Given:
In triangle [tex]BGU,BG=x,GU=7,BU=y,m\angle U=90^\circ,m\angle B=44^\circ[/tex].
To find:
The value of y.
Solution:
In a right angle triangle,
[tex]\tan \theta=\dfrac{Perpendicular}{Base}[/tex]
In triangle BGU,
[tex]\tan B=\dfrac{GU}{BU}[/tex]
[tex]\tan 44^\circ=\dfrac{7}{y}[/tex]
[tex]0.966=\dfrac{7}{y}[/tex]
Isolating y, we get
[tex]y=\dfrac{7}{0.966}[/tex]
[tex]y=7.2463[/tex]
[tex]y\approx 7.2[/tex]
Therefore, the correct option is A.
Which equation represents exponential decay?
a) y=0.5x3
b) y=0.5x2 - x
c) y=0.5(1.07) dy=0.5(0.87)*
-7x + y = -2 in slope-intercept form. what is the y-intercept and slope?
add -7x to the other side so the equation is
y=7x-2
slope is 7
y-int is -2
A rocket is launched from a tower. The height of the rocket, y in feet, is
related to the time after launch, x in seconds, by the given equation.
Using this equation, find out the time at which the rocket will reach its
max, to the nearest 100th of a second.
y = 16x^2+ 238x + 81
Answer: 7.44
Step-by-step explanation: DeltaMath
What is the value of x in the equation −8 + x = −2?
Can someone please help me with math.
a. The sum of two numbers is 22 and their difference is 14.
i. Form the simultaneous equations.
ii. Find the two numbers.
What is the value of x in the diagram?
an amusement park is open for 15 hours a day 7 days a week
Their admission prices are listed below
3 hours or less: $15
Between 3 hours and 7 hours: $22
7 or more hours:$30
Identify their domains and functions for this context.
Answer:
f(x)=15 when: 0<x(less than or equal to)3
f(x)=22 when: 3<x<7
f(x)=30 when: 7(is less than or equal to)x
Part B- Evaluate the function for f(2): 15
Step-by-step explanation:
Algebra Nation; Section 8 topic 6
The domain of each function is the set of all possible values of t for which the function is defined. In this case, the domain of each function is:
For f(t) = 15: 0 < t ≤ 3
For f(t) = 22: 3 < t ≤ 7
For f(t) = 30: t > 7
How to calculate the domain?The admission prices at the amusement park can be represented as functions of the amount of time a customer spends at the park. Let's denote the amount of time by t (in hours). Then we can define the following functions:
For t ≤ 3: f(t) = 15
For 3 < t ≤ 7: f(t) = 22
For t > 7: f(t) = 30
The domain of each function is the set of all possible values of t for which the function is defined. In this case, the domain of each function is:
For f(t) = 15: 0 < t ≤ 3
For f(t) = 22: 3 < t ≤ 7
For f(t) = 30: t > 7
Note that the domain for each function reflects the fact that customers can only be charged according to the specified rates for the corresponding time intervals.
Additionally, since the amusement park is open for 15 hours a day, 7 days a week, we can say that the total operating time is 15 x 7 = 105 hours per week.
To know more about the domain follow
https://brainly.com/question/26098895
#SPJ3
Without using a protractor, you can determine whether the angles are right angles by measuring the length of the diagonal and applying the converse of the Pythagorean Theorem.
help please ! I dont understand this question
Answer:
x = 4
Step-by-step explanation:
all angles in triangle add to 180
90+70=160
180-160=20
20÷5=4
Is 2.36 a rational number?
Answer:
Yes
Step-by-step explanation:
Since it is a terminating (it ends) decimal and could be written as a fraction
Find P(A') given that P(A) = 0.75
Answer:
I'm not sure what you're asking if P (A) = 0.75 P(A) is equal to 0.75
please help HEYMLMUM
Answer:
A.
Step-by-step explanation:
I need help please! DON'T USE LINKS! WILL BE REPORTED
9514 1404 393
Answer:
222 cm²
Step-by-step explanation:
The surface area can be found using the formula ...
A = 2(LW +H(L+W))
To minimize fraction nonsense, we'll let H be the fraction.
A = 2(12·8 +(3/4)(12 +8)) = 2(96 +15) = 222
The surface area of the prism is 222 square centimeters.
Which expression represents the difference of (6x - 5) - (-x - 4)?
(6x-5)-(-x-4)
6x-5=x+4
6x-x=4+5
5x=9
Ronald is growing 1/3 inch each year. How many years will it take for him to grow 5 inches?
How do you find 3/4 of 20
Fast response please!!
Answer:
15
Step-by-step explanation:
3/4(20/1) = (3*20)/(4*1)
60/4
15
2. A bottle of water contains 40 fluid ounces of water. How many pints of water does the bottle
contain?
F. 2 pints
G. 3 pints
H. 1.75 pints
J. 2.5 pints
PLES HALP POINTS PIC DOWN BELOW
Answer:
The answer is D
Step-by-step explanation:
Answer:
D) Quadrant IV (quadrant 4)
Step-by-step explanation:
Point C is in quadrant IV because its point is (4,-4)
For points that have a positive x-coordinate and a negative y-coordinate, that means they are in quadrant IV.
Another way to figure this out is by looking at this graphically:
y
|
Quadrant | Quadrant
II | I
|
------------------------------|----------------------------- x
|
Quadrant | Quadrant
III | IV
|
I hope this helps!
please help i’m kinda stressed right now.
Answer:
17) G
18) J
19) F
20) A
hope this helps :)
PLEASE HELP! NO LINKS OR I WILL REPORT!! I SUCK AT ALGEBRA
Answer:
-5 and 3
Step-by-step explanation:
(-(-2) +/- √(4- (4(1)(-15))) ÷ 2
(2 +/- √64 )÷ 2
(-2+8) ÷ 2 = 3
(-2 -8) ÷ 2 = -5
a1 = -7 a18 = 3393 find d
Answer:
d = 200
Step by Step Explanation:
The table below shows the transportation method of all of the employees who work at the mall. What percent of employees walk to work?
Car: 758
Bus: 530
Walk: 7
Other: 105
Answer:
0.005 or 0.5% walk
Step-by-step explanation:
Total:
758 + 530 + 7 + 105 = 1400
To find how many employees walk:
7/1400 = 0.005
At a school, 133 students play at least one sport. This is 35 % of the students at the school. How many students are at the school?
Answer:
380 students
Step-by-step explanation:
133 = 35%
[tex]\frac{133}{35}[/tex] = 1%
3.8 = 1%
3.8 * 100
= 380
The time required to drive a fixed distance varies inversely as the speed. It takes 40 hr at a speed of 10 km/h to drive a fixed distance. How long will it take to drive the same distance at a speed of 8 km/h?
Answer:
50 hours
Step-by-step explanation:
Given data
Time=40hr
Speed=10km/hr
Let us find the fixed distance first
Speed= distance/Time
10= distance/40
distance= 10*40
distance= 400miles
Now our speed= 8km/h
hence the time is
8= 400/time
time= 400/8
time=50 hours
Hence the time is 50 hours
a recipe uses 10 cups of flour. you can only measure using 2/3 cups.
How many 2/3 cups are needed for the recipe?
Ok so I am not exactly sure if you want to know how many whole cups can be added or simply how many 2/3 cups make up 10, but heres what I found.
So to find how many 2/3 is in 10 cups you simply have to divide
10/(2/3) = 15
So 10 cups of flour is 15 (2/3) cups of flour.
Hope this helps :)
Regular hexagon ABCDEF is inscribed in circle X and has an apothem that is 6√3 inches long. Use the length of the apothem to calculate the exact length of the radius and the perimeter of regular hexagon ABCDEF. In your final answer, include your calculations.
Answer:
Part A
[tex]The \ circumradius, \ R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}[/tex]
Plugging in the given values we get;
[tex]The \ circumradius, \ R = \dfrac{6 \cdot \sqrt{3} }{cos \left(\dfrac{\pi}{6} \right)} = \dfrac{6 \cdot \sqrt{3} }{\left(\dfrac{\sqrt{3} }{2} \right)} = 6 \cdot \sqrt{3} \times \dfrac{2}{\sqrt{3} } = 12[/tex]
R = 12 inches
The radius of the circumscribing circle is 12 inches
Part B
The length of each side of the hexagon, 's', is;
[tex]s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)[/tex]
Therefore;
[tex]s = 6 \cdot \sqrt{3} \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3} \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12[/tex]
s = 12 inches
The perimeter, P = n × s = 6 × 12 = 72 inches
The perimeter of the hexagon is 72 inches
Step-by-step explanation:
The given parameters of the regular hexagon are;
The length of the apothem of the regular hexagon, a = 6·√3 inches
The relationship between the apothem, 'a', and the circumradius, 'R', is given as follows;
[tex]a = R \cdot cos \left(\dfrac{\pi}{n} \right)[/tex]
Where;
n = The number of sides of the regular polygon = 6 for a hexagon
'a = 6·√3 inches', and 'R' are the apothem and the circumradius respectively;
Part A
Therefore, we have;
[tex]The \ circumradius, \ R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}[/tex]
Plugging in the values gives;
[tex]The \ circumradius, \ R = \dfrac{6 \cdot \sqrt{3} }{cos \left(\dfrac{\pi}{6} \right)} = \dfrac{6 \cdot \sqrt{3} }{\left(\dfrac{\sqrt{3} }{2} \right)} = 6 \cdot \sqrt{3} \times \dfrac{2}{\sqrt{3} } = 12[/tex]
The circumradius, R = 12 inches
Part B
The length of each side of the hexagon, 's', is given as follows;
[tex]s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)[/tex]
Therefore, we get;
[tex]s = 6 \cdot \sqrt{3} \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3} \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12[/tex]
The length of each side of the hexagon, s = 12 inches
The perimeter of the hexagon, P = n × s = 6 × 12 = 72 inches
The perimeter of the hexagon = 72 inches
Answer: radius = 12, perimeter = 72
Step-by-step explanation:
We know that in 30-60-90 right triangles, the hypotenuse is exactly twice the length of the short leg and the long leg is the short leg times √3.
so therefore, if the long leg (apothem) is equal to 6√3, the short leg is equal to 6
long leg = 6√3
long leg = short leg √3
short leg = 6
hypotenuse (radius) = 2(short leg)
hypotenuse (radius) = 2(6)
hypotenuse (radius) = 12
The radius of hexagon ABCDEF = 12 inches
Perimeter = r (sides)
Perimeter = r (6)
Perimeter = 12 (6)
Perimeter = 72
The perimeter of hexagon ABCDEF = 72 inches
Which function g(x) or f(x) has the equation y=x^2-4
Answer:
f x
Step-by-step explanation:
the equqtion's y intercept is -4 , and f (x) has that intercept
Answer:
f(x)
Step-by-step explanation:
The equation says -4 meaning that it moved down 4 spaces on the y-axis.
can someone help i dont know any of these formulas
s.a=C.A xH
v of n.o.2 =lxwxh
Step-by-step explanation:
v of no.3=πr2h and s.a=πdh
no.1=area of cross section x area of all faces and v=area of cross section x length
try those ones
The radius of a circle is 7 miles. What is the circle's area?
Use 3.14 for .
Answer:
A≈153.94mi²
Step-by-step explanation:
A = πr2 = π · 72 ≈ 153.93804mi²