Answer:
The square root of one million is 1000 because 1000 x 1000 = 1,000,000
Identify the type of hypothesis test below. H0:X=10.2, Ha:X>10.2 Select the correct answer below: The hypothesis test is two-tailed. The hypothesis test is left-tailed. The hypothesis test is right-tailed.
Answer:
The hypothesis test is right-tailed
Step-by-step explanation:
To identify a one tailed test, the claim in the case study tests for the either of the two options of greater or less than the mean value in the null hypothesis.
While for a two tailed test, the claim always test for both options: greater and less than the mean value.
Thus given this: H0:X=10.2, Ha:X>10.2, there is only the option of > in the alternative claim thus it is a one tailed hypothesis test and right tailed.
A test with the greater than option is right tailed while that with the less than option is left tailed.
Answer:
Please help with questions on my profile somebody
Step-by-step explanation:
g Suppose that three hypothesis tests are carried out, each using significance level 0.05. What is the worst-case probability of a type I error in at least one of these tests?
Answer:
The worst-case probability is 0.05
Step-by-step explanation:
The given significance level ([tex]\alpha[/tex]) = 0.05
since Probability of a type I error is [tex]\alpha[/tex]
∴ P (type I error) = 0.05
0.05 will be the worst-case probability of a type I error in at least one of the tests.
Find the area of the triangle. Round the answer to the nearest tenth. A. 4.4 square units B. 5.2 square units C. 6.8 square units D. 8.8 square units
Answer:
A. 4.4 units²
Step-by-step explanation:
Area of a Triangle: A = 1/2bh
sin∅ = opposite/hypotenuse
cos∅ = adjacent/hypotenuse
Step 1: Draw the altitude down the center of the triangle
- We should get a perpendicular bisector that creates 90° ∠ and JM = KM
- We should also see that we use sin∅ to find the h height of the triangle and that we use cos∅ to find length of JM to find b base of the triangle
Step 2: Find h
sin70° = h/3.7
3.7sin70° = h
h = 3.47686
Step 3: Find b
cos70° = JM/3.7
3.7cos70° = JM
JM = 1.26547
Step 4: Find entire length base JK
JM + KM = JK
JM = KM (Definition of Perpendicular bisector)
2(JM) = JK
2(1.26547) = 2.53095
b = 2.53095
Step 5: Find area
A = 1/2(3.47686)(2.53095)
A = 4.39988
A ≈ 4.4
During the summer months Terry makes and sells necklaces on the beach. Last summer he sold the necklaces for $10 each and his sales averaged 20 per day. When he increased the price by $1, he found that the average decreased by two sales per day. If the material for each necklace costs Terry $6, what should the selling price be to maximize his profit?
Answer:
The selling price in other to maximize his profit is $13
Step-by-step explanation:
In the above question we are given the following information:
Cost of material per necklace = $6
Firstly, terry sold 20 necklaces per day
= $10 each
Later he increased he increased the prices by 1 dollar and the number of necklaces he sold reduced by 2
Mathematically
18 necklaces = $11 each
Step 1
We find the Cost function C(x)
Let's assume that x = number of necklaces sold
If each material cost $6 , then
C(x) = 6 × x = 6x
Step 2
P(Profit) = R(x) - C(x)
R(x) = Revenue
Where Revenue = x × p(x)
Since p(20) = 10 and p(18) = 11
p(x) = -1/2x + 20
P(Profit) = x ( -1/2x + 20) - C(x)
C(x) = 6x
P = x(-1/2x + 20) - 6x
P = -1/2x² + 20x - 6x
P = -1/2x² + 14x
Step 3
We maximise the profit by differentiating P
P = Profit
P = -1/2x² + 14x
We differentiate P to find x
∆P/∆x = dp/dx = -x + 14
-x + 14 = 0
-x = -14
x = 14
Hence, we substitute 14 for x in the price function
p(x) = - 1/2x + 20
since , x = 14
p(14) = - 1/2 × 14 + 20
= -7 + 20
= $13
Therefore, the selling price function to maximize his profit is $13
Above question the given data:
Cost of material per necklace = $6 Terry sold 20 necklaces per day = $10 each Price increase by 1 dollar Number of necklaces sold reduced by 2
1.Cost function C(x)
Let's assume that x = number of necklaces sold
If each material cost $6 , then
C(x) = 6 × x
C(x) = 6x
2.P(Profit) = R(x) - C(x)
R(x) = Revenue ,Where Revenue = x × p(x)
Given data:
p(20) = 10
p(18) = 11
p(x) = -1/2x + 20
P(Profit) = R(x) - C(x)
P(Profit) = x ( -1/2x + 20) - C(x)
P = x(-1/2x + 20) - 6x
P = -1/2x² + 20x - 6x
P = -1/2x² + 14x
3.Maximise Profit
P = Profit
P = -1/2x² + 14x
We differentiate P to find x
∆P/∆x = dp/dx = -x + 14
-x + 14 = 0
-x = -14
x = 14
Now, we will substitute 14 for x in the price function
Now ,p(x) = - 1/2x + 20
since , x = 14
p(14) = - 1/2 × 14 + 20
p(14)= -7 + 20
p(14)= $13
Thus, the selling price function to maximize his profit is $13.
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Which represents the solution of the graphed system of equations, y=x^2-2x and y=-2x-1
Answer:
x = √(-1) = i
Since the value of √(-1) is not real.
The system has no real solution.
Step-by-step explanation:
The solution to the system of equations is at the point where they intercept each other.
y1 = y2
For the given equation;
y=x^2-2x and y=-2x-1
To get the where they intercept, we will equal both equations;
y=x^2-2x = -2x-1
x^2 - 2x = -2x - 1
x^2 - 2x + 2x + 1 =0
x^2 +1 = 0
x^2 = -1
x = √(-1) = i
Since the value of √(-1) is not real.
The system has no real solution.
A research study investigated differences between male and female students. Based on the study results, we can assume the population mean and standard deviation for the GPA of male students are µ = 3.5 and σ = 0.05. Suppose a random sample of 100 male students is selected and the GPA for each student is calculated. What is the probability that the random sample of 100 male students has a mean GPA greater than 3.42?
Answer: 0.0548
Step-by-step explanation:
Given, A research study investigated differences between male and female students. Based on the study results, we can assume the population mean and standard deviation for the GPA of male students are µ = 3.5 and σ = 0.05.
Let [tex]\overline{X}[/tex] represents the sample mean GPA for each student.
Then, the probability that the random sample of 100 male students has a mean GPA greater than 3.42:
[tex]P(\overline{X}>3.42)=P(\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}>\dfrac{3.42-3.5}{\dfrac{0.5}{\sqrt{100}}})\\\\=P(Z>\dfrac{-0.08}{\dfrac{0.5}{10}})\ \ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=P(Z>1.6)\\\\=1-P(Z<1.6)\\\\=1-0.9452=0.0548[/tex]
hence, the required probability is 0.0548.
These are the weekly wages paid to staff in a hotel. £245 £140 £525 £163 £195 £174 £140 What is the range of these wages? £ What is the mean wage?
Answer:
Range of wages is £140 to £525.
Mean wage = £226
Step-by-step explanation:
Given:
Weekly wages paid to the staff are :
£245, £140, £525, £163, £195, £174 and £140.
To find:
Range of these wages = ?
Mean wage = ?
Solution:
First of all, let us learn about the range of wages and mean wage.
Range of wages has a minimum pay and a maximum pay.
Here, if we have a look £140 is the minimum pay and
£525 is the maximum pay.
So, range of wages is £140 to £525.
Mean wage means the average of all the wages given to the staff.
Mean is defined as the formula:
[tex]\text{Average/Mean =} \dfrac{\text{Sum of all the observations}}{\text{Number of observations}}[/tex]
Here, Sum of all observations mean sum of the wages of all the staff members.
Number of observations mean the number of staff members i.e. 7 here.
Applying the formula:
[tex]\text{Average/Mean =} \dfrac{\text{245+140+525+163+195+174+140}}{\text{7}} \\\Rightarrow \text{Average/Mean =} \dfrac{\text{1582}}{\text{7}}\\\Rightarrow \text{Average/Mean =} 226[/tex]
So, the answer is:
Range of wages is £140 to £525.
Mean wage = £226
The image of a parabolic lens is traced onto a graph. The function f(x) = (x + 8)(x – 4) represents the image. At which points does the image cross the x-axis?
Answer:
x = -8 and x = 4
Step-by-step explanation:
given
f(x) = (x+8) (x - 4)
recall that at any point on the x-axis, y = 0 [i.e f(x) = 0]
hence to find where the graph crosses the x-axis, we simply substitue f(x) = 0 into the equation and solve for x
f(x) = (x+8) (x - 4)
0 = (x+8) (x - 4)
Hence
either,
(x+8) = 0 ----> x = -8 (first crossing point)
or
(x-4) = 0 ------> x = 4 (second crossing point)
Hence the graph crosses the x-axis at x = -8 and x = 4
Answer:
A (-8, 0) and (4, 0)
Mary wants to make brownies to make brownies she needs 7/12 of a cup of flour per batch of brownies if Mary has 7 cups of flour then how many batches of brownies can mary make?
━━━━━━━☆☆━━━━━━━
▹ Answer
12
▹ Step-by-Step Explanation
[tex]7/\frac{7}{12} \\\\= 7 * \frac{12}{7} \\\\= \frac{84}{7} \\\\= 12[/tex]
Hope this helps!
CloutAnswers ❁
Brainliest is greatly appreciated!
━━━━━━━☆☆━━━━━━━
Explain how to use the vertex and the value of “A” to determine the range of an absolute value function. PLEASE HELP!!
Answer:
First, a absolute value function is something like:
y = f(x) = IxI
remember how this work:
if x ≥ 0, IxI = x
if x ≤ 0, IxI = -x
Notice that I0I = 0.
And the range of this function is all the possible values of y.
For example for the parent function IxI, the range will be all the positive reals and the zero.
First, if A is the value of the vertex of the absolute function, then we know that A is the maximum or the minimum value of the function.
Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:
y ≥ A
Or all the real values equal to or larger than A.
if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:
y ≤ A
Or "All the real values equal to or smaller than A"
A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed of the film and believes that this can be achieved by reducing the thickness of the film to 20 mils. Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured. For the 25-mil film, the sample data result is: Mean Standard deviation 1.15 0.11 For the 20-mil film the data yield: Mean Standard deviation 1.06 0.09 *Note: An increase in film speed would lower the value of the observation in microjoules per square inch. We may also assume the speeds of the film follow a normal distribution. Use this information to construct a 98% interval estimate for the difference in mean speed of the films. Does decreasing the thickness of the film increase the speed of the film?
Answer:
A 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].
Step-by-step explanation:
We are given that Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured.
For the 25-mil film, the sample data result is: Mean Standard deviation 1.15 0.11 and For the 20-mil film the data yield: Mean Standard deviation 1.06 0.09.
Firstly, the pivotal quantity for finding the confidence interval for the difference in population mean is given by;
P.Q. = [tex]\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] ~ [tex]t__n_1_+_n_2_-_2[/tex]
where, [tex]\bar X_1[/tex] = sample mean speed for the 25-mil film = 1.15
[tex]\bar X_1[/tex] = sample mean speed for the 20-mil film = 1.06
[tex]s_1[/tex] = sample standard deviation for the 25-mil film = 0.11
[tex]s_2[/tex] = sample standard deviation for the 20-mil film = 0.09
[tex]n_1[/tex] = sample of 25-mil film = 8
[tex]n_2[/tex] = sample of 20-mil film = 8
[tex]\mu_1[/tex] = population mean speed for the 25-mil film
[tex]\mu_2[/tex] = population mean speed for the 20-mil film
Also, [tex]s_p =\sqrt{\frac{(n_1-1)s_1^{2}+ (n_2-1)s_2^{2}}{n_1+n_2-2} }[/tex] = [tex]\sqrt{\frac{(8-1)\times 0.11^{2}+ (8-1)\times 0.09^{2}}{8+8-2} }[/tex] = 0.1005
Here for constructing a 98% confidence interval we have used a Two-sample t-test statistics because we don't know about population standard deviations.
So, 98% confidence interval for the difference in population means, ([tex]\mu_1-\mu_2[/tex]) is;
P(-2.624 < [tex]t_1_4[/tex] < 2.624) = 0.98 {As the critical value of t at 14 degrees of
freedom are -2.624 & 2.624 with P = 1%}
P(-2.624 < [tex]\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] < 2.624) = 0.98
P( [tex]-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] < [tex]2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] < ) = 0.98
P( [tex](\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] < ([tex]\mu_1-\mu_2[/tex]) < [tex](\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] ) = 0.98
98% confidence interval for ([tex]\mu_1-\mu_2[/tex]) = [ [tex](\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] , [tex](\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] ]
= [ [tex](1.15-1.06)-2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } }[/tex] , [tex](1.15-1.06)+2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } }[/tex] ]
= [-0.042, 0.222]
Therefore, a 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].
Since the above interval contains 0; this means that decreasing the thickness of the film doesn't increase the speed of the film.
Find the coordinate vector [Bold x ]Subscript Upper B of x relative to the given basis BequalsStartSet Bold b 1 comma Bold b 2 comma Bold b 3 EndSet
Answer:
The answer to this question can be defined as follows:
Step-by-step explanation:
In the question equation is missing so, the equation and its solution can be defined as follows:
[tex]B={b_1,b_2}\\\\b_1= \left[\begin{array}{c}5&5\end{array}\right] \ \ \ \ \b_2= \left[\begin{array}{c}2&-5\end{array}\right] \ \ \ \ \x= \left[\begin{array}{c}-7&-35\end{array}\right][/tex]
[tex]\left[\begin{array}{c}a&c\end{array}\right] =?[/tex]
[tex]\to \left[\begin{array}{c}-7&-35\end{array}\right]= a\left[\begin{array}{c}5&5\end{array}\right]+c \left[\begin{array}{c}2&-5\end{array}\right] \\[/tex]
[tex]\to \left[\begin{array}{c}-7&-35\end{array}\right]= \left[\begin{array}{c}5a+2c&5a-5c\end{array}\right]\\\\\to 5a+2c=-7....(1)\\\\\to 5a-5c=-35....(2)\\\\[/tex]
subtract equation 1 from equation 2:
[tex]\to 7c=28\\\\\to c=\frac{28}{7}\\\\\to c= 4\\\\[/tex]
put the value of c in equation 1
[tex]\to 5a+2(4)=-7\\\to 5a+8=-7\\\to 5a=-7-8\\\to 5a=-15\\\to a= -3[/tex]
coordinate value is [-3,4].
please help me out with these questions. Its trigonometry.
Find the value of the lettered angles
In case the pic's not clear;
[tex] \cos \alpha = \sin(50 + \alpha ) [/tex]
Answer: i) θ = 30°, 60°, 210°, & 240°
ii) θ = 20° & 200°
Step-by-step explanation:
i) sin (2θ) = cos 30°
[tex]\sin(2\theta)=\dfrac{\sqrt3}{2}\\\\.\quad 2\theta=\sin^{-1}\bigg(\dfrac{\sqrt3}{2}\bigg)\\\\.\quad 2\theta=60^o\qquad 2\theta=120^o\\\\.\quad \theta=30^o\qquad \theta=60^o[/tex]
To include all of the solutions for one rotation, add 360/2 = 180 to the solutions above. θ = 30°, 60°, 210°, 240°
If you need ALL of the solutions (more than one rotation), add 180n to the solutions. θ = 30° + 180n & 60° + 180n
*********************************************************************************************
ii) cos α = sin (50 + α)
Use the Identity: cos α = sin (90 - α)
Use Transitive Property to get: sin (50° + α) = sin (90° - α)
50° + α = 90° - α
50° + 2α = 90°
2α = 40°
α = 20°
To find all solutions for one rotation, add 360/2 = 180 to the solution above.
α = 20°, 200°
If you need ALL of the solutions (more than one rotation), add 180n to the solution. α = 20° + 180n
a store specializing in mountain bikes is to open in one of two malls if the first mall is selected the store anticipates a yearly profit of $825,000 if successful a yearly loss of 275,000 otherwise the probability of success is 1/2 if the second mall is selected it is an estimated that the yearly profit will be 550,000 if successful otherwise the annual loss will be 165,000 the probability of success at the second mall is three Force
Complete question :
a store specializing in mountain bikes is to open in one of two malls if the first mall is selected the store anticipates a yearly profit of $825,000 if successful a yearly loss of 275,000 otherwise the probability of success is 1/2 if the second mall is selected it is an estimated that the yearly profit will be 550,000 if successful otherwise the annual loss will be 165,000 the probability of success at the second mall is three Fourth (3/4).
What is the expected profit of thesecond mall?
Answer:
$453,750
Step-by-step explanation:
Given the following :
First mall:
Profit if successful = $825,000
Loss if otherwise = $275000
Probability of success = 1/2
Second mall:
Profit if successful = $550,000
Loss if otherwise = $165,000
Probability of success = 3/4
Expected profit of second mall:
If probability of profit ' P(profit)' = 3/4
Then,
Probability of loss P(loss) = 1 - P(profit)
P(loss) = 1 - 3/4 = 1/4
Expected profit:
[P(profit) * profit] + [P(loss) * loss])
(0.75 * $550,000) + (0.25 * (-$165,000))
$412,500 - $41,250 = $453,750
URGENT!! The quotient of the rational expressions
Answer:
[tex] \frac{2 {x}^{2} }{3 {x}^{2} - 7x + 2 } [/tex]Option C is the correct option
Step-by-step explanation:
[tex] \frac{x}{3x - 1} \div \frac{x - 2}{2x} [/tex]
To divide by a fraction, multiply by the reciprocal of that fraction
[tex] \frac{x}{3x - 1} \times \frac{2x}{x - 2} [/tex]
Multiply the fractions
[tex] \frac{2 {x}^{2} }{(3x - 1)(x - 2)} [/tex]
Multiply the parentheses
[tex] \frac{2 {x}^{2} }{3x(x - 2) - 1(x - 2)} [/tex]
[tex] \frac{2 {x}^{2} }{3 {x}^{2} - 6x - x + 2 } [/tex]
Collect like terms
[tex] \frac{2 {x}^{2} }{3 {x}^{2} - 7x + 2 } [/tex]
Hope this helps...
Best regards!!
What is the Greatest Common Factor GCF between two expressions?
Answer:
The GCF is the largest expression that is factor of all expressions
Answer:
The GCF of two expressions is the greatest expression that is a factor of both the expressions.
Step-by-step explanation:
For example 7x² and 14x.
7x² = 1, 7, x, x
14x = 2, 7, x
The greatest common factor of the two expressions is 7x.
The amount of flow through a solenoid valve in an automobile's pollution-control system is an important characteristic. An experiment was carried out to study how flow rate depended on three factors: armature length, spring load, and bobbin depth. Four different levels (low, fair, moderate, and high) of each factor were chosen, and a single observation on flow was made for each combination of levels.A) The resulting data set consisted of how many observations?
B) Is this an enumerative or analytic study? Explain.
Answer:
A) 64 observations
B) analytic study
Step-by-step explanation:
Given:
There are 3 number of factors i.e. armature length, spring load, and bobbin depth.
There are 4 levels i.e. low, fair, moderate, and high
There is a single i.e. 1 observation on flow made for each combination of levels.
A)
To find:
Number of observations.
There are 4 levels so these 4 levels are to be considered for each factor.
Number of observations = 4.4.4 = 64
For example if we represent low fair moderate and high as L,F,M,H
and factors armature length, spring load, and bobbin depth as a,s,b
Then one of the observations can be [tex]L_{a} F_{s} H_{b}[/tex]
So resulting data set has 64 observations.
B)
This is analytic study.
The study basically "analyses" the amount of flow through a solenoid valve in an automobiles pollution control system. This study is conducted in order to obtain information from this existing process/experiment and this study focuses on improvement of the process, which created the results being analysed. So the goal is to improve amount of flow through a solenoid valve practice in the future. Also you can see that there is no sampling frame here so if the study was enumerative that it should focus on collecting data specific items in the frame so it shows that its not enumerative but it is analytic study.
express 3.222......in p/q form
Answer:
3.22222...... = [tex]\frac{29}{9}[/tex]
Step-by-step explanation:
In this question we have to convert the number given in recurrent decimals into fraction.
Recurrent decimal number is 3.22222.......
Let x = 3.2222......... -------(1)
Multiply this expression by 10.
10x = 32.2222........... -------(2)
Now subtract the expression (1) from (2),
10x = 32.22222.....
x = 3.22222.......
9x = 29
x = [tex]\frac{29}{9}[/tex]
Therefore, recurrent decimal number can be written as [tex]\frac{29}{9}[/tex] which is in the form of [tex]\frac{p}{q}[/tex].
Find the total area of the prism.
Answer:
A=1,728
Step-by-step explanation:
To find the area of a prism, you must find the area of one side, then multiply it by so it would be Width*Hight*Depth, W*H*D.
The width is 12, the hight is 12, and the depth is 12 so you can write
A=12*12*12
Multiply 12 by 12
A=144*12
Multiply 12 by 144 to get your final total area
A=1,728
Hope this helps, feel free to ask follow-up questions if confused.
Have a good day! :)
Help, no time left; almost !
Answer:
x = 50
Step-by-step explanation:
Since the triangle has 2 congruent sides then it is isosceles, thus the base angles are congruent, that is x and x
The sum of the angles in a triangle = 180°, thus
x + x + 80 = 180
2x + 80 = 180 ( subtract 80 from both sides )
2x = 100 ( divide both sides by 2 )
x = 50
verify sin4x - sin2x = cos4x-cos2x
Answer:
sin⁴x - sin²x = cos⁴x - cos²x
Solve the right hand side of the equation
That's
sin⁴x - sin²x
From trigonometric identities
sin²x = 1 - cos²xSo we have
sin⁴x - ( 1 - cos²x)
sin⁴x - 1 + cos²x
sin⁴x = ( sin²x)(sin²x)
That is
( sin²x)(sin²x)
So we have
( 1 - cos²x)(1 - cos²x) - 1 + cos²x
Expand
1 - cos²x - cos²x + cos⁴x - 1 + cos²x
1 - 2cos²x + cos⁴x - 1 + cos²x
Group like terms
That's
cos⁴x - 2cos²x + cos²x + 1 - 1
Simplify
We have the final answer as
cos⁴x - cos²xSo we have
cos⁴x - cos²x = cos⁴x - cos²xSince the right hand side is equal to the left hand side the identity is true
Hope this helps you
Jacob needs to know if the volume of a storage bin is under 3,000 cubic feet. The
dimensions of the bin are 17 ft. X 15 ft. x 10 ft.
a. Is the bin under 3,000 cubic ft.?
b. If yes, by how much?
Answer:
It is less than 3000 ft^3 by 450 ft^3
Step-by-step explanation:
The volume of the bin
V = l*w*h
V = 17*15*10
V =2550 ft^3
If it less than 3000 ft^3
V = 3000- 2550 =450 ft^3
If is less by 450 ft^3
Answer:
Let’s first multiply all the numbers given
Since it wants the volume we need to use the formula
LxWxH
17x15x10=2,550
Part A: yes the bin is under 3,000
Part B: by 450 more because if you subtract 3,000 and 2,550 you will get 450
Hope this helps! :)
43.
Some of the ingredients used by a baker for making 1 dozen
normal sponge cakes are listed below:
225g unsalted butter; 4 eggs; 125ml milk;
2 tsp vanilla extract; 264g plain flour
To make fully vegetarian cakes, the baker replaces each egg
with an additional 30g of plain flour.
The baker got an order for 100 normal cakes and 60 vegetarian
cakes. How much kilograms of flour would the baker need to
complete the order?
Answer:
4.12 kg
Step-by-step explanation:
Regular cakes:
1 dozen normal sponge cakes: 264 g plain flour
Vegetarian cakes:
1 dozen cakes: 264 g plain flour
4 eggs are replaced by 4 * 30 g of flour = 120 g flour
total flour for 1 dozen vegetarian cakes = 264 g + 120 g = 384 g
Proportion for regular cakes:
12 cakes to 264 g flour = 100 cakes to x grams flour
12/264 = 100/x
12x = 26400
x = 2200
2200 g flour for 100 regular cakes
Proportion for vegetarian cakes:
12 cakes to 384 g flour = 60 cakes to y grams flour
12/384 = 60/y
12y = 384 * 60
12y = 23040
y = 1920
1920 g flour for 60 vegetarian cakes
Total flour needed:
2200 g + 1920 g = 4120 g
4120 g * 1 kg/(1000 g) = 4.12 kg
Answer: 4.12 kg
Item 25
The linear function m=45−7.5b represents the amount m (in dollars) of money that you have after buying b books. Select all of the values that are in the domain of the function.
0
1
2
3
4
5
6
7
8
9
10
Item 25
The linear function m=45−7.5b represents the amount m (in dollars) of money that you have after buying b books. Select all of the values that are in the domain of the function.
0
1
2
3
4
5
6
7
8
9
10
Answer:
5
Step-by-step explanation:
Can someone help me with this one
Answer:
b^2
------
2a
Step-by-step explanation:
-6ab^3 10b
-------------- * -----------
5a -24 ab^2
Rewriting
-6ab^3 10b
-------------- * -----------
-24 ab^2 5a
Canceling like terms
b 2b
-------------- * -----------
4 a
Canceling the 2 and 4
b b
-------------- * -----------
2 a
b^2
------
2a
Answer:
b²/2a
Step-by-step explanation:
[(-6ab³)/5a]*[(10b)/(-24ab²)]
-60ab^4/-120a²b²= ( when divide ,subtract the exponents)
b²/2a
Plzzzzzzzzzzzzzzzzzzzzzz find the hcf of 15a²b² and -24ab
Let's take a look at each term separately.
15a^2b^2:
15 has factors 1, 3, 5, 15
a x a
b x b
-24ab
-24 has factors 1, 2, 3, 4, 6, 8, 12, 24
a
b
Now, we can see what each of these terms has in common. Both have a 3 in their factor lists, as well as one a and one b.
Therefore, the greatest common factor is 3ab.
Hope this helps!! :)
Answer:
3ab
Step-by-step explanation:
[tex]15a^{2} b^{2} - 24ab[/tex] is divided by 3
[tex]5a^{2} b^{2} - 8ab[/tex] take away a and b once
hope this helped!!!
[tex]5ab - 8[/tex]
= 3ab
Suppose that your uncle is decorating his house for christmas.He uses 300 strands of lights each containing 150 light bulbs.Each light bulb consumes 4 watts of power. If he illuminates his light for 5 hours a day for 30 days and power in his area sells for $0.08/kWh, how much will he end up paying to light his home for the holidays?
Answer:
$14.4
Step-by-step explanation:
From the question;
There are 300 strands of light each containing 150 light bulbs. Altogether, there are;
300 x 150 light bulbs = 45000 light bulbs.
Also;
Each bulb consumes 4 watts of power. Since there are 45000 light bulbs, the total power consumed by all the bulbs is;
45000 x 4 watts = 180000watts
Next convert the total power consumed to kW by dividing by 1000. i.e
180000watts = 180kW
Therefore, total power consumed is 180kW
He lights up for 5 hours a day for 30 days. This means that the total number of hours he lights his home for those 30 days is:
30 x 5 hours = 150 hours.
Now since power in his area sells for $0.08/kWh, this means that;
1kWh costs $0.08
Then;
180kWh will cost [180kWh x $0.08 / 1kWh] = $14.4
Therefore, he will end up paying $14.4 to light his home for the holidays.
surface area of a equilateral by hand
surface area of a equilateral by hand a 140.4 cm and 9cm
In this exercise, we estimate the rate at which the total personal income is rising in a metropolitan area. In 1999, the population of this area was 924,900, and the population was increasing at roughly 9400 people per year. The average annual income was $30,388 per capita, and this average was increasing at about $1400 per year (a little above the national average of about $1225 yearly). Use the Product Rule and these figures to estimate the rate at which total personal income was rising in the area in 1999.
Answer:
the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion
Step-by-step explanation:
From the given information:
Let consider y to represent the number of years after 1999
Then the population in time (y) can be expressed as:
P(y) = 9400y + 924900
The average annual income can be written as:
A(y) = 1400y + 30388
The total personal income = P(y) × A(y)
The rate at which the total personal income is rising is T'(y) :
T'(y) = P'(y) × A(y) + P(y) × A'(y)
T'(y) = (9400y + 924900)' (1400y + 30388) + (9400y + 924900) (1400y + 30388)'
T'(y) = 9400(1400y + 30388) + (9400y + 924900) 1400
Since in 1999 y =0
Then:
T'(0) = 9400(1400(0) + 30388) + (9400(0) + 924900) 1400
T'(0) = 9400(30388) + (924900)1400
T'(0) = $1,580,507,200 billion
Therefore; the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion
-6+4q+(-6q)−6+4q+(−6q)minus, 6, plus, 4, q, plus, left parenthesis, minus, 6, q, right parenthesis ?
Answer:
-16-5q
Step-by-step explanation:
-6+4q-6q-6+4q-6q-6+4q-6q= -18-6q
Answer:C
Step-by-step explanation: 100% correct I did it on Khan Academy