Solve Each system using elimination

Answer:

Yes, they are equivalent

Step-by-step explanation:

15 months= 1.25 years

60/2.5= 24

30/1.25 = 24

Answer:

Step-by-step explanation:

Since 2.5 years equals 2.5(12)=30months you have

60cm/30mo and 30cm/15mo these are equivalent because (2/2)(30/15)=60/30

Answer:

25728

Step-by-step explanation:

Amount i would have in 3 months = simple interest + amount deposited

Simple interest = principal x time x interest rate

Principal = 25600

Interest rate = 2%

Time = 3/ 12 = 0.25

25,600 x 0.02 x 0.25 = 128

Total amount = 25,600 + 128 = 25728

Step-by-step explanation:

Set M = {20,22,24,26,28,30,32,34}

n(M) = no. of elements in set M

i.e.

n(M) = 8

Answer:

7

Step-by-step explanation:

Even numbers between 20 and 35 are 22, 24, 26, 28, 30, 32, 34.

M = { 22, 24, 26, 28, 30, 32, 34}

There are 7 elements in the set M.

Thus, n(M) = 7

Answer:

1/10th

Step-by-step explanation:

You multiply,

1/2 x 1/5 = 1/10

You can also picture it. Cut half a sheet of paper into 5 pieces. that means the other half would have 5 pieces too you cut it. That means there would be 10 pieces in total. He uses one of those pieces.

Answer:

It is 39.3

Step-by-step explanation:

You find the circumference using the formula 2πr so you get 20π.

and then you multiply that by 225/360 bc 360 is how much the whole circle is and the 225 part is the part you want to solve.

So 20π*225/360 is about 39.3

Answer:

m+ p+ q= 180°

m+76°+72°=180°

m+ 148=180°

m=180°-148

m=32°

Answer:

no

Step-by-step explanation:

The given ratios 3/11 and 17/6 are not proportional.

A ratio is the relation between two numbers as a / b. A proportion is the equality of two ratios as a / b = c / d.

Ratio and proportion can be applied to solve Mathematical problems dealing with unit values of the quantities.

The given ratios are 3/11 and 17/6.

In order to check the proportionality cross multiplication is done as follows,

3/11 and 17/6

Cross multiply the numerators and denominators as follows,

3 × 6 and 17 × 11

=> 18 and 187

Since the cross multiplication of the numerators and denominators are not equal, the given ratios are not proportional.

Hence, the given ratios are not proportional.

To know more about ratio and proportion click on,

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Answer:

54

Step-by-step explanation:

put 5 in for x and 6 in for y

Answer:99

Step-by-step explanation:

Answer:

Step-by-step explanation:

⅔n - 5 = ⅓n + 7

⅓n = 12

n = 36

Answer: The simplification is [tex]5*a^{-9}*b^{-9}[/tex]

Step-by-step explanation:

Here we need to use the property:

[tex]\frac{a^n}{a^m} = a^{n - m}[/tex]

We have the expression:

[tex]\frac{25*a^{-5}*b^{-8}}{5*a^{4}*b}[/tex]

We can separate it in parts with the same base, then we can rewrite this as:

[tex]\frac{25*a^{-5}*b^{-8}}{5*a^{4}*b} = \frac{25}{5} \frac{a^{-5}}{a^4} \frac{b^{-8}}{b}[/tex]

Using the first property we can rewrite this as:

[tex]\frac{25}{5} \frac{a^{-5}}{a^4} \frac{b^{-8}}{b} = 5*a^{-5 - 4}*b^{-8 - 1} = 5*a^{-9}*b^{-9}[/tex]

Answer:

Step-by-step explanation:

If a number gets increased by scale factor = k

Then k > 1

If the number gets decreased by a scale factor 'k'

Then 0 < k < 1

Let numbers gets increased by the scale factor = 2,

And decreased by the scale factor = [tex]\frac{1}{2}[/tex]

Numbers             Scale up by 2           Scale down by [tex]\frac{1}{2}[/tex]

   0.05                  0.05 × 2 = 0.1             0.05 × [tex]\frac{1}{2}[/tex] = 0.025

    [tex]\frac{1}{2}[/tex]                        [tex]\frac{1}{2}\times 2 = 1[/tex]                      [tex]\frac{1}{2}\times \frac{1}{2}=\frac{1}{4}[/tex]

    7                       7 × 2 = 14                     7 × [tex]\frac{1}{2}[/tex] = 3.5

   13                      13 × 2 = 26                  [tex]13\times \frac{1}{2}=6.5[/tex]

   25                     25 × 2 = 50                 [tex]25\times \frac{1}{2}=12.5[/tex]                

  102                   102 × 2 = 204              [tex]102\times \frac{1}{2}=51[/tex]

Answer:

y = 1/2x + 1/2

Step-by-step explanation:

y = 1/2x + b  [Parallel lines have the same slope but different y-intercepts]

-2 = (1/2)(-5) + b  [Plug in the coordinates (-5,-2) to find the y-intercept b]

b = 1/2  [Solve for b]

y = 1/2x + 1/2

Answer:

y= 1/2x + 0.5

Step-by-step explanation:

plug in the x and y values to get the y-intercept the slope stays the same. hope this helps! :P

Answer:

50 times

Step-by-step explanation:

Since the odds of her getting a heads is 50% (1/2) every time she flips the coin. So she should expect to get 50 heads. However this number varies practically because in every single flip there is a 50-50 chance. If she had flipped it infinitely many times then it would be exactly 50%

Answer:

Step-by-step explanation:

Convert all the batting averages to a single unit so that comparison is easier.

Use percentages.

Jaden batting average:

= 0.214 = 214/1,000 = 21.4%

Raul = 24.3%

Abraham:

= 2 / 9 * 100%

= 22.2%

Mark = 22%

Raul has the greatest batting average.

Jaden has the least batting average.

Answer:

The ordered pairs of [tex]p(x) = x^{2}-2\cdot x -35[/tex] are [tex](r_{1}, p(r_{1})) = (-5, 0)[/tex] and [tex](r_{2},p(r_{2})) = (7,0)[/tex], respectively.

Step-by-step explanation:

Let be [tex]p(x)[/tex] a quadratic expression whose two real zeros are real, a value of [tex]x[/tex] is a zero of the expression when [tex]p(x) = 0[/tex]. The factored form of the expression is represented by [tex]p(x) = (x-r_{1})\cdot (x-r_{2})[/tex], where [tex]r_{1}[/tex] and [tex]r_{2}[/tex] are the zeroes of the polynomial.

If [tex]p(x) = x^{2}-2\cdot x -35[/tex], then the ordered pairs that represent the zeros are:

[tex](r_{1}, p(r_{1})) = (-5, 0)[/tex] and [tex](r_{2},p(r_{2})) = (7,0)[/tex]

Quadratic equation has a leading coefficient of the second degree. The ordered pairs of the quadratic equation are (-5,0) and (7,0).

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers.

It is written in the form of ax²+bx+c.

As the factors of the quadratic equation are given, therefore, equating the factors with zero in order to get the value of x.

[tex](x+5)=0\\x = -5[/tex]

[tex](x-7)=0\\x = 7[/tex]

Now, if we see the quadratic equation or the function it is written as,

[tex]y = x^2-2x-35 \\\\ x^2-2x-35 = 0[/tex]

Therefore, the value of y is 0.

Thus, the ordered pairs of the quadratic equation are (-5,0) and (7,0).

Learn more about Quadratic Equation:

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Answer:

[tex]2\frac{1}{5}[/tex]

Step-by-step explanation:

11 goes into 5 two times, but we are left with a remainder of 1.

So, we can say that the mixed number would be [tex]2\frac{1}{5}[/tex].

Answer:

C. y=3/x

Step-by-step explanation:

hope this helps, sorry if I am wrong

Answer:

A 5c+ 275 > 500

Step-by-step explanation:

Answer:  -2.25

Step-by-step explanation:

We plug in the numbers.

[tex]\frac{3xy}{2z}\\= \frac{3(2)(-3)}{2(4)}\\= \frac{-18}{8}\\= -2.25[/tex]

Answer:

P'(7,-3)

Q'(3,-1)

R'(7,-1)

Step-by-step explanation:

Switch signs of y-value when reflecting across x-axis.

Switch signs of x-value when reflecting across y-axis.

Hope this helped!

Answer:

[tex]5^{12}[/tex]

Step-by-step explanation:

Lets say there's a number 'x' and there's an expression [tex](x^a)^b[/tex] where 'a' & 'b' are also numbers , the simplified form of the expression is [tex]x^{a \times b}[/tex].

So ,

[tex](5^4)^3 = 5^{4 \times 3} = 5^{12}[/tex]

Answer:

No b/c the hypotenuse is too short

Step-by-step explanation:

13² + 15² = 19²

169 + 225 = 361

394 ≠ 361

Answer:

The answer is 48pi

Step-by-step explanation:

Circumference: C=2*pi*radius

The radius of Circle B is 2*12=24

Thus, the circumference of Circle B is: 2*pi*24=48pi

Question:

Carlos mixed [tex]\dfrac4{15}\text{ L}[/tex] of chocolate syrup with [tex]\dfrac12\text{ L}[/tex] of milk. Determine a reasonable estimate of the total amount of liquid Carlos mixed

Answer:

0.8 liters of liquid

Step-by-step explanation:

Given

[tex]Chocolate:= \dfrac4{15}\text{ L}[/tex]

[tex]Milk:= \dfrac12\text{ L}[/tex]

Required

An estimate of the total liquid

First, we get the actual total liquid.

[tex]Total = Chocolate + Milk[/tex]

[tex]Total =\dfrac4{15}\text{ L} + \dfrac12\text{ L}[/tex]

Take LCM

[tex]Total =\dfrac{8 + 15}{30}\text{ L}[/tex]

[tex]Total =\dfrac{23}{30}\text{ L}[/tex]

Express as decimal

[tex]Total ={0.7666}\text{ L}[/tex]

Estimate [Approximate]

[tex]Total ={0.8}\text{ L}[/tex]

Answer:

about 3/4

Step-by-step explanation:

start fraction, 3, divided by, 4, end fraction, start text, space, L, end text

Hint #11 / 5

We can make an estimate by picturing each fraction:

A tape diagram made up of two tapes of equal length. The tape on the top is divided into fifteen equal parts with each part labeled one-fifteenth. The first four parts are shaded. The tape on the bottom is divided into two equal parts with each part labeled one-half.  The first part is shaded.

A tape diagram made up of two tapes of equal length. The tape on the top is divided into fifteen equal parts with each part labeled one-fifteenth. The first four parts are shaded. The tape on the bottom is divided into two equal parts with each part labeled one-half. The first part is shaded.

Hint #22 / 5

To find the total amount of chocolate milk, we need to add \greenD{\dfrac{4}{15}}

15

4

​

start color #1fab54, start fraction, 4, divided by, 15, end fraction, end color #1fab54 and \purpleD{\dfrac12}

2

1

​

start color #7854ab, start fraction, 1, divided by, 2, end fraction, end color #7854ab.

A tape diagram made up of two tapes of equal length. The tape on the top is divided into fifteen equal parts with each part labeled one-fifteenth. The first four parts are shaded. The tape on the bottom is divided into two equal parts with each part labeled one-half.  The first part is shaded. Below the tapes, a curved bracket across the tapes is labeled 1.

A tape diagram made up of two tapes of equal length. The tape on the top is divided into fifteen equal parts with each part labeled one-fifteenth. The first four parts are shaded. The tape on the bottom is divided into two equal parts with each part labeled one-half. The first part is shaded. Below the tapes, a curved bracket across the tapes is labeled 1.

Hint #33 / 5

We can compare our sum to benchmarks like {\dfrac12}

2

1

​

start fraction, 1, divided by, 2, end fraction and 111:

A number line labeled 0 to 1 with tick marks every one-half unit. A tape diagram is above the number line from the tick mark at 0 to the tick mark at 1. The tape diagram is divided into 6 unequal parts. The first 4 parts are equal in size, shaded, and each labeled one-fifteenth. The next part is shaded and labeled one-half. The sixth part is not shaded and not labeled. Together, the five shaded parts of the tape diagram are from the tick mark at zero to an approximate halfway point between the tick mark at one-half and the tick mark at one of the number line.

A number line labeled 0 to 1 with tick marks every one-half unit. A tape diagram is above the number line from the tick mark at 0 to the tick mark at 1. The tape diagram is divided into 6 unequal parts. The first 4 parts are equal in size, shaded, and each labeled one-fifteenth. The next part is shaded and labeled one-half. The sixth part is not shaded and not labeled. Together, the five shaded parts of the tape diagram are from the tick mark at zero to an approximate halfway point between the tick mark at one-half and the tick mark at one of the number lines.

Hint #44 / 5

Our sum is more than

2

1

​

start fraction, 1, divided by, 2, end fraction but less than 111.

Answer:

19.1

Step-by-step explanation:

13²+14²=365

√365≈ 19.1