Answer:
Explanation:
Elongation in the spring when a mass of 2 kg hangs from it
k d = mg where d is the elongation
32 d = 2 x 9.8
d = .6125 m .
When it rises by .40 m , the elongation reduces to .6125 - .40 = .2125 m
upward restoring force at this point = 32 x .2125 = 6.8 N .
Its weight = 2 x 9.8 = 19.6 N acting downwards
Net force on mass of 2 kg = 19.6 - 6.8 N = 12.8 N .
acceleration in downward direction = net force / mass = 12.8 / 2 = 6.4 m/s²
At the bottommost point , total extension = .6125 + .40 = 1.0125 m
restoring force in upward direction = 32 x 1.0125 = 32.4 N .
Net force in upward direction = 32.4 - 19.6 N = 12.8 N
acceleration = 12.8 / 2 = 6.4 m /s² in upward direction .
wHICH WAVES MOVE BY REPLACING ONE PARTICLE WITH ANOTHER?
A. LIGHT WAVES
B. SOUND WAVES
C. ELECTROSTATIC WAVES
D. ELECTROMAGNETIC WAVES
AGAIN IF ANYONE I KNOW SEES THIS IGNORE BC IM FINNA JUMP OFF A CLIFF
Answer:
I think it's B. Sound Waves
What is the saying that can help you remember the order of the visible spectrum? ROYBVIG ROYGBIV RIBYOVG RYOBIVG
Answer:
ROYGBIV
Explanation:
mark me brainliest pls
Answer:
ROYGBIV
Explanation:
Please help ASAP with questions
You are studying a population of flowering plants for several years. When you present your research findings you make the statement that, "Increased allocation of resources to reproduction relative to growth diminished future fecundity." Which of the following graph descriptions could accurately present your data?
a) With seeds in the current year on the y-axis and seeds in the previous year on the x-axis, you would see a line that increased from left to right
b) With survivorship on the y-axis and number of seeds produced on the x-axis, you would see a line that decreased left to right.
c) With leaf area on the y-axis and number of seeds produced on the x-axis, you would see a line that increased left to right
d) With survivorship on the y-axis and number of seeds produced on the x-axis, you would see a line that increased left to right.
e) With seeds in the current year on the y-axis and seeds in the previous year on the x-axis, you would see a line that decreased from left to right
Answer:
Option A
Explanation:
The graph for this problem must depict the following ""Increased allocation of resources to reproduction relative to growth diminished future fecundity."
Hence, the survivor ship must be on the Y axis and the resources on the X axis.
Here the resources include the number of seeds produced.
hence, the higher is the number of seeds (resource), the lower is the survivorship (future fecundity)
Hence, option A is correct
A 10- kg ball starting from rest rolls down a 5 m tall smooth hill from one person to another person who is standing at the bottom of the hill with a big spring whose constant is 100 N/m. How far does the spring compress in order to stop the ball
Answer: 3.13 m
Explanation:
Given
mas of the ball is m=10 kg
The ball rolls down a vertical distance of 5 m
Spring constant of spring is [tex]k=100\ N/m[/tex]
Here, the potential energy of the ball converted into kinetic energy which in turn converts into elastic potential energy
[tex]\Rightarrow mgh=\frac{1}{2}kx^2\quad [\text{x=compression in the spring}]\\\\\Rightarrow 10\times 9.8\times 5=\frac{1}{2}\cdot 100\cdot x^2\\\Rightarrow x=\sqrt{9.8}\\\Rightarrow x=3.13\ m[/tex]
Thus, the spring compresses by 3.13 m.
Which statement describes a characteristic of deposition
Explanation:
when soil builds up over time in the location
What is hypothesis testing
When an object levitates, the magnetic force causes the object to repel. Without this magnetic force, ________ would pull the object down.
Answer:
gravity
Explanation:
I don't know what the explanations would be
a car drives 24 meters to the left in three seconds what is the velocity of the car?
Answer:
8 m/s to the left.
Explanation:
Applying,
V = d/t...................... Equation 1
Where V = Velocity of the car, d = distance, t = time
From the question,
Given: d = 24 meters, t = 3 seconds
Substitute these values into equation 1
V = 24/3
V = 8 m/s to the left.
Hence the velocity of the car is 8 m/s to the left.
PLEASE HELP!! WILL GIVE POINTS
A machine does 9,800 joules of work to life a couch twenty meters off the ground. What is the is mass of the couch?
Answer:
49 kg is the mass of the couch.
Explanation:
GPE = mgh
9800 = m * 10 * 20
9800 = 200m
m = (9800/20) = 49 m
Thenks and mark me brainliest :))
A spinning disc with a mass of 2.5kg and a radius of 0.80m is rotating with an angular velocity of 1.5 rad/s. A ball of clay with unknown mass is dropped onto the disk and sticks to the very edge causing the angular velocity of the disk to slow to 1.13 rad/s. What is the mass of the ball of clay
Answer:
M = 1.90 Kg
Explanation:
Given data: mass = 2.5 Kg
radius R = 0.8 m
angular velocity ω = 1.5 rad/s
Angular momentum L =0.5×Iω^2
Where, I is the moment of inertia of the spinning disc.
I = 0.5MR^2
I = 0.5×2.5×0.8^2
I = 0.8 Kg/m^2
Then L = 0.5×0.8×1.5^2 = 0.8×2.25 = 0.9 Kg-m^2/sec
Let unknown mass be M
New mass of disc = (2.5+M) Kg, R = 0.8 m
New I = 0.5(2.5+M)(0.8)^2
Since, angular momentum is conserved
Angular momentum before = angular momentum after
0.5×0.5(2.5+M)(0.8)^2×(1.13)^2 = 0.9
Solving for M we get
0.204304(2.5+M)=0.9
M = 1.90 Kg
define rectilinear propagation of light
Answer:
Electromagnetic waves to travel in a straight line. Light only deviates from a straight line when the medium it is travelling through changes density. This is called refraction. Light does not deviate when travelling through a homogeneous medium, which has the same refractive index throughout. Wikipe
10 A particle in circular motion performs 30 oscillations in 6
seconds. Its angular velocity is?
Explanation:
Let omega = angular velocity (in rad/s). Then
omega = (# of oscillations)/(6 s)
= (30 osc)/(6 s) = 5 osc/s
We need to convert this to rad/s:
omega = (5 osc/s)(2π rad/osc)
= 10π rad/s
= 31.4 rad/s
a football player starts from rest and speeds up to a final velocity of 12 m/s. the speeding up takes a total of 6 seconds. what is the football players acceleration
Answer:
2 m/s²
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 0 m/s
Final velocity (v) = 12 m/s
Time (t) = 6 s
Acceleration (a) =?
The acceleration of the player can be obtained as follow:
v = u + at
12 = 0 + (a × 6)
12 = 6a
Divide both side by 6
a = 12 / 6
a = 2 m/s²
Thus, the acceleration of the player is 2 m/s²
Select the correct answer.
A car moves with an average speed of 45 miles/hour. How long does the car take to travel 90 miles?
OA.
2 minutes
OB.
2 hours
O c.
45 minutes
OD.
45 hours
O E.
90 minutes
Reset
Next
Answer:
B. 2 hours
Explanation:
45 miles an hour times 2 is 90 miles in 2 hours
Answer:
B. 2 Hours
Explanation:
If your going at a constant speed of 45 miles per hour then, it will take two hours because 45x2 is 90. and if you divided 90 and 45, you will get 2.
A chocolate brownie has a volume of 360cubic centimeters and a mass of 270grams. Calculate its density.
Write your answer to the hundredths place.
Answer:
Its density is 0.75 grams per cubic centimeters.Explanation:
Given that:
A chocolate brownie has a volume of 360 cubic centimeters and a mass of 270 grams.To Calculate:
Its density.We know that:
Density = Mass/VolumeWe have:
Mass = 270 gVolume = 360 ccFinding its density:
⟶ Density = 270/360
⟶ Density = 0.75
Hence,
Its density is 0.75 g/cc.A child is holding a wagon from rolling straight back down in a driveway that inclined at 20 degree horizontal. if the wagon weigh 150n with what force must the child pull on the handle if the handle is parallel to the incline?
Answer:
F = 51.3°
Explanation:
The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:
[tex]F = Parallel\ Component\ of\ Weight\ of\ Wagon= WSin\theta\\[/tex]
where,
W = Weight of Wagon = 150 N
θ = Angle of Inclinition = 20°
Therefore,
[tex]F = (150\ N)Sin\ 20^o[/tex]
F = 51.3°
What are the biotic factors in this image?
Someone help thank you!!
A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.50 km/s in the +x-direction experiences a force of 2.25 \times 10^{-16} N2.25×10 −16 N in the +y-direction, and an electron moving at 4.75 km/s in the -z-direction experiences a force of 8.50 \times 10^{-16} \mathrm{N}8.50×10 −16 N in the +y-direction.
(a) What are the magnitude and direction of the magnetic field?
(b) What are the magnitude and direction of the magnetic force on an electron moving in the -y-direction at 3.20 km/s?
Answer:
a) B = 0.9375 T -z, b) B = 1.54 T
Explication
a) The magnetic force is
F = q v x B
f = q v B sin θ
bold indicates vectors
For direction let's use the right hand rule.
If the charge is positive
the flea in the direction of velocity, toward + x
the fingers extended in the direction of B
the palm the direction of the force + and
therefore the magnetic field goes in the direction of -z
F = q v B
2.25 10-16 = 1.6 10-19 1.50 103 B
B = 2.25 10-16 / 2.4 10-16
B = 0.9375 T -z
b) now an electron
thumb speed direction, -z
opposite side of palm force + y
therefore the direction of the magnetic field is + x
B = F / qv
B = 8.5 10-16 / 1.16 10-19 4.75 103
B = 1.54 T
What is Hooke's law? what is meant by elastic limit?
please answer me
Answer:
Explanation:
The law is about how object will be deformed when certain amount force is applied. Elastic limit is a point where object will not return its previous shape after being deformed
A car of mass 2 320 kg is descending a sloping road, inclined at 10.0° to the horizontal. The driver sees a hazard and brakes to make an emergency stop. The distance travelled while braking is 22.5 m.
The initial speed of the car was 13.4 m s−1. Calculate the average braking force. Assume air resistance is negligible.
f = 1.32×10^4 N
Explanation:
We can use the work-energy theorem to find the work done by the braking force f:
W = ∆KE + ∆PE
= (KEf - KEi) + (PEf - PEi)
= [(1/2)mvf^2 - (1/2)mvi^2] + (mhf - mghi)
At the bottom of the slope, vf = 0 and hf = 0 and hi = dsin10° (d = braking distance) so work W becomes
W = -[(1/2)mvi^2 + mgdsin10°]
= -m[(1/2)vi^2 + gdsin10°]
= -(2320kg)[(1/2)(13.4m/s)^2 + (9.8 m/s^2)(22.5m)sin10]
= -2.97×10^5 J
Since W = fd, where f is the braking force, we can now solve for f:
f = W/d = (-2.97×10^5 J)/(22.5 m)
= -1.32×10^4 N
Note: the negative sign means that it is a dissipative force.
Average braking force is 1.32×10^4 N.
What is force?A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
We can use the work-energy theorem to find the work done by the braking force f:
W = ∆KE + ∆PE
= (KEf - KEi) + (PEf - PEi)
= [(1/2)mvf^2 - (1/2)mvi^2] + (mhf - mghi)
At the bottom of the slope, vf = 0 and hf = 0 and hi = dsin10° (d = braking distance) so work W becomes
W = -[(1/2)mvi^2 + mgdsin10°]
= -m[(1/2)vi^2 + gdsin10°]
= -(2320kg)[(1/2)(13.4m/s)^2 + (9.8 m/s^2)(22.5m)sin10]
= -2.97×10^5 J
Since W = fd, where f is the braking force, we can now solve for f:
f = W/d = (-2.97×10^5 J)/(22.5 m)
= -1.32×10^4 N, the negative sign means that it is a dissipative force.
Average braking force is 1.32×10^4 N.
To learn more about force refer to the link:
brainly.com/question/13191643
#SPJ2
que estudia la estática?
Light from a He-Ne laser of wavelength 633 nm passes through a circular aperture. It is observed on a screen 4.0 m behind the aperture. The width of the central maximum is 1.1 cm. What is the diameter of the hole
Answer:
The diameter of the hole is 5.6164 μm
Explanation:
Given the data in the question;
wavelength λ = 633 nm = 633 × 10⁻⁹ m
L = 4.0 M
width of the central maximum D = 1.1 cm.
Now,
Y = D / 2
Y = 1.1 / 2 = 0.55 cm
So diameter of the aperture will be;
α = 1.22λ / ( Y / L )
we substitute in our values;
α = ( 1.22 × (633 × 10⁻⁹ m)) / ( 0.55 / 4.0 )
α = 0.00000077226 / 0.1375
α = 5.6164 × 10⁻⁶ m
α = ( 5.6164 × 10⁻⁶ × 10⁶ ) μm
α = 5.6164 μm
Therefore, the diameter of the hole is 5.6164 μm
el sistema energético que importancia tiene en el cuerpo
Answer:
De un modo más claro, los sistemas energéticos son los modos que tiene el organismo para suministrar ATP a los músculos. Como decimos, en todos los esfuerzos físicos es necesario contar con la cantidad suficiente de energía y esto viene determinado por la producción de ATP, el adenosin trifosfato.
What is the acceleration of a race car if it has a mass of 1200kg and is moving with an engine force of 400N
Answer:
0.34 m/s^2
Explanation:
force=mass × acceleration
400 =1200 × acceleration
acceleration=400/1200
=0.34 m/s^2
A teacher sets up the following demonstration in which he places a clear glass rod with an index of refraction of 1.47 into a beaker containing an unknown liquid. When he does this, the submerged portion of the glass rod seems to disappear. The teacher gives the students the following list of possible liquids in which this glass rod has been submerged.
Material Index of Refraction
Salt Water 1.37
Glycerin 1.47
Silicon Oil 1.52
Required:
Which material is most likely to represent the liquid in the beaker and why?
Answer:
salt water
total internal reflection
Explanation:
Let's analyze this experiment, for the rod to disappear it must have happened that the light coming from it does not reach us that we are seeing from the air n = 1, therefore the light from the rod must be reflected, for this to happen we use the refractive ratio
n₁ sin θ₁ = n₂ sin θ₂
where n₁ is the refractive index of the rod, the greatest angle that could exist in the liquid is 90º, therefore sin 90 = 1
n₁ sin θ₁ = n₂
sin θ₁ = n₂ /n₁
the only way this expression is correct is that
n₂ <n₁
that is
n₂ < 1.47
When reviewing the given materials, the only one that meets this condition is salt water by the total internal reflection
he electric field is dependent on the distance between the plates. false: The voltage of a connected charged capacitor decreases when the plate area is increased. false: The voltage of a disconnected charged capacitor increases when the plates are brought closer together.
Answer:
False.
Explanation:
The voltage of a disconnected charged capacitor decreases when the plates are brought closer together because the capacitance is inversely proportional to the area. If the area between plates decreases, its capacitance increases and vice versa. There is direct relationship between voltage of a disconnected charged capacitor and plates. If the distance between plates decreases, the voltage of a disconnected charged capacitor is also decreases while on the other hand, if the distance between plates increases, the voltage of a disconnected charged capacitor is also increases.
A golf club hits a 0.0459 kg golf ball at rest; the club is in contact with the ball for 0.00138 s. Afterwards the ball leaves at 63.9 m/s. How much force acted on the ball? (Unit = N)
Answer: 2120 N is correct
Explanation: correct answer for acellus
A train sounds its whistle at a constant frequency as it passes by the platform. Compared to the sound emitted by the whistle, the sound that people on the platform hear as the train moves away has a frequency that is ...
-higher
-the same
-lower
-exactly half
Answer: Higher.
Explanation: The doppler effect essentially. "The Doppler effect can be described as the effect produced by a moving source of waves in which there is an apparent upward shift in frequency for observers towards whom the source is approaching and an apparent downward shift in frequency for observers from whom the source is receding."
Suppose that an electron and a positron collide head-on. Both have kinetic energy of 1.20 MeV and rest energy of 0.511 MeV. They produce two photons, which by conservation of momentum must have equal energy and move in opposite directions. What is the energy Ephoton of one of these photons
Answer:
E = 1.711 MeV
Explanation:
From the law of the conservation of energy:
[tex]K.E_{e}+K.E_p + E_{e}+E_{p} = 2 E[/tex]
where,
[tex]K.E_e=K.Ep=[/tex] the kinetic energy of positron and electron = 1.2 MeV
[tex]E_e=E_p =[/tex] Rest energy of the electron and the positron = 0.511 MeV
E = Energy of Photon = ?
Therefore,
[tex]1.2\ MeV + 1.2\ MeV + 0.511\ MeV + 0.511\ MeV = 2E\\\\E = \frac{3.422\ MeV}{2}\\\\[/tex]
E = 1.711 MeV