The chart shows the distances, in miles, between three places.
a)Write down the distance
from Hereford to Chester.
b) Which town is 99 miles
from Kendal?
c)If Ellen drives from Kendal to
Hereford via Chester, how
many miles will she drive?

The t-statistic for this hypothesis test will be 1.50 as "the average flight time for the pilots is found to be 8.12 hours. the standard deviation reported by the faa is 0.72 hours, and there were 81 pilots in the sample."

A statistic used in statistical hypothesis testing is known as a test statistic. A test statistic, which can be thought of as a numerical summary of a data set that condenses the data into a single value that can be used to conduct the hypothesis test, is how a hypothesis test is typically expressed. A number derived from a statistical test of a hypothesis is the test statistic. It displays how closely your actual data match the distribution predicted by the statistical test's null hypothesis.

Here,

test statistic t is,

t = (x' - μ)/(σ/√n)

x'=8.12 hours

μ=8 hours

σ=0.72 hours

n=81 pilot

t=(8.12-8)/0.72/(√81)

=0.12/0.08

t=1.5

For this hypothesis test, the t-statistic will be 1.50 as "The pilots' average flight time was found to be 8.12 hours. There were 81 pilots in the sample, and the faa reported a standard deviation of 0.72 hours."

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Step-by-step explanation:

In Peter class three times as many students who wear glasses are those who do not.there are 28 students in the class. How many students do not wear glasses?

with glasses: x
without glasses: 3x

x + 3x = 28

4x = 28

x = 7 with glasses

7 * 3 = 21 without glasses

A(n) Control Chart is a scatter chart with time on the horizontal axis, measurement scale on the vertical axis, displays mean and control limits, and may mark two standard deviations from the mean.

A control chart is one of the process improvement techniques or simply it is a graph to study how a process changes over time. In layman's terms the control chart shows if a process is under control or out of control. For calculating the average, there is always a central line in the control chart, an upper line and a lower line for upper control limit and lower control limit respectively.

The control charts are used to serve many purposes including monitoring a process for special variations and their causes and to remove them, estimating the process average and the variation, predicting the impacts of the process , etc.

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Answer:

x=12°

Step-by-step explanation:

10x-20+6x+8=180°

16x=180+20-8

16x=192

x=12°

The greater principal is there for Account A as $400.

Simple interest can be defined as a type of interest where the rate is applied on the same principal.

Given that,

The interest for Account A is $15.75 and Account B is  $28.

The total time for interest is 21 months.

Rate of interest for Account A is  3% and Account B is 4%.

Now, the time period can be written in years as,

21 months = 21 / 12 years

                  = 7 / 4

Suppose the principal for Account A and Account B is P₁ and P₂ respectively.

The formula for simple interest is given as,

(P × r × t) / 100

Substitute the respective values for both the accounts to get,

For Account A,

15.75 = (P × 3 × 7 / 4) / 100

⇒ P = (1575 × 4) / (3 × 7)

⇒ P = 300

For Account B,

28 = (P × 4 × 7 / 4) / 100

⇒ P = 2800 / 7

⇒ P = 400

Hence, Account B had greater principal.

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No , Sydney does not have enough beads to make 15 rings .

beads required for one ring = 60

total rings she have to make is = 15

total beads she has to make rings = 852 beads

now,

60 beads make ring = 1

852 beads make rings = 1/60 x 852

                                     =    14.2 rings

                             OR

                          14 total rings

So , Sydney does not have enough beads to make 15 rings . she can only make 14 beads from the given amount of beads.

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Answer: x=10

Step-by-step explanation:

Images below

Help this helps

For the given triangle JKL, the value of x is 10. An angle is a figure in Plane Geometry formed by two rays or lines that share a common endpoint.

Given information:

In  ∠J K L,JL is extended through point L to point M.

[tex]$&m \angle J K L=(2 x+14)^{\circ} \\[/tex]

[tex]$&m \angle L J K=(3 x+15)^{\circ} \\[/tex]

[tex]$&m \angle K L M=(7 x+9)^{\circ}[/tex]

See the attached figure.

At point L, the measure of angle JLK will be as,

[tex]$&m \angle J L K=180-m \angle K L M=180-7 x-9 \\[/tex]

[tex]$&=(171-7 x)^{\circ}[/tex]

Now, in triangle JKL, use the angle sum property to find the value of x as,

[tex]$$m \angle J K L+m \angle L J K+m \angle J L K=180[/tex]

[tex]$$$(2 x+14)^{\circ}+(3 x+15)^{\circ}+(171-7 x)^{\circ}=180$[/tex]

-2 x+200=180

2 x=20

x=10

Therefore, the value of x for the given triangle JKL is 10.

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The system of equations has its solutions to be (1, -1) and (7, -1)

The system of equations is given as

(x−4)² + (y+1)² = 9

(x−4)²/9 + (y+1)²/81 = 1

Make (y + 1)² the subject in the equation (x−4)² + (y+1)² = 9

So, we have

(y+1)² = 9 - (x−4)²

Substitute (y+1)² = 9 - (x−4)² in (x−4)²/9 + (y+1)²/81 = 1

This gives

(x−4)²/9 + [9 - (x−4)²]/81 = 1

Split

(x−4)²/9 + 9/81 - (x−4)²/81 = 1

Collect the like terms

(x−4)²/9 - (x−4)²/81 = 1 - 9/81

Evaluate the like terms

[9(x−4)² - (x−4)²]/81 = 72/81

So, we have

9(x−4)² - (x−4)² = 72

Evaluate the difference

8(x−4)² = 72

Divide by 8

(x−4)² = 9

Take the square roots

x - 4 = ±3

So, we have

x = 4 ± 3

Evaluate

x = 1 or 7

Substitute x = 1 or 7 in (y+1)² = 9 - (x−4)²

(y + 1)² = 9 - (1−4)² or (y + 1)² = 9 - (7−4)²

This gives

(y + 1)² = 0 or (y + 1)² = 0

This gives

y + 1 = 0

Evaluate

y = -1

Hence, the solution is (1, -1) and (7, -1)

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The equation of given graph is y = |x - 3| + 5.

The graph of a absolute or modulus function is a V- shape graph. The function of absolute is f(x) = |x|. The general form of absolute function is f(x)=a |x - h| + k. Where (h,k) is the vertex of graph.

Here, we can see that graph is in the form of V shape, so the function will be absolute function. Now, we have to find the vertex of graph.

As seen from the graph the minimum point on the graph is located at the point (3, 5) and the value of a should be 1.

So, by putting the value of vertex in general equation we get the equation of the graph,

y = |x - 3| + 5

Therefore, the equation of given graph is y = |x - 3| + 5.

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The statement that cannot be assumed from the figure is

B) BD bisects ∠ADE

What are Supplementary and Complementary Angles?

Supplementary angles are two angles that have a sum of 180°.

Complementary angles are two angles that have a sum of 90°.

Given data ,

From the figure we can arrive at each conclusions

A)

∠ABD and ∠DBE are supplementary

Now , from the figure we can see that point B lies on the line AE

And , ∠ABD + ∠DBE = 180°

Hence , ∠ABD and ∠DBE are supplementary and the statement is TRUE

B)

Bisecting a line means dividing the line into two equal parts

And from the figure BD does not bisect ∠ADE

Hence , BD does not bisect ∠ADE so the statement is FALSE

C)

∠CDA and ∠ADE are complementary

From the figure we can see that ∠EDC is 90°

And , ∠CDA + ∠ADE = ∠EDC

So , ∠CDA + ∠ADE = 90°

Hence , ∠CDA and ∠ADE are complementary and the statement is TRUE

D)

∠EDB and ∠BDA are adjacent and are not complementary

From the figure we can see that ∠EDB and ∠BDA are adjacent

∠EDB + ∠BDA ≠ 90°

Hence , they are not complementary and the statement is TRUE

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The scenario describes the stratified random sampling method .

There are many sampling techniques to collect sample from a given population such as Simple random sampling , Systematic Sampling , Cluster Sampling and so on . All of them vary in reliability , accuracy and efficiency .

Stratified Random Sampling : It is a method of  sampling in which division of population is done into smaller subgroups known as strata .The strata are formed based on member's shared attributes or characteristics . It has numerous applications . It is also called proportional random sampling or quota random sampling .

Therefore , the scenario describes the stratified random sampling method .

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Using the concepts of probability, we got that  0.0764 is the probability that the sum of the 100 values is greater than 3,908 when a researcher measure the amount of sugar in several cans of the same soda.

The z-score of a measure X of a normally distributed variable with mean  and standard deviation is given by:

                 Z=(X-μ)/σ

For this problem, these parameters are given as follows:

μ=39.01,σ=0.5,n=100,s=0.5/√100=0.05

A sum of  3908 is equivalent to a sample mean of 3908/100 = 39.08, which means that the probability is the p-value of Z when X = 39.08, hence:

Z=(X-μ)/σ

By the Central Limit Theorem:

Z=(X-μ)/s

=>Z=(39.08-39.01)/0.05

=>Z=(0.07)/0.05

=>Z=7/5

=>Z=1.4

Z = 1.4 has a p-value of 0.0764.

Hence, the probability that the sum of the 100 values is greater than 3,908 is 0.0764.

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Answer:

[tex]\huge\boxed{\sf m = 11}[/tex]

Step-by-step explanation:

-7m + 10m - 8 = 25

3m - 8 = 25

Add 8 to both sides

3m = 25 + 8

3m = 33

Divide 3 to both sides

m = 33/3

m = 11

[tex]\rule[225]{225}{2}[/tex]

Answer:

y = [tex]\frac{2}{3}[/tex] x - 6

Step-by-step explanation:

y - [tex]\frac{2}{3}[/tex] x = - 6 ( isolate y by adding [tex]\frac{2}{3}[/tex] x to both sides )

y = [tex]\frac{2}{3}[/tex] x - 6

The value of b of the equation is -9/5

Given that: line JK passes through points J(-4,-5) and K(-6,3) and if the equation of the line is written in slope-intercept form, y=mx+b

The equation of line is an algebraic form of representing the set of points, which together form a line in a coordinate system

Using the y-y₁/y₂-y₁ = x-x₁/x₂-x₁

where (x₁, y₁) = (-4,-5) and (x₂, y₂) = (-6,3), the equation is:

y-(-5) / 3-(-5) = x-(-4)/-6-(-4)

y+5 / 3+5 = x+4 /6+4

(y+5)/8 =  (x+4)/10       cross multiply:

10(y+5) = 8(x+4)

10y + 50 = 8x + 32

10y = 8x +32 - 50

10y = 8x - 18

y = 8x/10 - 18/10

y = 4x/5 - 9/5

Comparing y = 4x/5 - 9/5 with y=mx+b

b = -9/5

Therefore, the value of b is -9/5

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The probability of not rolling a 5 is [tex]\frac{1}{6}[/tex]

For any event A, the probability of not getting A is given by

[tex]P(not A)= 1- P(A)[/tex]

A number cube with six sides numbered 1 through 6 is rolled.

Then we have,

The total number of possible outcomes [tex]= 6[/tex]

Also, it is given that, The probability of rolling a 5 is

P(rolling 5)=[tex]\frac{1}{6}[/tex].

Now, the probability of not rolling a 5 will be

[tex]P(\text{not rolling a 5})= 1- P(\text{rolling 5})[/tex]

[tex]=1-\frac{1}{6}[/tex]

[tex]=\frac{5}{6}[/tex]

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The maximum number of hikers who could have walked between 6 miles and 17 miles is 19.

We need to find the maximum number of hikers who could have walked between 6 miles and 17 miles.

When the derivative equals 0, rearrange the function using elementary algebraic principles to find the value for x. The x-coordinate of the function's vertex, which is where the maximum or lowest will occur, is provided in this answer. the solution back into the original function to determine the minimum or maximum.

From the table, we can see

Between intervals 5≤x<10 there are 2 hikers

Between intervals 10≤x<15 there are 9 hikers

Between intervals 15≤x<20 there are 8 hikers

So, total number of hikers = 2+9+8

= 19

Hence, the maximum number of hikers who could have walked between 6 miles and 17 miles is 19.

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Answer: 27 dogs

Step-by-step explanation: 2 cats + 3 dogs= 5 in total for animals. 2/5x45=18 cats

3/5x45= 27 dogs

27+18=45 animals

There is 27 dogs in the shelter

Brian has  £63 Initially, by using the ratio and proportion method.

What are Ratio and Proportion?

In this section, the terms ratio and percentage are defined. Both ideas play a significant role in mathematics. Numerous examples where the notion of the ratio is highlighted may be found in daily life, such as the rate of speed (distance/time) or price (rupees/meter) of a substance.

An equation known as proportion shows that the two ratios presented are equal to one another. For instance, the time it takes a train to go 100 kilometers per hour is equal to the time it needs to travel 500 kilometers in five hours. Example: 100 km/hr = 500 km/5 hour. The division technique of comparing two amounts can be quite effective in some circumstances. We can argue that a ratio is a comparison or condensed form of two quantities of the same type. We may determine how many times one quantity is equal to another using this relationship. The ratio may be defined as the number that can be used to represent one quantity as a percentage of another. Only when the two numbers in a ratio have the same unit can they be compared. Ratios are used to compare two objects. A ratio is indicated by the symbol ":".

In the question, It is given that:

The ratio of money in Brian's wallet to Colin's wallet one day was 7:2.

Let 7x denotes the amount in Brian's wallet and 2x denote the amount in  Colin's wallet on that day.

we know that:

Brian spent £39 that day.

Amount left in Brian's wallet = 7x- 39

Brian now had £4 less than Colin.

⇒ 2x -4= 7x- 39

⇒  7x-2x=4+39

⇒  5x=35

⇒  x=7   [Divide both sides by 5 ]

So , The initial amount in Brian's wallet  = 7(7)= £49

The initial amount in Colin's wallet = 2(7)= £14

The amount they had together =  £49+£14 = £63

So, They had £63 altogether initially.

Therefore, Brian has  £63 Initially.

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Answer: £14

Reject a null hypothesis because computed t is higher than 2.821 is the decision rule.

For the given question;

Test hypothesis:

H₀; μ = 3.5

Upper tailed test:

Hₐ; μ > 3.5

Significance value; α = 10.

Then, degree of freedom.

Df = α - 1

Df = 10 - 1

Df = 9

The critical value;

t(₀.₀₁, ₉) = 2.821

Rejection region;

Rejected H₀ for t > 2.821

Thus, reject a null hypothesis because computed t is higher than 2.821 is the decision rule for the absorption amount of the sponge.

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What is the correct standard form for 400+3+0.07+0.001

403.071

Answer:

=4.03071×10²

Step-by-step explanation:

400+3=403

=403+0.07=403.07

=403.07+0.001=403.071

so 403.071 to standard form is 403.071 divide by 100 is 4.03071 and 10 and and also change to 2 zeros and Chang it to powers so =4.03071×10²

The equation of a line is y = 5x - 6

What is Equation of line ?

A straight line's general equation is y = mx + b, where m denotes the gradient or slope and y = b denotes the point at which the line crosses the y-axis. On the y-axis, this value b is referred to as the intercept.

The given points are (2, 4) and (-4, 6)

The equation of line is given ,

y = mx + b

where, m = slope

b = y - intercept

To find slope , we have formula

slope (m) = (y2 - y1) / (x2 - x1)

let, (x1, x2) = (2, 4) and

(y2, y1) = (-4, 6)

Now, put the values in slope formula,

m = ( 6 - (-4) ) / ( 4 - 2)

m = (6 + 4) / 2

m = 10 / 2

m = 5

We get slope, now find y-intercept i,e, 'b'

y = 5x + b

so take any point to find 'b'

Let's take the point (2, 4) which is (x, y) so now put the (x, y) and find 'b'.

4 = 5 * 2 + b

4 = 10 + b

b = 4 - 10

b = -6

so, now put the values of slope and y-intercept in equation of line i.e,        y = mx + b

y = 5x - 6

Hence, the equation of a line is y = 5x - 6

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Answer:

8.31

Step-by-step explanation:

-6n² = -414

[take away negative]

6n² = 414

[divide by 6]

n² = 69

n = 8.3066 (to 5 significant figures)

n = 8.31 (to 3 significant figures)

The mean recurrence interval between earthquakes of this magnitude range over the previous 30 years essentially has been 4.769230 in a basically sort of big way in a subtle way.

Given, the earthquake's magnitude literally basically is between 6.0 and 7.0 in a very definitely big way, or so they for all intents and purposes thought. occurrences = 2 earthquakes

Duration: 30 years

particularly Mean Earthquake Recurrence Interval,

T=(n+1) / m

Where m = 6+7 / 2 = 6.5 , n = 30

T = ( 30+1)/6.5

   = 31/6.5

   = 4.769230

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Answer:

Step-by-step explanation:

Answer:Yes, because the line that represents the first wall has a slope of -.25 and the line that represents the second wall has a slope of 4

Step-by-step explanation:

check the slope of both points

(-6,11.5) to (2, 9.5)  

11.5-9.5= 2

-6-2=-8

2/-8

m=-1/4

(-1, -2.5) to (2,9.5)

-2.5=9.5=-12

-1-2=3

-12/-3

m=4

Yes, because the line that represents the first wall has a slope of -.25 and the line that represents the second wall has a slope of 4

We're given :
Patricia originally has $3425.82 in her account.

After that, she deposits $9120.75, meaning her amount in her account goes up by $9120.75

Lastly, she withdraws $185.90, meaning her amount in her account goes down by $185.90.

Therefore, after the transactions, she has a total of : 3425.82 + 9120.75 - 185.90 = $12360.67

The value of the car when she first purchased is $25001.73

Given,

current value of car =$18701.30

rate of depreciation annually=7%

time period =4 years

let the value of car when she first purchased be'x'

To find the value of car when she first purchased when it depreciated exponentially at constant rate ,use formula,

[tex]a(1-\frac{r}{100})^t=b[/tex]

Where,

a=value of car when she purchased

r=rate of depreciation annually

t=time period

b=current value of car

[tex]x(1-\frac{7}{100})^4=18701.30\\\\x(1-0.07)^4=18701.30\\\\x(0.93)^4=18701.30\\\\x(0.748)=18701.30\\\\x=\frac{18701.30}{0.748}\\\\x=25001.73[/tex]

Thus, the value of the car when she first purchased is $25001.73

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The coefficient of the third term in the given expression is -4

From the question, we are to determine the coefficient of the third term in the given expression.

A coefficient is the numerical value that is written along with a variable or it is multiplied by the variable.

The given expression is

5 – 2t3 – 4t3u3 + 8v

This can be properly written as

5 - 2t³ - 4t³u³ + 8v

The third term in this expression is - 4t³u³

In this term, the numerical value that is written along with the variable is -4

Hence, the coefficient is -4

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Maggie's age is less than or equal to 11, m ≤ 11

An inequality can simply be described as a relation that makes an unequal comparison between two objects, numbers, elements or mathematical expressions.

It is used to compare numbers on the number line on the basis of their sizes

From the information given, we have that;

Let's substitute the values

5m + 4 + m ≤ 70

Now, let's collect like terms

6m ≤ 70 - 4

Subtract like terms

6m ≤ 66

Make 'x' the subject of formula by dividing both sides by its coefficient

m ≤ 66/ 6

m ≤ 11

Hence, the value is m ≤ 11

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