Street B has a slope of 1/4 and passes through (4, 6).
Write this street's equation in standard form.

Answer:

increased=150%=0.75

original price =100%

100%*0.75/150

=$0.5

Answer:

Step-by-step explanation:

The degree of the function is:

Correct choice is D

Answer:

-9

Step-by-step explanation:

2 - 5 = -3 then you would do -3 x 3 = -9

Answer:

Step-by-step explanation:

First we replace the original 'x' with 'x + 4,' which causes translation of the original parabolic graph 4 units to the left.  Next, reflect this translated graph about the x-axis (which is the effect of multiplying by -1/2 as shown).  Finally, shift the entire graph (the most recent one) down 5 units.

Answer:

The value of t is 8

Step-by-step explanation:

¼ t - 6 = - 4

¼ t = 6 - 4

¼ t = 2

t = 2 × 4

t = 8

Thus, The value of t is 8

-TheUnknownScientist

Answer: 46 degrees

Step-by-step explanation:

180 degrees in a triangle and the two 5 sides are congruent, making the other two angles congruent

180 - 88 = 92

92 / 2 = 46

Answer:

a: (0,3)

Step-by-step explanation:

the input 0 currently has two outputs, deleting one, (0,5), would cause the set of ordered pairs to become a function

Answer:

vertical

Step-by-step explanation:

This 'A' has vertical symmetry.

Answer:

x = [tex]\frac{1}{4}[/tex]

Step-by-step explanation:

Given

8 - (5 - 9x) = 7(1 - x) ← distribute parenthesis on both sides

8 - 5 + 9x = 7 - 7x

3 + 9x = 7 - 7x ( add 7x to  both sides )

3 + 16x = 7 ( subtract 3 from both sides )

16x = 4 ( divide both sides by 16 )

x = [tex]\frac{4}{16}[/tex] = [tex]\frac{1}{4}[/tex]

Answer:

8 - (5 - 9x) = 7(1 - x)

8 - 5 + 9x = 7 - 7x

3 + 9x = 7 - 7x

3 + 16x = 7

16x = 4

x = 4/16

0.25

Step-by-step explanation:

Answer:

See Explanation

Step-by-step explanation:

Given

[tex]d_1 =6in[/tex] --- the first diagonal

[tex]Area = (20in^2,25in^2)[/tex]

The question is incomplete, as the image of the kite and what is required are not given

However, a possible question could be to calculate the length of the other diagonal

Calculating the length of the other diagonal, we have:

[tex]Area = 0.5 * d_1 * d_2[/tex]

Make d2 the subject

[tex]d_2 = \frac{Area }{0.5 * d_1}[/tex]

Multiply by 2/2

[tex]d_2 = \frac{2 * Area }{2* 0.5 * d_1}[/tex]

[tex]d_2 = \frac{2 * Area }{1 * d_1}[/tex]

[tex]d_2 = \frac{2 * Area }{d_1}[/tex]

When Area = 20, we have:

[tex]d_2 = \frac{2 * 20}{6}[/tex]

[tex]d_2 = \frac{40}{6}[/tex]

[tex]d_2 = 6.67[/tex]

When Area = 25, we have:

[tex]d_2 = \frac{2 * 25}{6}[/tex]

[tex]d_2 = \frac{50}{6}[/tex]

[tex]d_2 = 8.33[/tex]

So:

[tex]d_2 = (6.67,8.33)[/tex]

This means that the length of the other diagonal is between 6.67in and 8.33in

Answer:

Natural Number: 1, 2, 3

Whole number: 7, 19, 24

Integer: 12

Rational Number: 8, 1.5

Irrational Number: π

Step-by-step explanation:

8th grade k-12 xx

Answer:

Move downward by 7 units

Move leftward by 6 units

[tex](x,y) \to (x -6,y-7)[/tex]

Step-by-step explanation:

Given

See attachment for grid

Required

The transformation from the current location to the new location

To do this, we pick two corresponding points on the current location and the new location.

We have:

[tex]A = (3,2)[/tex] -- Current location

[tex]A' = (-6,-5)[/tex] -- New location

First, move A downwards by 7 units.

The rule to this is:

[tex](x,y) \to (x,y-7)[/tex]

So, we have:

[tex](3,2) \to (3,2-7)[/tex]

[tex](3,2) \to (3,-5)[/tex]

Next, move the above points leftward by 6 units.

The rule to this is:

[tex](x,y) \to (x-6,y)[/tex]

So, we have:

[tex](3,-5) \to (3-6,-5)[/tex]

[tex](3,-5) \to (-3,-5)[/tex]

Answer:

the ball reaches a height of 64 feet after 2 sec.

The ball is in the air 4 sec.

Step-by-step explanation:

The ball is following the path of a parabola.  The maximum height is at the vertex of the parabola.

Let (h, k) be the vertex.  h will be the time it takes to reach the maximum height, and k will be that height.

y = [tex]-16t^{2} + 64t[/tex]

h = -b/2a = 64/(-2)(-16) = 64/32 = 2

k = -16(2)^2 + 64(2)

     -16(4) + 128

     - 64 + 128 = 64

V:  (2, 64)

So the ball reaches a height of 64 feet after 2 sec.

Let [tex]-16t^{2} + 64t[/tex] = 0       (0 is the height when the balls hits the ground)

-16t(t - 4) = 0

t = 0  or t = 4

The ball is in the air 4 sec.

Answer:

Step-by-step explanation:

Use synthetic division:

The coefficients of 2x^3 - 1 are {2, 0, 0, -1}.  Setting up synthetic division, we get:

1    /    2    0    0    -1

                2     2    2

    ---------------------------

          2     2    2     1

Note that the remainder is 1.  The same result would be obtained through long division.

The quotient is 2x^2 + 2x + 2 with a remainder of 1.  

Answer:

C

Step-by-step explanation:

Using the cosine ratio in the right triangle

cosθ = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{7}{16}[/tex] , then

θ = [tex]cos^{-1}[/tex] ([tex]\frac{7}{16}[/tex] ) ≈ 64° ( to the nearest degree )

Answer:

[tex]C = 36.0[/tex]

[tex]B = 46.2[/tex]

[tex]A = 97.8[/tex]

Step-by-step explanation:

Given

[tex]\triangle ABC[/tex]

[tex]AC = 4.3[/tex]

[tex]BC = 5.9[/tex]

[tex]BA = 3.5[/tex]

Required

List the angles from smallest to largest

The given parameters is illustrated with the attached image.

[tex]AC = 4.3[/tex] -- b

[tex]BC = 5.9[/tex] --- a

[tex]BA = 3.5[/tex] --- c

This question will be solved using cosine rule

To calculate A, we have:

[tex]a^2 = b^2 + c^2 -2bc\ cos(A)[/tex]

So, we have:

[tex]5.9^2 = 4.3^2 + 3.5^2 - 2 * 4.3 * 3.5 * \cos(A)[/tex]

[tex]34.81 = 18.49+ 12.25 - 30.10* \cos(A)[/tex]

Collect like terms

[tex]34.81 - 18.49- 12.25 = - 30.10* \cos(A)[/tex]

[tex]4.07 = - 30.10* \cos(A)[/tex]

Make cos(A) the subject

[tex]\cos(A) = -\frac{4.07}{30.10}[/tex]

[tex]\cos(A) = -0.1352[/tex]

Take arccos of both sides

[tex]A = cos^{-1}(-0.1352)[/tex]

[tex]A = 97.8[/tex]

Solving for B, we have:

[tex]b^2 = a^2 + c^2 -2ac\ cos(B)[/tex]

This gives:

[tex]4.3^2 = 5.9^2 + 3.5^2 -2*5.9*3.5\ cos(B)[/tex]

[tex]18.49 = 34.81+ 12.25 -41.30 *\cos(B)[/tex]

Collect like terms

[tex]18.49 - 34.81 - 12.25 = -41.30 *\cos(B)[/tex]

[tex]-28.57 = -41.30 *\cos(B)[/tex]

Solve for cos(B)

[tex]\cos(B) = \frac{-28.57}{-41.30}[/tex]

[tex]\cos(B) = 0.6918[/tex]

Take arccos of both sides

[tex]B = cos^{-1}(0.6918)[/tex]

[tex]B = 46.2[/tex]

To solve for C, we make use of:

[tex]A + B + C = 180[/tex] --- angles in a triangle

[tex]97.8 + 46.2 + C = 180[/tex]

Collect like terms

[tex]C = - 97.8 - 46.2 + 180[/tex]

[tex]C = 36.0[/tex]

So, we have:

[tex]C = 36.0[/tex]

[tex]B = 46.2[/tex]

[tex]A = 97.8[/tex]

Answer:

-8/7 is your answer

Answer:

64 chickens (40%)

Step-by-step explanation:

16 horses(10%), 32 cows(20%), 48 goats(30%),

Answer:

b

Step-by-step explanation:

Answer:

4,320m

Step-by-step explanation:

Answer:

(x-9)(x-3)

Step-by-step explanation:

I hope it will help you

Answer:

4 and - 2

Step-by-step explanation:

f ( x ) = x^2 - 2x - 3

f ( x ) = 5

x^2 - 2x - 3 = 5

x^2 - 2x - 3 - 5 = 0

x^2 - 2x - 8 = 0

x^2 + 2x - 4x - 8 = 0

x ( x + 2 ) - 4 ( x + 2 ) = 0

( x - 4 ) ( x + 2 ) = 0

x - 4 = 0

x = 4

x + 2 = 0

x = - 2

x has 2 values,

x = 4, - 2

Answer:

8:00

Step-by-step explanation:

Answer:

13,188

Step-by-step explanation:

you have to times 4.2 by the C which is 4.14 adn that give you your anwser

Answer:

we need more info hun.

Step-by-step explanation:

Answer:

x = 43

Step-by-step explanation:

First, make the equation which is

x + 49 + 88 = 180

Next, add 49 + 88 which is 137

Now you have x + 137 = 180

Subtract 137 from both sides and you get your final answer:

x =43

Answer: The answer would be  C, I hope this isnt wrong so sorry if it is.

Step-by-step explanation:

Answer:

here it is

Step-by-step explanation:

if u have any question tell me

Answer:

[tex] \infty \infty \infty \infty \infty [/tex]