Answer:
a. [tex]\mathbf{P(Y \leq 60) = 0.3333}[/tex]
b. P(Y>50) = 0.8889
c. E(y) = 67.5 and Standard deviation [tex]\sigma[/tex] = 12.99
Step-by-step explanation:
From the information given :
an automobile body paint shop, has determined that the painting time of automobiles is uniformly distributed and that the required time ranges between 45 minutes to [tex]1\frac{1}{2}[/tex]hours.
The objective is to determine the probability that the painting time will be less than or equal to an hour?
since 60 minutes make an hour;
[tex]1\frac{1}{2}[/tex]hours = 60 +30 minutes = 90 minutes
Let Y be the painting time of the automobile; then,
the probability that the painting time will be less than or equal to an hour ca be computed as :
[tex]P(Y \leq 60) = \int ^{60}_{45} f(y) dy \\ \\ \\ P(Y \leq 60) = \int ^{60}_{45} \dfrac{1}{45} dy \\ \\ \\ P(Y \leq 60) = \dfrac{1}{45} \begin {pmatrix} x\end {pmatrix}^{60}_{45} \\ \\ \\ P(Y \leq 60) = \dfrac{60-45}{45 } \\ \\ \\ P(Y \leq 60) = \dfrac{15}{45} \\ \\ \\ P(Y \leq 60) = \dfrac{1}{3} \\ \\ \\ P(Y \leq 60) = 0.3333[/tex]
What is the probability that the painting time will be more than 50 minutes?
The probability that the painting will be more than 50 minutes is P(Y>50)
So;
[tex]P(Y>50) = \int \limits ^{90}_{50} f(y) dy[/tex]
[tex]P(Y>50) = \int \limits ^{90}_{50} \dfrac {1}{45} dy[/tex]
[tex]P(Y>50) = \dfrac{1}{45}[x]^{90}_{50}[/tex]
[tex]P(Y>50) = (\dfrac{90-50}{45})[/tex]
[tex]P(Y>50) = \dfrac{40}{45}[/tex]
P(Y>50) = 0.8889
Determine the expected painting time and its standard deviation.
Let consider E to be the expected painting time
Then :
[tex]E(y) = \int \limits ^{90}_{45} y f(y) dy \\ \\ \\ E(y) = \int \limits ^{90}_{45} y \dfrac{1}{45} dy \\ \\ \\ E(y) = \dfrac{1}{45} [\dfrac{y^2}{2}]^{90}_{45} \\ \\ \\ E(y) = \dfrac{1}{45}[\dfrac{(90^2-45^2)}{2}] \\ \\ \\ E(y) = \dfrac{1}{45} (\dfrac{6075}{2}) \\ \\ \\ E(y) = \dfrac{1}{45} \times 3037.8 \\ \\ \\ \mathbf{E(y) = 67.5}[/tex]
[tex]E(y^2) = \int \limits ^{90}_{45} y^2 f(y) dy \\ \\ \\ E(y^2) = \int \limits ^{90}_{45} y^2 \dfrac{1}{45} dy \\ \\ \\ E(y^2) = \dfrac{1}{45} [\dfrac{y^3}{3}]^{90}_{45} \\ \\ \\ E(y^2) = \dfrac{1}{45}[\dfrac{(90^3-45^3)}{3}] \\ \\ \\ E(y^2) = \dfrac{1}{45} (\dfrac{637875}{3}) \\ \\ \\ E(y^2) = \dfrac{1}{45} \times 2126.25 \\ \\ \\ \mathbf{E(y^2) = 4725}[/tex]
To determine the standard deviation, we need to first know what is the value of our variance,
So:
Variance [tex]\sigma^2[/tex] = E(x²) - [E(x)]²
Variance [tex]\sigma^2[/tex] = 4725 - (67.5)²
Variance [tex]\sigma^2[/tex] = 4725 - 4556.25
Variance [tex]\sigma^2[/tex] = 168.75
Standard deviation [tex]\sigma[/tex] = [tex]\sqrt{variance}[/tex]
Standard deviation [tex]\sigma[/tex] = [tex]\sqrt{168.75}[/tex]
Standard deviation [tex]\sigma[/tex] = 12.99
WILL MARK BRAINLIEST!!!!20 POINTS!!!!URGENT!!!
Answer:
the firsts third and last one
Step-by-step explanation:
hope this helped
Algebra pleaseeeeeee help
Answer:
Step-by-step explanation:
Remark
I have to assume that you know calculus. It is the only way the problem can be done that I know of. If you don't, I'm not sure how you will do this.
The curve is of y = e^(-2x) + x^2 - 3
The curve crosses the y axis when x = 0. The y value is
y = e^0 + x^2 - 3
yint = 1 + 0 - 3
yint = -2
The slope at point (0,-2) is
y' = -2e^(-2x) +2x
y' = -2 at point A
Therefore the normal will have a slope
m1 * m2 = - 1
The slope of the curve C at A = -2
The equation of the tangent line at A = -2x - 2
Call this m1
m2 = slope of the normal
-2 * m2 = -1
m2 = 1/2
Equation of the line (l) =
y = 1/2 x - 2
The graph is shown below. Notice the two lines actually look like they are at a 90 degree angle.
Mike wants to buy a used car for $3200. He has$400 in savings and can save another $250 each month. How many months will it take him to be able to buy this car?
Answer:
12 months
Step-by-step explanation:
mental math
Solve: XC - XV. Show your answer as a Roman Numeral. Standard Number 1 5 10 50 100 500 1,000 Roman Numeral 1 V X Х L с D M A) V B) VI C) VIL
Answer: A
Step-by-step explanation:
A 51-foot wire running from the top of a tent pole to the ground makes an angle of 58° with the ground. If the length of the tent pole is 44 feet, how far is it from the bottom of the tent pole to the point where the wire is fastened to the ground? (The tent pole is not necessarily perpendicular to the ground.)
Answer:
35.11 ft
Step-by-step explanation:
This given situation can be thought of as triangle [tex]\triangle PQR[/tex] where PQ is the length of pole.
PR is the length of rope.
and QR is the distance of bottom of pole to the point of fastening of rope to the ground.
And [tex]\angle Q \neq 90^\circ[/tex]
Given that:
PQ = 44 ft
PR = 51 ft
[tex]\angle R = 58^\circ[/tex]
To find:
Side QR = ?
Solution:
We can apply Sine Rule here to find the unknown side.
Sine Rule:
[tex]\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}[/tex]
Where
a is the side opposite to [tex]\angle A[/tex]
b is the side opposite to [tex]\angle B[/tex]
c is the side opposite to [tex]\angle C[/tex]
[tex]\dfrac{PR}{sinQ}=\dfrac{PQ}{sinR}\\\Rightarrow sin Q =\dfrac{PR}{PQ}\times sinR\\\Rightarrow sin Q =\dfrac{51}{44}\times sin58^\circ\\\Rightarrow \angle Q =79.41^\circ[/tex]
Now,
[tex]\angle P +\angle Q +\angle R =180^\circ\\\Rightarrow \angle P +58^\circ+79.41^\circ=180^\circ\\\Rightarrow \angle P = 42.59^\circ[/tex]
Let us use the Sine rule again:
[tex]\dfrac{QR}{sinP}=\dfrac{PQ}{sinR}\\\Rightarrow QR =\dfrac{sinP}{sinR}\times PQ\\\Rightarrow QR =\dfrac{sin42.59}{sin58}\times 44\\\Rightarrow QR = 35.11\ ft[/tex]
So, the answer is 35.11 ft.
Help pls
You add the same amount of money to your savings each week. At week 5 you have $45. At week 12 you have $80. How much money do you have at week 20?
Answer: $120
First, create a function
x = number of weeky = amount of money in savingsa = amount of money added each weekb = the amount of money in savings at week 0[tex]\left \{ {{5a+b=45} \atop {12a+b=80}} \right.\\\\(5-12)a+(1-1)b=45-80\\\\-7a=-35\\\\a=\frac{-35}{-7} =5\\\\5a+b=45\\\\5(5)+b=45\\\\b=45-25=20[/tex]
Therefore, the function is y = 5x + 20
To find the amount of money at week 20, set x = 20 and solve:
[tex]y=5(20)+20=100+20=120[/tex]
Therefore, the answer is $120.
Angie has 18 oatmeal cookies.She splits them evenly among b bags.Choose the expression that shows how many cookies are in each bag. 1.B-18 2.18/b 3.18 4.B
Answer:
2, 18/b
Step-by-step explanation:
if you divide by the number of bags you will get the number of cookies in each bag.
Answer:2,18/b
Step-by-step explanation:If you multiply the cookies in a bag by b, you will get 18
Question. 1 The product of a monomial and a binomial is a (a) monomial (b) binomial (c) trinomial (d) None of these
Answer:
The answer to this question is (D)
ILL MARK BRAINIEST IF U DO THIS RIGHT!!!
Answer:
D because even though the flat fee is 150 paying 5$ a hour it will cost less
SOMEBODY HELP PLEASE! ACME Hardware is introducing a new product called Greener Cleaner. Complete the table by finding the cost per milliliter for each size based on the sales price. One liter is 1,000 milliliters. (Answer the questions too, please!)
Answer:
Kindly check explanation
Step-by-step explanation:
SMALL SIZE :
AMOUNT OF LIQUID = 250 milliliters
Sales price = $4.50
Cost per milliliter :
Sales price / amount of liquid
$4.50 / 250 = $0.018
MEDIUM SIZE :
AMOUNT OF LIQUID = 500 milliliters
Sales price = $9.95
Cost per milliliter :
Sales price / amount of liquid
$9.95 / 500 = $0.0199
= $0.020 ( 3 decimal places)
LARGE SIZE :
AMOUNT OF LIQUID = 1 LITRE = 1000 milliliters
Sales price = $16.95
Cost per milliliter :
Sales price / amount of liquid
$16.95 / 500 = $0.0199
= $0.01695
= $0.017 ( 3 decimal places)
A) LARGE < SMALL < MEDIUM
B) LEAST EXPENSIVE WAY TO BUY 1500 milliliters of green cleaner :
1 large size + 2 small sizes
$16.95 + 2($4.50)
$16.95 + $9.00
= $25.95
C.) MOST EXPENSIVE WAY TO BUY 1500 milliliters of green cleaner :
3 medium sizes
3 * ($9.95)
$29.85
The average of four different positive integers is 9. What is the greatest value for one of the integers?
From the given information; Let the unknown different positive integers be (a, b, c and d).
An integer is a set of element that are infinite and numeric in nature, these numbers do not contain fractions.
Suppose we make an assumption that (a) should be the greatest value of this integer.
Then, the other three positive integers (b, c and d) can be 1, 2 and 3 respectively in order to make (a) the greatest value of the integer.
Therefore, the average of this integers = 9
Mathematically;
[tex]\mathbf{\dfrac{(a+b+c+d)}{4} =9}[/tex]
[tex]\mathbf{\dfrac{(a+1+2+3)}{4} =9}[/tex]
[tex]\mathbf{\dfrac{(6+a)}{4} =9}[/tex]
By cross multiplying;
6+a = 9 × 4
6+a = 36
a = 36 - 6
a = 30
Therefore, we can conclude that from the average of four positive integers which is equal to 9, the greatest value for one of the selected integers is equal to 30.
Learn more about integers here:
https://brainly.com/question/15276410?referrer=searchResults
The greatest value for one of the four positive integers is 30.
To find the largest positive integer, you have to minimize the other three positive integers.
The least three different positive integers available = 1, 2, 3let the largest positive integer = ythe sum of the four different positive integers = 1 + 2 + 3 + y = 6 + yFind the average of the four positive integers and equate it to the given value of the average.
[tex]\frac{6 + y}{4} = 9\\\\6+ y = 36\\\\y = 36-6\\\\y = 30[/tex]
Thus, the greatest value for one of the positive integers is 30
learn more here: https://brainly.com/question/20118982
The hypotenuse of a right triangle measures nem and one of its legs measures o em.
Mnd the measure of the other leg. If necessary, round to the nearest tenth.
Sun
attempt to
Using Pythagorean theorem
[tex]\\ \sf\longmapsto P^2=H^2-B^2[/tex]
[tex]\\ \sf\longmapsto P^2=11^2-9^2[/tex]
[tex]\\ \sf\longmapsto P^2=121-81[/tex]
[tex]\\ \sf\longmapsto P^2=40[/tex]
[tex]\\ \sf\longmapsto P=\sqrt{40}[/tex]
[tex]\\ \sf\longmapsto P=6.2cm[/tex]
Step-by-step explanation:
Given,
Hypotenuse = 11 cm
Base (One of the given leg) = 9 cm
Therefore,
According to Pythagoras Theorem,
[tex] {base}^{2} + {height}^{2} = {hypotenuse}^{2} [/tex]
[tex] = > {(9)}^{2} + {height}^{2} = {(11)}^{2} [/tex]
[tex] = > {height}^{2} = {(11)}^{2} - {(9)}^{2} [/tex]
[tex] = > {height}^{2} = 121 - 81[/tex]
[tex] = > {height}^{2} = 4 0[/tex]
[tex] = > height = \sqrt{40} [/tex]
=> height = 6.3245553203
When rounded to nearest tenth,
=> height = 6.3
Hence,
Required length of other leg is 6.3 (Ans)
Solving Inequalities and graphing them.
Answer:
I used to know this not anymore sry g
The length of the major axis of the ellipse below is 10 What is the sum of the lengths of the red and blue line segments? A. 10 B. 5 C. 15 D. 20
Answer:
A. 10
Step-by-step explanation:
As we know that
The length of the major axis of the ellipse is 10
i.e
2 a = 10
Also, the ellipse is the curve that consists of 2 focal points in order that the total of the distance to the 2 focal points would remain constant for each and every point displayed in the curve
Now we assume that P is the curve point
So,
PF1 + PF2
i.e
2 a (blue line) + (red line)
2 a = 10
Therefore the sum of the length is 10
Answer:
10
Step-by-step explanation:
PLEASE HELP Give me an example of a negative correlation
Answer:
Step-by-step explanation:
An example of a negative correlation is tv viewing and student test grades.
Another example is the video game playing and test grades
The two-way frequency table below shows data on years working with the company and college degree status for Tom's coworkers. Complete the following two-way table of row relative frequencies. (If necessary, round your answers to the nearest hundredth.)
Answer:
Lets start with the top row.
First, add the two values.
5+14=19
Now, divide each value by the total.
5/19=0.26315789473
Round the decimal to the nearest hundredth.
5/19=0.26
14/19=0.73684210526
Round it to the nearest hundredth.
14/19=0.74
Now, The second row.
Add the two values.
16+7=23
Divide the first value by the total.
16/23=0.69565217391
Round it to the nearest hundredth.
16/23=0.70
Divide the second value by the total.
7/23=0.30434782608
Round to the nearest hundredth.
7/23=0.30
Done!
Answer:
Row 1: 0.26 0.74
Row 2: 0.70 0.30
Step-by-step explanation:
Khan
problem that would represent
an elevator starts at street
level (main lobby) goes up 6
floors and then back down 8
floors to the parking garage.
1 + 7 - 8 = 0
0 + 8 + (-2) = 6
1 + 6 + (-8) = -1
0 + 6 + (-8) = -2
[tex]\\ \sf \longmapsto 1+6+(-8)[/tex]
Downward motion noted as negative and upward is positive.Lobby will be 1[tex]\\ \sf \longmapsto 1+6+(-8)[/tex]
[tex]\\ \sf \longmapsto 1+6-8[/tex]
[tex]\\ \sf \longmapsto 7-8[/tex]
[tex]\\ \sf \longmapsto -1[/tex]
option c is correct
Find the slope (rate of change) of each representation. Please explain how you got it.
Answer:
m = -3/2
Step-by-step explanation:
To find the slope of the representation, use the slope formula: [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
I'll pick (-4, 9) and (-2, 6) in this instance.
[tex]m=\frac{9-6}{-4-(-2)}\\\\m=-\frac{3}{2}[/tex]
Therefore, the slope of the representation is -3/2.
Answer:
-3/2
Step-by-step explanation:
To find the slope, we can use the formula
m = ( y2-y1)/(x2-x1)
= ( -6 -9)/(6 - -4)
= (-6-9)/(6+4)
-15/10
-3/2
Find the value of x for which pll q.
Answer:
D) 9
Step-by-step explanation:
These angles are equal to each other because they’re alternate interior angles so:
9x + 8 = 15x - 46
9x - 15x = -46 - 8
-6x = -54
x = 9
write the expression fourteen added to the product of seven and a number
Answer:
(7×x)+14
Step-by-step explanation: Because we have 14 added to something, we will need a + to whatever we are adding to. The product of 7 and a number is 7×x because product is the number you get after multiplication. So we get 7×x+14. You dont need parenthesis
Hope this helps!
Which expression gives the length of the transverse axis of the hyperbola
shown below?
X
У
Focus
Focus
O AY
O B. X-y
O c. xt
O D. X+ y
Answer:
Option (B)
Step-by-step explanation:
From the picture attached,
F1 and F2 are the focii of the hyperbola.
Point P(x, y) is x units distant from F1 and y units distant from the other focus F2.
By the definition of a hyperbola,
"Difference between the distances of a point from the focii is always constant and equals to the measure of transverse axis."
Difference in the distances of point P from focii F1 and F2 = (x - y) units
This distance is equal to the length of the transverse axis = (x - y) units
Therefore, Option (B) will be the answer.
Answer:
x-y
Step-by-step explanation:
Which equation can be used to solve for x in the following diagram? Choose 1 answer. 2x° degrees, 4x° degrees, 150° degrees
Answer:
The answer is option D.
Step-by-step explanation:
Hi, there!!!
Here, if you closely look this figure, you will find that AB and CD are interested at a point O.
now, OP is just a line constructed from point "O".
now, 2x°+4x°=150°.....is equation.
{Because, They are vertically opposite angle}
When two st. line intersects at a point then the abgle formed oppositely are equal.
Hope it helps..
What am I supposed to do when parentheses are side by side like this?
Answer:
Evaluate each expression inside both grouping symbols, then multiply the result.
Step-by-step explanation:
[tex]\displaystyle (3 - 1)(4 + 2) = (2)(6) = 12[/tex]
G - Grouping Symbols
E - Exponents
M\D - Division & Multiplication [left to right]
S\A - Subtraction & Addition [right to left OR vice versa]
I am joyous to assist you at any time.
Please answer this question now
Answer:
m∠C = 102°
Step-by-step explanation:
This is a quadrilateral inscribed in a circle
The sum of opposite angles in a cyclic quadrilateral is equal to 180°
m∠D + m∠B = 180°
m∠B = 180° - m∠D
m∠B = 180° - 80°
m∠B = 100°
We know what m∠B
We have external angles outside the circle.
m∠CDA is opposite m∠B
m∠CDA = 2 × m∠B
m∠CDA = 2 × 100°
m∠CDA = 200°
m∠CDA is the sum of m∠CD and m∠DA
m∠CDA = m∠CD + m∠DA
m∠DA = m∠CDA - m∠CD
m∠DA = 200° - 116°
m∠DA = 84°
m∠DAB is an exterior angle also, hence,
m∠DAB is the sum of m∠DA and m∠AB
m∠DAB = m∠DA + m∠AB
m∠DAB = 84° + 120°
m∠DAB = 204°
Finally we can solve for m∠C
m∠DAB is Opposite m∠C
So, m∠C = 1/2 × m∠DAB
m∠C = 1/2 × 204
m∠C = 102°
What are the solutions to the equation f(x)=g(x)?
A) x= -3, 4
B) x= -4, 2.5
C) x= -0.8, 2.5
D) x= 8, -8
Answer:
B
Step-by-step explanation:
The points where f(x) intersects g(x) are - 4 and 2.5. These points are the solution of the equation f(x)=g(x)
Answer:
(-4,8) and ( 2.5, -8)
Step-by-step explanation:
The solutions are where the two graphs intersect
They intersect at x = -4 and y = 8 and at x = 2.5 and y = -8
(-4,8) and ( 2.5, -8)
15 points! I will give Brainliest and heart! Answer ASAP but with DETAIL, I need step - by - step, clear words, correct grammar. A pair of equations is shown below: y = 3x − 5 y = 6x − 8 Part A: Explain how you will solve the pair of equations by substitution or elimination. Show all the steps and write the solution. (5 points) Part B: If the two equations are graphed, at what point will the lines representing the two equations intersect? Explain your answer. (5 points)
Hey there! I'm happy to help!
PART A
Let's look at our two equations.
y=3x-5
y=6x-8
We will solve this with substitution because we have two different values for y, so it will be be very easy to substitute.
We know that y is equal to 6x-8. This means that we can replace the y in the first equation with 6x-8 and then solve for x.
6x-8=3x-5
We add 8 to both sides.
6x=3x+3
We subtract 3x from both sides.
3x=3
We divide both sides by 3.
x=1
We can plug this x-value into either of our equations to figure out what y is.
y=6(1)-8
y=6-8
y=-2
Therefore, our solution is x=1 and y= -2.
PART B
When graphing the two equations in a systems of equation, the point where they intersect is the solution. We already have our solution, so now we will just write it as a point, which is (1,-2).
Have a wonderful day! :D
Answer:
see below
Step-by-step explanation:
y = 3x − 5
y = 6x − 8
I will use substitution by substituting for y in the first equation
y = 3x − 5
6x -8 = 3x-5
Subtract 3x from each side
6x-3x -8 = 3x-5-3x
3x-8 = -5
Add 8 to each side
3x-8+8 = -5+8
3x =3
Divide by 3
3x/3= 3/3
x =1
Now find y
y = 3x − 5
= 3(1) -5
=3-5
= -2
( 1,-2)
The two lines will intersect at ( 1,-2)
The solution to the two equations is where the lines intersect.
Correct answer gets brainliest and 5 stars
Answer:
Does the answer help you?
If f(x)= 5x+4 and g(x)= -2+1...... 1) f(6) + g(-8) = ? 2) g(4)= ? 3) f(-2)= ? PLZ PLZ PLZ HELP ME I AM SOOOOO CONFUSED!!!!!!!!!!!
Answer:
See below.
Step-by-step explanation:
So we have the two functions:
[tex]f(x)=5x+4\text{ and } g(x)=-2x+1[/tex]
1)
First, find the values of each function:
[tex]f(x)=5x+4\\f(6)=5(6)+4\\f(6)=30+4=34[/tex]
[tex]g(x)=-2x+1\\g(-8)=-2(-8)+1\\g(-8)=16+1=17[/tex]
Therefore:
[tex]f(6)+g(-8)\\=(34)+(17)=51[/tex]
2)
Plug in the number into the function:
[tex]g(x)=-2x+1\\g(4)=-2(4)+1=-8+1=-7[/tex]
3)
Like the last one:
[tex]f(x)=5x+4\\f(-2)=5(-2)+4=-10+4=-6[/tex]
what are the roots of the quadratic equation below 2x^2+8x+7=0
Answer:
x = -1.29 and -2.71
Step-by-step explanation:
Use the quadratic formula, which is [tex]x=\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex] and [tex]x=\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]
[tex]\frac{-8+\sqrt{8^2-4(2)(7)} }{2(2)}[/tex] and [tex]\frac{-8-\sqrt{8^2-4(2)(7)} }{2(2)}[/tex]
[tex]\frac{-8+\sqrt{8} }{4}[/tex] and [tex]\frac{-8-\sqrt{8} }{4}[/tex]
Further reduced down to:
[tex]\frac{-8+2\sqrt{2} }{4}[/tex] and [tex]\frac{-8-2\sqrt{2} }{4}[/tex]
In decimal form, to the hundredths place, both of these are:
-1.29 and -2.71
A truck costs $8,000 with a residual value of $1,000. It has an estimated useful life of 7 years. If the truck was bought on July 9 what would be the book value at the end of year 1?
Answer:
$7520.55
Step-by-step explanation:
Cost of truck = $8000
Residual value = $1000
Estimated useful life = 7 years
Depreciation = (cost of asset - salvage value) / useful life
Depreciation = (8000 - 1000) / 7
Depreciation = 7000 / 7
Depreciation = $1000
Truck was purchased on July 9, Therefore, Depreciation by the end of year one will be;
Number of days between July 9 and year end = 175 days
Daily Depreciation = $1000 / 365 = $2.739
Total Depreciation by year end = (daily Depreciation * 175 days) = $479.45.
Book value at the end of year 1 = (8000 - 479.45)
= $7520.55
Answer:
The answer is "$7,500".
Step-by-step explanation:
Formula:
In the month of July-December the depreciation:
[tex]\frac{\text{Cost-Residual}}{\text{Useful life}}\times \frac{6}{12} \\[/tex]
Cost-Residual= costs -residual value
Given:
Cost-Residual = $8, 000 - $ 1,00
= $7,000
Useful life= 7 years
Put the value in the above-given formula:
[tex]=\frac{7 000}{7}\times \frac{6}{12}\\\\= 1 000\times \frac{1}{2}\\\\= 5 00\\[/tex]
Therefore, the book value on point at the end of one year is:
= $8,000 -$ 500
= $7,500