Answer:
2KCl+Fe---->FeCl2+2K
Explanation:
You can observe that the no.of atoms in reactant side is equal to that of products side of each element.
6CuNO3 + Al2(SO4)3 → 3Cu2SO4 + 2Al(NO3)3
Molar mass of CuNO3 125.56 g/mol
Molar mass of Al(NO3)3 213.01 g/mol
How many grams of copper (I) nitrate (CuNO3) are required to produce 44.0 grams of aluminum nitrate (Al(NO3)3)?
Answer:
77.81 g of CuNO₃
Explanation:
6 CuNO₃ + Al₂(SO₄)₃ ⇒ 3 Cu₂SO₄ + 2 Al(NO₃)₃
This is your chemical equation. We will need this information for converting from Al(NO₃)₃ to CuNO₃.
First, convert grams of Al(NO₃)₃ into moles using the molar mass.
[tex]44.0g*\frac{mol}{213.01g} = 0.2065mol[/tex]
Next, convert moles of Al(NO₃)₃ to moles of CuNO₃. You can do this by using the stoichiometry (the numbers in front of the compounds). For every 6 moles of CuNO₃, you will get 2 moles of Al(NO₃)₃, causing the ratio of CuNO₃ to Al(NO₃)₃ to be 6:2.
[tex]0.2065mol*\frac{6}{2} =0.6197mol[/tex]
Now that you moles of CuNO₃, convert this to grams using its molar mass.
[tex]0.6197 mol * \frac{125.56g}{mol} =77.81 g[/tex]
You will need 77.81 grams of CuNO₃ to produce 44.0 grams of Al(NO₃)₃.
What does synthesis gas (water gas) consist of?
Answer:
ch4+h2o----725°-->co+2h2
Please someone help me with this!!
Ammonia can be made by reaction of water with magnesium nitride as shown by the following unbalanced equation: Mg3N2(s) + H2O(l) Mg(OH)2(s) + NH3(g) If this process is 71% efficient, what mass of ammonia can be prepared from 24.5 kg magnesium nitride?
The mass of ammonia prepared from 24.5 kg magnesium nitride, according to the reaction Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH₃(g), knowing that the process is 71% efficient is 5.87 kg.
The balanced reaction of production of ammonia is:
Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH₃(g) (1)
First, let's find the number of moles of magnesium nitride
[tex] n_{Mg_{3}N_{2}} = \frac{m_{Mg_{3}N_{2}}}{M_{Mg_{3}N_{2}}} [/tex] (2)
Where:
[tex]m_{Mg_{3}N_{2}}[/tex]: is the mass of Mg₃N₂ = 24.5 kg
[tex]M_{Mg_{3}N_{2}}[/tex]: is the molar mass of Mg₃N₂ = 100.9494 g/mol
The number of moles is (eq 2):
[tex] n_{Mg_{3}N_{2}} = \frac{m_{Mg_{3}N_{2}}}{M_{Mg_{3}N_{2}}} = \frac{24500 g}{100.9494 g/mol} = 242.70 \:moles [/tex]
We can calculate the mass of ammonia prepared, knowing that 1 mol of Mg₃N₂ reacts with 6 moles of H₂O to produce 3 moles of Mg(OH)₂ and 2 moles of NH₃ (reaction 1).
[tex]n_{NH_{3}} = \frac{2\: moles\: NH_{3}}{1\: mol\: Mg_{3}N_{2}}*n_{Mg_{3}N_{2} = \frac{2\: moles\: NH_{3}}{1\: mol\: Mg_{3}N_{2}}*242.70 \:moles \:Mg_{3}N_{2} = 485.4 \:moles[/tex]
Then, the mass of NH₃ is:
[tex] m_{NH_{3}} = n_{NH_{3}}*M_{NH_{3}} = 485.4 \:moles*17.031 g/mol = 8266.8 g = 8.27 kg [/tex]
Since the process is 71% efficient, the mass that can be prepared is:
[tex] m = 8.27 kg*0.71 = 5.87 kg [/tex]
Therefore, the mass of ammonia that can be prepared is 5.87 kg.
I hope it helps you!
Cell Walls are found in Prokaryotes and Plant cells. True O False
Answer:
i think true
Explanation:
lemme know if right if not sorry :))
Which best describes the process that occurs when liquid water becomes
ice?
Answer:
Freezing
Explanation:
When a liquid goes to a solid, this process is called freezing.
Answer:
The water molecules get condensed and form a solid matter called ice. This process is called Condensation.
The nucleus of an atom stays together only because the repulsive forces, called
forces, are overcome by
even stronger attractive forces.
fusion
nuclear
electrostatic
Answer:
Electrostatic
Explanation:
The forces that are overcome are the repulsive electrostatic forces between the protons (all charged positively).
3. Define the term zwitterion. Draw the structure of alanine and explain why this molecule is a
zwitterion in certain conditions.
Answer:
A zwitterion or a hybrid ion is an ion that has both a positive and negative charge and can act as either a base or an acid.
Explanation:
A zwitterion or a hybrid ion is an ion that has both a positive and negative charge and can act as either a base or an acid. The net charge on a zwitterion is zero since it has equal number of positive and negative charges.
Alanine, is a monoamino monocarboxylica acid that is diprotic when fully protonated. The carboxylic acid group, COOH and the amino group, NH₃⁺, are able to produce one proton each. At a pH equal to the isoelectric point of alanine, it exists mainly in the zwitterionic form with the α-amino group protonated as NH₃⁺ and the α-carboxyl group deprotonated as COO⁻ . This is because at the isoelectric point of alanine (6.0), pI is greater than the acid dissociation constant, pKa of the α-carboxyl group whereas, pI is less than the acid dissociation constant, pKa of the α-amino group, so the two groups are negatively and positively charged respectively.
PLZ HELP URGENT!!!!!
Answer:
A fluke because it is an vertebrae
Explanation:
Kevin is working on a model that shows the positions of Earth, the Moon, and the Sun during the phases of
the Moon. How should he position them to show a New Moon?
Answer:
Explanation:what’s the answer
Answer: A. With Earth between the Moon and the Sun.
Explanation:
Calculate the molecular mass for the following: SnO2
Answer:
[tex]MM=150.71g/mol[/tex]
Explanation:
Hello there!
In this case, since the molar masses of chemical compounds allow us to understand the mass they have per mole of substance, for tin oxide, we can see it has one tin atom and two oxygen atoms; thus, for the calculation of this molar mass we multiply the atomic masses by the number of atoms and them add the results up:
[tex]MM=m_{Sn}+2m_O\\\\MM=118.71g/mol+2*16.00g/mol\\\\MM=150.71g/mol[/tex]
Best regards!
Counting Atoms in Compound 8cl2o
milk milk milk........
Answer:
gimme that chocky milk.....
Explanation:
Answer:
m i l k
Explanation:
Which unit is NOT correctly paired?
O Liters : Volume
O Formula Mass : Count
O Grams: Mass
O Molecules : Mass
Answer:
Molecules : Mass
Explanation:
The first three answer choices correctly pair a unit with what it measures. Molecules are not used to measure mass; grams are.
find the number of molecules in 35.20 g of nitrogen dioxide
Answer:
4.584*10^23 molecules
Explanation:
Find molar mass of nitrogen and oxygen on periodic table.
find molar mass of nitrogen dioxide
use this to find moles of nitrogen dioxide
multiply by avagadros number
An empty steel container is filled with 2.0 atm of H₂ and 1.0 atm of F₂. The system is allowed to reach equilibrium according to the reaction below. If Kp = 0.45 for this reaction, what is the equilibrium partial pressure of HF?
The equilibrium partial pressure of HF is 0.55 atm.
The equation of the reaction is;
H2(g) + F2(g) ⇄ 2HF
I 2 1 0
C -x -x +x
E 2 - x 1 - x x
We know that;
pH2 = 2.0 atm
PF2 = 1.0 atm
pHF = ??
Kp = 0.45
So;
Kp = (pHF)^2/pH2. pF2
0.45 = x^2/(2 - x) (1 - x)
0.45 = x^2/x^2 - 3x + 2
0.45(x^2 - 3x + 2) = x^2
0.45x^2 - 1.35x + 0.9 = x^2
0.55 x^2 + 1.35x - 0.9 = 0
x = 0.55 atm
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HELP PLEASE I NEED HELP THANKS I LOVE U
How many moles of potassium nitrate (KNO3) are there in 0.300 L of a 2 molar solution?
Answer:
0.500-Molarity solution
Explanation:
The moles of the compound is given as the number of atomic mass unit in the compound. The moles of potassium nitrate in the solution are 0.6 mol
What is molarity?The molarity is the concentration unit, and it can be defined as the moles of compound present in the liter of solution.
The molarity can be expressed as:
[tex]\rm Molarity=\dfrac{Moles}{Volume(L)}[/tex]
The given potassium nitrate solution has, molarity = 2 M
The volume of the solution is 0.3 L.
Substituting the values for the moles of the compound:
[tex]\rm 2\;M=\dfrac{Moles}{0.3\;L} \\\\Moles=2\;\times\;0.3\;mol\\Moles=0.6\;mol[/tex]
The moles of potassium nitrate in 2 M solution is 0.6 mol.
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A 50.0-mL volume of 0.15 M HBr is titrated with 0.25 M KOH. Calculate the pH after the addition of 13.0 mL of KOH. Express your answer numerically.
Answer:
pH= 1.17
Explanation:
The neutralization reaction between HBr (acid) and KOH (base) is given by the following equation:
HBr(aq) + KOH(aq) → KBr(aq) + H₂O(l)
According to this equation, 1 mol of HBr reacts with 1 mol of KOH. Then, the moles can be expressed as the product between the molarity of the acid/base solution (M) and the volume in liters (V). So, we calculate the moles of acid and base:
Acid:
M(HBr) = 0.15 M = 0.15 mol/L
V(HBr) = 50.0 mL x 1 L/1000 mL = 0.05 L
moles of HBr = M(HBr) x V(HBr) = 0.15 mol/L x 0.05 L = 7.5 x 10⁻³ moles HBr
Base:
M(KOH) = 0.25 M = 0.25 mol/L
V(HBr) = 13.0 mL x 1 L/1000 mL = 0.013 L
moles of HBr = M(HBr) x V(HBr) = 0.25 mol/L x 0.013 L = 3.25 x 10⁻³ moles KOH
Now, we have: 7.5 x 10⁻³ moles HBr > 3.25 x 10⁻³ moles KOH
HBr is a strong acid and KOH is a strong base, so they are completely dissociated in water: the acid produces H⁺ ions and the base produces OH⁻ ions. So, the difference between the moles of HBr and the moles of KOH is equal to the moles of remaining H⁺ ions after neutralization:
moles of H⁺ = 7.5 x 10⁻³ moles HBr - 3.25 x 10⁻³ moles KOH = 4.25 x 10⁻³ moles H⁺
From the definition of pH:
pH = -log [H⁺]
The concentration of H⁺ ions is calculated from the moles of H⁺ divided into the total volume:
total volume = V(HBr) + V(KOH) = 0.05 L + 0.013 L = 0.063 L
[H⁺] = (moles of H⁺)/(total volume) = 4.25 x 10⁻³ moles/0.063 L = 0.067 M
Finally, we calculate the pH after neutralization:
pH = -log [H⁺] = -log (0.067) = 1.17
Question 2 (1 point)
Which of the following does NOT involve a chemical reaction?
Fallen leaves decay in a compost pile.
Leaves change color in the fall.
O A fire burns a pile of fallen leaves.
A pond freezes over in the winter.
Answer:
D. A pond freezing over is not a chemical reaction, it is a physical reaction.
A student mixes 5.00 mL of 0.0020 M Fe(NO3)3 with 3.00 mL of 0.0020 M KSCN solution and 2.00 mL water at a certain temperature. He places a sample of the resulting solution in a spectrometer, and measures the transmittance as 23% at 447 nm. What are the initial concentrations of [Fe3 ] and [SCN-]
Answer:
[Fe⁺³] = 0.0010 M
[SCN⁻] = 0.0006 M
Explanation:
First we calculate how many moles of Fe⁺³ and SCN⁻ were added, using the given volumes and concentrations:
Fe⁺³ ⇒ 5.00 mL * 0.0020 M = 0.010 mmol Fe⁺³SCN⁻ ⇒ 3.00 mL * 0.0020 M = 0.006 mmol SCN⁻Now we can calculate the initial concentrations, after calculating the new volume of the solution:
New volume = 5.00 mL + 3.00 mL + 2.00 mL = 10.00 mL[Fe⁺³] = 0.010 mmol / 10.00 mL = 0.0010 M[SCN⁻] = 0.006 mmol / 10.00 mL = 0.0006 MAnybody Understand this question please help me !
Answer:
[tex]m_{Sn}=630.57gSn[/tex]
Explanation:
Hello!
In this case, according to the chemical reaction:
[tex]SnO_2+2H_2\rightarrow Sn+2H_2O[/tex]
We can evidence the 2:1 mole ratio between hydrogen and tin, thus, we perform the following stoichiometric setup to obtain the mass of produced tin:
[tex]m_{Sn}=21.46gH_2*\frac{1molH_2}{2.02gH_2}*\frac{1molSn}{2molH_2} *\frac{118.71gSn}{1molSn} \\\\m_{Sn}=630.57gSn[/tex]
Best regards!
What enzyme catalyses the reaction of PRPP transfer to hypoxanthine with
formation of IMP?
Answer:
HPRT
Explanation:
HPRT catalyzes the salvage reactions of hypoxanthine and guanine with PRPP to form IMP and GMP
The formation of GMP from IMP requires oxidation at C-2 of the purine ring, followed by a glutamine-dependent amidotransferase reaction that replaces the oxygen on C-2 with an amino group to yield 2-amino,6-oxy purine nucleoside monophosphate, or as this compound is commonly known, guanosine monophosphate.
When 14 cal of heat are added to 12g of a liquid its temperature rises from 10.4 C to 12.7 C. What is the specific heat of the liquid
Answer:
0.51 cal/g.°C
Explanation:
Step 1: Given data
Added energy in the form of heat (Q): 14 calMass of the liquid (m): 12 gInitial temperature: 10.4 °CFinal temperature: 12.7 °CStep 2: Calculate the temperature change
ΔT = 12.7 °C - 10.4 °C = 2.3 °C
Step 3: Calculate the specific heat of the liquid (c)
We will use the following expression.
c = Q / m × ΔT
c = 14 cal / 12 g × 2.3 °C = 0.51 cal/g.°C
Which is a form of kinetic energy?
A. gravitational energy
B. chemical energy
C. electrical energy
D. sound energy
Please help me thanks
Answer:
your finger becomes negatively charged
Explanation:
hope it helps. follow me
Which postmortem parameter is fixed by 8 hours?
1)cloudiness of the eyes
2)rigor mortis
3)livor mortis
4)putrefaction
Go to the Phase Changes tab. Select the particular molecule, and set the temperature to the given values by using the stove to increase or decrease the temperature. Increase the pressure of the cylinder by moving the lid of the cylinder down with the help of the finger. The pressure of the cylinder is indicated by the pressure gauge on the top left corner of the simulation. On the right-hand side of the simulation is the phase diagram for the molecule.
As the molecules collide on the walls of the cylinder, the pressure of the cylinder does not remain constant; it fluctuates slightly as indicated by the gauge.
In the phase diagram, observe the red point. When a particular molecule is selected, set the temperature and pressure condition to the required value. Observe the position of the red point on the phase diagram when the pressure reaches approximately near the required value.
Which of the following conditions will result in the formation of a supercritical fluid?
Check all that apply.
1. Oxygen at 100 K and no pressure
2. Argon at 160 K and approximately 6 atm pressure
3. Water at 294 K and approximately 1 atm pressure
4. Neon at 32 K and approximately 1 atm pressure
5. Neon at 50 K and approximately 10 atm pressure
6. Water at 894 K and approximately 20 atm pressure
7. Argon at 100 K and no pressure
8. Oxygen at 194 K and approximately 2 atm pressure
Answer:
2. Argon at 160K and approximately 6 atm pressure
5. Neon at 50K and approximately 10 atm pressure
6. Water at 894 K and approximately 20 atm pressure
8. Oxygen at 194K and approximately 2 atm pressure
Explanation:
Super critical fluid is formed when temperature rises beyond critical point. The state of molecules can be liquid or gas. The pressure should be above the certain level with an introduction of different gases at minimum of 2 atm pressure.
What is the mass of 8.56 x 10^23 formula units of BaBr2? (3 sig figs in your answer)
296 g BaBr₂
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableMolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 8.56 × 10²³ formula units BaBr₂
[Solve] grams BaBr₂
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of Ba - 137.33 g/mol
[PT] Molar Mass of Br - 35.45 g/mol
Molar Mass of BaBr₂ - 137.33 + 2(35.45) = 208.23 g/mol
Step 3: Convert
[DA} Set up: [tex]\displaystyle 8.56 \cdot 10^{23} \ formula \ units \ BaBr_2(\frac{1 \ mol \ BaBr_2}{6.022 \cdot 10^{23} \ formula \ units \ BaBr_2})(\frac{208.23 \ g \ BaBr_2}{1 \ mol \ BaBr_2})[/tex][DA] Multiply/Divide [Cancel out units]: [tex]\displaystyle 295.99 \ g \ BaBr_2[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
295.99 g BaBr₂ ≈ 296 g BaBr₂
Thank you agenthammerx for helping me with this question!
Answer:
296 g BaBr₂
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
Left to Right
Chemistry
Atomic Structure
Reading a Periodic Table
Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
Using Dimensional Analysis
Explanation:
Step 1: Define
[Given] 8.56 × 10²³ formula units BaBr₂
[Solve] grams BaBr₂
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of Ba - 137.33 g/mol
[PT] Molar Mass of Br - 35.45 g/mol
Molar Mass of BaBr₂ - 137.33 + 2(35.45) = 208.23 g/mol
Step 3: Convert
[DA} Set up:
[DA] Multiply/Divide [Cancel out units]:
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
295.99 g BaBr₂ ≈ 296 g BaBr₂
Rick is creating a love potion for Morty. To make the potion, Rick's needs 51 mL of a mixture solution where 40% is carbonated water. After checking around his shop, Rick finds two solutions he could use. The first solution he found is 65% green tea, 15% carbonated water, and 20% whole milk. The second solution is 17% orange juice, 38% lemonade, and 45% carbonated water. How much of the first solution and second solution does Rick need to mix together to create the love potion? Round your final answers to one decimal place. You may solve this problem using any method we have learned in the class.
Answer:
The amount of the first solution rick needs to mix together to create the love portion is 8.5 mL
Explanation:
So as to make the love potion, we have;
The percentage of carbonated water in the love portion = 40%
The percentage of green tea in the first solution = 65%
The percentage of carbonated water in the first solution = 15%
The percentage of whole milk in the first solution = 20%
The percentage of orange juice in the second solution = 17%
The percentage of lemonade in the second solution = 38%
The percentage of carbonated water in the second solution = 45%
Let 'x' represent the volume in mL of the first solution added to make the love portion, and let 'y' be the volume in mL of the second solution added to make the love portion, we have;
x + y = 51...(1)
0.15·x + 0.45·y = 0.40×51 = 20.4
0.15·x + 0.45·y = 20.4...(2)
Solving the system of simultaneous equation by making 'y' the subject of each of the equation gives;
For equation (1)
y = 51 - x
For equation (2)
y = 20.4/0.45 - (0.15/0.45)·x = 136 - 3·x
y = 136/3 - (1/3)·x
Equating the two equations of 'y', gives;
51 - x = 136/3 - (1/3)·x
51 - 136/3 = x - (1/3)·x
17/3 = (2/3)·x
(2/3)·x = 17/3
x = (3/2) × (17/3) = 17/2 = 8.5
x = 8.5
y = 51 - x = 42.5
y = 42.5
Therefore, the amount of the first solution rick needs to mix together to create the love portion, x = 8.5 mL
How many atoms are in 90.43 moles of copper
Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 8.12×10²³ atoms are in 90.43 mole of copper.
What is mole?
The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance. It measure the number of elementary entities of a given substance that are present in a given sample. There are so many formula for calculating mole.
we know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number
number of atoms/molecules=number of moles × 6.022×10²³(Avogadro number)
number of moles of copper=90.43 moles
Substituting all the given values in the above equation, we get
number of atoms/molecules= 90.43 × 6.022×10²³
number of atoms/molecules=8.12×10²³ molecules
Therefore, 8.12×10²³ atoms are in 90.43 mole of copper.
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