suppose 20% of the students are ill on monday. what fraction or percentage of the students are likely to be ill on tuesday? on wednesday?

To compare the quantitative responses to the two conditions in a paired design, the differences between the response within each pair are used. These paired differences can be compared to the appropriate statistical procedures to determine the significance of the results.

For paired designs, the appropriate statistical procedure is the one-sample t procedure. This procedure is used to compare the mean of the paired differences to a hypothesized value, such as zero. The null hypothesis is that the mean difference is equal to zero, indicating no significant difference between the two conditions. If the calculated t-value is greater than the critical value, the null hypothesis can be rejected, indicating a significant difference between the two conditions.

In cases where the sample size is large and the population standard deviation is known, the two-sample z procedure can also be used. This procedure compares the difference between the means of the two samples to a hypothesized value. However, this procedure is less commonly used for paired designs.

The two-sample t procedure is used for independent designs, where two samples are selected from different populations. This procedure compares the means of the two samples to each other, rather than comparing the paired differences within each sample.

In summary, for paired designs, the appropriate statistical procedure is the one-sample t procedure, while the two-sample z procedures and the two-sample t procedures are used for independent designs.

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there are 4 kind of marble

6 possibilities of different chosing

6+4 = 10

The complete oxidation of linoleic acid (C18H32O2) produces 16 reducing equivalents.

To determine the number of reducing equivalents produced by the complete oxidation of linoleic acid (C18H32O2), we need to follow these steps:

1. Determine the number of hydrogen atoms in linoleic acid: Linoleic acid has the molecular formula C18H32O2, which contains 32 hydrogen atoms.    
     
2. Divide the number of hydrogen atoms by 2: Since 1 mole of electrons is donated by 1 reducing equivalent, and each pair of hydrogen atoms (H2) contributes 2 moles of electrons, we need to divide the number of hydrogen atoms by 2 to find the number of reducing equivalents.

32 hydrogen atoms ÷ 2 = 16 reducing equivalents

So, the complete oxidation of linoleic acid (C18H32O2) produces 16 reducing equivalents.

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It will take approximately 14.4 years for $2,700 to grow to $15,000 at a 6% compound interest rate, compounded semiannually.

A equals the projected value, in this case $15,000.

P is equal to the current value, in this case $2,700.

r = 6%, or 0.06 in decimal form, is the yearly interest rate.

The number n represents the number of times the interest is compounded yearly (because it is compounded twice annually).

t = the duration in years

Using the values we hold in place of:

15000 = 2700(1 + 0.06/2)^(2t)

by 2700, divide both sides.

15000/2700 = (1 + 0.06/2)^(2t)

Simplify:

5.56 = (1.03)^(2t)

Consider both sides' natural logarithms:

ln(5.56) = ln(1.03)^(2t)

Using the logarithm property, ln(ab) = b ln(a),

ln(5.56) = 2t ln(1.03)

Subtract the two sides by 2 ln(1.03):

t = ln(5.56) / (2 ln(1.03))

t ≈ 14.4

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The null hypothesis would be that there is no significant difference between the mean examination score for the new freshman applications and the historical mean of 900. The alternative hypothesis would be that there is a significant difference between the two means.

To determine if the mean examination score for new freshman applications has changed. To do this, you'll need to state your null and alternative hypotheses using the historical mean and given terms.
Step 1: State the null hypothesis (H₀)
The null hypothesis assumes that there is no significant change in the mean examination score for new freshman applications. In this case, the null hypothesis is that the mean remains equal to the historical mean of 900.
H₀: μ = 900
Step 2: State the alternative hypothesis (H₁)
The alternative hypothesis represents a significant change in the mean examination score for new freshman applications. In this case, the alternative hypothesis is that the mean is not equal to the historical mean of 900.
H₁: μ ≠ 900
So, your hypotheses are as follows:
- Null hypothesis (H₀): μ = 900
- Alternative hypothesis (H₁): μ ≠ 900

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The empirical rule (68-95-99.7%) is a widely used guide in statistics that helps determine the probability of occurrence of a raw score in a set of statistical data. This rule, also known as the rule of three sigma.

What is Three-Sigma Rule?

It states that for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, 95% of the data falls within two standard deviations of the mean,on average, 99.7% of the data fall within three standard deviations.

This rule is useful for understanding the distribution of data and can be used to make predictions and draw conclusions about a population based on a sample. Statisticians often rely on this rule when analyzing data and making decisions based on probability calculations.

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The solution is, : y = 1/3x+6, is the equation of a line that is perpendicular to the line y= -3x+2 and passes through the point (6,8).

We know that,

y = -3x+2 is in slope intercept form  y = mx+b  where m is the slope and b is the y intercept

The slope is -3

Perpendicular lines have slopes that are negative reciprocals

The slope of the perpendicular line is  -1/-3 = 1/3

The equation of the new line is

y = 1/3x +b

Using the point that passes through the line ( 6,8) and substituting in for x and y

8 = 1/3(6) +b

8 = 2+b

8-2 =b

6 =b

The equation becomes

y = 1/3x+6.

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To test the null hypothesis that the variance of the first group is twice as big as that of the second group in two independent normal random samples, you can use the F-test. The null hypothesis (H0) would be stated as follows:

[tex]H0: σ1^2 = 2 * σ2^2[/tex]

To conduct the F-test, calculate the F-statistic using the sample variances (s1^2 and s2^2) from both groups:

F = s1^2 / (2 * s2^2)

Next, compare the calculated F-statistic to the critical F-value found in the F-distribution table at a chosen significance level (typically α = 0.05) and degrees of freedom for both groups (n1-1 and n2-1).

If the F-statistic is greater than the critical F-value, you would reject the null hypothesis, concluding that there is significant evidence that the variance of the first group is not twice as big as that of the second group. If the F-statistic is less than or equal to the critical F-value, you would fail to reject the null hypothesis, indicating that there isn't enough evidence to conclude that the variances are different as stated.

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The weight of one green triangle is equal to: D. -2.

In this scenario and exercise, you are required to write a system of equations that represents the balance by using the balance shown in the image attached below and then determine the weight of one green triangle.

Since it is a balance, we can reasonably infer and logically deduce that all of the pink squares (s) and green triangles (t) on the left-hand side must be equal to the all of the parameters (numerical values) on the right-hand side of the balance as follows;

3s + 2t = 5    ......equation 1

2s + 5t = -4    ......equation 2

By solving the system of equations simultaneously using the elimination method and multiplying equation 2 by 3/2, we have:

3s + 2t = 5

3s + 7.5t = -6

(3s - 3s) + (2t - 7.5t) = (5 + 6)

-5.5t = 11

t = -11/5.5

t = -2.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

if the family gives up two nights in the hotel, they could afford d) 5 meals

The family has a budget of $800 for meals and hotel accommodations. If they could afford eight nights in a hotel without buying any meals, we can determine the cost of one night at the hotel. To do this, we can divide the total budget by the number of nights:

$800 / 8 nights = $100 per night

Now, let's consider the scenario where the family gives up two nights in the hotel. This would free up $200 from their budget ($100 per night x 2 nights). We can then use this amount to determine how many meals the family can afford by dividing the available funds by the cost of one meal:

$200 / $40 per meal = 5 meals

Therefore, if the family gives up two nights in the hotel, they could afford 5 meals. The correct answer is d. 5.

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The option that would result in the highest overall cost for the employee is C. Option A has the highest overall cost by $32.50.

Option A:

Monthly premium = $75

Out-of-pocket cost for prescriptions = 0.2 × $1250

Total monthly cost = $75 + $250 = $325

Option B:

Monthly premium = $45

Out-of-pocket cost for first $600 in prescriptions = 25% × $600 = $150

Out-of-pocket cost for prescriptions over $600 = $97.50

Total monthly cost = $29250

he correct option is C.

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The true statements about the populations and land areas are:

The population density of an area is obtained by dividing the population of the city or village by the area or land mass. Population density is defined as the population per unit of land area.

Based on the available information, we can say that the population density of city B is obtained with the ratios of population and density. Also, the calculation of the population densities will show that City B is greater than City C.

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The length of the side p is given as 11.2.

By applying the Law of Sines, we can find the length of any side of the triangle. The law of sines states that for any triangle with sides of lengths a, b, and c opposite angles A, B, and C, respectively.

Mathematically,

sin A / a = sin B / b = sin C / c

In this case, we know the values of sin P and sin R, and the length of side r. We want to find the length of side p. We can set up the equation as follows:

sin P / p = sin R / r

Substituting the given values, we get:

sin P / p = 0.5 / 14

Solving for p, we get:

p = sin P / (0.5 / 14)

p = sin P * 28

p = 0.4 * 28

p = 11.2

Therefore, the length of side p is 11.2.

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The correct order of steps is 1, 2, 3, 4. And the conditional probability that exactly four heads appear when a fair coin is flipped five times, given that the first flip came up tails, is 1/16.

To find the conditional probability that exactly four heads appear when a fair coin is flipped five times, given that the first flip came up tails, we need to follow these steps in order:
1. Identify the total number of possible outcomes when a fair coin is flipped five times, which is 2^5 = 32.
2. Determine the number of outcomes in which the first flip is tails, which is also 16.
3. Out of the 16 outcomes where the first flip is tails, identify the number of outcomes in which exactly four heads appear. There is only one such outcome: THHHH.
4. Calculate the conditional probability by dividing the number of favourable outcomes (i.e. THHHH) by the number of total outcomes given the condition (i.e. the first flip is tails), which is 1/16.
Therefore, the correct order of steps is 1, 2, 3, 4. And the conditional probability that exactly four heads appear when a fair coin is flipped five times, given that the first flip came up tails, is 1/16.

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Answer:

243π

Step-by-step explanation:

Area of the entire circle = πr² = π18² = 324π

Area of sector = (90/360)π(18)² = 81π

Shaded area = 324π - 81π = 243π

The expression using the greatest common factor is 6x²(x⁸ - 16).

The complete factored form of the expression is 6x²(x⁴ + 4)(x² + 2)(x² - 2).

The greatest common factor of function 6x¹⁰ - 96x², is 6x².

6x¹⁰ - 96x² = 6x²(x⁸ - 16)

The complete factorization of the expression is calculated as follows;

expand the function x⁸ - 16;

x⁸ - 16 = (x⁴ + 4)(x⁴ - 4)

We can also simplify the function x⁴ - 4 further as shown below;

x⁴ - 4 = (x² + 2)(x² - 2)

The complete factored form of the function 6x¹⁰ - 96x² is calculated as;

6x¹⁰ - 96x²  = 6x²(x⁴ + 4)(x² + 2)(x² - 2)

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The amount for each category is given as:

Initially, we must determine how much of each crop is present:

By now, we are able to construct the circle graph by knowing that a circle comprises of 360 degrees, assorted degrees can aid us in identifying every classification of crops:

To find out the amount for each category, we need to compute each percentage share:

Given this information, we can proceed and develop the circle graph.

Make use of a clean and circular diagram and divide it into three proportional parts using their corresponding degree values, then label every section with its matching crop name alongside the respective percentage owned.

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The farmer has the following distribution of crops:

Corn - 40%

Wheat - 35%

Cotton - 25%

A farmer uses his land to grow soybeans, corn, wheat, and cotton. He has a total of 500 crops consisting of corn, wheat, and cotton. The distribution of these crops is 40% corn, 35% wheat, and 25% cotton. Sketch a circle graph and label it with percentages.

Answer:

To convert each number to a percentage, we can simply multiply it by 100.

47.5 = 47.5%

64.5 = 64.5%

42 = 42%

54.5 = 54.5%

64.5 = 64.5%

54.5 = 54.5%

54.5 = 54.5%

54.5 = 54.5%

To find the total percentage, we can add up all the percentages and divide by the total number of values. In this case, there are 8 values.

Total percentage = (47.5 + 64.5 + 42 + 54.5 + 64.5 + 54.5 + 54.5 + 54.5) / 8

Total percentage = 437.5 / 8 = 54.6875%

Therefore, the total percentage of the given numbers is 54.6875%.

Step-by-step explanation:

Answer:

4th option

Step-by-step explanation:

to find the surface you need to find the area of the base square first.

7 in × 7 in = 49 in^2

then find the triangular sides

9 in × 7 in × 1/2 =31.5 in^2

31.5 in^2 × 4 = 126 in^2

so 126in^2 +49in^2 = 175in^2

Consider three random variables, U, V, and W. The answer is E(W) = 2.

To solve for E(W), we need to use the fact that U is equal to both 3V+2 and 5W-23. We can set these two expressions equal to each other:

3V + 2 = 5W - 23

Solving for V in terms of W, we get:

V = (5W - 25) / 3

Now we can use the formula for the expected value of a linear function of a random variable:

E(aX + b) = aE(X) + b

In this case, we have:

V = (5W - 25) / 3

So:

E(V) = E((5W - 25) / 3) = (5/3)E(W) - 25/3

We know that E(V) = -5, so we can substitute that in:

-5 = (5/3)E(W) - 25/3

Solving for E(W), we get:

E(W) = (-5 + 25/3) / (5/3) = 2

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To make wheels of a diameter of 67.5 mm and a width of 29.3 mm, Alfie requires 104891.38 cubic mm volume of plastic.

A cylinder is a 3-Dimensional shape with 3 faces that are one curved face and 2 flat ends. The volume of a cylinder is given by the expression:

V = π[tex]r^2h[/tex]

r is the radius

h is the height

Given, diameter = 67.5 mm

radius = d ÷ 2 = 67.5 ÷ 2

= 33.75 mm

height = width = 29.3 mm

Volume = [tex]\frac{22}{7}*33.75*33.75*29.3[/tex]

= 104891.38 cubic mm

Therefore, the volume of the cylindrical wheel that Alfie designed is 104891.38 cubic mm.

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The value of sin A to the nearest hundredth is,

⇒ sin A = 0.86

We have to given that;

Triangle ABC shown in figure, with sides of lengths,

AB = 11

BC = 9.5

CA = 6

Hence, We get;

sin A = BC / AB

sin A = 9.5 / 11

sin A = 0.86

Thus, The value of sin A to the nearest hundredth is,

⇒ sin A = 0.86

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The surface with the given vector equation is a portion of a cone with the axis along the y-axis and opening angle of 90 degrees.

The surface with the given vector equation r(s, t) = (s sin(9t), s^2, s cos(9t)) is a helicoid. The helicoid is generated by a line segment moving along a helical path while remaining perpendicular to the helix's axis. In this case, the helicoid has a variable height s^2 and is wrapped around the z-axis with a frequency of 9.

Vector equations are used to represent the lines or planes in a three-dimensional framework. The three-dimensional plane requires three coordinates with respect to the three-axis and here the vectors are helpful to easily represent the vector equation of a line or a plane. In a three-dimensional framework the unit vector along the x-axis is ^i, the unit vector along the y-axis is ^j, and the unit vector along the z-axis is ^k.

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Answer:

{(12, 3), (11, 2), (10, 1), (9, 0), (8, 1), (7, 2), (6, 3)}

Step-by-step explanation:

In a function, all x-coordinates must be different.

{(7, 2), (100, 10), (13, –7), (7, 9), (10, 100), (4, –2), (5, 5)}

7 appears twice as an x-coordinate. Not a function.

{(1000, 10), (1000, 12), (1000, 16), (100, 5), (100, 7), (78, 3), (90, 5)}

1000 appears 3 times as an x-coordinate. Not a function.

{(6, 3), (5, 2), (4, 1), (3, 0), (4, –1), (5 ,–2), (6 ,–3)}

4 appears twice as an x-coordinate. Not a function.

{(12, 3), (11, 2), (10, 1), (9, 0), (8, 1), (7, 2), (6, 3)}

All x-coordinates are different. Function.

This sequence does not converge because it does not approach a single value as n goes to infinity. The sequence appears to oscillate between certain values, specifically {1/5, 1/2, 1/6, 1/3, 1/7, 1/4, 1/8, 1/5,...}.

Therefore, the limit does not exist (DNE).
The given sequence is {1/5, 1/2, 1/6, 1/3, 1/7, 1/4, 1/8, 1/5,...}. To determine whether this sequence converges or diverges, let's find a pattern:

The numerators are always 1. To find the pattern in the denominators, we can examine their differences: (5-2), (6-2), (7-3), (8-4), and so on. We observe that the differences are increasing by 1 each time: 3, 4, 4, 4,...

Now let's write down the denominators based on this pattern: 5, 2, 6, 3, 7, 4, 8, 5,... . The denominators repeat after every four terms, which means the sequence is periodic with a period of 4.

A periodic sequence does not have a unique limit because the terms keep oscillating between different values. Therefore, this sequence diverges, and the answer is DNE (does not exist).

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Answer:

3 months

Step-by-step explanation:

To find the amount of months, m, we will have to solve the equation given. If you don't have any experience solving equations, this could be tricky, but hopefully my work below will be helpful.

15m + 35 = 10(m + 5)

15m + 35 = 10m + 50

15m - 10m + 35 = 10m - 10m + 50

5m + 35 = 50

5m + 35 - 35 = 50 - 35

5m = 15

5m/5 = 15/5

m = 3

After 3 months the cost of the gyms will be the same. Let me know if you need more clarification or were confused by my work. :)

Therefore, the correct option is (b) 46 that is the number of students who like Twix and Reese's peanut butter cups only (region D) by principle of inclusion-exclusion, we need to subtract the number of students who like Snickers, as well as the number of students who like all three kinds of candy, from the number of students who like Twix and Reese's peanut butter cups along with one or both of the other kinds of candy.

We can start by using the principle of inclusion-exclusion, which tells us that:

|A ∪ B ∪ C| = |A| + |B| + |C| - |A ∩ B| - |A ∩ C| - |B ∩ C| + |A ∩ B ∩ C|

where |X| denotes the number of elements in set X.

Using the numbers given in the problem, we have:

|A| = 129

|B| = 118

|C| = 145

|A ∩ B| = 22

|B ∩ C| = 54

|A ∩ C| = 55

|A ∩ B ∩ C| = 8

Substituting these values into the formula, we get:

|A ∪ B ∪ C| = 129 + 118 + 145 - 22 - 55 - 54 + 8 = 269

This tells us that 269 students like at least one of the three kinds of chocolate candy.

To find the number of students who like Twix and Reese's peanut butter cups only (region D), we need to subtract the number of students who like Snickers, as well as the number of students who like all three kinds of candy, from the number of students who like Twix and Reese's peanut butter cups along with one or both of the other kinds of candy:

|D| = |B ∩ C| - |A ∩ B ∩ C|

= 54 - 8

= 46

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Answer:

x=63/4

Step-by-step explanation:

let's firstly convert the mixed fractions to improper fractions, then subtract.

[tex]\stackrel{mixed}{9\frac{6}{7}}\implies \cfrac{9\cdot 7+6}{7}\implies \stackrel{improper}{\cfrac{69}{7}}~\hfill \stackrel{mixed}{2\frac{3}{7}} \implies \cfrac{2\cdot 7+3}{7} \implies \stackrel{improper}{\cfrac{17}{7}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{69}{7}~~ - ~~\cfrac{17}{7}\implies \cfrac{69-17}{7}\implies \cfrac{52}{7}\implies 7\frac{3}{7}[/tex]