Answer:
0.0009 grams
Step-by-step explanation:
The mass of the grain sand is:
[tex]9 \times {10}^{ - 8} \: Kg[/tex]
To convert kilograms to grams we divide by 1000 (1 × 10³)
[tex] \frac{9 \times {10}^{ - 8} }{1 \times {10}^{3} } [/tex]
Which gives us:
[tex]9 \times {10}^{ - 5} [/tex]
[tex]9 \times {10}^{ - 5} = 0.0009 \: g[/tex]
what’s the answer????
Answer:
3.6 m/h
Step-by-step explanation:
Distance (d) = 9 Km
Time (t) = 2.5 hour
Speed ( s )
Speed = Distance / Time
s = d / t
s = 9 / 2.5
s = 90 / 25
s = 18 / 5
s = 3.6 Km/h
What is the solution to the equation?
Answer: Your answer is X=-63
Hope this helps!
6) The frequency table represents lunch choices for 22 middle school students. Each student may only make one choice. What frequency count should be recorded for the soup category?
-------
A) 2
B) 4
C) 6
D) 8
The frequency count that should be recorded for the soup category is 6.
What does subraction mean?
Subtraction is the process of taking one number away from another number. The sign used to represent subtraction is -.
What is the frequency count for the soup category?The frequency count on the table should be equal to the number of students. Thus, in order to determine the frequency count for the soup category, subtract 22 from the total frequency count.
The frequency count for the soup category = 22 - (5 + 8 + 2 + 1 ) = 6
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Help me out please simple
A straight line is 180 degrees in measure
The straight line is made up of three angles
--> angle 1
--> angle 2
--> angle with a little square on it
(angle with a little square means it is 90 degrees in measure)
Let's set up an equation
[tex]angle1 + angle2 + 90 = 180\\angle1 + 87 + 90 = 180\\angle1 = 3[/tex]
Thus angle 1 is 3 degrees or the second choice
Hope that helps!
Lillian spent 18 minutes practicing her spelling words. How many seconds did she practice?
Answer:
1080 seconds.
Step-by-step explanation:
There are 60 seconds in a minute. As provided in the question, Lillian spent eighteen minutes, so 18x60=1080.
Answer:
1,080 seconds
Step-by-step explanation:
can someone help me really please
Answer:
5/6
Step-by-step explanation:
since there already is a common denominator all you have to do is add the numerators
help to search for JOIN in this alphabet soup please
Answer:
hopefully this helps :] 16th line down I think
What is the mode of the data set?
78, 82, 91, 78, 92, 77, 80, 74, 81
The mode is 78
Step-by-step explanation:Mode: The digit that has been repeated the most in a specific data.
To determine the mode of the data, let's arrange the data in ascending order.
Arranging the data in ascending form, we get:
⇒ 74, 77, 78, 78, 80, 81, 82, 91, 92In the ascending data, we can see that: (Refer to underlined and bolded text)
74 has been repeated once77 has been repeated once78 has been repeated twice80 has been repeated once81, has been repeated once82 has been repeated once91 has been repeated once92 has been repeated onceSince 78 has been repeated the most, 78 is the mode of the data.
solve for x ~
[tex]46x - 23x = 2[/tex]
thankyou ~
Answer: x = 2/23
Step-by-step explanation:
[tex]46x-23x=2[/tex]
[tex]\mathrm{Add\:like\:terms:}\:46x-23x=23x[/tex]
[tex]23x=2[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}23[/tex]
[tex]\frac{23x}{23}=\frac{2}{23}[/tex]
[tex]$$Simplify[/tex]
[tex]\bold{x=\frac{2}{23}}[/tex]
Answer:
x = 2/23Step-by-step explanation:
Inthis question we are given with one equation that is 46x - 23x = 2 and we have asked to find the value of x or solve for x .
So , from here we are solving :
[tex] \longmapsto \: 46x - 23x = 2[/tex]
Step 1 : Taking 23x common at left hand side :
[tex] \longmapsto \: 23x(2 - 1) = 2[/tex]
Step 2 : Subtracting 1 with 2 :
[tex] \longmapsto \:23x = 2[/tex]
Step 3 : Transposing 23 to right hand side :
[tex] \longmapsto \: \red{ \boxed{x = \frac{2}{23} }}[/tex]
Therefore, value of x is 2/23Verifying the answer :
We are verifying our answer by substituting the value of x in the given equation .
[tex] \longmapsto \: 46(\frac{2}{23}) - 23( \frac{2}{23} ) = 2[/tex]
Now , calculating :
[tex] \longmapsto \: \cancel{46}(\frac{2}{ \cancel{23}}) - \cancel{23}( \frac{2}{ \cancel{23}} ) = 2[/tex]
[tex] \longmapsto \: 4 - 2 = 2[/tex]
[tex] \longmapsto \: 2 = 2[/tex]
[tex] \longmapsto \: L.H.S = R.H.S[/tex]
[tex] \longmapsto \: Hence, \: Verified . \: [/tex]
Therefore , our value for x is correct .#Keep Learningplease help with this problem!!
Answer:
12 cups
Step-by-step explanation:
The ratio he uses is
2 parts strong coffee
3 parts milk
Let's say he makes a recipe exactly like the amounts of the ratio.
2 cups strong coffee
3 cups milk
Total: 2 cups + 3 cups = 5 cups
He wants to make 30 cups, so 5 cups is not enough.
Let's double the amounts of the recipe keeping the same ratio of 2 to 3.
2 × 2 = 4 cups strong coffee
3 × 2 = 6 cups milk
Total: 4 cups + 6 cups = 10 cups
He wants to make 30 cups, so 10 cups is not enough.
We can keep on going up by multiplying the numbers in the ratio by larger numbers, but there is a quicker way.
We need to multiply both numbers in the ratio by a number, let's call it x, so that when both numbers in the ratio are multiplled by x, and the ingredients are added, we end up with 30 cups.
Multiply both numbers in the ratio by x.
2x cups of strong coffee
3x cups of milk
Now add: the total amount will be 5x cups
We want 30 cups, so
5x = 30
Solve for x.
x = 30/5 = 6
x, the multiplier we need is 6.
2x cups strong coffee = 2(6) cups = 12 cups
3x cups milk = 3(6) cups = 18 cups
Answer: 12 cups
Critical Thinking: I am a 7-digit number. All my digits are non-zero and distinct, My ones digit is four times the tens digit. • The sum of the ones and tens digits is equal to the sum of the lakhs and ten lakhs digits. • The sum of the ten thousands and thousands digits is equal to the double of the hundreds digit. • The ten lakhs digit is greater than the lakhs digit , and the ten thousands digit is greater than the thousands digit. Find which number I am.
Answer:
3286714
Step-by-step explanation:
Let the digits of the number be :
ABCDEFGOur given conditions :
G = 4F [ones digit is four times the tens digit]G + F = B + A [sum of the ones and tens digits is equal to the sum of the lakhs and ten lakhs digits]C + D = 2E [sum of the ten thousands and thousands digits is equal to the double of the hundreds digit]A > B and C > D [ten lakhs digit is greater than the lakhs digit , and the ten thousands digit is greater than the thousands digit]Solving :
Condition 1 : G is either 1 or 2 and F is either 4 or 8For now, let G be 1 and F be 4 Now G + F = A + BThen A + B = 5 [but not 1 + 4] ⇒ A can be 3 and B can be 2Now C + D = 2E and our remaining numbers are 5,6,7,8,9C and D can be 8 and 6, then their mean would be 7, which is ESolution :
So, the number is :
ABCDEFG32867141. Determine the lateral and total surface area
of the square pyramid.
12 cm
12.8 cm
qom
Lateral Surface Area
Total Surface Area
The areas of the square pyramid are the amount of space on it
The lateral surface area is 307.2 square cmThe total surface area is 451.2 square cmHow to determine the lateral surface area?The given parameters are:
Base (b) = 12 cm
Slant height (l) = 12.8 cm
The lateral surface area is calculated using:
L = 2bl
So, we have:
L = 2 * 12 * 12.8
Evaluate the product
L = 307.2
How to determine the total surface area?This is calculated using:
T = L + b^2
So, we have:
T = 307.2 + 12^2
Evaluate
T = 451.2
Hence, the total surface area is 451.2 square cm
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5 Questions
Financial Mathematics
Questions Attached
Tom has 2 feet of wire. He uses of the wire to hang a picture. How much wire did he use to hang the picture?
A. 2 4/7 feet
B. 1 9/10
C. 1 7/10
D. 1 1/2
Answer:
D. 1 1/2 feet
Step-by-step explanation:
Multiply the numbers to find the length of wire used.
2 1/2 × 3/5 = 5/2 × 3/5 = 3/2 = 1 1/2 feetCorrect choice is D
PLEASW HELP
The number of bats in a colony is growing exponentially. After 4 years, there were 2025 bats. After 6
years, there were 18225 bats.
If the colony continues to grow at the same rate, how many bats are expected to be in the colony after
12 years? Do not include units in your answer.
Answer:
there would be around 40,000 colony of bats
There to be about 13,286,025 bats in the colony after 12 years if the growth rate remains constant.
What is Exponential Growth?An exponential function's curve is created by a pattern of data called exponential growth, which exhibits higher increases over time.
y = a(1+r)ˣ,
where a is the initial population and r is the rate in decimals and x is the time period.
To solve this problem, we need to use the formula for exponential growth:
N = N₀ (1 + r)ˣ
where:
N is the final number of bats after x years
N₀ is the initial number of bats
r is the annual growth rate (expressed as a decimal)
x is the number of years.
We can use the information given in the problem to find the values of N0, r, and t for the first two time periods:
For the first 4 years:
2025 = N₀(1 + r)⁴
For the next 2 years (6 years in total):
18225 = N₀ (1 + r)⁶
To solve for N₀ and r, we can divide the second equation by the first equation:
18225/2025 = (N₀ (1 + r)⁶) / (N₀(1 + r)⁴)
9 = (1 + r)²
Taking the square root of both sides, we get:
1 + r = 3
r = 2 (since r is expressed as a decimal)
Now that we know r, we can use either of the two original equations to find N₀. Let's use the first equation:
2025 = N₀(1 + 2)⁴
2025 = N₀(81)
N₀ = 25
So the initial number of bats was 25, and the annual growth rate is 200% (or 2 as a decimal).
Now we can use the formula to find the number of bats after 12 years:
N = 25 (1 + 2)¹²
N = 25 (531441)
N = 13,286,025
Therefore, we can expect there to be about 13,286,025 bats in the colony after 12 years if the growth rate remains constant.
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HELP MEEEEEE PLESEEE
Answer:
648 cubic centimeters
Step-by-step explanation:
6×9×12=648
Answer:
648 cubic centimeters
Step-by-step explanation:
All you need to do is multiply all of the measures that they show you.
6 x 9 x 12 which equals 648
please help me in this mathematics questionplease help me in this mathematics questionplease help me in this mathematics question
The twenty units of potatoes illustrates the measure of central tendency and probability
The modal weight, mean, and medianStart by sorting the dataset:
0.19; 0.28; 0.55;
0.62; 0.68; 0.77;
0.88; 0.89; 0.98;
0.99; 1.11; 1.22;
1.22; 1.22; 1.33;
1.44; 1.48; 1.68;
1.77; 1.99
The highest occuring element is 1.22 with a frequency of 3
The two middle elements are 0.99 and 1.11.
The mean of these two middle elements is: 0.5 * (0.99 + 1.11) = 1.05
The mean of the whole dataset is:
Mean = (0.19+ 0.28+ 0.55+ 0.62+ 0.68+ 0.77+ 0.88+ 0.89+ 0.98+ 0.99+ 1.11+ 1.22+1.22+ 1.22+ 1.33+ 1.44+ 1.48+ 1.68+1.77+1.99)/20
Mean = 1.06
Hence, the modal weight is 1.22, the mean is 1.06, and the median is 1.05
The probabilities(a) at least 1.1 kg
There are 10 potatoes that weigh at least 1.1 kg.
So, the probability is:
P = 10/20
P = 0.5
(b) more than 3.5kg
There are 0 potatoes that weigh more than 3.5 kg.
So, the probability is:
P = 0/20
P = 0
(c) below 0.50kg
There are 2 potatoes that weigh below 0.50 kg.
So, the probability is:
P = 2/20
P = 0.1
The Variance of the weight.
This is calculated as:
Var = [tex]\sum[/tex](x - mean)^2/n
This gives
Var = [(0.19 - 1.06)^2 + (0.28 - 1.06)^2 + (0.55 - 1.06)^2 + (0.62 - 1.06)^2 + (0.68 - 1.06)^2 + (0.77 - 1.06)^2 + (0.88 - 1.06)^2 + (0.89 - 1.06)^2 + (0.98 - 1.06)^2 + (0.99 - 1.06)^2 + (1.11 - 1.06)^2 + (1.22 - 1.06)^2 + (1.22 - 1.06)^2 + (1.22 - 1.06)^2 + (1.33 - 1.06)^2 + (1.44 - 1.06)^2 + (1.48 - 1.06)^2 + (1.68 - 1.06)^2 + (1.77 - 1.06)^2 + (1.99 - 1.06)^2]/20
Evaluate
Var = 0.22
This means that:
The expectation of the squared deviation of the random variable from the mean is 0.22 kg
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Answer:
0.22 kg
Step-by-step explanation:
I NEED HELP ASAP PLEASE LOOK AT THE PICTURE ATTACHED
Answer:
The distance is 20 units
Step-by-step explanation:
A bank pays $15 in interest for every $100 deposited.
The bank pays how much interest?
Answer:
15% interest
Step-by-step explanation:
because it's 15 out of 100 so that would be 15%
-1/2 (-3 / 2x + 6x + 1) -3 x
Answer: here
Step-by-step explanation:
−21−24
Answer: negative 21 Negative 224
-21-24
Solve the system of equations.
−4x+3y=−2y=x−1
Step-by-step explanation:
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C. Test your team's method by determining the midpoint of the segment with endpoints (-5,7) and (9, 4) and checking your answer with your teacher. On a map, Cary drew a set of coordinate axes. He noticed that the town of Coyner is located at the point (3,1) and Woottonville is located at (15,7), where 1 grid unit represents 1 mile. If the towns want to place a school at the midpoint between the towns, where should it be located? How far would it be from each town?
The town should be located 13.4 units from each other
How to calculate the distance between two pointsThe formula for calculating the distance between two points is expressed as:
√(x2-x1)²+(y2-y1)²
The midpoint of two coordinates is expressed as:
[tex]m(x, y)=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )[/tex]
Substitute the given coordinate
[tex]m(x, y)=(\frac{3+15}{2}, \frac{1+7}{2} )\\m(x,y)=(9,4)[/tex]
Hence the town should be located at coordinate (9, 4)
Calculate the distance
D = √(15-3)²+(7-1)²
D = √(12)²+(6)²
D = 13.4units
Hene the town should be located 13.4 units from each other
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Mr. Turner has two Algebra 1 classes. With one class, he lectured and the students took notes. In the other class, the students worked in small groups to solve math problems. After the first test, Mr. Turner recorded the student grades to determine if his different styles of teaching might have impacted student learning.
Class 1: 80, 81, 81, 75, 70, 72, 74, 76, 77, 77, 77, 79, 84, 88, 90, 86, 80, 80, 78, 82
Class 2: 70, 90, 88, 89, 86, 86, 86, 86, 84, 82, 77, 79, 84, 84, 84, 86, 87, 88, 88, 88
1. Analyze his student grades by filling in the table below. Which class do you think was the lecture and which was the
small group? Why?
Q1 Q2 IQR Mean Median MAD
Class 1 76.25 81.75 5.5 79.35 79.50 3.12
Class 2 84 88 4 84.60 86 3.85
What is Q1, Q3, IQR, Mean, Median and the MAD?The first step is to arrange the grades in the classes in ascending order.
Class 1: 70, 72, 74, 75, 76, 77, 77,77, 78, 79, 80, 80, 80, 81, 81, 82, 84, 86, 88, 90
Class 2: 70, 77, 79, 82, 84, 84, 84, 84, 86, 86, 86, 86, 86, 87, 88, 88, 88, 88, 89, 90
Q1 for class 1= 1/4(n + 1) = 21/4 = 5.25 = 76.25
Q2 for class 2 = 1/4(n + 1) = 5.25 = 84
Q3 for class 1= 3/4(n + 1) = 15.75 = 81.75
Q3 for class 2 = 3/4(n + 1) = 15.75 = 88
IQR for class 1 = Q3 - Q1 = 81.75 - 76.25 = 5.50
IQR for class 2 = Q3 - Q1 = 88 - 84 = 4
Mean for class 1 = sum of grades / total number of grades = 1587 / 20 = 79.35
Mean for class 2 = sum of grades / total number of grades= 1692 / 20 = 84.6
Median for class 1 = (n + 1) / 2 = 21/2 = 10.5 = 79.50
Median for class 1 = (n + 1) / 2 = 21/2 = 10.5 = 86
MAD = [tex]\frac{1}{n}[/tex]∑ l x - m(x) l
Where: n = number of observations
x = number in the data set
m = mean
Mean absolute deviation for class 1 = 62. 3/ 20 = 3.12
Mean absolute deviation for class 2. = 77/ 20 = 3.85
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Danita is working on a new sculpture. It will be 2 meters tall when she is finished. Will the sculpture fit in a room with a 300-centimeter high ceiling? Explain.
Answer:
yes; 2 m = 200 cm
Step-by-step explanation:
The SI prefix "centi-" signifies 1/100. That is 300 cm = 300/100 m = 3 m.
If the ceiling is 3 meters high, a sculpture that is 2 meters tall will have no difficulty fitting into the room.
What is a major difference between parallel lines and perpendicular lines?
Answer:
Parallel lines never intersect. Perpendicular lines are lines that intersect.
Step-by-step explanation:
Hope this helps.
Answer:
Perpendicular lines meet at a 90 degree angle while parallel lines will never touch
Step-by-step explanation:
Rodney says that he can draw two rectangles that have the same areas but different perimeters.
Which of the following pairs of rectangles could Rodney draw?
Select all that apply.
LIVE
A rectangle with side lengths 4 cm and 6 cm and a rectangle with side lengths 2 cm and 12 cm
LIVE
A rectangle with side lengths 4 cm and 6 cm and a rectangle with side lengths 2 cm and 8 cm
LIVE
A rectangle with side lengths 3 cm and 6 cm and a rectangle with side lengths 2 cm and 9 cm
LIVE
A rectangle with side lengths 5 cm and 6 cm and a rectangle with side lengths 2 cm and 9 cm
LIVE
A rectangle with side lengths 5 cm and 4 cm and a rectangle with side lengths 2 cm and 7 cm
Answer:
A rectangle with sides lengths 4cm and 6cm and a rectangle with side lengths 2cm and 12 cm...
A computer loses half of its value every two year. If the computer costs $75 after 6 years, how much
did the computer cost initially?
Answer:
$600
Step-by-step explanation:
This can be modeled as an exponential equation.
General form of an exponential function: [tex]y=ab^x[/tex]
where:
a is the initial valueb is the growth factorx is the independent variabley is the dependent variableTherefore:
a = initial cost of computerb = 0.5 (since the computer loses half its value)x = t/2 where t is the number of years ⇒ 3y = $75[tex]\implies 75=a(0.5)^3[/tex]
[tex]\implies 75=0.125a[/tex]
[tex]\implies a=\dfrac{75}{0.125}[/tex]
[tex]\implies a=600[/tex]
Therefore, the computer initially cost $600.
how many mL of normal saline should be added to 50mL of hydrogen peroxide to create a solution that is 5/8 strength?
Solve the simultaneous equations
4x + 5y = 4
2x - y = 9
Show clear algebraic working.
Answer:
[tex]x= \dfrac 72, ~~y= -2[/tex]
Step by step explanation:
[tex]4x+5y=4~~~...(i)\\\\2x-y=9~~~...(ii)\\\\\text{Multiply eq (ii) by 2 to isolate x:}\\\\4x-2y=18~~~.....(iii)\\\\(iii)-(i):\\\\4x-2y-4x-5y=18-4\\\\\implies -7y=14\\\\\implies y = -\dfrac{14}7 = -2\\\\\text{Substitute}~ y=-2~ \text{in equation (iii):}\\\\4x-2(-2) = 18\\\\\implies 4x +4 = 18\\\\\implies 4x = 18-4\\\\\implies 4x = 14\\\\\implies x = \dfrac{14}4 = \dfrac 72\\\\\text{Hence}~ (x,y) =\left(\dfrac 72 , -2 \right)[/tex]
Step-by-step explanation:
4x+5y=4 (equation 1)
2x-y=9 (equation2)
solving equation 1 and 2 and multiplying equation 2 by 2
4x+5y=4
4x-2y=18
- + -
________
7y= -14
y= -2
putting the value of y in equation 2
2x-y=9
2x+2=9
2x=7
x=3.5
Please hurry
What is the surface area of this figure? Enter your answer in the box.
Answer:
692ft3
Step-by-step explanation:
Surface area of the rectangular prism;
SA = lw(2) + wh(2) + hl(2)
SA = 15(5)(2) + 5(8)(2) + 8(15)(2)
SA = 150 + 80 + 240 =
SA = 470ft3
Surface area of the triangular prism
SA = (S1 + S2 + S3) l + bh
SA = (9 + 9 + 11) 5 + 11(7)
SA = (29) 5 + 11(7)
SA = 145 + 77
SA = 222ft3
Add both the SA's
470ft + 222ft = 692ft3