Superman used x-ray vision to detect objects. aside from detection of x-rays, what else would be needed for x-ray vision?

The angle of refraction in the glass is 30°.

i= 50°

u= 1.50

u1sini=u2sinr

⇒sinr =[tex]\frac{sin 50}{1.5\\}[/tex]

=0.50=1/2

so angle r = [tex]sin^{-1}[/tex](0.5) =30°

Then we have to calculate r final.

[tex]u_{glass}[/tex]sini= [tex]u_{air}[/tex] sinr

⇒ r = [tex]sin^{-1}[/tex] (1.5 x [tex]\frac{\sqrt{3} }{2}[/tex])

[tex]sin^{-1}[/tex](1.29) = 0.0225

Then the displacement can be calculated as follows:

T= thickness = 5cm

s= t (1- 1/u)

s= 2cm

Thus, all the values have been found out.

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The correct answer is :

According to classical electrodynamics, light energy is a wave that is absorbed by atoms in a manner similar to how an object absorbs radiant heat. So, the atoms of a metal would absorb more energy the brighter the light was. It would be feasible for an electron in a metal to break free from its atoms if it received enough energy from the incoming wave. The more energy absorbed, the more energetic the metal's released electrons would be. Additionally, no electrons could conceivably be ejected until each atom had enough light energy. Light intensity was far more important than light frequency.

In many respects, the photo-electric effect contradicted this strategy:

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A third positive charge [tex]x = \frac{2\sqrt{2}a }{1+\sqrt{2} }[/tex] can be placed on the x-axis so that the net electric force on it is zero.

whilst -factor charges are in touch, there may be

[tex]F = k \frac{q_{1}q_{2} }{ r^{2} }[/tex]

Where

[tex]k = 9 * 10^{9} Nm^{2}C^{-1}[/tex] = the coulomb constant.

The charges' magnitudes are [tex]q_{1}[/tex] and [tex]q_{2}[/tex].

r is the separation of the charges.

Let,

The third charge equals Q at, x equals x from the source.

because there is no net force acting on the third charge.

Hence,

[tex]f_{1} + f_{2} = 0[/tex]

⇒ [tex]k\frac{(2q)Q}{x^{2} }-k\frac{qQ}{(2a-x)^{2} } = 0[/tex]

⇒ [tex]\frac{2}{x^{2} } - \frac{1}{(2a-x)^{2} } = 0[/tex]

⇒ [tex]\frac{2}{x^{2} } = \frac{1}{(2a-x)^{2} }[/tex]

⇒ [tex]\frac{\sqrt{2} }{x} = \frac{1}{2a-x}[/tex]

⇒ [tex]2\sqrt{2}a - \sqrt{2} = x[/tex]

⇒ [tex]x = \frac{2\sqrt{2}a }{1+\sqrt{2} }[/tex]

handiest when forces resulting from previous prices cancel every different out will the pressure on a third fee be 0.

at the same time as the pressure between  identical costs is repulsive and is interpreted as high-quality, the pressure between two opposing expenses is attracted and is interpreted as bad.

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Once the object is dropped ,The only force acting on it is gravity.so acceleration due to gravity is 9.8 m/[tex]s^{2}[/tex].

Given,

Initial velocity = u = 0

Time taken = t = 0

Acceleration = g = 9.8 m/[tex]s^{2}[/tex]

Using [tex]3^{rd}[/tex] equation of motion ,

v = u + at

v =( 0 )+ (9.8) *(3)

v = 29.4

v≈ 30 m/s

So, the speed of object is 30 m/s.

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The upper cutoff accelerometer is made with a crystal of natural frequency of the accelerometer is 7.334 KHz.

An accelerometer is a tool that precisely measures acceleration. Proper acceleration is the acceleration of a body in its own instantaneous rest frame, as opposed to coordinate acceleration, which is acceleration in a fixed coordinate system.

Accelerometers are devices that measure the acceleration or vibration of a structure. They have a transducer that converts mechanical force caused by vibration or a change in motion into an electrical current by using the piezoelectric effect.

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Short focal length lens makes the background and foreground appear closer together.

Short focal length lenses are sometimes known as wide-angle or wide-field lenses, which accurately defines their key characteristic—they view a larger angle of a scene than is typical.

When your eyes are fixed in one place and you look at a scene, a lens with a typical focal length captures what you see.

The angle of view is narrower, and the magnification is higher the longer the focal length.

A shorter focal length results in a wider angle of view and a lower magnification.

Because they provide a broad field of view, short focal length lenses are frequently utilized in architectural, documentary, and landscape photography. These telephoto lenses enable

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Answer:

change in speed) / (time for the change)

              and the direction of the change.

Acceleration  =  (60 - 0) km per hour / 5 sec  =  12 km per hour per second, east.

I hear teachers all over the country complaining about that ugly unit.

It has to be changed to a more familiar unit of acceleration.

(12 km/hour) x (1 hour/3600sec) = 12,000/3600 = 3-1/3 meter/sec.

His acceleration is  3-1/3 meters per second² .

Explanation:

a

Answer:

u=0

v=60 km/ hr

60 \times 1000 \\ 60 \times 60 = 1800

t =5

t = 5 \times3600 = 18000

a= ?

a = v - u \div t

= 1800 - 0 \div 18000 \\

1m/s^2\: ans

Jorge was driving at 20m/s. He accelerated at a rate of 2m/s² for 10s.

So he travel ---m during this time.

Jorge was driving at 20m/s, so speed = 20 units

He accelerated at a rate of 2m/s² so acceleration = 2 units

Time taken by Jorge is 10 units.

We know by Newton's 2nd equation of motion that

S= ut + (1/2)*a*t*t

where S is distance, a is acceleration, u is initial velocity and t is time.

So S=?

Time t = 10

Acceleration a =2

Initial Velocity u = 20

Hence distance travelled by Jorge is S=300 m

Thus Jorge travelled 300m during this time  at speed 20m/s accelerated at a rate of 2m/s² for 10s.

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Answer:

11,907 m is the maximum height ymax reached by the rocket.

Explanation:

The equations which relate displacement, velocity, acceleration and time are known as Equation of Kinematics. In this problem we use second and third equation of kinematics solve,

s = vit+1/2at2

V2f − V2i=2as

It is important to note from the information provided in the question

Acceleration in the first phase a1=49.0m/s2

Time for acceleration t=9.00s

Acceleration in the second phase a2=−9.8 ms-2

Height reached in first phase

y1=vit+1/2a1t2

y1 =0ms-1 × 9.00s + 12×49.0 ms-2 × (9.00s)2

=1984.5m

velocity at the end of first phase

v1=49.0 ms-2 × 9.00s

=441m/s

Now height reached in the second phase

V2f − V21 = 2a2y2

At maximum height final velocity is zero.

=02−(441.0m/s)2

=2(−9.80 ms-2) y2

y2=(0-(441.0 ms-2))/(2×(-9.80ms-2))

=9922.5m

So, the maximum height ymax reached by the rocket

ymax = y1+y2

ymax  =1984.5m+9922.5m

=11907m

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An object has a 2 c charge. the object breaks into two pieces. one piece has a charge of -5 c is 7

Charge is the traveling longitudinal wave energy. Mass and charge are the indeed related and can be simplified to a single energy equation. To relate mass and charge, Coulombs can be explained as the wave amplitude, which is measured as a distance (meters).  If one assumes a substance in vacuum of space that has a physical property of kilograms, and moves as waves, then mass and charge can be described as their motion.  In EWT, this substance is referred to as the ether and its components as granules.

Let's call Q the initial charge of object, which is:

Q=2c

When it breaks, two pieces will have charge  and , and since the total charge must be conserved, the sum of these two charges must be equal to the initial charge of the object:

Q=Q1+Q2

We also know charge of one of the two pieces:

Q1=-5

So, by substituting Q and Q1 into the equation, we can find charge of the second piece, Q2:

Q2=Q-Q1=2-(-5)=+7

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The Grand Canyon is 884 m deep from the spot where I heard the echo

The formula for uniformly rectilinear motion (URM) and procedure we will use to solve this exercise is:

v = x /t

Where:

Information about the problem:

Notice that the echo is a sound that is produced when its wave hits an object (Grand Canyon) and returns to the place where it was emitted (person), that is to say that to calculate the time in which the echo arrived effectively to the bottom of the canyon we must divide it by 2.

t(canyon's bottom) = t(echo)/2

t(canyon's bottom)  = 5.2 s/2

t(canyon's bottom)  = 2.6 s

Applying the velocity formula, and isolating the distance, we get:

v = x /t(canyon's bottom)

x = v * t(canyon's bottom)

x = 340 m/s * 2.6 s

x = 884 m

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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A ball hits a wall going 10 m/s, and bounces off going 8 m/s. the coefficient of restitution is

Given that

To find

So according the question

We have

                       u = 10 m/s.

                      v = 7 m/s.

Now, We have to find the coefficient of restitution

We know that,

         [tex]n = \frac{velocity \;\;of \; \;separation}{velocity \;of \;approach}[/tex]

So,

             [tex]n = \frac{8}{10}[/tex]

              n = 0.8

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a system is a collection of particles or interacting parts that is regarded as a unique physical entity for the purposes of study.

It is an entity that has a physical existence. An entity is something that exists in itself, real or potential, concrete or abstract, physical or not. It does not have to be of material existence. In particular, legal abstractions and fictions are generally considered entities. Also, in general, an entity is not considered animate. The word entitative is the adjective form of the nominal entity. Something entity is considered for itself. In philosophy, ontology consists in recognizing entities. The words ontic and entity derive from the present participles of ancient Greek and Latin, respectively, meaning being.

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Answer:

d = 102 m

Explanation:

distance = 36 m + 44 m + 22 m

Distance = 102 m

A position-time graph shows how far an object has traveled from its starting position at any given time since it started moving.

The graph on which the immediate function x of a particle is plotted at the y-axis and the time t on the x-axis is called the position-time graph.

The distinction between them is that the velocity-time graph famous the speed of an item and whether it's miles slowing down or dashing up, whilst the position-time graph describes the motion of an item over a period of time.

Position-time graph and displacement-time graph is same. but each are different from distance-time graph. role-time graph and displacement-time graph may be bad. Distance-time graph can by no means be negative.

The shapes of the position-time graph for these  basic varieties of motion - consistent pace movement and multiplied movement i.e., converting speed - monitor an vital precept. The precept is that the slope of the road on a position-time graph well-known shows beneficial statistics about the speed of the item.

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The correct answer is 1.575 A.

a)

From Transformer turns ration

N_s/N_p =V_s/V_p

=>N_p =N_s × (V_p/V_s) =100 × (1.6 × 10^4/120)

N_P=1.33 × 10^4 Turns

b)

P_out =P_in

V_sI_s =V_PI_P

210 × 120 =(1.6 × 10^4)I_p

I_p=1.575 A

What is the working principle of an electric generator?

The generator is composed of a coil with many copper wires coiled around an iron core that is rectangular in shape. The armature is the term for this coil. This armature's purpose is to boost the magnetic flux. The armature revolves between two powerful permanent magnets that have been set. Here, the magnetic lines that are created are orthogonal to the axis of the armature. Two slip rings are further attached to the armature's arms. Two metallic brushes are also linked to the slip rings, which aid in moving current from the armature to the slip rings. These rings are employed for creating moveable contact. Last but not least, the current flows via a load resistance that is wired in parallel with and across the two slip rings.

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126 J work input is required in each cycle .

Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.

Mathematically, the above statement is expressed as follows:

W = (F cos θ) d = F. d

Where,

W is the work done by the force.

F is the force, d is the displacement caused by force

θ is the angle between the force vector and the displacement vector

The dimension of work is the same as that of energy and is given as, [ML2T–2].

Given,

refrigerator absorbs 230 J of heat from the freezer

expels 356 J of heat to the room

work input is required in each cycle =  356 - 230

=  126 J.

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The momentum of both the engaged animals—a bird and its prey—is conserved.

What does linear momentum conservation mean?

If there is no external force acting on the colliding objects, the total momentum before and after the collision will be the same, according to the conservation of momentum principle.

Initial momentum is the same as final momentum.

As a result, both the engaged animals—a bird and its prey—keep their momentum.

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The resultant of these two vectors is 19 units of two vectors, one with a magnitude of 14 units and one with a magnitude of 5 units, are both pointing east.

Explanation

As we know R = A + B

where is R resultant A and B are vectors is possible only if the both the vectors are in the same direction.

Therefore, R = 14 + 5

                     19 units

A resultant force is the single force and corresponding torque that are created when a system of forces and torques acting on a rigid body is added together using vectors in physics and engineering. A consequent force, also known as a resultant force-torque, is one that acts on a rigid body in the same way as the initial system of forces.

Through computational analysis or (in the case of sufficiently simple systems) a free body diagram, the resultant force on a body is calculated and visualized.

The resultant force's location of application defines the torque it produces. Some people use the term resultant force-torque to describe the forces and torques acting on a rigid body; the word resultant force should be understood to include both.

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The muzzle velocity of the bullet is 510.3 m/s.

The projectile's speed when it exits the gun's muzzle is known as muzzle velocity.

The quality (burn speed, expansion) and quantity of the propellant, the mass of the projectile, and the length of the barrel all affect the muzzle velocity of conventional firearms. While a slower burning propellant can use a heavier projectile, it requires a longer barrel to burn completely.

Apply the kinematics equation,

v=u+at

Here v is the final velocity, u is the initial velocity, a is the acceleration and t is the time interval during which a body is under acceleration.

The muzzle velocity of a bullet is the velocity with which the bullet leaves contact with the barrel of the gun.

The muzzle velocity or the final velocity of the bullet will be

v=u+at

v=0+(6.3×[tex]10^{5}[/tex])(8.1×[tex]10^{-4}[/tex])
=50.3 m/s

Therefore, the muzzle velocity of the bullet is 510.3 m/s.

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By applying the specified constant pressure, the system's work done to reduce its volume from start to final is 32 l atm.

Initial volume v1 = 17.0  l

final volume v2 = 9.0 l

Pressure P= 4.0 atm

When a gas expands, there is an amount of work that is done that is equal to the product of the gas's pressure and its volume change.

We apply the formula for work done by gas against a constant external pressure.

expression: Work done = -(P. d V)

Therefore substituting the values :

Work done = - P (v2 - v1)

= - 4.0 x (-8.0) l atm

= 32 l atm.

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The magnitude of the resultant velocity of the soccer ball is: 25.059 m/s

The formula for projectile motion that we will use to solve this exercise is:

vf= √[v(x)² + v(y)²]

Where:

Information about the problem:

Applying the final velocity formula we have:

vf= √[v(x)² + v(y)²]

vf= √[(22 m/s)² + (12 m/s)²]

vf= √[484 m²/s² + 144 m²/s²]

vf= √[628 m²/s²]

vf= 25.059 m/s

The projectile motion is the motion whose trajectory describes a parabola having a horizontal and a vertical component of motion.

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If you walk 3 km due east, then 2.5 km due south, then 11 km due west, then you are 9.34 km far from the starting point.

If you connect all the paths, it will make a triangle. If you join your current position with the start position, then you get the triangle ADE.

This question can be solved by using the application of Pythagoras theorem.

This theorem states that in a right-angled triangle, square of longest side is equal to the sum of the individual squares of the other two sides

Here, AD is the same as BC = 2.5km

and then EC = 11km and DC = AB = 3km

ED= EC-DC = 9 km

In the triangle ADE, according to Pythagoras theorem,

AE^2 = AD^2 + ED^2

so, AE = sqrt (9^2 + 2.5^2)

⇒ AE= sqrt (81 + 6.25)

⇒ AE = 9.34 km

Thus, you are about 9.34 km distance from your start point.

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v^2 = k am sn,

where k is a dimensionless constant.

we have to tell the whether it is dimensional or dimensionless

v = m/sec  dimesions

a = m/sec^2  dimesion,  m = m

v^2  =  m^2 / sec^2 = k  m/sec^2 * m

k =  dimesionless constant.

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The distance between the stations is 1320 m

We'll begin by calculating the distance travelled by the train in the first 20 s. This can be obtained as follow:

s = ut + ½at²

s = (0 × 20) + (½ × 1.1 × 20²)

s = 0 + 220

s = 220 m

The distance between the stations can be obtained as illustrated below:

Total distance = 220 + 110

Total distance = 1320

Thus, the distance between both stations is 1320 m

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The simple solution is to count all the integers that only have odd digits and subtract them from 900. Final solution: 900 – 125 = 775.

Odd and even numbers have opposite parities, therefore 13 is an example of an odd number. In particular, zero has an even parity. The parity of any pair of consecutive integers is opposite. The last digit of an integer stated in the decimal numeral system determines whether the value is even or odd. That example, an odd number is one where the last digit is one, three, five, seven, or nine; otherwise, an even number is one where the last digit is one, two, four, six, or eight.

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Gravity helps to widen the valley of the Colorado River through the Grand Canyon through the forces which increases the pressure thereby leading to it being eroded.

This is referred to as the force of attraction which occurs on objects which draws them toward the center of the planet.

Gravity acts downwards on all bodies on earth which is why the Colorado River erodes downward. This then results in the movement of materials from high to low areas.

This the leads to the continual widening of the valley of the Colorado River through the Grand Canyon and is therefore referred to as the most appropriate answer.

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A hockey player is standing on his skates on a frozen pond, if he accelerates uniformly at 0.22 m/s2, the player will catch his opponent in 19.49 seconds.

Uniform Motion

The object's uniform motion should follow the following rules as provided

vt = vo + at

vt² = vo² + 2a . s

s = vo*t + 1/2*a*t²

Here vt is seen as the final velocity, vo = initial velocity

a= acceleration t= time and s= displacemnt

according to the question,

v = 2

t= 1.4

vo= 0 m/s

a = 0.22 m/s²

The distance between the players is seen as

Vt= 2x 1.4 = 2.8 m

The player will thus catch his opponent with the same distance. This means,

Sopponent = Splayer

so + vt = vo*t + 1/2 at²

⇒ 2.8 + 2.t = 0 . t + 1/2 . 0.22 . t²

⇒ 0.11t² - 2t - 2.8 = 0

⇒ t = 19.49 s

on solving the above quadratic equation, we calculate the possible root as 19.49 seconds.

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Answer: 6 km

works on odyseyware

The answer would be  is 6 km

The time taken for the boat to reach the dock is 2.19 s

From the question given above, the following data were obtained:

The time taken for the boat to reach the dock can be obtained as illustrated below:

s = ut + ½at²

12 = (0 × t) + (½ × 5 × t²)

12 = 0 + 2.5t²

12 = 2.5t²

Divide both side by 2.5

t² = 12 / 2.5

Take the square root of both side

t = √(12 / 2.5)

t = 2.19 s

Thus, the time taken is 2.19 s

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