The balloon will attach to the wall because the balloon's negative charges will drive the electrons in the wall to shift to the other side of their atoms, leaving the wall's surface positively charged.
how r u
________________.
You are riding a bicycle up a gentle hill. It is fairly easy to increase your potential
energy, but to increase your kinetic energy would be harder.
True or false
The force of a hammer drives a nail into wood. This is an example of?
A. An unbalanced force.
B. Gravitational force.
C. Friction.
D. Balanced forces.
Answer:
A. An unbalanced force.
Explanation:
There needs to be a net force in order for the nail to be driven into presumably the wall. Without the net force then the hammer and nail wouldn't move.
An object absorbs red, orange, yellow, blue, indigo, and violet light. What color is it?
A. blue
B. green
C. indigo
D. red
Answer: B. Green
Explanation:
Since the object absorbs all the other options listed here, it will reflect green light. This makes the object appear green to our eyes.
Blue (A), indigo (C), and red (D) are listed in red, orange, yellow, blue, indigo, and violet. Green is not, so this is our answer.
Fun fact:
An example of this is grass!
Answer:
green
Explanation:
A magnet gets demagnetized when it is heated.
Answer:
The delicate balance between temperature and magnetic domains is destabilized when a magnet is subjected to high temperatures. If a magnet is exposed to this temperature for an extended length of time or heated over its Curie temperature, it will lose its magnetism and become irreversibly demagnetized.
Explanation:
A 7 kg ball of clay traveling at 12 m/s collides with a 25 kg ball of clay traveling in the
same direction at 6 m/s. What is their combined speed if the two balls stick together
when they touch?
Answer:
Given:
m1 = 7 kg
V1 = 12 m/s
m2 = 25 kg
V2 = 6 m/s
To find:
Combined speed of two balls stick together after collision V = ?
Solution:
According to law of conservation of momentum,
m1V1 + m2V2 = (m1+m2)V
7×12 + 25×6 = (7+25)V
84 + 150 = 32V
V = 234/32
V = 7.31 m/s
Combined speed of two ball is 7.31 m/s
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What is the angular momentum at a radius of 2 m with an object of 5 kg at a
velocity of 20 m/s?
The angular momentum is 200 kg m^2 s^-1
what is angular momentum?Angular momentum is the product of linear momentum and the perpendicular distance. Linear momentum is the product of mass and velocity, where radius is the perpendicular distance
Angular momentum = mass * velocity * radius
Angular momentum = 5 * 2 * 20
Angular momentum = 200 kg m^2 s^-1
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Determine
i. the total capacitance for the circuit
ii. the total charge stored in the circuit
iii. the charge stored in C9 (3μF)
(i) The total capacitance for the circuit is 5 μF.
(ii) The total charge stored in the circuit is 1 x 10⁻⁴ C.
(iii) The charge stored in 3μF capacitor is 6 x 10⁻⁶ C.
Total capacitance of the circuit
The total capacitance of the circuit is determined by reolving the series capacitors separate and parallel capacitors separate as well.
C1 and C2 are in series[tex]\frac{1}{C_{12}} = \frac{1}{C_1 } + \frac{1}{C_2} \\\\\frac{1}{C_{12}} = \frac{1}{4 } + \frac{1}{4} \\\\\frac{1}{C_{12}} = \frac{1}{2} \\\\C_{12} = 2 \ \mu F[/tex]
C1 and C2 are parallel to C3[tex]C_{123} = C_{12} + C_3\\\\C_{123} = 2\ \mu F + 2\ \mu F \\\\C_{123} = 4 \ \mu F[/tex]
C(123) is series to C5 and C6[tex]\frac{1}{C_{t} } = \frac{1}{C_{123}} + \frac{1}{C_5} + \frac{1}{C_6} \\\\\frac{1}{C_{t} } = \frac{1}{4} + \frac{1}{6} + \frac{1}{6} \\\\\frac{1}{C_{t} } = \frac{12}{24} \\\\\frac{1}{C_{t} } = \frac{1}{2} \\\\C_t = 2 \ \mu F[/tex]
C7 and C8 are in series[tex]\frac{1}{C_{78}} = \frac{1}{6} + \frac{1}{6} \\\\\frac{1}{C_{78}} = \frac{2}{6} \\\\\frac{1}{C_{78}} =\frac{1}{3} \\\\C_{78} = 3 \ \mu F[/tex]
Total capaciatnce of the circuitCt + C(78) = 2 μF + 3 μF = 5 μF
Total charge stored in the circuitThe total charge stored in the capacitor is calculated as follows;
Q = CV
Q = (5 x 10⁻⁶) x (20)
Q = 1 x 10⁻⁴ C
Charge stored in 3μF capacitorQ = (3 x 10⁻⁶) x (20)
Q = 6 x 10⁻⁶ C
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A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C. How much water freezes onto the ice? The specific heat of ice is 0.5 cal/g · ◦ C and its heat of fusion of is 80 cal/g. Answer in units of g.
For A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C, the amount of water that freezes onto the ice? is mathematically given as
x = 9.93 g
What is the amount of water that freezes onto the ice?Where
Energy received = energy given out
Generally, the amount of water is mathematically given as
(53)(0.5)(30) = (80)(x)
Therefore
x = (49)(0.5)(16)/(80)
x = 9.93 g
In conclusion, the mass of water
x = 9.93 g
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. A rope is being used to pull a mass of 10 kg vertically upward. Determine the tension on the rope, if starting from rest, the mass acquires a velocity of 4 ms-1 in 8s [g= 10ms-2]
[tex]\text{Given that,}\\\\\text{Mass, m =10 kg}\\\\\text{Time, t = 8 sec}\\\\\text{Velocity, v = 4~m/s}\\\\\text{When a body is moving upwards,}\\\\\text{Tension,}~ T=mg +ma\\\\~~~~~~~~~~~~~~~=mg+m\left(\dfrac{v-u}t \right)\\\\~~~~~~~~~~~~~~~=10(10)+10\left(\dfrac{4-0}8\right)\\\\~~~~~~~~~~~~~~~=100+10\left(\dfrac 12\right)\\\\~~~~~~~~~~~~~~~=100+5\\\\~~~~~~~~~~~~~~~=105~N[/tex]
How do human population growth trends differ between developed nations and developing nations?
Answer:
Replacement-Level Fertility
Another important population characteristic that differ btw develop nation and developing nations is relates to births is replacement-level fertility. Replacement-level fertility is the fertility rate that will result in the replacement of the parents in the population. Again, in an ideal world, the human replacement-level fertility rate would be exactly two. This would mean that each couple would produce two offspring that would replace them in the population. If this occurred, then the human population would stay at a stable rate
While cruising on the high sea at speed of v = 22 km/hr, a cargo ship suddenly encounters a problem with its propeller shaft leading to the main engine being shut down. This causes the vessel to slow down to 12 km/hr over the next 14 minutes. Assuming that its deceleration profile is following a correlation of as a = -0.85ct², where c is the acceleration constant for any time t, determine; i) The magnitude for constant c from the two boundary limits of deceleration profile given above, and ii) Plot against the timescale for same interval above, a total distance covered by the vessel as it's slowing down from 22 km/hr to 12 km/hr. Also plot the speed profile for the vessel during that 14 minutes' span.
Answer:
how can you support to leprosy victims?
Select the correct answer. Based on the law of conservation of energy, which statement is correct? O A. Energy is always being added to all parts of the Universe. O B. Energy is often destroyed in some parts of the Universe. O C. Energy in a closed system cannot change forms. O D. Energy in an isolated system remains constant.
Answer:
d. energy in an isolated system remains constant.
Explanation:
energy can neither be replaced or destroyed
How far back into the universe are we able to see? Explain.
Answer:
About 46 billion light years Because space expands so what we didn’t see before is what we could see now. An example could be how everyone thought Pluto was a regular sized planet but once you get a look at the bigger picture and compare it to other thing in space we now know Pluto is a dwarf planet.
The magnetic field perpendicular to a single wire loop of diameter 10.0 cm decreases from 0.50 T to zero. The wire is made of copper and has a diameter of 2.0 mm and length 1.0 cm. How much charge moves through the wire while the field is changing?
I know how to do the calculations, but can someone please explain what is the 10cm diameter and 2mm diameter? Why is there one wire and two diameters? I understand this problem mathematically but not conceptually.
Hi there!
We can begin by using Lenz's Law:
[tex]\epsilon = -N\frac{d\Phi _B}{dt}[/tex]
N = Number of Loops
Ф = Magnetic Flux (Wb)
t = time (s)
Also, we can rewrite this as:
[tex]\epsilon = -NA\frac{dB}{dt}[/tex]
A = Area (m²)
Since the area is constant, we can take it out of the derivative.
This is a single wire loop, so N = 1.
Now, we can develop an expression for the induced emf.
We can begin by solving for the area:
[tex]A = \pi r^2 \\\\d = r/2 r = 0.05cm \\\\A = \pi (0.05^2) = 0.007854 m^2[/tex]
We can also express dB/dt as:
[tex]\frac{dB}{dt} = \frac{\Delta B}{t} = \frac{0-0.5}{t} = \frac{-0.5}{t}[/tex]
Now, we can create an equation.
[tex]\epsilon = -(1)(0.007854)\frac{-0.5}{t} = \frac{0.003927}{t}[/tex]
To solve the system, we must now develop an expression for current given an emf and resistance.
Begin by calculating the resistance of the copper wire:
[tex]R = \frac{\rho L}{A}[/tex]
ρ = Resistivity of copper (1.72 * 10⁻⁸ Ωm)
L = Length of wire (0.01 m)
A = cross section area (m²)
Solve:
[tex]R = \frac{(1.72*10^{-8})(0.01)}{\pi (0.001^2)} = 5.475 * 10^{-5} \Omega m[/tex]
Now, we can use the following relation (Ohm's Law):
[tex]\epsilon = iR\\\\\epsilon = \frac{Q}{t}R[/tex]
*Since current is equivalent to Q/t.
Plug in the value of R and set the two equations equal to each other.
[tex]\frac{Q}{t}(5.475 * 10^{-5}) = \frac{0.003927}{t}[/tex]
Cancel out 't'.
[tex]Q (5.475 * 10^{-5}) = 0.003927 \\\\Q = \frac{0.003927}{5.475*10^{-5}} = \boxed{71.73 C}[/tex]
Suppose a grower sprays (2.2x10^1) kg of water at 0 °C onto a fruit tree of mass 180 kg. How much heat is released by the water when it freezes?
There is no temperature change which drives heat flow, thus no heat will be released by the water.
Heat released by the water when it freezesThe heat released by the water when it freezes is calculated as follows;
Q = mcΔФ
where;
m is mass of waterc is specific heat capacity of waterΔФ is change in temperature = Фf - ФiInitial temperature of water, Фi = 0 °C
when water freezes, the final temperature, Фf = 0 °C
Q = 22 x 4200 x (0 - 0)
Q = 0
Since there is no temperature change which drives heat flow, thus no heat will be released by the water.
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You see a car that appears very small, so you assume that it must be far from you. You are using the monocular cue of
The monocular cue of relative size
1. What is the distance covered by a T-Rex that goes from 0 m/s to 9 m/s in 6.78 seconds? (10
points)
With the use of first and third equation of motion, the distance covered by a T-Rex is 30.51 m
Linear MotionWhen a body is in linear motion, the body is moving in a straight line. some of the parameters to consider are:
Distance coveredSpeedVelocityAccelerationE.T.CGiven that a T-Rex move from 0 m/s to 9 m/s in 6.78 seconds, the distance covered can be found by calculating the acceleration.
Let us use equation 1
V = U + at
9 = 0 + 6.78a
a = 9 / 6.78
a = 1.33 m/[tex]s^{2}[/tex]
Now let us use equation 3
[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as
[tex]9^{2}[/tex] = 2 x 1.33 x S
81 = 2.655S
S = 81/2.655
S = 30.51 m
Therefore, the distance covered by a T-Rex is 30.51 m.
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Two identical spheres, A and B, carry charges of
+6 microcoulombs and -2 microcoulombs,
respectively. If these spheres touch, what will be
the resulting charge on sphere A?
The resulting charge in sphere A from the two given different charges is determined as +2 μC.
Resulting of the two speheres
The resulting charge of the two spheres is determined by suming the two individual charges together as shown below;
Resulting charge = +6 μC - 2 μC
Resulting charge = +4 μC
Charge in sphere AThe resulting charge will be distributed uniformly between the two spheres and charge in sphere A and B will be equal.
Charge in sphere A = charge in sphere B = ¹/₂ x +4 μC = + 2 μC
Thus, the resulting charge in sphere A from the two given different charges is determined as +2 μC.
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A satellite with a mass of 45 kg fires its rocket thrusters, which give an impulse of 1035 kg•m/s. What was the total change in the velocity of the satellite - that is, what was the total ΔV?
O 58 m/s
O 23 m/s
O 39 m/s
O 47 m/s
The total change in velocity of the satellite is 23 m/s
What is Impulse?In Physics, Impulse is the product of mass and change in velocity
Given:
mass = 46 kg
Impulse = 1035 kg•m/s
change in velocity = ?
impulse = mass * velocity
change in velocity = Impulse / mass
change in velocity = 1035 / 45
change in velocity = 23 m/s
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A circular ferris wheel that revolves at a constant rate once every 30 seconds. The
radius of the ferris wheel is 10 m. What is the normal force of the ferris wheel on a 10
kg toddler at the very bottom of the ferris wheel?
The normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is 102.41 N.
Centripetal force of the Ferris wheelThe normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is calculated as follows;
Fn = Fc + mg
Fn = mω²r + mg
where;
ω is the angular speed = 1 rev/30 s = 2π/30 s = 0.21 rad/sFn = 10(0.21²) 10 + 10(9.8)
Fn = 102.41 N
Thus, the normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is 102.41 N.
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"A ball with a mass of 0.1 kg is rolling at a velocity of 5 m/s. What is its
momentum?" What Given is the 5 in this problem? *
mass
velocity
acceleration
momentum
Answer:
velocity
Explanation:
because the si unit of mass is kg, velocity is m/s, acceleration is m/S2 , moment is kgm2/s . so 5 is given as velocity.
Water of mass, m at 100 ℃ is added to 0.50 kg of water at 20 ℃ in a lagged calorimeter of thermal capacity 105 JK −1 . If the specific heat capacity of water is 4200 kg −1K −1 and the final temperature of the mixture is 70℃, determine the value of m.
The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg
Determine the value of mApplying the principle of energy conservation
Heat lost by the hot body = heat absorbed by the cold water + calorimeter
= m * 4200 * ( 100 - 70 ) = 0.50 * 4200 * ( 70 -20 ) + 105 * ( 70 -20 )
= m * 126000 = 110250
therefore ;
m = 110250 / 126000
= 0.875 kg
Hence we can conclude that The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg
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If an object accelerates from rest, with a constant acceleration of
10 m/s2, what will its velocity be after 2 s?
The velocity of the body affter 2 seconds is 20 m/s
What is acceleration?Acceleration, a is the change of velocity with time. this is represented mathematically as
a = ( v - u ) / t
where:
u = intial velocity
v = final velocity
t = time
Given:
a = 10 m/s2
t = 2s
u = 0 ( from rest means initial velocity is zero )
therefore
a = v / t
v = a t
v = 10 * 2
v = 20 m/s
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When must scientific theories be changed
Answer:
when new information disproving the current theory becomes available.
Explanation:
hope this helps..
Answer:
when new evidence is discovered
Does every light source emit only one type of light?
Yes it is possible. Spectrum of emitted light depends upon the chemical composition of the source. and the way of its excitation. a clear example to us is that of sun.
A boy stands 190m from a high wall and claps his hands,if he hears an echo 1.3 seconds later. calculate the speed of sound in air.
Answer:
292.31 m/s
Explanation:
If Distance (d) = 190m
Time (t) = 1.3s
Speed of sound in air (v) =?
then
2d=vt
v=2d/t
v= 2×190/1.3
v=292.31 m/s
Physics Momentum topic question. I will mark brainliest please help.
Answer:
10 m/s
Explanation:
Given
mass of ball 1, m1 = 1 kgmass of ball 2, m2 = 0.25 kginitial velocity of ball 1, u1 = 10 m/sinitial velocity of ball 2, u2 = 0 m/s [stationary]final velocity of ball 1, v1 = 7.5 m/smomentum of ball 2 after collision = 2.5 kg m/sSolving :
We do not require all of this informationOnly require points 2 and 6Momentum = mass x velocity⇒ velocity = 2.5 / 0.25⇒ velocity = 10 m/sWhat type of heat transfer occurs in your stomach when you eat hot soup and an ice cold beverage
The type of heat transfer occurs in your stomach when you eat hot soup and an ice cold beverage is Conduction.
What is Conduction?This is the process by which heat energy is transmitted through collisions between neighboring atoms or molecules.
This happens when they are in close contact with each other which was why Conduction was chosen as the most appropriate choice.
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The resistance of a 60.-watt lightbulb operated at
120 volts is approximately
Answer:
The resistance of a 60 watt light bulb designed to operate at 120 volts is 240 Ω.
Explanation: