The equations can be solved as shown below.
How do you solve the equations?a) We have that;
( x+2 ) ( 10-x ) = 0
10x - x^2 + 20 - 2x = 0
x^2 + 2x - 10x - 20 = 0
x^2 -8x - 20 = 0
x = 10 or - 2
b) 7x + 15 = 6x + 3
7x - 6x = 3 - 15
x = - 12
c) 5x ( 3x + 5 ) = 0
15x^2 + 25x = 0
x = 0 or -5/3
d) (2x-1) ² = 0
(2x - 1) (2x - 1)
4x^2 - 2x - 2x + 1 =0
4x^2 - 4x + 1 = 0
x = 1/2(twice)
e) 4x² +13 = 14
4x² + 13 -14 = 0
4x² - 1 = 0
x = ±1/2
f) ( x-9 )² =16
(x - 9) (x - 9) = 16
x^2 - 9x - 9x + 81 = 16
x^2 - 18x +81 - 16 = 0
x^2 - 18x + 65 = 0
x = 13 or x = 5
These are the solutions of the equations.
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identify all of the necessary assumptions for a significance test for comparing two independent means. group of answer choices at least 15 successes and 15 failures in both groups. random samples or random application of treatments quantitiative data both sample sizes are greater than 30 or both population distributions could be normally distributed categorical data
The correct necessary assumptions for a significance test for comparing two independent means are:
B. Random samples or random application of treatments.C. Quantitative data.D. Both sample sizes are greater than 30 or both population distributions could be normally distributed.To conduct a significance test for comparing two independent means, you need to ensure the following necessary assumptions are met:
B. Random samples or random application of treatments: This ensures that the samples are representative of the populations, and any differences observed can be attributed to the treatments rather than biases in the selection process.C. Quantitative data: The data should be numeric and continuous to perform a significance test for comparing means.D. Both sample sizes are greater than 30 or both population distributions could be normally distributed: This ensures that the sampling distribution of the differences in means follows a normal distribution, allowing the use of methods like t-tests or z-tests for comparing the means.The reasons why the other options are incorrect:
Assumption A (at least 15 successes and 15 failures in both groups) is not necessary for comparing two independent means. It is more relevant to significance tests for proportions or categorical data.Assumption E (categorical data) is also not necessary for comparing two independent means, as means are calculated from numerical data, not categorical data.So, the correct answer is: B, C and D.
This question should be provided as:
Identify all of the necessary assumptions for a significance test for comparing two independent means. group of answer choices:
A. At least 15 successes and 15 failures in both groups.B. Random samples or random application of treatments.C. Quantitative data.D. Both sample sizes are greater than 30 or both population distributions could be normally distributed.E. Categorical data.Learn more about necessary assumptions: https://brainly.com/question/31972628
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if the coefficient of determination is 0.94, what can we say about the relationship between two variables? multiple choice the direction of the relationship is negative. ninety-four percent of the total variation of the dependent variable is explained by the independent variable. the direction of the relationship is positive. the strength of the relationship is 0.94.
If the coefficient of determination is 0.94, we can say that ninety-four percent of the total variation of the dependent variable is explained by the independent variable. The correct answer is: ninety-four percent of the total variation of the dependent variable is explained by the independent variable.
This means that there is a strong positive relationship between the two variables. The coefficient of determination, represented as R², measures the proportion of the total variation in the dependent variable that is explained by the independent variable. In this case, an R² of 0.94 indicates that 94% of the total variation in the dependent variable can be explained by the independent variable. The coefficient of determination does not provide information about the direction or strength of the relationship. The correct answer therefore is ninety-four percent of the total variation of the dependent variable is explained by the independent variable.
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Triangle ABC ~ triangle DEF. Use the image to answer the question. Determine the measurement of DF.
Answer:
3.04
Step-by-step explanation:
df/7.6=4.4/11
11df=4.4×7.6
df=4.4×7.6/11
df=3.04
Given f^-1(x) = -3/4 + 2, which equation represents f(x) ?
The equation for f(x) = 8/3 - 4x/3
We have function
[tex]f^{-1[/tex](x) = -3/4x + 2
let [tex]f^{-1[/tex](x) = y
So, y= -3/4x + 2
Now, solve the above equation for x we get
y -2 = -3/4x
-3x = 4y- 8
-x= 4y/3 - 8/3
x= 8/3 - 4y/3
Thus, the equation for f(x) = 8/3 - 4x/3
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decide which method of data collection you would use to collect data for the study specif either observational study experiment simulation or survey a study where political pollsters wishes to determine if his canditate is leading in the polls
For the study where political pollsters wish to determine if their candidate is leading in the polls, the most appropriate method of data collection would be a survey. This allows the pollsters to gather data directly from a representative sample of the population, ensuring accurate and relevant information about voters' preferences.
Surveys involve collecting data through questionnaires or interviews and are widely used in political polls to gather information from a large number of people. A survey would allow the pollsters to ask specific questions about the candidate and measure the responses from a representative sample of the population.
This method of data collection would provide the necessary information to determine if the candidate is leading in the polls.
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{(x, y)} : x3 }{ ( x, y ) : y-3} CAN ANYONE GRAPH THIS
The graph of {(x, y)} : x3 } and { ( x, y ) : y-3} is shown in image.
We have to given that;
Expression is,
⇒ {(x, y)} : x3 } and { ( x, y ) : y-3}
Now, We can find that;
Point (1.672, 4.672) is a solution of the give expression.
Hence, We get;
The graph of {(x, y)} : x3 } and { ( x, y ) : y-3} is shown in image.
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Differentiating pooled variance and the estimated standard error of the difference in sample means.
a. True
b. False
True. Pooled variance is the weighted average of the variances of two or more groups or samples, and it is used in calculating the estimated standard error of the difference in sample means.
The estimated standard error of the difference in sample means, on the other hand, is a measure of the variability of the differences between two sample means, and it takes into account the sample sizes and variances of the two groups being compared. Therefore, these two terms are related, but they represent different concepts in statistics.
The difference between pooled variance and the estimated standard error of the difference in sample means lies in their purpose and calculation. Pooled variance is a weighted average of the variances from two or more independent samples, while the estimated standard error of the difference in sample means measures the variability of the difference between the means of two samples.
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find the differential of the function. t = v 6 + uvw
The differential of the function, dt, can be represented as: dt = (∂t/∂v) dv + (∂t/∂u) du + (∂t/∂w) dw = (6v^5 + uw) dv + (vw) du + (uv) dw, Therefore, the differential of the function t = v6 + uvw is (6v5 + uw) dv + uv dw.
To find the differential of the function t = v6 + uvw, we can use the rules of calculus.
First, we can take the derivative of each term separately. The derivative of v6 is 6v5, and the derivative of uvw with respect to v is uw.
Then, we can multiply each derivative by the differential of the corresponding variable. So the differential of v is dv, the differential of u is du, and the differential of w is dw.
Putting it all together, we get:
dt = 6v5 dv + uw dv + uv dw + uv dv
Simplifying this expression, we get:
dt = (6v5 + uw) dv + uv dw
Therefore, the differential of the function t = v6 + uvw is (6v5 + uw) dv + uv dw.
To find the differential of the function t = v^6 + uvw with respect to a variable, say x, we'll use partial derivatives.
The partial derivative with respect to v: ∂t/∂v = 6v^5 + uw
The partial derivative with respect to u: ∂t/∂u = vw
The partial derivative with respect to w: ∂t/∂w = uv
The differential of the function, dt, can be represented as:
dt = (∂t/∂v) dv + (∂t/∂u) du + (∂t/∂w) dw = (6v^5 + uw) dv + (vw) du + (uv) dw
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A random sample of 100 customers at a local ice cream shop were asked what their favorite topping was. The following data was collected from the customers.
Topping Sprinkles Nuts Hot Fudge Chocolate Chips
Number of Customers 12 17 44 27
Which of the following graphs correctly displays the data?
a bar graph titled favorite topping with the x axis labeled topping and the y axis labeled number of customers, with the first bar labeled sprinkles going to a value of 17, the second bar labeled nuts going to a value of 12, the third bar labeled hot fudge going to a value of 27, and the fourth bar labeled chocolate chips going to a value of 44
a bar graph titled favorite topping with the x axis labeled topping and the y axis labeled number of customers, with the first bar labeled nuts going to a value of 17, the second bar labeled sprinkles going to a value of 12, the third bar labeled chocolate chips going to a value of 27, and the fourth bar labeled hot fudge going to a value of 44
a histogram titled favorite topping with the x axis labeled topping and the y axis labeled number of customers, with the first bar labeled sprinkles going to a value of 17, the second bar labeled nuts going to a value of 12, the third bar labeled hot fudge going to a value of 27 ,and the fourth bar labeled chocolate chips going to a value of 44
a histogram titled favorite topping with the x axis labeled topping and the y axis labeled number of customers, with the first bar labeled nuts going to a value of 17, the second bar labeled sprinkles going to a value of 12, the third bar labeled chocolate chips going to a value of 27, and the fourth bar labeled hot fudge going to a value of 44
The correct answer is A because this represents discrete categories - ice cream toppings specifically, and not continuous numerical data
How to solveThe provided data showcases the popular toppings among a random selection of customers and their respective frequency counts.
As this represents discrete categories - ice cream toppings specifically, and not continuous numerical data – it merits presentation via a bar graph which makes a suitable choice for accurate representation.
In contrast, using a histogram is inappropriate in this instance as histograms are intended to exhibit the distribution of frequency for continuous data points.
The relevant chart, Option A displays information using a precisely labeled x-axis ("Topping") along with a y-axis (“Number of Customers”) showcasing labeled bars, each accounting for exact values regarding topping popularity:
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What is the value of x?
The value of x is given as follows:
x = 9.
What is the Pythagorean Theorem?The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.
The theorem is expressed as follows:
c² = a² + b².
In which:
c is the length of the hypotenuse.a and b are the lengths of the other two sides (the legs) of the right-angled triangle.For this problem, we have that x is the length of the radius of the circle, hence:
The legs are of 12 and x.The hypotenuse is of x + 6.Hence the value of x is obtained as follows:
12² + x² = (x + 6)²
144 + x² = x² + 12x + 36
12x = 108
x = 108/12
x = 9.
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What is the slope of the line that
passes through the points (2, −5)
and (5, 7
Answer:4
Step-by-step explanation:
Since the slope of a line is equal to
[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex], you can use this to find the slope.
[tex]\frac{7-\left(-5\right)}{5-2}[/tex]
[tex]\frac{7+5}{5-2}[/tex]
[tex]\frac{12}{5-2}[/tex]
[tex]\frac{12}{3}[/tex]
[tex]4[/tex]
you plan on purchasing a new LCD television that cost $890 plus 8.1% tax. How much is the total cost of the television after tax?
The total cost of the television after tax is $962.09.
The total cost of the television after tax is equal to the sum of the cost of the television and the tax amount.
The tax amount is calculated as,
Tax amount = 8.1% of $890
Tax amount = 0.081 x $890
Tax amount = $72.09
Total cost of the television after-tax = Cost of the television + Tax amount
Total cost of the television after tax = $890 + $72.09
The total cost of the television after-tax = $962.09
Therefore, the total cost of the television after tax is $962.09.
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Find the distance between the two points in simplest radical form. (-6,5) and (-3,7)
Answer:
d = [tex]\sqrt{13}[/tex]
Step-by-step explanation:
The formula for distance, d, between two points is
[tex]d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex], where (x1, y1) are one point and (x2, y2) are another point.
We can allow (-6, 5) to be our (x1, y1) point and (-3, 7) to be our (x2, y2) point and plug the points into the formula:
[tex]d=\sqrt{(-6-(-3))^2+(5-7)^2}\\ d=\sqrt{(-6+3)^2+(-2)^2}\\ d=\sqrt{(-3)^2+4}\\ d=\sqrt{9+4}\\ d=\sqrt{13}[/tex]
√13 is already in simplest radical form because there are no perfect squares which can be factored out from 13
PLEASE HELP I INCLUDED THE PROBLEM IN IMAGE I WROTE IT DOWN!!!
The solution for the inequality expression g/20 ≤ 5 is derived to be g ≤ 100, which makes option B correct.
What are inequality signsInequality signs are mathematical symbols used to indicate that one quantity is greater than, less than, or equal to another quantity. These inequality signs includes:
Less than: <
Greater than: >
Less than or equal to: ≤
Greater than or equal to: ≥
These symbols are used in mathematical expressions and equations to compare values and express relationships between them.
Solving for the solution of the expression g/20 ≤ 5 as follows:
multiply both side of the inequality by 20
20 × g/20 ≤ 5 × 20
g ≤ 5 × 20 {20 will cancel out at the left hand side}.
g ≤ 100.
Therefore, the solution for the inequality expression g/20 ≤ 5 is derived to be g ≤ 100.
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Find an equation for the line that passes through the points (3, -5) and (-5, -3).
Answer:
y = -1/4x -17/4
Step-by-step explanation:
find answer attached...
Simplify using sutible identities
(2√2+1)2
The expression (2√2+1)² can be simplified to 9 + 4√2 using the identity (a+b)² = a² + 2ab + b².
We can simplify the expression (2√2+1)² using the identity (a+b)² = a² + 2ab + b².
The identity (a+b)² is a useful tool in simplifying expressions and can be used in a variety of mathematical problems.
Let a = 2√2 and b = 1, then we have:
(2√2+1)² = (2√2)² + 2(2√2)(1) + 1²
= 8 + 4√2 + 1
= 9 + 4√2
Therefore, (2√2+1)² simplifies to 9 + 4√2.
In summary, we can use the identity (a+b)² = a² + 2ab + b² to simplify expressions of the form (a+b)². In this case, we identified a = 2√2 and b = 1 and used the identity to simplify (2√2+1)² to 9 + 4√2.
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What is the formula for the volume of an octagon?
The formula for calculating the volume of an octagonal pyramid is
V = 1/3(Bh)
Formula to determine the volume of an Octagonal pyramidFrom the question, we are to determine the formula that can be used to determine the volume of octagonal pyramid.
An octagonal pyramid is a pyramid that has a bottom that's the shape of an octagon and has triangles as sides. It has a total of nine faces. The octagonal base and eight connecting triangles.
The formula for calculating the volume of an octagonal pyramid is
V = 1/3(Bh)
Where V is the volume of the octagonal pyramid
B is the area of the base
and his the perpendicular height
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4. consider the following time series (use excel for this problem). t 1 2 3 4 5 6 7 8 9 10 yt 120 110 100 96 94 92 88 84 82 78 a) construct a time series plot. what type of pattern exists in the data? b) develop the linear trend equation. what are the values for slope and intercept? c) what is the forecast for t
The forecast for t=11 is 90.76.
a) To construct a time series plot in Excel, you can follow these steps:
Enter the time period (t) in column A, starting from cell A2 and continuing down to A11.
Enter the corresponding values of the time series (yt) in column B, starting from cell B2 and continuing down to B11.
Select the range of cells containing the time period and the time series values (A1:B11).
Click on the "Insert" tab in the Excel ribbon.
Click on the "Line" chart type and select the first option (2-D Line).
Your time series plot should now appear on the worksheet.
Based on the plot, it appears that there is a downward linear trend in the data.
b) To develop the linear trend equation, we can use Excel's LINEST function. Follow these steps:
In cell D2, enter the formula "=LINEST(B2:B11,A2:A11)"
Press CTRL+SHIFT+ENTER to enter the formula as an array formula. The slope and intercept values should appear in cells D2 and D3, respectively.
The linear trend equation is: yt = -3.04t + 123.6
The slope is -3.04 and the intercept is 123.6.
c) To find the forecast for t=11, we can use the linear trend equation and substitute t=11.
Therefore, yt = -3.04(11) + 123.6 = 90.76.
So the forecast for t=11 is 90.76.
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find the indefinite integral by making a change of variables. (hint: let u be the denominator of the integrand. remember to use absolute values where appropriate. use c for the constant of integration.)
The indefinite integral is: ∫(1/(x^2+1))dx = ln|x^2 + 1| + c, where c is the constant of integration
To find the indefinite integral by making a change of variables, we can use the substitution method. Let u be the denominator of the integrand, so we can write:
∫(1/(x^2+1))dx = ∫(1/u) * (du/dx) dx
To find du/dx, we differentiate both sides of u = x^2 + 1 with respect to x:
du/dx = 2x
Substituting this into our integral, we get:
∫(1/u) * (du/dx) dx = ∫(1/u) * (2x) dx
Now we can make a change of variables by letting f(u) = ln|u|. Using the chain rule, we have:
df/du = 1/u
Substituting this into our integral, we get:
∫(1/u) * (2x) dx = 2∫(df/du) * x dx
Integrating with respect to x, we get:
2∫(df/du) * x dx = x * ln|u| + c
Substituting u = x^2 + 1, we get:
x * ln|u| + c = x * ln|x^2 + 1| + c
Therefore, the indefinite integral is:
∫(1/(x^2+1))dx = ln|x^2 + 1| + c, where c is the constant of integration.
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Enter the number that makes the equation true. 17
0. 54 +
100
+
100
17
100
The number that makes the equation 0.54 + 17/100 = x/100 + 17/100 true is 54.
To solve this equation, we want to isolate x on one side of the equation.
Starting with:
0.54 + 17/100 = x/100 + 17/100
We can first simplify the left side by finding a common denominator for 0.54 and 17/100:
0.54 = 54/100
54/100 + 17/100 = 71/100
Now, we can simplify the right side by combining like terms:
x/100 + 17/100 = (x + 17)/100
Substituting these simplifications back into the original equation, we get:
71/100 = (x + 17)/100
To isolate x, we can multiply both sides by 100:
71 = x + 17
Subtracting 17 from both sides, we get:
x = 54
Therefore, the number that makes the equation true is 54.
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The question is -
Enter the number that makes the equation true.
0.54 + 17/100 = x/100 + 17/100
The graph shows Wilson's science scores versus the number of hours spent doing science homework.
A graph titled Wilsons Science Scores shows Hours of Practice in a Week on x axis and Science Scores on y axis. The x axis scale is shown from 0 to 5 at increments of 1, and the y axis scale is shown from 0 to 50 at increments of 5.The ordered pairs 0, 15 and 0.5, 18 and 1, 18 and 1.5, 25 and 2, 30 and 2.5, 35 and 3, 40 and 3.5, 43 and 4, 41 and 4.5, 45 and 5, 48 are shown on the graph. A straight line joins the ordered pairs 0, 14.9 and 5, 50.
What will most likely be Wilson's approximate science score if he does science homework for 6 hours a week? (5 points)
33 points
42 points
52 points
55 points
Answer:
Since we are given a straight line on the graph that connects the two endpoints, we can assume that Wilson's scores will follow a linear relationship with the number of hours of science homework done. We can use the equation of the line to estimate Wilson's approximate science score for 6 hours of science homework.
From the graph, we can see that the slope of the line is:
slope = (50 - 14.9) / (5 - 0) = 35.1 / 5 = 7.02
This means that Wilson's science score increases by approximately 7.02 for each additional hour of science homework per week.
To estimate Wilson's score for 6 hours of science homework, we can use the equation of the line:
y = mx + b
where y is Wilson's science score, x is the number of hours of science homework per week, m is the slope of the line, and b is the y-intercept of the line.
We can use the point (0, 14.9) on the line to find the value of b:
14.9 = 7.02(0) + b
b = 14.9
Now we can use the equation of the line to estimate Wilson's score for 6 hours of science homework:
y = 7.02(6) + 14.9
y = 42.12 + 14.9
y = 57.02
Therefore, Wilson's approximate science score if he does science homework for 6 hours a week would be around 57.02.
Step-by-step explanation:
In a Cartesian coordinate system for a three-dimensional space.
Sphere (S) is represented by equation: [tex](x-1)^2+(y+2)^2+(z-3)^2=25[/tex].
Plane (P) is represented by equation: [tex]x+2y-2z+1=0[/tex].
Line (d) is parallel to (P), passes through the origin and passes through (S) at two separate points A & B. Find the maximum length of AB.
In a Cartesian coordinate system for a three-dimensional space, let the sphere S be represented by the equation:
(x - a)^2 + (y - b)^2 + (z - c)^2 = r^2
where (a, b, c) are the coordinates of the center of the sphere, and r is the radius.
Let the plane P be represented by the equation:
Ax + By + Cz + D = 0
where (A, B, C) is the normal vector to the plane.
Since the line d is parallel to P and passes through the origin, it can be represented by the equation:
lx + my + nz = 0
where (l, m, n) is a vector parallel to the plane P.
To find the intersection points of the sphere S and the line d, we can substitute the equation of the line into the equation of the sphere, which gives us a quadratic equation in t:
(lt - a)^2 + (mt - b)^2 + (nt - c)^2 = r^2
Expanding this equation and collecting terms, we get:
(l^2 + m^2 + n^2) t^2 - 2(al + bm + cn) t + (a^2 + b^2 + c^2 - r^2) = 0
Since the line d passes through the origin, we have:
l(0 - a) + m(0 - b) + n(0 - c) = 0
which simplifies to:
al + bm + cn = 0
Therefore, the quadratic equation reduces to:
(l^2 + m^2 + n^2) t^2 + (a^2 + b^2 + c^2 - r^2) = 0
This equation has two solutions for t, which correspond to the two intersection points of the line d and the sphere S:
t1 = -(a^2 + b^2 + c^2 - r^2) / (l^2 + m^2 + n^2)
t2 = -t1
The coordinates of the intersection points can be obtained by substituting these values of t into the equation of the line d:
A = lt1, B = mt1, C = nt1
and
D = lt2, E = mt2, F = nt2
To find the distance between A and B, we can use the distance formula:
AB = sqrt((A - D)^2 + (B - E)^2 + (C - F)^2)
To maximize this distance, we can differentiate the distance formula with respect to t1 and set the derivative equal to zero:
d/dt1 (AB)^2 = 2(A - D)l + 2(B - E)m + 2(C - F)n = 0
This equation represents the condition that the direction vector (A - D, B - E, C - F) is orthogonal to the line d. Therefore, the vector (A - D, B - E, C - F) is parallel to the normal vector (l, m, n) of the plane P.
Using this condition, we can find the values of t1 and t2 that correspond to the maximum distance AB. Then we can substitute these values into the distance formula to find the maximum length of AB.
Rationalize the denominator and simplify:
a+√b / √b
Rationalizing the denominator and simplifying a+√b / √b gives (a√b + b)/b
Rationalizing the denominator and simplifyingFrom the question, we have the following expression that can be used in our computation:
a+√b / √b
Rationalizing the denominator, we get
a+√b / √b * √b/√b
So, we have
(a√b + b)/b
Hence, the solution is (a√b + b)/b
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y= A(0.5)^t/(half-life) What is half-life
The half-life is the amount of time it takes for a quantity to reduce to half its initial value.
In the equation y = A(0.5)^(t/half-life), the half-life is represented as a variable in the denominator of the exponent.
y is the final value of the quantity after a certain amount of time, t.
A is the initial value of the quantity at the beginning (t = 0).
0.5 is the factor that represents a 50% decrease, as we are considering half-life.
t is the time that has passed.
half-life is the time it takes for the quantity to reduce to half its initial value.
In this equation, the half-life is used to determine how much of the initial quantity (A) remains after a certain amount of time (t). By dividing t by the half-life in the exponent, we can calculate the remaining quantity (y) after the specified time.
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The shape of a colony of bacteria on a Petri dish is circular Find the approximate increase in its area if its radius increases from 30 mm to 31 mm. [Recall that the area of a circle is A = ar?) The estimated change in area is mm2. (Round to two decimal places as needed.) ed con ew!
The approximate increase in area, rounded to two decimal places, is: ΔA ≈ 61 × 3.14 ≈ 191.54 mm². The estimated change in area can be calculated using the formula for the area of a circle, A = πr^2.
When the radius increases from 30 mm to 31 mm, the new area can be found as:
A_new = π(31 mm)^2 = 961π mm^2
Similarly, the original area can be found as:
A_old = π(30 mm)^2 = 900π mm^2
The approximate increase in area can be found by subtracting the old area from the new area:
ΔA = A_new - A_old = 961π mm^2 - 900π mm^2 = 61π mm^2
Using a calculator or approximating π to 3.14, we can calculate the approximate increase in area as:
ΔA ≈ 61(3.14) mm^2 ≈ 191.54 mm^2
Therefore, the estimated change in area is approximately 191.54 mm^2.
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Deepa usa unidades cuadradas para hallar el área de la figura
The units of your measurements will determine the square units of your final result
How to solveCalculating the area of a shape is reliant on determining how many square units can be accommodated within the perimeter, without gaps or overlaps.
Here are instructions to help determine this for various shapes:
Rectangle or Square:
Start by gauging both the length (l) as well as width (w) measurements of the rectangle/square.
Compute the dimensions by multiplying the pre-existing values which in turn will give you the overall area; Area = l × w.
The concluding value shall be measured in square units such as e.g., square centimeters, and square inches.
Triangle:
Begin by gauging two factors -- base (b), and height (h) of the triangle. The height refers to the perpendicular measurement from one end of a baseline to its opposite vertex.
Next, obtain the magnitude of the intended dimension by computing the product of base and height measurements before dividing by 2 which leads to arriving at the final area figure: Area = (b × h) / 2
This resultant figure also measures in square units.
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The question in English is:
Deepa uses square units to find the area of the figure
This is an incomplete question, so a general overview was provided above.
(6m−7)⋅4= how do you distribute this equation to creat an a equivalent expression
Step-by-step explanation:
= 6m* 4 - 7 *4
= 24 m - 28
A (-3,6 ) B (-2,9 ) the equation in point slope form step by step
The equation in point-slope form of the line that passes through the points given is expressed as: y - 6 = 3(x + 3).
What is the Equation for a Line in Point-Slope Form?The equation of a line can be expressed in the point-slope form, where (x1, y1) is a point on the line and m is the slope of the line, as:
y - y1 = m(x - x1).
Given the following points:
A (-3,6 ) and B (-2,9 )
Slope (m) = change in y / change in x = (9 - 6) / (-2 - (-3))
Slope (m) = 3 / 1
m = 3
Using one of the points and the slope, we can write the equation by substituting x1 = -3, y1 =6, and m = 3 into y - y1 = m(x - x1):
y - 6 = 3(x + 3)
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halp witht these two problems and show you got the answer
The required measure of the angle ∠KJL is 40°.
From the figure,
The circle O, with tangent JPL and secant JIKY,
The sum of the arcs is 360°,
KP + IP + IK = 360°
IP + IP + 120 = 360
IP = 80°
Now,
KP = 2 × 80 = 160°
Here,
Following the expression to determine the ∠KJL,
= KP - IP / 2
= 160 - 80 / 2
= 40°
Thus, the required measure of the angle ∠KJL is 40°.
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Please find minimum value of g. Will mark brainliest.