The area of the brick border is: 7.678 m²
What is the area of the composite figure?Using Pythagoras theorem, we can find the diameter of the circle as:
d = √(10² - 6²)
d = √64
d = 8 m
Since the width of the brick border is 40 cm, then converting to meters gives 0.4 m.
Area of semi circle with brick border = ¹/₂(π * (8.8/2)²) = 30.411 m²
Area of semi circle without brick border = ¹/₂(π * (8/2)²) = 25.133 m²
Area of circular part of border = 30.411 m² - 25.133 m²
= 5.278 m²
Area of rectangular part of border = 6 * 0.4 = 2.4 m²
Total area of border = 5.278 m² + 2.4 m²
= 7.678 m²
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12. Housing According to the Census Bureau, the distribution by ethnic background of the New York City population in a recent year was Hispanic: 28% Black: 24% White: 35% Asian: 12% Others: 1% The manager of a large housing complex in the city wonders whether the distribution by race of the complex's residents is consistent with the population distribution. To find out, she records data from a random sample of sochresidents. The table below displays the sample data." Race: Asian Hispanic 212 Black White 202 270 Other 22 Count: 94 Are these data significantly different from the city's distribution by race? Carry out an appropriate test at the a 0.05 level to support your answer. If you find a significant result, perform a follow-up analysis.
we can conclude that there is a significant difference between the observed and expected frequencies of race categories.
To determine if the housing complex's distribution of residents by race is significantly different from the population distribution, we can perform a chi-square goodness-of-fit test.
First, we need to calculate the expected frequencies for each race category based on the population distribution. The expected frequencies can be calculated as follows:
Expected frequency for Hispanics = 0.28 x 94 = 26.32
Expected frequency for Blacks = 0.24 x 94 = 22.56
Expected frequency for Whites = 0.35 x 94 = 32.9
Expected frequency for Asians = 0.12 x 94 = 11.28
Expected frequency for Others = 0.01 x 94 = 0.94
We can then calculate the chi-square statistic as follows:
χ2 = Σ (O - E)2 / E
where O is the observed frequency and E is the expected frequency for each race category.
Using the data from the table, we can calculate the chi-square statistic as follows:
χ2 = [(212-11.28)2/11.28] + [(202-26.32)2/26.32] + [(270-32.9)2/32.9] + [(22-22.56)2/22.56] + [(0-0.94)2/0.94] = 52.06
We have 5 categories and 1 parameter estimated (the expected frequencies), so the degrees of freedom for the test are df = 5 - 1 = 4.
Using a chi-square distribution table with 4 degrees of freedom and a significance level of 0.05, the critical value is 9.49.
Since our calculated chi-square statistic (52.06) is greater than the critical value (9.49), we can reject the null hypothesis that the housing complex's distribution of residents by race is consistent with the population distribution. Therefore, we can conclude that there is a significant difference between the observed and expected frequencies of race categories.
For the follow-up analysis, we can perform post-hoc tests to determine which race categories have significantly different distributions. One way to do this is to perform chi-square tests of independence between the housing complex's distribution and the population distribution for each race category. We can also calculate the standardized residuals for each race category to determine which categories have the largest contributions to the overall chi-square statistic.
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an extrinsic reward is enjoying what one does for its own sake and an intrinsic reward is an inducement such as money, grades, or recognition.True or False
False. An intrinsic reward is enjoying what one does for its own sake, while an extrinsic reward is an inducement such as money, grades, or recognition.
Intrinsic and extrinsic rewards are two different types of motivational factors that can influence behavior.
Intrinsic rewards are those that come from within oneself, such as the enjoyment of doing a task or the sense of accomplishment that comes from completing it. These rewards are inherently satisfying and enjoyable, and they motivate people to continue doing the task or activity because of the pleasure they derive from it. For example, a person may engage in a hobby like playing music, painting, or playing a sport simply because they find it enjoyable and rewarding in itself.
On the other hand, extrinsic rewards are external motivators that are used to induce or encourage behavior. These rewards are typically tangible, such as money, grades, or recognition, and are given as a result of completing a task or activity. They are designed to incentivize individuals to perform specific actions, often with the aim of achieving a specific goal or outcome. For example, a person may work hard at their job in order to earn a promotion or raise, or may study hard in school to earn good grades.
Intrinsic and extrinsic rewards can both be effective motivators, but they operate in different ways. Intrinsic rewards are powerful because they come from within the individual and are based on personal enjoyment and satisfaction. Extrinsic rewards, on the other hand, are often seen as less powerful and may only work in the short term, because they are not inherently satisfying and may not motivate people to continue performing the task or activity once the reward is removed. However, when used effectively, extrinsic rewards can be a useful tool for motivating people and achieving specific outcomes.
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a committee of 5 members is to be selected from 6 seniors and 4 juniors. fine the number of ways in which this can be done if the committee has at least 1 junior.
a.252
b.6
c.246
d.120
The answer to the question is 'c. 246'. This is calculated by determining the total number of ways to form the committee, subtracting the ways in which only seniors can be selected to ensure at least one junior is included.
Explanation:This question is related to combinatorics, a branch of Mathematics that deals with counting, arrangement, and permutation. Given we have 6 seniors and 4 juniors, and we need to select a committee of 5 members with at least one junior, we can approach it in the following way:
First we consider the total number of ways to form a 5-member committee without any restriction. From 10 people (6 seniors + 4 juniors), we can choose 5 in 10C5 ways, which equals 252. Next, we consider the number of ways to form a 5-member committee with only seniors. From 6 seniors, we can choose 5 in 6C5 ways, which equals 6. We subtract the number of committees that contain only seniors from the total number of committees to find the number of committees with at least one junior. Hence, 252 - 6 = 246 ways.Learn more about Combinatorics here:https://brainly.com/question/32015929
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A soccer player has a large cylindrical water cooler that measures 2.5 feet in diameter and is 5 feet tall. If there are approximately 7.48 gallons of water in a cubic foot, how many gallons of water are in the water cooler when it is completely full? Use π = 3.14 and round to the nearest hundredth.
98.13 gallons
733.98 gallons
24.53 gallons
183.49 gallons
The volume in gallons of the water cooler is 183.49 gallons
How many gallons of water are in the water cooler when it is completely full?We know that the volume of a cylinder of radius R and height H is.
V = pi*R²*H
Where pi = 3.14
Here we know that the diameter is 2.5 ft, then the radius is:
R = 2.5ft/2 = 1.25ft
And the height is 5ft
So the volume is:
V = 3.14*(1.25ft)²*5ft = 24.53125 ft³
And we know that
1ft³ = 7.48 gallons
Then we can do a change of units to get:
24.53125*7.48 gal = 183.49 gal
That is the correct option.
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determine the time necessary for p dollars to doubl when it is invested at ineterest rate r compounded annually, monthly, daily, and continously, (round your answers to two decimal places.)
The time necessary for p dollars to double when it is invested at interest rate r compounded annually is given by the formula:
t = (ln 2) / (r ln (1 + r))
When compounded monthly, the formula becomes:
t = (ln 2) / (12 r ln (1 + r/12))
When compounded daily, the formula becomes:
t = (ln 2) / (365 r ln (1 + r/365))
When compounded continuously, the formula becomes:
t = ln 2 / (r)
Note that ln is the natural logarithm function.
To use these formulas, you need to know the value of the interest rate r. For example, if r is 5%, then:
When compounded annually, t = (ln 2) / (0.05 ln 1.05) = 13.86 years
When compounded monthly, t = (ln 2) / (12 x 0.05 ln 1.0041) = 14.21 years
When compounded daily, t = (ln 2) / (365 x 0.05 ln 1.000137) = 14.27 years
When compounded continuously, t = ln 2 / (0.05) = 13.86 years
Therefore, the time necessary for p dollars to double depends on the interest rate and the frequency of compounding. Generally, the more frequently the interest is compounded, the shorter the time necessary for p dollars to double.
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Select the correct answer. Which logarithmic equation correctly rewrites this exponential equation? 8x = 64 A. log8 64 = x B. log8 x = 64 C. log64 8 = x D. logx 64 = 8 PLEASE HELP
This equation 8^x = 64 rewritten in logarithmic form is x = log₈(64)
What is this equation rewritten in logarithmic form?From the question, we have the following parameters that can be used in our computation:
8^x = 64
Take the logarithm of both sides
So, we have
xlog(8) = log(64)
Divide both sides by log(8)
So, we have
x = log₈(64)
Hence, the equation is x = log₈(64)
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If a section of a line graph is flat, what does that indicate?
A. a mistake in the graph
B. an increase
C. a decrease
D. no change
90° 20" - 78° 45' 30"
Quick pls
I NEED HELP ASAP!!! Please help me!!!
Yes, Step 1 is correct.
No, Step 2 is not correct.
We have to given that;
Simone wants to create a graph of the function g (x) = 1 /(18e¹⁰⁺⁷ˣ) as a transformation of the graph of f (x) = eˣ.
Now, We can simplify as
g (x) = 1 /(18e¹⁰⁺⁷ˣ)
g (x) = (18e¹⁰⁺⁷ˣ) ⁻¹
g (x) = 1/18 e⁻¹⁰⁻⁷ˣ
Hence, We get;
To solve the expression Step 2 is incorrect.
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5, 6, 10
A. Determine whether the side lengths form a triangle. (explain your reasoning)
B. If it is a triangle, determine whether it is a right, acute, or obtuse triangle. (show your work)
The side lengths do indeed form a triangle
The type of triangle is an obtuse triangle.
How to find the triangle ?In order to ascertain if given side lengths culminate in a triangle, recourse may be taken to the triangle inequality theorem. The said theorem stipulates, as a prerequisite for determining any given shape as a triangle, that it is contingent upon the addition of two sides being greater than the length of the third one.
The sums of two sides are greater than the third for all the combinations so this is indeed a triangle.
We can use the Pythagorean theorem to see the type of triangle.
c ² = 10 x 10 = 100
b ² + a ² = 5² + 6² = 61
c² > b ² + a ²
So this is an obtuse triangle.
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Partial differential equation Using the characteristic (integration constant) find the solution to x . ∂u (x.y)/∂x + y . ∂u(x,y)/∂y = 0
with the boundary condition (1, y) = y
The solution to the given Partial differential equation is u(x,y) = y
What is Partial differential equation?
A partial differential equation (PDE) is a mathematical equation that involves two or more independent variables, an unknown function, and its partial derivatives with respect to the independent variables.
To solve the given partial differential equation using the method of characteristics, we need to find the solution along the characteristic curves.
Let dx/dt = x, dy/dt = y
Using the chain rule, we have:
∂u/∂x = ∂u/∂t * dt/dx = ∂u/∂t * 1/x
∂u/∂y = ∂u/∂t * dt/dy = ∂u/∂t * 1/y
Substituting these values in the given PDE, we get:
x * (∂u/∂t * 1/x) + y * (∂u/∂t * 1/y) = 0
∂u/∂t = 0
This means that u is constant along the characteristic curves, which are given by:
dx/x = dy/y
Integrating both sides, we get:
ln|x| = ln|y| + C1
x = C2 * y
where C1 and C2 are integration constants.
Using the boundary condition u(1,y) = y, we get:
u(x,y) = y = C2 * y
C2 = 1
Therefore, the solution to the given PDE is u(x,y) = y
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Identify the form of the following quadratic
Answer:
Standard Form
ax^2 +bx + c = 0
Notice you can already solve for the y-intercept which is (0,4) or y=4
Wyatt walks 3 miles each day for 6 days. Aaliyah walks 4 1/2 miles each day for 6 days. How many more miles will Aaliyah walk in 6 days than Wyatt?
Someone pleeeeease help me
Answer:
Wyatt walks 3 miles per day for 6 days, so he walks a total of:
3 x 6 = 18 miles
Aaliyah walks 4 1/2 miles each day for 6 days, so she walks a total of:
4 1/2 x 6 = 27 miles
To find how many more miles Aaliyah walks than Wyatt, we can subtract Wyatt's total distance from Aaliyah's total distance:
27 - 18 = 9 miles
Therefore, Aaliyah will walk 9 more miles than Wyatt in 6 days.
Step-by-step explanation:
How many functions are there from A = {1, 2, 3} to B = {a, b, c,d}? Briefly explain your answer.
There are 64 functions from set A to set B.
To determine how many functions there are from A = {1, 2, 3} to B = {a, b, c, d}, you can use the following step-by-step explanation:
1. Understand that a function maps each element of set A to exactly one element in set B.
2. Notice that set A has 3 elements, and set B has 4 elements.
3. For each element in set A, there are 4 choices in set B it can be mapped to.
4. Therefore, the total number of functions is equal to the product of the number of choices for each element in set A, which is 4 × 4 × 4 = 64.
So, there are 64 functions from A = {1, 2, 3} to B = {a, b, c, d}.
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Evaluate the integral
The integral expression [tex]\int\limits^4_{-4} {f(x)} \, dx[/tex] when evaluated has a value of 352/3
Evaluating the integral expressionFrom the question, we have the following parameters that can be used in our computation:
[tex]\int\limits^4_{-4} {f(x)} \, dx[/tex]
The function f(x) is a piecewise function
When the functions are combined, we have
f(x) = 4 + 16 - x²
Evaluate the like terms
So, we have
f(x) = 20 - x²
So, we have
[tex]\int\limits^4_{-4} {f(x)} \, dx = \int\limits^4_{-4} {20 - x\²} \, dx[/tex]
Integrate the function
So, we have
[tex]\int\limits^4_{-4} {f(x)} \, dx = 20x - \frac{x^3}3|\limits^4_{-4}[/tex]
Expand the integral expression
This gives
[tex]\int\limits^4_{-4} {f(x)} \, dx = 20(4) - \frac{4^3}3 - 20(-4) + \frac{(-4)^3}3[/tex]
Evaluate the expression
So, we have
[tex]\int\limits^4_{-4} {f(x)} \, dx = \frac{352}{3}[/tex]
Hence, the solution is 352/3
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Given the system of equations: 3x − 3y = 6 2x + 6y = 12 Solve for (x, y) using elimination.a. (−6, 0) b. (3, 1)c. (4, 2)d. (8, 6)
The solution of the system of equations 3x − 3y = 6 and 2x + 6y = 12 is x = 3 and y = 1, hence option is b is correct.
We must eliminate one of the variables by adding or subtracting the two equations in order to solve for (x, y) using elimination. Let us multiply the equation by 2 and 3 respectively so that the equations becomes,
6x - 6y = 12
6x + 18y = 36
Now, using the equations,
24y = 24
So, y = 1. Substituting this back into either of the original equations gives:
3x - 3(1) = 6
3x = 9
So, x = 3. Therefore, the answer of equation is (b) (3, 1).
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Find y' when X4 y - 5xy? = siny +11.
The solution for y' is:
y' = (cosy - 4x^3 y + 5xy'') / (x^4 - 5)
To find y', we will differentiate both sides of the equation with respect to x using the product rule:
First, we differentiate the left side:
d/dx (x^4 y - 5xy') = d/dx (siny + 11)
Using the product rule, we get:
4x^3 y + x^4 y' - 5y' - 5xy'' = cosy * dy/dx
Next, we can simplify the right side since the derivative of a constant is zero:
4x^3 y + x^4 y' - 5y' - 5xy'' = cosy
Finally, we solve for y':
x^4 y' - 5y' - 5xy'' = cosy - 4x^3 y
y'(x^4 - 5) = cosy - 4x^3 y + 5xy''
y' = (cosy - 4x^3 y + 5xy'') / (x^4 - 5)
Therefore, the solution for y' is:
y' = (cosy - 4x^3 y + 5xy'') / (x^4 - 5)
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1000 independent rolls of a fair die will be made. Given that the number 4 appears exactly 128 times and the number 2 appears exactly 160 times, find the probability that the number 1 will appear less than 123 times
The probability that the number 1 appears less than 123 times, given that the number 4 appears exactly 128 times and the number 2 appears exactly 160 times, is approximately 0.9989
To solve this problem, we can use the binomial distribution with n=1000 and [tex]p=\frac{1}{6}[/tex] for each roll of the fair die.
Let X be the number of times the number 1 appears in 1000 rolls. Then X follows a binomial distribution with parameters n=1000 and [tex]p=\frac{1}{6}[/tex].
We want to find P(X < 123), given that the number 4 appears exactly 128 times and the number 2 appears exactly 160 times.
First, we can use the fact that the total number of rolls is 1000 to find the number of remaining rolls:
Remaining rolls = 1000 - (128 + 160) = 712
Next, we can find the number of rolls that are not 1:
Non-1 rolls = 1000 - X
We know that the number 2 appears exactly 160 times, which means that the number of non-2 rolls is:
Non-2 rolls = 1000 - 160 = 840
Similarly, the number of non-4 rolls is:
Non-4 rolls = 1000 - 128 = 872
Since all rolls are independent, we can find the probability that the number 1 appears less than 123 times by using the binomial distribution with parameters n=712 and [tex]p=\frac{5}{6}[/tex] (the probability that a roll is not 1). Thus, we have:
P(X < 123 | X=128, 2=160) = P(Non-1 rolls < 589)
= P(Binomial(712,[tex]\frac{5}{6}[/tex] ) < 589)
=0.9989
Therefore, the probability that the number 1 appears less than 123 times, given that the number 4 appears exactly 128 times and the number 2 appears exactly 160 times, is approximately 0.9989.
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Date: Practise Section 7.2 1. Find the greatest common factor (GCF) of a) 64 and 72 b) 2a2 and 12a c) 4x2 and 6x 2. For each polynomial, indicate if it is in the factored form or expanded form and identify greatest common factor. a) 3x - 12 b) 5(13y - x) c) 3x2 12x + 9 - GCF = GCF = GCF = 3. Completely factor each polynomial and check by expanding a) 3p - 15 b) 21x2 - 9x + 18 c) 6y2 + 18y + 30 = 3( - ) Check: Check: Check: 4. Write a trinomial expression with a GCF of 3n. Factor the expression.
1. a) The prime factorization of 64 is 2^6 and the prime factorization of 72 is 2^3 × 3^2. The common factor is 2^3, so the GCF of 64 and 72 is 8. b) The GCF of 2a^2 and 12a is 2a. c) The GCF of 4x^2 and 6x is 2x.
2. a) Factored form: 3(x - 4), GCF = 3 b) Factored form: 5(13y - x), GCF = 5 c) Expanded form: 3x^2 + 12x + 9, GCF = 3
3. a) 3(p - 5), check: 3p - 15 b) 3(7x - 3)(x + 2), check: 21x^2 - 9x + 18 c) 6(y + 1)(y + 5), check: 6y^2 + 18y + 30
4. A trinomial expression with a GCF of 3n is 3n(x^2 + 4x + 3). Factoring the expression, we get 3n(x + 3)(x + 1).
Let us discuss this in detail.
1. a) The GCF of 64 and 72 is 8.
b) The GCF of 2a^2 and 12a is 2a.
c) The GCF of 4x^2 and 6x is 2x.
2. a) 3x - 12 is in expanded form, GCF = 3.
b) 5(13y - x) is in factored form, GCF = 5.
c) 3x^2 + 12x + 9 is in expanded form, GCF = 3.
3. a) Factoring 3p - 15 gives 3(p - 5), Check: 3(p - 5) = 3p - 15.
b) Factoring 21x^2 - 9x + 18 gives 3(7x^2 - 3x + 6), Check: 3(7x^2 - 3x + 6) = 21x^2 - 9x + 18.
c) Factoring 6y^2 + 18y + 30 gives 6(y^2 + 3y + 5), Check: 6(y^2 + 3y + 5) = 6y^2 + 18y + 30.
4. A trinomial expression with a GCF of 3n could be 3n(x^2 + y^2 + z^2). Factoring this expression gives 3n(x^2 + y^2 + z^2), which is already in factored form.
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plsssssssssss help me
Answer: 40
Step-by-step explanation:
38+ 52=90
230-90=40
Quasilinearization Method
Q9-) Define the maximal solutions and minimal solutions of the
first order IVP.
The Quasilinearization Method is defined as a numerical method used to approximate the solutions of nonlinear differential equations. In the context of first-order initial value problems (IVPs), a maximal solution is the largest possible solution that exists for the given initial value, while a minimal solution is the smallest possible solution that exists for the given initial value.
In other words, a maximal solution is a solution that extends as far as possible beyond the given initial value without encountering any singularities or breaking down, while a minimal solution is a solution that is defined only on a minimal interval around the initial value, beyond which it cannot be extended without encountering a singularity or breaking down.
It is worth noting that not all first-order IVPs have both maximal and minimal solutions, as some may have either no solution, a unique solution, or multiple solutions that overlap or intersect.
However, if a maximal solution and a minimal solution do exist for a given IVP, they are guaranteed to be unique and continuous.
In summary, the Quasilinearization Method can be used to approximate both the maximal and minimal solutions of a first-order IVP, which represent the largest and smallest possible solutions that exist for the given initial value.
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You wish to test the following claim (Ha) at a significance level of a = 0.005. HP1 = P2 Ha:pi < P2 You obtain 31.8% successes in a sample of size ni = 600 from the first population. You obtain 44.6% successes in a sample of size n2 = 314 from the second population. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = -3.861 X What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = 5.6298 X The p-value is... less than (or equal to) a O greater than a
The test statistic for this sample is -3.861, and the p-value for this sample is 0.0001. The p-value is less than the significance level α.
To test the claim (Ha) at a significance level of α = 0.005, with the given information, we will first find the test statistic and then the p-value.
1. Calculate the sample proportions: p1 = 31.8% successes in a sample of size n1 = 600, and p2 = 44.6% successes in a sample of size n2 = 314.
2. Find the difference between the sample proportions: d = p1 - p2.
3. Calculate the pooled proportion: P = (p1 * n1 + p2 * n2) / (n1 + n2).
4. Find the standard error: SE = sqrt(P * (1 - P) * (1/n1 + 1/n2)).
5. Calculate the test statistic (z): z = (d - 0) / SE.
Using the given information, the test statistic is -3.861.
Now, let's find the p-value:
6. Using the standard normal distribution table or calculator, find the p-value corresponding to the test statistic.
The p-value for this sample is 0.0001.
Now, compare the p-value to the significance level α:
The p-value (0.0001) is less than the significance level α (0.005).
Therefore, the test statistic for this sample is -3.861, and the p-value for this sample is 0.0001. The p-value is less than the significance level α.
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Example 1. What are the dimensions of an aluminum can that holds 40 in of juice and that uses the least material? Assume that the can is cylindrical, and is capped on both ends.
Follow the work in example 1 to find an equation (in terms of the radius r) for the total material used in a can having a volume of 10 cubic inches
The juice can will have a minimum material used if the radius of the cylinder is 1.8533 in and the height is 3.7069 in.
Let the radius of the cylindrical can be r in
We are given that the can holds 40 in³ of juice
Hence from the formula of cylinder, we have
πr² X height = 40
or, height = 40/πr²
The total surface area of a cylinder is given by
2π X radius X height + 2π X (radius)²
= 2πr X 40/πr² + 2πr²
= 80/r + 2πr²
Now we need to minimize the above equation
Hence differentiating with respect to r and equating to 0 we get
-80/r² + 4πr = 0
or, -20/r² + πr = 0
or, -20 + πr³ = 0
or, r³ = 20/π
or, r = ∛(20/π)
or, r = 1.8533
Now differentiating again with respect to r we get
160/r³ + 4π
Putting r = ∛(20/π) gives us
8π + 4π = 12π
Since the above result is positive, r = 1.8533 in is the value of the radius for which the surface area is minimized
Hence height is 3.7069 in
Hence the juice can will have a minimum material used if the radius of the cylinder is 1.8533 in and height is 3.7069 in.
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Correct Question
(Image Attached)
Solve the following equation using the zero product property. Enter one solution per box. No brackets {} are needed.
The solution is, the solutions using the Zero Product Property: is x =8 and -5.
The expression to be solved is:
(x-8) (x + 5) = 0
we know that,
The zero product property states that the solution to this equation is the values of each term equals to 0.
now, we have,
(x-8) (x + 5) = 0
i.e. we get,
(x-8) × (x + 5) = 0
so, using the Zero Product Property:
we get,
(x-8) = 0
or,
(x + 5) = 0
so, we have,
x = 8 or, x = -5
The answers are 8 and -5.
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Betty the Baker is baking cakes. Each cake uses 112 cups of flour. She has a 50 pound bag of flour which equals 181 12 cups. How many cakes can she bake with 50 pounds of flour? Write an equation to solve the problem. Be prepared to explain how you determined your answer.
The equation to show the number of cakes that can be baked with 50 pounds of flour, is 181. 5 = c × 112.
How to find the number of cakes ?If we represent the quantity of cakes Betty can make as "c", and it is known that each cake requires 112 cups of flour, with a total of 181.5 cups available, then the equation may be expressed as:
Total flour = Number of cakes × Flour per cake
181. 5 = c × 112
c = 181. 5 / 112
c = 1.62 cakes
In conclusion, 1. 62 cakes can be baked.
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which is better? A 12.5 oz bag of doritos for 3.79 or a bag oz bag for 1.00
Answer: might be the 2nd one
Step-by-step explanation:
Find the exact value.
- sin 150°
- cos 150°
The value of sin 150° is -1/2. and cos 150° is √3/2 (note that it is negative because it is in the second quadrant).
We can use the unit circle to find the exact values of sin 150° and cos 150°.
First, let's consider sin 150°. Since 150° is in the second quadrant, we know that sin 150° is negative. Also, we know that the sine function is periodic with a period of 360°, which means that sin 150° is equal to sin (150° - 360°) = sin (-210°). Now we can use the reference angle of 30° (since 210° is 30° past the 180° mark in the second quadrant) to find the exact value of sin 150°:
sin 150° = sin (-210°) = -sin 30° = -1/2
Therefore, sin 150° is -1/2.
Next, let's consider cos 150°. Since 150° is in the second quadrant, we know that cos 150° is negative. Also, we know that the cosine function is periodic with a period of 360°, which means that cos 150° is equal to cos (150° - 360°) = cos (-210°). Now we can use the reference angle of 30° to find the exact value of cos 150°:
cos 150° = cos (-210°) = cos 30° = √3/2
Therefore, cos 150° is √3/2 (note that it is negative because it is in the second quadrant).
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In each of the following scenarios, we consider the distribution of a quantity along an axis. a. Suppose that the function c(x) = 200 + 100e0.13 models the density of traffic on a straight road, measured in cars per mile, where x is number of miles east of a major interchange, and consider the definite integral Só (200 + 100e-0.12) dr. i. What are the units on the product c(x) · Ax? ii. What are the units on the definite integral and its Riemann sum approximation given by 1 cle *= c(x) dx = c(x;)Ax? 2=1 iii. Evaluate the definite integral ſ c(x) dx = fó (200 + 100e -0.13) de and write one sentence to explain the meaning of the value you find. b. On a 6 foot long shelf filled with books, the function B models the distribution of the weight of the books, in pounds per inch, where x is the number of inches from the left end of the bookshelf. Let B(x) be given by the rule B(x) = 0.5 + (2+1)2 i. What are the units on the product B(x) · Ax? ii. What are the units on the definite integral and its Riemann sum approximation given by 36 B(x)dt = B(;)Az? 12 21 ii. Evaluate the definite integral f," B(z) dx = fo? (0.5+ (213) de + (x+1) and write one sentence to explain the meaning of the value you find.
In scenario a, the function c(x) represents the density of traffic on a straight road, measured in cars per mile, where x is the number of miles east of a major interchange. The product c(x) · Ax has units of cars, as it represents the number of cars in a certain segment of the road. The definite integral ∫ c(x) dx and its Riemann sum approximation given by 1/n ∑ c(xi) · Δx have units of cars per mile, as they represent the average density of traffic over a certain distance. When evaluating the definite integral ∫ c(x) dx, we get a value that represents the total number of cars on the road between two given points.
In scenario b, the function B(x) represents the distribution of the weight of books on a shelf, in pounds per inch, where x is the number of inches from the left end of the shelf. The product B(x) · Ax has units of pounds, as it represents the weight of books in a certain segment of the shelf. The definite integral ∫ B(x) dx and its Riemann sum approximation given by 1/n ∑ B(xi) · Δx have units of pounds, as they represent the total weight of books on the shelf. When evaluating the definite integral ∫ B(x) dx, we get a value that represents the total weight of books on the shelf.
a. i. The units on the product c(x) · Δx are cars per mile (from c(x)) multiplied by miles (from Δx), resulting in cars.
a. ii. The units on the definite integral and its Riemann sum approximation are the same as the units on the product c(x) · Δx, which are cars.
a. iii. To evaluate the definite integral, we have:
∫(200 + 100e^(-0.12x)) dx
Using the integral rules, we get:
[200x - (100/0.12)e^(-0.12x)] (evaluate this from 0 to a specific value to find the total cars between 0 and that value)
The meaning of the value is the total number of cars on the road between 0 miles and the specified value of x miles east of the major interchange.
b. i. The units on the product B(x) · Δx are pounds per inch (from B(x)) multiplied by inches (from Δx), resulting in pounds.
b. ii. The units on the definite integral and its Riemann sum approximation are the same as the units on the product B(x) · Δx, which are pounds.
b. iii. To evaluate the definite integral, we have:
∫(0.5 + (x+1)^2) dx
Using the integral rules, we get:
[0.5x + (1/3)(x+1)^3] (evaluate this from 0 to 72 to find the total weight of books on the shelf)
The meaning of the value is the total weight of the books on the 6-foot-long shelf.
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If $16000 is invested in an online saving account earning 4% per year, how much will be in the account at the end of 25 years if there are no other deposits or withdrawals and interest is compounded: semiannually? , quarterly? , daily? , continuously?
The amount of money in the account at the end of 25 years will be:
$38,419.83 if interest is compounded semiannually
$39,020.28 if interest is compounded quarterly
$39,214.44 if interest is compounded daily
$39,243.86 if interest is compounded continuously
We have,
We can use the formula for compound interest.
[tex]A = P(1 + r/n)^{nt}[/tex]
where:
A is the amount of money in the account after t years
P is the initial principal amount (the amount invested)
r is the annual interest rate (as a decimal)
n is the number of times the interest is compounded per year
t is the number of years
Now,
P = $16,000
r = 4% = 0.04
To find the amount of money in the account with different compounding periods, we need to plug in different values for n.
If interest is compounded semiannually, we have n = 2 and t = 25:
So,
A = 16000(1 + 0.04/2)^(2 x 25)
A = $38,419.83
If interest is compounded quarterly, we have n = 4 and t = 25:
A = 16000(1 + 0.04/4)^(4 x 25)
A = $39,020.28
If interest is compounded daily, we have n = 365 (assuming 365 days in a year) and t = 25:
A = 16000(1 + 0.04/365)^(365 x 25)
A = $39,214.44
If interest is compounded continuously, we have n = infinity and t = 25:
A = 16000e^(0.04 x 25)
A = $39,243.86
Therefore,
The amount of money in the account at the end of 25 years will be:
$38,419.83 if interest is compounded semiannually
$39,020.28 if interest is compounded quarterly
$39,214.44 if interest is compounded daily
$39,243.86 if interest is compounded continuously
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If you go on both rides, can you be confident that your wait time for Speed Slide will be longer than your wait time for Wave Machine? Yes. Every Speed Slide wait time is more than every Wave Machine wait time. No. There is a lot of overlap in the two data sets.
Answer:
No
Step-by-step explanation:
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