Tarea de rendimiento
12
La señora Ericson preparó sándwiches para sus 4 hijos. Todos los sándwiches tenían
el mismo tamaño. Después del almuerzo, a cada niño le quedaba una fracción
diferente de su sándwich. Matt tenía, Elisa tenía
7
3, Carl tenía 2, y Riley tenía 8
8
4
A Usa esta información para escribir un problema en que se comparen dos fracciones
con el mismo numerador.

Answer:

Sidama Cofee Football Team, the Ethiopian premier league club in Yiregalem, plays 70 percent of their games at night and 30 percent during the day. The team wins 50 percent of their night games and 90 percent of their day games. According to today’s news, they won yesterday. What is the probability the game was played at night?

Answer:

x = 27°

Step-by-step explanation:

using the co-function identity

cos x = sin(90 - x) , then

cos63° = sin(90 - 63)° = sin27° with x = 27°

The first derivative of the function f(x) = x^4 + 3x^2 + 2 at x=2 using Richardson's method with h=0.01 is approximately 33.8933.

To calculate the first derivative of the function f(x) = x^4 + 3x^2 + 2 using Richardson's method, we need to first calculate the approximate values of the function at x=2 and x=2+h, where h=0.01.

So, we have:

f(2) = 2^4 + 3(2^2) + 2 = 24

f(2+h) = (2+h)^4 + 3(2+h)^2 + 2

= 16 + 32h + 24h^2 + 8h^3 + h^4 + 12 + 12h + 3h^2 + 2

= h^4 + 8h^3 + 24h^2 + 35h + 30

Now, we can use Richardson's extrapolation formula to calculate the first derivative of the function at x=2:

f'(2) ≈ (4f(2+h) - f(2)) / (3h)

Substituting in the values we have:

f'(2) ≈ (4(h^4 + 8h^3 + 24h^2 + 35h + 30) - 24) / (3h)

= (4h^4 + 32h^3 + 96h^2 + 140h + 96) / (3h)

= (4h^3 + 32h^2 + 96h + 140) / 3

Now, we can substitute h=0.01 to get the value of the first derivative at x=2:

f'(2) ≈ (4(0.01^3) + 32(0.01^2) + 96(0.01) + 140) / 3

≈ (4(0.000001) + 32(0.0001) + 0.96 + 140) / 3

≈ (0.000004 + 0.0032 + 0.96 + 140) / 3

≈ 140.9632 / 3

≈ 33.8933

Therefore, the first derivative of the function f(x) = x^4 + 3x^2 + 2 at x=2 using Richardson's method with h=0.01 is approximately 33.8933.

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The time it will take for your account balance to reach $10,000 is given as follows:

t = 10.8 years.

The balance of an account after t years, using continuous compounding, is given as follows:

A(t) = A(0)e^(kt).

In which:

The parameters for this problem are given as follows:

A(0) = 6500, k = 0.04.

Hence the time needed for a balance of $10,000 is obtained as follows:

10000 = 6500e^(0.04t)

e^(0.04t) = 10000/6500

0.04t = ln(10000/6500) -> ln is the inverse operation of the exponential

t = ln(10000/6500)/0.04

t = 10.8 years.

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Answer:

difference = 12.5

Step-by-step explanation:

the median score is the value of the line inside the box.

median in afternoon = 75

median in morning = 87.5

difference = 87.5 - 75 = 12.5

Answer:

C. No, it is not possible to determine the order of the rational numbers because we do not know the signs of the rational numbers.

There are 5,040 different ways you can arrange your 7 favorite books on the small shelf.

The organization or positioning of a group of items or components in relation to one another is referred to as an arrangement. It can be used in a variety of situations, such as mathematics, art, or event planning, and can relate to the arrangement, positioning, or grouping of things.

The number of different ways you can arrange 7 books in a specific order is given by the permutation formula:

P(7,7) = 7!

where "!" denotes the factorial operation.

Thus, the number of ways you can arrange your 7 favorite books along a small shelf, assuming that the order of the books makes a difference to you, is:

7! = 7 x 6 x 5 x 4 x 3 x 2 x 1 = 5,040

Therefore, there are 5,040 different ways you can arrange your 7 favorite books on the small shelf.

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The surface area of the cylinder is calculated as approximately:

8,444.6 mm².

The surface area of a cylinder (SA) = 2πrh + 2πr², where:

r is the radius

h is the height of the cylinder.

Given the following:

Diagonal of cylinder = 40 mm

Height of cylinder (h) = 32 mm

Radius (r) = √(40² - 32²) = 24 mm [based on Pythagorean Theorem]

Plug in the values:

surface area of the cylinder (SA) = (2 * π * 24 * 32) + (2 * π * 24²)

≈ 8,444.6 mm²

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Answer:

World's Fair. Is the correct answer

Class 1 wiring is required to exceed standards for power and lighting wiring. Class 3 wiring is functionally similar to Class 2 wiring, but with higher voltage and power limitations.

It should be noted that a Class 2 circuit associated with the electrical equipment that is part of a residential oil furnace, for example, usually receives power from a 24-V transformer whose primary connects to a 120-V premises branch circuit.

In conclusion, a class 1 must sit in metal or non-metallic raceway or be metal-sheathed wiring as compared to jacketed cable such as type NM.

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Electricians know about Class 1, 2, and 3 wiring because these terms are spelled out in the National Electrical Code. Electronics engineers, however, tend to be in the dark about these terms. So here is a short primer on classes of wiring for the curious.

The NEC in Article 725 makes a sharp distinction between wiring for “ordinary” power and light circuits and specialized circuits where the power and/or voltage is limited. These circuits are designated Class 1, 2 and 3, not to be confused with the Class I, II and III hazardous locations – an entirely different matter. Class 1, 2 and 3 circuits are defined primarily in terms of the power supply to which they are connected. Power supplies are generally batteries, transformers or electronic power supplies. When working on an existing installation, it is a simple matter of identifying the power source and checking its marking. A Class 2 circuit associated with the electrical equipment that is part of a residential oil furnace, for example, usually receives power from a 24-V transformer whose primary connects to a 120-V premises branch circuit. The relatively high impedance of this small device ensures that its voltage and power output will be in the Class 2 range. Such a device will be marked as suitable as a Class 2 power source. Describe how the results from Class 1, Class 2, and Class 3 differ.

It should be noted that to evaluate whether an organized array of numbers serves as a resolution for a combination of equations, one can apply this method.

Write down the arrangement of equations that you wish to evaluate the solution for. For illustration, let us say that we have this system:

2x + 3y = 7

x - y = 2

Inject the data from the orderly list into the equations. For example, if the ordered list is (x=1, y=3), then we have:

2(1) + 3(3) = 7

1 - 3 = -2

Verify whether the outcome of the equations are equivalent to the values in the ordered list. If they are, then the orderly list is a resolution of the arrangement of equations. On the other hand, if not, then it is not a solution.

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The expression that can be represented by product (50)*(-5) is 250

Any number that can be expressed as the product of 50 and -5 can be represented using the expression (50)*(-5).

For example, if we multiply 50 and -5, we get -250. Therefore, -250 can be represented using the expression (50)*(-5).

Similarly, if we multiply 50 and -5 by any other number, we can represent the product using the expression (50)*(-5).

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So the correct possible triangular outline for the garden is:

5 + 2.5 > 4

4 + 2.5 > 5

4 + 5 > 2.5

Given information:

Gabriel finds some wooden boards in the backyard with lengths of 5 feet, 2.5 feet, and 4 feet.

He decides he wants to make a triangular garden in the yard and uses the triangle inequality rule to see if it will work.

The sums that prove that the boards will create a triangular outline for the garden are:

5 + 2.5 > 4

4 + 2.5 > 5

4 + 5 > 2.5

So the correct options are:

5 + 2.5 > 4

4 + 2.5 > 5

4 + 5 > 2.5

These sums satisfy the triangle inequality rule, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the remaining side.

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The vertex of the parallelogram is (5, 13)

We know that in a parallelogram the opposite sides are equal

AB=√(-3-4)²+(-6+3)²

=√49+9

=√58 units

BC=√(6-4)²+(2+3)²

=√4+25

=√29 units

AD=√(-3-x)²+(-6-y)²

AD=√58 units

√58 units=√(-3-x)²+(-6-y)²

58 units=(-3-x)²+(-6-y)²

Now CD=√(6-x)²+(2-y)²

29 units=(6-x)²+(2-y)²

x=5 and y=13 satisfies the equation

Hence, the vertex of the parallelogram is (5, 13)

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The factored expression would have two brackets as shown.

We can see that the Polynomial that we have to deal with in the questions that we have here are quadratic in nature and we have to deal with them as such. We are going to have that when we deal with the quadratic;

r^2 - 25r - 150

This can be factored into (r + 5) (r - 30)

Then;

64y^2 - 49z^2

This can be factorized to give;

(8y + 7z) (8y - 7z)

Also;

16y^2 - 88y + 121

Can be factorized to;

(4y - 11) (4y - 11)

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The parabola for the expression are given in attachment.

A parabola is a U-shaped plane curve where any point is at an equal distance from a fixed point (known as the focus) and from a fixed straight line, which is known as the directrix

y=2x(x-7)

Let us take few values of x and y and draw the parabola

Similarly we draw the graph for (x+4)(x-4)

Hence, the parabola for the expression are given in attachment.

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The value of the linear sum ∑(i = 1 to 124) (29a_i - 13b_i) is -30.

We have,

Using the linearity of the sum, we have:

∑(i = 1 to 124) (29a_i - 13b_i)

= 29∑(i = 1 to 124)a_i - 13∑(i = 1 to 124)b_i [Distributive property]

= 29(-10) - 13(-20) [Substitute the given sums]

= -290 + 260

= -30

Therefore,

The value of ∑(i = 1 to 124) (29a_i - 13b_i) is -30.

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Answer:

45%

Step-by-step explanation:

Divide $360,000 by $800,000 to find the percentage

360,000/800,000=.45

To conver the decimal to a percentage, move the decimal point two places to the right, so .45 becomes 45%

The equation that best represents the population of the town, which increases exponentially at the rate of 6% every year, after x years is C. y = 158,260(1.06)ˣ.

Exponential growth refers to a constant percentage or rate of growth per period.

The opposite of exponential growth is exponential decay and refers to the constant rate of decay in value per period.

The town's initial population = 158,260

Growth rate per year = 6%

Let x = the number of years of growth

Let y = the population after x years

y = 158,260(1 + 0.06)^x

Thus, the correct equation representing population growth after x years is Option C.

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The probability that a randomly selected ounce of chocolate chips will contain between 62 and 66 chocolate chips is 0.6644.

Using the z-score formula to standardize the values and find the probability using a standard normal distribution table:

z1 = (62 - 63) / 1.8 = -0.56

z2 = (66 - 63) / 1.8 = 1.67

Using the standard normal distribution table, we find that the area to the left of z1 is 0.2881 and the area to the left of z2 is 0.9525.

Therefore, the probability that a randomly selected ounce of chocolate chips will contain between 62 and 66 chocolate chips is:

P(62 < x < 66) = P(z1 < z < z2) = P(z < z2) - P(z < z1)

= 0.9525 - 0.2881

= 0.6644

Therefore, the probability is approximately 0.6644.

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The statement is false, a triangle can't have two angles of 90°.

Remember that for any triangle, the sum of the 3 interior angles should be equal to 180°.

So if the 3 interior angles are A, B, and C we have.

A + B + C = 180°

In this case we know that two of the angles are of  90°, so let's say that:

A = 90°

B = 90°

Replacing that we will get:

90° + 90° + C = 180°

C = 180° - 90° - 90°

C = 0°

And we can't have a 0° degree angle, so the statement is false, triangles with two 90° don't exist.

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The  probability that the student does not own a trampoline is given by the relation P ( A' ) = 5/12

Given data ,

Let the probability that the student does not own a trampoline be P ( A ' )

Given that there are 14 students who own a trampoline out of 24 students in total, the probability of owning a trampoline is 14/24. Therefore, the probability of not owning a trampoline is:

1 - 14/24 = 10/24 = 5/12

So, the probability that a student chosen at random from Jared's class does not own a trampoline is 5/12

Hence , the probability is 5/12

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Answer:

you got them all right except graph 4 is a function! The trick is to use the vertical line test. Put your pencil vertically on your paper and move it across the graph. If your pencil passes through the same point twice, it's not a function. :)

Step-by-step explanation:

Area of rectangular prism: Base x Height.

so 3x1/3x2/5=0.4 0r 2/5

answer:

15

step-by-step explanation:

-4x - 6y = 8

+ (6x + 5y = 7)

__________

2x - y = 15

The three different values of n to demonstrate that 2n + 3n is equivalent to 5n are 1, 4 and 10.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

A = 2n + 3n

On simplifying the equation , we get

A = 5n

when n = 1 , we get

2n + 3n = 2(1) + 3(1) = 2 + 3 = 5

5n = 5(1) = 5

Therefore, both expressions give the same result of 5.

when n = 4 , we get

2n + 3n = 2(4) + 3(4) = 8 + 12 = 20

5n = 5(4) = 20

Again, both expressions give the same result of 20.

when n = 10 , we get

2n + 3n = 2(10) + 3(10) = 20 + 30 = 50

5n = 5(10) = 50

Hence , the equation is solved

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The value of the expression x² + 10x, when x = 2 is 24.

In the expression x² + 10x, x represents a variable, which is a placeholder for a value that can change. We are given that x = 2, which means we substitute 2 for x in the expression:

x² + 10x = 2² + 10(2)

Here, 2² means 2 raised to the power of 2, which is 2 multiplied by itself: 2² = 2 x 2 = 4.

10(2) means 10 multiplied by 2, which is 20.

So we can substitute these values in the expression:

x² + 10x = 2² + 10(2)

= 4 + 20

= 24

Therefore, when x is equal to 2, the value of the expression x² + 10x is 24.

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The complete question:

Evaluate the expression x² + 10x, when x = 2.

The expected number of hits

= [tex]\sum xP(X=x) = 0.96[/tex]

Let X be a Binomial random variable that denotes the number of hits

where the parameters are n = 3, p = 0.320

P(X = x) = [tex]\binom{3}{x}*0.32^{x}*0.68^{3-x} , x = 0,1,2,3[/tex]

(a) The probability distribution of X is

P(X = 0) = 0.3144

P(X = 1) = 0.4439

P(X = 2) = 0.2089

P(X = 3) = 0.0328

X 0 1 2 3

P(X = x) 0.3144 0.4439

0.2089

0.0328

(c) Expected number of hits

= [tex]\sum xP(X=x) = 0.96[/tex]

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answer

a. 5,8

explanation

use numbers in each answer choice

+5 * -8 = - 40

+5 -8 = -3

Consider the form [tex]x^2+bx+c[/tex]. Find a pair of integers whose product is [tex]c[/tex] and whose sum is [tex]b[/tex]. In this case, whose product is -40 and whose sum is -3.

[tex]\longrightarrow\boxed{\bold{(-8,5)}}[/tex]

Write the factored form using these integers.

[tex](x-8) \ (x+5)[/tex]