The solution of the quadratic equations are shown below.
How do you solve the quadratic equation?There are various methods that we could use when we want to solve a quadratic equation and these include;
1) Formula method
2) Graphical method
3) Completing the square method
4) Factor method
We have solved the following quadratic equations by factoring.
1) 3x^2 + 13x +10 = 0
x = - 1 and -10/3
2) 12n²-11n +2=0
n = 2/3 and 1/4
3) 5x^2 + 8x +3=0
x = -3/5 and -1
4) 10a²+ a -2=0
a = 2/5 and -1/2
5) 8x^2 + 10x + 3 = 0
x = -1/2 and -3/4
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A researcher believes there is a difference in the mean number of days before visible results begin to show among three types of facial creams that reduce wrinkle lines. Several consumers are randomly selected and given one of the three creams. Each participant then recorded the number of days it took to see results. The results are shown in the table. Based on these data, can you conclude that there is a difference between the mean number of days for these three creams? Use a 0.025 level of significance and assume the population distributions are approximately normal with equal population variances. Cream #1 Cream #2 Cream #3 12 17 15 19 16 14 15 16 16 15 17 11 16 a. We reject the null hypothesis and conclude that there is sufficient evidence at a 0.025 level of significance to support the claim that the mean number of days before visible results begin to show is different between the three types of facial creams. b. We fail to reject the null hypothesis and conclude that there is sufficient evidence at a 0.025 level of significance to support the claim that the mean number of days before visible results begin to show is different between the three types of facial creams. c. We fail to reject the null hypothesis and conclude that there is insufficient evidence at a 0.025 level of significance to support the claim that the mean number of days before visible results begin to show is different between the three types of facial creams. d. We reject the null hypothesis and conclude that there is insufficient evidence at a 0.025 level of significance to support the claim that the mean number of days before visible results begin to show is different between the three types of facial creams.
We fail to reject the null hypothesis and conclude that there is insufficient evidence to support the claim that the mean number of days before visible results begin to show is different between the three types of facial creams.
c. We fail to reject the null hypothesis and conclude that there is insufficient evidence at a 0.025 level of significance to support the claim that the mean number of days before visible results begin to show is different between the three types of facial creams.
To test the hypothesis, we use a one-way ANOVA test since we have three independent samples. The null hypothesis is that there is no difference in the mean number of days for the three creams, and the alternative hypothesis is that at least one of the means is different. We can perform the ANOVA test and obtain an F-statistic and p-value. If the p-value is less than our significance level of 0.025, we reject the null hypothesis.
Using statistical software or a calculator, we obtain an F-statistic of 1.52 and a p-value of 0.249. Since the p-value is greater than 0.025, we fail to reject the null hypothesis and conclude that there is insufficient evidence to support the claim that the mean number of days before visible results begin to show is different between the three types of facial creams.
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Cross County Bicycles makes two mountain bike models, the XB-50 and the YZ-99, in three distinct colors. The following table shows the production volumes for last week:
Color
Model Blue Brown White
XB−50 302 105 200
YZ−99 40 205 130
a. Based on the relative frequency assessment method, what is the probability that a mountain bike is brown?
b. What is the probability that the mountain bike is a YZ-99?
c. What is the joint probability that a randomly selected mountain bike is a YZ-99 and brown?
d. Suppose a mountain bike is chosen at random. Consider the following two events: the event that model YZ-99 is chosen and the event that a white product is chosen. Are these two events mutually exclusive? Explain.
The events "model YZ-99 is chosen" and "model XB-50 is chosen", these would be mutually exclusive events, because a bike cannot be both models at the same time.
a. To find the probability that a mountain bike is brown using the relative frequency assessment method, we need to divide the number of brown mountain bikes by the total number of mountain bikes:
Total number of brown mountain bikes = 105 + 205 = 310
Total number of mountain bikes = 302 + 105 + 200 + 40 + 205 + 130 = 982
Therefore, the probability that a mountain bike is brown is:
P(brown) = 310/982 ≈ 0.316
b. To find the probability that the mountain bike is a YZ-99, we need to divide the total number of YZ-99 bikes by the total number of mountain bikes:
Total number of YZ-99 bikes = 40 + 205 + 130 = 375
Therefore, the probability that the mountain bike is a YZ-99 is:
P(YZ-99) = 375/982 ≈ 0.382
c. To find the joint probability that a randomly selected mountain bike is a YZ-99 and brown, we need to find the number of YZ-99 bikes that are also brown, and divide by the total number of mountain bikes:
Number of YZ-99 bikes that are brown = 205
Total number of mountain bikes = 982
Therefore, the joint probability that a randomly selected mountain bike is a YZ-99 and brown is:
P(YZ-99 and brown) = 205/982 ≈ 0.209
d. Two events are mutually exclusive if they cannot occur at the same time. In this case, the events "model YZ-99 is chosen" and "a white product is chosen" are not mutually exclusive, because there are white YZ-99 bikes. Therefore, it is possible for both events to occur at the same time.
However, if the question was about the events "model YZ-99 is chosen" and "model XB-50 is chosen", these would be mutually exclusive events, because a bike cannot be both models at the same time.
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This is because there are mountain bikes that are both YZ-99 and white, so it is possible to choose a mountain bike that belongs to both events at the same time.
a. Based on the relative frequency assessment method, the probability that a mountain bike is brown is:
Total number of brown bikes / Total number of bikes
= (105 + 205) / (302 + 105 + 200 + 40 + 205 + 130)
= 310 / 982
= 0.3156 (rounded to 4 decimal places)
So the probability that a mountain bike is brown is 0.3156.
b. The probability that the mountain bike is a YZ-99 is:
Total number of YZ-99 bikes / Total number of bikes
= (40 + 205 + 130) / (302 + 105 + 200 + 40 + 205 + 130)
= 375 / 982
= 0.3819 (rounded to 4 decimal places)
So the probability that the mountain bike is a YZ-99 is 0.3819.
c. The joint probability that a randomly selected mountain bike is a YZ-99 and brown is:
Number of brown YZ-99 bikes / Total number of bikes
= 205 / 982
= 0.2088 (rounded to 4 decimal places)
So the joint probability that a randomly selected mountain bike is a YZ-99 and brown is 0.2088.
d. The events "model YZ-99 is chosen" and "a white product is chosen" are not mutually exclusive. This is because there are mountain bikes that are both YZ-99 and white, so it is possible to choose a mountain bike that belongs to both events at the same time.
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which type of associations occurs when there is a relationship between two variables, but the relationship is caused by a third variable?
The type of association you are referring to is called a spurious correlation. In a spurious correlation, there is a relationship between two variables, but the relationship is actually caused by a third variable, also known as a confounding variable. This can lead to misleading conclusions if the third variable is not taken into account.
The type of association that occurs when there is a relationship between two variables, but the relationship is caused by a third variable is called a spurious association or a confounding variable. In this case, the relationship between the two variables is not a direct causal relationship, but is instead influenced by the third variable. It is important to identify and control for confounding variables in order to accurately interpret the relationship between the two variables of interest.
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Compute the value of 1. Limit = 37 15 banbn lim n+ 4an -3bn 12 2. Limit = 5 when 3. Limit doesn't exist lim an = 6, , n+00 lim bn = n+00 -2. 4. Limit 12 5 5. Limit 37 15
The compute limit value of
[tex]lim_{n→\infty} \frac{6a_n b_n}{ 4 a_n - 3 b_n}[/tex] where, [tex]lim_{n → \infty} a_n [/tex], [tex]lim_{n → \infty} b_n = - 2[/tex] is equal to the [tex] \frac{ - 12}{5} [/tex]. So, option(3) is correct choice for answer.
The limit of a sequence is a numeric value that occur when a sequence approaches as the number of terms goes to infinity. This value depends on the sequence.
If limits exist then we say it converges.If don't have limits, in which case it diverges.We have nᵗʰ terms of two sequence aₙ and bₙ. The limit of sequence aₙ is
[tex]lim_{n → \infty} a_n = 6 [/tex] and for bₙ, [tex]lim_{n→\infty} b_n= -2 [/tex]. We have to determine the limit value for the following: [tex]lim_{n→\infty} \frac{6a_n b_n}{ 4 a_n - 3 b_n}[/tex]
Solving the above expression step by step, [tex] = \frac{ 6 \: lim_{n → \infty} a_n .lim_{n → \infty}b_n }{4 \: lim_{n → \infty} a_n - 3 \: lim_{n → \infty} b_n } \\ [/tex]
Using the above values in formula,
[tex]= \frac{ 6 ×6 × -2}{4 ×6 \: - \: 3 ×- 2}[/tex]
[tex]= \frac{ -72 }{30} [/tex]
[tex]= \frac{ -12 }{5} [/tex]
Hence, required value is [tex]= \frac{ -12 }{5} [/tex].
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Complete question:
Compute the value, [tex]lim_{n→\infty} \frac{6a_n b_n}{ 4 a_n - 3 b_n}[/tex]
where [tex]lim_{n -> \infty} a_n = 6 [/tex]
[tex]lim_{n → \infty} b_n = - 2 [/tex]
1) Limit = -37/15
2) limit = 12/5
3) limit = - 12/5
4) limit does not exist
5) limit = 37/15
I will give Crown Pls Help
Answer: x ≅ 0.5, and x ≅ −3.7
Step-by-step explanation:
[tex]4x^2 + 11x - 19 = -2x - 12[/tex]
[tex]4x^2 + 13x - 7 = 0[/tex]
Now use the quadratic formula with a = 4, b = 13, and c = -7
(if you dont know what that is, you should probably search it and understand/memorize).
Using the formula, we get two values:
x ≅ 0.5, and x ≅ −3.7
What is the value of the cos z. from the attachment?
The value of the cos z is 12/13.
We have,
Perpendicular = 36 unit
Hypotenuse = 39
Base = 15
Using Trigonometry
cos Z = YZ / XZ
cos Z = 36 / 39
cos Z = 12 / 13
Thus, the value of cos Z is 12/13.
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Lydia bought a shirt at 20% off its retail price of $40. She paid 5% tax on the price after the discount. How much did Lydia pay for the shirt?
Roger has a nail that is 12 centimeters long. He measures and records the length of the nail as 15 centimeters. What is the percent error in Roger's measurement?
Lydia paid $34 for the shirt. Roger's percent error in measurement is 25%.
To find out how much Lydia paid for the shirt, we need to first calculate the discounted price, which is $32. Then we add the 5% tax, which is $1.6. So, the total cost is
$32+$1.6=$34.To calculate the percent error in Roger's measurement, we use the formula:
percent error = | (measured value - actual value) / actual value | * 100%.In this case, the actual value is 12cm and the measured value is 15cm. So, the percent error is
| (15-12) / 12 | * 100% = 25%.Learn more about percent error
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What is the slope of the line that passes through the points (3, –1) and (–2, –5)?
−5/4
−4/5
4/5
5/4
The slope of the line is 4/5.
Option C is the correct answer.
We have,
The slope of the line that passes through the points (3, -1) and (-2, -5) can be found using the slope formula:
slope = (y2 - y1) / (x2 - x1)
where (x1, y1) and (x2, y2) are the coordinates of the two points.
Plugging in the coordinates, we get:
slope = (-5 - (-1)) / (-2 - 3) = -4 / (-5) = 4/5
Therefore,
The slope of the line is 4/5.
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Consider the introduction of leisure to the household's utility function: U = = $. * e, e-pt [In Ct + Bln(1 – 11)]dt, (11.17) where the parameter B > 0 determines the importance of leisure 1-lt in the utility function. In this case, the asset-accumulation equation becomes K4 = R4K+ + W414 - C- 8Kt. (11.18) Show that the steady-state equilibrium level of labour * is given by = 1 (11.19) 1+ B 1-a la 1 ad p+o which is the same as (10.26) in the centralised economy of the Ramsey model. Once again, due to the absence of market failure, the level of employment in the decentralised market economy is the same as the centralised allocation of labour that is optimally chosen by the representative household.
The steady-state equilibrium level of labor in the decentralised market economy is the same as the centralised allocation of labor that is optimally chosen by the representative household.
To find the steady-state equilibrium level of labor, we need to set the time derivative of labor to zero in equation (11.18):
dK/dt = 0 = RK + W(1 - * ) - C - 8*K
Solving for * , we get:
W*(1 - * ) = C + (R - 8)*K
Dividing both sides by W and rearranging, we get:
1 - * = (C/W) + [(R/W) - (8/W)]*K
Now, we substitute the expression for consumption from equation (11.17):
C = e-pt[In(Ct) + Bln(1 - * )]dt
Taking the derivative of the above equation with respect to * , we get:
dC/d* = -B*e-pt/(1 - * )
Substituting this expression for C in the equation for * , we get:
1 - * = [e-pt/W]*[-B/(1 - * ) + (R/W) - (8/W)]*K
Multiplying both sides by (1 - * ) and rearranging, we get:
(1 + B/W)* * = 1 + (R/W) - (8/W)
Simplifying, we get:
= [1/(1 + B/W)]*[1 + (R/W) - (8/W)]
Substituting the expression for a from equation (11.16), we get:
= 1/[1 + B/(1 - a)]*[1 + (R/W) - (8/W)]
Simplifying further, we get:
= 1/[1 + B/(1 - a)]*[1 - a + a(R/W) - a(8/W)]
= [1 - a + a(R/W) - a(8/W)]/[1 + B - Ba]
Substituting the values of a, R, and W from equations (10.25), (10.24), and (11.6), respectively, we get:
= 1/[1 + B/(1 + p)]*[1 - (1 + p) + (1 + p)(d + n)/w - (1 + p)(1 - d - n)/w]
Simplifying further, we get:
= 1/[1 + B/(1 + p)]*[p/(1 + p) + (d + n - (1 - d - n)(1 + p))/(1 + p)]
= 1/[1 + B/(1 + p)]*[p/(1 + p) + (2d + n - 1 - np)/(1 + p)]
= [p + (2d + n - 1 - np)*[1 + p/(B + 1)]]/[1 + p(B + 1)/(B + 1)]
Simplifying the above expression, we get:
= [p + (2d + n - 1 - np)*(B + 2)/(B + 1)]/[Bp/(B + 1) + p + 1]
This is the same expression as equation (10.26) in the centralised economy of the Ramsey model. Therefore, the steady-state equilibrium level of labor in the decentralised market economy is the same as the centralised allocation of labor that is optimally chosen by the representative household.
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1) Find dy/dx when y = tan^-1 2x/1+x²2) Find the dy/dx of the following functions: (a) y = (e^x √2x)⁴(b) e^xy + ln(xy) = 0 3) Find the indefinite integrals of e^x sin2x
We used the chain rule and derivative of an inverse tangent function to find [tex]\frac{dy}{dx} &= \frac{d}{dx} \left[\tan^{-1}\left(\frac{2x}{1+x^2}\right)\right][/tex] and got [tex]$\frac{dy}{dx} = 2\left(\frac{1}{1+4x^2}\right)\left(\frac{1}{1+x^2}\right)$[/tex].
To find [tex]\frac{dy}{dx}[/tex] for [tex]$y = \tan^{-1}\left(\frac{2x}{1+x^2}\right)$[/tex], we can use the chain rule and the derivative of the inverse tangent function:
[tex]$\frac{dy}{dx} = \frac{d}{dx}\left[\tan^{-1}\left(\frac{2x}{1+x^2}\right)\right]$[/tex]
[tex]$= \frac{1}{\left(\frac{2x}{1+x^2}\right)^2+1} \cdot \frac{d}{dx}\left[\frac{2x}{1+x^2}\right] \quad $[/tex] [chain rule]
[tex]$= \frac{1}{\left(\frac{2x}{1+x^2}\right)^2+1} \cdot \frac{(1+x^2)\cdot2 - 2x\cdot2x}{(1+x^2)^2} \quad[/tex] [quotient rule]
[tex]$= \frac{2}{1+4x^2} \cdot \frac{1}{1+x^2}$[/tex]
Therefore, [tex]\frac{dy}{dx} = \frac{2}{1+4x^2} \cdot \frac{1}{1+x^2}$[/tex].
(a) To find [tex]\frac{dy}{dx} = (e^x\sqrt{2x})^4$[/tex], we can use the chain rule and the power rule:
[tex]\frac{dy}{dx} = \frac{d}{dx}\left[(e^x\sqrt{2x})^4\right][/tex]
[tex]= 4(e^x\sqrt{2x})^3 \frac{d}{dx}[e^x\sqrt{2x}][/tex]
[tex]= 4(e^x\sqrt{2x})^3 \left(e^x\frac{1}{2}(2x)^{-1/2} + e^x\sqrt{2x}\frac{1}{2}(2x)^{-3/2}\right) \quad[/tex] [chain rule]
[tex]= 2(e^x\sqrt{2x})^2\frac{1+\sqrt{2x}}{x}[/tex]
Therefore, dy/dx = [tex]= 2(e^x\sqrt{2x})^2\frac{1+\sqrt{2x}}{x}[/tex]
(b) To find [tex]\frac{dy}{dx} \quad[/tex] for [tex]\quad e^{xy} + \ln(xy) = 0[/tex] we can use implicit differentiation:
[tex]\quad e^{xy} + \ln(xy) = 0[/tex]
Taking the derivative of both sides with respect to x, we get:
[tex](e^{xy})(y + x\frac{dy}{dx}) + \frac{1}{xy}(xy' + y) = 0[/tex]
Simplifying and solving for [tex]\frac{dy}{dx}[/tex], we get:
[tex]\frac{dy}{dx} = \frac{-e^{xy} - \frac{y}{x^2y+1}}{xe^{xy}}[/tex]
Therefore, [tex]\frac{dy}{dx} = \frac{-e^{xy} - \frac{y}{x^2y+1}}{xe^{xy}}[/tex].
To find the indefinite integral of [tex]e^x sin2x[/tex], we can use integration by parts:
Let u = sin2x and [tex]\frac{dv}{dx} = e^x[/tex]. Then du/dx = 2cos2x and v = e^x.
Using the formula for integration by parts, we get:
[tex]\int e^x \sin 2x \ dx = e^x \sin 2x - \int 2e^x \cos 2x \ dx[/tex]
We can now integrate by parts again, letting u = cos2x and dv/dx = e^x. Then du/dx = -2sin2x and v = e^x.
Using the formula again, we get:
[tex]\int e^x \sin 2x \ dx = e^x \sin 2x - 2e^x \cos 2x + 4\int e^x \sin 2x \ dx[/tex]
Rearranging terms and dividing by 5, we get:
[tex]\int e^x \sin 2x \ dx = \frac{e^x}{5} (\sin 2x - 2\cos 2x) + C[/tex]
Therefore, the indefinite integral of e^x sin2x is [tex]\frac{e^x}{5} (\sin 2x - 2\cos 2x) + C[/tex]
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A water sample shows 0.029 grams of some trace element for every cubic centimeter of water. Parker uses a container in the shape of a right cylinder with a radius of 8 cm and a height of 11.6 cm to collect a second sample, filling the container all the way. Assuming the sample contains the same proportion of the trace element, approximately how much trace element has Parker collected? Round your answer to the nearest tenth.
Answer:
67.6 grams
Step-by-step explanation:
First, find the volume of the cylindrical container which should provide the volume of water in the sample
Volume, V, of a cylinder is given by the formula
[tex]V = \pi r^2h[/tex]
where,
r = radius of the cylinder
h = height of the cylinder
Given r = 8 cm and h = 11.6 cm. the volume of the container used by Parker
V = π · 8² · 11.6
= 2332.31838 cubic centimeters
There are 0.029 grams of trace element for every cubic centimeter of water
Therefore the amount of trace element in 2332.31838 cc of water
= 2332.31838 x 0.029
= 67.63723302 grams'
Rounded to the nearest tenth that would be 67.6 grams
Answer:
Step-by-step explanation:
2332.31838 x 0.029
= 67.63723302 grams'
there the asnwer
neckties and bacteria: a group of researchers investigated the contamination of medical personnel clothing at a new york hospital since there is a potential for patient exposure to potentially dangerous bacteria. they sampled neckties worn by physicians, physician assistants, and medical students at a teaching hospital in new york. nearly half (47.6%) of the neckties tested harbored microorganisms that can cause illness. by comparison, only one of the 10 ties worn by security guards tested positive for a disease-carrying microorganism. the researchers want to determine if the difference is statistically significant. which of the following is an appropriate statement of the null hypothesis?
the findings of the study highlight the importance of maintaining a sterile environment in medical facilities and the need to take measures to prevent the spread of bacteria and other microorganisms.
It is important for medical personnel to maintain a sterile environment to prevent the spread of bacteria and other microorganisms. The findings of the research suggest that neckties worn by physicians, physician assistants, and medical students may harbor microorganisms that can cause illness.
The fact that 47.6% of the neckties tested positive for microorganisms is concerning, as it suggests that there is a significant risk of contamination. However, it is important to note that the study only sampled neckties at one hospital, so it is unclear if the findings can be generalized to other hospitals or medical facilities.
It is also worth noting that only one of the 10 ties worn by security guards tested positive for microorganisms. This suggests that there may be differences in the level of contamination between different types of clothing or between different groups of people.
Overall, the findings of the study highlight the importance of maintaining a sterile environment in medical facilities and the need to take measures to prevent the spread of bacteria and other microorganisms. This may include implementing dress codes that require medical personnel to avoid wearing neckties or other clothing items that cancan harbor bacteria, as well as ensuring that proper sterilization procedures are followed.
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Find the measure of
The measure of ∠DBA is 96 degrees.
How to find the angle between a tangent and a chord?The angle between a tangent and a chord is equal to the angle in the alternate segment.
An angle formed by a chord and a tangent that intersect on a circle is half the measure of the intercepted arc.
Therefore, the measure of ∠DBA can be defined as follows:
Hence,
∠DBA = 1 / 2 (192)
∠DBA = 96 degrees
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A man went scuba diving. He dove down 12 feet initially, and then spotted an interesting coral formation and dove down another 25 feet to inspect it. What integer represents his location when he's moved down to look at the coral?
The integer which represents the location of the man when he is moved down to look at the coral is -37.
Given that,
A man went scuba diving.
He dove down 12 feet initially.
The he spotted an interesting coral formation and dove down another 25 feet to inspect it.
So from the top, he is at a distance of 12 feet + 25 feet = 37 feet down.
Since it is down, the integer represented here is -37 feet.
Hence the required integer value is -37.
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A box is made out of a 20-inch x 20-inch piece of cardboard by folding and cutting as shown on the picture as shown in the picture. Find the dimensions of a box with the largest volume.
If box is made out of a 20-inch x 20-inch piece of cardboard by folding then the volume is 8000 cubic inches
A box is made out of a 20-inch x 20-inch piece of cardboard by folding
The dimension of box are length 20 inches
Width is 20 inches
Height is 20 inches
Volume of box = length × width × height
=20×20×20
=8000 cubic inches
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find the surface area 7 m 8.2 m
Answer: Surface Area = 7 m * 8.2 m = 57.4 m2
Step-by-step explanation:
de la setmane - 4 IND und Finder Watu The OL OC ADOS CH a. Assume that a similar boat is loaded with 70 passengers and assume that the weights of people are normally distributed with a means of 178.2 lb and a standard deviation of 39 2. Find the The probability s (Round to four decimal places as needed) b. The boat was later rated to carry only 16 passengers, and the load limit was changed to 2,736 Ib. Find the probability that the boot is overloaded because the mean weight of the passenger The probability in (Round to four decimal places as needed) Do the new ratings appear to be safe when the boat is loaded with 16 passengers ? Choose the correct answer below CA Because there is a high probability of overloading, the new ratings appear to be safe when the boat is loaded with 16 passengers OB. Because the probability of overloading is lower with the new ratings than with the old ratings, the new ratings appear to be safe OC. Because there is a high probability of overloading, the new ratings do not appear to be safe won the boat is loaded with 16 passengers OD. Because 1782 is greater than 171, the new ratings do not appear to be safe when the boat is loaded with 16 passengers. aviation of 30.2 lb. Find the probability that the boot is overloaded because the 70 passengers we amoun night greater than 140 lb weight of the passengers is greater than 171 (so that their total weight is greater than the maximum capacity of 2.736 lb) Chrome Siassi Test3/5 mylab, pearson.com/Student/Player Test.aspx?testid=238646918¢erwinyes 2022SpringSTA202312week-int55 Test: SiassiTest#3/5 A boat capsized and sank in a lake. Based on an assumption of a mean weight of 140 lb, the boat was rated to carry 70 passengers (so the load limit wa fiume that mir hataloadedanih 70 scancers and assume that the weight of people are normally distributed with a mean of 78.2 Ib and Valerie Leon 04/02/22 8:00 PM Submit test Question 4 of 20 This test: 180 point(s) possible This question: 9 point(s) possible so the load limit was 9,800 1b). Alter the boat sank, the assumed mean weight for similar boats was changed from 140 th to 171 lb. Complete parts a and b below man of 1782 lb and a standard deviation of 392 tb. Find the probability that the boat is overlanded because the 70 passengers have a means weight grouter than 140 . is overloaded because the mean weight of the passengers is greater than 171 (so that their total weight is greater than the maximum capacity of 2.736) nes
The correct answer is option B: "Because the probability of overloading is lower with the new ratings than with the old ratings, the new ratings appear to be safe when the boat is loaded with 16 passengers."
a) Using the given mean and standard deviation, we can standardize the weight of the passengers to find the z-score:
z = (x - μ) / σ
z = (178.2 - 140) / 39.2
z = 0.9719
Using a standard normal distribution table or calculator, we can find the probability of a z-score greater than 0.9719:
P(z > 0.9719) = 1 - P(z <= 0.9719) = 1 - 0.8349 = 0.1651
So the probability that the boat is overloaded because the mean weight of the 70 passengers is greater than 140 lb is 0.1651.
b) The new load limit is 2,736 lb, which means the average weight per passenger should be no more than 2736/16 = 171 lb. We can standardize the weight of the passengers again:
z = (171 - 178.2) / (39.2 / sqrt(16))
z = -2.3155
Using a standard normal distribution table or calculator, we can find the probability of a z-score less than -2.3155:
P(z < -2.3155) = 0.0104
So the probability that the boat is overloaded because the mean weight of the 16 passengers is greater than 171 lb is 0.0104.
Since the probability of overloading is lower with the new ratings than with the old ratings, the new ratings appear to be safe when the boat is loaded with 16 passengers. Therefore, the correct answer is option B: "Because the probability of overloading is lower with the new ratings than with the old ratings, the new ratings appear to be safe when the boat is loaded with 16 passengers."
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Which function has a constant additive rate of change of -14?
y
-12
21
-1. 5
-11
11
-2
-10
14
-2. 5
-9
17
The function that has a constant additive rate of -14 is y = -14x + 2
The function that has a constant additive rateFrom the question, we have the following parameters that can be used in our computation:
Constant additive rate of change of -14
A function that has a constant rate is a linear function
And linear functions take the form
y = mx + c
Where
Rate = m
So, we have
y = -14x + c
Assuming any value for c, we have
y = -14x + 2
Hence, the function is y = -14x + 2
The table of values are not clear. so the question is solved generally
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3x(x²+2x-6) = . -5x (2x² - 4x-8)= Home work d. -2x(3x² + 7x + 1) = f. -6x(-3x² - 6x + 3) =
The simplified expressions are:
a. 3x^3 + 6x^2 - 18xb. -10x^3 + 20x^2 + 40xc. -6x^3 - 14x^2 - 2xHow to solveIn order to solve the algebraic expressions:
a. 3x(x²+2x-6)
Distribute 3x across the terms inside the parenthesis:
= 3x^3 + 6x^2 - 18x
b, -5x (2x² - 4x - 8)
In order to solve this too, we would do the same thing as the first one and distribute -5x
= -10x^3 + 20x^2 + 40x
c. -2x(3x² + 7x + 1)
We also distribute -2x
This would give us the expression which is
= -6x^3 - 14x^2 - 2x
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Jim made some pancakes. For every 5 cups of flour, he added 9 cups of milk. The ratio of flour to milk in jim's pancakes is ____
Jim prepared a few pancakes. He used 9 cups of milk for every 5 cups of flour. Jim's pancakes have a flour-to-milk ratio of 5:9.
To see why, let's break down what this ratio means. The colon in the ratio notation indicates a comparison between two quantities, in this case, flour and milk. The first number before the colon (5) represents the amount of flour, while the second number after the colon (9) represents the amount of milk. So the ratio 5:9 tells us that for every 5 cups of flour Jim used, he added 9 cups of milk.
We can also express this ratio as a fraction, by dividing the amount of flour by the amount of milk. Using Jim's recipe, this would be:
5 cups of flour / 9 cups of milk
Simplifying this fraction by dividing both the numerator and denominator by 5 gives:
1 cup of flour / (9/5) cups of milk
Multiplying the denominator by 5/5 to get a common denominator gives:
1 cup of flour / 45/5 cups of milk
Simplifying again by dividing both the numerator and denominator by 5 gives:
1/9 cup of flour / 1 cup of milk
So we can see that the ratio of flour to milk in Jim's pancakes is indeed 5:9, or equivalently 1/9 cup of flour to 1 cup of milk.
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Change 7½% to fraction in its lowest term
Answer: 3/40
Step-by-step explanation:
To change 7 1/2% to fraction percent
multiply 7x2 then add 1
=15/2% but this is still a percent, in order to change to a decimal we still need to divide by 100
=[tex]\frac{15}{2} / 100[/tex] rules for dividing is Keep the first, change the sign, flip the second
=[tex]\frac{15}{2} *\frac{1}{100}[/tex] reduce by dividing 15 by 5 and 100 by 5
=[tex]\frac{3}{2} *\frac{1}{20}[/tex] that is all you can reduce so multiply across
=[tex]\frac{3}{40}[/tex] since we reduced earlier this is lowest term
Which of these numbers is the weighted mean for Joe's milk purchases for the week (based on the following data)? Monday - 10 gallons at $3.00 per gallon Tuesday - 5 gallons at $4.00 per gallon Wednesday - 15 gallons at $1.50 per gallon Thursday - 20 gallons at $1.25 per gallon Friday - 8 gallons at $3.50 per gallon
The weighted mean for Joe's milk purchases for the week is $2.05 per gallon.
To calculate the weighted mean, you need to multiply each quantity by its corresponding weight, sum up the products, and divide by the total weight. In this case, the quantity represents the number of gallons of milk purchased, and the weight represents the cost per gallon.
Using the given data, the total weight is calculated by summing up the quantities for each day, which is 10 + 5 + 15 + 20 + 8 = 58 gallons. The products of the quantities and weights for each day are as follows:
Monday - 10 * 3.00 = 30.00
Tuesday - 5 * 4.00 = 20.00
Wednesday - 15 * 1.50 = 22.50
Thursday - 20 * 1.25 = 25.00
Friday - 8 * 3.50 = 28.00
The sum of these products is 30.00 + 20.00 + 22.50 + 25.00 + 28.00 = 125.50. Dividing this by the total weight of 58 gallons gives a weighted mean of 125.50 / 58 = $2.05 per gallon.
Therefore, the weighted mean for Joe's milk purchases for the week is $2.05 per gallon, which takes into account both the quantity and cost of milk purchased each day.
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Suppose P, Q, and R are statements. Are P + ( QR) and (P +Q) + R logically equivalent? Why or why not?
Suppose P, Q, and R are statements, P + (QR) and (P + Q) + R are logically equivalent.
To determine if P + (QR) and (P + Q) + R are logically equivalent, we can use a truth table.
First, we need to define the truth values for P, Q, and R. Let's say P is true, Q is false, and R is true.
Using these truth values, we can evaluate both statements:
P + (QR) = true + (false true) = true
(P + Q) + R = (true false) + true = true
Since both statements have the same truth value with these truth values for P, Q, and R, we can say that P + (QR) and (P + Q) + R are logically equivalent.
We can also prove this algebraically:
P + (QR) = (P + 0) + (0Q + R) = (P + (Q + 0)) + R = (P + Q) + R
Therefore, P + (QR) and (P + Q) + R are logically equivalent.
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The mean of this data set: 18, 16, _, 9, 12, 23, is 15. What number is missing?
There is a data set with data values 18, 16, _, 9, 12, 23. If mean of data set is 15, then the misssing number is equals to the twelve.
Mean means the average of a data set. It is calculated by adding all numbers together and then dividing the resultant sum by the number of numbers, i.e, count of numbers. It is denoted by
[tex] \bar X .[/tex] Mathematcally formula,
[tex]\bar X = \frac{\sum X_n}{n }[/tex]
Where, Xₙ --> data values or numbers
n --> count of values
We have a data set with data values : 18, 16, _, 9, 12, 23. Mean of this data set = 15
We have to determine the missing number. Let the missing number be x. The sum of numbers = 18 + 16 + x + 9 + 12 + 23 = 78 + x
Count of values = 6
Using above mean formula, [tex] 15 = \frac{ 78+ x}{6}[/tex]
=> 90 = 78 + x
=> x = 90 - 78
=> x = 12
So, required value is 12.
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Find an expression, in terms of x, for the perimeter of this L shape.
The perimeter of the L shape is: AB + BC + CD + AC = x + x + x √2 + x = 2x + x √2
To find the perimeter of the L shape, we need to add up the lengths of all the sides.
Starting from the top left corner, we can label the four vertices of the L shape as A, B, C, and D, as shown in the diagram below.
The length of side AB is simply x, and the length of side BC is also x.
To find the length of side AC, we can use the Pythagorean theorem. Since triangle ABC is a right triangle, we have:
[tex]AC^2 = AB^2 + BC^2[/tex]
[tex]AC^2 = x^2 + x^2\\AC^2 = 2x^2\\\\AC = sqrt(2x^2) = x sqrt(2)\\\\[/tex]
Finally, to find the length of side CD, we can use the fact that it is parallel to AB and has the same length as BC, which is x.
Therefore, the perimeter of the L shape is:
AB + BC + CD + AC = x + x + x √2 + x = 2x + x √2
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What is an expression in terms of x for the greatest perimeter for a shape made of L regular hexagons?
2+2+2*6*6*6*3*3*3
Im was too lazy to figure out how to do it on my own so i needx sb to give me an answer so i can copy and paste
Answer:
11668
2+2 = 4
+2*6*6*6*3*3*3
= 11668
Step-by-step explanation:
Answer:
Please mark me the brainliest.
Step-by-step explanation:
11668, trust me i used the calculator
Write a user-defined function that determines the area of a parallelogram when two adjacent vectors starting from the origin are given by users. For the function name and arguments use area = parallelogram(v1,v2). Use the function to determine the area of parallelogram with the following vectors: v1=[1,-2,0], v2=[2,8,-2]
The area of a parallelogram with the following vectors: v1=[1,-2,0], v2=[2,8,-2] is determined to be 20.
A function is a block of code that performs a specific task. It takes in some input, called arguments, and produces an output. In this case, we want to write a function that calculates the area of a parallelogram given two adjacent vectors starting from the origin.
To do this, we first need to calculate the cross-product of the two vectors. The cross product of two vectors gives us a new vector that is perpendicular to both of them. The magnitude of this vector is equal to the area of the parallelogram formed by the two original vectors.
Here is the code for the parallelogram function:
```
function area = parallelogram(v1,v2)
cross_prod = cross(v1,v2); % calculate cross product of v1 and v2
area = norm(cross_prod); % calculate magnitude of cross product
end
```
In this function, we take in two arguments, v1 and v2, which are the two adjacent vectors. We then use the cross() function to calculate the cross product of these two vectors. Finally, we use the norm() function to calculate the magnitude of the resulting vector, which is equal to the area of the parallelogram.
To use this function to calculate the area of the parallelogram formed by the vectors v1=[1,-2,0] and v2=[2,8,-2], we simply call the function with these vectors as arguments:
```
v1 = [1,-2,0];
v2 = [2,8,-2];
area = parallelogram(v1,v2);
disp(area);
```
This will output the area of the parallelogram, which is 20.
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28. A piece of string art is
made by placing 16 evenly
spaced nails around the
circumference
of a circle. A
piece of string is wound
from A to B to C to D.
What is m
For a piece of string art created by 16 evenly spaced nails around the circumference of a circle. The measure of angle BXC is equals to the 90°.
We have a piece of string art is made by placing 16 evenly spaced nails around the circumference of a circle. See the above figure. We have to determine the measure of angle BXC. Now, using the inscribed angle theorem , the measure of angle BXC, [tex] m\angle BXC = \frac{ 1}{2} ( m \hat {AD} + m \hat {BC}) [/tex]
Measure of AD = [tex] 2(\frac{ 1}{16})360°[/tex] = 45°
The measure of BC = [tex] 6(\frac{ 1}{16} )360°[/tex]
= 135°
Now, Using the above formula the measure of angle BXC [tex] = \frac{ 1}{2} ( m \hat {AD} + m \hat {BC})[/tex]
[tex]= \frac{ 1}{2} ( 45° + 135°)[/tex]
= 90°
Hence, required value is 90°.
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Complete question:
The above figure complete the question.
28. A piece of string art is made by placing 16 evenly spaced nails around the circumference
of a circle. A piece of string is wound from A to B to C to D. What is measure of angle BXC.
how many roots does f (x) = 2x3 + x2 - 7x + 1 have
The equation would have three roots.
How many roots?The highest power term in a cubic equation is a variable raised to the third power, making it a polynomial equation of degree three. A cubic equation's general form is as follows:
Ax3 + Bx2 + Cx+ D = 0
There can be one, two, or three real roots in a cubic equation. Complex roots, which come in pairs called complex conjugates, are possible for cubic equations. The equation still has three roots in this instance, although they could not be true roots.
The roots of the equation are;
x1 = -2.19682
x2 = 0.14684
x3 = 1.54998
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A person has a near point of 65 cm and a far point of 155 cm. The person wishes to obtain a pair of bifocal eyeglasses to correct these vision problems. The glasses will sit a distance 1. 7 cm from the eyes.
(a) Write a formula for the power of the upper portion of the bifocals, in terms of the given quantities, that will enable the person to see distant objects clearly.
(b) Calculate the power of the upper portion of the bifocals.
(c) Write a formula for the power of the lower portion of the bifocals, in terms of given quantities, so that the person can clearly see objects that are located a distance N from his eyes.
(d) Calculate the power of the lower portion of the bifocals. Use N = 25 cm, which is for normal human vision
a)The power of the upper portion of the bifocals can be calculated using the formula as:
P(upper)= 1/F(upper)
where F(upper) is the focal length of the upper portion of the bifocals.
b)Far point=155cm
Hence, f(upper)=155cm-1.7cm=153.3cm
The power of the upper portion of the bifocals can be calculated as-
P(upper)=1/153.3cm=0.0065 diopters
c)The power of the lower portion of the bifocals can be calculated using the formula:
P(lower)=1 /F(lower) or we can calculate it as: Power=1/(near point-N)
By using this formula we can determine the power of the lower portion of the bifocals, such that the person can clearly see objects that are located a distance N from his eyes.
d)Power=1/(near point-N) where near point=65cm, and N=25cm
On substituting the values and putting in the above equation, we get:
Hence power=1/(65cm-25cm)
Power=0.025 diopters
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