The demand for a new computer game can be modeled by p (x )equals 48.5 minus 5 ln x​, for 0less than or equalsxless than or equals​800, where​ p(x) is the price consumers will​ pay, in​ dollars, and x is the number of games​ sold, in thousands. Recall that total revenue is given by R (x)= x * p (x). Complete parts​ (a) through​ (c) below.



a. Find R(x).


b. Find the marginal revenue, R'(x)



c. Is there any price at which revenue will be maximized? Why or why not? Choose the correct answer below.



a. No, because p(x)R'(x). Therefore, the revenue cannot be maximized.


b. No, because the marginal revenue, R'(x), has no maximum. Therefore, revenue will always increase


c. Yes, because the revenue will be maximized when R(x)-R'(x). The price to the consumer would be $:_____


d. Yes, because the revenue will be maximized when R'(x)=0. The price to the consumer would be $:_____

Answer:

a. R(x) = 48.5x - x5inx

b. R'(x) = 43.5 - 5lnx

c. The correct option is d. Yes, because the revenue will be maximized when R'(x)=0. The price to the consumer would be $5.

Explanation:

Given:

p(x) = 48.5 - 5lnx, for 0 ≤ x ≤ 800 ............. (1)

a. Find R(x).

R (x) = x * p (x) ........................ (2)

Substitute equation (1) into (2), we have:

R(x) = x(48.5 - 5lnx)

R(x) = 48.5x - x5inx .............................. (3)

Equation (1) is the R(x) required to be found.

b. Find the marginal revenue, R'(x)

The derivative of equation (3) is taken to obtain R'(x) as follows:

R'(x) = 48.5 - 5lnx - x5(1/x)

R'(x) = 48.5 - 5lnx - 5

R'(x) = 48.5 - 5 - 5lnx

R'(x) = 43.5 - 5lnx ...................... (4)

Equation (4) is the marginal revenue, R'(x), required to found.

c. Is there any price at which revenue will be maximized? Why or why not? Choose the correct answer below.

Profit is maximized when R'(x) = 0

Equating equation (4) to 0 and solve for x, we have:

43.5 - 5lnx = 0

43.5 = 5lnx

5lnx = 43.5

lnx = 43.5 / 5

x = e^(43.5 / 5)

x = 6,002.91

Substituting x = 6,002.91 into equation (1), we have:

p(x) = 48.5 - (5 * ln(6,002.91))

p(x) = 48.5 - (5 * 8.70)

p(x) = 48.5 - 43.5

p(x) = $5

Therefore, the correct option is d. Yes, because the revenue will be maximized when R'(x)=0. The price to the consumer would be $5.

Mill Company began operations on January 1, 20X1, and recognized income from construction-type contracts under different methods for tax purposes and financial reporting purposes. Information concerning income recognition under each method is as follows: Year Tax Purposes Book Purposes 20X1 $ 400,000 $ 0 20X2 625,000 375,000 20X3 750,000 850,000 Required: Assume the income tax rate is 21% in all years and that Mill has no other temporary differences. In its December 31, 20X3, balance sheet, what amount of deferred income taxes should Mill report