are able to estimate a population proportion more precisely with a larger sample size.
As the confidence level increases the width of the confidence interval also increases. A larger confidence level increases the chance that the correct value will be found in the confidence interval. This means that the interval is larger.
Thus, Decreasing the sample size while the confidence level remains the same, will make the length of the confidence interval Bigger
The answer is: Make it bigger
During game 3 of the basketball championships, San Antonio scored 97 points consisting of 2-point and 3-point baskets. If San Antonio made a total of 45 baskets, how many of each type did they made? A 2-point baskets: 7 3-point baskets: 38 B 2-point baskets: 38 3-point baskets: 7 с 2-point baskets: 42 3-point baskets: 3 D 2-point baskets: 3 3-point baskets: 42 A. A В. B с. С D D
We have the following:
To solve the problem we must plan a system of equations of two equations with two unknowns
let x numbers of 2-point baskets
let y numbers of 3-point backets
[tex]\begin{gathered} x+y=45 \\ 2x+3y=97 \end{gathered}[/tex]solving the system:
[tex]\begin{gathered} y=45-x \\ 2x+3\cdot(45-x)=97 \\ 2x+135-3x=97 \\ -x=97-135 \\ x=38 \end{gathered}[/tex]for y:
[tex]\begin{gathered} y=45-38 \\ y=7 \end{gathered}[/tex]The answer is 38 2-point baskets and 7 3-point baskets, the option B
The point P is on the unit circle. If the y-coordinate of P is -3/7and P is in quadrant IV, thenT=Question Help: VideoSubmit Question
Answer:
[tex]x=\frac{\sqrt{40}}{7}[/tex]Explanation: Provided a point on a unit circle, that has a y-coordinate of y=(-3/7) and lies in the fourth quardrand, we have to find the x-coordinate of the point, the visulization of the problem is as follows:
Using the Pythagorean theorem, the following equation can be constructed:
[tex]\begin{gathered} x^2+(-\frac{3}{7})^2=1^2 \\ x^2+(-\frac{3}{7})^2=1^\text{ }\Rightarrow(1) \end{gathered}[/tex]Simplifying the equation (1) gives the following answer:
[tex]\begin{gathered} x^2+(-\frac{3}{7})^2=1^ \\ x^2=1-(-\frac{3}{7})^2 \\ x=\frac{\sqrt{40}}{7} \end{gathered}[/tex]In conclusion, the answer is:
[tex]x=\frac{\sqrt{40}}{7}[/tex]slove for f-45=-56+ ( radical) f
The numbers on two consecutively numbered gym lockers have a sum of 123 what are the locker numbers?
According to the statement, we have two consecutively numbered gym lockers which sum 123.
Let's suppose that the first locker has the number X, so the consecutive has a number X+1, and because the sum of the numbers is 123, we can write the following equation:
[tex]X+(X+1)=123[/tex]Solving the last equation for X we find that:
[tex]\begin{gathered} 2X+1=123 \\ 2X=123-1 \\ 2X=122 \\ X=\frac{122}{2} \\ X=61 \end{gathered}[/tex]Answer
The numbers of the lockers are 61 and 62.
need help with my homework please look at the picture.
Solution:
Given the dot plot as shown below:
To evaluate the mean, we write out the data values as seen on the x-axis.
Thus, the data values are:
[tex]2,4,4,4[/tex]The mean is expressed as
[tex]\frac{sum\text{ of individual values}}{total\text{ number of values}}[/tex]Thus, the mean number of times Zach's teammates were late to practice last week is evaluated as
[tex]\begin{gathered} \frac{2+4+4+4}{4} \\ =\frac{14}{4} \\ =3.5 \end{gathered}[/tex]Evaluate 5 x + 3 when x = 2 .The value of the expression is _____.The solution is _________
The expression given is,
[tex]5x+3[/tex]The value of x is x = 2 .
Substiute the value of x in the expression to find the value of the expression.
[tex]5x+3=5(2)+3[/tex][tex]10+3=13[/tex]Thus the value of the expression is 13.
The black graph is the graph of y = f(x).Choose the equation for the red graph.A. y + 4 = f(x)B. y - 4 = f(x)C. y = f(x - 4)D. y = f(x + 4)Enter
We can infer from the black graph that ,
For x = 0, y = 5.
SImilarly for red graph, for x = 0, y = 1
That is,
[tex]\begin{gathered} y=5-4 \\ y=f\mleft(x-4\mright) \end{gathered}[/tex]need help pls and th x s not a quiz
3, 15, 75, 375, 1875
r = common ratio
[tex]r=\text{ }\frac{15}{3}\text{ = }\frac{75}{15}\text{ = }\frac{375}{75}\text{ = }\frac{1875}{375}\text{ = 5}[/tex][tex]\text{ a first term = 3}[/tex][tex]\begin{gathered} y=a(r^{n\text{ - 1}}) \\ \\ y=3(5^{n\text{ - 1}})\text{ This is the exponential function} \\ \end{gathered}[/tex]please help me!!!!!!
It is given that P(A)=0.73 and P(B)=0.56 It is also given that:
[tex]P(A\cap B)=0.4088[/tex]The events are independent if:
[tex]P(A\cap B)=P(A)P(B)[/tex][tex]P(A)P(B)=0.73\times0.56=0.4088[/tex]Hence the events are independent.
Option A is correct.
Which triangle is similar to ABC if sin(A) =cos(A) = vs., and tan(A) = VIS?1_JXR3кMол51312V153246V15のS3v15L V6 N12YTN6
Suppose that triangle ABC is a right triangle; therefore, we can use the following trigonometric identities,
[tex]\sin \theta=\frac{O}{H},\cos \theta=\frac{A}{H},\tan \theta=\frac{O}{A}[/tex]Then, in our case,
[tex]\begin{gathered} \frac{1}{4}=\frac{O}{H},\frac{A}{H}=\frac{\sqrt[]{15}}{4},\frac{O}{A}=\frac{1}{\sqrt[]{15}} \\ \Rightarrow O=1.A=\sqrt[]{15},H=4 \end{gathered}[/tex]In a diagram,
Comparing the ratio of the corresponding sides of triangles ABC and RST
[tex]\begin{gathered} \frac{13}{4}=3.25 \\ \frac{12}{1}=12,\frac{12}{\sqrt[]{15}}=3.09833 \end{gathered}[/tex]The ratio between corresponding sides is not constant; thus, triangle RTS is not similar to ABC.
On the other hand, as for triangle KJI
[tex]\begin{gathered} \frac{12}{4}=3 \\ \frac{3\sqrt[]{15}}{\sqrt[]{15}}=3 \\ \frac{3}{1}=3 \end{gathered}[/tex]The ratio is constant; therefore, the answer is triangle JKI
I need help with my geometry homework.it is talking about inductive reasoning and logic symbols hw
So we need to take the expressions written with logical symbols and write them as compound statement. Then we must find their thruth value which basically means that we have to tell if they are true or false.
The first one is:
[tex]p\lor q[/tex]This is called a disjunction and can be described with the word "or". So considering what the statements p and q are the compund statement would be:
[tex]p\lor q\colon\text{ Points C, E and }B\text{ are collinear or }\angle AEC\cong\angle DEB[/tex]This is the first compound statement, we just need to find if its true or false. Since what we have is a disjunction then if both p and q are true, the statement is true. Also, if only one of them is true the statement is still true. A disjunction like this can only be false if both statement are false so let's check which is the case.
The first part, statement p is "Points C, E and B are collinear". Being collinear means that they all three share the same line. As you can see this is not true.
The second part is statement q and says that:
[tex]q\colon\angle AEC\cong\angle DEB[/tex]If you look carefully, you can see that angles AEC and DEB are defined by the same lines, share the same vertex and are opposite. All these means that in deed AEC and DEB have the same measure which means that this statement is true. So from the two statements that form the compund statement p v q one is true which means that the truth value of this one is True.
And that's the solution for number 1. Let's see number 2, we have:
[tex]q\wedge s[/tex]This is called a conjuction and can be expressed with the word "and". Then:
[tex]q\wedge s\colon\angle AEC\cong\angle DEB\text{ and }\angle BEC\text{ is an acute angle}[/tex]For conjuction, their truth value is true if both statements are true. In any other case, the truth value is false. So let's see, we have already found that statement q is true. We have to see what happens with statement s:
[tex]s\colon\angle BEC\text{ is an acute angle}[/tex]An acute angle is an angle whose measure is smaller than 90°. As you can see, BEC has to measure more than 90° since a 90° angle is made by two perpendicular sides. This means that statement s is false. Since both q and s are true then the Truth value of q ^ s is False.
Now in number 3 we have:
[tex]\text{ \textasciitilde}p\wedge r[/tex]This is also a conjuction (we'll use the word "and") but this time there's a symbol ~ before p. In logical terms ~p is the statement that is exactly the opposite of p. So if p is "Points C, E and B are collinear" then ~p is "Points C, E and B aren't collinear". Another thing to notice is that if p is false then ~p has to be true. Now that we know this let's write the compound statement:
[tex]\text{ \textasciitilde}p\wedge r\colon\text{Points C, E and }B\text{ aren't collinear and }EF\text{ is the angle bisector of }\angle AED[/tex]And let's find the truth value. As I said, if p is false then ~p is true so we just need to see if r is true or false. The angle bisector is a line or segment that "cuts" an angle through the middel. As you can see on the image EF does exactly this so statement r is true. So we have a conjuction of two true statements so the truth value is True.
In 4 we have:
[tex]r\lor\text{ \textasciitilde}s[/tex]This is a disjunction so we have to use the word "or" and ~s is the opposite or the negation of s so we have that the compound statement is:
[tex]r\lor\text{ \textasciitilde}s\colon EF\text{ is the angle bisector of }\angle AED\text{ or }\angle BEC\text{ isn't an acute angle}[/tex]As we already saw before, r is a true statement and ~s is also true because s is false. This means that the truth value in this case is True.
In the last one we have:
[tex]\text{ \textasciitilde}q\wedge\text{ \textasciitilde}r[/tex]So we have a conjuction. This means that the compound statement is given by joining the negation of q with that of r with the word "and" between them:
[tex]\text{ \textasciitilde}q\wedge\text{ \textasciitilde}r\colon\angle AEC\ne\angle DEB\text{ and }EF\text{ isn't the angle bisector of }\angle AED[/tex]As we saw before, q and r are true so both ~q and ~r are false and the truth value is False.
On the putting green, a golf ball travels at 1.4 m/s in a direction of 130°. The ball encounters wind blowing at 1.1 m/s in the direction of 50°. What is the true speed and direction of the ball? Round the speed to the thousandths place and direction to the nearest degree.
In order to calculate the true speed and direction of the ball, let's calculate the horizontal and vertical directions of the ball speed (b) and of the wind speed (w):
[tex]\begin{gathered} b_x=b\cdot\cos(\theta)\\ \\ b_x=1.4\cdot\cos(130°)\\ \\ b_x=1.4\cdot(-0.6428)\\ \\ b_x=-0.900\text{ m/s}\\ \\ \\ \\ b_y=b\cdot\sin(\theta)\\ \\ b_y=1.4\operatorname{\cdot}\sin(130°)\\ \\ b_y=1.4\operatorname{\cdot}0.766\\ \\ b_y=1.072\text{ m/s} \end{gathered}[/tex][tex]\begin{gathered} w_x=w\cdot\cos(\theta)\\ \\ w_x=1.1\operatorname{\cdot}\cos(50°)\\ \\ w_x=1.1\operatorname{\cdot}0.6428\\ \\ w_x=0.707\text{ m/s}\\ \\ \\ \\ w_y=w\operatorname{\cdot}\sin(\theta)\\ \\ w_y=1.1\operatorname{\cdot}\sin(50°)\\ \\ w_y=1.1\operatorname{\cdot}0.766\\ \\ w_y=0.843\text{ m/s} \end{gathered}[/tex]Now, let's add the horizontal components together and the vertical components together:
[tex]\begin{gathered} v_x=b_x+w_x=-0.9+0.707=-0.193\text{ m/s}\\ \\ v_y=b_y+w_y=1.072+0.843=1.915\text{ m/s} \end{gathered}[/tex]To calculate the magnitude and direction of this resultant speed, we can use the formulas below:
[tex]\begin{gathered} v=\sqrt{v_x^2+v_y^2}\\ \\ v=\sqrt{(-0.193)^2+(1.915)^2}\\ \\ v=1.925\text{ m/s}\\ \\ \\ \\ \theta=\tan^{-1}(\frac{v_y}{v_x})\\ \\ \theta=\tan^{-1}(\frac{1.925}{-0.193})\\ \\ \theta=96° \end{gathered}[/tex]Therefore the correct option is the second one.
What is the sum of 12.043992 and 184.285?
The answer is: 196.328992
To solve this, both numbers must be aligned in such way that the decimal point are aligned, and then we add from left to right:
Then, the 992 isn't adding anything so remains the same.
3 + 5 = 8 so we can put this directly
4 + 8 = 12
then we do the same as when we're adding whole numbers, we put the unit and take the 1 to the next place.
The next place have 0 + 2 = 2 but also have the 1 from before: 2 + 1 = 3
Now we need to add 12 + 184
2 + 4 = 6 and 1 + 8 = 9:
Then: 12 +184 = 196
What is 34 times 56?
Given
What is 34 times 56?
Solution
[tex]34\times56=1904[/tex]Alternatively
Find the distance between the points(-2,5) and (4,-3).
EXPLANATION:
To find the distance between these two points we must use the following formula:
[tex]d(p1,p2)=\sqrt[]{(x2-x1)^2+(y2-y1)^2}[/tex]Now we must correctly identify which values of the points correspond to x and which to y, and then we must replace them in the distance formula;
points: (-2 ,5) and ( 4, - 3)
x1 y1 x2 y2
Now we must replace in the formula:
[tex]\begin{gathered} d(p1,p2)=\sqrt[]{(4-(-2))^2+(-3-5)^2} \\ d(p1,p2)=\sqrt[]{(4+2)^2+(-8)^2} \\ d(p1,p2)=\sqrt[]{(6)^2+(64)^{}} \\ d(p1,p2)=\sqrt[]{36+64} \\ d(p1,p2)=\sqrt[]{100} \\ d(p1,p2)=10 \\ \text{ANSWEWR: distance equals 10} \end{gathered}[/tex]Line WZ and line XR are diameters of circle C. The figure is not drawn to scale. What is the measure of ZWX?thank you :)
Answer:
[tex]198^{\circ}[/tex]Explanation:
We were given the information:
Line WZ and line XR are diameters of circle C
We will obtain the measure of ZWX as shown below:
[tex]\begin{gathered} ZWX=ZRW+WX \\ ZRW=180^{\circ}(straight\text{ }line) \\ WX=18^{\circ} \\ ZWX=180+18 \\ ZWX=198^{\circ} \end{gathered}[/tex]Therefore, the correct option is the third option
While reading a book, Shara estimates that she is 75% finished. If she has read 216 pages, then how long is the book? Maneuvering the Middle 2015
Try some examples with 3 odd numbers to check this conjecture
We have the following conjecture: "The square of an odd number is always odd".
4.1) We select the odd numbers 1, 3, 5 and check the conjecture:
[tex]\begin{gathered} 1^2=1, \\ 3^2=9, \\ 5^2=25. \end{gathered}[/tex]We notice that the results of the squares are odd numbers, so the conjecture is true for these numbers.
4.2) We can't find an example where the conjecture is false. In point 4.4, we will prove that the conjecture is true.
4.3) We agree with the conjecture. We believe that it is TRUE.
4.4) We prove that the conjecture is true for all odd numbers.
By definition, an odd number can be written as:
[tex]m=2n+1.[/tex]Where:
• n is an integer,
,• 2n is an even number because 2n is divisible by 2.
Now, we compute the square of m:
[tex]m^2=(2n+1)^2=(2n+1)\cdot(2n+1)=4n^2+4n+1=2\cdot(2n^2+2n)+1.[/tex]We see that the result is the sum of an even number 2*(2n²+2n) plus 1, so the result is an odd number for every odd number m = 2n + 1. This result proves the conjecture.
The conjecture is TRUE for all odd numbers.
A tree is 12 feet tall and casts a shadow 9 feet long. A building nearby castsa shadow that measures 21 feet. How tall is the building?*
Firstly, calculate angle m
[tex]\begin{gathered} \tan \text{m =}\frac{12}{9}\text{ =}\frac{4}{3} \\ m\text{ = }\tan ^{-1}(\frac{4}{3}) \\ m\text{ = 53.13 degrees} \\ \end{gathered}[/tex]To calculate x
[tex]\begin{gathered} \tan \text{ m = }\frac{x}{12\text{ + 9}} \\ \tan \text{ 53.13 = }\frac{x}{21} \\ x\text{ = 21 x tan 53.13} \\ x\text{ = 27.99 ft} \\ x=28\text{ ft (nearest whole number)} \end{gathered}[/tex]The height of the building is 28ft
What is the value of x in the circle on the right?
Determine the value of x by using the pythagoras theorem.
[tex]\begin{gathered} (9+x)^2=(x)^2+(14)^2 \\ 81+x^2+18x=x^2+196 \\ 18x=196-81 \\ x=\frac{115}{18} \\ =6.3888 \\ \approx6.4 \end{gathered}[/tex]So value of x is 6.4.
Karen deposits $3,500 in a savings account that pays 0.8% interest, compounded quarterly. Find the second quarter’s interest. Round to the nearest cent.
Given the information, we have that the present value is $3500, the rate of interest is 0.8%=0.008 and we want to know the second quarter's interest, that is, t=2, then:
[tex]\begin{gathered} FV=3500\cdot(1+0.008)^2 \\ =3500\cdot(1.016064)=3556.22 \end{gathered}[/tex]Therefore, the future value of the savings account for the second quarter is 3556.22. To find the interest, we just substract the present value from this result:
[tex]i=3556.22-3500=56.22[/tex]therefore, the second quarter interest is $56.22
This box is packed with cubes that measure one cubic foot.Enter the volume of the box in cubic feet.cubic feetYou may use the scratchpad to show your work.
ANSWER
72 cubic feet
EXPLANATION
The total volume of the box is the sum of the volumes of all the cubes that form it.
We can see that at the top there are 18 squares, which belong to the tops of 18 cubes. Also we can see that there are 4 rows of cubes along the height of the box. This means that in total there are:
[tex]18\times4=72[/tex]72 cubes that form this box.
If each cube has a volume of 1 cubic foot, then the volume of the box is:
[tex]72\times1ft^3=72ft^3[/tex]72 cubic feet.
Given lines 1, m and n are all parallel and cut by two transversal lines, find the value of x. 11 m 33 6 n
In the given figure, lines l, m, and n are parallel.
These parallel lines are cut by two transversal lines proportionally.
So, we can set up the following proportion.
[tex]\frac{x}{6}=\frac{11}{33}[/tex]Let us solve for x.
[tex]\begin{gathered} \frac{x}{6}=\frac{11}{33} \\ x=6\cdot\frac{11}{33} \\ x=2 \end{gathered}[/tex]Therefore, the value of x is 2