suppose a chord is 10 units long and 5 units away from the center of the circle. what is the radius?

Answers

Answer 1

The radius of the circle can be determined using the Pythagorean theorem. Since the chord is 5 units away from the center of the circle, a right triangle can be formed where one leg is half the length of the chord (5 units) and the hypotenuse is the radius of the circle. Using the Pythagorean theorem, we can solve for the radius as follows:

r^2 = (10/2)^2 + 5^2

r^2 = 25 + 25

r^2 = 50

r = sqrt(50) = 5sqrt(2) units

Therefore, the radius of the circle is 5sqrt(2) units.

To further explain, the Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides. In this case, the chord is a line segment connecting two points on the circle and is perpendicular to the radius passing through the midpoint of the chord. Since the chord is 10 units long and 5 units away from the center of the circle, the length of one leg of the right triangle is 5 units (half the length of the chord), and the length of the other leg is the radius of the circle. Using the Pythagorean theorem, we can solve for the unknown length of the radius.

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Related Questions

Find the solution to the linear system of differential equations {x' = 11x + 24y y' = -3x - 6y satisfying the initial conditions x(0) = -33 and y(0) = 12. x(t) = y(t) =

Answers

The  solution to the system of differential equations with initial conditions x(0) = -33 and y(0) = 12 is:

x(t) = 15e^(11t), y(t) = -24e^(-2t)

To solve the system of differential equations {x' = 11x + 24y, y' = -3x - 6y}, we can use the method of matrix exponentials. First, we write the system in matrix form:

{{x'}, {y'}} = {{11, 24}, {-3, -6}} {{x}, {y}}

Next, we compute the matrix exponential of the coefficient matrix:

e^(tA) = {{e^(11t), 4e^(11t)}, {-3e^(-2t), e^(-2t)}}

Then, we can use this matrix exponential to find the solution to the system of differential equations:

{{x(t)}, {y(t)}} = e^(tA) {{x(0)}, {y(0)}}

Plugging in the initial conditions x(0) = -33 and y(0) = 12, we get:

{{x(t)}, {y(t)}} = {{-33e^(11t) + 4(12)e^(11t)}, {-3(12)e^(-2t) + 12e^(-2t)}}

Simplifying, we get:

x(t) = -33e^(11t) + 48e^(11t) = 15e^(11t)

y(t) = -36e^(-2t) + 12e^(-2t) = -24e^(-2t)

Therefore, the solution to the system of differential equations with initial conditions x(0) = -33 and y(0) = 12 is:

x(t) = 15e^(11t), y(t) = -24e^(-2t)

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If you roll a fair dice, what is the probability that the number you get is
a.) 5
b.) an odd number
c.) a number greater than 1
d.) a multiple of 4?

Answers

Answer:

a) 1/6

b)1/2

c)5/6

d)1/6

Step-by-step explanation:

because the probability of rolling one number is one in six we can add however many other probabilities

Choose a Strategy. In a single elimination tournament a team plays until it loses. Eight teams play in a tournament. How many games must be played?

Answers

In a single elimination tournament, a team plays until it loses. Therefore, for a tournament with 8 teams, 7 games must be played. The number of games in a single elimination tournament equals the number of teams minus 1.

Hope this helps! Have a great day. :)

2. (02. 01 LC
Factor completely 25x2 - 36

Answers

Factored 25x^2 - 36 as the product of (5x + 6) and (5x - 6). To factor completely 25x^2 - 36, we first note that both 25 and 36 are perfect squares. Specifically, 25 = 5^2 and 36 = 6^2.

Using the difference of squares identity, we can write:

25x^2 - 36 = (5x)^2 - 6^2

Now, we can use the difference of squares formula again to obtain:

25x^2 - 36 = (5x + 6)(5x - 6)

In general, when factoring a quadratic expression of the form ax^2 + bx + c, where a, b, and c are constants, it is helpful to look for common factors or perfect squares first. The difference of squares formula can also be a useful tool in factoring quadratic expressions.

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when a tax is imposed, some of the lost surplus is converted to tax revenue and the rest is:

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When a tax is imposed, some of the lost surplus is converted to tax revenue, while the rest is deadweight loss.

A tax creates a wedge between the price paid by buyers and the price received by sellers, reducing the quantity of goods traded in the market. This reduction in quantity causes a loss in surplus, which is the sum of consumer surplus and producer surplus. However, some of this lost surplus is converted to tax revenue, which is the amount of money collected by the government from the tax. The amount of lost surplus converted to tax revenue depends on the price elasticity of demand and supply in the market. If the demand and supply are relatively inelastic, a larger share of the lost surplus is converted to tax revenue. On the other hand, if the demand and supply are relatively elastic, a smaller share of the lost surplus is converted to tax revenue. The rest of the lost surplus that is not converted to tax revenue is called deadweight loss, which represents the reduction in economic welfare that is not compensated by the tax revenue. Deadweight loss occurs because the tax creates a distortion in the market that reduces the efficient allocation of resources, leading to inefficiencies in production and consumption.


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find the work done by f in moving a particle once counterclockwise around the given curve. f=(x−3y)i (3x−y)j c: the circle (x−5)2 (y−5)2=25

Answers

The work done by f in moving a particle once counterclockwise around the given curve is -15π.

How to find the work done by f in moving the particle once around the given curve counterclockwise?

The problem requires us to calculate the work done by the vector field f along a closed curve C, which is a circle centered at (5,5) with a radius of 5. To do this, we can use the line integral of f along C, which is given by:

∫C f · dr = ∫C (f(x,y) · T) ds

where T is the unit tangent vector to C and ds is the arc length element along C.

To parameterize the curve C, we can use the parametric equations:

x = 5 + 5cos(t)

y = 5 + 5sin(t)

with 0 ≤ t ≤ 2π. Then, the unit tangent vector T is given by:

T = (-sin(t), cos(t))

and the arc length element ds is given by:

ds = √(x'(t)² + y'(t)²) dt = 5 dt

Using these expressions, we can compute the line integral as:

∫C f · dr = ∫C [(x-3y)i + (3x-y)j] · (-sin(t)i + cos(t)j) 5 dt

After some algebraic manipulation, we obtain:

∫C f · dr = -15π

Therefore, the total work done by f in moving the particle once around the given curve counterclockwise is -15π.

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The work done by f in moving a particle once counterclockwise around the given curve is zero.

To find the work done by a vector field f in moving a particle along a curve C, we use the line integral formula. The line integral of a vector field f along a curve C is given by the formula ∫C f · dr, where dr is the differential of the position vector r(t) of the curve C. In this case, the vector field is f = (x - 3y)i + (3x - y)j and the curve is the circle (x - 5)² + (y - 5)² = 25 centered at (5,5) with radius 5. To evaluate the line integral, we need to parameterize the curve. Since the curve is a circle, we can use the parametrization r(t) = 5cos(t)i + 5sin(t)j, where t ranges from 0 to 2π. Then, dr = -5sin(t)dt i + 5cos(t)dt j.

Evaluating the line integral, we get ∫C f · dr = ∫0^2π f(r(t)) · dr/dt dt = ∫0^2π (-15sin²(t) + 15cos²(t))dt = 0. Therefore, the work done by f in moving a particle once counterclockwise around the given curve is zero.

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In a survey of 800 Florida teenagers, 79% said that helping others who are in need will be very important to them as adults. The margin of error is (+/-) 2.9%.

A. Give an interval that is likely to contain the exact percentage of all Florida teenagers who think that helping others who are in need will be very important to them as adults.

The interval is from [ ]% to [ ]%

B. Assume the population of teenagers in Florida id 2.1 million. What is the range of the number of teenagers in Florida who think helping others will be very important to them?

Between [ ] and [ ] teenagers.

Answers

The true percentage of Florida teenagers who value helping others in need lies between 76.1% and 81.9%.we can estimate with 95% confidence that the number of Florida teenagers who value helping others in need is between interval 1,596,900 and 1,722,900.

According to a survey of 800 Florida teenagers, 79% of them said that helping others in need will be very important to them as adults.

However, due to the limitations of a sample survey, this percentage might not be an exact representation of the entire population of Florida teenagers.

To estimate the true percentage of Florida teenagers who value helping others in need, a confidence interval can be used.

The margin of error given in the survey is +/- 2.9%, which means that we can be confident that the true percentage lies within a range of 2.9% above or below the sample percentage of 79%.

To calculate the confidence interval, we need to find the upper and lower bounds of the range. To find the lower bound, we subtract the margin of error from the sample percentage:

Lower bound = 79% - 2.9% = 76.1%

To find the upper bound, we add the margin of error to the sample percentage:

Upper bound = 79% + 2.9% = 81.9%

Therefore, we can say with 95% confidence that the true percentage of Florida teenagers who value helping others in need lies between 76.1% and 81.9%.

If we assume that the population of Florida teenagers is 2.1 million, we can also estimate the range of the number of teenagers who value helping others in need. To do this, we multiply the lower and upper bounds of the confidence interval by the population size:

Lower bound = 76.1% x 2.1 million = 1,596,900 teenagers

Upper bound = 81.9% x 2.1 million = 1,722,900 teenagers

Therefore, we can estimate with 95% confidence that the number of Florida teenagers who value helping others in need is between 1,596,900 and 1,722,900.

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of the following random variables, which have only nonnegative values: z, t, chi-square, f? (select all that apply.)

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Among the random variables you mentioned - z, t, chi-square, and F - the ones that have only nonnegative values are the chi-square and F distributions.

The chi-square (χ²) distribution is a special case of the gamma distribution, and it is used extensively in hypothesis testing and statistical modelling.

It is defined for nonnegative values, as it represents the sum of squared independent standard normal random variables.
The F-distribution, named after statistician Sir Ronald A. Fisher, is another continuous probability distribution that is defined only for nonnegative values. It is commonly used in the analysis of variance (ANOVA) to test the equality of multiple group means or in regression analysis to test the overall significance of a model.
In contrast, both the z (standard normal) and t (Student's t) distributions are defined for values across the entire real number line, including positive, negative, and zero values. The z-distribution is used for hypothesis testing and confidence intervals in situations where the population standard deviation is known, while the t-distribution is used when the population standard deviation is unknown and estimated from the sample data.

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what is the probability that among 4 randomly selected motorists, the officer will find at least one motorist driving more than 5 miles per hour over the speed limit (decimal to the nearest ten-thousandth.)

Answers

Rounded to the nearest ten-thousandth, the probability is 0.9375.

What is probability?

Probability is a branch of mathematics in which the chances of experiments occurring are calculated. It is by means of a probability, for example, that we can know from the chance of getting heads or tails in the launch of a coin to the chance of error in research.

Let's assume that the probability of a randomly selected motorist driving more than 5 miles per hour over the speed limit is p. Then, the probability of a motorist not driving more than 5 miles per hour over the speed limit is 1-p.

The probability of at least one motorist driving more than 5 miles per hour over the speed limit can be found by using the complement rule. That is:

P(at least one motorist driving more than 5 miles per hour over the speed limit) = 1 - P(no motorist driving more than 5 miles per hour over the speed limit)

The probability of no motorist driving more than 5 miles per hour over the speed limit can be found by using the binomial distribution. Since there are 4 motorists and each one has a probability of 1-p of not driving more than 5 miles per hour over the speed limit, the probability is:

P(no motorist driving more than 5 miles per hour over the speed limit) = (1-p)⁴

Therefore, the probability of at least one motorist driving more than 5 miles per hour over the speed limit is:

P(at least one motorist driving more than 5 miles per hour over the speed limit) = 1 - (1-p)⁴

We are not given a specific value for p, so we cannot calculate the probability exactly. However, if we assume that p = 0.5 (i.e., there is a 50-50 chance of a randomly selected motorist driving more than 5 miles per hour over the speed limit), then the probability of at least one motorist driving more than 5 miles per hour over the speed limit is:

P(at least one motorist driving more than 5 miles per hour over the speed limit) = 1 - (1-0.5)⁴ = 0.9375

Rounded to the nearest ten-thousandth, the probability is 0.9375. However, if we assume a different value for p, the probability will be different.

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What is the mean age of the employees to the nearest year?
Responses
A 33
B 35
C 37
D 39

Answers

Answer:The answer is B . 35 . Hope it helps

Step-by-step explanation:Mean: Addition of everything (314) / frequency (9)

It gives you 34.8… rounded to 35

WILL GIVE BRAINLIST TO BEST ANSWER
State if the two triangles are congruent. If they are, state how you know.
3 and 4

Answers

The line in 3 it happens two times so their equal and 4 doesn’t have those line so it’s not congruent

true or false: with a classic update using linear function approximation, we will always converge to some values, but they may not be optimal. why?

Answers

The statement is true. With a classic update using linear function approximation, we will always converge to some values, but they may not be optimal. This is because linear function approximation only allows for a limited representation of the value function, and the approximated function may not capture the true underlying structure of the problem.

Linear function approximation is commonly used in reinforcement learning to estimate the value function. The idea is to approximate the value function using a linear combination of features. During the learning process, the weights of the linear combination are updated using the classic update rule. While this approach is computationally efficient, it can result in suboptimal policies. The reason for this is that the approximated function may not be able to capture the complexity of the problem. This can lead to inaccuracies in the value function estimates, which in turn can result in suboptimal policies. To address this issue, more advanced function approximation methods, such as neural networks, can be used to approximate the value function. These methods can capture more complex relationships in the data and provide more accurate estimates of the value function.

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find an equation for the conic that satisfies the given conditions. ellipse, foci (0, −2), (8, −2), vertex (9, −2)

Answers

The parametric equation for the ellipse with foci (0, −2), (8, −2), and vertex (9, −2) is ((x-9)^2/64) + (y+2)^2/36 = 1.

To find the equation for the ellipse with the given foci and vertex, we can use the standard form of the equation for an ellipse:

((x-h)^2/a^2) + ((y-k)^2/b^2) = 1,

where (h, k) is the center of the ellipse, a is the distance from the center to the vertex, and b is the distance from the center to the co-vertex. Since the foci are on the x-axis, the center of the ellipse is at (c, −2), where c is the distance from the center to a focus. Using the distance formula, we have:

c = √(8^2/4) = 4

The distance from the center to the vertex is a = 5, since the vertex is 5 units to the right of the center. The distance from the center to the co-vertex is b = 3, since the co-vertex is 3 units above or below the center. Substituting these values into the standard form of the equation, we get:

((x-9)^2/25) + (y+2)^2/9 = 1

Since the foci are on the x-axis, we have:

2c = 8, or c = 4

The distance from the center to the vertex is a = 5, so:

a^2 = 25

Using the relationship between a, b, and c for an ellipse, we have:

b^2 = a^2 - c^2 = 25 - 16 = 9

Substituting these values into the standard form of the equation, we get:

((x-9)^2/64) + (y+2)^2/36 = 1

Therefore, the equation for the ellipse with foci (0, −2), (8, −2), and vertex (9, −2) is ((x-9)^2/64) + (y+2)^2/36 = 1.

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Abdul earns and spends money during the week. On weekdays, he earns $8.00 per day for mowing lawns. On weekdays, he spends $2.25 per day for school lunch.
After 4 weeks, he saves 1/3 of what is left for a new lacrosse stick. Enter a numerical expression that represents the amount of money in dollars that Abdul has saved after 4 weeks.

(urgent!!!)

Answers

(4 * (5 * 8 - 5 * 2.25)) * 1/3

what does it mean to say that the sample correlation coefficient r is significant?

Answers

When we say that the sample correlation coefficient r is significant, it means that the correlation observed between two variables in a sample is unlikely to have occurred by chance.

This is often determined by comparing the value of r to a critical value calculated from a statistical test, such as a t-test or an F-test. The sample correlation coefficient r is a statistical measure that reflects the strength and direction of the linear relationship between two variables in a sample. It can range from -1 to +1, where -1 indicates a perfect negative correlation, 0 indicates no correlation, and +1 indicates a perfect positive correlation.

To determine whether the observed correlation is significant, we need to conduct a hypothesis test. The null hypothesis is that there is no correlation between the two variables in the population, and the alternative hypothesis is that there is a significant correlation. We then calculate a test statistic, such as a t-value or an F-value, which compares the observed correlation to the expected correlation under the null hypothesis. If the test statistic is larger than the critical value, we reject the null hypothesis and conclude that the correlation is statistically significant.

In practice, the significance of a correlation coefficient depends on several factors, including the sample size, the magnitude of the correlation, and the level of statistical significance chosen for the test. It is important to keep in mind that a significant correlation does not necessarily imply causation and that other factors may be involved in the relationship between the two variables.

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If a = 4, then a 2 · a 3 is equivalent to all of the following except _____.
4 6
1,024
4 2 · 4 3
a 5

Answers

If a = 4, then a 2 · a 3 is equivalent to all of the following except _ 4^2 · 4^3 = 1,024

Noted that Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

We are given that a = 4, then the expression could be;

a^2 · a ^3

Substitute the values;

a^2 · a ^3  = 4^2 · 4^3

= 16 . 64

= 1,024

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{ASAP}
Triangle XYZ is similar to triangle JKL.

Determine the length of side LJ.
4.59
5.13
12.48
13.12

(Use Image added)

Answers

Answer:

LJ = 13.12

Step-by-step explanation:

given the triangles are similar then the ratios of corresponding sides are in proportion, that is

[tex]\frac{LJ}{ZX}[/tex] = [tex]\frac{JK}{XY}[/tex] ( substitute values )

[tex]\frac{LJ}{8.2}[/tex] = [tex]\frac{13.92}{8.7}[/tex] ( cross- multiply )

8.7 × LJ = 8.2 × 13.92 = 114.144 ( divide both sides by 8.7 )

LJ = [tex]\frac{114.144}{8.7}[/tex] = 13.12

A rancher just bought a triangular piece of land for his cattle. He plotted a diagram of the land's boundaries on a coordinate plane where each unit represents 25 yards. He is building part of a fence connecting points A and B, and has completed seven-ninths of this part of fence. Assuming he began at one of the endpoints of this section of the fence, at what points could his fence currently end?

Answers

Possible endpoint for the fence, if the rancher started at point A and completed seven-ninths of the way to point B, is approximately (2.34, 5.19).

The distance from point B to point A can be found using the distance formula:

d = √[(x2 - x1)² + (y2 - y1)²]

where (x1, y1) = (0, 0) and (x2, y2) = (3, 6):

d = √[(3 - 0)² + (6 - 0)²] = √(9 + 36) = √45

To find the coordinates of point A, we need to count seven-ninths of this distance from point B:

7/9 × √45 ≈ 3.21

Starting from point B (3, 6), we can move 3.21 units in the direction of point A. We can find the coordinates of point A by subtracting this distance from the coordinates of point B:

x-coordinate of A: 3 - 7/9 × 3 ≈ 1.67

y-coordinate of A: 6 - 7/9 × 6 ≈ 4.67

So the current possible endpoint for the fence, if the rancher started at point B and completed seven-ninths of the way to point A, is approximately (1.67, 4.67).

To find the other possible endpoint, we need to determine the coordinates of point B. Since the rancher started at one of the endpoints of the fence section and has completed seven-ninths of the way to point A, the current length of the fence section is two-ninths of the distance from point A to point B. We can use this information to find the coordinates of point B by counting two-ninths of the distance from point A to point B:

2/9 × √[(5 - 1.67)² + (2 - 4.67)²] ≈ 1.33

Starting from point A (1.67, 4.67), we can move 1.33 units in the direction of point B. We can find the coordinates of point B by adding this distance to the coordinates of point A:

x-coordinate of B: 1.67 + 2/9 × (3 - 1.67) ≈ 2.34

y-coordinate of B: 4.67 + 2/9 × (6 - 4.67) ≈ 5.19

Hence, the other possible endpoint for the fence, if the rancher started at point A and completed seven-ninths of the way to point B, is approximately (2.34, 5.19).

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7. (I’ll give 30 points plus brainpower if you answer the ones in the photo)
Simplify.
x²+3x-4 over x+4

(Does it equal -4 ,4, or 1 at all? Which one does it not equal)

Answers

9.C
10.A
Took in class and made 100

find the right end behavior, x → [infinity] , for each of the following: (a) y = log6(x) : y → incorrect: your answer is incorrect. (b) y = e−3x :

Answers

Therefore, The exponential function approaches zero as the input approaches negative infinity, and as x increases towards infinity, the value of e−3x approaches zero.

(a) The right end behavior of y = log6(x) as x approaches infinity is that y approaches negative infinity. This is because as x increases towards infinity, the value of log6(x) becomes larger and larger negative values. Explanation: The logarithm function approaches negative infinity as the input approaches zero, and as x increases towards infinity, the value of log6(x) approaches negative infinity.
(b) The right end behavior of y = e−3x as x approaches infinity is that y approaches 0. This is because as x increases towards infinity, the exponent -3x becomes larger and larger negative values, making the value of e−3x approach zero.  

Therefore, The exponential function approaches zero as the input approaches negative infinity, and as x increases towards infinity, the value of e−3x approaches zero.

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find the sum of the series x[infinity] n=1 (−1)n (2n 1)3n .

Answers

We can use the power series representation sum of the function f(x) = (1+x)^3 to find a closed-form expression for the series x[infinity] n=1 (-1)^n (2n+1)^3n.

Specifically, we have:

f(x) = (1+x)^3 = 1 + 3x + 3x^2 + x^3

Taking the cube of this expression gives:

f(x)^3 = (1 + 3x + 3x^2 + x^3)^3

Expanding this out using the binomial theorem gives:

f(x)^3 = 1 + 9x + 36x^2 + 84x^3 + 126x^4 + 126x^5 + 84x^6 + 36x^7 + 9x^8 + x^9

We can rewrite the terms with even powers of x as:

f(x)^3 = 1 + 9x + 36x^2 + 84x^3 + x^4 (126 + 126x + 84x^2 + 36x^3 + 9x^4)

Note that the expression in parentheses is just the power series representation of (1+x)^4. Therefore, we can simplify the above expression to:

f(x)^3 = 1 + 9x + 36x^2 + 84x^3 + x^4 (1+x)^4

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What is the value of the variable?

Answers

Answer:

Step-by-step explanation:

for the geometric sequence, assume n1 and find (a) the common ratio r, (b) the general nth term, (c) the 10th term of the sequence, and (d) the sum of the first 16 terms. , , , , , ...

Answers

The common ratio of a geometric sequence is the ratio of any term to the previous term. The general nth term is given by an = n1 * r^(n-1), and the 10th term is a10 = n1 * r^9. The sum of the first 16 terms is S = (n1 * (1 - r^16)) / (1 - r).

Without the first term n1, we cannot find the common ratio r. However, we can still find the general nth term and the sum of the first 16 terms of the sequence.

(a) The common ratio r of a geometric sequence is the ratio of any term to the previous term. Let's assume that the first term of the sequence is n1. Then, the second term is n1r, the third term is n1r^2, and so on. Therefore, the common ratio is r = (n2 / n1) = (n3 / n2) = (n4 / n3) = ...

(b) The general nth term of a geometric sequence is given by an = n1 * r^(n-1).

(c) To find the 10th term of the sequence, we use the formula above with n = 10. Therefore, a10 = n1 * r^(10-1) = n1 * r^9.

(d) To find the sum of the first 16 terms of the sequence, we use the formula for the sum of a geometric series: S = (n1 * (1 - r^n)) / (1 - r), where n is the number of terms. In this case, n = 16. Thus, the sum of the first 16 terms is S = (n1 * (1 - r^16)) / (1 - r).


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(Please help!!!) In Ms. Talley's class, 9 out of 30 students have afterschool jobs. In Mr. William's class, 8 out of 25 students have afterschool jobs. Which statement is correct?

Mr. William's class has a higher rate of students with afterschool jobs because 9 over 30 is greater than 8 over 25.
Mr. William's class has a higher rate of students with afterschool jobs because 9 over 30 is less than 8 over 25.
Ms. Talley's class has a higher rate of students with afterschool jobs because 9 over 30 is less than 8 over 25.
Both classes have the same ratio of students with afterschool jobs.

Answers


Answer: Ms. Talley's class has a higher rate of students with afterschool jobs because 9 over 30 is less than 8 over 25.

8/25 > 9/30
Their common denominator is 750.

25 x 30 = 750
30 x 25 = 750

Do the same to their numerators.

8 x 30 = 240
9 x 25 = 225

240/750 > 225/750 -> 8/25 > 9/30

I have four number cards. The median is 4.
If the range is 10, what are the missing numbers?



Please help

Answers

The missing number in those three card are 5 and 12 when the median is 4 and the range is 10.

Median:

Median refers the middle value of the given set of numbers.

Given,

I have three number cards. the median is 4.

Here we need to find the missing number when the range is 10.

Let us consider x and y be the missing number.

We know that, the range is difference of smallest and largest number,

So, we can write it as,

[tex]\sf x - y = 10[/tex]

Now, we know that the median is the middle value

Then it can be written as,

[tex]\sf y, 4, x[/tex]

The smallest possible values of y is 11, 12, and 13

Similarly, the possible values of x is 15, 16, 17

But based on the value of range we have only take the values, 5 and 12.

Because that one is satisfies the condition of range.

Therefore, the missing numbers are 5 and 12.

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8.68 the manufacturer of Boston and Vermont asphalt shingles provides its customers with a 20-year warranty on most of its products. To determine whether a shingle will last the entire warranty period, accelerated-life testing is conducted at the manufacturing plant. Accelerated-life testing exposes the shingle to the stresses it would be subject to in a lifetime or normal use via a laboratory experiment that takes only a few minutes to conduct. In this test, a shingle is repeatedly scraped with a brush for a short period of time, and the shingle granules removed by the brushing are weighed (in grams). Shingles that experience low amounts of granule loss are expected to last longer in normal use than shingles that experience high amounts of granule loss. In this situation, a shingle should experience no more than 0.8 grams of granule loss if it is expected to last the length of the warranty period. The file granule contains a sample of 170 measurements made on the company’s Boston shingles and 140 measurements made on Vermont shingles.

A. For the Boston shingles, construct a 95% confidence interval estimate for the mean granule loss.

B. For the Vermont shingles, construct a 95% confidence interval estimate for the mean granule loss.

C. Do you think the assumption needed to construct the confidence interval estimates in (a) and (b) is valid?

D. Based on the results of (a) and (b), what conclusions can you reach concerning the mean granule loss of the Boston and Vermont Shingles

Boston Vermont
0.14 0.38
0.31 0.33
0.28 0.29
0.14 0.24
0.17 0.28
0.13 0.27
0.10 0.28
0.11 0.32
0.27 0.33
0.24 0.25
0.19 0.27
0.29 0.22
0.20 0.27
0.25 0.15
0.33 0.19
0.22 0.38
0.13 0.16
0.21 0.15
0.13 0.20
0.17 0.24
0.23 0.19
0.17 0.25
0.21 0.14
0.17 0.08
0.12 0.16
0.17 0.31
0.22 0.28
0.23 0.19
0.28 0.22
0.21 0.17
0.08 0.14
0.15 0.22
0.15 0.20
0.11 0.22
0.17 0.28
0.17 0.25
0.20 0.20
0.18 0.26
0.24 0.18
0.18 0.20
0.27 0.14
0.22 0.23
0.12 0.25
0.14 0.31
0.15 0.23
0.43 0.27
0.38 0.31
0.34 0.21
0.27 0.15
0.22 0.16
0.27 0.21
0.22 0.13
0.12 0.40
0.21 0.46
0.27 0.51
0.27 0.37
0.16 0.24
0.24 0.27
0.32 0.29
0.53 0.48
0.23 0.32
0.15 0.29
0.08 0.31
0.11 0.34
0.22 0.51
0.33 0.36
0.28 0.28
0.15 0.16
0.21 0.58
0.22 0.47
0.44 0.25
0.20 0.22
0.29 0.24
0.28 0.36
0.29 0.19
0.35 0.24
0.47 0.19
0.58 0.21
0.46 0.11
0.40 0.16
0.49 0.56
0.39 0.83
0.56 0.31
0.81 0.20
0.36 0.02
0.20 0.08
0.40 0.09
0.43 0.08
0.41 0.15
0.45 0.04
0.42 0.04
0.35 0.10
0.32 0.20
0.25 0.11
0.51 0.28
0.23 0.19
0.58 0.05
0.42 0.05
0.23 0.21
0.25 0.12
0.26 0.13
0.26 0.15
0.22 0.09
0.23 0.09
0.21 0.05
0.25 0.06
0.60 0.09
0.44 0.17
0.60 0.11
0.39 0.14
0.56 0.08
0.98 0.05
0.29 0.12
0.32 0.12
0.24 0.13
0.52 0.18
0.20 0.13
0.54 0.41
0.52 0.13
0.24 0.33
0.22 0.10
0.24 0.10
0.24 0.07
0.28 0.20
0.45 0.21
0.45 0.24
0.43 0.19
0.32 0.20
0.33 0.10
0.34 0.18
0.12 0.26
0.05 0.14
0.04 0.35
0.13 0.14
0.14 0.10
0.24 0.12
0.17 0.05
0.19 0.15
0.19 0.12
0.10 0.28
0.25
0.19
0.06
0.18
0.12
0.06
0.17
0.23
0.24
0.14
0.15
0.19
0.25
0.16
0.20
0.09
0.18
0.11
0.04
0.19
0.19
0.20
0.29
0.27
0.30
0.20
0.37
0.23
0.30
0.20
- please help

Answers

Answer:

a metal brush to simulate wear and tear from wind, rain, and other environmental factors. The shingle is then exposed to extreme temperatures and humidity levelsthat it may encounter during its lifetime, and the overall effect of these tests is used to estimate the shingle's durability over time.

The manufacturer uses statistical analysis to determine the expected failure rate of its shingles based on the results of the accelerated-life

Kay measured herself, her shadow, and the shadow length of a nearby tree. She sketched out the picture below and wants to use it to determine the height of the tree. Calculate the height of the tree in meters. only write the number! don't round!

Answers

The height of the tree is 6.08 meters.

We are given that;

Base to kays feet= 4.75m, kays feet to end of shadow=1.25m, kays height=1.60m

Now,

To find the height of the tree, you need to use similar triangles. The ratio of the corresponding sides of similar triangles is equal, so you can set up a proportion between the heights and the shadow lengths. You can write your solution as:

1.60/1.25 = h/4.75 h = 1.60/1.25 x 4.75 h = 6.08

Therefore, by the proportions the answer will be 6.08 meters.

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assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1. if p ( z > c ) = 0.2445 p(z>c)=0.2445 , find c. c = c=

Answers

c = 0.71, which means that the probability of obtaining a z-score greater than 0.71 in a standard normal distribution is 0.2445. We need to use a standard normal distribution table or calculator.

From the given information, we know that the area to the right of z (which is c in this case) is 0.2445. Looking up this value in a standard normal distribution table, we find that the z-score that corresponds to this area is approximately 0.71. Therefore, c = 0.71. We can also use a calculator to find the value of c. Using the inverse normal function (also known as the z-score function) on a calculator or spreadsheet, we can input the area to the right of c (0.2445) and get the corresponding z-score, which is 0.71.

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A past study claimed that adults in America spent an average of 18 hours a week on leisure activities. A researcher wanted to test this claim. She took a sample of 10 adults and asked them about the time they spend per week on leisure activities. Their responses (in hours) are as follows. 13. 415. 921. 21. 421. 534. 71717. 920. 320. 6Assume that the times spent on leisure activities by all adults are normally distributed. Using the 5% significance level, can you conclude that the average amount of time spent by American adults on leisure activities has changed? (Hint: First calculate the sample mean and the sample standard deviation for these data. Then make the test of hypothesis about ?. )Round the sample standard deviation to three decimal places. ¯x�¯ (x bar) =s=The claim is false or true?

Answers

There is not enough evidence to conclude that the average time spent on leisure activities by American adults has changed. Sample standard deviation (s) is 8.984 hours. Sample mean (x') is 19.9 hours per week

To test whether the claim that American adults spend an average of 18 hours per week on leisure activities is true or false, we can conduct a hypothesis test.

First, we need to define the null and alternative hypotheses. Let µ be the population mean time spent on leisure activities by American adults.

Null hypothesis: µ = 18 hours per week

Alternative hypothesis: µ ≠ 18 hours per week

We can then calculate the sample mean and standard deviation from the data given as follows:

Sample mean (x') = (13+4+15+9+21+42+15+34+20+6) / 10 = 19.9 hours per week

Sample standard deviation (s) = 8.984 hours

Next, we can calculate the test statistic (t-value) using the formula:

t = (x' - µ) / (s / √(n))

where n is the sample size (10).

Using a t-distribution with 9 degrees of freedom (n-1), we can find the critical t-value at a 5% significance level to be ±2.306.

We calculate the t-value as:

t = (19.9 - 18) / (8.984 / √(10)) = 0.911

Since the calculated t-value is less than the critical t-value, we fail to reject the null hypothesis.

In other words, the claim that American adults spend an average of 18 hours per week on leisure activities is not contradicted by the sample data.

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Graph
4) y=sin 2(x-pi/2)

5) y=cos 1/2(x-pi)

6) y=3cos 2(x+pi)-1

Please include if it has an
Period
Amplitude
Phase shift
Reflection
Vertical shift

Answers

The properties of the functions are

(4) y = sin 2(x - π/2): Period = π, Amplitude = 1, Phase shift = π/2 right, Reflection = None and Vertical shift = None(5) y = cos 1/2(x - π): Period = 4π, Amplitude = 1, Phase shift = π right, Reflection = None and Vertical shift = None(6) y = 3cos 2(x + π) - 1: Period = π, Amplitude = 3, Phase shift = π left, Reflection = None and Vertical shift = 1 unit down

Calculating the properties of the sinusoidal functions

A sinusoidal function is represented as

f(x) = Acos(2π/B(x + C)) + D or

f(x) = Asin(2π/B(x + C)) + D

Where the properties are

Period = BAmplitude = APhase shift = CVertical shift = DReflection is if A is negative or the coefficient of x is negative

Using the above as a guide, we have the following:

4) y = sin 2(x - π/2):

Period = πAmplitude = 1Phase shift = π/2 rightReflection = NoneVertical shift = None

5) y = cos 1/2(x - π):

Period = 4πAmplitude = 1Phase shift = π rightReflection = NoneVertical shift = None

6) y = 3cos 2(x + π) - 1:

Period = πAmplitude = 3Phase shift = π leftReflection = NoneVertical shift = 1 unit down

The graphs of the functions are added as attachments

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