The design of a new road includes a straight stretch that is horizontal and flat but that suddenly dips down a steep hill at 18°. The transition should be rounded with what minimum radius so that cars traveling 95 km/h will not leave the road

Answers

Answer 1

Answer:

  74.7 m

Explanation:

You want the minimum radius of curvature of a vertical circular arc so that vehicles traveling 95 km/h making the transition from horizontal to an 18° down grade will not leave the road.

Acceleration

The acceleration due to gravity on the vehicle at the point it is traveling 18° down is ...

  g·cos(18°) ≈ (9.8 m/s²)·0.95106 ≈ 9.32 m/s²

Radius

The radius of an arc and the speed of travel are related to the normal acceleration by ...

  r = v²/a

where v is the speed along the arc, and 'a' is the normal acceleration required to make an object follow the circular curve.

The speed of 95 km/h can be translated to m/s by ...

  (95 km/h) · (1000 m/(1 km)) · (1 h)/(3600 s) = 95/3.6 m/s ≈ 26.389 m/s

Radius

Using the above relation to find the radius, we get ...

  r = (26.389 m/s)²/(9.32 m/s²) ≈ 74.72 m

The minimum radius of the vertical circular arc should be 74.7 meters to prevent vehicles from becoming airborne.

__

Additional comment

In actual roadway design, factors of sight distance and stopping distance come into play. Sight distance over this crest would be about 25 m. It would need to be more than 6 times that distance for the roadway to be safe at 95 km/h.

An 18° down grade is about 3 times the usual maximum for roadway design, which will severely increase stopping distance. The vertical arc described here would leave the car with no normal force on the roadway at the end of the arc, so braking would be impossible. Passengers would be feeling weightless, too.

Roadway curves are generally parabolic (not circular), so they have a constant rate of change of slope with horizontal distance.

 The Design Of A New Road Includes A Straight Stretch That Is Horizontal And Flat But That Suddenly Dips

Related Questions

A force of 10 N acts on a toy car of mass 2kg. What is the acceleration if the force is doubled?



Answers

Explanation:

According to newton's second law.

The acceleration of the car would be 10 m/s² if the force (10 N) on it is doubled.

We know that the acceleration of an object can be calculated using the formula ⇒ a = F/m (i)

Here, the force experienced by the car is ⇒ F = 10 N

If this force is doubled we would have ⇒ 2×10 ⇒ 20 N (ii)

The mass of the car is ⇒ m = 2 kg (iii)

Now, putting the values of the doubled force and mass (ii and iii) in (i), we get ⇒ a = 20/2

a = 10 m/s²

Therefore, the car has an acceleration of 10 m/s² when the force on it is doubled.

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Show that an electron falling from n = 4 to n = 3 in the hydrogen atom will produce a photon in the infrared region.

Answers

The wavelength of the light is 1.92 * 10^-6 m which corresponds to the infrared region as shown in the image attached.

What is the energy of the hydrogen atom?

We know that the hydrogen atom has electrons that occupy energy levels that are in conformity with the Bohr model. According to the Bohr model, electrons can move from a higher to a lower energy level.

We now have;

1/λ = RH (1/[tex]n_{2} ^2[/tex] - 1/[tex]n_{1}^2[/tex])

λ = wavelength

RH = Rydberg constant

The initial and the final levels are also shown therefore;

1/λ = 1.097 * 10^7 ( 1/3^2 - 1/4^2)

1/λ= 1.097 * 10^7 (0.11 - 0.0625)

λ=1.92 * 10^-6 m

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what form of energy can you produce by rubbing an eraser against a piece of paper?

Answers

Answer:

it gets hot

Explanation:

because you are rubbing it hard

you can produce heat by rubbing an eraser against a piece of paper.

It takes 5.91 J of work to stretch a Hooke’s-law spring 4.78 cm from its unstressed length.
How much the extra work is required to stretch it an additional 9.95 cm?
Answer in units of J.

Answers

The extra work is required to stretch the spring to an additional 9.95 cm is 25.61 J.

What is the spring constant of spring?

The spring constant of the spring is determined by applying the formula for elastic potential energy of a spring as shown below.

E = ¹/₂kx²

where;

k is the spring constantx is the extension of the spring

kx²= 2E

k = 2E/x²

k = (2 x 5.91)/(0.0478²)

k = 5,173.2 N/m

The work done to stretch the string to 9.95 cm is calculated as;

E = ¹/₂kx²

E = ¹/₂(5173.2)(0.0995)²

E = 25.61 J

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give me a water analogy of an electric current with high current but low voltage

Answers

A battery is analogous to a pump in a water circuit

What is the water analogy for current ?

A pump receives water at low pressure, processes it, and ejects it at high pressure. A battery absorbs a charge at low voltage, processes it, and then expels it at high voltage.

Voltage, current, and power may all be explained using the water/hose analogy in relation to electricity. Generally speaking, charge, voltage, and current represent the flow, pressure, and charge of water, respectively. Water flowing continuously throughout time is referred to as power.

An illustration of a water tank is frequently used to explain voltage, current, and resistance. This analogy compares charge to the volume of water, voltage to the pressure of the water, and current to the movement of the water.

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Explain how friction affects the mechanical energy of a system

Answers

Friction decreases the kinetic energy which decreases the mechanical energy


Calculate the useful power output for an electric motor that uses 200 W and has an
efficiency of 40%

Answers

Correct option is B)

Power with which crane lifts the load =0.8×0.9 × input power

P=0.8×0.9×200 kW

Now, P=

F

.

v

Here, F=mg (since there is no acceleration)

10

3

×0.8×0.9×200=3.6×10

3

×10×v

⇒v=4 m/s

A 975-kg car accelerates from rest to 26.7 m/s in a distance of 120 m. What is the magnitude of the average net force acting on the car?

Answers

The force that is applied to the car is 2896 N.

What is the acceleration?

We know that the acceleration is the often gotten by the use of the kinematic equations. We can write;

v^2 = u^2 + 2as

Given that;

v = final velocity

u = initial velocity

a = acceleration

s = distance

Then we know that u = o m/s since it started from rest

v^2 = 2as

a = v^2/2s

a = (26.7)^2/ 2 *  120

a = 2.97 m/s^2

We know that;

Force = mass * acceleration

Force = 975-kg * 2.97 m/s^2

Force = 2896 N

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A 10 kg object is on a movable platform. Rank the size of the normal force acting on the object from largest to smallest.
a) The object is at rest and the platform is not moving

b) the object is at rest on the stationary platform and there is a downward force of 10N applied to the top of the object while it remains stationary

c) the object is at rest on the stationary platform and there is an upward force of 10N applied to the top of the object while it remains stationary

d) the platform is accelerating the object upward at 1.5 m/s^2

e) the platform is accelerating the object downward at 0.5 m/s^2

Answers

The size of the normal force acting on the object from largest to smallest are;

(b) The object is at rest on the stationary platform and there is a downward force of 10N applied to the top of the object while it remains stationary.

(e) The platform is accelerating the object downward at 0.5 m/s^2.

(a) The object is at rest and the platform is not moving.

(c) The object is at rest on the stationary platform and there is an upward force of 10N applied to the top of the object while it remains stationary

(d) the platform is accelerating the object upward at 1.5 m/s^2.

What is normal force?

The normal force of an object is the upward force exerted on the object by the supporting surface due to weight of the object acting downwards.

The formula for normal force is given as;

Fn = mg

where;

m is mass of the objectg is acceleration due to gravity

The normal force on the 10 kg object when it is  at rest and the platform is not moving,

Fn = mg

Fn = 10 x 9.8

Fn = 98 N

When the object is at rest on the stationary platform and there is a downward force of 10N applied to the top of the object while it remains stationary,

Fn = (10 x 9.8) + 10 N

Fn = 108 N

When the object is at rest on the stationary platform and there is a upward force of 10N applied to the top of the object while it remains stationary,

Fn = (10 x 9.8) - 10 N

Fn = 88 N

When the platform is accelerating the object upward at 1.5 m/s^2

Fn = (10 x 9.8) - (1.5 x 10)

Fn = 98 N - 15 N

Fn = 83 N

When the platform is accelerating the object downward at 1.5 m/s^2

Fn = (10 x 9.8) + (10 x 0.5)

Fn = 103 N

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Which of the following are projectiles (using the definition of a projectile)? (KEEP IN MIND, these are under normal circumstances unless otherwise stated) human walking meteor in Earth's atmosphere car driving airplane landing asteroid basketball being shot by Steph Curry ball on a rope , swinging around a pole (tetherball football thrown bird flying tennis ball served at 140 mph

Answers

The example of projectile is a basketball being shot by Steph Curry.

What is projectile?

Projectile is any object propelled through space by the application of a force.

Projectile is used to describe any object that is cast, fired, flung, heaved, hurled, tossed, or thrown. For example, when a ball is thrown straight upward, or kicked.

In projectile motion, gravity is the only force acting on the object. This doesn’t necessarily mean that other forces do not act on it, just that their effect is minimal compared to gravity. The path followed by a projectile is known as a trajectory.

Other examples of projectile is as follows:

Firing a canonJavelin throwArcheryGun fireGolf ball

Therefore, it can be said that a basketball being shot by a renowned basket baller into the air is an example of projectile.

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If the motion of an object in the x direction and y direction is known, how can the total motion of the object be found?

Answers

Explanation:

resultant motion = √x² + y²

this is using Pythagoras theorem whereas the x and y components can be used to construct a right angle triangle with the hypotenuse = resultant.

hope it helps. :)

Jacob and his scooter have a combined mass of 15 kg What is the force it will take to accelerate his scooter at 3 m/s²?​

Answers

Answer:

45 N

Explanation:

F = m a  = 15 * 3 = 45 N

A wave on a rope is shown in the diagram. In the diagram, d = 3 m.
(a) What is the wavelength of this wave?
(b) If the frequency is 5 Hz, what is the speed of the wave?

Answers

The wavelength of the wave is 3m and the speed of the wave is  15 m/s

What is a wave?

We define a wave as a disturbance that occurs along a medium and leads to the transference of energy from one point to another. As we can see the energy in this case is transferred along the length of the string. We know that the wavelength is the distance between the two successive crests or troughs.

Now we know that the distance between the two successive crests as we can see is the wavelength of the wave and this is shown the length that have been designated as d and we thus have the wavelength as 3m.

Again we have;

v = λf

v = speed of the wave

f = frequency of the wave

λ = wavelength of the wave

Then;

v = 3 m * 5 Hz

= 15 m/s

Thus the wave speed is obtained as 15 m/s.

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ASTRONOMY QUESTION
Over what range of distances from the Sun would you expect to find solid, rocky material collecting together to form a terrestrial planet?
Group of answer choices

A) 5 - 50 AU

B) beyond 50 AU

C) 0.2 - 5 AU

D) 0 - 0.2 AU

Answers

The range of distances from the Sun that you would expect to find solid, rocky material collecting together to form a terrestrial planet is option (C)  0.2 - 5 AU.

What is  formation of  a terrestrial planet about?

Jovian planets can be found at distances of 2 AU to 50 AU or more. This is the area where the early Solar System's temperature was below 273 K, water's freezing point.

Therefore, While rocky and metallic materials (Terrestrial planets) might have condensed over the whole range of distances from the Sun, only the rocky material could have accumulated over the range from 2 AU and inwards. H and He may have also been captured by the planet if it had been further from the Sun than 2 AU, which would have made it a Jovian or gas giant planet.

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A 40 N force is applied to a 10 kg block, but the object only accelerates at 2 m/s?. Explain why this happens using a free-body diagram.

Answers

Using a free body diagram to explain the situation,  the acceleration of the block decreased because of force of friction acting in opposite direction reducing the net force on the block and consequently the acceleration of the block.

What is net force on an object?

The net force on an object is the sum of all the forces acting on an object.

According to Newton's second law of motion, the net force on an object is directly proportional to the product of mass and acceleration of the object.

F(net) = ma

F - Ff = ma

where;

F is the applied force on the objectFf is the force of friction on the objectm is the mass of the objecta is the acceleration of the object

In the absence of friction force, the maximum acceleration of the block is calculated as;

a = F/m

a = 40 N / 10 kg

a = 4 m/s²

In the presence of friction force, the net force will decrease and the acceleration of the block will decrease as well.

In free body diagram (FBD) this can be represented as;

F →       Ф     ← Ff

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What is the speed of the car with a distance of 100 meters in 35 seconds?​

Answers

Answer:

Formula

V = D/T

Resolve:

V = 100m / 35sV = 2m/5

Hope this helped

Hello..!

We first apply the data to the problem.

Data:

Depth = 100 metersT = 35sV = ?

Then, we apply the formula that is.

Formula:

V = D/T

Finally we develop the problem.

Developing:

V = 100m / 35sV = 2m/s

The speed is 2 meters per second.

how long (in seconds) would it take a Narwhal to accelerate from rest down a 30 meter long ravine with an acceleration of 2.2 m/s^2

Answers

The time (in seconds) it will take the Narwhal to accelerate from rest down a 30 meter long ravine is 5.2 s

How do I determine the time?

We know from equations of motion that distance, acceleration and time are related according to the following formula:

s = ut + ½at²

Where

s is the distanceu is the initial velocitya is the accelerationt is the time

With the above formula, we can obtain the time as follow:

Initial velocity (u) = 0 m/sDistance (s) = 30 mAcceleration(a) = 2.2 m/s²Time (t) = ?

s = ut + 1/2at²

30 = (0 × t) + (½ × 2.2 × t²)

30 = 0 + (1.1 × t²)

30 = 1.1 × t²

Divide both side by 1.1

t² = 30 / 1.1

Take the square root of both side

t = √(30 / 1.1)

t = 5.2 s

Thus, the time taken is 5.2 s

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according to particle model of light what happens to the speed of light as it enters a optically denser medium.

Answers

According to particle model of light, speed of light decreases as it enters a optically denser medium.

Refraction occurs when a light beam crosses a barrier between two different materials. The ray changes direction and speed in accordance with the following relationship:

where n is the material's index of refraction, which is greater for a medium with a higher optical density, and v and c are the speed of light in a vacuum and the ray of light, respectively, in the material. As a result, the equation shows that the wave's speed decreases with increasing optical density.- Since the frequency of the light is independent of the characteristics of the medium, it is constant.

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Regarding the likelihood of planets orbiting other stars,

Answers

I hate to leave you answer less, but there isn't even a question here to answer.

Ametal cube of side 6cm at 20 degree Celsius on
heating to 600 degree Celsius increases by 0.3cm
calculating the coefficient of linear expansion
coefficient of superficial expression
coefficient of cubical expansion

Answers

We have the following from the question;

The coefficient of linear expansion is 8.6 * 10^-5

The coefficient of superficial expression is 1.72 * 8.6 * 10^-4

The coefficient of cubical expansion is  2.5  * 10^-4

What is the linear expansivity?

Let us recall that the term linear expansivity has to do with the increase in length, per unit length, per degree Kelvin rise in temperature. Now we know that we have the following information from the question;

Initial length =  6cm

Increase in length = 0.3cm

Initial temperature = 20 degree Celsius

Final temperature =  600 degree Celsius

We then have;

coefficient of linear expansion = e/[tex]l_{1}[/tex]([tex]T_{2}[/tex] - [tex]T_{1}[/tex])

e = extension

[tex]l_{1}[/tex] = initial length

[tex]T_{2}[/tex] = Final temperature

[tex]T_{1}[/tex] = initial temperature

coefficient of linear expansion = 0.3/6(600 - 20)

= 8.6 * 10^-5

coefficient of superficial expression = 2( 8.6 * 10^-5)

= 1.72 * 8.6 * 10^-4

coefficient of cubical expansion = 3(8.6 * 10^-5)

= 2.5  * 10^-4

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Technology has changed and continues to change the way we live our lives, directly affecting our health and wellness. List three ways that modern technology has enhanced people’s health and three ways that it has diminished their health. Address personal, family, and community health. Do you believe that the good outweighs the bad? Why or why not?

Answers

Advanced medicine, good healthcare and easy diagnose are three ways that modern technology has enhanced people’s health

Technology has changed how individuals go about their daily lives. Practically every action you take, including regular work and conversation, is affected by it. Thanks to technology, carrying out tasks around the house or going to work has become easier. Many gadgets and pieces of equipment make it easier for people to live. Transportation, education, and medicine are just a few of the societal fields it has affected.

Another significant benefit of technology in people's lives is the modernization of the healthcare industry. The days of waiting in an outpatient department queue for hours to see a doctor are long gone. Patients may schedule hospital visits and look up the business hours of their doctors' offices using mobile devices.

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The figure shows an overhead view of a 1.40 kg plastic rod of length 1.20 m on a table. One end of the rod is attached to the table, and the rod is free to pivot about this point without friction. A disk of mass 38.0 g slides toward the opposite end of the rod with an initial velocity of 35.5 m/s. The disk strikes the rod and sticks to it. After the collision, the rod rotates about the pivot point.
A thin vertical rod has a point labeled pivot at its bottom, and a disk moving horizontally along an arrow labeled vector v that will reach the rod perpendicularly at the top.

(a) What is the angular velocity, in rad/s, of the two after the collision?

Answers

The angular velocity, in rad/s, of the two after the collision is 28.7 rad/s.

What is the angular velocity after collision?

The angular velocity, in rad/s, of the two after the collision is determined by applying principle of conservation of angular momentum as follows;

I₁ω₁ = I₂ω₂

where;

I₁ is the initial moment of inertia of the rodI₂ is the final moment of inertia of the rodω₁ is the initial angular speed of the diskω₂ is the final angular velocity of the system after the collision

Initial moment of inertia of the rod is calculated as follows;

I₁ = ¹/₃ML²

where;

M is mass of the rodL is length of the rod

I₁ = ¹/₃ x 1.4 x (1.2²)

I₁ = 0.67 kgm²

Final moment of inertia of the rod is calculated as;

I₂ = ¹/₃ x (1.4 + 0.038) x (1.2²)

I₂ = 0.69 kgm²

I₁ω₁ = I₂ω₂

0.67(0 + 35.5/1.2) = 0.69ω₂

19.82 = 0.69ω₂

ω₂ = 19.82/0.69

ω₂ = 28.7 rad/s

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If one of the cars starts and ends at the same point in the race (making a loop around the track), what is the car's displacement?
A 0
B 1
C 2
D 7.5

PLEASE

Answers

Answer:

A.0

Explanation:

A weightless spring of force constant 2.50 N/cm is 15.0 cm long when nothing is attached to it. It is now used to pull horizontally on a 12.5 kg box on a smooth horizontal floor. You observe that the box starts from rest and moves 96.0 cm during the first 1.60 s of its motion. How long is the spring during this motion?

Answers

The length of the spring during the motion is 16.875 cm

How do I determine the length of the spring?

We'll begin by obtaining the velocity during the first 1.60 s. This is illustrated as follow:

Distance = 96 cm = 96 / 100 = 0.96 mTime = 1.60 sVelocity =?

Velocity = distance / time

Velocity = 0.96 / 1.6

Velocity = 0.6 m/s

Next, we shall determine the acceleration.

Initial velocity (u) = 0 m/sFinal velocity (v) = 0.6 m/sTime (t) = 1.6 sAcceleration (a) =?

a = (v – u) / t

a = (0.6 – 0) / 1.6

a = 0.6 / 1.6

a = 0.375 m/s²

Next, we shall determine the force.

Mass (m) = 12.5 kg

Acceleration (a) = 0.375 m/s²

Force (F) =?

Force = mass × acceleration

Force = 12.5 × 0.375

F = 4.6875 N

Next, we shall determine the extension of the spring.

Force (F) = 4.6875 NSpring constant (K) = 2.50 N/cmExtension (e) =?

F = Ke

Divide both sides by K

e = F / K

e = 4.6875 / 2.5

e = 1.875 cm

Finally, we shall dtermin the length of the spring. This can be obtained as follow:

Original length = 15 cmExtended length = 1.875 cmLength of spring =?

Length of spring = 15 + 1.875

Length of spring = 16.875 cm

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Does the coaster car travel as high as point h

Answers

Answer:

no coaster car does not travel as high

if the wet bulb depression is 3° and the dewpoint is 24°, what’s the relative humidity?

Answers

The relative humidity (RH) where the Wet Bulb Depression is 3° and the Dewpoint is 24° is given as 78.92%.

What is relative humidity?

Relative humidity (RH) is a percentage ratio of the quantity of atmospheric moisture available to the amount that would exist present if the air was saturated.

The relationship between Relative Humidity, Air Temperature, and Dewpoint is given as follows:

RH = 100 *[[tex]e^{\frac{(\beta * Dp)}{(\lambda + Dp)}}[/tex] / [tex]e^{\frac{(\beta * T)}{(\lambda + T)}}[/tex]]

Where

RH = Relative Humidity

T = Air Temperature

Dp = Dewpoint

β = 17.625 and λ = 243.04°C; (revised Magnus coefficients)

e = 2.7182818 [exponential constant]

Note that Air temperature (T) is determined using the attached Dewpoint Psychrometer Table /chart

As given on the chart and in the question;
T = 28°

Dp = 24°

Hence,

RH = 100 x [[tex]e^{\frac{(17.625 * 24)}{(243.04+ 24)}}[/tex] / [tex]e^{\frac{(17.625 * 28)}{(243.04+ 28)}}[/tex] ]
RH = 100 x [ [tex]e^{(423/267.04)}[/tex] )/ [tex]e^{(493.5/271.04)}[/tex]]

RH = 100 x [[tex]e^{1.584}[/tex]/[tex]e^{1.8207}[/tex]]

RH = 100 x (4.874414/6.176578)

RH = 100 x 0.789177113929

RH = 78.9177113929

RH [tex]\approx[/tex] 78.92%

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What ,begin emphasis,two,end emphasis, actions will ,begin emphasis,best,end emphasis, help people in Cape Town lessen the water shortage problem?

Answers

The following actions will help people in Cape Town to lessen the water shortage problem.

Diversifying the municipal water portfolio with water recycling, The desalination processUse of groundwater can reduce risk of water shortages due to drought

What is drought?

A drought is described as a moisture deficit relative to the average water availability at a given location and season. A drought is also defined as drier than normal conditions.

Water shortage is becoming an increasing threat in Cape town because of climate change impacts which includes changing rainfall patterns and rising temperatures and increasing water demand.

In summary, the city of Cape town can develop engineering dams and 'importing' water through inter-basin transfer schemes to help in fighting drought.

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In a series connection, three lamps are available L(1), L(2) and L(3). If we take out the L(3) bulb, what happens to each of the other bulbs?
Helpp :'v​

Answers

Hello..!

¿What is a series circuit?

A series circuit is a connection configuration in which the terminals of devices are connected successively, that is, the output terminal of one device is connected to the input terminal of the next device.

Problem:

In a series connection, three lamps are available L(1), L(2) and L(3). If we take out the L(3) bulb, what happens to each of the other bulbs?

If we put two lamps in a series circuit, the following can be obtained: the voltage that enters the first lamp will go out in the second lamp, that is, if we have a switch and we turn the lamps on and off, they will light up together.If we have a circuit of three lamps, the same thing happens.If the L(2) bulb burns out or we take it out, what will happen is that there will not be enough voltage for the L(1) and L(3) bulbs and that means these two bulbs will not work. If we remove the lamp L(1), not enough voltage passes to the lamp L(2) and it is not enough for the L(3), because the lamp L(2) shares voltage with the L(2)If we remove the lamp L(3) we can turn off the lamp L(2) and L(1) as there is not enough voltage to turn them on.

Why does it happen?

This is because the battery voltage is divided between the components, which will therefore have a lower voltage than the battery. This means that the lamps light less when they are in series.

The answer is that if we remove the L(3) lamp, the others stop working.

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[tex]\begin{gathered}\rule{7cm}{0.01mm}\\\texttt{Bons estudos! :D}\\\rule{7cm}{0.01mm}\end{gathered}[/tex]

Answer:

This is because the battery voltage is divided between the components, which will therefore have a lower voltage than the battery.

Hope this helped

Which method occurs in a refrigerator?

A. Conduction
B. Convection
C. Radiation

Answers

Convection is the method which occurs in a refrigerator

What is Convection ?

Convection is used in a refrigerator's system to remove heat from the freezer and refrigeration compartments and send it outside the appliance. The process of convection involves the transfer of heat through the movement of material, typically a gas or a liquid.

Cool air sinks, hence the freezer is located at the top of a refrigerator. The warmer air rises, creating a convection current inside the refrigerator that helps keep it cool. Convection in refrigerators is crucial, so why? The food in the freezer cools the air at the top, which then cools the food as it descends.

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The decibel rules of thumb can be combined. (a) If a sound has intensity xdB, how many dB does a sound 100 times more intense have? (b) If another sound has intensity ydB, how many dB does a sound 4 times less intense have? (c) Combine what you know about (a) and (b): If a sound has intensity zdB, how many dB does a sound 25 times more intense have?

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C i think hope this help
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