Solve the inequality for x.
-10≤2x-4
Simplify your answer as much as possible.

Answers

Answer 1

Answer:

x ≥ -3

Step-by-step explanation:

-10 ≤ 2x - 4

-6 ≤ 2x

x ≥ -3

We can't simplify any more, so the answer is x ≥ -3


Related Questions

On January 1, Year 2, Kincaid Company's Accounts Receivable and the Allowance for Doubtful Accounts carried balances of $74,600 and $3,700, respectively. During Year 2, Kincaid reported $208,000 of credit sales, wrote off $2,000 of receivables as uncollectible, and collected cash from receivables amounting to $258,900. Kincaid estimates that it will be unable to collect one percent (1%) of credit sales.

What effect will recognizing the uncollectible accounts expense for Year 2 have on the elements of the financial statements?

Multiple Choice

Decrease total assets and net income


Decrease total assets and increase retained earnings


Increase total assets and decrease net income


Increase total assets and retained earnings

Answers

The correct answer is: Decrease total assets and net income.

What is statistics?

Statistics is a branch of mathematics that deals with the collection, analysis, interpretation, presentation, and organization of numerical data. It involves the use of methods and techniques to gather, summarize, and draw conclusions from data.

The recognition of uncollectible accounts expense for Year 2 will decrease total assets and net income.

When uncollectible accounts expense is recognized, it is recorded as a debit to the allowance for doubtful accounts and a credit to the uncollectible accounts expense account. This reduces the balance of accounts receivable, which is a current asset, and thus decreases total assets. Additionally, recognizing this expense reduces net income by the same amount.

Therefore, the correct answer is: Decrease total assets and net income.

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x=10 3x+5y=20 in the system of equations, what is the value of x

Answers

The value of x is given as x = 10 in the system of equations 3x + 5y = 20.

This means that we can substitute x = 10 into the equation 3x + 5y = 20 to solve for y:

3(10) + 5y = 20

30 + 5y = 20

5y = -10

y = -2

Therefore, the solution to the system of equations 3x + 5y = 20 and x = 10 is (x,y) = (10,-2).

The ratio of union members to nonunion members working for a company is 4 to 5. If there are 140 nonunion members working for the company,
what is the total number of employees?

Answers

The total number of employees is 112.

Explain numbers

Numbers are symbols or representations used to quantify or count objects, quantities, or measurements. They form the basis of mathematical operations, such as addition, subtraction, multiplication, and division, and are used in various fields such as science, finance, and engineering. Numbers can be positive, negative, whole, or fractional, and are essential for communication and calculation in our daily lives.

According to the given information

Let's use x to represent the total number of employees.

According to the problem, the ratio of union members to nonunion members is 4 to 5. This means that out of every 4 + 5 = 9 employee, 4 are union members and 5 are nonunion members.

So, we can set up the following proportion:

4/9 = x/(x - 140)

To solve for x, we can cross-multiply and simplify:

4(x - 140) = 9x

4x - 560 = 9x

560 = 5x

x = 112

Therefore, the total number of employees is 112.

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Work out sheet below please

Answers

Using division we know that per pound the loose sweets have a better value which is £0.0089 per pound.

What is division?

The division is one of the four basic arithmetic operations or the process by which two numbers are added together to produce a new number.

Multiplication, addition, and subtraction make up the remaining operations.

We may examine the quotient and the division's remainder using the division formula Dividend = (Divisor Quotient) + Remainder.

We can multiply our quotient by the divisor to check its accuracy if the remainder is 0.

If the product and dividend are equal, the quotient is correct.

So, the price per gram when pre-packed:

1.49/120 = £0.012

Now, the price per gram when the product is loose:

0.89/100 = £0.0089

Now, we know that per pound the loose sweets are better.

Therefore, using division we know that per pound the loose sweets have a better value which is £0.0089 per pound.

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The value of a certain collectible card in dollars from January 2020 to May 2021 can be modeled by the function V(m)=250m² -3,500m + 18,000, where mis
the approximate number of months since the start of 2020.
Over what period was the value of the card declining?

Answers

To respond to the question, we must identify the m-values for which V(m)  equation decreases. The value of the card decreased during the course of the time from January 2020 to July 2020 (about 7 months),

What is equation?

A mathematical equation is a formula that connects two claims and uses the equals symbol (=) to denote equivalence. An equation in algebra is a mathematical statement that establishes the equivalence of two mathematical expressions. For instance, in the equation 3x + 5 = 14, the equal sign places a space between the variables 3x + 5 and 14. The relationship between the two sentences that are written on each side of a letter may be understood using a mathematical formula. The symbol and the single variable are frequently the same. as in, 2x - 4 equals 2, for instance.

We must identify the values of m for which the function V(m) is dropping in order to estimate the time span during which the value of the card was declining.

The function V(m)'s derivative is provided by:

V'(m) = 500m - 3,500

By setting V'(m) = 0 and solving for m, we may determine the crucial point(s):

500m - 3,500 = 0

m = 7

V''(m) = 500

To respond to the question, we must identify the m-values for which V(m) decreases. The value of the card decreased during the course of the time from January 2020 to July 2020 (about 7 months), as we know that V(m) is falling for m 7.

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Find the inradius of triangle ABC.

Find the circumradius of triangle ABC.

The sides of the triangle are 5, 29, and 42.

Answers

To find the inradius of triangle ABC, we can use the formula:

inradius = area / semiperimeter,

where the semiperimeter is the sum of the three sides divided by 2, and the area can be found using Heron's formula:

semiperimeter = (5 + 29 + 42) / 2 = 38

area = sqrt(s * (s - a) * (s - b) * (s - c)), where s is the semiperimeter, and a, b, and c are the lengths of the sides.

area = sqrt(38 * (38 - 5) * (38 - 29) * (38 - 42)) = 90

inradius = area / semiperimeter = 90 / 38 = 45 / 19

Therefore, the inradius of triangle ABC is 45/19.

To find the circumradius of triangle ABC, we can use the formula:

circumradius = a/(2*sin(A)) = b/(2*sin(B)) = c/(2*sin(C)),

where a, b, and c are the lengths of the sides, and A, B, and C are the corresponding angles opposite those sides.

We can use the law of sines to find the angles:

sin(A) = (area * 2) / (a * b)
sin(B) = (area * 2) / (b * c)
sin(C) = (area * 2) / (c * a)

where area is the same area we found earlier using Heron's formula.

Substituting the values, we get:

sin(A) = 90 / (5 * 29) = 6/145
sin(B) = 90 / (29 * 42) = 10/87
sin(C) = 90 / (42 * 5) = 2/7

Now we can use the formula for the circumradius:

circumradius = a/(2*sin(A)) = b/(2*sin(B)) = c/(2*sin(C))

circumradius = 5/(2*6/145) = 29/(2*10/87) = 42/(2*2/7)

circumradius = 725/12

Therefore, the circumradius of triangle ABC is 725/12.

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Give the equation of a rational function which has all of the properties above.

Answers

Im probably wrong but here you go

To find the equation of a rational function that satisfies the given properties, we can use the fact that a rational function can be written as the quotient of two polynomials. We know that the function has x-intercepts at (2,0) and (6,0), which means that the denominator must contain factors of (x-2) and (x-6):

r(x) = A(x-2)(x-6)/...

where A is a constant coefficient that we need to determine and the ellipsis (...) represents the remaining factors of the denominator.

We also know that there is a hole at x=1, which means that both the numerator and denominator have a factor of (x-1). To ensure that the hole cancels out, we can simplify the expression by dividing both the numerator and denominator by (x-1):

r(x) = A(x-2)(x-6)/(x-1)(x-1)... (1)

Now, we need to include the vertical asymptotes at x=5 and x=3. This means that the denominator must contain factors of (x-5) and (x-3). However, we also need to ensure that the end-behavior of the function is given by f(x) -> 1 as x -> ± infinity. This can be achieved by making the degree of the numerator equal to the degree of the denominator, and ensuring that the leading coefficient of the numerator is equal to the leading coefficient of the denominator.

To achieve this, we can set the denominator to be (x-5)(x-3)^2, and choose the numerator to be a constant multiple of (x-1)(x-1):

r(x) = A(x-2)(x-6)/(x-1)(x-1)(x-5)(x-3)^2

Now, we need to determine the value of the constant A. Since we know that r(x) has a hole at x=1, we can use the fact that the limit of r(x) as x approaches 1 must exist and be finite. This means that the factors of (x-1) must cancel out in the numerator and denominator, and we can use this to solve for A:

lim(x->1) r(x) = lim(x->1) A(x-2)(x-6)/(x-1)(x-1)(x-5)(x-3)^2
= A(-1)(-5)/(-4)^3
= 5A/64

We know that the limit must exist and be finite, and we also know that it must equal some number k, since r(x) has a hole at x=1. Therefore, we can set 5A/64 = k, and solve for A:

A = 64k/5

Substituting this value of A into equation (1), we get the final equation for r(x):

r(x) = (64k/5)(x-2)(x-6)/(x-1)(x-1)(x-5)(x-3)^2

where k is any non-zero constant.

Answer:

One possible rational function that satisfies the given properties is:

r(x) = (x-2)(x-6) / [(x-3)(x-5)]

Step-by-step explanation:

x-intercepts at (2,0) and (6,0)

The x-intercepts are the points where the function crosses the x-axis, i.e., where the function value is zero. Since we are given that the function has x-intercepts at (2,0) and (6,0), we know that the function can be factored as:

r(x) = A(x-2)(x-6)

where A is a constant that we need to determine.

A hole at x=1 and vertical asymptotes at x=5 and x=3

A hole in a rational function occurs when there are factors in the numerator and denominator that cancel out, leaving a "hole" in the graph. In this case, we are given that there is a hole at x=1, which means that there must be a common factor of (x-1) in both the numerator and denominator. So, we can write:

r(x) = A(x-2)(x-6) / (B(x-1)(x-3)(x-5))

where B is another constant that we need to determine.

We are also given that there are vertical asymptotes at x=5 and x=3, which means that the denominator must have factors of (x-5) and (x-3) that do not cancel out with any factors in the numerator. So, we can write:

r(x) = A(x-2)(x-6) / (B(x-1)(x-3)(x-5)) = [A(x-2)(x-6)] / [(B(x-1))(x-3)(x-5)]

End behavior given by x → ∞ ,f(x) → 1 and x → -∞ ,f(x) → 1

The end behavior of a rational function is determined by the degree of the numerator and denominator. Since the numerator and denominator in this case have the same degree (3), we know that the end behavior is given by the ratio of the leading coefficients, which is A/B. We are told that the end behavior approaches 1 as x approaches infinity or negative infinity, so we can set A/B = 1 and solve for A in terms of B:

A/B = 1, so A = B

Putting it all together

We now have enough information to write the equation for the rational function with the given properties:

r(x) = A(x-2)(x-6) / (B(x-1)(x-3)(x-5))

Using A = B, we get:

r(x) = A(x-2)(x-6) / [A(x-1)(x-3)(x-5)]

Canceling out the common factor of (x-1) in the numerator and denominator, we get:

r(x) = (x-2)(x-6) / [(x-3)(x-5)]

which is the equation for the desired rational function.

What is the equation of the circle with centre
(1/2, 0)and radius 2?
Responses (attached)

Answers

The equation of the circle is (x - 1/2)^2 + y^2 = 15/4.

How to calculate the equation

The equation of a circle with center (a,b) and radius r is given by the equation:

(x - a)^2 + (y - b)^2 = r^2

Using the given values, the equation of the circle with center (1/2, 0) and radius 2 is:

(x - 1/2)^2 + (y - 0)^2 = 2^2

Expanding and simplifying, we get:

(x - 1/2)^2 + y^2 = 4 - 1/4

Therefore, the equation of the circle is:

(x - 1/2)^2 + y^2 = 15/4

So, the equation of the circle is (x - 1/2)^2 + y^2 = 15/4.

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please help meeeee. What is the value of k?

Answers

Answer:

k = 10

Step-by-step explanation:

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ MYZ is an exterior angle of the triangle , then

4k + 5 + 6k + 10 = 115

10k + 15 = 115 ( subtract 15 from both sides )

10k = 100 ( divide both sides by 10 )

k = 10

Answer:

k = 10

----------------------

Exterior angle of a triangle is equal to the sum of remote interior angles.

In the given picture, the exterior angle is 115°, and remote interior angles are (4k + 5)° and (6k + 10)°.

Set up equation and solve for k:

4k + 5 + 6k + 10 = 11510k + 15 = 11510k = 100k = 10

Therefore the value of k is 10.

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Angie is really fit and wants to test her endurance by competing in a swimming competition over four days. On the first day, she covers 25 per cent of the distance. On the second day, she covers one third of the remaining distance, on the third day, 25 per cent of the remaining distance and, on the final day, she swims half of the remaining distance. She still has 15km to swim to complete the competition. Form a linear equation and find the total distance of the swimming competition. (Use x as the total distance of the swimming competition).

Answers

Let's start by using algebra to represent the problem mathematically.

On the first day, Angie covers 25% of the total distance, which can be written as:

0.25x

On the second day, she covers one third of the remaining distance. After the first day, she has 75% of the total distance left to cover. So, the distance she covers on the second day can be written as:

(1/3)(0.75x) = 0.25x

On the third day, she covers 25% of the remaining distance. After the first two days, she has 50% of the total distance left to cover. So, the distance she covers on the third day can be written as:

0.25(0.5x) = 0.125x

On the final day, she covers half of the remaining distance. After the first three days, she has 25% of the total distance left to cover. So, the distance she covers on the final day can be written as:

0.5(0.25x) = 0.125x

Adding up the distances she covered on each day, we get:

0.25x + 0.25x + 0.125x + 0.125x = 0.75x

This represents the total distance she covered over the four days.

We know that Angie still has 15km left to swim to complete the competition. So, we can set the total distance x equal to the distance she covered plus the remaining distance:

0.75x + 15 = x

Solving for x, we get:

0.25x = 15

x = 60

Therefore, the total distance of the swimming competition is 60km.

Answer: Total distance of the swimming competition is 55.56 km.

Step-by-step explanation:

Let x be the total distance of the swimming competition.

On the first day, Angie covered 25% of the total distance, which means she swam 0.25x km.

On the second day, she covered one-third of the remaining distance, which is (1 - 0.25)x = 0.75x km.

So, she swam (1/3) * 0.75x = 0.25x km on the second day.

On the third day, she covered 25% of the remaining distance, which is (1 - 0.25 - 1/3)x = 0.42x km.

So, she swam 0.25 * 0.42x = 0.105x km on the third day.

On the final day, she swam half of the remaining distance,

which is (1 - 0.25 - 1/3 - 0.5)x = 0.125x km.

The total distance she swam is the sum of the distances swum on each day:

0.25x + 0.25x + 0.105x + 0.125x = 0.73x

We know that the total distance of the competition is x - 15 km (since she still has 15 km left to swim).

So we can set up the equation:

0.73x = x - 15

Solving for x, we get:

x-0.73x = 15

0.27x = 15

x = 55.56

Therefore, the total distance of the swimming competition is 55.56 km.

A retail manager constructs a 95% confidence interval to estimate the mean amount of money each customer spends per visit to the retail store. Assume that all conditions have been met. The one-sample t-interval is ($10.53, $31.89). The owner of the retail store will issue the manager a bonus if the customers spend $35, on average, per visit. Is it reasonable to believe this manager will receive a bonus? No. Because a different sample might give different results, no conclusion can be drawn. No. Because the interval does not contain $35, the manager would not be issued the bonus. Yes. Because the interval representing the mean amount customers spend per visit is entirely below $35, it is reasonable to believe the manager will be issued a bonus. Yes. Because the interval representing the mean amount customers spend per visit does not contain $35, it is reasonable to believe the manager will be issued a bonus.

Answers

The correct option is: No. Because the interval does not contain $35, the manager would not be issued the bonus.

What is an interval?

An interval refers to a range of values between two points on a numerical scale. It can be represented by two numbers, called endpoints, and includes all the values that lie between these endpoints.

The two common types of intervals are closed intervals and open intervals.

According to the given information:

In a confidence interval, the range of values within which the true population parameter (in this case, the mean amount of money each customer spends per visit) is likely to fall is estimated. A 95% confidence interval means that there is a 95% probability that the true population parameter falls within the interval.

In this case, the confidence interval is ($10.53, $31.89), which means that we are 95% confident that the true mean amount customers spend per visit falls between $10.53 and $31.89. Since the interval does not contain $35, it is not reasonable to believe that the manager will receive a bonus, as the estimated mean amount spent per visit is below $35 according to the confidence interval.

The correct answer is: No. Because the interval does not contain $35, the manager would not be issued the bonus.

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please answer in detail​

Answers

Answer:

y = 2x + 4

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 2x + 3 ← is in slope- intercept form

with slope m = 2

• Parallel lines have equal slopes , then

slope of line AB is m = 2

line AB crosses the y- axis at (0, 4 ) ⇒ c = 4

y = 2x + 4 ← equation of line AB

Workout 461÷4 give your answer as a whole number and a reminder

Answers

Step-by-step explanation:

the answer is 115 remainder 1

Find the gradients of lines A and B

Answers

I'm afraid you forgot to add a picture?

Is the graph increasing, decreasing, or constant?
-8 -6 4
A. Decreasing
B. Increasing
C. Constant
-2
4-
2
-2
AY
2
4
6
8
SUBMIT

Answers

Is the graph increasing, decreasing, or constant: C. Constant.

What is a graph?

In Mathematics and Geometry, a graph can be defined as a type of chart that is typically used for the graphical representation of data points or ordered pairs on both the horizontal and vertical lines of a cartesian coordinate, which are the x-coordinate (x-axis) and y-coordinate (y-axis) respectively.

By critically observing the graph shown above, we can reasonably infer and logically deduce that the graph is constant because it assumes only one y-value, which is represented by this equation y = 3.

In conclusion, the above is constant, rather than increasing or decreasing.

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Home values in a town have declined 26% per year for each of the past
four years. What was the total percentage decrease in home values
during the four-year period?

Answers

Answer: 104%

Step-by-step explanation: 26% times 4 years

4.4.3 Quiz: Stretching and Compressing Functions
f(x) = x². What is g(x)?
10
g(x)
Y
5- f(x)
O B. g(x) =
(2,2)
Click here for long description
2
O A. g(x) = (x)²
O c. g(x) =
OD. g(x) = 2x²
2
5


X

Answers

The equation of the function g(x) is g(x) = 1/2x²

Calculating the function g(x)

If we want to stretch or compress the function f(x) = x^2, we can multiply or divide the input variable x by a constant value a.

Specifically, if we use g(x) = f(ax), then g(x) is a stretched or compressed version of f(x).

To find the value of a that will make g(x) pass through the point (2,2), we can substitute these values into the equation g(x) = f(ax):

[tex]g(2)=f(a*2)=f(2a)=(2a)^2 =4a^2 =2[/tex]

So, we have

a = 1/2

Recall that

g(x) = f(ax)

So, we have

g(x) = f(1/2x)

This means that

g(x) = 1/2x²

Hence. the function is g(x) = 1/2x²


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Solve by using matrices.
2x -y + 3z = 180
-4x + 2y + 3z = 225
3x - 4y = 270
X
= -66, y = [?], z =
Enter

Answers

Solving the system of equations using matrices is : = -66, y = 163, and z = 11.

Solving the system of equations using matrices ?

To solve this system of equations using matrices, we can write it in the form AX = B, where:

A = coefficient matrix

X = variable matrix (containing x, y, and z)

B = constant matrix (containing the constants on the right-hand side of each equation)

So, we have:

| 2  -1  3 |   | x |   | 180 |

| -4  2  3 | x | y | = | 225 |

| 3  -4  0 |   | z |   | 270 |

We can solve for X by multiplying both sides of the equation by the inverse of A:

X = A^-1 * B

First, we need to find the inverse of A. We can do this by using the formula:

A^-1 = (1 / det(A)) * adj(A)

where det(A) is the determinant of A and adj(A) is the adjugate (transpose of the cofactor matrix) of A.

| 2  -1  3 |

| -4  2  3 |

| 3  -4  0 |

det(A) = 2(20 - 3(-4)) - (-1)(-40 - 33) + 3(-4*(-1) - 2*3) = 16

| 2  -1  3 |

| -4  2  3 |

| 3  -4  0 |

The cofactor matrix is:

| 2  9  6 |

| 12  0  -2 |

| 13  -9  8 |

Taking the transpose of the cofactor matrix gives us the adjugate of A:

| 2  12  13 |

| 9  0  -9 |

| 6  -2  8 |

So, we have:

A^-1 = (1 / det(A)) * adj(A) = (1 / 16) *

| 2  12  13 |

| 9  0  -9 |

| 6  -2  8 |

Multiplying A^-1 by B gives us:

| x |   | -66 |

| y | = | 163 |

| z |   | 11  |

Therefore, x = -66, y = 163, and z = 11.

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Help me thank you
click the screenshot for more info

Answers

Answer: The actual difference between the numbers is:

87.71 - 5.8 = 81.91

Therefore, Yasmine's estimate was 81, and the actual difference between the numbers is 81.91. Brainliest?

Step-by-step explanation:

To round 87.71 to the nearest whole number, we look at the digit in the ones place, which is 1. Since 1 is less than 5, we round down to 87. To round 5.8 to the nearest whole number, we look at the digit in the ones place, which is 8. Since 8 is greater than or equal to 5, we round up to 6.

Using these rounded values, Yasmine estimated the difference between the numbers to be 87 - 6 = 81.

The actual difference between the numbers is:

87.71 - 5.8 = 81.91

Therefore, Yasmine's estimate was 81, and the actual difference between the numbers is 81.91.

Answer:

Yasmine estimated the difference to be 82. The actual difference is 81.91.

Step-by-step explanation:

The rounded whole number of 87.71 is 88 and the rounded whole number of 5.8 is 6.

So, the difference between the numbers 87.71 and 5.8 by rounding each number to the nearest whole numbers will be

(88 - 6) = 82.

The actual difference between the numbers 87.71 and 5.8 is (87.71 - 5.8) = 81.91.

Therefore, Yasmine estimated the difference to be 82. The actual difference is 81.91.

Determine the domain and range of the graph of this function.

Answers

x ≤ 4, -2≤ y ≤ 2  are the domain and range of the graph of this function.

What is the domain and domain of the function in the graph?

Another way to identify domains and feature sets is with graphs. Domain refers to the set of possible input values, so a chart's domain consists of all input values ​​displayed on the x-axis.

                                    A range is the set of possible output values ​​plotted on the y-axis. To find the domain and domain of the equation y = f(x), find the value of the independent variable x for which the function is defined. 

y = f(x)

according to the graph value of y

 x ≤ 4,

-2≤ y ≤ 2

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Identify the correct equation of the graph.
-10
O f(b) = (6+4)² +8
O f(b) = (b+8)² +4
Of(b)=(6-8)²-4
O
-5
10
5
-5
-10
V
5
O f(b) = (b-8)² +4
Of(b) = (6-4)²-8
Of(b) (6-4)² +8
10
Check

Answers

Thus, the correct equation for the given parabolic graph is found as: f(b) = (b – 8)² + 4.

Explain about the quadratic function in vertex form:

A parabola has a lowest point if it opens upward. A parabola has a highest point if it opens downward.

The vertex of the parabola is located at this lowest or highest point.

Vertex form of a quadratic function:

f(x) = a(x – h)² + k, where a, h, and k are constants.

The vertex of the parabola is at because it is translated h horizontal units and k vertical units from the origin (h, k).

(h,k) are the vertex of parabola.

From the given graph:

f(b) is the given function:

Vertex (h,k) = (8, 4)

Thus, h= 8 and k = a = 1, x = b.

Put the values in quadratic function:

f(b) = 1(b – 8)² + 4

f(b) = (b – 8)² + 4

Thus, the correct equation for the given parabolic graph is found as: f(b) = (b – 8)² + 4.

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The angle measures for 2 supplementary angles are 3x and 2x +40.
What is the value of x?

Answers

Answer:

28°

Step-by-step explanation:

If the angles are supplementary, they add up to 180°.

(3x) + (2x + 40) = 180


5x + 40 = 180

     - 40   - 40

5x = 140

x = 28°

if the pink lines are parallel, solve for n

Answers

The option that is true about the equations for these two lines iis that they represent the same lines.

How to explain the information

The trick to questions like this is to get both equations into the slope-intercept form.  That is done for our first equation (y = 3x + 5).  However, for the second, some rearranging must be done:

5y – 25 = 15x; 5y = 15x + 25; y = 3x + 5

Note: Not only do these equations have the same slope (3), they are totally the same; therefore, they represent the same equation.

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Two lines are described by the equations:

y = 3x + 5 and 5y – 25 = 15x

Which of the following is true about the equations for these two lines?They represent perpendicular lines.

None of the other answers

They represent non-perpendicular, intersecting lines.

They represent the same lines.

They represent parallel lines.

Approximately of the Earth's surface is made up of the oceans. What fraction of the surface is not made up of oceans?​

Answers

The fraction of Earth that is not made up of ocean = 1/4.

Explain about the fraction:

The numbers we are familiar with are whole numbers, such as 1, 2, and so on.

Numbers expressed as fractions have a numerator and a denominator, separated by a line known as a vinculum.

In essence, a fraction explains how a portion of a group interacts with the entire group.

Given that-

fraction of Earth made up of water = 3/4

The fraction of Earth that is not made up of ocean = 1 - fraction of Earth made up of water

The fraction of Earth that is not made up of ocean = 1 - 3/4

The fraction of Earth that is not made up of ocean = (4 - 3)/4

The fraction of Earth that is not made up of ocean = 1/4

Thus, the fraction of Earth that is not made up of ocean = 1/4.

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Complete question:

Approximately 3/4 of the Earth's surface is made up of the oceans. What fraction of the surface is not made up of oceans?​

You have a jar of marbles, each marble is numbered 1-35. 10 Marbles are Blue, 12 Marbles are Green, and 13 Marbles are Red. You draw a random marble.What is the probability that you pull out a marble that is Green or an even number.

Answers

The probability of drawing a marble that is green or even-numbered is  28/35

Calculating the probability

The total number of marbles in the jar is 35, of which 10 are blue, 12 are green, and 13 are red.

We need to find the probability of drawing a marble that is green or an even number.

First, let's find the number of even-numbered marbles.

Out of 35 marbles, 17 of them are even-numbered (2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34).

There are 12 green marbles, and 17 even-numbered marbles,

Therefore, there are 12 + 17 - 1 = 28 marbles that are either green or even-numbered.

The probability of drawing a marble that is green or even-numbered is

28/35

So the probability of drawing a marble that is green or even-numbered is  28/35

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ZA =
Round your answer to the nearest hundredth.

Answers

Angle A equals 41.81°

c:

A coordinate plane with 2 lines drawn. The first line is labeled f(x) and passes through the points (0, negative 2) and (1, 1). The second line is labeled g(x) and passes through the points (negative 4, 0) and (0, 2). The lines intersect at about (2.5, 3.2)
How does the slope of g(x) compare to the slope of f(x)?

The slope of g(x) is the opposite of the slope of f(x).
The slope of g(x) is less than the slope of f(x).
The slope of g(x) is greater than the slope of f(x).
The slope of g(x) is equal to the slope of f(x)

Answers

Therefore, the correct answer is: The slope of g(x) is less than the slope of f(x).

Where do the X and Y axes intersect on the coordinate plane, at position 0 0?

The origin is the location where the two axes meet. On both the x- and y-axes, the origin is at 0. The coordinate plane is divided into four portions by the intersection of the x- and y-axes. The term "quadrant" refers to these four divisions.

We can use the slope formula to get the slopes of the lines f(x) and g(x):

slope of f(x) = (change in y)/(change in x) = (1 - (-2))/(1 - 0) = 3/1 = 3

slope of g(x) = (change in y)/(change in x) = (2 - 0)/(0 - (-4)) = 2/4 = 1/2

The slope of g(x) is 1/2, which is less than the slope of f(x), which is 3.

Therefore, the correct answer is: The slope of g(x) is less than the slope of f(x).

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Answer:

B

Step-by-step explanation:

Tentor, Inc., purchases disposable coffee cups on which to print logos for sporting events, proms, birthdays, and other special occasions. The owner received a large shipment of 861 cups this afternoon, and to ensure the quality of the shipment, he selected a random sample of 410 cups and identified 353 as defective.

What is the estimated proportion of defectives in the population? (Round the final answer to 3 decimal places.)

Answer

What is the standard error of the sample proportion? (Round your answer to 3 decimal places.)

Answer

What are the upper and lower bounds for a 98% confidence level? (Round the final answers to 3 decimal places.)

Upper bound is Answer

Lower bound is Answer

Answers

It is estimated that 0.861 percent of the population is faulty. The sample proportion's standard error is 0.022. A 98% confidence level has an upper bound of 0.910 and a lower bound of 0.812.

What is a proportion?

The comparative relationship between two or more things in terms of their size, amount, or number is referred to as a "proportion." Either a ratio or a fraction can be used to express it. The term "proportion" in statistics refers to the division of the total number of events by the frequency of each event.

The formula p = x/n, where p is the estimated proportion of defectives in the population, x is the number of defectives in the sample, and n is the sample size, can be used to determine the estimated proportion of defectives in the population.

When we substitute values, we obtain:

p = 353/410 = 0.861

As a result, the population's estimated defectiveness rate is 0.861.

The formula SE = √(p(1-p)/n), where SE is the standard error and n is the sample size, can be used to get the standard error of the sample percentage.

When we substitute values, we obtain:

SE is equal to√(0.861(1.0.861)/410) = 0.022.

As a result, the sample proportion's standard error is 0.022.

Using the following formula, the upper and lower bounds for a 98% confidence level can be determined:

Lower bound = z*SE - p

Upper bound = z*SE + p

where z is the z-score for a 98% degree of confidence.

We discover that the z-score corresponding to a 98% confidence level is roughly 2.33 using a z-table or calculator.

When we substitute values, we obtain:

Lower bound is equal to 0.861 - 2.33*0.022, or 0.812.

Upper bound is equal to 0.861 + 2.33 * 0.022 = 0.910.

Consequently, the range of a 98% confidence level is as follows:

Maximum: 0.910

Upper limit: 0.812

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It is estimated that 0.861 percent of the population is faulty. The sample proportion's standard error is 0.022. A 98% confidence level has an upper bound of 0.910 and a lower bound of 0.812.

What is a proportion?

The comparative relationship between two or more things in terms of their size, amount, or number is referred to as a "proportion." Either a ratio or a fraction can be used to express it. The term "proportion" in statistics refers to the division of the total number of events by the frequency of each event.

The formula p = x/n, where p is the estimated proportion of defectives in the population, x is the number of defectives in the sample, and n is the sample size, can be used to determine the estimated proportion of defectives in the population.

When we substitute values, we obtain:

p = 353/410 = 0.861

As a result, the population's estimated defectiveness rate is 0.861.

The formula SE = √(p(1-p)/n), where SE is the standard error and n is the sample size, can be used to get the standard error of the sample percentage.

When we substitute values, we obtain:

SE is equal to[tex]\sqrt{\frac{0.861(1.0.861)}{410)}[/tex]= 0.022.

As a result, the sample proportion's standard error is 0.022.

Using the following formula, the upper and lower bounds for a 98% confidence level can be determined:

Lower bound = z*SE - p

Upper bound = z*SE + p

where z is the z-score for a 98% degree of confidence.

We discover that the z-score corresponding to a 98% confidence level is roughly 2.33 using a z-table or calculator.

When we substitute values, we obtain:

Lower bound is equal to 0.861 - 2.33*0.022, or 0.812.

Upper bound is equal to 0.861 + 2.33 * 0.022 = 0.910.

Consequently, the range of a 98% confidence level is as follows:

Maximum: 0.910

Upper limit: 0.812

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A principal of $1500 is invested at 8.5% interest, compounded annually. How much will the investment be worth after 14 years?

Use the calculator provided and round your answer to the nearest dollar.

Answers

The investment would be worth approximately $4,498 after 14 years rounded to the nearest dollar

The number of potholes in any given 1 mile stretch of freeway pavement in Pennsylvania has a bell-shaped distribution. This distribution has a mean of 62 and a standard deviation of 11. Using the empirical rule (as presented in the book), what is the approximate percentage of 1-mile long roadways with potholes numbering between 51 and 84?

Answers

According to the empirical rule (also known as the 68-95-99.7 rule), for a bell-shaped distribution (or normal distribution), approximately:

- 68% of the data falls within one standard deviation of the mean
- 95% of the data falls within two standard deviations of the mean
- 99.7% of the data falls within three standard deviations of the mean

In this case, we can use the empirical rule to estimate the percentage of 1-mile long roadways with potholes numbering between 51 and 84.

To do this, we need to first calculate the z-scores for the values 51 and 84, using the formula:

z = (x - μ) / σ

where x is the value, μ is the mean, and σ is the standard deviation.

For x = 51:

z = (51 - 62) / 11 = -1

For x = 84:

z = (84 - 62) / 11 = 2

These z-scores tell us how many standard deviations away from the mean each value is. A z-score of -1 means that the value is 1 standard deviation below the mean, and a z-score of 2 means that the value is 2 standard deviations above the mean.

Now, we can use the empirical rule to estimate the percentage of 1-mile long roadways with potholes numbering between 51 and 84:

- The percentage of data within one standard deviation of the mean is approximately 68%. Since the mean is 62 and the standard deviation is 11, one standard deviation below the mean is 51, and one standard deviation above the mean is 73 (62 - 11 = 51, 62 + 11 = 73). Therefore, approximately 68% of the 1-mile long roadways have potholes numbering between 51 and 73.
- The percentage of data within two standard deviations of the mean is approximately 95%. Since two standard deviations below the mean is 40, and two standard deviations above the mean is 84 (62 - 2(11) = 40, 62 + 2(11) = 84), approximately 95% of the 1-mile long roadways have potholes numbering between 40 and 84.

Therefore, the approximate percentage of 1-mile long roadways with potholes numbering between 51 and 84 is approximately 95%.
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