Solve for X. Options are: 9,10,11, and 12.

Answer:

y - 3 = -(x + 1)

y - 3 = -x - 1

y = -x + 2

Answer:

Pick options, 1,2,3,4 but DO NOT select option 5!!!

Step-by-step explanation:

The basic equation is y=mx+b where slope is m and b is the y intercept.

So our y intercept for this equation is 2. The line has a negative slope bc as increases, y decreases. (The line is pointing down.) Those are two good clues to start.

Let's calc the slope. slope = rise/run = (y2-y1)/(x2-x1)

(-1,3) and (1,1) are shown on the graph

slope = (3-1)/(-1-1)

= 2/-2 = -1

Slope = -1

Our equation is now y=-x+2

So let's find everything that equals y=-x+2

y-3 = -x-1 is the same as

y = -x+2

So pick the first option, y-3 = -x-1

(y+1) = -(x-3)

y+1 = -x+3

y=-x+2

So pick the 2nd option, (y+1) = -(x-3)

(y-3) = -(x+1)

y-3 = -x-1

y=-x-1+3

y=-x+2

So pick the 3rd option, (y-3) = -(x+1)

We already know to pick the 4th option, y=-x+2

(y-3) = (x-1)

y= x-1+3

y=x-2

DON'T PICK THE 5th option, because this has the wrong slope and wrong intercept!

Answer:

  y < 3/4x -2

Step-by-step explanation:

You want the inequality expression that corresponds to the given graph.

The boundary line rises 3 squares for each 4 to the right. Its slope is ...

  m = rise/run = 3/4

The boundary line crosses the y-axis at y = -2. Its y-intercept is ...

  b = -2

The slope-intercept form of the equation of the boundary line is ...

  y = mx +b

  y = 3/4x -2

The shading is below the dashed line, so the line is not part of the solution set. Only y-values less than those on the line are in the solution set.

The inequality that describes the graph is ...

  y < 3/4x -2

1. Opposite side are parallel

2. A rhombus is a parallelogram

3. Opposite sides are equal length

Step-by-step explanation:

When a researcher conducts an analysis of variance (ANOVA) and finds that the F-test statistic is statistically significant, it means that there is a significant difference between the means of the groups being compared. In other words, at least one of the group means is significantly different from the others.

However, it is important to note that a significant F-test does not provide information about which specific group means are different. To determine which groups differ from each other, post-hoc tests or pairwise comparisons are typically conducted.

Therefore, the researcher can conclude that there is evidence to suggest that there are differences in the means of the groups being compared. Further analyses or comparisons are needed to determine the specific nature of these differences and which groups are significantly different from each other.

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The probability of guessing the top five winners (in any order) from a group of 17 finalists in a spelling bee is 1/6188.

The number of ways to select 5 winners from 17 finalists is given by the combination formula:

C(17, 5) = 17! / (5! * (17-5)!) = 6188

This is the total number of possible ways to select 5 winners from the group of 17 finalists.

The probability of guessing the top five winners in any order is 1 out of the total number of ways to select 5 winners:

P(guessing top 5) = 1/6188

Therefore, the probability of guessing the top five winners (in any order) from a group of 17 finalists in a spelling bee is 1/6188.

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a. modulus 6:The possible inverses of x modulo 6 are numbers y such that xy ≡ 1 (mod 6).

We can check each integer between 1 and 5 to see which ones have a multiplicative inverse modulo 6:

1 * 1 ≡ 1 (mod 6), so 1 is its own inverse.
2 * 3 ≡ 0 (mod 6), so 2 and 3 do not have inverses.
4 * 4 ≡ 4 (mod 6), so 4 does not have an inverse.
5 * 5 ≡ 1 (mod 6), so 5 is its own inverse.

Therefore, the least positive inverses congruent to 1 modulo 6 are 1 and 5.

b. modulus 8:

The possible inverses of x modulo 8 are numbers y such that xy ≡ 1 (mod 8).

We can check each integer between 1 and 7 to see which ones have a multiplicative inverse modulo 8:

1 * 1 ≡ 1 (mod 8), so 1 is its own inverse.
2 * 4 ≡ 0 (mod 8), so 2 and 4 do not have inverses.
3 * 3 ≡ 1 (mod 8), so 3 is its own inverse.
5 * 5 ≡ 1 (mod 8), so 5 is its own inverse.
6 * 7 ≡ 2 (mod 8), so 6 and 7 do not have inverses.

Therefore, the least positive inverses congruent to 1 modulo 8 are 1, 3, and 5.

c. modulus 9:

The possible inverses of x modulo 9 are numbers y such that xy ≡ 1 (mod 9).

We can check each integer between 1 and 8 to see which ones have a multiplicative inverse modulo 9:

1 * 1 ≡ 1 (mod 9), so 1 is its own inverse.
2 * 5 ≡ 1 (mod 9), so 2 and 5 are inverses.
3 * 6 ≡ 0 (mod 9), so 3 does not have an inverse.
4 * 7 ≡ 1 (mod 9), so 4 and 7 are inverses.
8 * 8 ≡ 1 (mod 9), so 8 is its own inverse.

Therefore, the least positive inverses congruent to 1 modulo 9 are 1, 4, 5, and 7.

d. modulus 10:

The possible inverses of x modulo 10 are numbers y such that xy ≡ 1 (mod 10).

We can check each integer between 1 and 9 to see which ones have a multiplicative inverse modulo 10:

1 * 1 ≡ 1 (mod 10), so 1 is its own inverse.
2 * 5 ≡ 0 (mod 10), so 2 and 5 do not have inverses.
3 * 7 ≡ 1 (mod 10), so 3 and 7 are inverses.
4 * 3 ≡ 2 (mod 10), so 4 and 9 are inverses.
6 * 1 ≡ 6 (mod 10), so 6 is its own inverse.
8 * 3 ≡ 4 (mod 10), so 8 and 7 are inverses.

Therefore, the least positive inverses congruent to 1 modulo 10 are 1, 3, 7,

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If he interest rate is 10% compounded annually, after 1 year, Maggie will have $33 in the account to the nearest cent.

To solve this problem, we can use the formula for compound interest:

B = p(1+r)ᵗ

where B is the balance, p is the principal, r is the interest rate expressed as a decimal, and t is the time in years.

In this case, we know that Maggie has $30 in the account, the interest rate is 10% (or 0.10), and she is investing for 1 year. We can plug these values into the formula to find her balance after 1 year:

B = 30(1+0.10)

B = 30(1.10)

B = 33

The formula for compound interest is a useful tool for calculating the growth of an investment over time, taking into account both the principal and the interest rate.

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Answer:

-6.29

Step-by-step explanation:

Add two negative integers together is just as simple as two positive integers together.

Let's for a little bit ignore that negative. What is 4.058 + 2.232? 6.290 or just 6.29. Now slap a negative in front of it!

Your answer is -6.29.

Different rules arise when adding a negative integer with a positive integer. We can cross the bridge when we get there :)

Answer:

Obtuse, scalene

Step-by-step explanation:

No same values for sides. So, scalene. Since 7^2 > 6^2 + sqrt5 ^2 , this triangle is obtuse.

This situation where there are at least 20 but not more than 25 guests attending the party, the range of the function is from 655 to 875, inclusive.

To find the range of the function for this situation, we need to evaluate the function for the given range of values of g, which is 20 to 25.

If there are 20 guests attending the party, then:

c = 28g + 75 = 28(20) + 75 = 655

If there are 25 guests attending the party, then:

c = 28g + 75 = 28(25) + 75 = 875

Therefore, for This situation where there are at least 20 but not more than 25 guests attending the party, the range of the function is from 655 to 875, inclusive.

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Within the range 0 ≤ x ≤ 3, the average rate of change of f(x) is 6.

Calculate the difference between the function values at the interval's endpoints and divide by the interval's length to determine the average rate of change of a function inside the interval.

In this case, the interval is [0, 3]. So, we need to find the values of f(0) and f(3) and calculate the difference, and then divide by 3 - 0 = 3.

[tex]f(0) = 2(0)^2 - 4 = -4\\\\f(3) = 2(3)^2 - 4 = 14[/tex]

The difference is: f(3) - f(0) = 14 - (-4) = 18

So, the average rate of change within the interval [0, 3] is:

average rate of change = (f(3) - f(0))/(3 - 0) = 18/3 = 6

Therefore, the average rate of change of f(x) within the interval 0 ≤ x ≤ 3 is 6.

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Answer:

a) 345

b) 0.0000002

Step-by-step explanation:

a)  We can multiply the 2.3 and 1.5 and 10^4 and 10^-2 together and simplify at the end.

Step 1:  Working out 2.3 * 1.5:

2.3 * 1.5 = 3.45

Step 2:  Working out 10^4 * 10^-2:

The product rule of exponents states that when you're multiplying the same bases with different exponents, you add the exponents.

So, 10^4 * 10^-2 = 10^(4 + (-2)) = 10^(4 - 2) = 10^2

Step 3:  Simplifying:  

Thus, we have 3.45*10^2 = 3.45 * 100 = 345

Step 4:  Checking our answer:  

We can check by doing the operations inside each parentheses instead of taking them out and seeing whether we still get 345 (i.e., the answer we got when we multiplied common terms instead):

(2.3 * 10^4) * (1.5 * 10^-2)

(2.3 * 10000) * (1.5 * 0.01)

23000 * 0.015

345

Thus, our answer is correct and 345 is the standard form of (2.3 * 10^4) * (1.5 * 10^-2)

b)  Similar to our process for part a), we can divide 3.6 by 1.8 and then divide 10^-5 by 10^2 and simplify at the end.

Step 1:  Working out 3.8 / 1.8:  

3.6 / 1.8 = 2

Step 2:  Working out 10^-5 / 10^2:  

The quotient rule of exponents states that when we divide the same bases with different exponents, we subtract the exponents.

Thus, 10^-5 / 10^2 = 10^(-5 - 2) = 10^-7

Step 3:  Simplifying:

2 * 10^-7 = 2 * 0.0000001 = 0.0000002

Step 4:  Checking our answer:

We can check by doing the operations inside each parentheses instead of taking them out and seeing whether we still get 0.0000002 (i.e., the answer we got when we multiplied common terms instead):

(3.6 * 10^-5) / (1.8 * 10^2)

(3.6 * 0.00001) / (1.8 * 100)

0.000036 / 180

0.0000002

Thus, our answer is correct and 0.0000002 is the standard form of (3.6 * 10^-5) / (1.8 * 10^2)

It is possible for a security with a positive standard deviation of returns to have a beta of zero if its returns are uncorrelated with the market.

The beta of an asset measures its sensitivity to market movements. A beta of zero indicates that the asset's returns are uncorrelated with the market. If a security has a positive standard deviation of returns, it means that it is still subject to some risk, even if it is not correlated with the market. Therefore, it is possible for a security with a positive standard deviation of returns to have a beta of zero if its returns are uncorrelated with the market.

According to the CAPM, the expected return on an asset is equal to the risk-free rate plus the market risk premium multiplied by the asset's beta. If a security has a beta of zero, then its expected return would be equal to the risk-free rate, regardless of its standard deviation of returns. This is because the asset's returns are uncorrelated with the market, and therefore it does not bear any systematic risk.

It is possible for a security with a positive standard deviation to have an expected return from the CAPM that is less than the risk-free rate if its beta is negative. Such a security would be considered very risky, as it would move in the opposite direction of the market. If such a security were to exist, it may not have many willing buyers, as it would be considered a very high-risk investment.

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g'(x) = 1/f'(g(x)) = 1/sin(g(x))

We know that g is the inverse function of f, which means that f(g(x)) = x for all x in the domain of g.

Taking the derivative of both sides of this equation with respect to x, we get:

f'(g(x)) * g'(x) = 1

We also know that f'(x) = sin(x). Substituting x with g(x), we get:

f'(g(x)) = sin(g(x))

Substituting this into the previous equation, we get:

sin(g(x)) * g'(x) = 1

Solving for g'(x), we get:

g'(x) = 1/sin(g(x))

Therefore, g'(x) is equal to the reciprocal of sin evaluated at g(x). It's worth noting that this expression is undefined whenever sin(g(x)) = 0, which occurs at integer multiples of π. So the domain of g'(x) is the set of all x such that g(x) is not an integer multiple of π.

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This is the equation of a circle is (x - 14)² + (y - 5)² = 1 with center at (14, 5) and radius 1.

Starting with the x terms:

x² - 28x

= x² - 28x + 196 - 196

= (x - 14)² - 196

And now for the y terms:

y² - 10y

= y² - 10y + 25 - 25

= (y - 5)² - 25

Substituting these into the original equation gives:

(x - 14)² - 196 + (y - 5)² - 25 + 220 = 0

Simplifying gives:

(x - 14)² + (y - 5)² = 1

This is the equation of a circle with center at (14, 5) and radius 1.

To graph this, plot the point (14, 5) and draw a circle with radius 1 around it.

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The partial fraction decomposition of the rational function 4x/(16x^2 + 40x + 25) is given by the sum of two terms: A/(4x + 5) + B/(4x + 5)^2, where A and B are constants that can be solved using algebraic manipulation

To find the partial fraction decomposition of the given rational function, we first factor the denominator into two linear factors: (4x + 5)(4x + 5). Then, we can write the function as a sum of two terms with undetermined coefficients:

4x/(16x^2 + 40x + 25) = A/(4x + 5) + B/(4x + 5)^2

To solve for A and B, we can multiply both sides by the common denominator (4x + 5)^2 and simplify:

4x = A(4x + 5) + B

Expanding and equating coefficients of like terms, we get:

4x = 4Ax + 5A + B

0 = 16A + 4B

Solving for A and B, we get:

A = -1/16

B = 1/16

Therefore, the partial fraction decomposition of the given rational function is: 4x/(16x^2 + 40x + 25) = -1/(16(4x + 5)) + 1/(16(4x + 5)^2)

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The modern square of opposition includes four types of propositions: A (universal affirmative), E (universal negative), I (particular affirmative), and O (particular negative). The given proposition is an E proposition, which states that "It is false that some lunar craters are volcanic formations."

To determine the validity of the immediate inference that "Therefore, no lunar craters are volcanic formations," we need to consider the opposite proposition, which is an A proposition that states "All lunar craters are not volcanic formations."

According to the modern square of opposition, the immediate inference from E to E (universal negative to universal negative) is invalid. Therefore, the given immediate inference is also invalid from the Boolean standpoint.

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Based on the normal model N(100,15) describing IQ scores, we can use the standard normal distribution to answer these questions. To find the percentage of people with IQs over 80, we need to calculate the Z-score for 80: Z = (80-100)/15 = -1.33. Using a standard normal distribution table, we find that the area to the right of Z = -1.33 is 0.0918, which means about 9.18% of people have IQs over 80.

To find the percentage of people with IQs under 90, we calculate the Z-score for 90: Z = (90-100)/15 = -0.67. Using the same table, we find that the area to the left of Z = -0.67 is 0.2514, which means about 25.14% of people have IQs under 90.

To find the percentage of people with IQs between 112 and 123, we need to calculate the Z-scores for 112 and 123: Z1 = (112-100)/15 = 0.80 and Z2 = (123-100)/15 = 1.53. Using the table, we find the area to the left of Z1 is 0.7881 and the area to the left of Z2 is 0.9370. Therefore, the percentage of people with IQs between 112 and 123 is approximately 14.89%.

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Answer: -31/15

Step-by-step explanation:

Answer:

-31/15

Step-by-step explanation:

u(b) = b^2/2,  we can evaluate the integral from u(a) to u(b), giving us the new definite integral in terms of u.

To find the new limits of integration, we need to express the integral in terms of the new variable u. Using the change of variables formula, we have:

du/dx = x/2

dx = 2du/x

Substituting into the integral, we get:

∫ f(x) dx = ∫ f(x(u)) dx/du * 2du/x

Since u = x^2/2, we have x = √(2u). Substituting this into the integral, we get:

∫ f(x(u)) dx/du * 2du/√(2u)

Simplifying, we have:

∫ f(x(u)) √2 du

Now, we need to determine the new limits of integration in terms of u. If the original limits were a and b, then the new limits are:

u(a) = a^2/2

u(b) = b^2/2

Therefore, we can evaluate the integral from u(a) to u(b), giving us the new definite integral in terms of u.

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The appropriate measure of variability for this data set is the IQR, and its value is 350.

The range is one measure of variability, but it is heavily influenced by extreme values, which makes it less reliable. The IQR (interquartile range) is a better measure of variability because it is not affected by extreme values. Therefore, the appropriate measure of variability for this data set is the IQR.

To calculate the IQR, we first need to find the median, which is the middle value in the ordered list of data:

200, 450, 600, 650, 700, 800

The median is (600 + 650) / 2 = 625.

Next, we find the values that mark the 25th and 75th percentiles of the data set. The 25th percentile is the value that is greater than 25% of the values in the data set, and the 75th percentile is the value that is greater than 75% of the values in the data set. We can use the following formula to find these values:

25th percentile = (n + 1) × 0.25

75th percentile = (n + 1) × 0.75

where n is the number of values in the data set. In this case, n = 6, so:

25th percentile = (6 + 1) × 0.25 = 1.75

75th percentile = (6 + 1) × 0.75 = 5.25

We round these values up and down to get the indices of the corresponding values in the ordered list:

25th percentile index = 2

75th percentile index = 5

The values at these indices are 450 and 800, respectively. Therefore, the IQR is:

IQR = 800 - 450 = 350

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The volume of the frustum of a pyramid with square base of side 9, square top of side 4, and height 5 is approximately 64.39 cubic units.

To find the volume of the frustum, we need to use the formula V = (1/3)h(A1 + A2 + √(A1A2)), where V is the volume, h is the height, A1 is the area of the base, A2 is the area of the top, and √(A1A2) is the geometric mean of the areas. In this case, the height is 5, the base and top are both squares with sides of 9 and 4, respectively, and we can calculate the areas using A = s^2. Thus, A1 = 81 and A2 = 16. Plugging these values into the formula, we get V = (1/3)(5)(81 + 16 + √(81*16)) ≈ 64.39 cubic units. Therefore, the volume of the frustum of the pyramid is approximately 64.39 cubic units.

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Therefore, the transition matrix P from basis b to b' is:
P = |  0  -1  -7 |
      |  0   6   0  |
      | -4   0  -4 |

First, let's consider b'1 = (0, 0, 4). We can express this as 0*(-1, 0, 0) + 0*(0, 1, 0) + (-4)*(0, 0, -1), so the first column of P is (0, 0, -4).
Next, for b'2 = (1, 6, 0), we can express it as -1*(-1, 0, 0) + 6*(0, 1, 0) + 0*(0, 0, -1), so the second column of P is (-1, 6, 0).
Lastly, for b'3 = (7, 0, 4), we can express it as -7*(-1, 0, 0) + 0*(0, 1, 0) + (-4)*(0, 0, -1), so the third column of P is (-7, 0, -4).

Therefore, the transition matrix P from basis b to b' is:
P = |  0  -1  -7 |
      |  0   6   0  |
      | -4   0  -4 |

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The first year in which the taxpayer could receive a qualified distribution from the Roth IRA would be 2022.

To determine this, we need to look at the five-year rule for Roth IRA distributions. This rule states that a taxpayer must wait five years from the year of their first contribution to a Roth IRA before they can take a qualified distribution (i.e., a tax-free distribution of earnings and contributions).

Since the taxpayer made their first contribution for the 2018 tax year, the five-year clock starts on January 1, 2018. Therefore, the earliest year in which they could receive a qualified distribution is 2022.

It is important to note that there are other rules and exceptions that could affect when a taxpayer can take distributions from a Roth IRA,

such as age and disability, and that tax implications should also be considered when making decisions about Roth IRA contributions and distributions.

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The angles for which tan() is positive are B. 3/4 and D. 3. Using the reference angle of each given angle, we can determine which quadrant it falls in and whether the tangent is positive or negative.

The tangent function is defined as the ratio of the opposite side to the adjacent side of a right triangle. When the angle is acute (less than 90 degrees), the tangent is positive if and only if the opposite side is positive and the adjacent side is negative. This occurs in the second quadrant and fourth quadrant of the unit circle.

Using the reference angle of each given angle, we can determine which quadrant it falls in and whether the tangent is positive or negative.

A. - is not an angle measure, so it cannot be evaluated.

B. 3/4: The reference angle is 1/4 of a full rotation, which falls in the second quadrant. Therefore, the tangent is positive.

C. -3/4: The reference angle is 1/4 of a full rotation, which falls in the second quadrant. Therefore, the tangent is positive.

D. 3: The reference angle is 3/4 of a full rotation, which falls in the first quadrant. Therefore, the tangent is positive.

E. 7/6: The reference angle is 1/6 of a full rotation, which falls in the third quadrant. Therefore, the tangent is negative.

In summary, the angles for which tan() is positive are B. 3/4 and D. 3.

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To find the flow of the velocity field f=4y^2 i + (8xy)j along each of the paths from (0,0) to (4,8), we need to integrate the vector field along the paths. Let's consider two paths: (i) a straight line path from (0,0) to (4,8) and (ii) a curved path along the parabola y=x^2 from (0,0) to (4,16).

(i) For the straight line path, we have the parametric equations x=t, y=2t. Substituting these into the velocity field, we get f(t)=4(2t)^2 i + (8t)(2t)j = 16t^2 i + 16t^2 j. Integrating f(t) with respect to t from 0 to 4, we get the flow along the straight line path as:

∫f(t) dt = ∫16t^2 i + 16t^2 j dt = [4t^3 i + 4t^3 j] from 0 to 4

= 64i + 64j

(ii) For the curved path along the parabola y=x^2, we have the parametric equations x=t, y=t^2. Substituting these into the velocity field, we get f(t)=4(t^2)^2 i + (8t)(t^2)j = 4t^4 i + 8t^3 j. Integrating f(t) with respect to t from 0 to 4, we get the flow along the curved path as:

∫f(t) dt = ∫4t^4 i + 8t^3 j dt = [t^5 i + 2t^4 j] from 0 to 4

= 1024i + 512j

Therefore, the flow of the velocity field along the straight line path from (0,0) to (4,8) is 64i + 64j, and the flow along the curved path along the parabola y=x^2 from (0,0) to (4,16) is 1024i + 512j.

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The orthogonal decomposition of v with respect to w is v = (-4/10, -4/10, 6/10) + (22/10, -16/10, 9/10) = (18/5, -24/5, 15/5) = (18/5, -24/5, 3).

To find the orthogonal decomposition of v with respect to the subspace w, we need to find a vector w in w and a vector u in w⊥ such that v = w + u.

Let's begin by finding a basis for the subspace w. We can do this by setting up the augmented matrix [w | 0] and row reducing:

[−1 −1 0 | 0]

[3 4 1 | 0]

Row reducing gives us:

[1 1/3 0 | 0]

[0 0 1 | 0]

So a basis for the subspace w is {(-1, -1, 0), (0, 0, 1)}. We can use the Gram-Schmidt process to find an orthonormal basis for w, but for simplicity, let's just choose (0, 0, 1) as our basis vector w.

To find u, we need to project v onto w⊥, which is the subspace spanned by the vectors orthogonal to w.

Since we only have one basis vector for w, we can find a basis for w⊥ by finding a vector orthogonal to w. Let's choose (1, -1, 0) as our basis vector for w⊥. Then we can compute:

proj_w(v) = ((v ⋅ w)/(w ⋅ w)) w = (-4/10, -4/10, 6/10)

u = v - proj_w(v) = (22/10, -16/10, 9/10)

Therefore, the orthogonal decomposition of v with respect to w is v = (-4/10, -4/10, 6/10) + (22/10, -16/10, 9/10) = (18/5, -24/5, 15/5) = (18/5, -24/5, 3).

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The translation rule is (x, y) → (x + (-2) , y + 4)

We have,

From the figure,

We see the coordinates of Figure I.

(4, -5), (2, 1), and (-3, -3) _____(1)

We see that the coordinates of Figure Ii.

(2, -1), (0, 5), and (-5, 1) _____(2)

Now,

From (1) and (2),

Taking the corresponding coordinates.

(4, -5) and (2, -1)

(2, 1) and (0, 5)

(-3, -3) and (-5, 1)

We see that,

x coordinates is substrated by 2 and y coordinate is added by 4.

So,

The translation rule is (x, y) → (x + (-2) , y + 4)

Thus,

The translation rule is (x, y) → (x + (-2) , y + 4)

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Solving an exponential equation, we can see that it will take 14.4 years.

We know that Darin invests $4000 in an account that earns 4.8% annual interest compounded continuously.

The formula for a continuous copound is:

[tex]f(t) = A*e^{r*t}[/tex]

Where A is initial amount and r is the rate of interest, in this case we have:

A = $4000

r = 0.048

Then the formula is.

[tex]f(t) = 4000*e^{0.048*t}[/tex]

It will be doubled when f(t) = 8000, then we need to solve:

[tex]8000 = 4000*e^{0.048*t}\\\\8000/4000 = e^{0.048*t}\\2 = e^{0.048*t}\\\\ln(2) = 0.048*t\\\\t = ln(2)/0.048 = 14.4[/tex]

So it will take 14.4 years.

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