The diameter of a circle is 8 units. What is the circle's circumference? Do not round your answer.

(Use 3.14

Answer: i BELIEVE YOUR ANSWER IS

.....  

B

Step-by-step explanation:

Answer:

1)1

2)x3

3)x8

4)576

5)36

Step-by-step explanation:

Answer:

1. 1 2. x³ 3.x∧8 4. 576 5. 6² 6. y∧12

7. a¹b∧-5 8. 8x∧9y∧6 9. 225 10. mº=1

Step-by-step explanation:

Answer:

5x+(-3x+11)=21

2x+11=21

2x=21-11

2x=10 2x/2=10/2

x=5

Answer:

X = 5

Step-by-step explanation:

here's your solution

=> y= -3x + 11.

=> given equation = 5x + y = 21

=> by putting value of Y in given equation

=> 5x -3x + 11 = 21

=> 2x + 11 = 21

=> 2x = 21-10

=> x = 10/2

=> x = 5

hope it helps

Answer:

x=⅗ or 0.6ft

y=7ft

step by step explanation

Answer:

Divide both numbers by five, apparently

I am glad i helped! Have a good day and remember to be tiger fierce!! :)

Answer:

Sum of angles of a polygon with one side less = (12-2)x180 = 1800

Sum of angles of a polygon with one side more​ = (14-2)x180 = 2160

Step-by-step explanation:

(n-2)x180 = 1980

n = 13

Sum of angles of a polygon with one side less = (12-2)x180 = 1800

Sum of angles of a polygon with one side more​ = (14-2)x180 = 2160

Illustrations in reverce order

Explanations:

6. [tex]\displaystyle y = Atan(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]

You can choose to figure the period out by looking at the distanse between each endpoint on the x-axis, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, ALL tangent, secant, cosecant, and cotangent functions have NO amplitudes, so you figure out what you want to put in the blank, but make sure it is not a numerical value. Not even ZERO can be plased there.

_______________________________________________

5. [tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 4[/tex]

You can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline.

_______________________________________________

4. [tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{2}{1}\pi \\ Amplitude \hookrightarrow 3\frac{1}{2}[/tex]

Again, you can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midine.

_______________________________________________

3. [tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow \frac{1}{2}[/tex]

Again, you can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline.

_______________________________________________

2. [tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 1[/tex]

Again, you can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline.

_______________________________________________

1. [tex]\displaystyle y = Atan(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{\pi} \hookrightarrow \frac{\pi}{1} \\ Amplitude \hookrightarrow N/A[/tex]

Again, you can choose to figure the period out by looking at the distanse between each endpoint on the x-axis, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period.

I am delighted to assist you at any time.

*I also apologise for the sixth photograph not being present [exercise 1]. The system ALL OF A SUDDEN no longer allows me to display more than five photographs. You will have to see the graph somewhere elce.

Answer:

15cmerote

Step-by-step explanation:

Answer:

[tex]V=\frac{45\sqrt{3} }{2}cm^{2}[/tex]

Step-by-step explanation:

Volume= Area*height

height: h=10cm

Area of isosceles triangle:

[tex]A=\frac{9\sqrt{3} }{4} cm^{2}[/tex]

Volume:

[tex]V=\frac{9\sqrt{3} }{4}*10\\\\V=\frac{90\sqrt{3} }{4}\\\\V=\frac{45\sqrt{3} }{2}cm^{2}[/tex]

Step-by-step explanation:

As we can see it is a parallelogram so here the diagonals bisect so

6y + 1 = 4y + 9

6y - 4y = 9 - 1

2y = 8

y = 8 / 2

y = 4

2x - 5 =x + 7

2x + x = 7 + 5

3x = 12

x = 12 / 3

x = 4

Hope it will help :)

Answer:

equation

180=90+38+x

where x equals missing angle

x=52

Step-by-step explanation:

Hello There!

remember the sum of the interior angles of a triangle is 180

so to find the measure of the missing angle we subtract the given angles from 180

180-90-38=52

so the measure of the missing angle is 52

Answer:

MATHMATICS - MTHMTCS

SEPTEMBER - SPTMBR

ANCILLARY - NCLLR

PTERODACTYL-PTRDCTL

Hopefully this helps <3

9514 1404 393

Answer:

  (d)  (-2, 6)

Step-by-step explanation:

We can rewrite the function using vertex form.

  f(x) = (x^2 +4x) +10

  f(x) = (x^2 +4x +4) +10 -4 . . . . . . . add and subtract (4/2)^2

  f(x) = (x +2)^2 +6

Compare to vertex form:

  f(x) = (x -h)^2 +k

we see that (h, k) = (-2, 6) . . . . the vertex

_____

Additional comment

The value added and subtracted is the square of half the x-coefficient. Inside parentheses, that value "completes the square". Outside parentheses, that value ensures the overall function remains unchanged.

Answer:

Rounded it's 46,000

Step-by-step explanation:

Answer:

X = 1 , 2

Y = -1 , 2

Z = -2 , -1

Answer:

0.75

Step-by-step explanation:

Given:

The polynomial is

[tex]-x+5x^2+1[/tex]

To find:

The polynomial in the form [tex]ax^2+bx+c[/tex] and find the values of a, b and c.

Solution:

We have,

[tex]-x+5x^2+1[/tex]

Arranging the terms in descending order of their degrees, we get

[tex]=5x^2-x+1[/tex]

[tex]=(5)x^2+(-1)x+1[/tex]

On comparing this polynomial with [tex]ax^2+bx+c[/tex], we get

[tex]a=5,b=-1,c=1[/tex]

Therefore, the value of a is 5, the value of b is -1 and the value of c is 1.

Answer: The number which Fran is thinking about is 82 or 93.

Step-by-step explanation:

A two-digit number can be written as:

a*10 + b

Where a and b are single-digit numbers.

We know that:

"the first digit is 6 more than the second digit"

then:

a = b + 6

And we know that the second digit is a prime number.

Then we can have:

b = 2

b = 3

b = 5

b = 7

Now let's try with these different options.

if b = 2, then:

a = 2 + 6 = 8

Then the number is:

8*10 + 2 = 82

If b = 3, then:

a = 3  + 6 = 9

Then the number is:

9*10 + 3 = 93

if b = 5, then:

a = 5 + 6 = 11

But a needs to be a single-digit number, then b can not be 5 or larger.

Then the only two possible numbers are:

82 and 93.

So the number which Fran is thinking about is 82 or 93.

Answer:

≈ 18.3 m²

Step-by-step explanation:

The shaded area (A) is calculated as

A = area of sector - area of right triangle

area of sector = area of circle × fraction of circle

A = πr² × [tex]\frac{90}{360}[/tex]

   = π × 8² × [tex]\frac{1}{4}[/tex] = 64π × [tex]\frac{1}{4}[/tex] = 16π m²

area of triangle = [tex]\frac{1}{2}[/tex] × 8 × 8 = 4 × 8 = 32 m²

shaded area is then

A = 16π - 32 ≈ 18.3 m² ( to the nearest tenth )

Answer:

84 in^2

Step-by-step explanation:

Answer:

84in^2

Step-by-step explanation:

First we can calculate the rectangle which would be

6*11=66

then we can calculate the triangle

we know that the base is 6, so if we cut it in half we get two triangles which could get put back together in another rectangle so we would just need to do

6*3=18

then add them together

66+18=84

Answer:

v≤-12, and the graph is left 12  

Step-by-step explanation:

9514 1404 393

Answer:

  a) $15,779.70

  b) $13,679.70

  c) $210.92

Step-by-step explanation:

a) When tax is added, the total cost is ...

  total = price × (1 +tax rate)

  total = $14,775 × 1.068 = $15,779.70

__

b) The amount financed is the difference between the total cost and the down payment.

  financed = total - down35

  financed = $15,779.70 -2100 = $13,679.70

__

c) The monthly payment is found using the amortization formula. It can also be found using any of a number of financial calculators, spreadsheets, or apps.

  A = P(r/12)/(1 -(1 +r/12)^-n) . . . . annual rate r, n monthly payments, principal P

  A = $13,679.70(0.035/12)/(1 -(1 +0.035/12)^-72) ≈ $210.92

Answer:

this is to hard

Step-by-step explanation:

7, 8 ,9 ,0 10

Answer: 34

Step-by-step explanation:

D+F+E = 12+14+8=34

Answer:

17 in

Step-by-step explanation:

DE = 1/2(14) = 7

DF = 1/2(8) = 4

EF =1/2(12) = 6

7 + 4 + 6 = 17 in

Square the two smallest values and then add them together. If they are greater than the square of the largest number in the set, than it is obtuse. If smaller it is acute. If it is the same it is a right triangle.

9514 1404 393

Answer:

Step-by-step explanation:

The Law of Cosines tells you the largest angle C will be found from ...

  C = arccos((a² +b² -c²)/(2ab))

where c is the longest side of the triangle.

For the purpose of classifying the triangle as acute, right, or obtuse, you need only look at the sign of the argument of the arccos function. Since all side lengths are positive, this means you only need to look at the sign of the "form factor" a²+b²-c².

When f = a²+b²-c² is negative, the cosine is of an angle larger than 90°, so the triangle is obtuse. When it is 0, the angle is 90°, so a right triangle. (That condition is recognizable as related to the Pythagorean theorem.) When f > 0, the triangle is acute.

__

In the attached spreadsheet, we have done these calculations by summing the squares of all three sides, then subtracting twice the square of the longest side. (This makes the formula fairly simple.) It shows ...

  Triangle 1: f < 0 — obtuse triangle

  Triangle 2: f > 0 — acute triangle

_____

In summary, you can compute a form factor ...

  f = a² +b² -c² . . . . . . . triangle with side lengths a, b, c with c longest

Answer:

[tex]\frac{3}{16} x^{3}-\frac{9}{4}x+6 = y[/tex]

Step-by-step explanation:

Lets start with the easiest part of this question - simply plugging in to get easier equations:

[tex]-8a+4b-2c+d=9\\[/tex]

[tex]8a+4b+2c+d=3[/tex]

Something that now immedietly pops out is that many of the terms would cancel if we added them together. We get the following results by adding the two equations together:

[tex]8b+2d = 12[/tex]

Now lets look at the other bit of inromation the question gives you -- that the two points are horizontal tangents. Taking the derivative of the standard form of a cubic, we get:

[tex]y' = 3ax^2+2bx+c[/tex]

Since the points are both horizontal tangents, y' will be equal to 0 at the points. Thus, plugging in we get:

[tex]y'(-2) = 0 = 12a-4b+c[/tex]

[tex]y'(2) = 0 = 12a+4b+c[/tex]

We again see a simple subtracting opportunity that will cancel out two terms:

[tex]-8b = 0[/tex]

[tex]b = 0[/tex]

Now going back to the equation we got by adding the two equations that we got from simply plugging our points in:

[tex]d = 6[/tex]

Now that we have b and d, we can now plug them back into our step one and derivative equations in order to get a simple system:

[tex]-8a - 2c=3[/tex]

[tex]12a+c=0[/tex]

Solving for a and c, we get:

[tex]a = \frac{3}{16}[/tex]

[tex]c = \frac{-9}{4}[/tex]

Thus, finally, our answer is:

[tex]\frac{3}{16} x^{3}-\frac{9}{4}x+6 = y[/tex]

Attached is desmos, which you can use to check.

Answer:

40

Step-by-step explanation:

I dont know the area of a semi circle.

10 x 8 = 80 divided by 2 = 40

Answer:

B 21.50 dollars

Step-by-step explanation:

Answer: 10 km/ hr

Step-by-step explanation:

In the graph below, Diego's speed at various points during his 10 kilometer race is shown on the y axis while the distance is shown on the x axis.

Looking at the 1km mark on the x axis, Diego's speed on the y-axis is at 10km/ hr and this was the speed he started the race with. After the kilometer mark however, his speed changed and went on to increase to 11km/ hr by the second kilometer mark.

QTR & TRS

.....................................

Answer:

triangle TQR to triangle TRS

AS angle QRT= angle RTS

QR=TS

and their height are same

hope it helps! :)