the area of a trapezium is given by the formula A=1/2h(a+b), where h is the height and a and b are the measures of the two bases. what is the height of a trapezoid with an area of 24 square inches if the two bases measure 4 inches and 6 inches?

Answers

Answer 1

Answer:

[tex] h = 4.8 \: inches.[/tex]

Step-by-step explanation:

[tex]A= \frac{1}{2} h(a+b) \\ h(a + b) = 2A \\ h = \frac{2A}{(a+b)} = \frac{2 \times24 }{4 + 6} \\ h = \frac{48}{10} \\ h = 4.8 \: inches.[/tex]

Answer 2

Answer:

h=4.8

Given:

area=24 , a=4 , b=6

To find:

height

Step-by-step explanation:

A = [tex]\frac{1}{2}[/tex] × h(a+b)

24 = [tex]\frac{1}{2}[/tex] × h(4+6)

24 × 2 = h(10)

48 = 10h

48/10 = h

h=24/5

h=4.8

therefore, height of the trapezium is 4.8

hope it helps you!

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Answers

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