Answer:
a. 0.5413
b. 20
c. 0.3724
d. 4.4721
Step-by-step explanation:
Solution:-
- We will start by defining a random variable X.
X : The number of support requests arrived
- The event defined by the random variable ( X ) is assumed to follow Poisson distribution. This means the number of request in two distinct time intervals are independent from one another. Also the probability of success is linear within a time interval.
- The time interval is basically the time required for a poisson event to occur. Consequently, each distributions is defined by its parameter(s).
- Poisson distribution is defined by " Rate at which the event occurs " - ( λ ). So in our case the rate at which a support request arrives in a defined time interval. We define our distributions as follows:
X ~ Po ( λ )
Where, λ = 1 / 30 mins
Hence,
X ~ Po ( 1/30 )
a)
- We see that the time interval for events has been expanded from 30 minutes to 1 hour. However, the rate ( λ ) is given per 30 mins. In such cases we utilize the second property of Poisson distribution i.e the probability of occurrence is proportional within a time interval. Then we scale the given rate to a larger time interval as follows:
λ* = [tex]\frac{1}{\frac{1}{2} hr} = \frac{2}{1hr}[/tex]
- We redefine our distribution as follows:
X ~ Po ( 2/1 hr )
- Next we utilize the probability density function for poisson process and accumulate the probability for 2 to 4 request in an hour.
[tex]P ( X = x ) = \frac{e^-^l^a^m^b^d^a . lambda^x}{x!}[/tex]
- The required probability is:
[tex]P ( 2 \leq X \leq 4 ) = P ( X = 2 ) + P ( X = 3 ) + P ( X = 4 )\\\\P ( 2 \leq X \leq 4 ) = \frac{e^-^2 . 2^2}{2!} + \frac{e^-^2 . 2^3}{3!} + \frac{e^-^2 . 2^4}{4!}\\\\P ( 2 \leq X \leq 4 ) = 0.27067 + 0.18044 + 0.09022\\\\P ( 2 \leq X \leq 4 ) = 0.5413[/tex] Answer
b)
We will repeat the process we did in the previous part and scale the poisson parameter ( λ ) to a 10 hour work interval as follows:
λ* = [tex]\frac{2}{1 hr} * \frac{10}{10} = \frac{20}{10 hr}[/tex]
- The expected value of the poisson distribution is given as:
E ( X ) = λ
Hence,
E ( X ) = 20 (10 hour work day) .... Answer
c)
- We redefine our distribution as follows:
X ~ Po ( 20/10 hr )
- Next we utilize the probability density function for poisson process and accumulate the probability for 20 to 24 request in an 10 hour work day.
[tex]P ( X = x ) = \frac{e^-^l^a^m^b^d^a . lambda^x}{x!}[/tex]
- The required probability is:
[tex]P ( 20 \leq X \leq 24 ) = P ( X = 20 ) + P ( X = 21 ) + P ( X = 22 )+P ( X = 23 ) + P ( X = 24 )\\\\P ( 20 \leq X \leq 24 ) = \frac{e^-^2^0 . 20^2^0}{20!} + \frac{e^-^2^0 . 20^2^1}{21!} + \frac{e^-^2^0 . 20^2^2}{22!} + \frac{e^-^2^0 . 20^2^3}{23!} + \frac{e^-^2^0 . 20^2^4}{24!} \\\\P ( 20 \leq X \leq 24 ) = 0.0883 +0.08460 +0.07691 +0.06688+0.05573\\\\P ( 20 \leq X \leq 24 ) = 0.3724[/tex] Answer
c)
The standard deviation of the poisson process is determined from the application of Poisson Limit theorem. I.e Normal approximation of Poisson distribution. The results are:
σ = √λ
σ = √20
σ = 4.4721 ... Answer
Bill and Ben each have three cards numbered 4,5,6 they each take one of their own cards then they add the two numbers on the cards what is the probability that their answer is an odd number. What is the probability that their answer is a number less than 11.
Answer:
P(odd) = 4/9P(<11) = 2/3Step-by-step explanation:
There are 9 possible outcomes for (Bill, Ben)'s cards:
(4, 4) total 8; (4, 5) total 9; (4, 6) total 10;
(5, 4) total 9; (5, 5) total 10; (5, 6) total 11;
(6, 4) total 10; (6, 5) total 11; (6, 6) total 12.
Of these 9 outcomes, 4 have an odd total; 6 are less than 11.
P(odd) = 4/9
P(sum < 11) = 2/3
If y = x2 + 2x , find the value of y when x = 3
and
If y = x3 - 3 , find the value of y when x = 2 plsss help me
Answer:
y=15; y=5
Step-by-step explanation:
y=x2+2x
plug in x as 3:
y=3 2+ 2*3
y=9+6
y=15
Next problem:
y=x3-3
plug in x as 2:
y=2 3-3
y=8-3
y=5
Suppose Z has a standard normal distribution with a mean of 0 and standard deviation of 1. 27% of the possible Z values are greater than _____________.
Answer:
27% of the possible Z values are greater than 0.613
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 0, \sigma = 1[/tex]
27% of the possible Z values are greater than
The 100 - 27 = 73rd percentile, which is X when Z has a pvalue of 0.73. So X when the z-score is 0.613.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]0.613 = \frac{X - 0}{1}[/tex]
[tex]X = 0.613[/tex]
27% of the possible Z values are greater than 0.613
Write a pair of integers whose sum is- -8
Answer:
-3+(-5)
Checking our answer:
Adding this does indeed give -8
Which is greater 36÷(4×3) or 54-48-(16÷4
Step-by-step explanation:
36 ÷ (4 x 3)
36 ÷ 12
= 3
54 - 48 - (16 ÷ 4)
54 - 48 - 4
= 2
So first one is greater
WILL GIVE BRAINLIEST TO ANSWER:)) <33
Q: A committee of six people is to be formed from a pool of six grade 11 students and seven grade 12 students. Determine the probability that the committee will have two grade 11 students.
Answer: 5/26
Step-by-step explanation: 6/13 x 5/12
Suppose Gabe, an elementary school student, has just finished dinner with his mother, Judy. Eyeing the nearby cookie jar, Gabe asks his mother if he can have a cookie for dessert. She tells Gabe that she needs to check his backpack to make sure k. Gabe cannot remember where he left his backpack, but he knows for sure that he did not complete his bomework and will not be alowed to cat a cookie. Gabe believes his only option is to quickly steal a cookie while his mother is out of the room. Judy then leanves the room to look for Gabe's backpack. Assome that Judy could return at any time in the next 90 seconds with equal probability, For the first 40 seconds, Gabe sheepishly wonders if he will get caught rying to grab a nearby cookie. After waiting and not secing his mother, Gabe decides that he needs a cookie and begins to take one from the jar Assuming it takes Gabe 30 seconds to grab a cookie from the jar and devour it without a trace, what is the probability that his mother returns in time to catch Gabe stealing a cookie?
Answer:
0.56
Step-by-step explanation:
What is the probability that his mother returns just in time to catch Gabe stealing a cookie?
The probability of this is the same as 1 minus the probability that Gabe is NOT caught.
- Judy could return at anytime in the next 90 seconds
- Gabe spends the first 40 seconds pondering... time wasted=40secs
- It takes 30 seconds (out of the remaining 50secs) to finish eating a cookie without a trace
- The question says that Gabe was going to do it, so he probably did
Now we're looking for the probability that he gets caught. That is, probability that he does not "successfully" complete the 30secs task within the remaining 50secs.
Remember that each second has an equal probability of being the second that Judy comes back in. The latter of the 90 seconds does not carry a higher probability!
So the probability of catching Gabe (despite the 30secs it takes to complete his task) is 50/90 which is equal to 0.56
4) A large number of people were polled and asked which of four different animals were their
favorite. 13% said Penguin, 21% said Iguana, 22% said Parrot, and 44% said Turtle. Suppose you
decide to carry out a simulation given these percentages. You decide to select two digits at a
time. Which would be a proper assignment of digits for these teams?
a) 01-13 = Penguin, 01-21 = Iguana, 01-22 = Parrot, 01-44 = Turtle
b) 00-13 = Penguin, 14-34 = Iguana, 35-56 = Parrot, 57-99 = Turtle
c) 01-13 = Penguin, 14-35 = Iguana, 36-58 = Parrot, 59-99 & 00 = Turtle
d) 01-13 = Penguin, 14-34 = Iguana, 35-56 = Parrot, 57-99 & 00 = Turtle
e) None of these
Answer:
d) 01-13 = Penguin, 14-34 = Iguana, 35-56 = Parrot, 57-99 & 00 = Turtle
Step-by-step explanation:
13 − 01 + 1 = 13
34 − 14 + 1 = 21
56 − 35 + 1 = 22
99 − 57 + 1 + 1 = 44
Below you are given a partial computer output from a multiple regression analysis based on a sample of 16 observations.
Coefficients Standard Error
Constant 12.924 4.425
x1 -3.682 2.630
x2 45.216 12.560
Analysis of Variance
Source of Degrees of Sum of Mean
Variation Freedom Squares Square F
Regression 4853 2426.5
Error 485.3
We want to test whether the variable x1 is significant. The critical value obtained from ttable at the 1% level is:_______.
1. ±2.650.
2. ±2.921.
3. ± 2.977.
4. ± 3.012.
Answer:
4. ± 3.012
Step-by-step explanation:
Hello!
Assuming that for both variables X₁ and X₂ n₁= n₂ = 16
You need to test at 1% if the variable is significant, this means, if the slope for X₁ is different from zero (β₁≠0) using the t-statistic and the critical value approach.
The hypotheses are:
H₀: β₁= 0
H₁: β₁≠ 0
α: 0.01
[tex]t= \frac{b_1-\beta_1}{Sb_1} ~t_{n_1-3}[/tex]
The degrees of freedom "n₁-3" are determined by the number of parameters that you estimate for the multiple regression, in this case there are three "β₁" "β₂" and "δ²e"
The rejection region for this test is two-tailed, the critical values are:
±[tex]t_{n-3;1-\alpha /2}= t_{13;0.995}= 3.012[/tex]
I hope this helps!
Factor completely 2x⁴y³-12x³y²-8x²y
Lisa drew three circles to form a figure. The areas of the circles were in the
ratio 1:4:16. She then shaded some parts of the figure as shown.
What fraction of the figure was shaded?
Answer:
Fraction of the figure shaded = [tex]\frac{13}{16}[/tex]
Step-by-step explanation:
Ratio of the areas of the given circles are 1 : 4 : 16
Then the radii of the circles will be in the ratio = [tex]\sqrt{1}:\sqrt{4}:\sqrt{16}[/tex]
= 1 : 2 : 4
If the radius of the smallest circle = x units
Then the radius of the middle circle = 2x units
and the radius of the largest circle = 4x units
Area of the smallest circle = πx²
Area of the middle circle = π(2x)² = 4πx²
Area of the largest circle = π(4x)²= 16πx²
Area of the region which is not shaded in the middle circle = πx²(4 - 1)
= 3πx²
Therefore, area of the shaded region = Area of the largest circle - Area of the region which is not shaded
= 16πx² - 3πx²
= 13πx²
Fraction of the figure which is not shaded = [tex]\frac{\text{Area of the shaded region}}{\text{Area of the largest circle}}[/tex]
= [tex]\frac{13\pi x^{2} }{16\pi x^{2} }[/tex]
= [tex]\frac{13}{16}[/tex]
Use synthetic division to solve What is the quotient?
Answer:
[tex]3{x}^{3} + 2x + 5[/tex]
Step-by-step explanation:
Sorry if my notes weren't very clear.
Answer:B
Step-by-step explanation: got it right
Use the counting principle to determine the number of elements in the sample space. Two digits are selected without replacement from the digits 1, 2, 3, and 4.
Answer:
if the order of the digit matters, we have:
options: 1, 2, 3, 4.
We want to select two digits.
First selection: we have 4 options
Second selection: we have 3 options (because we already selected one in the first selection)
The total number of elements in the sample space, or the total number of combinations, is equal to the product of the number of options in each selection, this is:
P = 4*3 = 12
Entertainment Software Association would like to test if the average age of "gamers" (those that routinely play video games) is more than 30 years old. A Type I error would occur if Entertainment Software Association concludes that the average age of gamers is: _______.
A. Equal to 30 years when, in reality, the average age is not equal to 30 years
B. Not equal to 30 years when, in reality, the average age is equal to 30 years
C. Greater than 30 years when, in reality, the average age is 30 years or less
D. 30 years or less when, in reality, the average age is more than 30 years
Answer:
"30 years or less when, in reality, the average age is more than 30 years"
Step-by-step explanation:
Type I error is produced when conclusion rejects a true null hypothesis.
The null hypothesis is
"The average gamer is more than 30 years old"
(deduced from the wording, not explicitly stated).
Then if the conclusion is "the average gamer is less than or equal to 30 years old" when in reality the average age is more than 30 years, then there is a type I error, since the null hypothesis is rejected.
Answer is D:
"30 years or less when, in reality, the average age is more than 30 years"
what is 3 + 3 × 3 + 3 =
Answer:
15
Step-by-step explanation:
PEMDAS
3x3 = 9
3+3 = 6
9+6 = 15
By the BODMAS rule we get, 3 + 3 × 3 + 3 = 15
The acronym BODMAS rule is used to keep track of the right sequence of operations to do when solving mathematical issues. Brackets (B), order of powers or roots (O), division (D), multiplication (M), addition (A), and subtraction (S) are all represented by this acronym (S).
3 + 3 × 3 + 3 =
3 × 3 = 9
3 + 9 + 3 = 15.
Therefore, the correct answer is 15.
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Given the following diagram, are OC and OE opposite rays ?
Answer:
No
Step-by-step explanation:
If they were opposite, they would be equal.
But they are not, (on one of the spaces in between them is smaller and one is larger.)
Hope I have helped you, since it seems I haven't helped "other people" the last time :/
Answer:
No
Step-by-step explanation:
how large of a sample of state employee should be taken if we want to estimate with 98% confidence the mean salary to within 2000 g
The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
How large of a sample of state employees should be taken if we want to estimate with 98% confidence the mean salary to be within $2,000? The population standard deviation is assumed to be $10,500. z-value for 98% confidence level is 2.326.
Answer:
Sample size = n = 150
Step-by-step explanation:
Recall that the margin of error is given by
[tex]$ MoE = z \cdot (\frac{\sigma}{\sqrt{n} } ) $\\\\[/tex]
Re-arranging for the sample size (n)
[tex]$ n = (\frac{z \cdot \sigma }{MoE})^{2} $[/tex]
Where z is the value of z-score corresponding to the 98% confidence level.
Since we want mean salary to be within $2,000, therefore, the margin of error is 2,000.
The z-score for a 98% confidence level is 2.326
So the required sample size is
[tex]n = (\frac{2.326 \cdot 10,500 }{2,000})^{2}\\\\n = (12.212)^{2}\\\\n = 149.13\\\\n = 150[/tex]
Therefore, we need to take a sample size of at least 150 state employees to estimate with 98% confidence the mean salary to be within $2,000.
You are given that sin(A)=−20/29, with A in Quadrant III, and cos(B)=12/13, with B in Quadrant I. Find sin(A+B). Give your answer as a fraction.
Answer:
[tex]sin(A+B)=-\dfrac{345}{377}[/tex]
Step-by-step explanation:
Given that:
[tex]sin(A)=-\dfrac{20}{29}\\cos(B)=\dfrac{12}{13}[/tex]
A is in 3rd quadrant and B is in 1st quadrant.
To find: sin(A+B)
Solution:
We know the Formula:
1. [tex]sin(A+B) = sinAcosB+cosAsinB[/tex]
2. [tex]sin^{2} \theta+cos^{2} \theta=1[/tex]
Now, let us find the values of cosA and sinB.
[tex]sin^{2} A+cos^{2} A=1\\\Rightarrow (\frac{-20}{29})^2+cos^{2} A=1\\\Rightarrow cos^{2} A=1- \dfrac{400}{941}\\\Rightarrow cos^{2} A=\dfrac{941-400}{941}\\\Rightarrow cos^{2} A=\dfrac{441}{941}\\\Rightarrow cos A=\pm \dfrac{21}{29}[/tex]
A is in 3rd quadrant, so cosA will be negative,
[tex]\therefore cos A=-\dfrac{21}{29}[/tex]
[tex]sin^{2} B+cos^{2} B=1\\\Rightarrow sin^{2} A+(\frac{12}{13})^2=1\\\Rightarrow sin^{2} B=1- \dfrac{144}{169}\\\Rightarrow sin^{2} B=\dfrac{169-144}{169}\\\Rightarrow sin^{2} B=\dfrac{25}{169}\\\Rightarrow sinB=\pm \dfrac{5}{13}[/tex]
B is in 1st quadrant, sin B will be positive.
[tex]sinB =\dfrac{5}{13}[/tex]
Now, using the formula:
[tex]sin(A+B) = sinAcosB+cosAsinB\\\Rightarrow -\dfrac{20}{29} \times \dfrac{12}{13}-\dfrac{21}{29}\times \dfrac{5}{13}\\\Rightarrow -\dfrac{20\times 12+21\times 5}{29\times 13} \\\Rightarrow -\dfrac{240+105}{29\times 13} \\\Rightarrow -\dfrac{345}{377}[/tex]
[tex]sin(A+B)=-\dfrac{345}{377}[/tex]
Jane is collecting data for a ball rolling down a hill. She measures out a set of different distances and then proceeds to use a stop watch to find the time it takes the ball to roll. What are the independent, dependent, and control variables in this experiment?
Answer:
Step-by-step explanation:
The independent variables are the input values which are not dependent on the other value.
The dependent variables are the output values whose values depends on the value of some other number.
The independent variable in this case is the data on the set of distances she measured out.
The dependent variable in this case is the the time (measured by the stopwatch) it takes for the ball to roll.
The control variable in this case study is the size of ball, slope of hill, weight of ball etc.
11. What's the approximate area of a segment of a circle with a height 6 m and the length of the chord is 20 m? round to the nearest whole number.
O A. 746 67 m2
O B. 74 6 m2
O C.85 4 m2
O D. 8 54 m2
Answer:
85.4
Step-by-step explanation:
first you have to find the radius before you find the area. so given the height, the radius is 11.3 meters. then, you need to find the area behind the arc, which is 85.4 meters/
Determine f(-1) (3). Use the following table of values
Answer:
-5
Step-by-step explanation:
The value of x that gives f(x) = 3 is -5.
[tex]f^{-1}(3)=-5[/tex]
Dr. Pagels is a mammalogist who studies meadow and common voles. He frequently traps the moles and has noticed what appears to be a preference for a peanut butter-oatmeal mixture by the meadow voles vs apple slices are usually used in traps, where the common voles seem to prefer the apple slices. So he conducted a study where he used a peanut butter-oatmeal mixture in half the traps and the normal apple slices in his remaining traps to see if there was a food preference between the two different voles.
Indicate which of the following is the null hypothesis, and which is the alternate hypothesis.
There food preferences among vole species are independent of one another. _____
There is a relationship between voles and food preference. ______
To test for independence, we need to calculate the Chi-square statistic.
These are the data that Dr. Pagels collected:
meadow voles common voles
apple slices 26 32
peanut butter-oatmeal 35 25
When transferring your answers, make sure you carry them out to AT LEAST SIX SIGNIFICANT FIGURES unless otherwise stated.
_____= expected meadow vole/apple slices
_____= expected common vole/apple slices
_____= expected meadow vole/peanut butter-oatmeal
_____= expected common vole/peanut butter-oatmeal
_____= chi-square value
_____= degrees of freedom (whole number only)
_____= using Statistical Table A (pg 704 of your textbook), what is the chi-square critical value with significance level of alpha=0.05?
_____= will you reject or fail to reject the null hypothesis? (answer either reject or fail to reject)
Answer:
Null hypothesis = H₀ = There food preferences among vole species are independent of one another.
Alternate hypothesis = H₁ = There is a relationship between voles and food preference.
Expected meadow vole/apple slices = 29.983051
Expected common vole/apple slices = 28.016949
Expected meadow vole/peanut butter-oatmeal = 31.016949
Expected common vole/peanut butter-oatmeal = 28.983051
Chi-square value = χ² = 2.154239
Degree of freedom = 1
Critical value = 3.841
χ² < Critical value
We failed to reject H₀
We do not have significant evidence at the given significance level to show that there is a relationship between voles and food preference.
Step-by-step explanation:
He frequently traps the moles and has noticed what appears to be a preference for a peanut butter-oatmeal mixture by the meadow voles vs apple slices are usually used in traps, where the common voles seem to prefer the apple slices.
So he conducted a study where he used a peanut butter-oatmeal mixture in half the traps and the normal apple slices in his remaining traps to see if there was a food preference between the two different voles.
Null hypothesis = H₀ = There food preferences among vole species are independent of one another.
Alternate hypothesis = H₁ = There is a relationship between voles and food preference.
Data collected by Dr. Pagels:
meadow voles common voles Row Total
apple slices 26 32 58
peanut butter-oatmeal 35 25 60
Column Total 61 57 118
Where 118 is the grand total.
The expected number is given by
Expected = (row total)×(column total)/grand total
Expected meadow vole/apple slices = 58×61/118
Expected meadow vole/apple slices = 29.983051
Expected common vole/apple slices = 58×57/118
Expected common vole/apple slices = 28.016949
Expected meadow vole/peanut butter-oatmeal = 60×61/118
Expected meadow vole/peanut butter-oatmeal = 31.016949
Expected common vole/peanut butter-oatmeal = 60×57/118
Expected common vole/peanut butter-oatmeal = 28.983051
The chi-square statistic value is given by
χ² = Σ(Observed - Expected)²/Expected
χ² = (26 - 29.983051)²/29.983051 + (32 - 28.016949)²/28.016949 + (35 - 31.016949)²/31.016949 + (25 - 28.983051)²/28.983051
χ² = 2.154239
The degrees of freedom is given by
DoF = (row - 1)×(col - 1)
For the given case, we have 2 rows and 2 columns
DoF = (2 - 1)×(2 - 1)
DoF = 1
The given level of significance = 0.05
The critical value from the chi-square table at α = 0.05 and DoF = 1 is found to be
Critical value = 3.841
Conclusion:
Reject H₀ If χ² > Critical value
We reject the Null hypothesis If the calculated chi-square value is more than the critical value.
For the given case,
χ² < Critical value
We failed to reject H₀
We do not have significant evidence at the given significance level to show that there is a relationship between voles and food preference.
how many are 4 x 4 ?
If two chords in a circle are congruent, then they are
_____
Answer:
A
Step-by-step explanation:
Two congruent chords in a circle have the same distance from the center.
If two chords in a circle are congruent, then they are the same distance from the center of the circle .
What are the properties of equal chords of a circle?The properties of Equal Chords of a Circle are:
In a circle equal-chords are equidistant from the center.Equal-chords of congruent circles are equidistant from the corresponding centers.In a circle equal chords subtend equal angles at the center.According to the question
If two chords in a circle are congruent, then they are
Now,
By properties of Equal Chords of a Circle
The equal chords will be equal distance from the center of the circle .
Hence, If two chords in a circle are congruent, then they are the same distance from the center of the circle .
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Solve this correctly for brainliest !!!!!! 3(7) + 2 • |7 - 8| - 12
Answer:
3(7) + 2* |7 - 8| - 12 = 11
Step-by-step explanation:
3(7) + 2* |7 - 8| - 12
21 + 2* |-1| - 12
21 + 2* 1 - 12
21 + 2 - 12
23 - 12 = 11
Hope this helps! :)
What is if we divide 8 by 4 multiply by 6 and add 2 then subtract 2 what is the result?
Answer:
its its 12.
Step-by-step explanation:
=8÷4×6+2-2
=2×6+2-2
=12+2-2
=14-2
=12 is answer..
Answer:
12
Step-by-step explanation:
8÷4×6+2-2
=2×6+2-2
=12+2-2
14-2
=12
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean 1261 and a standard deviation of 118. (a) Determine the 30th percentile for the number of chocolate chips in a bag. (b) Determine the number of chocolate chips in a bag that make up the middle 98% of bags. (c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip cookies?
Answer:
(A) 1199.168
(B) 1503.372
(C) 159.17728
Step-by-step explanation:
(A) To determine the 30th percentile for the number of chocolate chips in the bag, we find the z-score for the 30th percentile.
Found using a z-table or z-calculator, the z-score for the 30th percentile is -0.524
The formula for finding X (the number of items in a given percentile) is:
X = M + Z(S.D.)
Where M is the mean, Z is the specific z-score of the sought percentile and S.D. is the standard deviation.
So for the 30th percentile,
X = 1261 + (-0.524)(118)
X = 1261 - 61.832 = 1199.168
(B) The number of chocolate chips that make up the middle 98% of chips in the bag is
X = 1261 + (2.054)(118)
X = 1261 + 242.372 = 1503.372
(C) For normal distributions, Interquartile range is Q3 - Q1, that is; 3rd quartile minus 1st quartile.
This is within 1.34896 standard deviations of the mean.
IQR = (1.34896)(118)
IQR = 159.17728
20 pts! If Quadrilateral J K L M is congruent to quadrilateral C B D A, which pair of sides must be congruent? Segment J K and Segment A B Segment J K and Segment C B Segment J M and Segment A D Segment J M and Segment B C
Answer:
segment I'm and segment ad
Answer:
The answer is B
Step-by-step explanation:
0.3y+ z y 0, point, 3, y, plus, start fraction, y, divided by, z, end fraction when y=10y=10y, equals, 10 and z=5z=5z, equals, 5.
Answer:
5
Step-by-step explanation:
Substitute the given values and do the arithmetic.
[tex]0.3y+\dfrac{y}{z}=0.3\cdot 10+\dfrac{10}{5}=3+2=\boxed{5}[/tex]
find the value of x that makes abcd a parallelogram
The 4 angles need to add to 360.
2 of them are 70
The other two need to equal 360-140 = 220
They are both the same so one angle needs to equal 220/2 = 110
Now find x:
X + 60 = 110
Subtract 60 from both sides:
X = 50. The answer is D