. The average human walks at a speed of 5 km per hour. If your PE teacher asks you to walk for 30 minutes in
gym class, how far would you walk (km)?

Answer:

50 N

Explanation:

We are given;

Force on larger piston; F2 = 5000 N

Ratio of diameter of smaller piston to larger piston = 1:10

Now, formula for force on smaller piston which we will denote with F1 is gotten from;

F1 = F2 × A1/A2

Now, A1 = π(d1)²/2

A2 = π(d2)²/2

Thus:

F1 = F2 × (π(d1)²/2)/(π(d2)²/2)

This gives;

F1 = F2 × (d1/d2)²

Plugging in the relevant values;

F1 = 5000 × (1/10)²

F1 = 50 N

Answer:

Explanation:

20 watts

Answer:

the force of gravity acting between the earth and any other object is directly proportional to the mass of the earth, directly proportional to the mass of the object, and inversely proportional to the square of the distance that separates the centers of the earth and the object.

Explanation:

Answer:

l

Explanation:

Answer:

true I believe

Explanation:

Answer:

300 pascals

Explanation:

P=F/A

P=15N/0.05

P=300 pascals

A switched-mode power supply (switching-mode power supply, switch-mode power supply, switched power supply, SMPS, or switcher) is an electronic power supply that incorporates a switching regulator to convert electrical power efficiently.

Answer:

A switched-mode power supply (switching-mode power supply, switch-mode power supply, switched power supply, SMPS, or switcher) is an electronic power supply that incorporates a switching regulator to convert electrical power efficiently.

Explanation:

Answer:

the answer is all of the above

Explanation:

brainliest please

Answer:

the number of donated valence electrons

Explanation:

  A metallic bond is formed when atoms come together in a metallic crystal lattice.

The metal atoms are usually ionized such that in a metallic crystal lattice consists of metal ions and a sea of mobile electrons. Attraction between these positively charged ions and the sea of electrons constitutes the metallic bond.

Hence, the more the number of donated valence electrons, the stronger the metallic bond.

Answer:

Troposphere

High-pressure areas form due to downward motion through the troposphere, the atmospheric layer where weather occurs.

Answer:

Momentum is a vector quantity that has the same direction as the velocity of the object. The quantity of force multiplied by the time it is applied is called impulse. Impulse is a vector quantity that has the same direction as the force. Momentum and impulse have the same units: kg·m/s

Explanation:

Hope it helps!

If you dont mind can you please mark me as brainlest?

Answer:

H-Hydrogen

B-Boron

O-Oxygen

Au-Gold

Co-Cobolt

He-Helium

Na-Sodium

S-Sulfur

K-Potassium

Ag-Silver

Explanation:

Normally, chemical symbols are either the first letter or the first two letters of the element.

However, there are some exceptions where they use the Latin names e.g:

Aurum-Au-Gold

Natrium-Na-Sodium

Kalium-K-Potassium

Argentum-Ag-Silver

Hope this helps :)

Answer:

38 cm from q1(right)

Explanation:

Given, q1 = 3q2 , r = 60cm = 0.6 m

Let that point be situated at a distance of 'x' m from q1.

Electric field must be same from both sides to be in equilibrium(where EF is 0).

=> k q1/x² = k q2/(0.6 - x)²

=> q1(0.6 - x)² = q2(x)²

=> 3q2(0.6 - x)² = q2(x)²

=> 3(0.6 - x)² = x²

=> √3(0.6 - x) = ± x

=> 0.6√3 = x(1 + √3)

=> 1.03/2.73 = x

≈ 0.38 m = 38 cm = x

Answer:

friction as friend

friction as foe

hope it helps

Answer:

Wear and tear of soles of our shoes is due to friction.

When a tyre deflates, it is difficult to move the vehicle because of increased friction between the tyre and the road surface.

Machines get heated up and produce noise because of friction.

Answer:

yellow

Explanation:

yellow

make me brain

Answer; Sodium 2-Aminopentanedioate The chemical formula of MSG is C5H8NO4Na and its IUPAC name is sodium 2-aminopentanedioate. Since it is known to intensify meaty flavours in food, monosodium glutamate is widely used as a flavour enhancer in the food industry. This compound was first produced by the Japanese chemist Kikunae Ikeda in the year 1908.

Explanation:

Answer:

953.5 J/kg.°C

Explanation:

From the question,

Heat lost by the metal = heat gained by the glass.

cm(t₁-t₃) = c'm'(t₃-t₂)................. Equation 1

Where c = specific heat capacity of the metal, m = mass of the metal, c' = specific heat capacity of the glass, m' = mass of the glass, t₁ = initial temperature of  metal, t₂ = initial temperature of glass, t₃ = Equilibrium temperature

Make c' the subject of the equation

c' = cm(t₁-t₃)/m'(t₃-t₂)................ Equation 2

Given: m = 5 kg, c = 650 J/kg.°C, m' = 1.25 kg, t₁ = 80 °C, t₂ = 20 °C, t₃ = 63.9 °C

Substitute these values into equation 2

c' = 5×650(80-63.9)/1.25(63.9-20)

c' = (5×650×16.1)/(1.25×43.9)

c' = 52325/54.875

c' = 953.5 J/kg.°C

Answer:

960 J/(kg*C)

Explanation:

i got this right in acellus  trust me :D

Answer:

A. Gravitational force

C. Their charges

Explanation:

As we'll discuss in this lesson, he found that the force between charged particles was dependent on only two factors: the distance between the particles and the amount of electric charge that they carried.

Hope it help you

have a good day :)

Answer:

[tex]m=1.01\times 10^6\ kg[/tex]

Explanation:

Given that,

Pressure, P = 1 atm = 101325 Pa

Area of the square surface, A = 10² = 100 m²

We need to find the mass of vertical column of air. We know that, pressure is equal to the force acting per unit area. So,

[tex]P=\dfrac{mg}{A}\\\\m=\dfrac{PA}{g}\\\\m=\dfrac{101325\times 10^2}{10}\\\\m=1.01\times 10^6\ kg[/tex]

So, the required mass of the vertical column of air is [tex]1.01\times 10^6\ kg[/tex].

Answer: The answer is A

Explanation:

Inner Planets:

- Rocky

- Small

- Only 3 moons total

- Very close to each other (for space)

- Underweight

Outer Planets:

- Gassy oop-

- GIANT

- Over 200 moons total

- VERY far from each other

- Obese

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Good luck foe.

Lb.

Answer:

sound waves

Explanation:

this is because sound waves are longitudinal waves, and longitudinal waves are waves that travel parallel to the direction of the wave motion

thus it cannot be light or electromagnetic waves but only sound waves

hope this helps, please mark it

Answer:

  w = 16.73 rad / s,  v = - 1.04 m / s

Explanation:

This is an exercise in oscillatory motion of a system of a spring and a mass, the angular velocity is

         w = [tex]\sqrt{ \frac{k}{m} }[/tex]

To calculate the spring constant we use the data that Δx = 3.5 cm = 0.035 m with a mass of m = 0.38 kg, let's write Hooke's law

          F = -kx

in this case the applied force is the weight of the body

          F = W

we substitute

          mg =  k x

          k = m g / x

         k = 0.38 9.8 / 0.035

         k = 106.4 N / m

let's find the angular velocity

         w = Ra 106.4 / 0.38

         w = 16.73 rad / s

the movement of this system is described by the expression

          ax = A cos (wt + Ф)

the quantity A is called the amplitude of the movement in this case A = 7.5 cm = 0.075 m

to encode the constant we use that the system is released from its position of maximum displacement (x = A)

we substitute

          A = A cos (0 + Ф)

         cos Ф = 1

         Ф = cos-1 1

         Ф = 0º

by substituting in the equation of motion

            x = 0.075  cos (16.73 t)

Let's find the time it takes to reach the desired position x = 4.2 cm = 0.042 m

           cos 16.73 t = 0.042 / 0.075 = 0.56

            16.73 t = cos -1 0.56

remember that angles must be expressed in radians

            t = 0.976 / 16.73

            t = 0.0583 s

body velocity is

           v = [tex]\frac{dx}{dt}[/tex]

            v = -0.075 16.73 sin 16.73t

let's calculate for the time found

           v = - 1.25475 sin (16.73  0.0583)

           v = - 1.04 m / s

Answer:

Assume that [tex]g =9.81\; \rm m\cdot s^{-1}[/tex], and that the air resistance on the stone is negligible.

a.

Height of the stone: [tex]389.5\; \rm m[/tex] (above the ground.)

Velocity of the stone: [tex]\left(-110.5\; \rm m \cdot s^{-1}\right)[/tex] (the stone is travelling downwards.)

b.

Height of the stone: [tex]629.5\; \rm m[/tex] (above the ground.)

Velocity of the stone: [tex]\left(-86.5\; \rm m \cdot s^{-1}\right)[/tex] (the stone is travelling downwards.)

Explanation:

If air resistance on the stone is negligible, the stone would be accelerating downwards at a constant [tex]a = -g = -9.81\; \rm m \cdot s^{-2}[/tex].

Let [tex]h_0[/tex] denote the initial height of the stone (height of the stone at [tex]t = 0[/tex].)

Similarly, let [tex]v_0[/tex] denote the initial velocity of the stone.

Before the stone reaches the ground, the height [tex]h[/tex] (in meters) of the stone at time [tex]t[/tex] (in seconds) would be:

[tex]\displaystyle h(t) = -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0[/tex].

Similarly, before the stone reaches the ground, the velocity [tex]v[/tex] (in meters-per-second) of the stone at time [tex]t[/tex] (in seconds) would be:

[tex]v(t) = -g\cdot t + v_0[/tex].

In section a., [tex]h_0 = 1000\; \rm m[/tex] while [tex]v_0 = -12\; \rm m\cdot s^{-1}[/tex] (the stone is initially travelling downwards.) Evaluate both [tex]h(t)[/tex] and [tex]v(t)[/tex] for [tex]t = 10\; \rm m \cdot s^{-1}[/tex]:

[tex]\begin{aligned} h(t) &= -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0 \\ &= -\frac{1}{2}\ \times 9.81\; \rm m\cdot s^{-2}\times (10\; \rm s)^{2} \\&\quad\quad + \left(-12\; \rm m \cdot s^{-1}\right) \times 10\; \rm s + 1000\; \rm m \\[0.5em] &= 389.5\; \rm m \end{aligned}[/tex].

Indeed, the value of [tex]h(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is greater than zero. The stone hasn't yet hit the ground, and both the representation for the height of the stone and that for the velocity of the stone are valid.

[tex]\begin{aligned} v(t) &= -g\cdot t + v_0 \\ &= -9.81\; \rm m\cdot s^{-2}\times 10\; \rm s - 12\; \rm m\cdot s^{-1} \\ &= -110.5\; \rm m \cdot s^{-1} \end{aligned}[/tex].

The value of [tex]v(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is negative, meaning that the stone would be travelling downwards at that time.

In section b., [tex]h_0 = 1000\; \rm m[/tex] while [tex]v_0 = 12\; \rm m\cdot s^{-1}[/tex] (the stone is initially travelling upwards.) Evaluate both [tex]h(t)[/tex] and [tex]v(t)[/tex] for [tex]t = 10\; \rm m \cdot s^{-1}[/tex]:

[tex]\begin{aligned} h(t) &= -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0 \\ &= -\frac{1}{2}\ \times 9.81\; \rm m\cdot s^{-2}\times (10\; \rm s)^{2} \\&\quad\quad + 12\; \rm m \cdot s^{-1} \times 10\; \rm s + 1000\; \rm m \\[0.5em] &= 629.5\; \rm m \end{aligned}[/tex].

Verify that the value of [tex]h(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is indeed greater than zero.

[tex]\begin{aligned} v(t) &= -g\cdot t + v_0 \\ &= -9.81\; \rm m\cdot s^{-2}\times 10\; \rm s + 12\; \rm m\cdot s^{-1} \\ &= -86.5\; \rm m \cdot s^{-1} \end{aligned}[/tex].

Similarly, the value of [tex]v(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is negative because the stone would be travelling downwards at that time.

Answer:

The relation between velocity and time is a simple one during uniformly accelerated, straight-line motion. The longer the acceleration, the greater the change in velocity. Change in velocity is directly proportional to time when acceleration is constant.

~Hoped this helped~

~Brainiliest?~

Answer:

We describe motion in terms of velocity and acceleration. Velocity: The rate of change of displacement of an object (displacement over elapsed time) is velocity. Velocity is a vector since it has both magnitude (called speed) and direction. ... Acceleration: The rate of change of velocity is acceleration.

Explanation:

Displacement is a vector which points from the initial position of an object to its final position. ... Instantaneous velocity, on the other hand, describes the motion of a body at one particular moment in time. Acceleration is a vector which shows the direction and magnitude of changes in velocity.

Displacement is the vector difference between the ending and starting positions of an object. Velocity is the rate at which displacement changes with time. ... The average velocity over some interval is the total displacement during that interval, divided by the time.

Hope this helps      :)

Answer:

2m/s^2

Explanation:

Force is equal to;

mass × acceleration

therefore;

acceleration equals

force divided by mass

acceleration = 2m/s ^2

Answer:

f = 60N

m = 30kg

f= m×a

60N= 30 × a

a = 60/30

a = 2

Answer:

nuclear energy

Explanation:

Answer:

40N

Explanation:

Using the newton's second law of motion

\sum Fx = max

Fm - Ff = max

Fm is the applied force

Ff is the frictional force

m is the mas of the cupboard

ax is the acceleration

Since the speed from the lorry is steady, ax = 0m/s^2

Also Ff = 40N

Substitute into  the formula;

Fm - 40 = m(0)

Fm - 40 = 0

Add 40 to both sides

Fm - 40 + 40 = 0 + 40

Fm = 40N

Hence the force with which the man applied to push is 40N