The answer to part A is 7 and the answer to part B is 51. Solve part C.

The Answer To Part A Is 7 And The Answer To Part B Is 51. Solve Part C.
The Answer To Part A Is 7 And The Answer To Part B Is 51. Solve Part C.

Answers

Answer 1
Explanation

The ways a waiter and a dishwasher are paid are different. A waiter has a flat $25 dollars daily wage so despite having a lower payment per hour than a dishwasher is logical and expected that a waiter earns more money in the short run. However, as working hours increase the inportance of that fixed daily payment decreases and the contribution to the total payment given by the payment per hour begins to dominate.

It's easy to see this in the graph of both wages. Both are straight lines but the one representing a waiter's wage starts with an offset whereas that of a dishwasher starts at 0. However, since the later receives a better hourly payment the slope of its graph is higher and at some point it surpasses the wage of the waiter. This also happens at a reasonable number of hours (7 hours) because the difference between payments per hour (which define the slopes of the lines) is not minimal.


Related Questions

One of the Boston Red Sox's player has the following stats thus far this season. He has been to bat (at-bat) 619 times and had 190 hits, that consisted of 50 doubles, 4 triples, and 31 homeruns. What is his slugging Avg?

Answers

Answer:

His slugging average is 0.551.

Step-by-step explanation:

Slugging average:

Sum of:

Singles multiplied by 1.

Doubles multiplied by 2.

Triples by 3.

Home runs by 4.

Divided by:

Number of at bats.

This player:

190 hits(singles + doubles + triples + homeruns)

His number of singles is:

190 - (50+4+31) = 190 - 85 = 105

His slugging average is given by:

[tex]S=\frac{1\ast105+2\ast50+3\ast4+4\ast31}{619}=\frac{105+100+12+124}{619}=0.551[/tex]

His slugging average is 0.551.

Choy has $25 in his lunch account at school. He spends $3 each day to eat in the cafeteria, What is Choy's lunch account balance after two weeks of buying his lunch in the cafeteria?

Answers

First of all, we need to write a function or equation that describes the behavior of Choy's lunch account at school.

if x will be the numbers of days, y will be the amount of money in his account, then=

[tex]y(x)=25-3x[/tex]

Now, after two weeks = 5*2 = 10 days, we need to find y(10) replacing x= 10 in the previous equation, like this:

[tex]\begin{gathered} y(x)=25-3x \\ y(14)=25-3(10) \\ y(14)=25-30 \\ y(14)=-5 \end{gathered}[/tex]

Finally, the balance on his account is a debt of 5 dollars.

Draw a point that belongs to the solution region of this system of inequalities

Answers

Given:

The inequality is:

[tex]\begin{gathered} y>1.5^x+4 \\ \\ y<\frac{2}{3}x+6 \end{gathered}[/tex]

Find-:

Graph of inequality

Explanation-:

The graph of inequality is:

[tex]y>1.5^x+4[/tex]

The graph of ineqaulity

[tex]y<\frac{2}{3}x+6[/tex]

The solution for both inequalities is:

write each phrase as an algebraic expression: three more than x

Answers

Recall that the phrase:

n more than m

in algebraic notation is:

[tex]m+n\text{.}[/tex]

Therefore, the phrase:

three more than x

in algebraic notation is:

[tex]x+3.[/tex]

Answer:

[tex]x+3.[/tex]

Find the vertex and write the quadratic function in vertex form (which our OpenStax textbook also calls the standard form).f(x)=x^2−10 x + 74 Give the vertex. Enter your answer as a point (a,b) .Vertex:Enter the coordinates of the vertex to write f(x) in vertex form:f(x)=(x− )^2+

Answers

We have the parabola equation in standard form:

[tex]y=ax^2+bx+c[/tex]

and we need to convert it into a vertex form:

[tex]y=A(x-h)^2+k[/tex]

In order to obtain it, we can note that

[tex]f(x)=x^2-10x+74[/tex]

can be rewritten as

[tex]f(x)=(x-5)^2-25+74[/tex]

this is because

[tex](x-5)^2=x^2-10x+25[/tex]

From our last result, we have

[tex]f(x)=(x-5)^2+49[/tex]

By comparing this result with the general vertex form, we can note that

[tex]\begin{gathered} A=1 \\ h=5 \\ k=49 \end{gathered}[/tex]

Therefore, the equation in vertex form is given by:

[tex]f(x)=(x-5)^2+49[/tex]

with vertex:

[tex](h,k)=(5,49)[/tex]

THE LIFETIME OF A BATTERY USED IN A SMOKE ALARM IS NORMALLY DISTRIBUTED WITH A MEAN OF 4,000 HOURS AN A STANDARD DEVIATION OF 600 A. FIND THE % OF BATTERIES THAT WILL LAST BETWEEN 4120 AND 4720 HOURS? B.IF 500,000 BATTERIES ARE PRODUCED HOW MANY WILL LAST UP TO 4600 HOURS?

Answers

Answer:

A) 30.6%

B) 420,500 batteries

Explanations:

A) First, we need to convert the range of number of hours to z-scores, this can be expressed as:

[tex]z=\frac{x-\overline{\mu}}{\sigma}[/tex]

where

µ is the mean value

σ is the standard deviation

If the number of hours is 4120 hours, then the z-score will be;

[tex]\begin{gathered} z_1=\frac{4120-4000}{600} \\ z_1=\frac{120}{600} \\ z_1=0.2 \end{gathered}[/tex]

If the number of hour is 4720 hours, then the z-score wil be;

[tex]\begin{gathered} z_2=\frac{4720-4000}{600} \\ z_2=\frac{702}{600} \\ z_2=1.2 \end{gathered}[/tex]

The equivalent z-score will be;

[tex]0.2Find the equivalent probability[tex]\begin{gathered} P(0.2Hence the percentage of batteries that will last between 4120 and 4720 hours is 30.6%

B) In order to determine the total batteries that will last up to 4600 hours if the there are 500,000 batteries, we will have;

[tex]\begin{gathered} z=\frac{4600-4000}{600} \\ z=\frac{600}{600} \\ z=1 \end{gathered}[/tex]

Such that;

[tex]P(z<1)=0.8413=84.13\%[/tex]

Find the required number of batteries

[tex]\begin{gathered} Total\text{ batteries<}0.8413\times500,000 \\ Total\text{ batteries}<420650batteries \\ Total\text{ batteries}=420,500 \\ \end{gathered}[/tex]

Since 420,500 is less than the calculated, hence the total batteries that will last up to 4600 hours is 420,500 batteries

Find the true value and round to three decimal places

Answers

Given:

[tex]\cos 53.75\text{ degr}ees[/tex]

Asked: Find the trigonometric value.

ANSWER: 0.5913096484

Rounded to three decimal points = 0.591

7 friend used 1/4 cuos of flour in their cske recipe. How many cups of flour were used altogether? Expess your answer in a mixed number

Answers

1 3/4 cups of flour were used altogether

Explanation:

Quantity used by each friend = 1/4 cups of flour

There are 7 friends

The total number of cups used all together:

[tex]\begin{gathered} =\frac{1}{4}\text{cups of flour }\times\text{ }7\text{ friends} \\ =\text{ 7/4} \end{gathered}[/tex]

The total number of cups used all together = 7/4

In mixed fraction = 1 3/4 cups of flour were used altogether

Which of the following circumstances would likely make the quadratic formula, completing the square, or factoring the best method for solving a quadratic equation?

Answers

[tex]\begin{gathered} \text{ Remember that when you have a square difference that is } \\ \text{ an algebraic expression which looks like this. } \\ a^2-b^2 \\ \text{That expression could be factored as follows. } \\ a^2\text{ }-b^2=(a-b)(a+b) \\ \text{And if you equal that to zero, it would look like this. } \\ (a-b)(a+b)=0 \\ \text{Therefore } \\ a=-b\text{ } \\ or\text{ } \\ a=b \\ \text{ That is much easier than applying the quadratic formula. } \end{gathered}[/tex]

Divide. 9(cos(11π/6) +sin(11π/6))3√3(cos(π/4) +i sin(π/4)) Enter your answer by filling in the boxes. Enter all values as exact values in simplest form. (Cos () +i sin ()

Answers

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given expression

[tex]\frac{9(cos(\frac{11x}{6})+isin(\frac{11x}{6}))}{3\sqrt{3}(cos(\frac{\pi}{4})+isin(\frac{\pi}{4}))}[/tex]

STEP 2: Simplify the expression

[tex]3\sqrt{3}\left(\cos\left(\frac{\pi}{4}\right)+i\sin\left(\frac{\pi}{4}\right)\right)=3\sqrt{3}\left(i\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}\right)[/tex]

STEP 3: Rewrite the expression

[tex]=\frac{9\left(\cos \left(\frac{11x}{6}\right)+i\sin \left(\frac{11x}{6}\right)\right)}{3\sqrt{3}\left(i\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}\right)}[/tex]

Divide the numbers:

[tex]\begin{gathered} \mathrm{Divide\:the\:numbers:}\:\frac{9}{3}=3 \\ =\frac{3\left(\cos \left(\frac{11x}{6}\right)+i\sin \left(\frac{11x}{6}\right)\right)}{\sqrt{3}\left(i\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}\right)} \end{gathered}[/tex]

STEP 4: Apply Radical rule

[tex]\begin{gathered} \mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}} \\ \sqrt{3}=3^{\frac{1}{2}} \\ =\frac{3\left(\cos \left(\frac{11x}{6}\right)+i\sin \left(\frac{11x}{6}\right)\right)}{3^{\frac{1}{2}}\left(i\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}\right)} \end{gathered}[/tex]

STEP 5: Apply Exponent rule

[tex]\begin{gathered} \mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b} \\ \frac{3^1}{3^{\frac{1}{2}}}=3^{1-\frac{1}{2}} \\ =\frac{3^{-\frac{1}{2}+1}\left(\cos \left(\frac{11x}{6}\right)+i\sin \left(\frac{11x}{6}\right)\right)}{\frac{\sqrt{2}}{2}+i\frac{\sqrt{2}}{2}} \\ \mathrm{Subtract\:the\:numbers:}\:1-\frac{1}{2}=\frac{1}{2} \\ =\frac{3^{\frac{1}{2}}\left(\cos \left(\frac{11x}{6}\right)+i\sin \left(\frac{11x}{6}\right)\right)}{\frac{\sqrt{2}}{2}+i\frac{\sqrt{2}}{2}} \end{gathered}[/tex]

STEP 6: Apply Radical rule

[tex]\begin{gathered} \mathrm{Apply\:radical\:rule}:\quad \:a^{\frac{1}{n}}=\sqrt[n]{a} \\ 3^{\frac{1}{2}}=\sqrt{3} \\ =\frac{\sqrt{3}\left(\cos \left(\frac{11x}{6}\right)+i\sin \left(\frac{11x}{6}\right)\right)}{\frac{\sqrt{2}}{2}+i\frac{\sqrt{2}}{2}} \\ \text{By Multiplication,} \\ i\frac{\sqrt{2}}{2}=\frac{\sqrt{2}i}{2} \\ =\frac{\sqrt{3}\left(\cos \left(\frac{11x}{6}\right)+i\sin \left(\frac{11x}{6}\right)\right)}{\frac{\sqrt{2}}{2}+\frac{\sqrt{2}i}{2}} \end{gathered}[/tex]

STEP 7: Combine the fractions

[tex]\begin{gathered} \frac{\sqrt{2}}{2}+\frac{\sqrt{2}i}{2}=\frac{\sqrt{2}+\sqrt{2}i}{2} \\ =\frac{\sqrt{3}\left(\cos \left(\frac{11x}{6}\right)+i\sin \left(\frac{11x}{6}\right)\right)}{\frac{\sqrt{2}+\sqrt{2}i}{2}} \\ \mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{\frac{b}{c}}=\frac{a\cdot \:c}{b} \\ \frac{\sqrt{3}\left(\cos \left(\frac{11x}{6}\right)+i\sin \left(\frac{11x}{6}\right)\right)\cdot \:2}{\sqrt{2}+\sqrt{2}i} \end{gathered}[/tex]

STEP 8: Factor out common term

[tex]\begin{gathered} =\frac{\sqrt{3}\left(\cos \left(\frac{11x}{6}\right)+i\sin \left(\frac{11x}{6}\right)\right)\cdot \:2}{\sqrt{2}\left(1+i\right)} \\ =\frac{\sqrt{3}\left(\cos \left(\frac{11x}{6}\right)+i\sin \left(\frac{11x}{6}\right)\right)\sqrt{2}}{1+i} \end{gathered}[/tex]

By simplification,

[tex]=\frac{\sqrt{6}\left(\cos \left(\frac{11x}{6}\right)+i\sin \left(\frac{11x}{6}\right)\right)}{1+i}[/tex]

STEP 9: Rationalize

[tex]\frac{\sqrt{6}\left(\cos\left(\frac{11x}{6}\right)+i\sin\left(\frac{11x}{6}\right)\right)}{1+i}=\frac{\sqrt{6}\left(1-i\right)\left(\cos\left(\frac{11x}{6}\right)+i\sin\left(\frac{11x}{6}\right)\right)}{2}[/tex]

STEP 10: Write the answer in the required form

[tex]\begin{gathered} \frac{\sqrt{6}\left(1-i\right)\left(\cos \left(\frac{11x}{6}\right)+i\sin \left(\frac{11x}{6}\right)\right)}{2} \\ \frac{\sqrt{6}\left(1-i\right)}{2}\times\left(\cos\left(\frac{11x}{6}\right)+i\sin\left(\frac{11x}{6}\right)\right) \\ =\sqrt{\frac{3}{2}}-\sqrt{\frac{3}{2}}i\times(\cos(\frac{11x}{6})+\imaginaryI\sin(\frac{11x}{6})) \end{gathered}[/tex]

ANSWER:

[tex]\sqrt{\frac{3}{2}}-\sqrt{\frac{3}{2}}i\cdot\left(\cos\left(\frac{11x}{6}\right)+i\sin\left(\frac{11x}{6}\right)\right)[/tex]

Which inequality is represented by this graph?5(0.1)(5,0)5-5O A. y >- x+1B. yy<- 6x +1C. 72-*x+1D. ys-x+1

Answers

We can see a graph representing an inequality. We also can see that we have two points (two coordinates) that lie on a line, and since we have a dotted line, we need to use an inequality symbol that does not take into account the values of the line, that is, we need to use < or >.

Now, to find the expression of the inequality on the graph, we need to proceed as follows:

1. Find the equation of the line using the given points: (0, 1) and (5, 0).

We can use the two-point form of the line to find the equation:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

And now we can label both points as follows:

• (0, 1) ---> x1 = 0, y1 = 1

,

• (5, 0) ---> x2 = 5, y2 = 0

And we can substitute these values into the above equation:

[tex]\begin{gathered} y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1}) \\ \\ y-1=\frac{0-1}{5-0}(x-0) \\ \\ y-1=\frac{-1}{5}x \\ \\ y-1+1=-\frac{1}{5}x+1 \\ \\ y=-\frac{1}{5}x+1 \\ \end{gathered}[/tex]

2. We need to use a test point to find the direction of the inequality. Since we can see that the point (0, 0) is part of the shaded part of the inequality, we can substitute this point in the line equation above as follows:

[tex]\begin{gathered} x=0,y=0 \\ \\ 0=-\frac{1}{5}(0)+1 \\ \\ 0<1 \\ \end{gathered}[/tex]

And we can see that the inequality is of the form (<).

Therefore, in summary, the expression that represents the inequality is:

[tex]y<-\frac{1}{5}x+1[/tex]

(Option B).

When 3.9 is added to 6 times a number, the result is 52.5 Find the number.

Answers

Answer: x = 8.1

Explanation:

Let the number be x.

6 times the number = 6x

When 3.9 is added to 6 times a​ number, the result is 52.5. This means that

3.9 + 6x = 52.5

Subtracting 3.9 from both sides, we have

3.9 - 3.9 + 6x = 52.5 - 3.9

6x = 48.6

Dividing both sides by 6, we have

6x/6 = 48.6/6

x = 8.1

The number is 8.1

A track runner ran for 15 minutes, walked for 15 minutes, ran for another 20 minutes, and then stretched in place for 10 minutes.Which graph describes the relationship between runner's total distance and time?

Answers

Note that:

When the track runner runs, he is expected to cover more distance than when walks

When he stretches his body, he is not expected to cover any distance because there is no motion when the body is stretched in place.

By carefully observing the graphs shown, the correct graph will be plotted in the format below:

Long distance for the first 15 minutes

Short distance for the second 15 minutes

Longer distance for the next 20 minutes

No distance covered in the last 10 minutes

Therefore, the only graph that describes the relationship between the runner's total distance and time is option B

Answer:

its A

Step-by-step explanation:

He rested and stretched for 15 minutes, aka he did not move

Find the slope of each line.y=-5x – 1can you help me solve this

Answers

y=-5x – 1

To find the slope y=-5x – 1

we will compare it with the standard slope -intercept equation

which is y=mx + b

where m is the slope and b is the intercept

comparing the two, m=-5

Hence the slope = -5

Which of the following is the point and slope of the equation y+2=(x-8)

Answers

Answer:

y=x-10

Step-by-step explanation:

y+2=(x-8)

y=x-8-2

y=x-10

you can also graph it on any graphing calculator to get the same answer

There are 21 Women on the busThe ratio of Women to Men is 3:2How many people are on the bus all together?

Answers

Given:

Number of women in the bus = 21

Ratio of women to men = 3:2

Let's find the total number if people.

Where:

Total ratio = 3 + 2 = 5

To find the total number of people, we have:

[tex]\frac{3}{5}*x=21[/tex]

Where:

x represents the total number of people.

To solve for x, multiply both sides by 5/3:

[tex]\begin{gathered} \frac{5}{3}*\frac{3}{5}x=21*\frac{5}{3} \\ \\ x=\frac{21*5}{3} \\ \\ x=\frac{105}{3} \\ \\ x=35 \end{gathered}[/tex]

Therefore, the total number of people on the bus is 35.

ANSWER:

35 people

Point C(1,4) is reflected over the line x = 2. Write the coordinates of C'Point D(2,-10) is rotated 90° clockwise about the origin. Write the coordinates of D'Point E(2,-3) is translated using the rule (x,y) --> (x+2,y-2). Write the coordinates of E'

Answers

C' = (3,4)

2.- D = (2, -10)

D' = (-10, -2)

3.- E = (2, -3)

E' = (4, -5)

A rectangular parking lot has an area of 2/3 square miles. The length of the parking lot is 1/6 of a mile. What is the width, in miles, of the parking lot ?

Answers

Answer

Width of the parking lot = 4 miles

Explanation

The area of a rectangle is given as

Area = L × W

where

L = Length of the rectangle = (1/6) mile

W = Width of the rectangle = ?

Area = (2/3) square miles

Area = L × W

(2/3) = (1/6) × W

[tex]\begin{gathered} \frac{2}{3}=\frac{1}{6}\times W \\ \frac{2}{3}=\frac{W}{6} \\ \text{Cross multiply} \end{gathered}[/tex]

3W = (2)(6)

3W = 12

Divide both sides by 3

(3W/3) = (12/3)

W = 4 miles

Hope this Helps!!!

(-3, 1) is translated 1 unit right

Answers

Given point ( -3, 1)

we need to translate it 1 unit right

So, the rule will be:

[tex](x,y)\rightarrow(x+1,y)[/tex]

so, the point after translation will be:

[tex](-3,1)\rightarrow(-2,1)[/tex]

So, the answer will be: ( -2, 1 )

What is the equation of the graph below?On a coordinate plane, a curve crosses the y-axis at (0, negative 1). It has a minimum of negative 1 and a maximum of 1. It goes through 1 cycle at 2 pi.y = cosine (x + pi/2 )y = cosine (x + 2 pi) y = cosine (x + pi/3)y = cosine (x + pi)

Answers

ANSWER:

4th option: y = cosine (x + pi)

STEP-BY-STEP EXPLANATION:

For the function y = cosine (x), when x = 0, y = 1 and when x = , y = -1. The graph shows the opposite, when x = 0, y = -1 and when x = , y = 1, so we must add the same amount x = , for y to be positive 1.

So the equation of the graph would be:

[tex]y=\cos(x+)[/tex]

The correct answer is then the 4th option y = cosine (x + pi)

63. Find CD to the nearest tenth if point Cis at (12, -8) and point Dis at (5, 19).

Answers

Answer

CD - 27.9

Step-by-step explanation:

Point C = (12, -8) and Point D = (5, 19)

CD means the distance between point C and D

[tex]\begin{gathered} CD\text{ = }\sqrt[]{(x1-x2)^2+(y1-y2)^2} \\ \text{where x1 = 12, y1 = -8, x2 = 5, y2 = 19} \\ CD\text{ = }\sqrt[]{(12-5)^2+(-8-19)^2} \\ CD\text{ = }\sqrt[]{7^2+(-27)^2} \\ CD\text{ = }\sqrt[]{49\text{ + 729}} \\ CD\text{ = }\sqrt[]{778} \\ CD\text{ = 27.9} \end{gathered}[/tex]

Hence, CD IS 27.9

I just want to know if I solved it right before I turn it in

Answers

Solving for x in the second equation, we get:

[tex]\begin{gathered} -3x+4y=-13 \\ -3x=-13-4y \\ x=\frac{-13}{-3}-\frac{4y}{(-3)} \\ x=\frac{13}{3}+\frac{4y}{3} \end{gathered}[/tex]

Replacing x on the first one and solving for y, we get:

[tex]\begin{gathered} 2x+5y=1 \\ 2(\frac{13}{3}+\frac{4y}{3})+5y=1 \\ \frac{26}{3}+\frac{8y}{3}+5y=1 \\ \frac{8y}{3}+5y=1-\frac{26}{3} \\ \frac{23}{3}y=\frac{-23}{3} \\ y=-1 \end{gathered}[/tex]

Finally, replacing y by -1, we get:

[tex]\begin{gathered} x=\frac{13}{3}+\frac{4}{3}\cdot(-1) \\ x=\frac{13}{3}-\frac{4}{3} \\ x=3 \end{gathered}[/tex]

Answer: x = 3 and y = -1

What is 13% of 2.1billon? What are the step by step instructions to solve the problem

Answers

The value of 13% of 2.1 billion is Two Hundred Seventy Three Million .

In the question

it is given that

a number is 2.1 billion ,

we have to find the value 13% of 2.1 billion

In order to find the value of 13% of 2.1 billion , we first need to express 2.1 billions in numbers

1 billion = 1000000000

So , 2.1 billion = 2.1*1000000000

= 2100000000

So , 13% of 2100000000 is

= 0.13 × 2100000000

= 273000000

= Two Hundred Seventy Three Million

Therefore , The value of 13% of 2.1 billion is Two Hundred Seventy Three Million .

Learn more about Percent here

https://brainly.com/question/811737

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What will it cost to place baseboard around the region shown if the baseboard costs $0.55 per foot? No baseboard is needed for the 2-foot doorway.

Answers

Answer:

It will cost $19.25 to place the baseboard around the region

Explanation:

The total number of feet that need the baseboard is the perimeter of the region minus 2 ft for the door.

10 ft + 7 ft + (13 - 2) ft + 3 ft + 4 ft = 35 ft

Now the cost is $0.55 per foot; therefore, for 35 ft the cost will be

[tex]cost\text{ per foot }\times number\text{ of feet}=\frac{\$0.55}{ft}\times35ft=\$19.25[/tex]

Hence, the cost to place baseboard around the region will be $19.25.

Find the slope of the line passing through the points (-3, 3) and (5, 9).

Answers

Answer:

slope = [tex]\frac{3}{4}[/tex]

Step-by-step explanation:

calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 3, 3 ) and (x₂, y₂ ) = (5, 9 )

m = [tex]\frac{9-3}{5-(-3)}[/tex] = [tex]\frac{6}{5+3}[/tex] = [tex]\frac{6}{8}[/tex] = [tex]\frac{3}{4}[/tex]

A 14 -inch laptop has a screen that is 7 inches tall. How wide is the screen?

Answers

Answer:

Explanation:

The laptop screens are measured diagonally. Meaning a 13 the laptop has a distance of 14 inches from one corner to the other.

Therefore, to find the width of the laptop screen, we use Pythagoras's theorem.

[tex]7^2+w^2=14^2[/tex]

Now subtracting 7^2 from both sides gives

[tex]w^2=14^2-7^2[/tex][tex]w^2=147[/tex]

taking the square root of both sides gives

[tex]w=\sqrt{147}[/tex]

the radical on the right can be simplified to give

[tex]\boxed{w=7\sqrt{3}}[/tex]

which is our answer!

Hence, the laptop screen is 7√3 inches wide.

Figures I to VI represent one of the six situations described below. Match each graph to the situation it describes. 1 ) the temperature as the weather changes from rainy to snowy_________2) the number of fish caught per hour on a bad fishing day__________ 3) the total amount of rain that falls on a rainy day ____

Answers

1) The temperature when the weather changes from rainy to snowy will decrease over time, then, the figure II represents this situtation.

2)The number of fish caught per hour on a bad fishing day will have an almost constant function (since it was a bad day for fishing) thus, the figure V models this situation.

3)The total amount of rain that falls on a rainy day increases over time. Therefore, the figure IV can be used to represent this situation.

What term best describes 3x + 5?algebraic expressionvariablecoefficientnumeric expression

Answers

Answer:

Algebraic expression

Explanation:

Given the sum:

[tex]3x+5[/tex]

• The ,letter x, is referred to as a ,variable,.

,

• The ,number beside x, that is, 3 ,is referred to as a ,coefficient.

A combination of these two, 3x will give an algebraic term.

Thus, a sum of the algebraic term, 3x and the constant, 5 is best referred to as an algebraic expression.

find the value of expression when a=1/3, b=9, c=5, d=10; expression is 3c + b^2 : 27a - d

Answers

3c + b^2 : 27a - d​

Replace

c with 5

b with 9

a with 1/3

d with 10

And solve:

3 (5) + 9^2 : 27(1/3) - 10

Use PEMDAS to solve in order.

First exponents:

3 (5) + 81 : 27 (1/3) -10

Then multiplications and divisions:

15 + 81 : 9 -10

15+ 9-10

Then add and subtract

14

Find the missing coordinate given m = 4/3 and goes through the points (6, y) and (0,4).

Answers

Here's the slope formula we'll be using

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

The two points will give us the numbers and variable that will replace the subscripted variables in the slope equation.

[tex]\begin{gathered} \frac{4}{3}=\frac{4-y}{0-6} \\ \frac{4}{3}=\frac{4-y}{-6} \\ \frac{4}{3}(-6)=\frac{4-y}{-6}(-6) \\ -8=4-y \\ -8-4=4-y-4 \\ -12=-y \\ y=12 \end{gathered}[/tex]

coordinate: (6,12) and (0,4)

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