The barometer at an indoor pool reads 105.00 kPa. If the temperature in the room is 26c, what is the patial pressure of the "dry" air??
a. 30.88 kPa
b. 101.60 kPa
c. 108.40 kPa
d. 357.00 kPa

Answer: Molar mass of [tex]NH_3[/tex] is 17.00 g and moles in 50.0 grams is 2.94.

Explanation:

Molar mass is defined as the mass in grams of 1 mole of a substance.

S.I Unit of Molar mass is gram per mole and it is represented as g/mol.

Atomic Mass of Nitrogen (N) = 14.00 g

Atomic Mass of Hydrogen (H) = 1.00 g

Molar mass of [tex]NH_3[/tex] = 1(14.00)+3(1.00) g = 17.00 g

According to avogadro's law, 1 mole of every substance contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles and weigh equal to its molecular mass.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

[tex]\text{Number of moles of }NH_3==\frac{50.0g}{17.00g/mol}=2.94moles[/tex]

Answer:

Nucleus

Explanation:

they originate in the nucleus

Answer:

stress

Explanation:

people cn get stressed and not want to do work

Answer:

(8.3×40)+(8.3×71)

921.3grames

Answer:

[tex]\Large \boxed{\sf 921.3 \ g}[/tex]

Explanation:

Use formula

[tex]\displaystyle moles=\frac{mass}{M_r}[/tex]

[tex]M_r=40+35.5 \times 2 = 111[/tex]

Solve for mass

[tex]mass=8.3 \times 111=921.3[/tex]

Answer:

Explanation:

It processes the environment and sends out signals.

Answer:

yes correct salt hardens soap

Answer:

Promethium

Pm 61

Discovered by Jacob .A. Marinsky

aswer: protactinium-234 is more dang erous than uranium

There can be emissions of radiations like gamma radiation. There can be emission of particles too like alpha particle. Therefore protactinium-234 is more dangerous than uranium-234.

Nuclear decay is process in which the radioactive element releases particles or radiations. Alpha particles is ⁴₂He. Alpha particle is nothing but helium particle.  Protactinium-234 and uranium-234 are radioactive element.

If we were sitting near a gram of protactinium-234 and a gram of uranium-234, both solid materials then protactinium-234 is more dangerous than uranium-234. The half-life of protactinium-234 is smaller than that of uranium-234. So, protactinium-234 is more active than uranium-234 and hence more harmful than uranium-234.

Therefore, protactinium-234 is more dangerous than uranium-234.

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Answer:

pls answer this link for the answer :D

Explanation:

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Answer:

3 moles of NH₄Cl

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

NH₃(g) + HCl(g) → NH₄Cl(s) ΔH = –176 kJ

From the balanced equation above,

1 mole of NH₄Cl where obtained when the change in enthalphy (ΔH) was –176 kJ.

Finally, we shall determine the number of mole of NH₄Cl produced when the change in enthalphy (ΔH) is –528 kJ. This can be obtained as follow:

From the balanced equation above,

1 mole of NH₄Cl where obtained when the change in enthalphy (ΔH) was –176 kJ.

Therefore, Xmol of NH₄Cl will be obtained when the change in enthalphy (ΔH) is –528 kJ i.e

Xmol of NH₄Cl = –528 / –176

Xmol of NH₄Cl = 3 moles

Thus, 3 moles of NH₄Cl where obtained from the reaction.

Explanation:

It is represented using the ideal gas equation , or PV = nRT, where P is the pressure in atmospheres, V is the volume in liters, n represents the quantity of particles in the container, T represents the temperature in Kelvin, and R is the ideal gas constant equal to 0.0821 liters atmospheres per moles Kelvin.

Answer: Ammonia Ice

Explanation: Like Jupiter, Saturn boasts layers of clouds. The upper layers of clouds are made up of ammonia ice. Traveling toward the core, clouds of water ice form, with bands of ammonium hydrosulfide ice intermixed. The lower layers of Saturn see higher temperatures and pressures.

Answer:

B

Explanation:

Answer:

B

Explanation:

Edge 2022

Answer:

A. Energy

B. Chemical potential

C. Endothermic reaction

D.The law of conservation of mass

E. Transfers of energy

The fill in the blanks for energy, reaction, and the law of mass is

A. Energy

B. Chemical potential

C. Endothermic reaction

D. The law of conservation of mass.

E. Transfers of energy

The law says that energy can neither be created nor destroyed.

The law was given by Antoine Lavoisier.

Thus, fill in the blanks are: A. Energy

B. Chemical potential

C. Endothermic reaction

D. The law of conservation of mass.

E. Transfers of energy

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Answer:  According to the Arrhenius concept, an acid is a substance that  causes an increase in the concentration of H in aqueous solutions

Explanation:

According to the Arrhenius concept, an acid is a substance that ionizes in the water to give hydronium ion or hydrogen ion and a bases is a substance that ionizes in the water to give hydroxide ion .

[tex]HA(aq)\rightarrow H^+(aq)+A^-(aq)[/tex]

[tex]BOH(aq)\rightarrow B^+(aq)+OH^-(aq)[/tex]

According to lewis concept , an acid is a substance that accepts electrons and a base is a substance that can donate electrons.

Answer:

In general, the number of valence electrons is the same within a column and increases from left to right within a row. Group 1 elements have just one valence electron and group 18 elements have eight, except for helium, which has only two electrons total.

Answer:

Summary. Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m).

Explanation:

Hope it helps! Correct me if I am wrong :>

Can you please mark me as brainlest?

Distance is the measure of how far or near an object is placed. It can be referred to as the length between the two points. The distance can be calculated by the formula, [tex]\rm Work = Force \times Distance.[/tex]

Work is the amount of force or energy required by the system to move the thing or the object from its original position to another. It is estimated in joules.

Force is the strength or the power required by the object to change its motion. It is calculated in Newtons.  

The distance can be measured by using the work and the force applied by the object to move from initial to the final position as,

[tex]\rm Work = Force \times Distance[/tex]

Therefore, distance can be calculated by work and force.

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Answer:

The graph shown is not a function because points (-1,2) and (-1,0) have the same x value.

Explanation:

The given question is incomplete. The complete question is:

Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis. Determine the mass of glucose (C6H1206) produced

Answer: 60.0 g of glucose

Explanation:

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

a) moles of [tex]CO_2[/tex]

[tex]\text{Number of moles}=\frac{88.0g}{44g/mol}=2.0moles[/tex]

b) moles of [tex]H_2O[/tex]

[tex]\text{Number of moles}=\frac{64.0g}{18g/mol}=3.5moles[/tex]

[tex]6CO_2+6H_2O\rightarrow C_{6}H_{12}O_6+6O_2[/tex]

According to stoichiometry :

6 moles of [tex]CO_2[/tex] require = 6 moles of [tex]H_2O[/tex]

Thus 2.0 moles of [tex]CO_2[/tex] require=[tex]\frac{6}{6}\times 2.0=2.0moles[/tex]  of [tex]H_2O[/tex]

Thus [tex]CO_2[/tex] is the limiting reagent as it limits the formation of product.

As 6 moles of [tex]CO_2[/tex] give =  1 moles of glucose

Thus 2.0 moles of [tex]CO_2[/tex] give =[tex]\frac{1}{6}\times 2.0=0.33moles[/tex]  of glucose

Mass of glucose = [tex]moles\times {\text {Molar mass}}=0.33moles\times 180g/mol=60g[/tex]

Thus 60.0 g of glucose will be produced from 88.0 g of carbon dioxide and 64.0 g of water  

In green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis produces 60.0 g of glucose.

To calculate the moles, we use the equation:

Mole fraction is a unit of concentration, described to be same to the range of moles of a element divided via way of means of the entire range of moles of a solution.

Thus it is well explained.

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This question is incomplete, the complete question is;

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.

Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained

Answer:

the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg

Explanation:

Given the data in the question;

thickness of sheet t = 5 mm

Area A = 0.20 m²

Temperature T = 500°C

diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s

concentration high pressure side C[tex]_A[/tex] = 2.4

concentration low pressure side C[tex]_B[/tex] = 0.6 kg

from the question, we calculate the concentration gradient

dc/dx = (C[tex]_A[/tex] -  C[tex]_B[/tex])/dt

so we substitute

dc/dx = (2.4 - 0.6) / ( - 5 × 10⁻³ )

dc/dx = -360

now, mass of hydrogen per hour that diffuse through a pd sheet

M = -∝AT(dc/dx)

where time t is 1 hour ( 3600 sec )

we substitute

M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)

M = 0.002592

M = 2.592 × 10⁻³ kg per one hour

Therefore, the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg

The number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500°C is 2.592 × 10⁻³ kg.

Purification: It refers to the process of removing impurities or contaminants from a substance in order to make it cleaner, purer, or more refined. It also involves the elimination or reduction of unwanted substances or components that may be present in the original material.

According to the question, given data is:

Thickness of sheet t = 5 mm

Area A = 0.20 m²

Temperature T = 500°C

Diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s

Concentration high pressure side [tex]C_A[/tex] = 2.4

Concentration low pressure side[tex]C_B[/tex]= 0.6 kg

from the question, we calculate the concentration gradient,

[tex]dc/dx = (C _A- C_B)/dt[/tex]

so, we substitute the values,

[tex]dc/dx[/tex] = (2.4 - 0.6)/ ( - 5 × 10⁻³)

[tex]dc/dx = -360[/tex]

Now, mass of hydrogen per hour that diffuse through a Palladium sheet,

M = -∝[tex]AT(dc/dx)[/tex]

where time t is 1 hour (3600 sec)

We substitute,

M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)

M = 0.002592

M = 2.592 × 10⁻³ kg per hour.

Therefore, the number of kilograms of hydrogen that pass per hour through a palladium sheet is approximately 2.592 × 10⁻³ kg.

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This question is incomplete, the complete question is;

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.

Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.

Answer:

MgS + KI = K2S + MgI2

Answer:

By moving heat from the equator toward the poles, ocean currents play an important role in controlling the climate. Ocean currents are also critically important to sea life. They carry nutrients and food to organisms that live permanently attached in one place, and carry reproductive cells and ocean life to new places.

Explanation:

:)

Answer:

Explanation:

Atomic number = 8

Electron = 8

1s level= 2

2nd level = 6

3rd level =0

Hope this help

[tex]\huge\underline\mathbb\pink{ANSWER\::}\\\\[/tex]

Atomic Number : 8

Total number of electron : 8

1st level Electrons : 2

2nd level Electrons : 6

3rd level Electrons : 0

[tex]\\\\\\[/tex]

HOPE IT HELPS

PLEASE MARK ME BRAINLIEST ☺️

Answer:

[tex]\mathbf{a \ strong \ base \ such \ as\ LiOH \ or \ NaOH.}[/tex]

Explanation:

In the condensation reactions of carbonyl compounds, it is essential to establish the order of events in advance to minimize or suppress the possibilities of self-condensation and the occurrence of cross-condensation, which unfortunately are an obvious threat in these reactions.

Self-condensation:

Any carbonyl compound that has one or more alpha hydrogens, on the carbons adjacent to the carbonyl group, runs the risk of undergoing a self-condensation reaction if the corresponding rigor is not carried out.

Cross-condensation:

Ideally, in the condensation reactions of carbonyl compounds, one of the reacting molecules should quickly enolise, while the other preferably should not have Hα, to ensure that no other by-products are formed.

[tex]\text{To achieve this process;}[/tex] [tex]\text{A self-aldol or crossed aldol requires a strong base such as LiOH or NaOH.}[/tex]