The actual data below is shown along with two possible lines of best fit. Use the blank tables to calculate theresiduals for both lines of fit and then find the sum of the squared residuals. Identify the line with better fit.17. (1 point)Xy(actual)PredictedfromEquationResidualsLine of fit A:2Square ofResidualsxy (actual)13213y = 3x + 5312418312523418523Line of fit B: y = 3.5x + 4231312(actual)PredictedfromEquationResidualsPossible Line of fit A: y = 3x + 5Possible Line of fit B: y = 3.5x + 4Square ofResidualsCompare the sum of the squared residuals to determine which line has the better fit.418co523

The Actual Data Below Is Shown Along With Two Possible Lines Of Best Fit. Use The Blank Tables To Calculate

Answers

Answer 1

Let us first complete the first table for the line of fit A. Using the given x-values and the equation y = 3x + 5, we predict the values of x to be:

if x = 2, y = 3(2) + 5 = 11

if x = 3, y = 3(3) + 5 = 14

if x = 4, y = 3(4) + 5 = 17

if x = 5, y = 3(5) + 5 = 20

Then we calculate for the residuals by subtrating the actual y-values and the predicted y-values.

for x = 2, residual = 13 - 11 = 2

for x = 3, residual = 12 - 14 = -2

for x = 4, residual = 18 - 17 = 1

for x = 5, residual = 23 - 20 = 3

Then we square the residuals.

2^2 = 4

(-2)^2 = 4

1^2 = 1

3^2 = 9

We have completed the first table. We repreat the same process to complete the second table for the line of fit B.

Finally, we add the squares of the residuals.

A: 4 + 4 + 1 + 9 =18

B: 4 + 6.25 + 0 + 2.25 = 12.5

Comparing the sums of the squares of the residuals, we see that Line of fit B has the better fit becaue it has a smaller sum of the squares of the residuals, meaning there is less variation.

To answer the follow up question (#18), remember that the smaller the sum of the squares of the residuals, the better the fit.

So, the answers are: true, false, and true.

The Actual Data Below Is Shown Along With Two Possible Lines Of Best Fit. Use The Blank Tables To Calculate
The Actual Data Below Is Shown Along With Two Possible Lines Of Best Fit. Use The Blank Tables To Calculate
The Actual Data Below Is Shown Along With Two Possible Lines Of Best Fit. Use The Blank Tables To Calculate
The Actual Data Below Is Shown Along With Two Possible Lines Of Best Fit. Use The Blank Tables To Calculate

Related Questions

Which equation has no real solutions?(А)2x2+2x+15= 02x2 + 5x - 3=0© x2 + 7x+2=0x2 - 4x + 2 = 0

Answers

We are asked to find out which of the given quadratic equation has no real solutions.

Recall that a quadratic equation has no real solutions if the discriminant is less than 0.

The discriminant is given by

[tex]d=b^2-4ac[/tex]

Where a, b, and c are the coefficients of the quadratic equation.

Let us analyze each of the given quadratic equations.

Option A:

[tex]2x^2+2x+15=0[/tex]

The coefficients are

a = 2

b = 2

c = 15

The discriminant is

[tex]\begin{gathered} d=b^2-4ac \\ d=2^2-4(2)(15) \\ d=4-120 \\ d=-116 \end{gathered}[/tex]

As you can see, the discriminant is less than 0, therefore, this quadratic equation has no real solutions.

Therefore, the correct answer is option A.

What will James need to score on his 4 test to have an average of 85?

Answers

Explanation

We are asked to find the score James needs to have on his 4th test to have an average of 85

Let his fourth score be x

Next, we will use the formula

[tex]Average=\frac{sum\text{ of scores}}{number\text{ of tests}}[/tex]

In our case, the total number of tests is 4

The sum of scores is

[tex]73+80+88+x[/tex]

The average is 85

So, solving for x

[tex]\begin{gathered} 85=\frac{73+80+88+x}{4} \\ \\ 85=\frac{241+x}{4} \end{gathered}[/tex]

Solving for x

[tex]\begin{gathered} 241+x=85\times4 \\ 241+x=340 \\ x=340-241 \\ x=99 \end{gathered}[/tex]

Therefore, James has to score 99 in his fourth test to have an average of 85

complete the table below to find solutions to the linear equation -8x+y=8the table reads x. y. (x,y)0. fill in. fill in3. fill in. fill infill in. 0. fill in

Answers

Given:

[tex]-8x+y=8[/tex]

When x=0,

[tex]y=8[/tex]

When x=3,

[tex]\begin{gathered} -8(3)+y=8 \\ -24+y=8 \\ y=32 \end{gathered}[/tex]

When y=0,

[tex]\begin{gathered} -8x+0=8 \\ -8x=8 \\ x=-1 \end{gathered}[/tex]

Final answers are

[tex]\begin{gathered} x=0,y=8;(0,8)\text{ } \\ x=3,y=32;;(3,32) \\ x=-1,y=0;;(-1,0) \end{gathered}[/tex]

you are asked to draw a colored marble out of there are 6 red marbles 3 blue marbles and 6 green marbles in the Box what is the probability of drawing a red marble and then a green marble without replacing the first marble round to the three decimal places

Answers

Given:

there are 6 red marbles 3 blue marbles and 6 green marbles in the Box

So, the total marbles = 6 + 3 + 6 = 15

The probability of drawing a red marble = 6/15

After drawing the red, the remaining marbles = 14

The probability of drawing a green marble = 6/14

So, the probability of drawing a red marble and then a green marble without replacing the first marble =

[tex]\frac{6}{15}\cdot\frac{6}{14}=\frac{6}{35}=0.171[/tex]

So, the answer will be 0.171

what is equivalent to 1:4?

Answers

1:4 is equivalent to 0.25 or 25% of something

1) Looking at the ratio 1:4 we can rewrite it as

[tex]\frac{1}{4}=0.25\text{ or 25\%}[/tex]

Because 1 ÷ 4 = 0.25 or we can also rewrite it as 25%.

2) So 1:4 is equivalent to 0.25 or 25% of something

I am trying to solve for the missing side in a triangle. Trying to figure out whether to use cos,tan or sin.[tex]41 = x \div 6 \sin(?) [/tex]

Answers

Triangle length = ?

Sin 41 = X/ 6•

then rewrite

X = 6• Sin 41 =

. = 6 • 0.65

. = 3.9

Then answer is

Missing side X = 3.9

.

Find the slope of the line containing the points p1 and p2. P1(-5,3) P2( 5, 1)

Answers

Given the line passing through the points P1 and P2

The coordinates of the points are;

P1: ( -5, 3 )

P2: ( 5, 1 )

The slope of the line is given by the formula;

[tex]slope=\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1}[/tex]

Substitute with the given points:

[tex]slope=\frac{1-3}{5-(-5)}=\frac{1-3}{5+5}=\frac{-2}{10}=-\frac{1}{5}[/tex]

So, the answer will be the slope = -1/5

The longer leg of a right triangle is 7 cm longer than the shorter leg. The hypotenuse is 9cm longer than the shorter leg. Find the side lengths of the triangle.

Answers

Given:

a.) The longer leg of a right triangle is 7 cm longer than the shorter leg.

b.) The hypotenuse is 9cm longer than the shorter leg.

Let,

a = length of the longer leg

b = length of the shorter leg

c = length of the hypotenuse

We get,

Equation 1:

a = b + 7

c = b + 9

Since it's been mentioned that the figure is a right triangle, we will be using the Pythagorean Theorem in getting the measure of the sides.

[tex]\text{ a}^2+b^2=c^2[/tex][tex]\text{ (b + 7)}^2+b^2=(b+9)^2[/tex][tex]\text{ b}^2+14b+49+b^2=b^2\text{ + 18b + 81}[/tex][tex]\text{ 2b}^2+14b+49\text{ - }b^2\text{ - 18b - 81 = 0}[/tex][tex]\text{ b}^2\text{ - 4b - 32 = 0}[/tex]

[tex]\mleft(b^2+4b\mright)+\mleft(-8b-32\mright)\text{ = 0}[/tex][tex]b\mleft(b+4\mright)-8\mleft(b+4\mright)\text{ = 0}[/tex]

[tex]\mleft(b+4\mright)\mleft(b-8\mright)\text{ = 0}[/tex]

Therefore,

b = -4 (b + 4)

b = 8 (b - 8)

Since a length is never a negative value, we can therefore conclude that the measure of the shorter leg is 8 cm.

ANSWER:

Longer leg = shorter leg + 7 = 8 + 7 = 15 cm

Hypotenuse = shorter leg + 9 = 8 + 9 = 17 cm

Shorter leg = 8 cm

Solve the question Find 85% of 360°.

Answers

ANSWER

[tex]\text{ 360}\degree[/tex]

EXPLANATION;

Follow the steps below to evaluate the given expression

[tex]\text{ Part = percentage }\times\text{ whole}[/tex]

Let percentage = 85%

whole = 360

Let x = part

[tex]\begin{gathered} \text{ x = 85\% }\times\text{ 360} \\ \text{ x = }\frac{\text{ 85}}{\text{ 100}}\times\text{ 360} \\ \\ \text{ x = }\frac{\text{ 85 }\times\text{ 360}}{\text{ 100}} \\ \\ \text{ x = }\frac{\text{ 30600}}{\text{ 100}} \\ \text{ x = 306}\degree \end{gathered}[/tex]

[tex]\text{ Hence, 85\% of 360}\degree\text{ is 306}\degree[/tex]

A cooler contains four colas, seven root beers, and four ginger ales. Three people grab a drink at random, one at a time.a) What is the probability that the first person grabs a cola, the second person grabs a ginger ale, and the third person grabs a cola? b) What is the probability that the third person grabs a root beer given that the first two grabbed colas?

Answers

Given:

• Number of colas = 4

,

• Number of robot beers = 7

,

• Number of ginger ales = 4

Where:

Total number if drinks = 4 + 7 + 4 = 15

Given that 3 people grab a drink at random, one at a time.

Let's solve for the following:

• (a). What is the probability that the first person grabs a cola, the second person grabs a ginger ale, and the third person grabs a cola?

• Probability the first person grabs a cola is:

[tex]P(first\text{ cola\rparen=}\frac{number\text{ of colas}}{total\text{ number of drinks}}=\frac{4}{15}[/tex]

• Probability second person grabs a ginger is:

[tex]P(second\text{ ginger\rparen=}\frac{number\text{ of ginger ales}}{total\text{ number -1}}=\frac{4}{15-1}=\frac{4}{14}=\frac{2}{7}[/tex]

The probability the third prson grabs a cola is:

[tex]P(third\text{ cola\rparen=}\frac{4-1}{15-2}=\frac{3}{13}[/tex]

Therefore, the total probability will be:

[tex]\begin{gathered} P=\frac{4}{15}*\frac{2}{7}*\frac{3}{13} \\ \\ P=\frac{4*2*3}{15*7*13} \\ \\ P=\frac{24}{1365} \\ \\ P=\frac{8}{455} \end{gathered}[/tex]

Therefore, the probability that the first person grabs a cola, the second person grabs a ginger ale, and the third person grabs a cola is 8/455.

• (b). What is the probability that the third person grabs a root beer given that the first two grabbed colas?

The probability will be:

[tex]\begin{gathered} P=\frac{4}{15}*\frac{3}{14}*\frac{7}{13} \\ \\ P=\frac{4*3*7}{15*14*13} \\ \\ P=\frac{84}{2730} \\ \\ P=\frac{2}{65} \end{gathered}[/tex]

Therefore, the probability that the third person grabs a root beer given that the first two grabbed colas is 2/65.

ANSWER:

• (a). 8/455

• (b). 2/65

which congruence postulate or theorem can prove that angle ABD = angle CDB?

Answers

Given :

[tex]\bar{AB}\cong\bar{CD}[/tex]

and

[tex]\bar{BC}\cong\bar{AD}[/tex]

Required: Congruency postulate

Explanation: In triangle ABD and triangle CDB

[tex]\bar{AB}\cong\bar{CD}[/tex][tex]\bar{BC}=\bar{AD}[/tex]

and

[tex]\bar{BD}=\bar{BD}[/tex]

Therefore, by SSS (Side Side Side) congurency theorem

Triangle ABD is congurent to triangle CDB.

Final Answer: Option 2 is correct

The points (−5, 14) and (7, r) lie on a line with slope 5. Find the missing coordinate r. r=

Answers

EXPLANATION :

Recall the slope formula :

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

From the problem, we have the points (-5, 14) and (7, r).

The slope of the line is m = 5

Using the formula above :

[tex]\begin{gathered} 5=\frac{r-14}{7-(-5)} \\ \\ 5=\frac{r-14}{12} \\ \\ \text{ Cross multiply :} \\ \\ 5(12)=r-14 \\ 60=r-14 \\ r=60+14 \\ r=74 \end{gathered}[/tex]

ANSWER :

The value of r is r = 74

Question:A study of several cities show positive correlation between 2% of people biking to work and 2% of people spending their vacation time at home. Which statement is most likely true? A. Correlation implies causation,therefore, vacationing at home makes people want to ride thief bike.B. Correlation does not imply causation,therefore,the correlation is due to a third variable: cost of milkC. Correlation does not imply causation,therefore,the correlation is due to a third varabile: cost of gas

Answers

The study shows positive correlation between 2% of people biking to work and 2% of people spending their vacation time at home .

Which of the binomials below is a factor of this trinomial? 10x^2 + 27x - 28A. 2x - 7B. x + 7C. 2x + 7D. x - 7

Answers

Solutions

Which of the binomials below is a factor of this trinomial?

[tex]10x^2+27x-28[/tex]

Factorise the trinomial

[tex]\begin{gathered} 10x^2+27x-28 \\ 10x^2+35x-8x-28 \\ 5x^(2x+7)-4(2x+7) \\ (5x-4)(2x+7) \end{gathered}[/tex]

Therefore the correct answer is:

[tex]2x+7[/tex]

Option C

A library has a book sale to raise money. Hardcover books cost $4 each. Paperback books cost $2 each. Marvin goes to the sale and buys 12 total books. He spends $36. Write and solve a system of linear equations to find the numberof hardcover and paperback books he purchased.

Answers

This problem will lead us to a system of simultaneous equations.

Let x represent hardcover books,

Let y represent paperback books,

Therefore, we have:

[tex]\begin{gathered} x+y=12\ldots(1) \\ 4x+2y=36\ldots(2) \end{gathered}[/tex]

We will solve via the elimination method.

[tex]\begin{gathered} \text{ We multiply eqn 1 by 2 and eqn 2 by 1 to get:} \\ 2x+2y=24\ldots(3) \\ 4x+2y=36\ldots(4) \\ \text{ Subtract eqn 3 from 4 to get:} \\ 2x=12 \\ \text{Divide both sides by 2 to get:} \\ x=\frac{12}{2}=6 \end{gathered}[/tex]

Having solved for x, we substitute this value of x into equation q to get y as:

[tex]\begin{gathered} 6+y=12 \\ \text{ We subtract 6 from both sides to get:} \\ y=12-6=6 \end{gathered}[/tex]

x = 6,

y = 6

. You have budgeted $48.50 to purchase books and CD's for your toddler. Each book costs an average of$3.95 and each CD costs an average of $3.10. Because the shelf you are storing them on is only so big, youhave decided you will not purchase over 14 books and CD's combined. You are going to resell the booksand want to make a maximum profit. You will make a profit of 5$ for each book and 4$ each CD.a. Write a system of linear inequalities to find the possible amounts that can be purchased.

Answers

We have to write a system of inequalities to find the possible amount od CD's and books that can be purchased.

The profit function can be expressed as the sum of the profit of each piece multiplied by the number of CD's or books.

If C is the number of CD's and B is the number of books, we can write:

[tex]P(C,B)=5B+4C[/tex]

The constraints are:

- The budget, that is $48.50.

- The space in the shelf, that fits 14 items.

Then, we can write that the sum of the money spent on CD's and the money spent on books should be equal or less than $48.50:

[tex]3.95\cdot C+3.10\cdot B\le48.50[/tex]

For the shelf, we can write that the sum of CD's and books is equal or less than 14:

[tex]C+B\le14[/tex]

Answer:

a) The linear inequalities (constraints) for this problem are:

3.95C + 3.10B ≤ 48.50

C + B ≤ 14

Write an inequality from the sentence. The product of a number and 7 more than 5 is no more than 21.

Answers

Answer:

[tex]7x+5\leq21[/tex]

Explanation:

Let the unknown be x

The product of the number and 7 more than 5 is expressed as 7x + 5

If this no more than 21, then 7x + 5 must be less than or equal to 21 as shown;

[tex]7x+5\text{ }\leq\text{ 21}[/tex]

Hence the product of a number and 7 more than 5 is no more than 21 is expressed as 7x+5 <= 21

In AQRS, ZR = ZQ, QR = 11 and SQ = 8. Find the length of RS.

Answers

To solve the exercise it may be a little more practical to graph the QRS triangle:

Since two of the angles of the QRS triangle are congruent, that is, they measure the same, then the QRS triangle is isosceles. This implies that the SQ and SR sides measure the same.

Therefore, the length of RS is 8.

12) Complete the table for m(x) = 5 – x. Show your work in the space below.X m(x)3-98-8.6

Answers

Answer:

X | m(x)

3 | 2

-9 | 14

8 | - 3

-8 | 13

6 | - 1

Step-by-step explanation:

We are given the following function:

m(x) = 5 - x

Now we have to find the values of m for the values of x given.

Finding the values:

When x = 3.

m(3) = 5 - 3 = 2

When x = -9

m(-9) = 5 - (-9) = 5 + 9 = 14

When x = 8

m(8) = 5 - 8 = -3

When x = -8

m(-8) = 5 - (-8) = 5 + 8 = 13

When x = 6

m(6) = 5 - 6 = -1

Table:

X | m(x)

3 | 2

-9 | 14

8 | - 3

-8 | 13

6 | - 1

Find the inverse of the following function. gx= 1/x-2

Answers

In order to find the inverse function of g(x) = 1/x - 2, we just need to switch g(x) for x and x for g-1(x), then we isolate the inverse function g-1(x):

[tex]\begin{gathered} g(x)=\frac{1}{x}-2 \\ x=\frac{1}{g^{-1}(x)}-2 \\ \frac{1}{g^{-1}(x)}=x+2 \\ g^{-1}(x)=\frac{1}{x+2} \end{gathered}[/tex]

So the inverse function is g-1(x) = 1/(x+2)

a Bismuth-210 has a half-life of about 5 days. After 17 days, how many milligrams of a 1,728 mg sample will remain? Round answer to the nearest tenth place. If answer does not have tenths place use a zero so that it does.

Answers

Step-by-step explanation:

We have been given that Bismuth-210 has a half-life of about 5 days.

To solve our given problem we will use half-life formula.

[tex]y=a\times(\frac{1}{2})^{\frac{t}{b}}[/tex]

Where,

a = Initial value,

t = Time,

b = half-life.

Given:

[tex]\begin{gathered} a=1728mg \\ t=17 \\ b=5 \end{gathered}[/tex]

Therefore,

[tex]y=1728(\frac{1}{2})^{\frac{17}{5}}[/tex]

Simplify

[tex]y=163.69738\approx163.7mg[/tex]

Hence, the answer is

[tex]163.7mg[/tex]

Let f(x) = x + 2 and g(x) = 2x^2. Perform the function operation, (f.g)(x),and then find the domain of the result. (^2 means raised to the power of 2,or it is an exponent.)

Answers

Given the function f(x) and g(x) defined as follows:

[tex]\begin{gathered} f(x)=x+2 \\ g(x)=2x^2 \end{gathered}[/tex][tex]\begin{gathered} (f\mathrm{}g)(x)=f(x)\cdot g(x) \\ =2x^2(x+2) \\ (f\cdot g)(x)=2x^3+4x^2 \end{gathered}[/tex]

The domain of a function is the set of all possible values of x.

Since x can take on any value in (f.g)(x), we say the domain of the function is the set of real numbers, R.

How would I use the Triangle Proportionality Theorom and/or the Triangle Angle for an equation like this?

Answers

Triangle proportionality theorem states that if a line is parallel to one side of a triangle and it intersects the other two sides, then it divides those sides proportionally

From the figure

DE is parallel to BA

That is DE || BA

Therefore, we have

CD / BD = CE / AE

CD = 9.5

BD = x

CE = 13.75

AE = 5.5

Substitute the above values into the above equation

9.5 / x = 13.75 / 5.5

Introduce cross multiplication

9.5 * 5.5 = 13.75 * x

52.25 = 13.75x

Re - arrange the equation

13.75x = 52.25

Divide both sides by 13.75

13.75x / 13.75 = 52.25 / 13.75

x = 52.25 / 13.75

x = 3.8

The answer is 3.8

Can you please help me

Answers

To solve this question we need to use the tangent of 49º. In this case, this is given by:

tan 49º = 14/x

x = 14/(tan 49º)

Now, using a calculator, we find that

tan 49º = 1.15 (approximately)

Therefore, using this value, we find:

x = 14/1.15 = 12.17

help me out with this question

Answers

We have to calculate the probability of having at least 7 defects in a 26 sq ft metal sheet.

The number of defects is modeled by a Poisson distribution with an average umber of defects of 4 defects per 16 sq ft.

We can write the parameter rate as:

[tex]r=\frac{4\text{ defects}}{16\text{ sq ft}}=0.25\text{ defect per sq ft}[/tex]

Then, we have to calculate the probability of having at least 7 defects in a 26 sq ft metal sheet.

The probability can be calculated as:

[tex]P(k\ge7)=1-P(k<7)=1-\sum ^6_{k=0}P(k)[/tex]

The parameter, average number of defects, for this metal sheet can be calculated as:

[tex]r\cdot S=\frac{0.25\text{ defects}}{\text{sqft}}\cdot26\text{ sqft}=6.5\text{ defects}[/tex]

Then, we can calculate all the probabilities from k=0 to k=6 as:

[tex]\begin{gathered} P(0)=6.5^0\cdot e^{-6.5}/0!=1*0.0015/1=0.002 \\ P(1)=6.5^1\cdot e^{-6.5}/1!=6.5*0.0015/1=0.01 \\ P(2)=6.5^2\cdot e^{-6.5}/2!=42.25*0.0015/2=0.032 \\ P(3)=6.5^3\cdot e^{-6.5}/3!=274.625*0.0015/6=0.069 \\ P(4)=6.5^4\cdot e^{-6.5}/4!=1785.0625*0.0015/24=0.112 \\ P(5)=6.5^5\cdot e^{-6.5}/5!=11602.9063*0.0015/120=0.145 \\ P(6)=6.5^6\cdot e^{-6.5}/6!=75418.8906*0.0015/720=0.157 \end{gathered}[/tex]

Then, we can calculate:

[tex]\begin{gathered} P(x\ge7)=1-P(x<7) \\ P(x\ge7)=1-(0.002+0.01+0.032+0.069+0.112+0.145+0.157) \\ P(x\ge7)=1-0.525 \\ P(x\ge7)=0.475 \end{gathered}[/tex]

The probability of having 7 or more defects in the 26 sq ft metal sheet is 0.475.

Linda graphed a system of equations and found that it had no solution. Which could be the system of equations that Linda graphed? A: 3y = 2x + 4 y = 3/2xB: y = 2/3x + 1 3y = 2x + 3C: 2x + y = 4 y = -2x - 1D: y = 1/2x + 3 y = 1/3x + 3

Answers

The equations that has no solution is

[tex]\begin{gathered} 2x+y=4 \\ y=-2x-1 \\ 2x+y=4 \\ 2x+y=-1 \\ 2x-2x=0 \\ y-y=0 \\ 4-(-1)=5 \\ \\ \text{Therefore, the equation} \\ 2x+y=4 \\ y=-2x-1 \\ \text{has no solution} \end{gathered}[/tex]

Find the value of x. (geometry) (image attached)thank you ! :)

Answers

Given the figure of a polygon that has 4 sides

So, the sum of the interior angles = 360

But the given angles are the supplementary angles for the polygon

so, the angles of the polygon will be as follow:

180 - 6x

180 - 5x

180 - (x+16)

180 - (3x-1)

the sum of the angles = 360

So, we can write the following equation:

[tex]4*180-(6x+5x+x+16+3x-1)=360[/tex]

Solve the equation to find (x), combine the like terms:

[tex]\begin{gathered} 720-(15x+15)=360 \\ 720-15x-15=360 \\ -15x=360-720+15 \\ -15x=-375 \\ x=\frac{-345}{-15}=23 \end{gathered}[/tex]

So, the answer will be x = 23

Lauren's vet commented that her puppy games 10% and weight since the first visit write an expression that could be evaluated to show the puppies current weight. Use a variable to represent the weight of the puppy at the first visit write the expression in simplified form. If the puppy gaind another 10% and weight from the current visit to a future visit how much will the puppy weigh ?write an expression that could be evaluated to show the puppies future weight write the expression in simplified form

Answers

Answer:

Current weight = 1.1W

Future weight = 1.21W

Explanation:

Let's call W the initial weight of the puppy at the first visit.

If the puppy gained 10% in weight since the first visit, the current weight of the puppy will be the initial weight plus 10% of the initial weight.

Then, if we call C the current weight of the puppy, the expression will be:

C = W + 10%(W)

C = W + 0.1W

So, simplifying, we get:

C = 1.1W

Now, let's call the future weight A. So If the puppy gained another 10% and weight from the current visit to a future visit, the expression that gives us the future weight is:

A = C + 0.1C

A = 1.1C

Since C is equal to 1.1W, we can rewrite the expression for future weight A as:

A = 1.1*(1.1W)

A = 1.21W

Therefore, the expressions for the current and future weight are:

C = 1.1W

A = 1.21W

Where W is the initial weight of the puppy.

I posted the question in two halves that go together.

Answers

Looking at the diagram, we were told that angle QPs is equivalent to angle TPR

Also,

angle SPR + angle SPT = angle TPR

angle SPR = angle TPR - angle SPT

Again,

angle QPR + angle SPR = angle QPS

angle SPR = angle QPS - angle QPR

Therefore,

angle TPR - angle SPT = angle QPS - angle QPR

A survey or is conducting measures to see how wide a river is between points A and B. Using her surveying instrument, she creates two similar right triangles. AABC - AEDC, CE = 34 meters, DE=16 meters, and AC=85 meters. What is the distance between A and B? A C D B E O A) 24 m OB) 36 m OC) 40 m OD) 48 m

Answers

We have that the ratio is

[tex]\frac{AC}{CE}=\frac{85}{34}[/tex]

So to find the AB we need to do

[tex]\begin{gathered} AB\text{ = }DE\cdot\text{ }\frac{85}{34} \\ =\text{ }16\cdot\text{ }\frac{84}{34} \\ =\text{ }39,529411765 \end{gathered}[/tex]

The answer is AB = 40 m, option C.

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