Answers
Answer:
x=√2, x=-√2, x= 3 and x=-3
Step-by-step explanation:
We need to solve the equation x^4 - 11x^2+18=0
We can replace x^4 = u^2 and x^2 = u
So, the equation will become
u^2 -11u+18 = 0
Factorizing the above equation:
u^2 -9u-2u+18 =0
u(u-9)-2(u-9)=0
(u-2)(u-9)=0
u=2, u=9
As, u = x^2, Putting back the value:
x^2 =2 , x^2 =9
taking square roots:
√x^2 =√2 ,√x^2=√9
x=±√2 , x = ±3
so, x=√2, x=-√2, x= 3 and x=-3
Answer:
The second answer is correct.
Step-by-step explanation:
Mark brainliest if correct please
Related Questions
X^9/7 convert from exponent form to radical form
Answers
Answer:
[tex]x^{\frac{9}{7}} = \sqrt[7]{x^9}[/tex]
Step-by-step explanation:
You can solve this by realising that the denominator of a fractional exponent can be expressed as the base of a radical.
Note also that the order does not matter. You could also express it as
[tex]\sqrt[7]{x}^9[/tex]
The reason this works is that you're effectively breaking the exponent into fractions. The first answer is the equivalent of:
[tex](x^9)^{1/7}[/tex]
and the second would be:
[tex](x^{1/7})^9[/tex]
In both cases, the exponents would be multiplied, giving the same result.
Luis solves the following system of equations by elimination.
5s+ 3t = 30
2s+3t=-3
What is the value of s in the solution of the system?
Answers
Asphere has a radius of 27 inches. A horizontal plane passes through the center of the sphere.
Part 1 out od 2
Describe the cross section formed by the plane and the sphere.
Answers
9514 1404 393
Answer:
circle of radius 27 inches
Step-by-step explanation:
Anywhere a plane cuts a sphere, the cross section is a circle. When the plane includes the center of the sphere, the circle has the same radius the sphere has.
The cross section is a circle of radius 27 inches.